Answer:
what is heat and transfer
Three different scientific institutions provide data about how much the annual global temperature has deviated from the norm in the years 1880 to 2014. The nort is
based on the temperatures of a base period, from 1951 to 1980
Institution A's data show that the annual global temperature deviated from the norm by 0.75°C in 2010
Institution B's data show that the annual global temperature deviated from the norm by 0.72°C in 2010
Institution C's data show that the annual global temperature deviated from the norm by 0.77°C in 2010.
Which are accurate statements about this data? Select the two correct answers
(1 point)
Based on the findings above, the accurate statements are:
B. The institutions have not yet gathered enough data for scientists to draw a conclusion about whether the annual global temperature is gradually increasing.C. The data gathered by each institution is very similar to the data gathered by the other institutions.What are the accurate statements?The information that all three institutions gathered is quite similar with their results showing a range of annual temperature deviation of 0.05°C in 2010.
However, this data is not enough to say that temperatures are rising gradually because there is no information on temperatures from the previous years.
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The jet engine of an airplane expels hot gas.
A. The airplane is propelled in the same direction as the hot gas.
B. The airplane is propelled in the opposite direction as the hot gas.
C. The airplane is propelled against the outside air.
Answer:
B. The airplane is propelled in the opposite direction as the hot gas.
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How far back into the universe are we able to see? Explain.
Answer:
About 46 billion light years Because space expands so what we didn’t see before is what we could see now. An example could be how everyone thought Pluto was a regular sized planet but once you get a look at the bigger picture and compare it to other thing in space we now know Pluto is a dwarf planet.
The centripetal force is proportional to the _____. mass velocity squared inverse of the radius All of the above
Answer:
Velocity squared.
Explanation:
We know that,
[tex]\text{F}_{\text{Centripetal}} = \dfrac{mv^2}{r}, \text{which implies} ~\text{F}_{\text{Centripetal}} \propto v^2[/tex]
What is the absolute error expression of this ?
Answer:
n=(A+B)+k4
Explanation:
because if u add all the things to it u will get that
You are an astronaut floating in DEEP space (very little gravity). If you come upon a small metal object,
what can you do to test if the object has MORE or LESS mass than you? What would happen? Explain
Momentum questions help
Answer:
a=25000 kg•m/s
b=1200 kg•m/s
c=what force?
Explanation:
for question a you multiply the mass which is 1000kg with velocity 25m/s.
for question b you multiply the force 60n with time 20s
A light bulb operating at a dc voltage of 120 V has a power rating of 60 W. How much current is flowing through this bulb
[tex]\\ \rm\rightarrowtail I=\dfrac{P}{V}=\dfrac{60}{120}=\dfrac{1}{2}=0.5A[/tex]
Suppose that a car speaker produces sound waves with a frequency of 4000 Hz. As the car speaker moves away from an observer, which of the
following occurs?
Frequency is reduced with the sound waves being less heard when the speaker moves away from an observer.
What is Frequency?
This is defined as the number of occurrences of a repeating event per unit of time.
As the speaker is moved away from the observer, the wavelength increases and the frequency decreases thereby resulting in less sound being heard.
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A stage has a radius R = 2.00 m and a mass M = 100 kg. The stage, which has a circular disk
shape, rotates in a horizontal plane, without any friction, about a vertical axle. Sandra has a
mass of m = 60.0 kg and she walks from the rim of the stage toward the center. Calculate the
angular speed when she reaches a point r = 0.500 m from the center, if the angular speed of the
system is 2.0 rad/s when Sandra is at the rim
i want the answer of this exercise
2. What value did you calculate for the index of refraction of the acrylic block in Part 2? How does your value compare to the accepted value of 1.50? Calculate the percentage error. Different materials have distinct indexes of refraction. Explain how you might identify a material based on experiments like this one. Mention at least one of the difficulties in identifying materials based on their indexes of refraction.
The percentage error in calculated value of the refractive index of acrylic block is calculated using the formula: (true value - calculated value/true value) × 100%.
What is refractive index of a refracting medium?The refractive index of a medium is the ratio of the sine of the angle of incidence on the medium and the sine of the angle of refraction.
