The magnitude of the electric field at (a) 0 cm, (b) 10.0 cm, (c) 40.0 cm, and (d) 60.0 cm from the center of the sphere will be respectively, (a) Infinite, (b) 2.26 × 10^5 N/C, (c) 6.52 × 10³ N/C, and (d) 2.26 × 10³ N/C.
If an electric field is r distance from the center of a uniformly charged sphere which has the radius R and if the charge total is Q the equation of charge equal to,
E = k × Q / r² ( k is the coulomb-constant )
If the distance is 0 cm the magnitude of the charge will be infinite.
If the distance is 10 cm, the magnitude will be,
8.99 × 10^9 Nm²/C² × 26 × 10^-6 C / (10² cm)² = 2.26 × 10^5 N/C
If the distance from the sphere is 40 cm, the magnitude of the electric field will be,
8.99 × 10^9 Nm²/C² × 26 × 10^-6 C / (40² cm)² = 6.52 × 10³ N/C.
If it is 60 cm then,
8.99 × 10^9 Nm²/C² × 26 × 10^-6 C / (60² cm)² = 2.26 × 10³ N/C.
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2-82 the tank truck is half filled with water. determine the magnitude of the resultant force on the elliptical back
The magnitude of the resultant force on the elliptical back will be equal to the difference between gravity and normal force.
The weight of the water and the force of gravity pressing on it determine the size of the resulting force on the elliptical tank truck. The water in the tank truck serves as a weight, creating a force of gravity proportionate to its mass. This force acts vertically downwards and is equal to the weight of the water, which can be estimated by multiplying the mass of the water by the gravity acceleration (g = 9.8 m/s^2).
When the tank truck is half full, the weight of the water may be estimated by multiplying the volume of water by its density and gravity acceleration. The volume of water may be calculated by taking the volume of the elliptical tank and dividing it by half. Water's density is constant and equal to 1000 kg/m3.
The total of the vertical components of gravity and normal force equals the size of the resulting force on the elliptical tank truck. The normal force is equal to the weight of the water and acts vertically upwards, against the force of gravity.
The amount of the resulting force on the elliptical back may be calculated by calculating the weight of the water, determining the force of gravity operating on it, and taking into account the normal force acting in the opposite direction.
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the index of refraction for red (660 nm) and green (550 nm) light respectively in flint glass is 1.662 and 1.674. by how much do the critical angles for red and green light differ in flint glass surrounded by air?
The sine refraction of the two angles, or sin(c, red) - sin(c, green), is equal to the difference between the critical angles for red and green light.
How does critical angle work?The critical angle is the angle of incidence (angle between the incoming light and the surface normal) where no more refraction takes place and the refracted ray is just skimming the surface. Beyond this angle, the light won't enter the second medium and will instead begin to reflect back into the first.
What is the flint glass' violet refractive index?Flint glass has red and violet light refractive indices of 1.613 and 1.632, respectively. The refractive indices of the materials define the critical angle.
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What is a wave's wavelength if it was
traveling at 33 m/s and had a frequency of
11 Hz? What was the period?
Important Formulas:
[tex]v=\lambda f[/tex]
velocity(measured in m/s) = wavelength(measured in meters) * frequency(measured in hertz)
[tex]T=\dfrac{1}{f}[/tex]
period(measured in seconds) = 1 / frequency(measured in hertz)
__________________________________________________________
Given:
[tex]v=33m/s[/tex]
[tex]f=11Hz[/tex]
[tex]\lambda=?[/tex]
[tex]T=?[/tex]
__________________________________________________________
Wavelength:Rearrange formula for velocity to make wavelength the subject:
[tex]v=\lambda f[/tex]
[tex]\dfrac{v}{f} =\dfrac{\lambda f}{f}[/tex]
[tex]\lambda=\dfrac{v}{f}[/tex]
__________________________________________________________
Finding wavelength:
[tex]\lambda=\dfrac{v}{f}[/tex]
[tex]\lambda=\dfrac{33}{11}[/tex]
[tex]\lambda=3m[/tex]
__________________________________________________________
Period:Finding period:
[tex]T=\dfrac{1}{f}[/tex]
[tex]T=\dfrac{1}{11}[/tex]
[tex]T=0.09[/tex]
__________________________________________________________
Answer:
[tex]\boxed{\lambda=3 \texttt{ meters}}\\\boxed{T=0.09 \texttt{ seconds}}[/tex]
a car is moving at the rate of 45 miles per hour, and the diameter of its wheels is 2.5 feet. (round your answers to one decimal place.) (a) find the number of revolutions per minute that the wheels are rotating. 18 rev/min (b) find the angular speed of the wheels in radians per minute. rad/min
Number of revolutions per minute that the wheels rotates is 504rev/min and angular speed is 3160 rad/min.
