Answer:
[tex]h=1.60\mu m[/tex]
Explanation:
Hello,
In this case, given the density and the mass of the aluminum foil, we can compute the occupied volume as shown below:
[tex]\rho =\frac{m}{V}\\ \\V=\frac{m}{\rho}=\frac{2.07g}{2.7g/cm^3} =0.767cm^3[/tex]
Next, since the volume is defined as:
[tex]V=24cm*20cm*h[/tex]
Whereas [tex]h[/tex] accounts for its thickness, we can find it to be:
[tex]h=\frac{V}{24cm*20cm}=\frac{0.767cm^3}{20cm*24cm}\\ \\h=1.60x10^{-3}cm*\frac{10000\mu m}{1cm} \\\\h=1.60\mu m[/tex]
Regards.
How many seconds (s) are needed to deposit 7.25 g of copper metal from an aqueous solution of CuCl2, using a current of 3.1 Amps.
Answer:
7,052.6secs
Explanation:
n of Cu = +2
R.A.M of Cu = 64g
m = 7.25g
I = 3.1A
F = 96500
nF = R.A.M
It = m
2*96500 = 64
3.1*t = 7.25
1,399,250 = 198.4t
t = 7,052.6secs
Students in a science class placed ice cubes in a cup. They were studying variables that affected how long it takes the ice to melt. Select the variable that
would most likely NOT affect the time it takes the ice to melt.
O Size of cup
O Size of ice cube
O Number of students
O Temperature of the room
Answer:
Number of students-this has nothing to do with the question, its called a distractor.
The variable that would most likely not affect the time it takes the ice to melt is the Number of students. The correct option is C.
What are the variables in the experiments?Variables are the different substances or objects that participate in the experiment directly or indirectly. They are substances that together form the experiment. These variables impact the result of the experiment.
There are two types of variables. They are Dependent and independent variables. Dependent variables can be controlled in the experiment, but independent variables can't be controlled.
Students are performing the experiment, so they cannot be the variables because their presence or absence would be to impact the experiment.
Thus, the correct option is C. Number of students.
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An unknown gas diffusion 0.25 times as fast as he .what is the molecules mass of the unknown gas
Answer:
identical conditions, separate samples of O2 and an unknown gas were allowed to effuse through identical membranes simultaneously. After a certain amount of time, it was found that 6.23 mL of O2 had passed through the membrane, but only 3.85 mL of of the unknown gas had passed through. What is the molar mass of the unknown gas
identical conditions, separate samples of O2 and an unknown gas were allowed to effuse through identical membranes simultaneously. After a certain amount of time, it was found that 6.23 mL of O2 had passed through the membrane, but only 3.85 mL of of the unknown gas had passed through. What is the molar mass of the unknown gas
Explanation:
identical conditions, separate samples of O2 and an unknown gas were allowed to effuse through identical membranes simultaneously. After a certain amount of time, it was found that 6.23 mL of O2 had passed through the membrane, but only 3.85 mL of of the unknown gas had passed through. What is the molar mass of the unknown gas
Calculate the solubility of PbF2 in water at . You'll find data in the ALEKS Data tab. Round your answer to significant digits.
Answer:
0.5 g/L.
Explanation:
Hello,
In this case, for this solubility problem, we can write for the lead (II) fluoride:
[tex]PbF_2(s)\rightleftharpoons Pb^{2+}(aq)+2F^-(aq)[/tex]
And the equilibrium expression is:
[tex]Ksp=[Pb^{2+}][F^-]^2[/tex]
Whereas Ksp of lead (II) fluoride is 3.3x10⁻⁸. In such a way, we can write the equilibrium expression in terms of the molar solubility [tex]x[/tex] as follows:
[tex]Ksp=(x)(2x)^2=3.3x10^{-8}[/tex]
Hence, solving for [tex]x[/tex] we find:
[tex]x=\sqrt[3]{\frac{3.3x10^{-8}}{4} }\\\\x=2.02x10^{-3}M[/tex]
Moreover, since the molar mass of lead (II) fluoride is 245.2 g/mol, the solubility turns out:
[tex]2.02x10^{-3}\frac{molPbF_2}{L}*\frac{245.2gPbF_2}{1molPbF_2}\\ \\0.5\frac{g}{L}[/tex]
Best regards.
Calculate the pH of a 0.10 M HCN solution that is 0.0070% ionized.
