Answer:
C). Ball B transfers energy to Ball A
Explanation:
The motion of ball A is a because of the energy it acquires.
Ball A initially due to its position posses potential energy due to its position.
The moving ball B has kinetic energy due to the motion of this ball.
Due to the collision, momentum is transferred from the moving ball to the static one. As the momentum of the static ball changes, potential energy is converted to kinetic energy. The magnitude of the energy possessed by the static ball must be lesser than that of the moving.Answer:
c
Explanation:
What is the oxidation number for S in the compound SO3? (Recall that o has an oxidation number of -2.)
0
O +2
O +4
O +6
The oxidation number for S in the compound SO₃ : +6
Further explanationThe formula for determining Oxidation Numbers :
1. Single element atomic oxidation number = 0.
Group IA (Li, Na, K, Rb, Cs, and Fr): +1
Group IIA (Be, Mg, Ca, Sr and Ba): +2
H in compound = +1, except metal hydride compounds (Hydrogen which binds to groups IA or IIA) oxidation number H = -1, for example, LiH, MgH₂, etc.
2. Oxidation number O in compound = -2, except OF₂ = + 2 and in peroxide (Na₂O₂, BaO₂) = -1 and superoxide, for example KO₂ = -1/2.
3 The oxidation number in an uncharged compound = 0,
Total oxidation number in ion = ion charge, Example NO₃⁻ = -1
The oxidation number for S in SO₃ :
[tex]\tt oxidation~number~of~S+3\times oxidation~number~of~O=0\\\\oxidaton~number~of~S+3\times(-2)=0\\\\oxidation~number~of~S=+6[/tex]
balance by oxidation number method<br />KMnO4 + Na2O₂ + H2 so4 ko2so4 +<br />Mosou4 + Na2so<br />4 + O2 + H₂O
Answer:
8H2SO4 + 2KMnO4 + 5Na2O2 => 8H2O + 2MnSO4 + 5Na2SO4 + 5O2 + K2SO4
have:
Explanation:
describe manganese as oxidizing agent
Answer:
See explanation
Explanation:
A reducing agent in chemistry is any substance that accepts electrons and its oxidation number is decreased in a redox reaction.
Manganese occurs in a variety of oxidation states; +7, +6, +5, +4, +3, +2. This makes it an exceptionally good reducing agent since it can accept different number of electrons and change from one oxidation state to another.
The commonest compound of manganese used as a strong oxidizing agent is KMnO4 in which manganese has an oxidation number of +7.
If the enantiomeric excess of a mixture is 81 %, what are the percent compositions of the major and minor enantiomer?
Answer:
major enantiomer = 90.5 %
minor enantiomer = 9.5 %
Explanation:
Assuming that the major isomer is in excess;
From, ee/2 + 50
ee = enantiomeric excess = 81%
% major =81/2 + 50 = 90.5 %
% minor = 100% - 90.5 %
% minor = 9.5 %
Which two things are produced when a plant breaks down sugar to release energy
Answer:
Glucose is combined with oxygen and releases usable energy, carbon dioxide, and water. Cells can use that extra energy to power their functions. The energy isn't just floating around. It's stored in an excitable compound called ATP (adenosine triphosphate).
Explanation:
Answer: ATP(adenosine triphosohate) is released with water and carbon dioxide as byproducts.
Explanation: Remember that water, CO2,and ATP are the products of cellular respiration.
How do fossils provide evidence that evolution has happened on Earth?
Answer:
i dunno
Explanation:
Answer:
Explanation:
Evidence for early forms of life comes from fossils. By studying fossils, scientists can learn how much (or how little) organisms have changed as life developed on Earth. There are gaps in the fossil record because many early forms of life were soft-bodied, which means that they have left few traces behind.
Acetylene gas is often used in welding torches because of the very high heat produced when it reacts with oxygen O2 gas, producing carbon dioxide gas and water vapor. Calculate the moles of oxygen needed to produce 1.3mol of carbon dioxide. Be sure your answer has a unit symbol, if necessary, and round it to 2 significant digits.
Answer:
3.2 moles of carbon dioxide
Explanation:
When C₂H₂ reacts with O₂ the chemical reaction is:
C₂H₂ + 5/2O₂ → 2CO₂ + H₂O
Where 1 mole of acetylene produce 2 moles of carbon dioxide.
Based on the chemical equation of this reaction, there are produced twice the moles of acetylene in moles of carbon dioxide assuming a compete reaction.