Angular speed is characterized as the pace of progress of rakish relocation, and it is communicated as follows: ω = θ t where θ is the precise uprooting, t is the time and ω is the precise speed Rakish Speed Unit The unit of precise speed is radian each second. A similar recipe addresses both precise speed and rakish speed.
The unit of angular speed is radian each second. A similar recipe addresses both precise speed and rakish speed. Angular speed is a vector amount that communicates both bearing and size, while precise speed portrays greatness as it were.
It is given that rate of car is 45 miles/hr.
Firstly,we convert this into inches/min.
In 1mile=5280feet
=>45mile=45×5280
In 1 feet=12inches
=>45×5280feet=45×5280×12inches/hr
In 1 hr=.(45×5280×12)/60inches/min.
Now,we have diameter=2.5feet
=>Therefore,radius=2.5/2=1.25feet=1.25×12inches
So,angular speed=(45×5280×12)/60inches/min / 1.25×12inches
=>angular speed=(47520)/15=3168
Now,number of revolutions is =Distance/Circumference
=>Number of revolutions=(45×5280×12)/60 / 2×3.14×1.25×12
=>Number of revolutions=47520/94.2
=>Number of revolutions=504.45
Hence,number of revolutions=504 and angular speed is 3168/min.
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4. For each of the following cases, indicate whether the work done on the second object in each example will have a positive or a negative value.
5. If a neighbor pushes a lawnmower four times as far as you do but exerts only half the force, which one of you does more work and by how much?
c. Air exerts a force on a parachute as the parachutist falls to Earth.
b. A rope exerts a force on a bucket as the bucket t is raised up a well.
a. The road exerts a friction force on a speeding car skidding to a stop.
Work done on an object- Measure of energy transfer when an object is moved over a distance by an external force, at least some of which is applied in the displacement direction.
a. When the road exerts a friction force on a speeding car skidding to a stop, the work done by the friction force is negative. This is because the friction force opposes the motion of the car and slows it down. When the force is in the opposite direction of the motion of an object, the work done by the force is negative.
b. When a rope exerts a force on a bucket as it is raised up a well, the work done by the rope is positive. The force of the rope is in the same direction as the displacement of the bucket, so the work done by the rope is positive. When the force is in the same direction as the motion of an object, the work done by the force is positive.
c. When air exerts a force on a parachutist as they fall to Earth, the work done by the air is negative. The force of air resistance opposes the motion of the parachutist and slows them down, so the work done by the air is negative.
Comparison of work done:
The work done by a force is defined as the product of the force and the distance traveled by an object.
If a neighbour pushes a lawnmower four times as far as you do but exerts only half the force, neighbour does more work. The work done by neighbour is four times the distance traveled by the lawnmower multiplied by half the force exerted .
To find the exact difference in the amount of work done, calculate the product of the distance traveled by the lawnmower and the difference in the force exerted by each person. Assuming that person pushed the lawnmower a distance of d units and exerted a force of f units. Then, neighbour pushed the lawnmower a distance of and exerted a force of
The work done by person is given by the equation
The work done by neighbour is given by the equation
The difference in the amount of work done is given by the equation W2 -
So, neighbour did units more work than the person has done.
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In Fig. 22−35 the four particles form a square of edge length a=5.00 cm and have charges q1=+10.0 nC,q2=−20.0 nC,q3=+20.0 nC, and q4=−10.0 nC, In unit vector notation, what net electric field do not particles produce at the square's center?
The net electric field that the particles produce at the square's center will be [tex]E_n_e_t = -2.03[/tex].
