A sample of calcium bromide contains 20% calcium and 80% bromine by mass. The empirical formula of the compound formed is CaBr2
Given:
A substance with the chemical formula 20% Ca and 80% Br.
In search of:
When the compound's molecular weight is 200.
Let's say that the mixture formed is 100.
Let's search for the mole of Ca and Br individually now.
Ca mole = 20/40 = half
"Mole of Br" = "80/80"
CaBr2 is the result of the 1:2 ratio between Ca and Br.
So, the empirical formula is CaBr2.
An empirical formula is a chemical formula for a compound that only specifies the ratios of the elements present in the molecule and not the exact number or arrangement of atoms. This would be the element to whole number ratio of the lowest valued compound.
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I'll give brainliest:)
1. Why do you think sodium and potassium react the way they do?
2. What did you learn about the valence electrons for sodium and potassium?
3. Why do you think that potassium has a lower ionization energy than sodium?
4. How does the number of valence electrons of sodium and potassium explain the reactions they have with water?
5. How does the pattern in ionization energy in the alkali metals explain the difference between sodium and potassium in their reaction with water?
Sodium and potassium are s-block alkali metals. Because potassium and sodium are metals, they each lose one electron.
What is chemical reactivity?Reactivity is indeed a measure of how easily a material conducts a chemical reaction in chemistry. The reaction might include the chemical alone or in combination with those other atoms or molecules, and it is usually followed by the release of energy. The most reactive components and elements have the potential to spontaneously or explosively ignite.
Because potassium and sodium are metals, they each lose one electron. They create cations and react with nonmetals to generate salt. Sodium and potassium are s-block alkali metals.
Therefore, because potassium and sodium are metals, they each lose one electron.
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Calculate the kinetic energy of a 100kg cart moving at a speed of 6 m/s.
The kinetic energy of a 100kg cart moving at a speed of 6 m/s is 1800 J.
Kinetic energy is defined as the energy that an object has because of its motion. If you want to accelerate an object, then you must apply a force. Force can be applied when work is done by us. After work has been done, the energy will get transferred to the object, and the object will be moving with a new constant speed.
K.E = 1/2 mv²
m = 100 kg
v = 6 m/s
Substituting the values we get,
K.E = 1/2 × 100 × 6 × 6
⇒ K.E = 1800 J
Hence, The kinetic energy of a 100kg cart moving at a speed of 6 m/s is 1800 J.
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You have made up a stock aqueous dye solution of known concentration equal to 500. 0 parts per million (ppm) of green dye. If you take 2. 0 mL of the stock solution and add 8. 0 mL of water to it, what would the concentration of the diluted solution be in units of ppm?
The concentration of the diluted solution be 100 ppm.
What is the Ppm solution?Chemistry uses the term PPM, or parts per million, to describe extremely low concentrations of solution. One liter of solution containing milligrams of the chemical is what is meant by this term. Technically speaking, it is a dimensionless quantity that can be used to measure lower concentrations in a solution.There are numerous scientific uses for this conversion.
It refers to how many of the one million parts that make up the entire solution a specific substance or molecule occupies. It is used to describe substance concentrations that are typically dissolved in a solvent. When there are two solutions, and one of them has a known ppm concentration, the ppm concentration can be calculated by:
ppm1 x volume = ppm2 volume
500 ppm x 2 mL = ppm2 x 10 mL
ppm 2 = 500 ppm x 2 mL/ 10 mL
ppm 2 = 100 ppm
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when 0.982 g of mercury oxide are heated until all oxygen is expelled, 0.909g of mercury remain. what is the formula of this oxide
when 0.982 g of mercury oxide are heated until all oxygen is expelled, 0.909g of mercury remain then the formula of the oxide will be HgO.
The formula of the oxide can be determined by using the mass loss during heating as a clue to the number of moles of oxygen that was present in the original sample.
First, we'll calculate the mass of oxygen that was expelled:
0.982 g - 0.909 g = 0.073 g
Next, we'll convert the mass of oxygen to moles:
0.073 g / (16.00 g/mol) = 0.00456 mol
Next, we'll convert the mass of mercury to moles:
0.909 g / (200.59 g/mol) = 0.00453 mol
The ratio of moles of mercury to moles of oxygen in the original sample is approximately 1:1, which means that the formula of the oxide is HgO.