If 1.6 moles of acetylene reacts there are produced:
1.6 moles Acetylene * (2 moles Carbon Dioxide / 1 mole Acetylene) =
3.2 moles of carbon dioxide
compound
element + element
1:Synthesis
2:Decomposition
3:Single Replacement
4:Double Replacement
5:Combustion
Answer:
4
Explanation:
Because of single replacement the ideal shape comes in form
Valence electrons are determined by the...
a. highest occupied energy level and Group Number. I
b. highest occupied energy level and Group Number - 8.
Explanation:
A) Highest occupied energy level and Group Number.
Which term refers to the process by which land is worn away by natural forces or human activity?
Answer:
erosion
Explanation:
erosion is the term that refers to the process by which land is worn away by natural forces or human activity.
Answer:
Erosion
Explanation:
Just took the test, hope it helps!
Which of the following aqueous solutions
would conduct electricity?
Electroyte and Vonvlectrolyte Solution
Answer:
H2CO
Explanation:
How many moles are in 347 grams of HBr
Answer:
4.289 mol
Explanation:
Given that the molar mass of HBr (known as Hydrobromic Acid or Hydrogen Bromide) has a molar mass of 80.91 g/mol.
To find the number of moles, we have the formula
(Grams of the substance ÷ moles of the substance) * (molar mass of the substance in grams ÷ one mol)
Here the Grams of the substance = 347grams,
Moles of the substance =?
Molar mass of the substance = 80.91 g/mol
By cross multiplying, we have
347 grams * 1 mol = Z * (80.91)
Z = 347 grams ÷ 80.91g/mol
Z = 4.289 mol
how much is a dogggggggggggggggggg
Answer:
it is 7
Explanation:
dogs are 7 HOPE THIS HELPED kidding i don get the question
Explanation:
DON"T EAT MY DOG OR I"LL EAT YOU
You better watch outYou better not cryYou better not poutCHEMISTRY HELP!
Can anyone help me understand or explain why my answer was wrong and why the correct answer is right? Please help!
Answer:
Li to Zn2+
Explanation:
Because oxidation number of Li changes from 0 to 2+ it means that Li has lost two electrons and oxidation number of Zn2+ changes to Zn which means Zn received two electrons.
Plz solve
A 20-g sample of sugar is dissolved in 59 g of water. The concentration of the solution is
Hint Water is a solvent
Answer:
0.98 M
Explanation:
Given data:
Mass of sugar = 20 g
Mass of water = 59 g
Concentration of solution = ?
Solution:
1 g = 0.01 L
59 g× 0.01 L/1 g
0.059 L
Concentration formula:
C = m/v
m = moles of solute
v = volume of solution
Number of moles of sugar:
Number of moles = mass/molar mass
Number of moles = 20 g/ 342.3 g/mol
Number of moles = 0.058 mol
Now we will calculate the concentration:
C = 0.058 mol/0.059 L
C = 0.98 mol/L
C = 0.98 M
List the symbol and the bonding capacity of the 4 most common elements found in
organic compounds.
Answer:
The four elements most commonly found in living things are carbon, nitrogen, hydrogen, and oxygen.
Explanation:
The four elements most commonly found in living things are carbon, nitrogen, hydrogen, and oxygen.
Identify this instrument.
Microscope
Refracting telescope
Reflecting telescope
Radio Telescope
Answer:
I believe the answer is Reflecting Telescope
Explanation:
-leeknowishawt
What is the molarity of a HCl solution that
contains 6.27 g of HCl in 163 mL of solution?
Answer in units of M.
Answer:
M = 1.04 M
Explanation:
Given data:
Molarity of solution = ?
Mass of HCl = 6.27 g
Volume of solution = 163 mL (163 mL× 1L /1000 mL = 0.163 L)
Solution:
Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.
Formula:
Molarity = number of moles of solute / L of solution
Number of moles of HCl:
Number of moles = mass/molar mass
Number of moles = 6.27 g / 36.5 g/mol
Number of moles = 0.17 mol
Molarity:
M = 0.17 mol/ 0.163 L
M = 1.04 M
Answer:
4.6 M HCI
Explanation:
on edge
Calcium Carbonate reacts with dilute hydrochloric acid. The equation for the reaction is shown. CaCo3 + 2Hcl = Cacl2 + H2O + Co2 1 g of calcium Carbonate is added to 50cm3 of 0.05mol/dm3 hydrochloric acid. Which volume of carbon dioxide is made in this reaction?