To find the net electric field at the center of the square, we need to calculate the electric field due to each particle at that point and then add them up vectorially.
Let's assume that the bottom left corner of the square is at the origin, and the positive x-axis points to the right and the positive y-axis points upwards. Coordinates of four particles:-
q1: (0,0)
q2: (a,0)
q3: (a,a)
q4: (0,a)
here, a = 5.00 cm.
Using the Coulomb's law, the electric field due to each particle at the center of the square:-
[tex]E_1 = k * q_1 / r_1^2[/tex],
here,
[tex]r_1 = a/\sqrt{2}[/tex] is distance between q1 & center of the square.
Since [tex]q_1[/tex] is a positive charge, the direction of its electric field is towards the center of the square.
[tex]E_1 = k * q_1 / r_1^2 * (-i - j)[/tex],
Putting values:-
[tex]E_1 = (9 * 10^9 Nm^2/C^2) * (10.0 * 10^-^9 C) / [(5.00/\sqrt{2} ) m]^2 * (-0.707i - 0.707j)[/tex]
[tex]= -2.03 * 10^5 N/C * (0.707i + 0.707j)[/tex]
Similarly, we can find the electric fields due to q2, q3, and q4:
[tex]E_2 = k * q_2 / r_2^2 * (i)[/tex],
here,
[tex]r_2 = a/2[/tex] is distance between q2 and the center of the square. The direction of its electric field is towards the right:-
[tex]E_2 = (9 * 10^9 Nm^2/C^2) * (-20.0 * 10^-^9 C) / [(5.00/2) m]^2 * i[/tex]
=[tex]-1.44 * 10^6 N/C * i[/tex]
[tex]E_3 = k * q_3 / r_3^2 * (i + j)[/tex],
here,
[tex]r_3 = a/\sqrt{2}[/tex] is distance between [tex]q_3[/tex] and the center of the square.
The direction of its electric field is towards the upper right:-
[tex]E_3 = (9 * 10^9 Nm^2/C^2) * (20.0 * 10^-^9 C) / [(5.00/\sqrt{2} ) m]^2 * (0.707i + 0.707j)[/tex]
= [tex]4.06 * 10^5 N/C * (0.707i + 0.707j)[/tex]
[tex]E_4 = k * q_4 / r_4^2 * (j)[/tex],
here,
[tex]r_4 = a/2[/tex] is distance between [tex]q_4[/tex] and center of the square.
The direction of its electric field is upwards:-
[tex]E_4 = (9 * 10^9 Nm^2/C^2) * (-10.0 * 10^-^9 C) / [(5.00/2) m]^2 * j[/tex]
[tex]= -7.20 * 10^5 N/C * j[/tex]
These four electric fields combine to form the net electric field at the center of the square:
[tex]E_n_e_t = E_1 + E_2 + E_3 + E_4[/tex]
Putting values:-
[tex]E_n_e_t = -2.03[/tex]
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planet x has an estimated mass of 1.78x1027 kg, while its diameter is approximately 142,984 km. consider the planet as a perfect sphere. what is the density of planet x in g/cm3? volsphere
1.16g/cm3 is the density of planet x in g/cm3 if planet x has an estimated mass of 1.78x1027 kg, while its diameter is approximately 142,984 km.
Radius = diameter/2
Radius of the planet X = 142984km/2 = 71492km = 71492000m = 7149200000cm
Volume of the planet X = (4/3) × 3.143 × ( 7149200000cm)3 = 1.53× 1030cm3
mass of the planet X = 1.78 × 1027 kg = 1.78 × 1030g
Density = mass /volume
Density of the planet X = 1.78 ×1030g/1.53×1030cm3 = 1.16g/cm3
Density is defined as d = M/V, where d represents density, M is mass, and V is volume. Density is generally measured in grammes per cubic centimetre. Water, for example, has a density of 1 gramme per cubic centimetre, but Earth has a density of 5.51 grammes per cubic centimetre. Density is sometimes measured in kilos per cubic metre (in metre-kilogram-second or SI units).