A) 1.00
B) 0.00070
C) 3.15
D) 5.15
E) 7.00
Answer:
D) 5.15
Explanation:
Step 1: Write the equation for the dissociation of HCN
HCN(aq) ⇄ H⁺(aq) + CN⁻(aq)
Step 2: Calculate [H⁺] at equilibrium
The percent of ionization (α%) is equal to the concentration of one ion at the equilibrium divided by the initial concentration of the acid times 100%.
α% = [H⁺]eq / [HCN]₀ × 100%
[H⁺]eq = α%/100% × [HCN]₀
[H⁺]eq = 0.0070%/100% × 0.10 M
[H⁺]eq = 7.0 × 10⁻⁶ M
Step 3: Calculate the pH
pH = -log [H⁺] = -log 7.0 × 10⁻⁶ = 5.15
The pH of the 0.10 M HCN solution that is 0.0070% ionized is 5.15 and the correct option is option D.
pH is a measure of the acidity or alkalinity of a solution. It is a logarithmic scale that indicates the concentration of hydrogen ions (H+) in the solution.
The pH scale ranges from 0 to 14, where a pH of 7 is considered neutral, pH values below 7 indicate acidity, and pH values above 7 indicate alkalinity.
The pH of a solution can be calculated using the formula:
pH = -log[H+]
Where [H+] represents the concentration of hydrogen ions in moles per liter.
Since HCN is a weak acid and only 0.0070% of it is ionized, assuming that the concentration of H+ ions is equal to 0.0070% of 0.10 M HCN.
0.0070% of 0.10 M HCN = (0.0070/100) × 0.10
= 0.000007 M
pH = -log(0.000007)
= 5.15
Thus, the ideal selection is option D.
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Give the effect on the melting point of the presence of a cis double bond in a fatty acid.
Answer:
The cis double bond present in unsaturated fatty acids acids results in lower melting point when compared to saturated fatty acids of the same chain length.
Explanation:
Melting point of a fatty acids are affected by the length and degree of unsaturation of the hydrocarbon chain.
At room temperature, saturated fatty acids with hydrocarbon chain lengths between 12-24 are waxy solids whereas unsaturated atty acids of the same chain length are liquids. This is due to the nature of the packing of the fatty acid molecules in the saturated and unsaturated compounds.
In the saturated compounds, the molecules are tightly packed side by side with minimal steric hindrance and maximal van der Waals forces of attraction between molecules. However, in unsaturated fatty acids, the cis double bond introduces a bend or kink in the molecules which then interferes with the tight packing of the molecules and reducing interaction between molecules. Therefore, less energy is required to cause a disorder in the arrangement of unsaturated fatty acids, leading to a lowering of melting point.
3. How many significant figures are in the number 805000? *
Answer:
3
Explanation:
Three significant figures
A student is designing an experiment about the factors that affect math
grades. Which statement best represents a possible hypothesis for this
experiment?
O A. I think practicing math problems is the most important factor in a
student's math grade.
OB. If students spend at least 1 hour per night studying math, then
they will get a grade of 85 or higher.
C. Students who study more get higher math grades.
O D. Steve studied math for 1 hour every night and got a grade of 87.
Answer:
B. If students spend at least 1 hour per night studying math, then they will get a grade of 85 or higher.
Explanation:
A hypothesis is defined as a tentative or predictions or an educated guess of scientific questions. A hypothesis is always done before performing an experiment.
The correct hypothesis for the given experiment will be "If students spend at least 1 hour per night studying math, then they will get a grade of 85 or higher" because it has an if-then statement which is a conditional statement where statement after "if represents hypothesis" and "then represents conclusion".
Hence, the correct answer is "B. If students spend at least 1 hour per night studying math, then they will get a grade of 85 or higher."
What is the definition of weight
Answer:
Weight is a noun that means a human body's mass.
For example: Joh is 168 pounds.
This is the correct definition of weight.
Here to help!
1. Aluminum forms a layer of aluminum oxide when exposed to air which protects the bulk metal from further corrosion.
4Al(s) + 3O2(g) ? 2Al2O3(s)
Using the thermodynamic data provided below, calculate S° for this reaction.
S°(J/K.mol)
Al(s) 28.3
O2(g) 205.0
Al2O3(s) 50.99
2. Aluminum forms a layer of aluminum oxide when exposed to air which protects the bulk metal from further corrosion.
4Al(s) + 3O2(g) ? Al2O3(s)
Calculate G° for this reaction, given that ?G°f of aluminum oxide is –1576.4 kJ/mol.