Answer:
Approximately [tex]0.224\;\rm L[/tex], assuming that this reaction took place under standard temperature and pressure, and that [tex]\rm CO_2[/tex] behaves like an ideal gas. Also assume that the reaction went to completion.
Explanation:
The first step is to find out: which species is the limiting reactant?
Assume that [tex]\rm CaCO_3[/tex] is the limiting reactant. How many moles of [tex]\rm CO_2[/tex] would be produced?
Look up the relative atomic mass of [tex]\rm Ca[/tex], [tex]\rm C[/tex], and [tex]\rm O[/tex] on a modern periodic table:
[tex]\rm Ca[/tex]: [tex]40.078[/tex].[tex]\rm C[/tex]: [tex]12.011[/tex].[tex]\rm O[/tex]: [tex]15.999[/tex].Calculate the formula mass of [tex]\rm CaCO_3[/tex]:
[tex]\begin{aligned} & M(\rm CaCO_3) \\ &= 40.078 + 12.011 + 3 \times 15.999 \\&= 100.086\; \rm g \cdot mol^{-1}\end{aligned}[/tex].
Calculate the number of moles of formula units in [tex]1\; \rm g[/tex] of [tex]\rm CaCO_3[/tex] using its formula mass:
[tex]\begin{aligned}& n(\mathrm{CaCO_3})\\&= \frac{m(\mathrm{CaCO_3})}{M(\mathrm{CaCO_3})} \\ &= \frac{1\; \rm g}{100.086\; \rm g \cdot mol^{-1}} \approx 1.00\times 10^{-2}\; \rm mol\end{aligned}[/tex].
In the balanced chemical equation, the ratio between the coefficient of [tex]\rm CaCO_3[/tex] and that of [tex]\rm CO_2[/tex] is [tex]\displaystyle \frac{n(\mathrm{CO_2})}{n(\mathrm{CaCO_3})} = 1[/tex].
In other words, for each mole of [tex]\rm CaCO_3[/tex] formula units consumed, one mole of [tex]\rm CO_2[/tex] would be produced.
If [tex]\rm CaCO_3[/tex] is indeed the limiting reactant, all that approximately [tex]1.00\times 10^{-2}\; \rm mol[/tex] of [tex]\rm CaCO_3\![/tex] formula would be consumed. That would produce approximately [tex]1.00\times 10^{-2}\; \rm mol\![/tex] of [tex]\rm CO_2[/tex].
On the other hand, assume that [tex]\rm HCl[/tex] is the limiting reactant.
Convert the volume of [tex]\rm HCl[/tex] to [tex]\rm dm^{3}[/tex] (so as to match the unit of concentration.)
[tex]\begin{aligned}&V(\mathrm{HCl})\\ &= 50\; \rm cm^{3} \\ &= 50\; \rm cm^{3} \times \frac{1\; \rm dm^{3}}{10^{3}\; \rm cm^{3}} \\ &= 5.00\times 10^{-2}\; \rm dm^{3} \end{aligned}[/tex].
Calculate the number of moles of [tex]\rm HCl[/tex] molecules in that [tex]5.00\times 10^{-2}\; \rm dm^{3}[/tex] of this [tex]\rm 0.05\; \rm mol \cdot dm^{-3}[/tex]
[tex]\begin{aligned}& n(\mathrm{HCl}) \\ &= c(\mathrm{HCl}) \cdot V(\mathrm{HCl}) \\ &= 0.05\; \rm mol \cdot dm^{-3}\\ &\quad\quad \times 5.00\times 10^{-2}\;\rm dm^{3} \\ &= 2.50 \times 10^{-3}\; \rm mol\end{aligned}[/tex].
Notice that in the balanced chemical reaction, the ratio between the coefficient of [tex]\rm HCl[/tex] and that of [tex]\rm CO_2[/tex] is [tex]\displaystyle \frac{n(\mathrm{CO_2})}{n(\mathrm{HCl})} = \frac{1}{2}[/tex].
In other words, each mole of [tex]\rm HCl[/tex] molecules consumed would produce only [tex]0.5\;\rm mol[/tex] of [tex]\rm CO_2[/tex] molecules.
Therefore, if [tex]\rm HCl[/tex] is the limiting reactant, that [tex]2.50 \times 10^{-3}\; \rm mol[/tex] of [tex]\rm HCl\![/tex] molecules would produce only one-half as many (that is, [tex]1.25\times 10^{-3}\; \rm mol[/tex]) of [tex]\rm CO_2[/tex] molecules.