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classify the type of microscope based on a radiation they use
Answer:
Light vs electron
Explanation:
Light Microscope vs Electron Microscope. Light microscopes and electron microscopes both use radiation - in the form of either light or electron beams, to form larger and more detailed images of objects (e.g. biological specimens, materials, crystal structures, etc.) than the human eye can produce unaided.
Answer the question given in the picture
Sample A was from a gunshot while sample B is from a blow. Option C
What is a blood pattern?In forensics, the blood pattern has to do with the way that the blood is arranged or the way that the blood flows among a particular target. It is common to see that when a person is shot, the blood would splatter on the wall behind the victim.
The pattern of the splatter of the blood can be used to tell if the would from a high velocity impact of if the would was just from a medium velocity impact as are shown by the images.
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if 39.0 g of c6h6 reacts with excess chlorine and produces 28.0 g of c6h5cl in the reaction above, what is the percent yield of c6h5cl? the molar mass of c6h6
According to the question, the molar mass of C₆H₆ is 60.5%.
What is molar mass?
Molar mass is the mass of one mole of a substance, measured in grams per mole. It is calculated by summing the atomic masses of the atoms in the molecular formula of the substance. Molar mass can be used to calculate the mass of a given amount of a substance, or to determine the amount of a substance needed to obtain a particular mass. Molar mass is an important concept in chemistry as it is used to calculate the amount of energy released or absorbed in a chemical reaction, as well as the amount of products formed.
Molar mass of C₆H₆ = 78.11 g/mol
Moles of C₆H₆ = 39.0 g / 78.11 g/mol = 0.500 mol
Molar mass of C₆H₅Cl = 92.56 g/mol
Moles of C₆H₅Cl = 28.0 g / 92.56 g/mol = 0.301 mol
Theoretical yield of C₆H₅Cl = 0.500 mol x 92.56 g/mol = 46.28 g
Actual yield of C₆H₅Cl = 28.0 g
Percent yield of C₆H₅Cl = (Actual yield / Theoretical yield) x 100%
= (28.0 g / 46.28 g) x 100%
= 60.5%
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determine the molecular formula of the compound with an empirical formula of ch and a molecular molar mass of 78 g/mol.
The molecular formula of the compound with an empirical formula of CH and a molecular molar mass of 78 g/mol is, [tex]C_6H_6[/tex].
An Empirical formula is the chemical formula of a compound that gives the proportions (ratios) of the elements present in the compound but not the actual numbers or arrangement of atoms. This would be the lowest whole number ratio of the elements in the compound.
Given,
Empirical formula = CH
The molar mass of empirical is 12+1 = 13 g
The molar mass of molecular formula = 78 g
To find the number of empirical units divide the molecular mass + empirical mass
No. of units = 78÷13 = 6
So, the molecular formula is 6×(CH)
[tex]C_6H_6[/tex]
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system a and system b contain the same substance. system a is a saturated vapor and is at the same temperature as system b. if system b has a lower pressure than a, what phase is system b in?
System B is in a liquid phase since it is at the same temperature as System A, but has a lower pressure.
When a substance is heated, the pressure of the vapour increases, and eventually the pressure of the vapour and the liquid become equal at the substance's boiling point. This is known as the saturated vapour point. If the pressure of the vapour is lowered, then the vapour will condense into a liquid, as is the case with System B. As a result, System B is in a liquid phase due to the lower pressure.
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PLEASEEEE HELP ME IM IN NEDD OF HELP
The response is untrue, thus no. Methane (CH4) and oxygen combine to produce water and carbon dioxide. Since there are different numbers of hydrogen atoms on either side.
Why happens when methane and oxygen interact?Methane (CH4) and oxygen combine to generate water and carbon dioxide. Since there are different numbers of hydrogen atoms on either side, we can see that the process is not balanced in this instance. The quantity of oxygen atoms is the same.
