A scalloped hammerhead shark swims at a steady speed of 1.5m/s with its 90cm-cm-wide head perpendicular to the earth's 53A scalloped hammerhead shark swims at a steady speT magnetic field. What is the magnitude of the emf induced between the two sides of the shark's head? Express your answer using two significant figures.

Answers

Answer 1

The magnitude of the emf induced between the two sides of the shark's head is 71.55 V (rounded to two significant figures).

The magnitude of the emf induced between the two sides of the shark's head can be calculated using the equation emf = B*L*v, where B is the magnetic field strength, L is the length of the conductor (in this case, the width of the shark's head), and v is the velocity of the conductor (the shark's speed).

Plugging in the given values, we have:

B = 53 A/m (given)
L = 0.9 m (given)
v = 1.5 m/s (given)

emf = (53 A/m) * (0.9 m) * (1.5 m/s) = 71.55 V

Therefore, the magnitude of the emf induced between the two sides of the shark's head is 71.55 V (rounded to two significant figures).

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Credits to ocean service

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Hope this helps

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Answers

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Correct question is;

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Pressure exerted at the base is the hydrostatic pressure and it is given by the formula;

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Answer:

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Answer:

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//

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