According to Ohm's Law, the total current flowing through a circuit with a resistance of 1200 ohms and a 12 V power supply is equal to 0.01 ampere.
Ohm's law is what?Electric current is inversely correlated with resistance according to Ohm's Law and proportionate to voltage. 'The law can be expressed mathematically as V = IR, in which 'V' is the voltage variation 'I' is the flowing current in amps, & the resistance (R) in ohm.
Given data :
Resistance = 1200 ohm
power supply = 12 V
By using Ohm's law
V = I × R
I = V / R
I = 12 / 1200
I = 0.01 ampere.
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Most of us know intuitively that in a head-on collision between a large dump truck and a subcompact car, you are better off being in the truck than in the car. Why is this? Many people imagine that the collision force exerted on the car is much greater than that exerted on the truck. To substantiate this view, they point out that the car is crushed, whereas the truck is only dented. This idea of unequal forces, of course, is false; Newton's third law tells us that both objects are acted upon by forces of the same magnitude. The truck suffers less damage because it is made of stronger metal. But what about the two drivers? Do they experience the same forces? To answer this question, suppose that each vehicle is initially moving at 6.60 m/s and that they undergo a perfectly inelastic head-on collision. Each driver has mass 75.0 kg. Including the masses of the drivers, the total masses of the vehicles are 800 kg for the car and 4,000 kg for the truck. If the collision time is 0.100 s, what force does the seat belt exert on each driver? (Enter the magnitude of the force.)
Answer:
According to Newton's third law, the force exerted on each driver during the collision is equal and opposite to the force exerted on their respective vehicles. We can use the principle of conservation of momentum to find the force experienced by each driver.
The initial momentum of the car and driver is the product of their mass and velocity: (800 kg)(6.60 m/s) = 5280 kgm/s. The initial momentum of the truck and driver is (4000 kg)(6.60 m/s) = 26400 kgm/s. After the collision, the final momentum of the combined system (the car, truck, and drivers) is 0, since the collision is perfectly inelastic and the two vehicles stick together. This means that the final momentum of the car and driver is equal and opposite to the final momentum of the truck and driver.
We can set up the following equation to solve for the force experienced by the car driver:
Force (car driver) = (final momentum of car and driver) / (collision time)
= (-final momentum of truck and driver) / (collision time)
= (-26400 kg*m/s) / (0.100 s)
= -26400 N
The negative sign indicates that the force is in the opposite direction of the initial momentum of the car and driver. The force experienced by the truck driver is equal in magnitude to the force experienced by the car driver, so the force experienced by the truck driver is also -26400 N.
Explanation:
for what emf e does the 200ω resistor in the following figure dissipate no power if δv = 150 v ?
The total power dissipated by the resistor is 150 V x 1.33 A = 199.5W.
Since the voltage of the battery is 150 volts, and the resistance of the resistor is 200ω, then the current through the resistor is equal to 150V/200ω = 1.33 A.
As a result, the resistor dissipates a total of 150 V x 1.33 A = 199.5 W of electricity.
Power in physics is the amount of energy that is transferred and converted in a given amount of time. The International System of Units uses the watt, or one joule per second, as the unit of power. In older texts, power is frequently referred to as activity. Power is a scalar quantity.
Other aspects have been linked to power; for example, the product of a ground vehicle's velocity, traction force on its wheels, and aerodynamic drag equals the power needed to propel the vehicle.
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4. A railcar of mass m and speed v collides and sticks to another identical, stationary railcar. The speed of the center of mass of the two-railcar system will be
The required speed of the centre of mass of the two-railcar system after the collision will be half as much as it was before the collision.
One of the railroads has zero motion prior to the collision. Following it, both railroads move at the same speed. By the conservation of the total momentum of the system, we have,
m vi = m vf + m vf
m vi = 2 m vf
vi = 2 vf
vf = 1/2 vi
vf is the velocity after collision
vi is the velocity before collision
Thus, the speed of the railroad together after the collision is calculated to be half of that before collision.
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Within galaxies there are billions of stars. Analyze the Hertzsprung Russell Diagram below and then choose the statements which are true, based on the diagram.