Refractive index = sin i/sin rwhere;
i is the angle of incidencer is angle of refraction.The refractive index of a medium increases with density of the medium.
To determine the percentage error in determining the refractive index of a medium, the following formula is used:
Percent error = error/true value × 100%Therefore, the percentage error in calculated value of the refractive index of acrylic block is the ratio of the error and true value multiplied by 100%.
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A __________is a large cool star located in the top right of the HR diagram.
Answer:
Vermeer star is located at the top of large Venus
What is an analogy of two different roads or rivers to compare a series and parallel circuit?
Answer:
In a series circuit, the same amount of current flows through all the components placed in it. On the other hand, in parallel circuits, the components are placed in parallel with each other due to which the circuit splits the current flow.
An athlete lifts a 330 N set of weights from ground level to a position over her head, a vertical distance of 2.05 m. Assume the weights are moved at constant speed. a) How much work does the athlete do? b) What is the mass of the weights?
Work done:-
Force×Displacement330(2.05)676.5JNow
Apply Newtons second law
F=mam is mass
a is acceleration due to gravity (10)
330=10mm=33kgwhat are the milestones of modern phyiscs?
Answer:
The articles appearing under "Milestones in Physics" will give an insight into special events or situations that have been decisive for the evolution of Physics
Answer:
We have invented many new ways to get energy, especially renewable means of energy, and we have made many new carbon-neutral devices more widespread and cheaper.
Modern physics milestones are getting harder and harder to get because almost every element has been discovered, many gaseous and liquid substances have been experimented with and dozens of other mid 20th century discoveries.
CAN SOMEONE PLS HELP ME!!!
Answer:
c
Explanation:
the question answered itself.
a diamond sparkles more than a glass cut to similar shapes,why?
Answer:
because when you shape glass it's not a shiny as diamond
How many times does the light beam shown in FIGURE 26-59 reflect from (a) the top and (b) the bottom mirror?
Answer:
5
Explanation:
I’m sorry, but the person you are calling has a voice mailbox that has not been set up yet.
Please try again later.
Bye Bye!
Answer:
bye bye
Explanation:
Answer: Or please call again to see if they reached the phone yet.
Explanation: It always stops ringing right before someone gets to there phone so call again in 2 minutes. :3
The weight of your science book presses on the desk.
A. Gravity pulls on the book.
B. Gravity pulls on the desk.
C. The desk pushes on the book.
Answer:
A. Gravity pulls on the book :)
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Two people of equal mass attempt a tug-of-war with a 10 m long rope
while standing on ice. On pulling the rope, they both slide towards
each other. What will be the acceleration for each person?
Answer:
Explanation:
As the poster has noted above in comment, the acceleration for each person will be the same. This is because when they tugon the rope, there will be tension force on the rope pulling the two persons towards each other. The tension force will be the same for them. As they also have equal mass, by Newton's Second Law of Motion, Force = mass * acceleration, their acceleration will be the same.
1. Greek scientist called Archimedes was asked to check the purity of the gold in a crown. He did this by comparing the density of the crown with the density of pure gold.
a) Describe how he could have measured the density of an irregular shaped object as a crown.
Answer:
Suppose Archimedes weighed the crown (we'll say 2700 grams)
Then he put the crown on a string and weighed the crown in water and found its weight to be 2560 g.
That means that an equivalent volume of water weighed
2700 - 2560 = 140 grams
Then the density of the crown is 2700 / 140 = 19.3
So this is the density of pure gold and the crown could be considered to be made of pure gold with no other metals in its composition.
Archimedes weighed the crown, then suspended it on a rope and measured the volume of water it displaced in order to determine its weight, then he calculated the density of the crown and compared it with the density of the pure gold.
What is density?It can be defined as the mass of any object or body per unit volume of the particular object or body. Generally, it is expressed as in gram per cm³ or kilogram per meter³.
As given in the problem statement Greek scientist called Archimedes was asked to check the purity of the gold in a crown. He did this by comparing the density of the crown with the density of pure gold.
Archimedes weighed the crown, then suspended it on a rope and measured the volume of water it displaced in order to determine its weight.
Thus, he could have measured the density of an irregularly shaped object as a crown.