Methane and carbon dioxide are converted in what way?Natural gas mostly consists of methane. Methane is released into the atmosphere where it ultimately mixes with oxygen to create additional carbon dioxide (CO2). This straightforward chemical process turns methane into carbon dioxide.
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Determine the pH at the equivalence point in the titration of 50. 0 ml of 0. 300 m ch3cooh with. 3 M NaOH. The Value of Ka for CH3COOH is 1. 8 x 10^-5
The pH at the equivalence point in the titration of 50.0 ml of 0.300 M CH₃COOH with 0.3 M NaOH is approximately 4.68.
To calculate the pH at the equivalence point, we need to determine the concentration of acetate ion (CH₃COO⁻) and hydronium ion (H³O⁺) at this point.
At the start of the titration, the initial concentration of acetic acid is 0.300 M and the initial concentration of hydronium ion is the same.
Let's say that x moles of NaOH are added to the solution. This will lead to the formation of x moles of acetate ion (CH³COO⁻) and x moles of hydroxide ion (OH⁻).
The final concentration of acetic acid will be (0.300 M - x M) and the final concentration of hydronium ion will be (x M).
The ionization constant (Ka) for acetic acid can be used to determine the concentration of acetate ion and hydronium ion in the solution. The equation for the ionization of acetic acid is:
CH₃COOH + H₂O ↔ CH₃COO⁻ + H₃O⁺
Ka = [CH₃COO⁻][H₃O⁺] / [CH₃COOH]
At the equivalence point, [CH₃COOH] = (0.300 M - x M), [CH₃COO⁻] = x M, and [H₃O⁺] = x M. Substituting these values into the equation for Ka, we get:
1.8 x 10⁻⁵ = (x)(x) / (0.300 - x)
Solving for x, we get:
x = 2.1 x 10⁻⁵ M
The pH at the equivalence point is equal to the negative log of the hydronium ion concentration:
pH = -log[H₃O⁺] = -log(2.1 x 10⁻⁵) = 4.68
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the chemical environment of protons can be deduced from their chemical shifts. what are the relative chemical shifts of the protons at the labeled positions? [protons that are highly shielded have low delta (chemical shift) values.]
1). The most shielded is c while the least shielded is a.
2). The most shielded is b while the least shielded is a.
In part 1 Since CH₃ has the most electrically rich carbon atom, it is also the most shielded, hence the answer to the question is c.
As oxygen is the electronegative radical and makes up the least protected carbon in the carbonyl group, the solution for the most shielded carbon atom is a.
In part 2 Since CH₃ has the most electrically rich carbon atom, it is also the most insulated, hence the correct response is b.
Due to the existence of the pi electrons, the carbon in a ring is least protected, hence the answer for the most shielded carbon atom is a.
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If a molecule has an uneven distribution of electrons then it is polar molecule and it will not be dissolved in water. Why?
If a molecule has an uneven distribution of electrons then it is polar molecule and it will not be dissolved in water because the distribution of electrons around the molecule is no longer symmetrical.
What is Polarity?This is referred to as a separation of electric charge leading to a molecule or its chemical groups having an electric dipole moment, with a negatively charged end and a positively charged end.
A polar covalent bond is a covalent bond in which the atoms have an unequal attraction for electrons and so the sharing is unequal. In a polar covalent bond, sometimes simply called a polar bond, the distribution of electrons around the molecule is no longer symmetrical.
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.0 carat is equal to 200 mg (0.200 g). if the density of a ruby is 4.02 g/cm3, what is the volume of a 1.00 carat ruby?
If the density of the ruby is 4.02 g/cm³, the volume of a 1.00 carat ruby is 0.049 cm³.
The density of the ruby = 4.02 g/cm³
The mass of the ruby = 1 carat
1 carat = 200 mg = 0.200 g
The mass of the ruby 0.200 g
The density is expressed as :
Density = mass / volume
The volume = mass / density
Volume = 0.200 / 4.02
Volume = 0.049 cm³
The volume of the ruby in mL = 0.049 mL.
Thus, the volume of the ruby is 0.049 mL in the 1 carat of the ruby.