The Hertzsprung-Russell (H-R) Diagram is a graph that plots the luminosity (or absolute brightness) of stars against their surface temperature (or spectral type). It is used to classify stars based on their properties and understand their evolution.
The following statements are true based on the H-R diagram:
Most stars are located on the main sequence, which runs from the upper left to the lower right of the diagram. This represents stars that are burning hydrogen in their cores and are in a state of equilibrium.Stars located in the upper right corner of the diagram are brighter and hotter than those on the main sequence and are known as "giants" or "supergiants". They have exhausted the hydrogen in their cores and are in a later stage of their evolution.Stars located in the lower left corner of the diagram are cooler and less bright than those on the main sequence and are known as "dwarfs". These stars are in the early stages of their evolution and are still burning hydrogen in their cores.Stars located on the horizontal branch are burning helium in their cores, this represents stars that are in a different stage of their evolution.There is a clear relationship between a star's luminosity and its temperature, with hotter stars being brighter than cooler stars.The diagram shows that there is a wide range of luminosities and temperatures among stars, with some being much brighter and hotter than others.It's important to mention that the H-R diagram is a representation of the stars that are observed, and it's also based on the assumption that all stars are similar in their formation and evolution process.
The answer is general since no option is provided and similar question is nowhere to be found.
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Diana raises a 1000 N piano a distance of 5.00 m using a set of pulleys. She pulls in 20.0 m of rope. How much effort force did Diana apply if this was an ideal machine
The amount of effort force applied by Diana if this was an ideal machine is 250 N.
How is force effort determined?The load is typically divided by the number of ropes to determine the effort. The mass must be divided by the quantity of ropes.
What unit does effort refer to?Hours per person, days, weeks, or something else could be your unit of work. (If you are using a scrum-based project approach, you may have chosen to assess effort in relative terms, using points (story points), in which case you can omit any information in the Effort fields.)
What is an illustration of force of effort?For instance, when using a shovel, you keep one end steady to serve as the fulcrum and use the other hand to pull up on a load of dirt. The dirt being scooped up is the resistance force, and the second hand is the effort force.
Given:
Load force = 1000 N
Load distance = 5.00 m
Effort distance = 20.0 m
For ideal machine,
Effort force × Effort distance = Load force × Load distance
[tex]Effort force= \frac{1000*5.00}{20.0}[/tex]
Effort force = 250N
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In 1935, a french destroyer , La Terrible , started from rest and accelerates to attain a speed of 83km/h. Suppose it took 2 minutes for the ship to speed up. Find the ships average acceleration.
According to the given statement The ships average acceleration is 2790 km/hr².
What is an explain acceleration?A measure of how quickly motion's speed and direction change over time. When a point or object advances or decelerates, it is moving straight forward. Motion on a circle increases despite the same speed because the direction is always changing.
Calculation:We know that from newton's equation,
v² + u² = 2as
S = ut + 0.5 at²
Where, v = final speed
u = initial speed
a = acceleration
S = distance covered
t = time taken
Given, u = 0
So the equations becomes:
v² = 2as
S = 0.5 at²
Using these equations we get:
v² = 2a(0.5)at²
v² = a²t²
v = at
v/t = a
Given, v = 93 km/hr
t = 2 min = 2/60 hr
Putting these values in above equation we get, a = 2790 km/hr²
So, the ships average acceleration is 2790 km/hr²
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A 50.0-kg child stands at the rim of a merry-go-round of radius 2.70 m, rotating with an angular speed of 3.95 rad/s. What minimum coefficient of static friction is required
A 50.0-kg child stands at the rim of a merry-go-round of radius 2.70 m, rotating with an angular speed of 3.95 rad/s. Minimum coefficient of static friction is required 13.56.
To find the minimum coefficient of static friction required, we need to calculate the centrifugal force acting on the child and compare it to the force of friction.