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Fill in the blank with the correct response.
Light striking a mirror at a 45° angle will be reflected at a
PLEASE HELP!! A TOTAL OF 50 POINTS WHEN GIVEN BRAINLIEST!!
Part A: Find the work done in lifting 1 L of blood (mass 1 kg ) from the foot to the head of a 1.9 m -tall person.
Part B: If blood circulates through the body at the rate of 5.0 L/min , estimate the heart's power output. (Your answer underestimates the power by a factor of about 5 because it neglects fluid friction and other factors.)
Explanation:
for part A:
work done is equal to change in potential energy which is
MgH
so the answer is 1.9 × 1 × 9.81
ANSWER FOR PART A: 18.639
FOR PART B:
power = flow rate x gh
= 5×9.81×1.9
93.195 watts
When a force is applied to a wheel, its axle exerts a greater force?
Answer:
That is true.
Explanation:
When the input force is applied to the wheel, as it is with a doorknob, the axle turns over a shorter distance but with greater force, so the mechanical advantage is greater than 1.
acar start from rest and go with velocity of 4m/s for 4second what is acceleration of car
Answer:
1 m/s^2
Explanation:
The formula for accleration is a=Δv/Δt
where, Δv = final velocity - initial velocity = 4 - 0 = 4
initial velocity = 0 since the car starts form rest and final velovity is 4 as the car goes from rest till 4 m/s
Δt = 4 since the car takes 4 seconds to reach a velocity of 4m/s
Hence, a = 4 m/s / 4 s = 1 m/s^2
Answer:
1m/s
Explanation:
Given
initial velocity(u)=0
final velocity(v)=4m/s
timetaken (t)=4
Aceleration(a)=v-u÷t
now
=4-0÷4
=1m/s
she incorrect? Select all that apply.
because electromagnetic waves can only travel in gases
А
B
because electromagnetic waves can only travel through solids
С
because electromagnetic waves only come from the Sun
D
because electromagnetic waves are not created using force on a medium
m
because electromagnetic waves are created using accelerating charges
F
because electromagnetic waves require a medium to travel
electromagnetic waves can travel not only through air and solid materials, but also through the vacuum of space.
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A negatively charged plastic comb is brought close to, but does not touch, a small piece of paper. If the comb and the paper are attracted to each other the charge on the paper
A) must be negative
B) may be positive or neutral
C) may be negative or neutral D)must be positive
If the comb and the paper are attracted to each other the charge on the paper, is D)must be positive
Laws of electrical attraction
This states that
Like charges attract Unlike charges repelNow, given that a negatively charged plastic comb is brought close to, but does not touch, a small piece of paper. If the comb and the paper are attracted to each other the charge on the paper, this implies that both the negatively charged plastic comb and the paper have opposite charges.
Since the charge on the plastic comb is negative, this means that the charge on the paper must be positive
So, if the comb and the paper are attracted to each other the charge on the paper, is D)must be positive
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A capacitor of cylindrical shape as shown in the red outline, few cm long carries a uniformly distributed charge of 7.2 uC per meter of length. By constructing a suitable Gaussian surface around the wire, Find the magnitude and direction of the electric field at points (a) 5.5 m and (b) 2.5 m perpendicular from the center of the wire. Show your detailed calculations and comment on the results.
Hi there!
Begin by using Gauss' Law to find the electric field.
[tex]\oint {E \cdot} \, dA = \frac{Q_{encl}}{\epsilon_0}[/tex]
E = Electric field (N/C)
dA = differential area element
Q = enclosed charge (C)
ε₀ = Permittivity of free space (8.85 * 10⁻¹² C²/Nm²)
We can construct a large cylinder around the wire in order to determine the electric flux. The electric field lines will pass through the LATERAL surface area of the cylinder, so:
[tex]A = 2\pi rL[/tex]
Where 'L' is the length of the cylinder and 'r' is the distance from the capacitor.
The enclosed charge is equivalent to the charge per meter length (λ) multiplied by the length, so:
[tex]\oint {E \cdot} \, dA = \frac{\lambda L}{\epsilon_0}[/tex]
We can rewrite the dot product as EA (where cosθ = 1 since the normal vector points in the direction of the field).
