A sample of an unknown metal has a mass of 6.557 g. The metal was carefully added to a graduated cylinder containing 10.50 mL of water. The water level in the graduated cylinder rose to 11.16 mL. What is the density of the unknown metal?​

Answer:

1) 1,1,1-trichloropropane

2) 1,1,2-trichloropropane

3) 1,2,2-trichloropropane

4) 1,2,3-trichloropropane

Explanation:

For this question, we must remember that isomers are molecules that have the same formula but different structures. For the formula [tex]C_3H_5Cl_3[/tex] we can draw a linear chain of three carbons and change the position of the chlorine atoms in the carbon chain.

With this in mind, if we put all the chlorine atoms on the same carbon we will get 1,1,1-trichloropropane. If we change an atom from chlorine to carbon 2 we will obtain 1,1,2-trichloropropane. If we move another chlorine atom to carbon two we will get 1,2,2-trichloropropane. Finally, if we put a chlorine atom in each carbon we will obtain 1,2,3-trichloropropane.

See figure one for further explanations

I hope it helps!

Answer:

3

Explanation:

Three significant figures

Answer:

Neon

Explanation:

A proton is the positively charged particle in the atom. The atomic number of an atom is the number of protons present in the atom while the mass number of an atom is the sum of the number of protons and neutrons in the nucleus of an atom.

If an extra proton is added to 19F, then neon is formed.

Answer:

[tex]M=6.03M[/tex]

Explanation:

Hello,

In this case, since the molarity is computed by:

[tex]M=\frac{n_{solute}}{V_{solution}}[/tex]

Whereas the solute is the hydrochloric acid, we compute the corresponding moles with its molar mass (36.45 g/mol):

[tex]n_{solute}=0.200gHCl*\frac{1molHCl}{36.45gHCl} =0.00549molHCl[/tex]

Next, since the solution contains both HCl and water, we compute the volume in liters by using its density:

[tex]V_{solution}=(0.200+0.801)g*\frac{1mL}{1.10g} *\frac{1L}{1000mL} =9.1x10^{-4}L[/tex]

Therefore, the molarity turns out:

[tex]M=\frac{0.00549mol}{9.1x10^{-4}L}\\ \\M=6.03M[/tex]

Regards.

Answer:

The answer is "Option A"

Explanation:

At 3300 cm-1, the wide region is equal to OH. It is a possible group of alcoholic features that includes drugs. In the given choices option a is correct that's the structure can be defined in attachment file please find it, and the wrong choice can be defined as follows:

the products formed from the reaction

all of the above

Answer:

ask a teacher is the correct answer.

Explanation:

You must ALWAYS ask a teacher if you are not sure about what to do during a lab activity.

Answer:

It's important to ask the teacher, lab safety policies all state that if you're confused about instructions it's always good to ask the teacher to clarify them.

Answer:

one atom of carbon

Explanation:

The relative atomic mass of elements can be used to determine their relative masses. If we look at all the options, we will notice that carbon has a relative atomic mass of 12, hydrogen has a relative atomic mass of 1 and lithium has a relative atomic mass of 7

We can now see that carbon has the greatest relative atomic mass among the options provided in the question.

Answer:

20 hydrogen atoms in 5 moles of methyl alcohol.

Explanation:

Hi!

So, there are 4 hydrogen atoms in 1 mole of methyl alcohol. If you multiply 4*5, it equals to 20.

Have a great day!

Answer:

1. Balanced Molecular equation

Ca(OH)2(aq) + 2HCl(aq) —> CaCl2(aq) + 2H2O(aq)

2. Net ionic equation

OH-(aq) + H+(aq) —> H2O(l)

Explanation:

1. Molecular balance equation for the reaction between Ca(OH)2(aq) and HCl(aq).

This is illustrated below:

Ca(OH)2(aq) + HCl(aq) —> CaCl2(aq) + H2O(aq)

There are 2 atoms of Cl on the right side and 1 atom on the left side. It can be balance by putting 2 in front of HCl as shown below:

Ca(OH)2(aq) + 2HCl(aq) —> CaCl2(aq) + H2O(aq)

There are 2 atoms of H on the right side and a total of 4 atoms on the left side. It can be balance by putting 2 in front of H2O as shown below:

Ca(OH)2(aq) + 2HCl(aq) —> CaCl2(aq) + 2H2O(aq)

Therefore the equation above is balanced.