The centrifugal force acting on the child is given by:
= Fc
= m * r * w^2
where
= m
= 50.0 kg (mass of child)
= r
= 2.70 m (radius of the merry-go-round)
= w
= 3.95 rad/s (angular velocity)
So, Fc = 50.0 kg * 2.70 m * (3.95 rad/s)^2
= 6629.775 N
The force of friction acting on the child is given by:
= Ff
= friction coefficient * normal force
where
friction coefficient = minimum coefficient of static friction required (unknown)
= normal force
= m * g
The normal force is equal to the weight of the child, which is
= m * g
= 50.0 kg * 9.8 m/s^2
= 490 N
So, Ff = friction coefficient * 490 N
To find the minimum coefficient of static friction, we need to set Ff equal to Fc and solve for the friction coefficient:
friction coefficient = Ff / N
friction coefficient = 6629.775 N / 490 N
= 13.56
So the minimum coefficient of static friction required is 13.56.
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An element has 1st, 2nd and 3rd ionization energies given in kJ mol-1. This element is a member of which group
An element has 1st, 2nd, and 3rd ionization energies given in kJ mol-1. The element in question is likely a member of the group known as the transition metals. This is because the elements in this group generally have higher ionization energies than other elements
For example, the first ionization energy of a transition metal is typically between 400 and 600 kJ/mol, the second ionization energy is typically between 1200 and 1600 kJ/mol, and the third ionization energy is typically between 2500 and 2800 kJ/mol. This range of ionization energies is consistent with the values given in the question. Transition metals are located in the middle of the periodic table, in between the s-block and the p-block elements.
They generally have higher melting points, densities, and boiling points than s-block elements and they display various oxidation states. All transition metals are metals, and they are usually the elements responsible for the color of compounds. Transition metals are also known for their catalytic properties, and they are often used as catalysts in various industrial and chemical processes. Furthermore, many transition metals are essential for life, including iron, cobalt, and copper. In conclusion, the element in question is likely a member of the transition metals group in the periodic table.
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An element has 1st, 2nd and 3rd ionization energies given in kJ mol-1. This element is a member of which group in the periodic table?
What is a way Accenture plans to achieve its sustainability goals by achieving net zero emissions through advanced robotics capabilities?
Accenture is leveraging its advanced robotics capabilities to reduce emissions and achieve its sustainability goals.
What do you mean by Emissions?
Emissions are substances that are released into the environment, usually as a result of human activities. These substances can be in the form of gases, particles, or radiation, and they can be either natural or man-made. Common emissions include carbon dioxide, methane, and other greenhouse gases, as well as air pollutants such as volatile organic compounds (VOCs) and particulate matter.
Accenture is developing autonomous robots to reduce the carbon footprint of its operations, as well as to enable more efficient and low-emission operations. These robots are designed to be energy-efficient and require minimal human intervention. They can detect and diagnose potential issues in the system, such as air quality, temperature, and humidity, and can be used to automatically reduce energy consumption. Additionally, Accenture is also exploring the use of robotics to enable more energy-efficient production processes, such as 3D printing and additive manufacturing.
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What are the similarities and differences between static stretching and dynamic stretching?
The similarities and differences between static stretching and dynamic stretching are the dynamic stretch is a style of stretching that is more strenuous and physically stimulating, while the static stretch is a form of stretching that is slower and more relaxing.
Another difference between static and dynamic stretching is that after a dynamic stretch, you may feel stronger and have more muscle endurance and speed, whereas static stretching before an exercise diminishes these same qualities; To get the most out of your workout, perform dynamic stretching before you begin, and static stretching afterward. Static and dynamic stretching have similar benefits in lowering the risk of injury by increasing flexibility, balance, and body awareness.
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Two expressions were used for the drag force experienced by a moving object in a liquid. One depended upon the speed, while the other was proportional to the square of the speed. In which types of motion would each of these expressions be more applicable than the other one
The expression for drag force that is proportional to the speed of the object is known as linear drag, while the expression that is proportional to the square of the speed is known as quadratic drag.
What is linear drag?Linear drag is generally more applicable to objects moving at low speeds, such as a swimmer moving through water. In this case, the drag force is directly proportional to the speed of the object, and the drag coefficient is constant.Quadratic drag is generally more applicable to objects moving at high speeds, such as a bullet moving through air. In this case, the drag force is proportional to the square of the speed of the object, and the drag coefficient increases as the speed of the object increases. This type of drag is caused by the formation of a turbulent boundary layer around the object, which results in a significant increase in drag force at high speeds.So linear drag is more applicable to low speed and quadratic drag is more applicable to high speed.