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isaac is mixing green, blue, and red paints together, and it looks like a muddy mess rather than pure white. why? the wavelengths are subtracted, rather than added. the wavelengths are added, rather than subtracted. more light is reflected as he mixes the colors. the colors have the same wavelengths.
Isaac is mixing green, blue, and red paints together, and it looks like a muddy mess rather than pure white then the wavelengths are subtracted, rather than added.
Additive and subtractive color mixing are the two major methods of color blending. A procedure known as additive color mixing involves adding one set of wavelengths to another set of wavelengths to produce a new hue. When lights of various wavelengths are combined, additive color mixing results. We see white light rather than numerous distinct hues when we combine all of the sun's various wavelengths. Because all of the wavelengths still reach our eyes, it is called additive. The variety of colors is produced by combining various wavelengths. By removing wavelengths from a light source with a wide spectrum of wavelengths, subtractive color mixing produces a new hue. When we combine paints, dyes, or pigments, subtractive color mixing takes place.
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when we describe electric flux, we say that a surface is oriented in a certain direction with respect to an electric field. when we try to calculate how much electric field passes through the surface, we make use of the:
When we try to calculate how much electric field passes through the surface, we make use of the: In the center of a uniformly charged ring, there is no electric field.
How does the direction of a surface impact the flow of electricity?
When a surface is perpendicular to the field (right panel), no field lines intersect it and there is no electric flux through it. The flux through the surface is between zero and the maximum value if the surface is rotated with respect to the electric field.
The electric flux through a surface only depends on the amount of charge contained by the surface, according to the electrostatics principle known as Gauss's theorem. It is independent of the size and contour of the surface. As a result, for all figures, the electric flux across the surface is the same.
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what horizontal force is required to hold a 3kg book vertically against the wall to prevent it from falling if the coefficient of static friction between the book and the wall is .3?
100N of horizontal force is required to hold a 3kg book vertically against the wall to prevent it from falling if the coefficient of static friction between the book and the wall is 0.3.
What is friction?
Friction between two surfaces causes kinetic energy from moving surfaces to be converted into thermal energy (that is, it converts work to heat). As demonstrated by the utilization of friction produced by rubbing pieces of wood together to start a fire, this feature can have dramatic effects. Every time there is motion with friction, such as when a viscous fluid is agitated, kinetic energy is transformed into thermal energy. Wear is a significant side effect of several types of friction that can result in deteriorated performance or component damage. The discipline of tribology includes friction.Friction=μN, where N is the normal force.
N = friction/μ.
N = mg/μ
m = 3 kg
g = 10m/s²
μ = 0.3
N = mg/μ
N = 300/3
= 100N
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The type of function that describes the amplitude of damped oscillatory motion is _______. quadratic sinusoidal inverse exponential linear
Because we already know that this function is exponential, that sort of function that describes the amplitude of damped oscillatory motion is exponential. [tex]y=A\times e^{\frac{-b}{2m} }[/tex][tex]\times cos\omega t[/tex]
The maximum displacement or distance a point on a vibrating body or wave can move in relation to its equilibrium location is referred to as the amplitude in physics. It is equivalent to the half-length of the vibration path. The bob swings halfway across the pendulum's amplitude when it shifts from one side to the other. Waves are produced by vibrating sources, and the amplitude of the waves is inversely proportional to the amplitude of the source. The largest deviation of any point on a transverse wave, such as the wave on a plucked string, from its position when the wave is at rest, is used to determine the wave's amplitude.
[tex]y=A\times e^{\frac{-b}{2m} }[/tex][tex]\times cos\omega t[/tex] [tex]\rightarrow(1)[/tex]
here function is [tex]A\times e^{\frac{-b}{2m} }[/tex] is amplitude
as per equation ( 1 ) it is exponential
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what is the minimum magnitude of an electric field that balances the weight of a plastic sphere of mass 6.4 g that has been charged to -3.0 nc?
Answer:
F = Q E force exerted by field on charge Q
F = M g weight of sphere
M g = Q E
E = M g / Q = .0064 kg * 9.80 m/s^2 / 3E-9 C
E = 2.09E7 Newtons/Coulomb
explain how the electric field could have a nonzero value in a point that has zero electric potential
Although the electric potential due to the charges in that position is non-zero, the electric field due to the charges in that position is zero. If the charges are positive, depending on the charges, the potential has two positive contributions or two negative contributions.