2. Net ionic equation for the reaction between Ca(OH)2(aq) and HCl(aq).

In solution, Ca(OH)2(aq) and HCl(aq) will dissociate as follow:

Ca(OH)2(aq) —> Ca2+(aq) + 2OH-(aq)

HCl(aq) —> H+(aq) + Cl-(aq)

Ca(OH)2(aq) + 2HCl(aq) —>

Ca2+(aq) + 2OH-(aq) + 2H+(aq) + 2Cl-(aq) —> Ca2+(aq) + 2Cl-(aq) + 2H2O(l)

Cancel out the spectator ions i.e Ca2+ and Cl- to obtain the net ionic equation

2OH-(aq) + 2H+(aq) —> 2H2O(l)

OH-(aq) + H+(aq) —> H2O(l)

[tex]3y-20=7\implies y=\frac{20+7}{3}=9[/tex].

Hope this helps.

y= 9

Explanation:

=> 3y - 20 = 7

=> 3y = 7+20

=> 3y = 27

=> y = 27/3

=> y = 9

HOPE OT HELPS. ◉‿◉

Answer:

A. 15.6 days

Explanation:

We have a general formula used to solve for questions dealing with half life.

N(t) = No (1/2)^t/t½

Where

N(t) = Quantity of sample left after t days

No = Initial amount of sample

t½ = Half life of sample

t = Duration or time required for sample to decay

In the above question, we are asked to determine how long(time) that the sample has been in storage.

The formula for time (t) has been derived as:

t =[ t½ × In(Nt/No)] ÷ - In 2

Where

No = 237 grams

N(t) = 29.625 grams

t½ = 5.2 days

t = ????? Unknown

t = [ t½ × In(Nt/No)] ÷ - In 2

t = [ 5.2 × In(29.625/237)] ÷ - In 2

t = [5.2 × -2.0794415417] ÷ - In 2

t = -10.813096017 ÷ - ln 2

t = 15.6 days

Therefore, the sample has been in storage for 15.6 days.

Answer:

C

Explanation:

Tertiary alcohol should be the answer.

This is because tertiary alcohol has a less polar compound which means it is less likely to have chemical reaction with other compounds whereas primary and secondary alcohol has a higher chance of having chemical reaction with other compounds.

Answer:

I think the answer is A

Explanation:

primary alcohol has only one methyl group bonded to the central carbon atom, and the extent of decrease in partial posative charge is less, making it more prone to attack by nucleophiles. thus tertiary alcohols are more stable than primary alcohols

Answer:

b. pH=12

Explanation:

Step 1: Given data

Concentration of NaOH: 0.01 mol/dm³ = 0.01 mol/L = 0.01 M

Step 2: Write the reaction for the dissociation of NaOH

NaOH is a strong base that dissociates according to the following equation.

NaOH(aq) ⇒ Na⁺(aq) + OH⁻(aq)

The molar ratio of NaOH to OH⁻ is 1:1. Then, the concentration of OH⁻ is 0.01 M.

Step 3: Calculate the pOH

pOH = -log [OH⁻] = -log 0.01 = 2

Step 4: Calculate the pH

We will use the following expression.

pH + pOH = 14

pH = 14 - pOH = 14 -2 = 12

Answer:

3,5-dichlorohex-1-ene

Explanation:

The compound is; H2C=CH-C(Cl)H-CH2-C(Cl)H-CH3. We can rightly call this compound by the name, 3,5-dichlorohex-1-ene.

We arrived at this name by first counting the longest parent carbon chain, that gives hexane. The compound has a double bond at the 1-position. Also, there are two substituent chlorine atoms at positions 3 and 5 in the structure, hence the name given.

Answer:

See explanation below.

Explanation:

We can obtain the Gibb's free energy from the formula;

∆G= ∆H - T∆S

Where;

∆G = change in free energy= the unknown

∆H= change in enthalpy = 3352 kJ

∆S= change in entropy of the solution= 625.1 J/K

T= absolute temperature = 298 K

Substituting values;

∆G= 3352 ×10^3 J - (298 K × 625.1 J/K)

∆G= 3352 ×10^3 J - 186279.8

∆G= 3.16 × 10^6 J

At 5975K,

∆G= ∆H - T∆S

∆G= 3352 ×10^3 J - (5975K × 625.1 J/K)

∆G= 3.352 ×10^6 J - 3.735 × 10^6

∆G= -3.83×10^5 J

At equilibrium, ∆G=0, Teq is given by;

0= 3352 ×10^3 J - (Teq × 625.1 J/K)

0= 3352 ×10^3 - 625.1Teq

625.1Teq = 3352 ×10^3

Teq= 3352 ×10^3/625.1

Teq= 5362.3 K

Standard Gibb's free energy at 298 & 5975K is 3.16×10⁶J and -3.83×10⁵J respectively, and temperature at equilibrium state is 5362.3 K.