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An antelope of mass 55 kg that is running at a speed of 10 m/s
and a tiger of mass 140 kg that is running at a speed of 15 m/s.
What's the total linear momentum of the antelope and the
tiger?
The total linear momentum of the antelope and the tiger is 2650 Kg m/s.
Linear momentum: what is it?The result of a system's mass x its velocity is its linear momentum. Linear momentum is denoted by the sign p = m v. The relationship between momentum and an object's mass and speed is straightforward.
Given -
mass of antelope = 55 Kg
mass of tiger = 140 Kg
speed of antelope = 10 m/s
speed of tiger = 15 m/s
from linear momentum formula
P = m × v
For antelope-
P = 55 × 10
P = 550 Kg m/s
For tiger-
P = m × v
P = 140 × 15
P = 2100 Kg m/s
Hence, total momentum is-
550 + 2100
2650 Kg m/s
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The more massive that an object is, the ______ (more, less) that the object will be attracted to Earth.
More large items will attract each other as the gravitational force between them grows because gravitational force is directly proportional to the mass of both interacting objects.
What transpires when an item has a higher mass?An object's inertia increases with mass, hence it requires more force to alter its state of motion. The mass of an item, which is roughly equal to the quantity of material inside it, determines how much inertia it has.
Why does gravity increase when an item becomes bigger?Theoretically, anything with mass generates small particles known as gravitons, which is why mass and gravity are related. The gravitational attraction is caused by these gravitons. Gravitons increase with mass.
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01) When operating a simple machine an effort of 60N is used to lift the load of 240 N. Find the mechanical advantage.
02) When operating the same machine the effort arm moves 4m while load moves 1m. Find velocity ratio
03) In the same machine find work input.
04) In the same machine find work output.
05) Find the efficiency of this simple machine.
Useless answers will be reported!
Answer:
1 MA= load/effort
MA= 240/60
MA=4
2.VR=Distance moved by effort/ Distance moved by Load
VR=4/1
= 4
5. Efficiency= MA/VR
4/4*100/1
=100%
On a frictionless surface, a 2-kilogram cart moves at a velocity of 3 meters per second west and hits a 4-kilogram cart that is not moving, initially. The two carts stick together and move off at a slower speed to the west. What is this slower speed?
a. 0. 5 meters/second
b. 1 meter/second
c. 1. 5 meters/second
d. 2 meters/second
Answer:
b
Explanation:
Use law of conservation of momentum
momentum before = momentum after hit
2 kg * 3 m/s = ( 2 + 4) kg * x m/s
solve for x = 1 m/s
a race car is moving at a constant speed around a track.What about the race car is changing and why
A race car is moving at a constant speed around a track. The race car is changing its velocity as the direction of motion changes.
What is velocity?The primary indicator of an object's position and speed is its velocity. It is the distance that an object travels in one unit of time. The displacement of the item in one unit of time is the definition of velocity.
The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction. SI unit of velocity is meter/second.
As the race car is moving at a constant speed around a track, the magnitude of velocity remains same but during race it may changes its direction of motion, that is why, velocity of it, which depends on both magnitude and direction, may changes.
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What is called solar energy?
Answer:
energy from the sun
Explanation:
the sun radiates energy known as solar energy.
What is the equation for torque use D for lever arm and F for force?
Torque is calculated using the formula =|r| |F|sin = | r | | F | sin, where |r| is the size of the lever arm, |F| is the size of the force vector, and is the angle formed between the two vectors.
force a "F" What is the torque calculation equation?Under ideal circumstances, M = F x r would be the equation for drive torque. In this instance, r denotes the length of a lever that is fastened to the axis of rotation and whose end is subject to a perpendicular force, F. The point of application, however, may alternatively be chosen at random.
R and F in the torque formula: what are they?The rotational rate (or "r") of an object is the amount by which a force acting on it rotates it. We'll refer to the force a "F" The moment arm, indicated by the letter "r," is the distance from the pivot point to the point at which the force acts.
