Answer:
lamda=10.5m
Explanation:
using the equation of progressive wave.
y=Asin(wt-kx)
comparing the two equations together, we have
kx=0.6x , k=0.6
k=2π/λ
0.6=2*3.142/λ
cross multiply
0.6λ=6.284
divide both sides by 0.6
λ=6.284/0.6
λ=10.47m
approximate
λ=10.5m
What is a Joule, and what are the SI units for a Joule?
The joule is a derived unit of energy in the International System of Units. It is equal to the energy transferred to an object when a force of one newton acts on that object in the direction of the force's motion through a distance of one metre.
Joule, unit of work or energy in the International System of Units (SI); it is equal to the work done by a force of one newton acting through one metre. Named in honour of the English physicist James Prescott Joule, it equals 107 ergs, or approximately 0.7377 foot-pounds.
What is the kinetic energy of a 3 kg ball that is rolling at 3 m/s?
Answer:
[tex]\Huge \boxed{\mathrm{13.5 \ Joules}}[/tex]
Explanation:
[tex]\sf Kinetic \ energy \ (J)=\frac{1}{2} \cdot mass \ (kg) \cdot (velocity \ (m/s)) ^2[/tex]
[tex]\mathrm{KE=\frac{1}{2} mv^2}[/tex]
The mass of the ball is 3 kg.
The velocity of the ball rolling is 3 m/s.
[tex]\mathrm{KE=\frac{1}{2} \cdot 3 \cdot 3^2}[/tex]
Evaluating and solving for kinetic energy.
[tex]\mathrm{KE=\frac{1}{2} \cdot 3 \cdot 9}[/tex]
[tex]\mathrm{KE=\frac{1}{2} \cdot 27}[/tex]
[tex]\mathrm{KE} =13.5[/tex]
The kinetic energy of the ball is 13.5 Joules.
Answer:
Kinetic energy =1/2mv^2.
1/2×3×3^2.
1/2×27=13.5 or 13 whole number 1/2.
Many types of scientific equipment are used to perform different functions in the science lab.Which of the folllowing combinations of equipment would be needed to bring one liter of water to 85 degree
Answer:
Many types of scientific equipment are used to perform different functions in the science lab. Which of the following combinations of equipment would be needed to bring one liter of water to 85°C? a. ... Various pieces of safety equipment are used in the lab to provide protection against injury.
Explanation:
Question 5 At 12:00 pm, a spaceship is at position ⎡⎣324⎤⎦ km ⎣ ⎢ ⎡ 3 2 4 ⎦ ⎥ ⎤ km away from the origin with respect to some 3 dimensional coordinate system. The ship is travelling with velocity ⎡⎣−12−3⎤⎦ km/h ⎣ ⎢ ⎡ −1 2 −3 ⎦ ⎥ ⎤ km/h What is the location of the spaceship after 2 hours have passed
Answer:
[1, 6, -2]
Explanation:
Given the following :
Initial Position of spaceship : [3 2 4] km
Velocity of spaceship : [-1 2 - 3] km/hr
Location of ship after two hours have passed :
Distance moved by spaceship :
Velocity × time
[-1 2 -3] × 2 = [-2 4 -6]
Location of ship after two hours :
Initial position + distance moved
[3 2 4] + [-2 4 -6] = [3 + (-2)], [2 + 4], [4 + (-6)]
= [3-2, 2+4, 4-6] = [1, 6, -2]
The location of the spaceship after 2 hours have passed is [1, 6, -2]
Calculation of the location:Since
Initial Position of spaceship : [3 2 4] km
Velocity of spaceship : [-1 2 - 3] km/hr
Now
Location of the ship after two hours should have passed
So,
Distance moved by spaceship should be
= Velocity × time
= [-1 2 -3] × 2
= [-2 4 -6]
Now
Location of ship after two hours should be
= Initial position + distance moved
= [3 2 4] + [-2 4 -6]
= [3 + (-2)], [2 + 4], [4 + (-6)]
= [3-2, 2+4, 4-6]
= [1, 6, -2]
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An object is located 25.0 cm from a convex mirror. The image distance is -50.0 cm. What is the magnification?
