What is the frequency of a wave with a wavelength of 12 meters and a velocity of 4 m/s?
Answer:
0.33 hz
Explanation:
the formula for the frequency in this situation is f=v/wavelength
PLEASE HELP ME! do tectonic plates play a major or minor role in the ROCK CYCLE
Answer: All igneous rocks the basis of the rock cycle is formed by plate tectonics. ... This movement from igneous to sedimentary back to igneous is a major part of the rock cycle. The heat from the mantle that fuels plate tectonics causes both igneous and sedimentary rocks to be turned into metamorphic rocks.
Explanation: BRAINLEST?
I AM TIMED !! 30 POINTS Which is the smallest possible particle of an element?
O molecule
O atom
O compound
O matter
Answer:
atoms
Explanation:
they are the smallest
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Which model of the solar system is shown here?
O O
A. The heliocentric model B. The spherical model
O
C. The geocentric model
O
D. The universal model
Answer:
A
My logic:
Heliocentrism is the astronomical model in which the Earth and planets revolve around the Sun at the center of the Universe.
Hope this helps!
Calculate the force of gravity between two protons located 1m apart 1.7x10-27kg charge of proton is +1.6x10-19c
Answer:
87, not very hard but u have to keep trying ❤❤❤❤❤❤❤
This image shows layers underground.
Top to bottom: Soil, Clay, Rocks, Granite.
Which layer will become saturated first when rain falls?
clay
granite
rocks
soil
Answer:
soil
Explanation:
CORRECT
Answer:
soil
Explanation:
Hope this will help
1. Acceleration can result from a change of _______, or a change in ___________, or both *
distance, direction
temperature, volume
speed, direction
force, momentum
2. The acceleration is _______ when an object is speeding up. *
positive
negative
zero
constant
2. The acceleration is _________ when an object is slowing down. *
positive
negative
zero
constant
3. When an object is moving at a constant speed, its acceleration is ________. *
positive
negative
zero
constant
4. A roller coaster is moving at 35 m/s at the bottom of a hill. Four seconds later it reaches the top of the hill moving at 7 m/s. What was the acceleration of the coaster? Include: the formula, the work, the units, and mention if the object was accelerating or decelerating. *
5. A train moves from stop to a speed of 30 m/s in 25.0 seconds. What is its acceleration? Include: the formula, the work, the units, and mention if the object was accelerating or deccelerating. *
6.How long will it take a car to go from a complete stop to 33 km/hr if they are accelerating at 11 km/hr2? Include: the formula, the work, the units, and mention if the object was accelerating or deccelerating.
7.A train was going 100 m/s hit the brakes after seeing a deer who decided to have a nap on the train tracks. It took the train 1 minute 40 seconds to stop, what was the train’s acceleration? Include: the formula, the work, the units, and mention if the object was accelerating or deccelerating.
8. Write a short story that contain an acceleration/decceleration problem. Include numbers and units and solve for the unknown according to your story. Make sure to include the formula, the work, and the right units. *
Answer:
not sure
Explanation:
jahhhhhsjjjjdddddhdhdj hbdbd#dialectical DHL I have no clue W Bush administration and I don't have any jshshhhhdgggddddddd the entire community was literate because
a. they had been slaves and had not been to school
b. they were too poor to go to school
c. work was more important to them than education
d. they avoided to going school
the entire community was literate because
a. they had been slaves and had not been to school
b. they were too poor to go to school
c. work was more important to them than education
d. they avoided to going school
the entire community was literate because
a. they had been slaves and had not been to school
b. they were too poor to go to school
c. work was more important to them than education
d. they avoided to going school
the entire community was literate because
a. they had been slaves and had not been to school
b. they were too poor to go to school
c. work was more important to them than education
d. they avoided to going school
jsbsbd the entire community was literate because
a. they had been slaves and had not been to school
b. they were too poor to go to school
c. work was more important to them than education
d. they avoided to going school
the entire community was literate because
a. they had been slaves and had not been to school
b. they were too poor to go to school
c. work was more important to them than education
d. they avoided to going school
the entire community was literate because
a. they had been slaves and had not been to school
b. they were too poor to go to school
c. work was more important to them than education
d. they avoided to going school
the entire community was literate because
a. they had been slaves and had not been to school
b. they were too poor to go to school
c. work was more important to them than education
d. they avoided to going school
BFF and I don't have any questions please call her and her husband to the hospital for a bit more time with my family grew up in the form of a ring whose inner circumference is it a lot of people who are you doing today beautiful and I don't have any questions please call her and her husband to the
Which is an example of physical weathering?
a- limestone in rock dissolving when acid rain flows across it
b- bits of rock rusting when exposed to oxygen and water
c- wind blowing off bits of a rock over time
d- oxidation of certain metals in rock
An example of physical weathering is the wind that is blowing off bits of a rock over time. This results into breaking down of large rocks. Thus, the correct option is C.