What is electric field ?
According to mathematics, the electric field is described as a vector field that may be connected to each point in space and represents the force per unit charge that is applied to a positive test charge that is at rest at that location. Either the electric charge or time-varying magnetic fields can produce an electric field.
What is electric potential?
Between two points in an electric field, there is a difference in potential energy per unit charge, which is known as the electric potential or voltage. The amount of work required to move a unit positive charge from infinity to a specific point in an electric field without accelerating is known as the electric potential (or potential).
Although the electric potential due to the charges at that same position is non-zero, the electric field due to the charges at that same point is zero. If the charges are positive, the potential either has two positive contributions or two negative contributions, depending on the charges.
Therefore, The electric field could have a nonzero value in a point that has zero electric potential was mentioned above.
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If you pull a pendulum with a mass of 7.4 kg back at an angle of 13°, what is the magnitude of the restoring force on it?
When the pendulum is brought back at an angle of 13°, there is a about 1.67 N restoring force on it.
What force is the restoring force in a straightforward pendulum in straightforward harmonic motion?A simple pendulum's restoring force is directed towards the mean position when it moves in a simple harmonic motion (lowest point). Here, the force of gravity acts as the restoring force at the centre of mass of the bob.
f_restoring = -m * g * sin(θ)
Where:
m = 7.4 kg (mass of the pendulum), g = 9.8 m/s^2 (acceleration due to gravity), θ = 13° (angle of displacement)
Converting the angle to radians:
θ = 13° * (π / 180) = 0.226 rad
Substituting the values into the equation:
f_restoring = -7.4 kg * 9.8 m/s^2 * sin(0.226 rad) = -7.4 kg * 9.8 m/s^2 * 0.226 = -1.67 N
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in the united states. which is not a potential reason for the rise in the frequency of iowobirthwcight babies?
There are main potential reason Genetic factors for the rise in the frequency of low birth weight babies in the United States, but it is not accurate to say that any one particular reason is not a potential cause.
Some of the most commonly cited factors that can contribute to low birth weight include maternal smoking, poor maternal nutrition, lack of access to prenatal care, maternal stress, and medical conditions such as diabetes or high blood pressure. Additionally, environmental factors such as air pollution, exposure to toxins, and social determinants of health, such as poverty and lack of education, can also play a role.
It is important to note that the causes of low birth weight are often complex and multifactorial, and can vary from person to person and from pregnancy to pregnancy. In order to address this issue, it is important to consider a comprehensive and individualized approach that addresses the multiple factors that can contribute to low birth weight.
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The complete question is
In the United States, which is NOT a potential reason for the rise in the frequency of low-birthweight babies?
A. Genetic factors
Mani has two digital stopwatches, C1 and C2, which he is using to measure the speed of a car. He does not know
how accurate the stopwatches are. He starts both the stopwatches at the start of a race on a track that is
exactly 5 km long.
When the car reaches the end point, stopwatch C1 shows 300 seconds and C2 shows 310 seconds.
Which of the following can we say based on this?
A. C1 is more accurate than C2.
B. C2 is more accurate than C1
C. Both C1 and C2 have the same accuracy.
D. The experiment cannot tell us which stopwatch is accurate.
The experiment cannot tell us which stopwatch is accurate. Then the correct option is D.
What is accuracy?There are two ways to assess observational error: accuracy and precision. Precision measures how closely two measurements are to one another, whereas accuracy measures how close a group of measurements is to its actual value. In other words, precision is both a measure of empirical unpredictability and a description of experimental noise.
Mani is measuring the speed of a car using two digital stopwatches, C1 and C2. He is unsure of the accuracy of the stopwatches. At the beginning of a race on a track that is exactly 5 km long, he starts both stopwatches.
There is no other information is given so that the stopwatches can be judged.
Thus, the correct option is D.
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the next three questions refer to an object whose position versus time graph is shown above. at which point is its speed the largest?