Answer:
[tex] \boxed{\sf Magnification \ (m) = 2} [/tex]
Given:
Object distance (u) = 25.0 cm
Image distance (v) = -50.0 cm
To Find:
Magnification (m)
Explanation:
[tex]\boxed{\bold{\sf Magnification \: (m) = - \frac{Image \: distance \: (v)}{Object \: distance \: (u)}}}[/tex]
Substituting values of Image distance(v) & Object distance (u) in the equation:
[tex] \sf \implies m = - \frac{( - 50)}{25} [/tex]
-(-50) = 50:
[tex]\sf \implies m = \frac{50}{25} [/tex]
[tex]\sf \implies m = \frac{2 \times \cancel{25}}{ \cancel{25}} [/tex]
[tex]\sf \implies m = 2[/tex]
Answer:
+2
Explanation:
m = -di/do
m = -(-50)/25 = 2
A car is traveling at some speed when it accelerates at 6 m/s2 for 3 seconds. If the car travels 39 meters in this time, how fast was it going before it sped up?
Answer:
4 m/s
Explanation:
Given:
Δx = 39 m
a = 6 m/s²
t = 3 s
Find: v₀
Δx = v₀ t + ½ at²
39 m = v₀ (3 s) + ½ (6 m/s²) (3 s)²
v₀ = 4 m/s
A scale at a grocery store is made of a metal pan (of negligible mass) placed on an ideal spring. The spring has a force constant of 655 N/m. A customer gently rests 1.00 kgs of bananas and 2.00 kg of potatoes on the scale. When the 2.00 kg potatoes is suddenly removed, how high above the starting position do the bananas reach?
Answer:
The ideal spring is 0.030 meters above the starting position.
Explanation:
Let consider that spring is modelled by the Hooke's Law, which is represented by the following expression:
[tex]F = k\cdot \Delta x[/tex]
Where:
[tex]F[/tex] - Force exerted on the ideal spring, measured in newtons.
[tex]k[/tex] - Spring constant, measured in newtons per meter.
[tex]\Delta x[/tex] - Spring elongation, measured in meters.
The elongation is now cleared:
[tex]\Delta x = \frac{F}{k}[/tex]
The initial force experimented by the spring is due to the weight of bananas and potatoes.
[tex]F = (m_{b} + m_{p})\cdot g[/tex]
Where:
[tex]m_{b}[/tex], [tex]m_{p}[/tex] - Masses of bananas and potatoes, measured in kilograms.
[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.
If [tex]m_{b} = 1\,kg[/tex], [tex]m_{p} = 2\,kg[/tex], [tex]g = 9.807\,\frac{m}{s^{2}}[/tex] and [tex]k = 655\,\frac{N}{m}[/tex], the initial elongation of the ideal spring is:
[tex]F = (1\,kg + 2\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)[/tex]
[tex]F = 29.421\,N[/tex]
[tex]\Delta x_{o} = \frac{29.421\,N}{655\,\frac{N}{m} }[/tex]
[tex]\Delta x_{o} = 0.045\,m[/tex]
The final elongation is obtained after eliminating the influence of potatoes due to gravity. That is to say:
[tex]F = m_{b}\cdot g[/tex]
[tex]F = (1\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)[/tex]
[tex]F = 9.807\,N[/tex]
The final elongation of the ideal spring is:
[tex]\Delta x_{f} = \frac{9.807\,N}{655\,\frac{N}{m} }[/tex]
[tex]\Delta x_{f} = 0.015\,m[/tex]
The displacement of the spring due to the removal of potatoes is:
[tex]d = \Delta x_{o} - \Delta x_{f}[/tex]
[tex]d = 0.045\,m-0.015\,m[/tex]
[tex]d = 0.030\,m[/tex]
The ideal spring is 0.030 meters above the starting position.
Two students are watching a person riding a skateboard up and down a ramp. Each student shares what they think about the energy of the skateboarder as they ride up and down the ramp. Elisa: I think the skateboarder has the more total energy at the top of the ramp than the bottom of the ramp. Raymond: I think the skateboarder has the same total energy at all points on the ramp. Which student do you agree with? Why?
Answer:
no
Explanation:
Answer:
Elisa
Explanation:
I I agree with her because when you're at the top of the ramp you are going down and you are going to go down in an exact fast speed so you do have more energy and momentum at the top of the ramp
Plants that listen to hard rock will grow slower than plants that listen to classical music is an example of
Answer:
Ummm... I dont know what the question really is. But I would say in English terms it is an example of Personfiction I guess
Explanation:
What is the SI unit of gravitational constant?