Answer:
Al(s) 28.3
Explanation:
Aluminum forms a layer of aluminum oxide when exposed to air which protects the bulk metal from further corrosion.
Aluminum forms a layer of aluminum oxide when exposed to air which protects the bulk metal from further corrosion.4Al(s) + 3O2(g) ? Al2O3(s)
AnswerAluminum forms a layer of aluminum oxide when exposed to air which protects the bulk metal from further corrosion.
4Al(s) + 3O2(g) ? 2Al2O3(s)
Using the thermodynamic data provided below, calculate S° for this reaction.
S°(J/K.mol)
Al(s) 28.3
O2(g) 205.0
Al2O3(s) 50.99
2. Aluminum forms a layer of aluminum oxide when exposed to air which protects the bulk metal from further corrosion.
4Al(s) + 3O2(g) ? Al2O3(s)
Calculate G° for this reaction, given that ?G°f of aluminum oxide is –1576.4 kJ/mol.
Answer:
Explanation:
Explanation:
find the value of y in the equation Зу – 20 = 7.
[tex]3y-20=7\implies y=\frac{20+7}{3}=9[/tex].
Hope this helps.
y= 9
Explanation:
=> 3y - 20 = 7
=> 3y = 7+20
=> 3y = 27
=> y = 27/3
=> y = 9
HOPE OT HELPS. ◉‿◉
Which of the following molecules has a characteristic broad stretch at 3300 cm-1?
A) (CH3)2CHCH2OH
B) (CH3)3CH
C) (CH3)2CHCCCH3
D) (CH3)2CHCH=CH2
E) (CH3)2CHCO2CH3
Answer:
The answer is "Option A"
Explanation:
At 3300 cm-1, the wide region is equal to OH. It is a possible group of alcoholic features that includes drugs. In the given choices option a is correct that's the structure can be defined in attachment file please find it, and the wrong choice can be defined as follows:
In choice B, It is wrong because it doesn't include OH. In choice C, it uses the triple bond, that's why it is wrong. In choice D, it uses the two bonds, that's why it is wrong. In choice E, it uses the characteristic bond, that's why it is wrong.A rigid tank contains 1.80 moles of nitrogen, which can be treated as an ideal gas, at a pressure of 25.5 atm. While the tank and gas maintain a constant volume and temperature, a number of moles are removed from the tank, reducing the pressure to 5.70 atm. How many moles are removed
Answer:
1.4 moles.
Explanation:
The following data were obtained from the question:
Initial mole (n1) = 1.8 moles
Initial pressure (P1) = 25.5 atm
Final pressure (P2) = 5.7 atm
Number of mole removed =?
Next, we shall obtain an expression relating pressure and number of mole together.
This is illustrated below:
From the ideal gas equation:
PV = nRT
Divide both side by V
P = nRT /V
Divide both side by n
P/n = RT/V
But volume (V) and temperature (T) are constant.
P/n = constant
P1/n1 = P2/n2
P1 is initial pressure.
P2 is final pressure.
n1 is the initial mole.
n2 is the final mole.
Next, we shall determine the final mole in tank as follow:
Initial mole (n1) = 1.8 moles
Initial pressure (P1) = 25.5 atm
Final pressure (P2) = 5.7 atm
Final mole (n2) =.?
P1/n1 = P2/n2
25.5/1.8 = 5.7/n2
Cross multiply
25.5 x n2 = 1.8 x 5.7
Divide both side by 25.5
n2 = (1.8 x 5.7) /25.5
n2 = 0.40 mole.
Therefore, the final mole in the tank is 0.40 mole.
Finally, we shall determine the number of mole that was removed as follow:
Initial mole (n1) = 1.8 moles
Final mole (n2) = 0.4 mole
Number of mole removed =?
The number of mole removed from the tank can be obtained by finding the difference between the initial mole and final mole as illustrated below:
Number of mole removed = initial mole – final mole
Number of mole removed = n1 – n2
Number of mole removed = 1.8 – 0.4
Number of mole removed = 1.4 moles
Therefore, 1.4 moles were removed from the tank.
PLEASE HELP WILL GIVE BRAINLIEST!!!!
Xenon-133 has a half life of 5.2 days. A 237 gram sample of Xenon is collected and stored. It is later measured to be 29.625 grams. How long has it been in storage?