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The aorta is a major artery, rising upward from the left ventricle of the heart and curving down to carry blood to the abdomen and lower half of the body. The curved artery can be approximated as a semicircular arch whose diameter is 4.1 cm. If blood flows through the aortic arch at a speed of 0.30 m/s, what is the magnitude (in m/s2) of the blood's centripetal acceleration
The centripetal acceleration of the aorta in which the blood travels with the speed of 0.30 m/s is 2.2 m/s²
The diameter of the aorta = 4.1 cm
= 4.1 x 10⁻² m
The speed of the blood through the aorta = 0.3 m/s
The centripetal acceleration of the blood passing through the aorta can be found using the formula,
a = v²/r
where a is the centripetal acceleration
v is the speed of the blood passing through the aorta
r is the diameter of the aorta
Let us substitute the known values in the above equation, we get
a = 0.30² / (4.1 x 10⁻²)
= 0.09 / (4.1 x 10⁻²)
= 0.022 x 10²
= 2.2 m/s²
Therefore, the centripetal acceleration of the aorta is 2.2 m/s²
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What is the relationship between mass and kinetic energy evidence?
The equation for Kinetic Energy is: KE = 1/2 mv2. Kinetic energy has a direct relationship with mass, meaning that as mass increases so does the Kinetic Energy of an object.
In physics, an object's kinetic energy is the energy it has as a result of its motion. It is defined as the amount of work required to accelerate a body of a given mass from rest to a certain velocity.
The body retains its kinetic energy after gaining it during acceleration until its speed changes. The body does the same amount of work while slowing down from its current pace to rest. Formally, kinetic energy is any term in a system's Lagrangian that contains a time derivative.
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A twig floating in a small pond is initially at rest. On the twig is a snail, which begins moving along the length of the twig with a speed of 1.2 cm/s. The twig moves in the opposite direction with a speed of
0.40 cm/s. If the snail's mass is 2.5 g, what is the mass of twig?
The mass of the twig can be calculated using the law of conservation of momentum.
What is law of conservation?The Law of Conservation states that matter and energy cannot be created or destroyed, only changed from one form to another. This law is one of the most fundamental laws of physics, and it applies to all forms of energy, including heat, light, and electrical energy. This law helps explain why energy is always conserved, meaning that it can never be lost, only transferred or converted into another form. This law is also important in understanding the behavior of matter, as it explains why matter can never be completely destroyed, only rearranged or changed in form.
Momentum is equal to the mass times the velocity, so the total momentum of the twig and the snail before the snail starts moving is zero. After the snail starts moving, the momentum of the twig and the snail is equal to the snail's momentum, which is equal to 2.5 g x 1.2 cm/s = 3.0 g cm/s. Since the velocity of the twig is 0.4 cm/s, the mass of the twig must be equal to 3.0 g cm/s / 0.4 cm/s = 7.5 g.
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In the grating equation nλ=d sin θ, the quantity θ will be determined in the lab: Using meter sticks and geometry/trigonometry, using the angular scale on the experimental apparatus, using a protractor.
In the laboratory, the quantity θ in the grating equation nλ=d sin θ can be determined in several ways.
What is laboratory ?
A laboratory is a specialized facility used to conduct scientific research, experiments, and analysis. Laboratories are typically equipped with instruments, tools, and other equipment necessary for conducting experiments, tests, and analyses. They may also be used to produce and store chemical, biological, or physical samples and materials.
Meter sticks and geometry/trigonometry can be used to measure the lengths of the grating lines, d, and the wavelength of light, λ, and then calculate the angle using the formula θ = sin-1 (nλ/d). The angular scale on the experimental apparatus can also be used to measure the angle directly. Alternatively, a protractor can be used to measure the angle directly.
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Complete Question
In the grating equation nλ=d sin θ, the quantity θ can be determined in the lab by using meter sticks and geometry/trigonometry, using the angular scale on the experimental apparatus, or using a protractor. To determine the value of θ using meter sticks and geometry/trigonometry, the lengths of the grating lines, d, and the wavelength of light, λ, must first be measured. Using these values, the angle can be calculated using the formula θ = sin-1 (nλ/d). To determine θ using the angular scale on the experimental apparatus, the angular scale can be used to measure the angle directly. To determine θ using a protractor, the angle can be measured directly using the protractor.