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The combustion of propane (C3H8) produces CO2 and H2O:
C3H8 (g) + 5O2 (g) → 3CO2 (g) + 4H2O (g)
The reaction of 2.0 mol of O2 will produce ________ mol of H2O.
The combustion of propane (C3H8) produces CO2 and H2O:
C3H8 (g) + 5O2 (g) → 3CO2 (g) + 4H2O (g)
The reaction of 2.0 mol of O2 will produce ________ mol of H2O.
4.0
2.5
2.0
1.6
1.0
According to the stoichiometry of the given chemical reaction, the reaction of 2.0 mole of O₂ will produce 1.6 mole of H₂O.
What is stoichiometry?It is the determination of proportions of elements or compounds in a chemical reaction. The related relations are based on law of conservation of mass and law of combining weights and volumes.
Stoichiometry is used in quantitative analysis for measuring concentrations of substances present in the sample.In the given reaction, 5 moles of oxygen gives 4 moles of water, thus 2 mole of oxygen will give 2×4/5=1.6 moles of water.
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how many electrons does a noble gas, other than helium, have in its highest-occupied energy level?
A noble gas, other than helium, have 8 electrons in its highest-occupied energy level.
The noble gas are a group of elements in the periodic table that have exceptional chemical stability and low reactivity due to their complete valence shell of electrons. These elements are found in the far right-hand column of the periodic table and include helium (He), neon (Ne), argon (Ar), krypton (Kr), xenon (Xe), and radon (Rn). Unlike other elements in the periodic table, the noble gases do not readily form compounds with other elements, making them highly unreactive. This characteristic makes them useful in a variety of industrial applications, such as filling incandescent lamps, as cooling agents in cryogenics, and in the production of semiconductors. The electron configurations of the noble gases, excluding helium, follow the pattern s^2p^6, meaning that the highest-occupied energy level has 8 electrons. This full valence shell of electrons gives the noble gases their exceptional stability and non-reactivity, making them unique among the elements in the periodic table.
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Unstable isotopes undergo radioactive decay. What is something that can occur during radioactive decay?
During radioactive decay Unstable isotopes can occur by releasing particles.
Isotopes are atoms with the same number of protons but differing numbers of neutrons. They differ in mass, which affects their physical characteristics even if they have nearly identical chemical properties. There are unstable isotopes that emit radiation as well as stable isotopes that do not. These are referred to as radioisotopes.
Unstable isotopes undergo radioactive decay.The unstable isotope can release particles like alpha particles, beta particles, or gamma rays during radioactive decay. By emitting particles, the isotope transforms into a different element or isotope and becomes stable.
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if 3.2 m3 of a gas initially at stp is placed under a pressure of 3.1 atm, the temperature of the gas rises to 38.0oc. what is the volume under those conditions? give the answer in m3, to 2 decimal places.
The relationship between the pressure, volume, and temperature of a gas can be described by the ideal gas law, which states that PV = nRT, where P is the pressure, V is the volume, n is the number of moles of gas, R is the ideal gas constant, and T is the temperature in kelvins.
We can rearrange the ideal gas law to solve for volume:
V = (nRT) / P
We know the initial volume of the gas at STP (standard temperature and pressure of 0 °C and 1 atm):
V1 = 3.2 m^3
We also know the initial temperature and pressure:
T1 = 273.15 K (0 °C converted to kelvins)
P1 = 1 atm
And we know the final temperature and pressure:
T2 = 38.0 + 273.15 = 311.15 K
P2 = 3.1 atm
Assuming the number of moles of gas stays constant, we can substitute the known values into the equation and solve for the final volume:
V2 = (nRT2) / P2
V2 = (n * R * 311.15) / 3.1
V2 = (n * 8.31 * 311.15) / 3.1
Since the number of moles n cancels out, we can simplify the equation:
V2 = (8.31 * 311.15) / 3.1
V2 = 936.76 / 3.1
V2 = 301.31 m^3
So the final volume of the gas under the specified conditions is 301.31 m^3 to two decimal places.