A. 15.6 days
B. 39.9 days
C. 20.8 days
D. 8 days
Answer:
A. 15.6 days
Explanation:
We have a general formula used to solve for questions dealing with half life.
N(t) = No (1/2)^t/t½
Where
N(t) = Quantity of sample left after t days
No = Initial amount of sample
t½ = Half life of sample
t = Duration or time required for sample to decay
In the above question, we are asked to determine how long(time) that the sample has been in storage.
The formula for time (t) has been derived as:
t =[ t½ × In(Nt/No)] ÷ - In 2
Where
No = 237 grams
N(t) = 29.625 grams
t½ = 5.2 days
t = ????? Unknown
t = [ t½ × In(Nt/No)] ÷ - In 2
t = [ 5.2 × In(29.625/237)] ÷ - In 2
t = [5.2 × -2.0794415417] ÷ - In 2
t = -10.813096017 ÷ - ln 2
t = 15.6 days
Therefore, the sample has been in storage for 15.6 days.
HCl(aq) + NaOH(aq) ––––> NaCl(aq) + H2O(l) What volume of 0.631 M HCl is required to react with 15.8 mL of 0.321 M NaOH?
Answer:
The correct answer is 8.04 mL
Explanation:
Given the neutralization reaction:
HCl(aq) + NaOH(aq) ––––> NaCl(aq) + H₂O(l)
1 mol of HCl reacts with 1 mol of NaOH.
The number of moles of NaOH there is in 15.8 mL is calculated as follows:
0.321 mol/L x 1 L/1000 mL x 15.8 mL = 5.07 x 10⁻³ mol NaOH
Thus, we need 5.07 x 10⁻³ mol of HCl to react with 5.07 x 10⁻³ mol NaOH. We have a 0.631 M HCl solution. We calculate the volume of HCl we need by considering that 1 mol NaOH reacts with 1 mol HCl and that there are 0.631 moles of HCl in 1 liter of solution (1000 mL):
5.07 x 10⁻³ mol NaOH x 1 mol HCl/1 mol NaOH x 1000 mL/0.631 mol HCl = 8.04 mL
The value of the equilibrium constant for a reaction is 2.65 x 10-6 at 35° Calculate the value of LaTeX: \DeltaΔG°rxn.
Answer:
The answer is "33.95 [tex]\bold{ \frac{kj}{mol}}\\[/tex]".
Explanation:
Formula:
[tex]\bigtriangleup G_0= -R \times T l_n \times K_{eq}\\[/tex]
where
[tex]K_{eq} = \text{equilibrium constant}\\[/tex]
Given value:
[tex]T =35^{\circ} C\\[/tex]
convert temperature celsius (°C) to Kelvin (K):
[tex]= (273+45) \ kelvin \\\\= 318 \ Kelvin \\\\= 318 \ K[/tex]
[tex]R = 8.314 \ \ \frac{J}{ mol \cdot K}[/tex]
[tex]\bigtriangleup G_0= -(8.314 ) \times 31.8 \times l_n (2.65\times 10^{-6})\\[/tex]
[tex]=-(8.314 ) \times 31.8T l_n \times (2.65\times 10^{-6})\\\\[/tex]
After solving the value it will give:
= 33.95 [tex]\bold{ \frac{kj}{mol}}\\[/tex]
Which has the greatest mass?a. one atom of carbon, b. one atom of hydrogenc. one atom of lithium
Answer:
one atom of carbon
Explanation:
The relative atomic mass of elements can be used to determine their relative masses. If we look at all the options, we will notice that carbon has a relative atomic mass of 12, hydrogen has a relative atomic mass of 1 and lithium has a relative atomic mass of 7
We can now see that carbon has the greatest relative atomic mass among the options provided in the question.
One of these two substances is a liquid at room temperature and the other one is a gas. Which one is the liquid and why?
A. CH3OCH3
B. CH3CH2OH
Answer:
B. CH3CH2OH
Explanation:
Ethanol has a chemical formula of CH3CH2OH, it is the second member of the series in the alkanol family. Ethanol is a colourless, volatile liquid with a characteristic smell and taste. It is readily soluble in water in all proportions. It has a boiling point of 78° C. The physical properties such as the solubility of alkanols are affected by the presence of hydrogen bonding. The hydroxyl group is capable of bonding to other alkanol molecules. The boiling points rise with increasing molecular mass.