What is Physical weathering?Physical weathering is also called as mechanical weathering. It is a process which causes the disintegration of large rocks, minerals, and large soil particles without any chemical change. The primary process in physical weathering is the abrasion, it is the process by which clasts and other particles are reduced in size and mix up with soil.
Physical weathering occurs when large rocks are broken down through mechanical processes such as wind blowing, water, gravitational force, freeze-thaw cycles, or the growth of roots into the rocks.
Therefore, the correct option is C.
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You have a working electrical series circuit with three light bulbs, then 1 bulb burns out. Describe how electric current flows through the series circuit after 1 of the 3 bulbs burns out?
Answer:
NARUTO IS A DIME GOD
Explanation:
Could somebody pls help me out with this?
1) You serve a Volleyball with a mass of 1.6kg. the ball leaves your hand with a speed of 25m/s. the ball has________energy. Calculate it.
2) Askateboard is sitting at the top of a hill that is 26m high. the skateboard weighs 2 N. the skateboard has _____energy. Calculate it.
A 1000kg truck is moving at a velocity of 4m/s what is it's momentum?
Answer:
4000 kg m/s
Explanation:
p=mv
p = momentum in kg m/sm = mass in kgv = velocity in m/ssubstitute values into the formula above to get:
p=1000x4
p=4000 kg m/s
What is the length of decay of carbon-14?
a.
A couple days
b.
A couple hours
c.
A couple seconds
d.
A few thousand years
Answer:
My answer will be (D) . A few thousand years
Explanation:
Carbon-14 is a radioactive isotope of carbon, containing 6 protons and 8 neutrons, that is present in the earth's atmosphere in extremely low concentrations.2
It is naturally produced in the atmosphere by cosmic rays (and also artificially by nuclear weapons), and continually decays via nuclear processes into stable nitrogen atoms.
Suppose we have a sample of a substance containing some carbon-14. Let m be the mass of carbon-14 in nanograms after t years. 3
It turns out that, if the sample is isolated, then m and t approximately 4 satisfy the differential equation
dmdt=−0.000121m.
Suppose our sample initially contains 100 nanograms of carbon-14. Let's investigate what happens to the sample over time.
First, we can solve the differential equation. Since m has a continuous decay rate of −0.000121, a general solution to the differential equation is
m(t)=Ce−0.000121t,
where C is a constant. Substituting the initial condition t=0, m=100 gives C=100, so
m(t)=100e−0.000121t.
With this formula, we can calculate the amount m of carbon-14 over the years.
Mass of carbon-14 in sample
t (years) m (ng to 4 decimal places)
0 100.0000
100 98.7973
1000 88.6034
2000 78.5056
5000 54.6074
10 000 29.8197
20 000 8.8922
Every year, the mass m of carbon-14 is multiplied by e−0.000121≈0.999879. After 100 years, 98.7973 nanograms still remain. After 1000 years, we still have 88.6034 nanograms. But after 5000 years, however, almost half of the carbon-14 has decayed.
Graph showing the decay of 100 nanograms of Carbon-14.
Detailed description
half-life of carbon-14
Example
How long does it take for precisely half of the carbon-14 in the sample to decay; that is, when does m=50? Give the answer to three significant figures.
Solution
The mass of carbon-14 in our sample is given by
m(t)=100e−0.000121t.
So we solve 50=100e−0.000121t, which gives e−0.000121t=12. Hence,
t=loge12−0.000121≈5730 years (to three significant figures).
The time period calculated in this example is called the half-life of carbon-14. In fact over any period of 5730 years, the amount of carbon-14 in an isolated sample will decay by half. This fact is used in radiocarbon dating to determine the age of fossils up to 60 000 years old. Roughly speaking, while an organism is alive, its interactions with its environment maintain a constant ratio of carbon-14 to carbon-12 in the organism; but after it dies, the carbon-14 is no longer replenished, and the ratio of carbon-14 to carbon-12 decays in a predictable way. (See Wikipedia Open new window for more on radiocarbon dating.)
Exercise 1
Explain why the mass of carbon-14 in the sample is given (approximately) by
m(t)=100(12)t5730,
and hence explain why the amount of carbon-14 in the sample decays by half over any period of 5730 years.