If [tex]\rm CaCO_3[/tex] is the limiting reactant, [tex]\rm 1.00\times 10^{-3}\; \rm mol[/tex] of [tex]\rm CO_2[/tex] molecules would be produced. However, if [tex]\rm HCl[/tex] is the limiting reactant, [tex]1.25\times 10^{-3}\; \rm mol[/tex] of [tex]\rm CO_2\![/tex] molecules would be produced.
In reality, no more than [tex]\rm 1.00\times 10^{-3}\; \rm mol[/tex] of [tex]\rm CO_2[/tex] molecules would be produced. The reason is that all [tex]\rm CaCO_3[/tex] would have been consumed before [tex]\rm HCl[/tex] was.
After finding the limiting reactant, approximate the volume of the [tex]\rm CO_2\![/tex] produced.
Assume that this reaction took place under standard temperature and pressure (STP.) Under STP, the volume of one mole of ideal gas molecules would be approximately [tex]22.4\; \rm L[/tex].
If [tex]\rm CO_2[/tex] behaves like an ideal gas, the volume of that [tex]\rm 1.00\times 10^{-3}\; \rm mol[/tex] of [tex]\rm CO_2\![/tex] molecules would be approximately [tex]\rm 1.00\times 10^{-3}\; \rm mol \times 22.4\; \rm L = 0.224\; \rm L[/tex].
hich of the following is a typical cost associated with renting?
a.
closing costs
b.
down payment
c.
property tax
d.
security deposit
Answer:
D
Explanation:
The other three are related to
a. selling a home
b. buying a home
c. owning a home
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Calculate the mole fraction of each solute and solvent in the solution of 46.85 g of codeine, C 18 H 21 NO 3 , in 125.5 g of ethanol, C 2 H 5 OH.
mol fraction Codein : 0.054
mol fraction Ethanol : 0.946
Further explanationGiven
46.85 g of codeine
125.5 g of ethanol
Required
mol fraction
Solution
The mole fraction : the mole ratio of a substance to the mole of solution /mixture
mol Codeine, C₁₈H₂₁NO₃(MW=299.4 g/mol) :
[tex]\tt mol=\dfrac{46.85}{299.4 g/mol}\\\\mol=0.1565[/tex]
mol Ethanol, C₂H₅OH(MW=46.07 g/mol)
[tex]\tt mol=\dfrac{125.5}{46.07}=2.7241[/tex]
mol of solution :
[tex]\tt mol~codein+mol~ethanol=0.1565+2.7241=2.8806[/tex]
mol fraction Codein :[tex]\tt \dfrac{0.1565}{2.8806}=0.054[/tex]
mol fraction Ethanol :
[tex]\tt \dfrac{2.7241}{2.8806}=0.946[/tex]
When paper is burned, the mass of the remaining ash is less than the mass of the original paper. Which statement best explains this result?
A. The ash has less volume than the paper.
B. Some of the matter is destroyed during the reaction.
C. The mass of the ash cannot be accurately determined
D. Some of the products of the reaction were given off as a gas.
Answer:
d
Explanation:
According to law of conservation of mass, mass is conserved during burning of paper although the mass of ash is less than paper as some of the products are given out as gas.
What is law of conservation of mass?According to law of conservation of mass, it is evident that mass is neither created nor destroyed rather it is restored at the end of a chemical reaction .
Law of conservation of mass and energy are related as mass and energy are directly proportional which is indicated by the equation E=mc².Concept of conservation of mass is widely used in field of chemistry, fluid dynamics.
Law needs to be modified in accordance with laws of quantum mechanics under the principle of mass and energy equivalence.This law was proposed by Antoine Lavoisier in the year 1789.
Learn more about law of conservation of mass ,here:
https://brainly.com/question/13383562
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When an element loses electrons, it forms *
Negative ions or anions
Positive ions or cations
neutral atoms or neutrons
alpha and beta particles
Answer: Positive ions or cations
Explanation:
The ions are formed when an atom gains or lose electrons.
The ions are classified into two which are called the cations and anions. The cation is classified as the positive charge formed by the loss of electrons. Example: [tex]Na^+[/tex] is formed by the loss of one electron by [tex]Na[/tex]
The anion is classified as the negative charge ion formed by the gain of electrons. Example : [tex]F^-[/tex] is formed the gain of one electron by [tex]F[/tex]
Thus when an element loses electrons, it forms positive ions or cations.
