A thin-walled sphere of 2m mean diameter with a wall thickness of100mm is subjected to an internal pressure of 10MPa. Biaxialcircumferential stresses are developed and calculated by σ 1 = σ 2 =pd/(4t), where d is the mean diameter and t the thickness. Neglectingthe radial stress, calculate the ratio of the von-Mises stress over themaximum shear stress.

Answer:

B a lever because it can move up and down

Explanation:

Answer:

[tex]\eta =46\%[/tex]

Explanation:

Hello!

In this case, we compute the heat output from coal, given its heating value and the mass flow:

[tex]Q_H=60\frac{tons}{h}*\frac{1000kg}{1ton}*\frac{1h}{3600s}*\frac{30,000kJ}{kg}\\\\Q_H=500,000\frac{kJ}{s}*\frac{1MJ}{1000J} =500MW[/tex]

Next, since the work done by the power plant is 230 MW, we compute the efficiency as shown below:

[tex]\eta =\frac{230MW}{500MW}*100\% \\\\\eta =46\%[/tex]

Best regards!

Answer:

The difference lies in the coverage of the construction.  While local level construction focuses on the local area, national level construction has a nation-wide coverage.

Explanation:

Residential construction concentrates on the construction of residential buildings that have sleeping accommodations.  Such constructions are opposed to the construction of other buildings that are meant for commercial uses as they lack sleeping accommodations.  The federal, state, and local governments can embark on the construction of residential quarters for their residents.  The constructions are also funded at the given level.  When it is locally funded, the construction is meant to satisfy specific local needs.  The constructions by the federal government consider the needs of many localities, and may not meet specific local needs.

Answer: A Residential construction is local in its effects even though those effects have a national impact.

Explanation:

Answer:

Following are the solution to this question:

Explanation:

Whenever a chemical reaction occurs between water and cement the heat is released, and a [tex]CaOSiO_2H_2O[/tex] (C-S-H gel) gel constructs gel is also recognized as "tobermorite gel."

This one gel acts like a pack of gum and also has a cement quality, that holds its particles intact and therefore contributes to the overall compression mix. An increase in supply explicitly causes the movement in the outcome of power. C3S and C2S are both the compounds of Bouge that produce hydration C-S-H gel.

It mixture must be balanced as [tex]Ca(OH)_2[/tex] with C-S-H gel also is given as a byproduct. It [tex]Ca(OH)_2[/tex] , that cause sudden with sulphate and form [tex]CaSO_4[/tex] , is an unacceptable substance. Sulfate attack or later deterioration of its cement is caused by this [tex]CaSO_4[/tex] .

All C3S and C2S generate various amounts of C-S-H gel so, the required strength can be maintained without compromising on real term durability.

Explanation:

Think of brushes as a sliding contact.

In an alternator the brushes provide power to the field coil which is physically mounted on the rotating shaft. They provide this direct current through two slip rings.

By controlling the power flow to the field, the power output of the alternator can be controlled. A regulator circuit is used to control the field so that the output voltage is maintained to about 13.5 to 14.5 VDC.

FUN FACT: Many brush holders have a small holes near the brush exit. When you assemble the alternator you physically push the brushes all the way into their holder and then thread a small wire through these hole. After the alternator is assembled you can pull the wire out and the brushes will snap into position.

Answer:

6:00 pm the next day

Explanation:

Given that

Tahir traveled twice as far as Ahmed. We say,

Ahmed traveled a distance, D

Tahir would travel a distan, 2D

Tahir traveled 1/3 as fast as Ahmed, so we say

Ahmed traveled at a speed, S

Tahir would travel at a speed, S/3

If Ahmed starts travel on tuesday at noon at point x to point z 300km, by 9:00pm,

Time taken by Ahmed to travel is

9:00 pm - 12:00 pm = 9 hours

Ahmed, traveled 300 km in 9 hours, meaning he traveled at 33.3 km in an hour.

Speed, S that Ahmed traveled with is 33.3 km/h

Remember, we stated that Tahir travels at a speed of S/3, that is, The speed of Tahir is

33.3/3 = 11.1 km/h.

300 km would then be traveled in 300 km/11.1 km/h = 27 hours.