Standard Gibb's free energy of any reaction will be calculated as:
∆G° = ∆H° - T∆S°, where

∆G° = change in free energy = to find?

∆H° = change in enthalpy = 3352 kJ = 3,352 × 10³J

∆S° = change in entropy = 625.1 J/K

T = absolute temperature = 298 K

On putting all these values on the above equation, we get

∆G° = (3,352 × 10³) - (298 × 625.1) = 3.16 × 10⁶J

Gibb's free energy at 5,975 K temperature:

∆G° = (3,352 × 10³) - (5,975 × 625.1) = -3.83 × 10⁵J

At the equilibrium state value of Gibb's free energy is zero, so from the equation and given data we can calculate the value of temperature as:

0 = (3352 × 10³)J - (T × 625.1 J/K) = 5362.3 K

Hence required values are 3.16 × 10⁶J, -3.83 × 10⁵J and 5362.3 K.

To know more about Gibb's free energy, visit the below link:

https://brainly.com/question/9908454

Answer:

E. a small yellow ball that represents the Sun

Explanation:

key word on the question, 'physical'

Answer:

Metal C

Explanation:

Density = mass (g)/ volume (mL, which is the same thing as cm cubed)

Divide mass by volume for each metal, the metal with the lowest value (metal C) is your answer.

Answer:

IT IS

NOT. I REPEAT - IT IS NOT> D

Explanation:

i got it wrong :(

Answer:

The correct answer is 8.04 mL

Explanation:

Given the neutralization reaction:

HCl(aq) + NaOH(aq) ––––> NaCl(aq) + H₂O(l)

1 mol of HCl reacts with 1 mol of NaOH.

The number of moles of NaOH there is in 15.8 mL is calculated as follows:

0.321 mol/L x 1 L/1000 mL x 15.8 mL = 5.07 x 10⁻³ mol NaOH

Thus, we need 5.07 x 10⁻³ mol of HCl to react with 5.07 x 10⁻³ mol NaOH. We have a 0.631 M HCl solution. We calculate the volume of HCl we need by considering that 1 mol NaOH reacts with 1 mol HCl and that there are 0.631 moles of HCl in 1 liter of solution (1000 mL):

5.07 x 10⁻³ mol NaOH x 1 mol HCl/1 mol NaOH x 1000 mL/0.631 mol HCl = 8.04 mL

Answer:

Weight is a noun that means a human body's mass.

For example: Joh is 168 pounds.

This is the correct definition of weight.

Here to help!

Answer:

The cis double bond present in unsaturated fatty acids acids results in lower melting point when compared to saturated fatty acids of the same chain length.

Explanation:

Melting point of a fatty acids are affected by the length and degree of unsaturation of the hydrocarbon chain.

At room temperature, saturated fatty acids with hydrocarbon chain lengths between 12-24 are waxy solids whereas unsaturated atty acids of the same chain length are liquids. This is due to the nature of the packing of the fatty acid molecules in the saturated and unsaturated compounds.

In the saturated compounds, the molecules are tightly packed side by side with minimal steric hindrance and maximal van der Waals forces of attraction between molecules. However, in unsaturated fatty acids, the cis double bond introduces a bend or kink in the molecules which then interferes with the tight packing of the molecules and reducing interaction between molecules. Therefore, less energy is required to cause a disorder in the arrangement of unsaturated fatty acids, leading to a lowering of melting point.  

Answer:

Explanation:

We can only talk about resonance hybrid for a compound in which more than one structure is possible based on its observed chemical properties.

There are compounds whose chemical properties can not be satisfactorily explained on the basis of a single chemical structure. In the case of such compounds, we invoke the idea of resonance.

A resonance hybrid is a single structure drawn to represent a given chemical specie which exhibits resonance behaviour and can otherwise be represented on paper in the form of an average of two or more chemical structures separated each from the next by a double-headed arrow.

Answer:

Resonance hybrids are best defined as a molecule's electron pattern cannot be described by a single structure.

Explanation:

its right

Answer:

Al(s) 28.3

Explanation:

Aluminum forms a layer of aluminum oxide when exposed to air which protects the bulk metal from further corrosion.