Half-life in general
In general, whenever a quantity x(t) obeys an exponential decay equation
x(t)=Cekt,
where the continuous decay rate k is negative, then the quantity x has a half-life T. After any time period of length T, the quantity x decreases by half. Let us see why.
As k is negative, the factor ekt decreases from 1 (at t=0) towards 0 (as t approaches ∞). Therefore there is a time t=T such that
ekT=12.
We now solve for T and obtain
kT=loge12=−loge2,
so
T=−1kloge2.
This T is the half-life. From time t=0 to time t=T, the factor ekt decreases from e0=1 to ekT=12, that is, decreases by half. Similarly, over any time period of length T, the term ekt decreases by half. 5
Note that, when k=−0.000121, we obtain T=5730, in agreement with our calculation for carbon-14.
Hope this work
If I'm wrong I'm sorry
If I'm right thank you (brainliest plz )
A 1500kg car is moving uniformly at 10 m/s2 down the road for 1250 meters in 60 seconds. How much power did the car have during this time?
Answer:
[tex]3.125\times 10^{5}watt[/tex]
Explanation:
We are given that
Mass of car, m=1500 kg
Acceleration,[tex]a=10m/s^2[/tex]
Distance, s=1250 m
Time, t=60s
We have to find the power of car during this time.
We know that
Force, F=ma
Using the formula
[tex]F=1500\times 10=15000N[/tex]
Work done, W=Fs
Work done, W=[tex]15000\times 1250[/tex]
Power, P=[tex]\frac{work\;done}{time}[/tex]
Using the formula
Power, P=[tex]\frac{15000\times 1250}{60}[/tex]
Power, P=312500watt
Power, P=[tex]3.125\times 10^{5}watt[/tex]
What is the charge on an object that experiences a force of 5 Newtons in an electric field of 50 Newtons per coulomb?
Answer:
Explanation:
F = qE
F is the force in Newtons
q is the test charge
E is the electrical field produced by the source charge
[tex]5=q(50)\\q=1*10^-^1Coulombs[/tex]
The magnitude of charge on the object is of 0.1 C.
Given Data:
The magnitude of electric field is, E = 50 N/C.
The magnitude of Electric force is, F = 5 N.
The region where any particle feels the effect of electric force on itself, due to other charged entities, is known as Electric field. And the relation between the electric force and electric field is given as,
F = E × q
Here,
q is the magnitude of charge on the object.
Solving as,
q = F/E
q = 5 / 50
q = 0.1 C
Thus, we can conclude that the magnitude of charge on the object is of 0.1 C.
Learn more about the electric field here:
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A coin is dropped off of a building landing on its side. It hits with a pressure of 400/2 It hits with a force of 0.1 Calculate the area of the coin?
Complete Question:
A coin is dropped off of a building landing on its side. It hits with a pressure of 400 N/m². It hits with a force of 0.1N. Calculate the area of the coin?
Answer:
Area = 0.00025 m²
Explanation:
Given the following data;
Pressure = 400N/m²
Force = 0.1N
To find the area of the coin;
Pressure = Force/area
Area = Force/pressure
Substituting into the equation, we have;
Area = 0.1/400
Area = 0.00025 m²
Question 2 options:
A ________ is an ability that allows you to perform a specific task effectively.
Answer: The answer is Skill
Explanation:
In the image is a type of energy? What is it?
What is the specific heat capacity of a 250g object that needs 34.125kJ to have its own temperature raised by 65.0∘C
Answer:
Specific heat capacity, = 2.1J/g°C
Explanation:
Given the following data;
Mass = 250g
Quantity of heat = 34.125kJ = 34.125 * 1000 = 34125 Joules.
Change in temperature = 65.0∘C
To find the specific heat capacity;
Heat capacity is given by the formula;
[tex] Q = mcdt[/tex]
Where;
Q represents the heat capacity or quantity of heat.
m represents the mass of an object.
c represents the specific heat capacity of water.
dt represents the change in temperature.
Making c the subject of formula, we have;
[tex] c = \frac {Q}{mdt} [/tex]
Substituting into the equation, we have;
[tex] c = \frac {34125}{250*65} [/tex]
[tex] c = \frac {34125}{16250} [/tex]
Specific heat capacity, = 2.1J/g°C
A 1 kg block with initial velocity 4 m/s collides elastically with a stationary 2 kg block. After the collision, the 1 kg block has a velocity of -1.33 m/s. Determine the speed of the 2 kg block after the collision.
Answer:
v₂ = 2,665 m / s
Explanation:
This is an exercise of conservation of the momentum, we define a system formed by the two cars, so that the forces during the collision are internal and the moment is conserved.