Hydrogen bonding helps the molecules to stick together. For example comparing the boiling point of pentane ( 36° C) with that of butan-1-ol (118° C) , the boiling point of alkanol is much higher even though the two compound are of similar relative molecular mass. This is due to the presence of hydrogen bonds in butanol.
Hydrocarbons are not soluble in water but alkanols are soluble in water because of the hydroxyl groups in the molecules can form hydrogen bond with water. Solubility of alkanol in water decreases as the number of carbon atom increases. Primary alcohol with more than five carbon atoms are insoluble in water.
Select the conjugate acid-base pair(s). a) HI, I b) HCHO2, SO4^2- c) CO3^2-, HCI d) PO4^3-, HPO4^2-
Answer:
d) PO4^3-, HPO4^2-
Explanation:
Basically, an acid and a base which differs only by the presence or absence of proton (hydrogen ion) are called a conjugate acid-base pair.
a) HI, I
This is incorrect. For the acid, HI the conjugate base is I⁻ ion.
b) HCHO2, SO4^2-
This is incorrect, there's no relationship between both entities.
c) CO3^2-, HCI
This is incorrect, there's no relationship between both entities.
d) PO4^3-, HPO4^2-
This is correct. The difference between both entities is the Hydrogen ion. This is the conjugate acid-base pair
Write the molecular balanced chemical equation and the net ionic equation for the reaction between Ca(OH)2(aq) and HCl(aq).
Answer:
1. Balanced Molecular equation
Ca(OH)2(aq) + 2HCl(aq) —> CaCl2(aq) + 2H2O(aq)
2. Net ionic equation
OH-(aq) + H+(aq) —> H2O(l)
Explanation:
1. Molecular balance equation for the reaction between Ca(OH)2(aq) and HCl(aq).
This is illustrated below:
Ca(OH)2(aq) + HCl(aq) —> CaCl2(aq) + H2O(aq)
There are 2 atoms of Cl on the right side and 1 atom on the left side. It can be balance by putting 2 in front of HCl as shown below:
Ca(OH)2(aq) + 2HCl(aq) —> CaCl2(aq) + H2O(aq)
There are 2 atoms of H on the right side and a total of 4 atoms on the left side. It can be balance by putting 2 in front of H2O as shown below:
Ca(OH)2(aq) + 2HCl(aq) —> CaCl2(aq) + 2H2O(aq)
Therefore the equation above is balanced.
2. Net ionic equation for the reaction between Ca(OH)2(aq) and HCl(aq).
In solution, Ca(OH)2(aq) and HCl(aq) will dissociate as follow:
Ca(OH)2(aq) —> Ca2+(aq) + 2OH-(aq)
HCl(aq) —> H+(aq) + Cl-(aq)
Ca(OH)2(aq) + 2HCl(aq) —>
Ca2+(aq) + 2OH-(aq) + 2H+(aq) + 2Cl-(aq) —> Ca2+(aq) + 2Cl-(aq) + 2H2O(l)
Cancel out the spectator ions i.e Ca2+ and Cl- to obtain the net ionic equation
2OH-(aq) + 2H+(aq) —> 2H2O(l)
OH-(aq) + H+(aq) —> H2O(l)
0.200 grams of HCl is dissolved in 0.801 grams water. The density of the solution formed is 1.10 g/mL. What is the molarity of the solution
Answer:
[tex]M=6.03M[/tex]
Explanation:
Hello,
In this case, since the molarity is computed by:
[tex]M=\frac{n_{solute}}{V_{solution}}[/tex]
Whereas the solute is the hydrochloric acid, we compute the corresponding moles with its molar mass (36.45 g/mol):
[tex]n_{solute}=0.200gHCl*\frac{1molHCl}{36.45gHCl} =0.00549molHCl[/tex]
Next, since the solution contains both HCl and water, we compute the volume in liters by using its density:
[tex]V_{solution}=(0.200+0.801)g*\frac{1mL}{1.10g} *\frac{1L}{1000mL} =9.1x10^{-4}L[/tex]
Therefore, the molarity turns out:
[tex]M=\frac{0.00549mol}{9.1x10^{-4}L}\\ \\M=6.03M[/tex]
Regards.