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Avogadro’s law states the volume of a gas is directly proportional to the number of moles of gas, but has nothing to do with the identity of the gas. Is this law correct for a real gas? Explain.
Answer:
Avogadro's law is an ideal gas law that states that, at a constant temperature and pressure, the volume of a gas is directly proportional to the number of moles of gas. This law assumes that the gas is an ideal gas, which is a theoretical gas that follows a set of idealized assumptions, such as having no intermolecular forces and occupying no volume.
In reality, gases are not always ideal and can deviate from the ideal gas behavior at high pressures and low temperatures. In these conditions, the volume of a gas is no longer directly proportional to the number of moles of gas due to the intermolecular forces between gas particles. Real gases can also have different molar volumes, which means that the identity of the gas does matter when considering the relationship between volume and number of moles.
Therefore, while Avogadro's law is a useful approximation in many situations, it is not always accurate for real gases.
8. A container of nitrogen gas has a pressure of 256. 4 mm Hg at 362 K. If the temperature is decreased to 251
K, what is the pressure of the gas in the container? Answer: 178mmHg
9. A 32. 4 L gas sample at STP is compressed to a volume of 28. 4 L, and the temperature is increased to 352 K.
What is the new pressure of the gas in atmospheres? Answer: 1. 47atm
10. At what temperature in Kelvin will 0. 1243 moles of fluorine exert a pressure of 2. 02 atm at a volume of
0. 625 L? Answer: 124K
Please explain step by step!!
8. The pressure of the gas in the container is 369.7 mmHg.
9. The new pressure of the gas in atmospheres is 1.47 atm
10. The temperature in Kelvin will 0. 1243 moles of fluorine exert a pressure of 2. 02 atm at a volume of 0. 625 L is 124 K.
The ideal gas equation is expressed as :
P V = n R T
8. The gas law is :
P₁ V₁ = P₂ V₂
P₂ = P₁ V₁ / V₂
P₂ = ( 256.4 × 362 ) / 251
= 369.7 mmHg
9. P₁ V₁ / T₁ = P₂ V₂ / T₂
P₂ = P₁ V₁ T₂ V₂T₁
P₂ = ( 1 × 32.4 × 352) / 28.4 × 273
= 1.47 atm
The pressure is 1.47 atm
10. P V = n R T
T = P V / n R
T = ( 2.02 × 625 ) / 0.1243 × 0.082
T = 124 K
Thus, the temperature is 124 K.
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HELP ME PLSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSS
Explanation:
burning fossil fuels adds carbon dioxide, and photosynthesis removes it
2NH3 + 3 CuO —-> 3 Cu + N2 + 3H2O
in the above equation, how many grams of N2 can be made when 5.3 grams of CuO are consumed?
use the following molar masses.
According to the stoichiometry, 0.621 g of nitrogen can be made when 5.3 grams of CuO are consumed.
What is stoichiometry?It is the determination of proportions of elements or compounds in a chemical reaction. The related relations are based on law of conservation of mass and law of combining weights and volumes.
Stoichiometry is used in quantitative analysis for measuring concentrations of substances present in the sample.In the given chemical equation, 238.62 g copper oxide gives 28 g nitrogen thus, 5.3 g will give 5.3×28/238.62=0.621 g.
Thus, 0.621 g of nitrogen can be made when 5.3 grams of CuO are consumed.
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the following balanced equation describes the combustion of ethene (c2h4). how many grams of carbon dioxide, co2, are produced if 29.4 g of ethene and 95.3 g of oxygen, o2, are used for the reaction?
In the given chemical reaction, 87.4 g of carbon dioxide gas is produced if 29.4 g of ethene and 95.3 g of oxygen is used in a reaction. The correct choice is option e.
Combustion is a chemical process that occurs in the presence of oxygen between a fuel and an oxidizing agent, creating heat and light.
We need to find the limiting reagent by calculating the moles of each reactant and comparing them to the stoichiometric ratio of the balanced equation.