Tahir started traveling, 3 hours after Ahmed, that is 12:00 pm + 3:00 hrs = 3:00 pm, and if he's to spend 27 hours on the journey he would reach destination z at 6:00 pm the next day

Answer:

AI 7075

Explanation:

Material                Density g/cc         Yield strength      

AI 7075                   2.81                         503

AISI 4340/SAE       7.85                         1160

Mg-ZK61                 1.83                          195

Ti8A|1Mo1V             4.37                         570

Determine the alloy with the lightest weight using this relationship

weight ∝  ( S / E )

E = yield strength

S = density

from the above calculation the alloy with the lightest weight is ;

AI 7075

Answer:

The answer is "909.3928  KJ".

Explanation:

[tex]70 \ kPa \ \ and \ \ 100^{\circ}C \\\\s_i= 7.56162\ \frac{kJ}{kgK}\\\\u_i= 2509.39 \ \frac{kJ}{kg}\\\\[/tex]

The method is isentropic since the cylinders are shielded.

Calculating the work:

[tex]w= u_2-u_i \\\\[/tex]

   [tex]= 3418.7728-2509.38 \\\\=909.3928 \ KJ[/tex]

The final temperature of the water is 676.164 °C and the specific work required is 1171.384 kilojoules per kilogram.

Let suppose that compression occurs quasi-statically, work is done on the closed system and enthalpy is increased. By First Law of Thermodynamics, we model compression process as following:

[tex]W_{in} + (U_{1} - U_{2}) + (P_{1}\cdot V_{1} - P_{2}\cdot V_{2}) = 0[/tex] (1)

Where:

By definition of enthalpy, in kilojoules per kilogram, and by dividing the resulting expression by the mass of the entire system, we have the following expression:

[tex]w_{in} = h_{2}-h_{1}[/tex] (2)

Where:

From steam tables we find that initial and final states of the water are represented by the following data:

Initial state

[tex]P = 70\,kPa[/tex], [tex]T = 100\,^{\circ}C[/tex], [tex]h = 2679.76\,\frac{kJ}{kg}[/tex], [tex]s = 7.56162\,\frac{kJ}{kg\cdot K}[/tex] (Superheated steam)

Final state

[tex]P = 4000\,kPa[/tex], [tex]T = 676.164\,^{\circ}C[/tex], [tex]h = 3851.144\,\frac{kJ}{kg}[/tex], [tex]s = 7.56162\,\frac{kJ}{kg}[/tex] (Superheated steam)

By (1) we have that the specific work required is:

[tex]w_{in} = 3851.144\,\frac{kJ}{kg} - 2679.76\,\frac{kJ}{kg}[/tex]

[tex]w_{in} = 1171.384\,\frac{kJ}{kg}[/tex]

The final temperature of the water is 676.164 °C and the specific work required is 1171.384 kilojoules per kilogram.

To learn more on closed systems, we kindly invite to check this verified question: https://brainly.com/question/3690180

Answer:

option  C

Explanation:

The correct statement is As specific ions form a film on the metal surface, hence those ions which form films may be adequate to cause SCC

other options are wrong as ; specific ions are not necessary for metals and alloys and also an environment causing SCC for an alloy might not cause SCC of another alloy found in the environment

Answer:

Explanation:

Step one:

given data

from the table  for R-134a

For the given pressure state the following data were extracted.

s=0.94202kJ/kg.K

h1=241.14kJ/kg

∝1=0.12355m^3/kg

By interpolation, the final enthalpy and pressure with data from the table of  R-134a

h2=277.12kJ/kg

The minimum power output is then determined from the energy balance

W=m(h2-h1)

W=V1/∝1(h2-h1)

W=2.4/60/0.12355(277.12-241.14)

W=0.04/0.12355(35.98)

W=0.3237(35.98)

W=11.65kW Approx.

The minimum power output of the compressor is 11.65kW

Answer:

The answer is "[tex]\bold{1.32 \times 10^{-3} \ cm}[/tex]".

Explanation:

All of the atoms in a BCC crystalline structure are contained in the 8-corner unit cell.  