A mixture containing only FeCl3 and AlClz weighs 5.95 g . The chlorides are converted to the hydrous oxides and ignited to Fe2O3 and Al2O3 . The oxide mixture weighs 2.62 g . Calculate the percent Fe and Al in the original mixture .
Answer:
The answer is "Al= 9.8% and Fe=18.0%"
Explanation:
Given:
The weight of [tex]FeCl_3\ and \ ALCl_3[/tex] = 5.95g
[tex]gFeCl_3=gFe (\frac{Mw\ FeCL_3}{\text{atomic weight of Fe}})\\\\gAlCl_3=gAl (\frac{Mw\ AlCL_3}{\text{atomic weight of Al}})\\\\[/tex]
[tex]\to a = FeCl_3+AlCl_3\\\\\to a=x+y \\\\ \to a= 5.95[/tex]
[tex]\to a =x \ gFe (\frac{Mw\ FeCL_3}{\text{atomic weight of Fe}})+ y \ gAl (\frac{Mw\ AlCL_3}{\text{atomic weight of Al}})\\\\[/tex]
[tex]\to x (\frac{162.2}{55.85})+ y (\frac{133.34}{26.98})= 5.95\\\\\to 2.90x+4.94y=5.95\\\\\ similarly \ for \ oxidies:\\\\\to 143x+1.89y=2.62\\\\\to x= 1.07 \ \ \ and \ \ y= 0.58\\\\\to \ Al \% = \frac{0.58}{5.95} \times 100= \bold{9.8} \%\\\\\to \ Fe \% = \frac{1.07}{5.95} \times 100= \bold{18.0} \%[/tex]
The mass of the compound has been given as the mass of each element in the compound. The percent Fe in the mixture is 18%, and the percent Al in the mixture is 9.8%.
What is the percent composition?The percent composition has been given as the mass of the element in the compound. The percent of iron and aluminum in their chlorides can be given as:
[tex]\rm Fe=Fe\;\times\;\dfrac{Mwt\;FeCl_3}{Mwt\;Fe}[/tex]
[tex]\rm Al=Al\;\times\;\dfrac{Mwt\;AlCl_3}{Mwt\;Al}[/tex]
The total mass of the compounds has been 5.95 grams.
Thus,
[tex]5.95=\rm FeCl_3+AlCl_3[/tex]
The mass of Fe and Al will be x and y of the mass in the compounds. Thus,
[tex]5.95=\rm x\;Fe\;\times\;\dfrac{Mwt\;FeCl_3}{Mwt\;Fe}\;+\;y\;Al\;\times\; \dfrac{Mwt\;AlCl_3}{Mwt\;Al}[/tex]
The oxides of the chemical has the sum of mass of 2.62 grams.
The mass of oxides can be given as:
[tex]2.62=\rm x\;Fe\;\times\;\dfrac{Mwt\;Fe2O_3}{Mwt\;Fe}\;+\;y\;Al\;\times\; \dfrac{Mwt\;Al_2O_3}{Mwt\;Al}[/tex]
Substituting the values of mass of Al, aluminum chloride, oxide, and Fe and its compounds.
[tex]\rm 2.90x+4.94y=5.95\\143x+1.89y=2.62[/tex]
Solving the equation, x = 1.07, and y = 0.58
The percent mass of the compounds has been given as the ratio of mass with compound mass.
Thus, the percent mass of Fe has been:
[tex]\rm Fe=\dfrac{1.07}{5.95}\;\times\;100\\ Fe=18\;\%[/tex]
The percent mass of Al has been:
[tex]\rm Al=\dfrac{0.58}{5.95}\;\times\;100\\ Al=9.8\;\%[/tex]
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Part B
What is the symbol of the atom obtained by adding one proton to 19F?
Express your answer as an isotope
Answer:
Neon
Explanation:
A proton is the positively charged particle in the atom. The atomic number of an atom is the number of protons present in the atom while the mass number of an atom is the sum of the number of protons and neutrons in the nucleus of an atom.
If an extra proton is added to 19F, then neon is formed.
Benzene exists as a resonance hybrid and its bonds exhibit characteristics that are halfway between single and double bonds. Resonance hybrids are best defined as
Answer:
Explanation:
We can only talk about resonance hybrid for a compound in which more than one structure is possible based on its observed chemical properties.
There are compounds whose chemical properties can not be satisfactorily explained on the basis of a single chemical structure. In the case of such compounds, we invoke the idea of resonance.