Initial instant. Before the crash
p₀ = m v_o
Final moment. Right after the crash
p_f = m v₁ + M v₂
where the first car uses subscript 1 and has a mass m = 1 kg and the second car uses the subscript 2 with a mass M = 2kg
how the moment is preserved
p₀ = p_f
m v_o = m v₁ + M v₂
They indicate that the collision is elastic, therefore the kinetic energy is conserved, the velocity of the first car is v1 = -1.33 me / S
v₂ = [tex]\frac{ m ( v_o - v_1)}{M}[/tex]
we calculate
v₂ = [tex]\frac{ 1 ( 4 + 1.33)}{2}[/tex]
v₂ = 2,665 m / s
Q.1- A 3000 cm3 tank contain O2 gas at 20 °C and a gauge pressure of 2.5 x 106 Pa. Find the mass of oxygen in the tank.
3. Gravitational potential energy depends on the ____ and _____ of the object
What are your initial thoughts on pro athletes salaries? Do you believe that athletes are paid too much? Why or why not
Answer:
Pro athletes are professional athletes, they are professional in their field. They are not paid too much in my thoughts.
Explanation:
I do not believe that professional athletes are paid too much or over paid. These group of athletes have become professionals in their fields after many years of training, they are highly talented with extra ordinary physical abilities. More so, fans love to watch them play and pay to watch them because they enjoy them. They are get sponsors due to the great crowd they attract.
What type of wave interaction causes dead spots?
Refraction
Reflection
Constructive Interference
Destructive interference
When we say the energy in a system remains "constant" what we really
mean is...
1 point
the total amount of energy goes up
the total amount of energy remains the same
the total amount of energy goes down
the speed remains the same
of the following is NOT a form of energy?
The total amount of energy remains the same.
4.
State the laws of reflection.
which system of units is used by only a small number of countries in the world, including the u.s
Answer:
imperial system
Explanation:
Answer:
british system
Explanation:
A P E X
5.Noise pollution is harmful forRequired to answer. Single choice.Immersive Reader
(1 Point)
Human
Cat
Bird
All
Answer:
D: All
Explanation:
In cats, noise pollution causes what is known as acoustic stress in them.
In birds, noise pollution delays their nesting because it makes their songs which they use to probe to be at a low frequency.
Noise pollution affects humans because it can lead to loss of hearing, sleep disturbance, stress, high blood pressure e.t.c
Therefore, it affects Cats, birds and humans.
So option D is correct.
Help, please!!!!!
I just need help putting the vocab word in the box where it belongs.
here's the first part but for the 2nd one all I know is that the word "compression" goes on the spirals that are closer together.
hope this helps!
how high is the pole from which the lamp fell freely if it hits the ground at a speed of 15 m/s
Answer & Explanation:
The acceleration due to gravity is about 10 m/s^2.
That means a the speed of a falling object will increase by 10 m/s every second that it falls.
We know that the lamp hits the ground at 15 m/s.
That means the lamp has been falling for
[tex]\frac{15 m/s}{10 m/s^{2} } = 1.5 s[/tex]
Now we use the formula [tex]h = \frac{1}{2} gt^{2}[/tex] to calculate the height, where
h is the height
g is the acceleration due to gravity and
t is the time taken to fall a height of h.
h = 1/2 x 10 x 1.5^2 = 11.25 m
Imagine a universe in which, like in ours, there are two kinds of charges (positive and negative), with the like charges repelling and unlike charges attracting each other, but with the electric force somewhat different from Coulomb's Law. Instead of varying with inverse distance squared, the force between charges in this imagined world would vary with the inverse distance cubed. In such a universe, would the static charges still always be distributed on the surfaces of conductors?
Answer:
the static charge is not always distributed on the surface of the conductor, there are also charges in the volume but of lesser magnitude
Explanation:
In this hypothetical system the electric force is of type
F = [tex]k' \frac{q_1 q_2 }{r^2}[/tex]
in this case the force decays to zero much faster,
if we call Fo the force of Coulomb's law
F₀ = [tex]k \frac{q_1 q_2 }{r^2}[/tex]
assuming the constant k is the same
the relationship between the two forces is
F / F₀ = 1 / r
F = F₀ / r
when analyzing this expression the force decays much faster to zero.
In an electric conductor, charges of the same sign may not feel any repulsive force from other charges that are at a medium distance, so there is a probability that some charges are distributed in the volume of the material, this does not happen with coulomb's law
Consequently, the static charge is not always distributed on the surface of the conductor, there are also charges in the volume but of lesser magnitude