Each corner connects the atom to a single cell [tex]\frac{1}{8}[/tex]  

Therefore, the unit cell number of atoms:  

[tex]= 8 \times \frac{1}{8}+ 1 \\\\= 1+1 \\\\= 2 \ atom[/tex]

[tex]The mass unit cell = \frac{ \text{Number of atoms} \times \text{atomic weight}} {Avagadro number}\\\\= \frac{2 \times 50.9}{6.023 \times 10^{23}}  \\\\= 1.69 \times 10^{-22} \ g\\\\Area Of the atom= \frac{4r}{\sqrt{3}}\\\\   5.96 = \frac{1.69 \times 10^{-22}}{volume}\\\\volume= 2.835 \times 10^{25}\\\\v=d^3\\\\v= (\frac{4r}{\sqrt{3}})^3\\\\\to 2.835 \times 10^{-23} \times (\sqrt{3})^3 = 4^3 r^3[/tex]  

[tex]\to \sqrt[3]{\frac{{2.835 \times 10^{-23} \times (\sqrt{3})^3}}{4^3}} =r\\\\\to r= 1.32 \times 10^{-3} \ cm[/tex]

Answer:

C

Explanation:

Answer:

A civil engineering degree program applies mathematics and physical science to solve specific, real-world problems in commerce and industry. A strong civil engineering program typically emphasizes the practical use of geometry, trigonometry, and calculus in conjunction with physics, material science, and chemistry.

Explanation:

Hope this helps!! Please consider marking brainliest! Have a good one!!

Answer:

Stages of Interpretation and Mapping

Selection of photographs. Whenever possible, all photographs of a site or small area should be assessed for fitness of purpose. ...

Control points. A good spread of control points on a photograph is vital to establish the exact location or size of features. ...

Transformation.

Explanation:

Answer:

d. 41.4

Explanation:

The initial diameter di = 100mm

The initial height hi {✓59m

Final height = 25 m

Final diameter = ?

Initial volume = after forging volume

D*(di)²*hi = D *(df)²*hf

D will cancel out from either sides of the equation

100² x 50 = df²x25

10000x2 = df²

20000 = df²

df = √20000

df = 141.42mm

Change in diameter = 141.42-100

= 41.42

The percentage change = 41.42/100*100

= 41.4%

The last option is the answer

Answer:c

Explanation:

Answer:

c thereeeeeeeeeeeeeeeeee

Answer:

2376 vph

Explanation:

Given data

free flow speed ( Vf ) = 45 mph

Jam density = 25 ft per vehicle

flow rate = 1950 vph

first we calculate the Jam density in vehicle /mile

= 5280 / 25 = 211.2 vehicle/mile

where ; 1 mile = 5280 feet

The maximum flow can be calculated using Greenshield method

q = ( Vf * jam density ) / 4  =  ( 45 * 211.2 ) / 4

  = 2376 vph

Answer: d. [tex]v(t)=(1-5t)e^{-5t}[/tex]V

Explanation: Inductance is a property of an inductor: when there is a change in current passing through a conductor, it creates a voltage in the conductor itself and in the other conductors. Inductance unit is Ω.s or henry (H)

So, the relation between Voltage and Current in an inductor is given by

[tex]v=L\frac{di}{dt}[/tex]

in which

L is inductance in H

i is current in A

Current is [tex]i(t)=10te^{-5t}[/tex], so, derivative will be:

[tex]\frac{di}{dt}=10e^{-5t}+10t(-5)e^{-5t}[/tex]

[tex]\frac{di}{dt}=10e^{-5t}-50te^{-5t}[/tex]

[tex]\frac{di}{dt}=10e^{-5t}(1-5t)[/tex]

Then, voltage is

[tex]v=0.1.10.e^{-5t}(1-5t)[/tex]

[tex]v=(1-5t)e^{-5t}[/tex]

Voltage across the 0.1H inductor is [tex](1-5t)e^{-5t}[/tex] V

Answer:

Impeller diameter should be 0.02 meter

Explanation:

The Impeller diameter is a parameter with a circular design of a high speed pump. The performance of the pump depends on this parameter.