Object whose position throughout time is represented by a graph Which point in position 6 has the highest speed
What is the definition of a velocity simple?A body and object's velocity determines the direction of its motion. Speed is fundamentally a scalar quantity. It is a vector term in its purest form. It refers to the rate at which distance varies.
We calculate velocity because?Any object's velocity is a measurement of how swiftly it moves. Therefore, it can be described as the shift in an object's position divided by time. Both a magnitude (a number) and a direction are associated with velocity. Meters a second (meter/second) is the unit used to measure velocity.
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A 66.9 kg high jumper leaves the ground with a vertical velocity of 8.9 m/s. How high can he jump? The acceleration of gravity is 9.8 m/s^2. Answer in units of m.
Answer:
Below
Explanation:
All of the Kinetic energy ( 1/2 mv^2) will be converted to Gravitational Potential Energy ( mgh) ....so
1/2 m v^2 = mgh divide both sides of the equation by 'm'
1/2 v^2 = gh ( not that the mass of the jumper is irrelevant !)
(1/2 v^2 ) /g = h
(1/2) (9.8 m/s)^2 / (9.8 m/s^2 ) = 4.9 m
The driver of a car moving with a uniform speed of 40m/s observes a truck approaching
in the opposite direction with a speed of 20m/s.Calculate the speed of the car relative to that of the truck.
Answer:
60m/s
Explanation:
Whenever two objects are moving in opposite direction the relative speed is obtained by adding the speeds of the two objects.
Here the two vehicles are moving with speed 20m/s and 40m/s .
So the relative speed of the car relative to that of the truck will be,
(40 + 20 ) m/s
60m/s
hope this helps!
According to the Stop the Static Campaign reading by the Petroleum Equipment Institute (PEI), there were 36 ignitions of gasoline vapors during the refueling process reported to PEI between 1999-2000.
What did all 36 of these incidents have in common?
The common cause for ignition of gasoline vapors during refueling is
static electrical discharge.
What is static electricity?Static electricity is an imbalance of electric charges within or on the surface of a material or between materials.
In petrol pumps,
During refueling, many petroleum products become electrically charged when they flow through pipes and hoses, including gasoline, kerosene, petrol, diesel etc. which are poor electrical conductors.
Charge remains until it is able to move away by means of an electric current or electrical discharge which causes the static spark that can ignite gasoline vapors, causing a flash fire.
Hence, static electrical discharge is common cause of all 36 incidents of gasoline vapor ignition.
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PLEASE HELP ASAP!!
An elevator has a mass of 250.0 kg. The sign inside the elevator says the maximum load that can be hauled in the elevator is 1000.0 kg. If the elevator accelerates upward at 3.25m/s² . What is the maximum force (Ft) that can be exerted on the cable? (Fnet = Fg + Fa must be used). (sketch a force body diagram of the scenario and label all forces)
The cable can withstand a tensile stress of up to 3265 N.
What in science is a force?It is appropriate to use the terms "push" or "pull" to describe a force at this moment. A power that something "contains" or "has in it" does not exist. A force is exerted on one item by another. The definition of a force includes both living and non-living things.
Here, T is the cable's tension force, m is the elevator's mass, g is gravity's acceleration (9.81 m/s2), and an is the elevator's upward acceleration.
The elevator's net force is supplied by:
Fnet = Fg + Fa
The sources of the gravitational pull are:
Fg = m * g
= 250.0 kg * 9.81 m/s²
= 2452.5 N
The force due to the elevator's acceleration is given by:
Fa = m * a
= 250.0 kg * 3.25 m/s²
= 812.5 N
The net force on the elevator is therefore:
Fnet = Fg + Fa
= 2452.5 N + 812.5 N
= 3265 N
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a point charge is placed 46 cm from an identical charge. how much work would be required to move a test charge from a point midway between them to a point 12 cm closer to either of the charges?
The work required to move a test charge of +0.50 C from a point midway between two identical charges of +35 C, 46 cm apart, to a point 12 cm closer to either of the charges would be W = 2.6 x 10^-5 J.
This can be calculated using the equation W = (1/4πε_0) q1 q2 / r, where q1 and q2 are the charges of the two charges, and r is the distance between them. In this case, q1 = q2 = 35 C, and r = 34 cm, so the work required is W = 2.6 x 10^-5 J.