Explanation:
The force between two bodies is given by :
[tex]F=G\dfrac{m_1m_2}{r^2}[/tex]
And this force is called the gravitational force
r is the distance between bodies
G is universal gravitational constant
[tex]G=\dfrac{Fr^2}{m_1m_2}[/tex]
SI unit of force is Newton or N
SI unit of r is meter or m
The SI unit of m₁ and m₂ is kg
[tex]G=\dfrac{\text{Nm}^2}{\text{kg}^2}\\\\G=Nm^2kg^{-2}[/tex]
Newton = kg m/s²
So,
[tex]G=\dfrac{kgm^3}{s^2kg^2}\\\\G=kg^{-1} m^3s^{-2}[/tex]
Hence, this is the required solution.
A man, holding a weight in each hand, stands at the center of a horizontal frictionless rotating turntable. The effect of the weights is to double the rotational inertia of the system. As he is rotating, the man opens his hands and drops the two weights. They fall outside the turntable. Then:
Answer:
w = 2w₀ the angular velocity of man doubles
Explanation:
In this exercise, releasing the weights reduces the moment of inertia
I= I₀ / 2
Therefore, since the platform system plus man is isolated, the kinetic moment must be conserved
L₀ = L
I₀ w₀ = I w
I₀ w₀ = I₀ / 2 w
w = 2w₀
therefore the angular velocity of man doubles
The weight of a body kept at a distance of 6400 km from the centre of the
earth is 10N. What will be the weight of another object kept at a distance of 12,800km ?
Answer:
2.5N
Explanation:
since force is inversely proportional to square of the distance apart. that means the ratio of distance apart. so u have 12800×12800÷(6400××6400)=4/1
so the weight will be reduced to 1/4 of 10N
If the angle of reflection of a propagated ray is 35°. Calculate the a. Angle of incidence b. Angle of deviation c. Angle of glance
[tex] \LARGE{ \underline{ \blue{ \tt{Required \: answers}}}}[/tex]
First of all,
Angle of incidence = Angle between normal and incident ray.Angle of reflection = Angle between normal and reflected rayGlance angle of incidence = Angle between incident ray and the surface.Glance angle of reflection = Angle between reflected ray and the surface.We have,
➝ Angle of reflection = 35°
(a) According to law of reflection,
Angle of incidence = Angle of reflection
➝ Angle of incidence = 35°
(b) By using formula,
Angle of Deviation = 180° - 2(Angle of incidence)
From (a),
➝ Angle of Deviation = 180° - 2(35°)
➝ Angle of Deviation = 180° - 70°
➝ Angle of Deviation = 110°
(c) We know,
Angle of Incidence + Glance angle of incidence = 90°
Angle of reflection + Glance angle of reflection = 90°
So,
As angle of incidence = angle of reflection
Then, Angle of glance is also equal.
➝ Angle of glance = 90° - 35° = 55°
━━━━━━━━━━━━━━━━━━━━
if a rock sample has a mass of 2.7 g and a volume of 1.1 cm³, what type of rock is it? (answer choices are Diamond, Common glass, ruby, and cubic zirconia)
Answer:
common glass
Explanation:
State the best unit for measuring mass:
a. mass of a chips:
b. your mass:
Answer:
Mass of chips: Gram ( g )
Your mass: Kilogram ( kg )
A 10 gram ball is rolling at 3 m/s. The ball has __________ energy. Calculate it. A 10 gram ball is held 2 meters from the ground. It has __________ energy. Calculate it. You serve a volleyball with a mass of 2100 g. The ball leaves your hand with a velocity of 30 m/s. The ball has ____________ energy. Calculate it. A toy baby carriage is sitting at the top of a hill that is 21 m high. The carriage with the baby has a mass of 200 grams . The carriage has ____________ energy. Calculate it. A toy car is traveling with a velocity of 4 m/s and has a mass of 1120 g. The car has ___________energy. Calculate it. A cinder block is sitting on a platform 20 m high. It has a mass of 790 grams. The block has _____________ energy. Calculate it. There is a bell at the top of a tower that is 5 m high. The bell has a mass of 190 grams. The bell has ____________ energy. Calculate it. A toy roller coaster is at the top of a 2 m hill and has a mass of 9660 grams. The coaster (at this moment) has ____________ energy. Calculate it.