Passengers get on a plane in Phoenix at 8:00 A.M. and fly to Los Angeles and land at 8:00 A.M. How can that possible?
Answer:
Because of time zones?
Explanation: The only thing that would make sense to me is the time zones.
A perfectly spherical balloon occupied 35°C of neon gas under a pressure of 2 atm.
The radius of the balloon is 15 cm. The balloon is then released up in the air until it
reached the temperature of -20°C under 0.3 atm. Determine its volume at that instant.
Answer:
V₂ = 116126.75 cm³
Explanation:
Given data:
Radius of balloon = 15 cm
Initial pressure = 2 atm
Initial temperature = 35 °C (35 +273 = 308K)
Final temperature = -20°C (-20+273 = 253 K)
Final pressure = 0.3 atm
Final volume = ?
Formula:
P₁V₁/T₁ = P₂V₂/T₂
P₁ = Initial pressure
V₁ = Initial volume
T₁ = Initial temperature
P₂ = Final pressure
V₂ = Final volume
T₂ = Final temperature
Solution:
Initial volume of balloon:
V = 4/3πr³
V = 4/3×22/7×(15cm)³
V = 14137.17 cm³
V₂ = P₁V₁ T₂/ T₁ P₂
V₂ = 2 atm × 14137.17 cm³ × 253 K / 308 K × 0.3 atm
V₂ = 7153408.02 atm .cm³. K / 61.6 K.atm
V₂ = 116126.75 cm³
please help!!!!!!!
according to the laws of conservation of mass how much zinc was present in the zinc carbonate
a. 40 g
b. 88 g
C. 104 g
d. 256 g
1
Aluminum metal and oxygen gas combine to produce aluminum oxide.
Which of these is the balanced equation for this reaction? *
Answer:
4 Al(s) + 3 O₂(g) ⇒ 2 Al₂O₃(s)
Explanation:
Let's consider the unbalanced molecular equation when aluminum metal and oxygen gas combine to produce aluminum oxide. This is a combination reaction.
Al(s) + O₂(g) ⇒ Al₂O₃(s)
We can balance O atoms by multiplying O₂ by 3 and Al₂O₃ by 2.
Al(s) + 3 O₂(g) ⇒ 2 Al₂O₃(s)
Finally, we multiply Al by 4 to get the balanced equation.
4 Al(s) + 3 O₂(g) ⇒ 2 Al₂O₃(s)
What advantage does a heterogeneous catalyst provide over a homogeneous catalyst in industrial processes?
Answer:
A heterogeneous catalyst can be easily separated from reactants.
Explanation:
How many liters of 0.305 m K3PO4 solution are necessary to completely react with 187 ml of 0.0184M NiCl2 according to the balanced chemical reaction:
2 K3PO4(aq) + 3NiCl2(aq)>Ni3(PO4)2(s) +6 KCl(aq)
Answer:
0.00752L of 0.305M K₃PO₄
Explanation:
Based on the balanced chemical equation, 2 moles of K₃PO₄ react with 3 moles of NiCl₂.
To find the volume of K₃PO₄ we need to determine the moles of this compound required for a complete reaction finding moles of NiCl₂ and using the chemical equation:
Moles NiCl₂:
187mL = 0.187L * (0.0184mol / L) = 0.00344 moles NiCl₂
Moles K₃PO₄:
As 2 moles of K₃PO₄ react with 3 moles of NiCl₂:
0.00344 moles NiCl₂ * (2 mol K₃PO₄ / 3 moles NiCl₂) =
0.002294 moles of K₃PO₄
Volume of 0.305M K₃PO₄:
0.002294 moles of K₃PO₄ * (1L / 0.305moles K₃PO₄) =
0.00752L of 0.305M K₃PO₄
Calculate the [H3O+] of 0.10 M HNO2 at equilibrium. Given: Ka = 4.46 × 10-4.
Answer:
0.0067 mol/dm³Explanation:
The [H3O+] of HNO2 can be found by using the formula
[tex][H_3O^{ + } ] = \sqrt{Kac} [/tex]
Ka is the acid dissociation constant
c is the concentration of the acid
From the question we have
[tex][H3O^{ + } ] = \sqrt{4.46 \times {10}^{ - 4} \times 0.1} \\ = 0.006678...[/tex]
We have the final answer as
0.0067 mol/dm³Hope this helps you