Electrical charge is a fundamental property of matter that exists in two types: positive and negative. Positive charges are attracted to negative charges, while negative charges are attracted to positive charges. This phenomenon is known as electrostatic attraction.
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a 1200kg car makes a right turn. the radius of this curve is 4.2m. if the maximum force of friction between the tires and the road is 2587.2n, what is the maximum velocity that the car can have before skidding?
The following equations provide the maximum speed at which an automobile may travel in a circular turn without skidding, (* g * r) = v max As a result, the car can travel at a maximum speed of about 3.23 m/s before skidding during the turn.
A car is a vehicle made specifically to move people and cargo over roads. Although electric and hybrid models have increased in popularity recently, internal combustion engines that use fossil fuels still provide the majority of the power for cars. The steering system, engine, gearbox, suspension, and brakes are a few of the crucial parts of a car. Modern vehicles frequently include a number of extra conveniences, such power windows, air conditioning, and sophisticated safety systems. The introduction of automobiles, which offer a practical and effective mode of transportation and enable the growth of new industries like travel and commuting, has had a significant impact on society.
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an object has a 4 c charge. the object breaks into two pieces. one piece has a charge of -2 c. what is the exact charge (in c) of the other piece? do not include units with your answer.
The total charge to conserved that is Q=-6C,Now the sum of the total charges on both the pieces should be Q=Q1+Q2 = -6C,given that one charge is Q1 =2C, there fore -6 =2+Q2, There fore the charge on other piece is Q2 = -6-2 = -8C.
Can something have a 2.8 * 10 18 charge?In accordance with the principle of charge quantization, the total charge on an object must be an integer multiple of the basic charge, which is the fee on an electron (e).Not an integer, this.Thus, a body charged at 2.810-18 C is not possible.
How can you tell if something has a positive or negative charge?If there are greater proton than electrons, the charge density of the thing is positive.If an object has more electrons than protons, it has a negative net charge.If there are an equal number of protons and electrons, the thing is neutral.
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A roller coaster features a near vertical drop of 135 meters. If the initial velocity was zero, the mass of the cart and riders was 1,500 kg, and the velocity at the end of the drop was 45 m/s, how much of the potential energy was converted into thermal energy?
Group of answer choices
392 kJ
579 kJ
468 kJ
518 kJ
The amount of potential energy that converted into thermal energy is 468 kJ.
What is energy?Energy, which is observable in the execution of labor as well as in the form of heat and light, is the quantitative quality that is transferred to a body or to a physical system in physics.
Energy is a preserved resource, energy can only be transformed from one form to another and cannot be created or destroyed.
Hence, form conservation of energy;
the amount of potential energy that converted into thermal energy =
Initial potential energy - final kinetic energy
= 1500 × 9.8 × 135 - 1/2×1500×45²
= 465750 Joule
= 468 kJ
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if the staggered and eclipsed populations of ethane had only differed 30-fold instead of the almost three orders-of-magnitude, what would the energy difference between them be?
The energy difference between the staggered and eclipsed populations of ethane depends on various factors such as bond length, bond angle, and bond energy.
In general, the energy difference between these two populations is proportional to the difference in their molecular structure.]
If the difference in molecular structure between the staggered and eclipsed populations of ethane had only been 30-fold instead of the almost three orders of magnitude, it would result in a proportionally smaller energy difference between them. However, without more specific information about the specific molecular structure and bond energies involved, it is not possible to determine the exact energy difference.
In general, it's important to note that the magnitude of the energy difference between the staggered and eclipsed populations of ethane can be influenced by various factors such as temperature, pressure, and the presence of other molecules. These factors can affect the magnitude of the energy difference and make it difficult to determine an exact value.