Answer:
a) KINETIC ENERGY K = 0.045 J , b) POTENTIAL ENERGY U = 0.196 J ,
c) KINETIC ENERGY K = 9.45 10⁵ J, d) POTENTIAL ENERGY , U = 41.16 J ,
e) POTENTIAL ENERGY U = 154.84 J , f) ENERGY IS POTENTIAL U = 9.31 J
g) energy is POTENTIAL U = 189.336 J
Explanation:
a) The ball is moving with a speed, so it has KINETIC ENERGY
K = ½ m v²
K = ½ 10 10⁻³ 3²
K = 0.045 J
b) The ball is at a given height therefore it has POTENTIAL GRAVITATORY ENERGY
U = m g y
U = 10 10-3 9.8 2
U = 0.196 J
c) The ball has speed so it has KINETIC ENERGY
K = ½ m v²
K = ½ 2,100 30²
K = 9.45 10⁵ J
d) The baby carriage is at a height whereby the POTENTIAL ENERGY
U = mg h
U = 0.200 9.8 21
U = 41.16 J
e) the concrete block is at a height that has POTENTIAL ENERGY
U = m g h
U = 0.790 9.8 20
U = 154.84 J
f) the hood has height, the ENERGY IS POTENTIAL
U = 0.190 9.8 5
U = 9.31 J
g) The roller coaster has height and speed, therefore the mechanical energy has a scientific part and a potential part, in general the speed at the top of the mountain is very small, so we can consider that almost all the energy is POTENTIAL
The value they give allows calculating the potential energy
U = 9.660 9.8 2
U = 189.336 J
The answer to all the questions on potential energy and kinetic energy have been done below;
A) We are told that the ball is rolling. An object in motion has kinetic energy. Formula for kinetic energy is;
K = ½mv²
We have; m = 10 g = 0.01 kg and v = 3 m/s
K = ½ × 0.01 × 3²
K = 0.045 J
B) We are told that the ball is held at a height. This means it is at rest and any object at rest has Potential Energy. Formula for potential energy is;
PE = mgh
We have; m = 10g = 0.01 kg and h = 2 m
PE = 0.01 × 9.8 × 2
PE = 0.196 J
C) Like in A above, the ball is in motion. Thus, it has kinetic energy.
K = ½ × 2.1 × 30²
K = 945 J
D) The baby carriage is sitting at rest and therefore has potential energy.
PE = 0.2 × 9.8 × 21
PE = 41.16 J
E) The toy car is in motion and has kinetic energy. Thus;
K = ½ × 1.12 × 4²
K = 8.96 J
F) The cinder block is sitting at rest and has potential energy. Thus;
PE = 0.79 × 9.8 × 20
PE = 154.84 J
G) The bell is at the top of the tower and is at rest and thus has potential energy.
PE = 0.19 × 9.8 × 5
PE = 9.31 J
g) The rollercoaster is at the top at rest and so has potential energy.
PE = 9.66 × 9.8 × 2
PE = 189.336 J
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Anyone please help ASAP Why must the volume of a stereo in a room with wall-to-wall carpet be tuned higher than in a room with a wooden floor?related to sound.
Explanation:
A carpet absorbs sound making the room quieter. A wooden floor reflects sound making it louder. ... The carpet surface absorbs some of the sound, making the room less “live.”
The bottle's mass is 0.2 kg. The diameter of its base is 10cm. How much pressure does the bottle exert on the table? A) 64 Pa B) 25 Pa C) 6.4 Pa D) 255 Pa
Answer:
B 25pa.................................
which of the following statements is true about the atoms of any element
Answer:
The number of protons in an atom of an element is unique to each element. A proton in an atom of one element is identical to a proton in an atom of another element. The number of protons in an atom of an element is the same for all elements.
What is most likely the author’s motive for writing this article?
A.to get you to buy sports products
B.to get you to support nuclear power plants
C.to get you to raise money for space programs
D.to get you to appreciate the benefits of atomic research
Answer:
D
Explanation:
Answer
Its D
Explanation:
What is the sub-unit of capacitance in physics?
Answer:
farad
Explanation:
The farad (symbol: F) is the SI derived unit of electrical capacitance, the ability of a body to store an electrical charge. It is named after the English physicist Michael Faraday. hope this helps you :)
In a double-slit interference experiment you are asked to use laser light of different wavelengths and determine the separation between adjacent maxima. You observe that this separation is greatest when you illuminate the double slit with
Answer:
y = m λ L / d
must use lasers of greater wavelength
Explanation:
The expression for the constructive interference of a double slit is
d sin θ = m λ
let's use trigonometry to find the angle
tan θ = y / L
in interference phenomena the angles are small
tan θ= sin θ/ cos θ = sin θ
sin θ = y / L
we subjugate
d y / L = m λ
y = m λ L / d
In this expression we see that the separation of the lines (and) increases linearly with the wavelength, therefore we must use lasers of greater wavelength
mike shoots a large marble (Marble A, mass:0.05 kg) at a smaller marble (Marble B, mass: 0.03 kg) that is sitting still. Marble A was initially lacking at a velocity of 0.6 m/s, but after the collision it has a velocity of -0.2 m/s what is the resulting velocity of marble B after the collision? be sure to show your work.