A = the lateral surface area of a cylinder, so:
[tex]E * 2\pi rL = \frac{\lambda L}{\epsilon_0}[/tex]
Rearrange to solve for 'E'.
[tex]E = \frac{\lambda L }{2\pi r L \epsilon _0}\\\\E = \frac{\lambda }{2\pi r \epsilon_0}[/tex]
a)
Plug in the distance into 'r'.
[tex]E = \frac{\lambda }{2\pi r \epsilon_0} \\\\E = \frac{0.0000072}{2\pi * 5.5 * (8.85 * 10^{-12})} = \boxed{23542.18 \frac{N}{C}}[/tex]
b)
Repeat:
[tex]E = \frac{\lambda }{2\pi r \epsilon_0}\\\\E = \frac{0.0000072}{2\pi * 2.5 * (8.85 * 10^{-12})} = \boxed{51792.8 \frac{N}{C}}[/tex]
We can see that the distance from the wire is INVERSELY related to the electric field strength by a power of r⁻¹. The field strength DECREASES as the distance INCREASES.
Two particles are 15 meters apart.
Particle A has a charge of 6.0*10^-4 C
Particle B has a charge of 5.0*10^-4 C.
The resulting Coulomb force is 12 N. At the same distance, what combination of charges would yield the same Coulomb force?
A. Particle A: 8.0*10^-4 C, and Particle B: 3.0*10^-4 C
B. Particle A: 12.0*10^-4 C, and Particle B: 2.5*10^-4 C
C. Particle A: 9.0*10^-4 C, and Particle B: 8.0*10^-4 C
D. Particle A: 9.0*10^-4 C, and Particle B: 3.0*10^-4 C
Considering the Coulomb's Law, the combination of particle A: 12.0×10⁻⁴ C and particle B: 2.5×10⁻⁴ C would yield the same Coulomb force of 12 N.
Coulomb's LawCharged bodies experience a force of attraction or repulsion on approach.
From Coulomb's Law it is possible to predict what the electrostatic force of attraction or repulsion between two particles will be according to their electric charge and the distance between them.
From Coulomb's Law, the electric force with which two point charges at rest attract or repel each other is directly proportional to the product of the magnitude of both charges and inversely proportional to the square of the distance that separates them:
[tex]F=k\frac{Qq}{d^{2} }[/tex]
where:
F is the electrical force of attraction or repulsion. It is measured in Newtons (N).Q and q are the values of the two point charges. They are measured in Coulombs (C).d is the value of the distance that separates them. It is measured in meters (m).K is a constant of proportionality called the Coulomb's law constant. It depends on the medium in which the charges are located. Specifically for vacuum k is approximately 9×10⁹ [tex]\frac{Nm^{2} }{C^{2} }[/tex].The force is attractive if the charges are of opposite sign and repulsive if they are of the same sign.
This caseIn this case, you know that two particles are 15 meters apart and the resulting Coulomb force is 12 N.
On the other side, you know:
Particle A: 8.0×10⁻⁴ C, and Particle B: 3.0×10⁻⁴ CParticle A: 12.0×10⁻⁴ C, and Particle B: 2.5×10⁻⁴ CParticle A: 9.0×10⁻⁴ C, and Particle B: 8.0×10⁻⁴ CParticle A: 9.0×10⁻⁴ C, and Particle B: 3.0×10⁻⁴ CReplacing in the Coulomb's Law, you get:
[tex]F=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{(8x10^{-4}C) (3x10^{-4} C )}{(15 m)^{2} }[/tex] → F= 9.6 N[tex]F=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{(12x10^{-4}C) (2.5x10^{-4} C )}{(15 m)^{2} }[/tex] → F= 12 N[tex]F=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{(9x10^{-4}C) (8x10^{-4} C )}{(15 m)^{2} }[/tex] → F= 28.8 N[tex]F=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{(9x10^{-4}C) (3x10^{-4} C )}{(15 m)^{2} }[/tex] → F=10.8 NFinally, the combination of particle A: 12.0×10⁻⁴ C and particle B: 2.5×10⁻⁴ C would yield the same Coulomb force of 12 N.
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