A resonance hybrid is a single structure drawn to represent a given chemical specie which exhibits resonance behaviour and can otherwise be represented on paper in the form of an average of two or more chemical structures separated each from the next by a double-headed arrow.
Answer:
Resonance hybrids are best defined as a molecule's electron pattern cannot be described by a single structure.
Explanation:
its right
Which one is most
stable.
A) primary alcohol.
B) secondary alcohol.
C) teritary alcohal.
Answer:
C
Explanation:
Tertiary alcohol should be the answer.
This is because tertiary alcohol has a less polar compound which means it is less likely to have chemical reaction with other compounds whereas primary and secondary alcohol has a higher chance of having chemical reaction with other compounds.
Answer:
I think the answer is A
Explanation:
primary alcohol has only one methyl group bonded to the central carbon atom, and the extent of decrease in partial posative charge is less, making it more prone to attack by nucleophiles. thus tertiary alcohols are more stable than primary alcohols
If you are not sure about what to do during a lab activity, what should you do?
Ask someone else at your table.
Use your best judgement.
Watch to see what everyone else isdoing.
Ask the teacher.
Answer:
ask a teacher is the correct answer.
Explanation:
You must ALWAYS ask a teacher if you are not sure about what to do during a lab activity.
Answer:
It's important to ask the teacher, lab safety policies all state that if you're confused about instructions it's always good to ask the teacher to clarify them.
Match.
The expression of concentration that provides the moles of solute per kilograms of solvent is _______.
A solution is made up of 0.15 grams of sodium chloride in 1 liter of water. For this solution,the_______ is water.
A solution is made up of 0.15 grams of sodium chloride in 1 liter of water. For this solution, the ________is sodium chloride.
If you place 5 moles of sodium chloride and 4 moles of sucrose into 11 moles of water, the ________of sodium chloride would be 0.25.
A way to express concentration that provides the moles of solute per liter of solution is _______-.
Solvent
Mole fraction
solute
pH
Molarity
Molality
Answer:
Molality, Solvent, Solute, Mole fraction, Molarity.
Explanation:
The expression of concentration that provides the moles of solute per kilograms of solvent is Molality. This in the only expression referred to the solvent.
A solution is made up of 0.15 grams of sodium chloride in 1 liter of water. For this solution, the Solvent is water. When water is present, it is usually considered the solvent.
A solution is made up of 0.15 grams of sodium chloride in 1 liter of water. For this solution, the Solute is sodium chloride. There can be 1 or more solutes in a solution.
If you place 5 moles of sodium chloride and 4 moles of sucrose into 11 moles of water, the Mole fraction of sodium chloride would be 0.25. The mole fraction is equal to the moles of a substance divided by the total number of moles.
A way to express concentration that provides the moles of solute per liter of solution is Molarity.
5
Select the correct answer.
Which of the following is a physical model of the Sun?
A.
an equation that describes the Sun's motion
B.
a chart that lists the temperatures of different parts of the Sun
O c.
a computer program that shows how the Sun changes over time
OD
a paragraph that describes the Sun's structure
O E.
a small yellow ball that represents the Sun
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Next
Answer:
E. a small yellow ball that represents the Sun
Explanation:
key word on the question, 'physical'
how many hydrogen atom are there in 5 moles of methyl alcohol
Answer:
20 hydrogen atoms in 5 moles of methyl alcohol.
Explanation:
Hi!
So, there are 4 hydrogen atoms in 1 mole of methyl alcohol. If you multiply 4*5, it equals to 20.
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Write the condensed nd structural formulas as well as the names for all isomers of C3H5Cl3.
Answer:
1) 1,1,1-trichloropropane
2) 1,1,2-trichloropropane
3) 1,2,2-trichloropropane
4) 1,2,3-trichloropropane
Explanation:
For this question, we must remember that isomers are molecules that have the same formula but different structures. For the formula [tex]C_3H_5Cl_3[/tex] we can draw a linear chain of three carbons and change the position of the chlorine atoms in the carbon chain.
With this in mind, if we put all the chlorine atoms on the same carbon we will get 1,1,1-trichloropropane. If we change an atom from chlorine to carbon 2 we will obtain 1,1,2-trichloropropane. If we move another chlorine atom to carbon two we will get 1,2,2-trichloropropane. Finally, if we put a chlorine atom in each carbon we will obtain 1,2,3-trichloropropane.
See figure one for further explanations
I hope it helps!