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Over several cycles, a refrigerator does 1.51 × 10^4 J of work on the refrigerant. The refrigerant in turn removes 7.55 × 10^4 J as heat from the air inside the refrigerator.
a. How much energy is transferred as heat to the outside air?
b. What is the net change in the internal energy of the refrigerant?
c. What is the amount of work done on the air inside the refrigerator?
d. What is the net change in the internal energy of the air inside the refrigerator?
a) The heat energy transferred to the outside air is 6.04 × 10^4 J.
b) The net change in the internal energy of the refrigerant is 1.51 × 10^4 J.
c) amount of work done inside is -1.51 × 10^4 J.
d) The net change in the internal energy is 9.06 × 10^4 J
Refrigerant Energy Analysisa. The amount of energy transferred as heat to the outside air is the difference between the amount of heat removed from the air inside the refrigerator and the work done on the refrigerant: 7.55 × 10^4 J - 1.51 × 10^4 J = 6.04 × 10^4 J.
b. The net change in the internal energy of the refrigerant is the work done on the refrigerant: 1.51 × 10^4 J.
c. The amount of work done on the air inside the refrigerator is negative of the work done on the refrigerant, as energy is transferred from the air to the refrigerant: -1.51 × 10^4 J.
d. The net change in the internal energy of the air inside the refrigerator is the heat removed from the air minus the work done on the air: 7.55 × 10^4 J - (-1.51 × 10^4 J) = 9.06 × 10^4 J.
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what is the magnitude of the electric field 2.8 cm from a tiny object that carries an excess charge of -16 nc?
The required magnitude of electric field from a tiny object is calculated to be -18.36× 10⁴ c.
The object carries a charge (q) of -16 nc.
q = - 16 × 10⁻⁹ c
The distance (d) from the charge is given as 2.8 cm.
d = 2.8 cm = 2.8 × 10⁻² m
The expression for calculating electric field is known to be,
E = kq/d²
where,
k is electrostatic constant (9× 10⁹N/m²c²)
q is charge
d is distance
When we enter the values into the formula,
E = kq/d² = (9 × 10⁹ × - 16 × 10⁻⁹)/(2.8 × 10⁻²)² = (-16×9× 10⁴)/(2.8 × 2.8) = -18.36× 10⁴ c
Thus, the required electric field is calculated to be -18.36× 10⁴ c.
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if a ping-pong ball and a golf ball both move in the same direction with the same amount of kinetic energy, the speed of the ping-pong ball must be
The speed of the ping-pong ball is more than that of the golf ball. Correct option is C.
If the kinetic energy of each ball is equal to that of the other,
(1/2) (mass of ppb) (speed of ppb)² = (1/2) (mass of gb) (speed of gb)²
where,
ppb is ping-pong ball
gb is golf ball
Multiplying each side by 2,
(mass of ppb) (speed of ppb)² = (mass of gb) (speed of gb)²
Divide each side by (mass of gb) and by (speed of ppb)²:
(mass of ppb)/(mass of gb) = (speed of gb)²/(speed of ppb)²
Take square root of each side,
√ (ratio of their masses) = ( 1 / ratio of their speeds)²
If their kinetic energies are equal, then the product of each mass and its speed² must be the same number.
If one ball has less mass than the other one, then the speed² of the lighter one must be greater than the speed² of the heavier one, in order to keep the products equal.
Thus, the pingpong ball is moving faster than the golf ball.
The given question is incomplete. The complete question is 'A. less than golf ball B. same as golf ball C. more than golf ball D. impossible to know'
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The efficiency of a petrol car engine is 40%. The speed of the car is 9.0 m s−1 when the power developed by the
engine is 20 kW. Calculate how many kilometres the car can go with one litre of petrol when driven at this speed.
The car will travel 6.12 km one litre of petrol when driven at this speed
Given the energy provided by one liter of gasoline e = 34 * 10⁶ Joules
efficiency of the car = 40%
The speed of the car is 9.0 ms⁻¹
Power of the car = P = 20 kW
The useful energy produced by the car is equal to
= P * e
Therefore the useful energy is
= 34 * 10⁶ * 40/100
= 1.36 * 10⁷ Joules
Now, we can say that car consumes 20 ± 10³ J/s to travel at the speed of 9 m/s
The time for which the car will keep moving at this speed using the energy provided by 1 liter of fuel is
[tex]t=\frac{1.36*10^{7} }{20*10^{3} }[/tex] = 680 sec
The distance travelled by car during this time is
d = 9 * 680
d= 6.12 km
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