Moles of [tex]\rm C_2H_4[/tex]= 29.4 g / 28.05 g/mol = 1.045 mol
Moles of [tex]\rm O_2[/tex] = 95.3 g / 32 g/mol = 2.978 mol
The stoichiometric ratio of the balanced equation is 1 mol [tex]\rm C_2H_4[/tex]: 3 mol [tex]\rm O_2[/tex]. Therefore, [tex]\rm O_2[/tex] is the limiting reagent because we have less moles of [tex]\rm O_2[/tex] than what is required by the stoichiometric ratio.
Now we can use the moles of [tex]\rm O_2[/tex] to determine the moles of [tex]\rm CO_2[/tex]produced.
Moles of [tex]\rm CO_2[/tex]= 2.978 mol [tex]\rm O_2[/tex] [tex]\times[/tex] (2 mol [tex]\rm CO_2[/tex]/ 3 mol [tex]\rm O_2[/tex]) = 1.985 mol [tex]\rm CO_2[/tex]
Finally, we can use the moles of [tex]\rm CO_2[/tex] to determine the mass of [tex]\rm CO_2[/tex]produced.
Mass of [tex]\rm CO_2[/tex]= 1.985 mol [tex]\rm CO_2[/tex][tex]\times[/tex] 44.01 g/mol = 87.4 g [tex]\rm CO_2[/tex]
Therefore, option e. 87.4 g is the correct choice.
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Your question is incomplete but most probably your full question was,
The following balanced equation describes the combustion of ethene
([tex]\rm C_2H_4[/tex]). How many grams of carbon dioxide, [tex]\rm CO_2[/tex], are produced if 29.4 g of ethene and 95.3 g of oxygen, [tex]\rm O_2[/tex], are used for the reaction? [tex]\rm 1C_2H_4+3O_2\rightarrow 2CO_2+2H_2O[/tex]
(a) 133 g
(b) 92.3 g
(c) 46.1 g
(d) 131 g
(e) 87.4 g
Oyster populations are primarily, if not exclusively, composed of _____. A. Larval and juvenile oysters. B. Adults C. Prereproductive oysters. D. Larvae
Oyster populations are primarily, if not exclusively, composed of Adults (option B.).
Oysters are found in coastal areas that are either salty or brackish, and they tend to congregate on older shells, rocks, piers, or any other submerged surface that is hard. They eventually build rock-like reefs by fusing together as they grow, which provides a habitat for a variety of other marine animals and plants.
The word "oyster" refers to a number of different families of bivalve mollusks that live in marine or brackish environments and are known together by the name "oyster." In other species, the valves are extremely calcified, and the shape of several of them is rather asymmetrical. The superfamily Ostreoidea contains a significant number of oysters, although not all of them.
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in the molecule cocl2, carbon is the central atom. draw the best lewis structure for cocl2. in the structure you provided, what is the formal charge on carbon?
the formal charge on carbon in the Lewis structure for COCl2 is 0.n the molecule cocl2, carbon is the central atom
The Lewis structure for COCl2 can be drawn as follows:
O=C=Cl
In this structure, the carbon atom is bonded to one oxygen atom and two chlorine atoms. Each chlorine atom is bonded to the central carbon atom by a single bond, and the oxygen atom is bonded to the carbon atom by a double bond.
To calculate the formal charge on carbon, we can use the following formula:
Formal charge = (# of valence electrons) - (nonbonding electrons + 1/2 bonding electrons)
In this case, carbon has 4 valence electrons and shares 2 electrons in the double bond with oxygen, and 1 electron with each of the two chlorine atoms, for a total of 4 electrons. Thus, the formal charge on carbon is:
Formal charge = (4) - (0 + 1/2 * 4) = 0
Therefore, the formal charge on carbon in the Lewis structure for COCl2 is 0.
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1.The boiling point of helium is 4 K. When helium boils, what interactions and/or bonds are overcome?
2. The boiling point of hydrogen is 20 K. When hydrogen boils, what interactions and/or bonds are overcome?
3. What interactions and/or bonds are overcome when hydrogen at 30 K is heated to 6000 K?
1. Helium has a boiling point of 4 k, and as it does so, the London dispersion force breaks bonds and interactions.
2. Helium has a boiling point of 20 k, and as it does so, the London dispersion force breaks bonds and interactions.
3. Hydrogen is able to break covalent bonds when heated from 30 K to 6000 K.
The least powerful bond-interaction force is the London dispersion force. The atoms of a substance are temporarily attracted to one another. Two atoms' electrons combine in a way that causes them to form dipoles. This force underlies every helium gas reaction.