Explanation:
According to Conservation of Linear Momentum :
[tex]m_1u_1+m_2u_2=m_1v_1+m_2v_2[/tex]
[tex]0.05 \times 0.6 + 0.03 \times 0 = 0.05 \times - 0.2 + 0.03 \times v_2[/tex]
[tex]0.04 = 0.03v_2[/tex]
Velocity of marble B after collision = 1.33 m/sec
The scale is 1:30 and their are 10 boulders. How many boulders are their in the real pond
A:20
B:10
C:300
D:3
Answer:
the correct answer is C
Explanation:
When we express that the scale is 1:30 we mean that the objects of the realization are reduced by a factor of 30 in the graph, for example a distance of 30 cm in the graph is represented by a distance of 1 cm.
Therefore something that in the graph has n value to bring it to real size must be multiplied by the scale.
Applying this to our case if there is
10 boulder on the chart
in reality there are #_boulder = 10 30
#_boulder = 300 boulder
so the correct answer is C
A blue train of mass 50 kg moves at 4 m/s toward a green train of 30 kg initially at rest. The trains collide. After the collision the green train moves with a speed of 3 m/s. What is the final momentum of the green train? A. 90 kgm/s B. 20 kgm/s C. 200 kgm/s D. 110 kgm/s
Explanation:
Momentum = mass × speed
p = (30 kg) (3 m/s)
p = 90 kg m/s
A track and field athlete is running forward with a javelin at a
velocity of 4.2 m/s. If he throws the javelin at a velocity relative
to him of 10.3 m/s, what is the velocity of the javelin relative to the ground?
Please help
Explanation:
The relative velocity is the velocity of the athlete relative to the ground plus the velocity of the javelin relative to the athlete.
v = 4.2 m/s + 10.3 m/s
v = 14.5 m/s
The relative velocity of the javelin relative to the ground be 14.5 m/s.
What is velocity?The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction. SI unit of velocity is meter/second.
Given parameters:
Velocity of the athlete: u = 4.2 m/s
Velocity of the javelin related to him: v = 10.3 m/s.
The relative velocity of the javelin relative to the ground is the velocity of the athlete relative to the ground plus the velocity of the javelin relative to the athlete.
So, The relative velocity of the javelin relative to the ground is:
V = 4.2 m/s+ 10.3 m/s
⇒ V= 14.5 m/s
Hence, the relative velocity of the javelin relative to the ground be 14.5 m/s.
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HELP ASAP!! WILL MARK BRAINLIEST!! WRITE IN YOUR OWN WORDS!! What is something that you would like to see a physicist develop in the future?
Answer:
Phones as sunglasses with a mic. I put on my glasses and I say what's the weather today, The sunglasses will tell me the weather and can be charged just like phones
Explanation:
The force of air particles over an area is_____?
(b) If the straight-line distance from her home to the university is 10.3 km in a direction 25.0° south of east, what was her average velocity?
Answer:
The time taken is missing in the question. The time is 18 minutes.
The answer is 34.3 km/hr
Explanation:
Average velocity is the speed or the velocity which is required to cover a distance in a time interval.
The time taken is = 18 min
= 18/60 hours
The distance from the university to her home is = 10.3 km
Therefore, the average velocity is = displacement/time taken
= 10.3 / (18/60) km/hr
= 34.3 km/hr
Hence, the average velocity is 34.3 km/hr
When you look at these spectra you can see different colors (wavelengths) at once. But each atom emits only one wavelength (one photon) at a time. o. Why are multiple wavelengths simultaneously visible
Answer:
Different wavelengths of light also have different frequencies, so the "individual" waves of light are different.
So when you see a given spectra, you are actually watching a superposition of different light waves, and as the waves do not interact that much between them, you can see the different colors.
You can think this similarly as the case with two different sound waves, one high in pitch, and another low.
You can easily identify them, as they do not collide between them.
Now, if you are asking "why the spectrum has different colors".
This is because the levels of energy in each element are different, the outer electrons have weaker bonds, so they will emit photons with less energy (larger wavelength) and so on.
So there are multiple wavelengths because electrons with stronger and weaker bonds are jumping between states at the same time.