As per the given data

Speed of pump = 3,560 rpm

Rate of water flow = 500 gpm = 0.0005 m^3/minutes

Size of head = 250 ft = 250 ft x 0.3048 m/ft = 76.2 m

The impeller diameter can be calculated using following formula

Impeller diameter =0.1 x  [tex]\sqrt{Water flow rate X 60}[/tex]

Impeller diameter =0.1 x  [tex]\sqrt{0.0005 X 60}[/tex]

Impeller diameter =0.1 x  [tex]\sqrt{0.03}[/tex]

Impeller diameter = 0.1 x 0.1732

Impeller diameter = 0.01732

Impeller diameter = 0.02 m

Prefix Symbol Multiplier Exponential

yotta Y 1,000,000,000,000,000,000,000,000 1024

zetta Z 1,000,000,000,000,000,000,000 1021

exa E 1,000,000,000,000,000,000 1018

peta P 1,000,000,000,000,000 1015

tera T 1,000,000,000,000 1012

giga G 1,000,000,000 109

mega M 1,000,000 106

kilo k 1,000 103

hecto h 100 102

deca da 10 101

1 100

deci d 0.1 10¯1

centi c 0.01 10¯2

milli m 0.001 10¯3

micro µ 0.000001 10¯6

nano n 0.000000001 10¯9

pico p 0.000000000001 10¯12

femto f 0.000000000000001 10¯15

atto a 0.000000000000000001 10¯18

zepto z 0.000000000000000000001 10¯21

yocto y 0.000000000000000000000001 10¯24

Answer:

c. 0.18

Explanation:

The Formula for Froude Number is given as follows:

Froude No. = Inertial Forces/Gravity Forces

Froude No. = v/√(gD)

where,

v = velocity = 1 m/s

g = 9.8 m/s²

D = Depth of channel = 3 m

Therefore,

Froude No. = (1 m/s)/√[(9.8 m/s²)(3 m)]

Froude No. = 0.18

hence, the correct option will be:

c. 0.18

Answer:

a) 764.45K

b) 210.48 kJ/kg

c) 30.14%

Explanation:

pressure ratio = 10

minimum temperature = 295 k

maximum temperature = 1240 k

isentropic efficiency for compressor = 83%

Isentropic efficiency for turbine = 87%

a) Air temperature at turbine exit

we can achieve this by interpolating for enthalpy

h4 = 783.05 kJ/kg ( calculated in the background ) at state 4 using Table A-17  for  Ideal gas properties of air

T4 ( temperature at Turbine exit ) = 760 + ( 780 - 760 ) [tex](\frac{783.05-778.18}{800.13-778.18} )[/tex] = 764.45K

b) The net work output

first we determine the actual work input to compressor

Wc = h2 - h1  ( calculated values )

     = 626.57 - 295.17 =  331.4 kJ/kg

next determine the actual work done by Turbine

Wt = h3 - h4  ( calculated values )

     = 1324.93 - 783.05 = 541.88 kJ/kg

finally determine the network output of the cycle

Wnet = Wt - Wc

         = 541.88 - 331.4  = 210.48 kJ/kg

c) determine thermal efficiency

лth = Wnet / qin  ------ ( 1 )

where ; qin = h3 - h2

equation 1 becomes

лth = Wnet / ( h3 - h2 )

      = 210.48 / ( 1324.93 - 626.57 )

      = 0.3014  =  30.14%

Answer:

A. Juna's answer is correct because both the number of feet and the number of inches are correct

Explanation:

Answer:

Wood is heavy

Explanation:

Answer:

0.124

Explanation:

We calculate the hydraulic gradient by the formulas below.

I = (change in h)/(change in l)-----eqn 1

I = (hk-hl)/change in L ----- equation 2

At k the headloss = hk,

At L the headloss = hL

The distance of water travel is change in I

Total head at k

hk = 543+23

= 566 ft

Total head at L

hL = 461+74

= 535 ft

Change in L = 250

When we substitute these values in equation 2

566-535/250

= 0.124

The hydraulic gradient is 0.124

Answer:

3 m/s²

Explanation:

Acceleration is calculated as :

a= Δv/ t

where ;

Δv = change in velocity

Δv = 45 - 0 = 45  m/s

t= 15 s

a= 45 /15

a= 3 m/s²

Answer:

Explanation:

This is not a question so to say. This is more like a complaint about how the platform works. Are you needing help with solving a personal problem or having troubles with the platform in itself

/~\ The correct answer is:

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

B. A demand for unique features.

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

I hope this helps! /~\

Answer:

A. A reliance on mass production of necessary parts.

Explanation:

Took the test