When two species share electrons, a covalent link is created. Usually, they happen amongst compounds with comparable electronegativities. Bond strength is based on how many bonds there are between the atoms.
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a potassium hydroxide (KOH) solution has a molar concentration of 0.026 M. calculate the [H3O+], [OH-] , and the pH of the solution
A 0.026 M KOH solution has [tex][OH-] = 0.026 M, [H3O+] = 10^(-13) M[/tex], and a pH of 12.97.
A potassium hydroxide (KOH) solution is a strong base and dissociates completely in water to produce hydroxide ions (OH-). The molar concentration of KOH can be used to calculate the concentration of hydroxide ions.
[OH-] = 0.026 M
The hydroxide ions will react with water to produce hydronium ions (H3O+), according to the equation:
[tex]OH- + H2O - > H3O+ + OH-[/tex]
The concentration of hydronium ions can be calculated using the equation:
[tex][H3O+] = Kw/[OH-] = 10^(-14)/[OH-] = 10^(-14)/0.026 = 10^(-13) M[/tex]
The pH of the solution can be calculated using the equation:
[tex]pH = -log[H3O+] = -log(10^(-13)) = 13.[/tex]
Therefore, the pH of the 0.026 M KOH solution is 12.97.
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Chemistry assessment
Elements were arranged by atomic number and properties of the elements varied periodically with atomic number.
What is Mendeleev's period Table?
Mendeleev's initial periodic table, which stated that "Element characteristics are a periodic function of their atomic weight," was first published in 1869.
The Periodic table of Mendeleev is a table in which Mendeleev listed elements in the order of their atomic masses.
Mendeleev made an effort to link the atomic masses to their chemical and physical characteristics.
Hence, the properties of the elements varied periodically with atomic number, and the elements were ordered according to their atomic numbers.
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0. Which of the following changes of state is
exothermic?
a. evaporation
b. melting
c. freezing
d. All of the above
The offered sentence describes the exothermic change in energy as "freezing."
Exothermic example: What is it?A reaction is deemed to be exothermic if it produces heat while also undergoing a net decrease in standard ∆h. Examples provide any type of flame, iron rusting, and water freezes. Exothermic processes are those that discharge heat and energy into the surrounding environment.
Exothermic vs. enthalpy change: what are they?Exothermic refers to chemical reactions which release energy. When bonds are created in the products of exothermic processes, more energy is produced than is required to break bonds between the reactants. Endothermic refers to chemical reactions that either use or absorb photons.
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when mtbe (shown) is reacted with hbr, carbons a and b will undergo nucleophilic substitution to yield two alkyl halides. by what mechanism of substitution will each c-o bond be cleaved?
when mtbe (shown) is reacted with hbr, carbons a and b will undergo nucleophilic substitution to yield two alkyl halides then by SN2 mechanism each c-o bonds will be cleaved.
When MTBE (methyl tert-butyl ether) is reacted with hydrogen bromide (HBr), the two C-O bonds in the molecule are expected to undergo an S N 2 substitution mechanism. This is because the reaction conditions are favorable for a bimolecular, concerted mechanism, where the nucleophilic (HBr) and substrate (MTBE) interact with each other to produce the products.
In the S N 2 mechanism, the C-O bonds in MTBE are cleaved via backside attack by the nucleophile, HBr. This involves the simultaneous formation of a new C-Br bond and breaking of the existing C-O bond. The attack takes place in a stereospecific manner, so that the orientation of the substrate and nucleophile determines the stereochemistry of the products. The S N 2 mechanism is typically favored under conditions where the substrate is a good leaving group and the nucleophile is a strong base.
In summary, both of the C-O bonds in MTBE are expected to be cleaved via an S N 2 mechanism when reacting with HBr.
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