Each of five satellites makes a circular orbit about an object that is much more massive than any of the satellites. The mass and orbital radius of each satellite are given below. Which satellite has the greatest speed? Mass Radius (A) ½m R (B) m ½R (C) m R (D) m
Correct option is B, satellite that has the greatest speed has Mass Radius m ½R.
Because the satellite orbits the earth, the gravitational pull of the planet on the satellite supplies the necessary centrifugal force. In a circular orbit, the gravitational force is constant, hence the satellite's velocity is also constant.
Kepler's third law informs us that
V² = GM/R
Therefore, v = (GM/R)
Where;
V is the speed
G stands for gravity constant.
Mass is M.
R is radius
Let's begin by examining the first choice, which is Option B.
Here, mass equals m and radius equals (1/2)R.
Consequently, v = (Gm/(R/2)) = (2Gm/R)
After carefully examining each choice, it is evident that option B will have the highest velocity because its numerator is the largest, which will result in a higher velocity.
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To understand electrical currents we need to understand
Electric current is a term used to describe how much electricity flows across a circuit and how it flows in an electronic circuit. Amperes are used to measure it (A).
How much electricity is best understood?The energy of charged particles is referred to as electricity. One option for storing electricity is a battery. Electricity flows when you connect a battery to a light bulb. Due to the fact that electrical charges (electrons) can freely transport energy from the battery through the bulb, this occurs.
What is the most crucial electrical rule?Disconnect the power source. This is the first and most crucial requirement to abide by. This is the first and most crucial rule to adhere to. If you ever need to repair electrical equipment in your house, be sure to first unplug it from the power source. It might not be sufficient to simply turn it off.
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A 1.65-kg mass stretches a vertical spring 0.215 m. If the spring is stretched an additional 0.130 m and released, how long does it take to reach the (new) equilibrium position again
The time it takes for the mass to reach the new equilibrium position is approximately 0.15 seconds.
To calculate the time it takes for the mass to reach the new equilibrium position, you will need to know the spring constant of the spring. The spring constant, denoted by the letter k, is a measure of the spring's stiffness, and it is related to the force required to stretch the spring by a certain distance. If the spring constant is not given, it can not be calculated.
Once you have the spring constant, you can use the equation:
T = 2π √(m/k) where,
T is the period of oscillation (the time it takes for the mass to complete one full cycle of motion) m is the mass of the object attached to the spring k is the spring constant.The spring constant (k) can be found by using the equation:
F = kx where,
F is the force applied to the spring x is the distance the spring is stretched from its equilibrium position, and k is the spring constant.In this case, the force is equal to the weight of the mass, which is m*g, where m is the mass and g is the acceleration due to gravity.
mg = kx
or, k = (m*g)/x
or, k = (1.65 kg * 9.8 m/s^2) / 0.215 m = 74.65 kg/s^2
Now that we know the spring constant, we can use the equation:
T = 2π √(m/k)
To find the time it takes for the mass to reach the new equilibrium position, where T is the period of oscillation, m is the mass of the object attached to the spring, and k is the spring constant.
T = 2π √(1.65 kg / 74.65 kg/s^2) = 0.15 sec
So the time it takes for the mass to reach the new equilibrium position is approximately 0.15 seconds.
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Marissa’s car accelerates at an average rate of 3. 6 m/s2. Calculate how long it takes her car to accelerate from 26. 4 m/s to 28. 6 m/s
It will take 1.5 seconds for Marissa's car to accelerate from 26. 4 m/s to 28. 6 m/s.
Acceleration can be calculated by looking at the change in velocity over a specific period of time. It is an important concept in physics as it is used to explain the motion of objects in the real world.
Acceleration is a measure of how quickly an object is changing its velocity on average, and it is usually expressed in meters per second squared (m/s2).
This simple calculation of Marissa's car acceleration can be determined by using the formula: Delta speed / Acceleration rate = Time taken.
In this case, that would be 2.2 m/s (28.6-26.4) / 3.6 m/s2
= 0.6 s or 1.5 sec (rounded up).
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Freight trains can produce only relatively small acceleration and decelerations. a. What is the final velocity (in m/s) of a freight train that accelerates at a rate of 0.050 m/s2 for 8.0 min, starting with an initial velocity of 3.0 m/s
The final velocity of the freight train is 27 m/s that accelerates at a rate of 0.050 m/s2 for 8.0 min, starting with an initial velocity of 3.0 m/s.
Information given:
Acceleration is 0.050 m/s²
Time is 8.0 min
Initial velocity is 3.0 m/s
We apply the resulting equations for rectilinear motion at constant acceleration to this problem.
a = (v - u)/t
where the,
a is acceleration
u and v are the initial and final velocities, respectively
s is the distance
t is the time
Substituting the values in the equation:
The solution is as follows:
a = (v - v₀)/t
0.050 m/s² = (v - 3 m/s)/(8 min * 60 s/1 min)
Time: 480 sec
Solving for v,
24=v-3
v=27 m/s
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A container is filled to a depth of 24.0 cm with water. On top of the water floats a 34.0 cm thick layer of oil with specific gravity 0.900. What is the absolute pressure at the bottom of the container
The Absolute pressure at the bottom of the container filled with water which has a thick layer of oil on the top will be 2735.21 Pa.
Information given as:
Height (h) = 31 cm = 0.31 m
Acceleration due to gravity (g) = [tex]9.8 m/s^{2}[/tex]
Specific gravity of oil = 0.900
So density of oil (ρ)= [tex]0.9X1000 = 900 kg/m^{3}[/tex]
We know that absolute pressure is given by the formula, here
So absolute pressure will be equal to [tex]P_{o} = 1.01 X 10^{5} Pa[/tex]
So absolute pressure of the oil will be 2735.21 Pa
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An object is experiencing an acceleration of 12 m/s2 while traveling in a circle of radius 5. 0 m. What is its velocity?
The velocity of the object is 7.74m/s
Though it may sound sophisticated, velocity is simply the rate at which an object's location changes with regard to a frame of reference and time. Since it is a vector quantity, the definition of velocity requires both magnitude (speed) and direction.
We are given that,
Acceleration = 12m/s²
Radius = r = 5.0m
Velocity = v = ?
The velocity of the object can be calculated by the formula ,
a = v²/r
v = √ar
v = √12m/s²× 5m
v = √60m²/s²
v= 7.74m/s
Thus , the velocity of the object would be 7.74m/s.
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A class
A class
A class
-
-
lever never has a mechanical advantage.
lever always has a mechanical advantage.
lever could go either way. (1 point)
O 2; 3; 1
O 2; 1; 3
O 1; 2; 3
O3; 2; 1
The correct answer is 1; 2; 3. Lever can either have a mechanical advantage or no mechanical advantage, depending on the lever's mechanical design.
What is mechanical design?Mechanical design is the process of taking a product from concept to reality. Through this process, engineers analyze, design, and manufacture components and systems that are used in a variety of industries. Mechanical design involves a broad range of skills, including mathematics, engineering, physics, and computer-aided design (CAD) software. The process begins with the understanding of the problem and the requirements of the design. From there, engineers must select the best materials, create a detailed design, and simulate the design in a virtual environment. After the design is complete, engineers then use the principles of manufacturing to produce the components through machining, molding, and other processes.
If the lever is designed with a long arm and a short arm, it can have a mechanical advantage. If the lever is designed with two arms of equal length, it will not have a mechanical advantage.
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Answer:
(Question)
A class __ lever never has a mechanical advantage.
A class __ lever always has a mechanical advantage.
A class __ lever could go either way.
(Answer)
3;2;1
(Question)
A lever is used to lift an object with a weight of 60 Newtons. The effort force is 15 meters from the fulcrum, while the load force is 5 meters from the fulcrum. What is the mechanical advantage?
(Answer)
3
(Question)
With which class of levers is it possible to increase the force that must be applied?
(Answer)
class 1 and 3
(Question)
600 Joules of work is used to lift a box from the ground to a height of six meters. How much work would have been done if a lever would have been used with an effort arm of 12 meters and a load arm of 6 meters?
(Answer)
600 J
(Question)
A lever with an effort arm of 10 meters and a load arm of 2 meters is used to lift an object weighing 220 Newtons to a height of 4 meters. If 400Joules of work is done, how much force must have been applied?
(Answer)
100 N
Explanation:
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