Aluminum forms a layer of aluminum oxide when exposed to air which protects the bulk metal from further corrosion.4Al(s) + 3O2(g) ? Al2O3(s)

AnswerAluminum forms a layer of aluminum oxide when exposed to air which protects the bulk metal from further corrosion.

4Al(s) + 3O2(g) ? 2Al2O3(s)

Using the thermodynamic data provided below, calculate S° for this reaction.

S°(J/K.mol)

Al(s) 28.3

O2(g) 205.0

Al2O3(s) 50.99

2. Aluminum forms a layer of aluminum oxide when exposed to air which protects the bulk metal from further corrosion.

4Al(s) + 3O2(g) ? Al2O3(s)

Calculate G° for this reaction, given that ?G°f of aluminum oxide is –1576.4 kJ/mol.

Answer:

Explanation:

Explanation:

Answer:

b) The boiling point of the solution is always greater than the boiling point of the pure solvent.

Explanation:

Hello,

In this case, when we add a nonvolatile solute to a volatile solvent which has a relatively low boiling point, we can evidence the increase of the boiling point of the resulting solution as more energy must be supplied to take the molecules from liquid to gas. This fact matches with the boiling point elevation colligative property due to the solute's addition, which states that the boiling point of the solution is always greater than the boiling point of the pure solvent, therefore, answer is b).

Best regards.

The statement true about the solution made from a nonvolatile solute and a volatile solvent is, the boiling point of the solution is always greater than the boiling point of the pure solvent. Thus option C is correct.

The boiling point of the solution can be defined as the temperature where the liquid has been converted to the gaseous state. In the solvent, the energy has been provided to the sample for the conversion of liquid molecules to gas.

The addition of a nonvolatile solute to the volatile solvent results in the addition of the molecules to the solvent. This will result in the requirement of more energy for the conversion of solvent from a liquid state to a gaseous state.

Thus, with the addition of a nonvolatile solute to the volatile solvent, the boiling point of the solution will be increased and will always be greater than the boiling point of the pure solvent.

Thus option C is correct.

For more information about the volatile solvent, refer to the link:

https://brainly.com/question/3013635

Answer:

0.5 g/L.

Explanation:

Hello,

In this case, for this solubility problem, we can write for the lead (II) fluoride:

[tex]PbF_2(s)\rightleftharpoons Pb^{2+}(aq)+2F^-(aq)[/tex]

And the equilibrium expression is:

[tex]Ksp=[Pb^{2+}][F^-]^2[/tex]

Whereas Ksp of lead (II) fluoride is 3.3x10⁻⁸. In such a way, we can write the equilibrium expression in terms of the molar solubility [tex]x[/tex] as follows:

[tex]Ksp=(x)(2x)^2=3.3x10^{-8}[/tex]

Hence, solving for [tex]x[/tex] we find:

[tex]x=\sqrt[3]{\frac{3.3x10^{-8}}{4} }\\\\x=2.02x10^{-3}M[/tex]

Moreover, since the molar mass of lead (II) fluoride is 245.2 g/mol, the solubility turns out:

[tex]2.02x10^{-3}\frac{molPbF_2}{L}*\frac{245.2gPbF_2}{1molPbF_2}\\ \\0.5\frac{g}{L}[/tex]

Best regards.

Answer:

1.4 moles.

Explanation:

The following data were obtained from the question:

Initial mole (n1) = 1.8 moles

Initial pressure (P1) = 25.5 atm

Final pressure (P2) = 5.7 atm

Number of mole removed =?

Next, we shall obtain an expression relating pressure and number of mole together.

This is illustrated below:

From the ideal gas equation:

PV = nRT

Divide both side by V

P = nRT /V

Divide both side by n

P/n = RT/V

But volume (V) and temperature (T) are constant.

P/n = constant

P1/n1 = P2/n2

P1 is initial pressure.

P2 is final pressure.

n1 is the initial mole.

n2 is the final mole.

Next, we shall determine the final mole in tank as follow:

Initial mole (n1) = 1.8 moles

Initial pressure (P1) = 25.5 atm

Final pressure (P2) = 5.7 atm

Final mole (n2) =.?

P1/n1 = P2/n2

25.5/1.8 = 5.7/n2

Cross multiply

25.5 x n2 = 1.8 x 5.7

Divide both side by 25.5

n2 = (1.8 x 5.7) /25.5

n2 = 0.40 mole.

Therefore, the final mole in the tank is 0.40 mole.

Finally, we shall determine the number of mole that was removed as follow:

Initial mole (n1) = 1.8 moles

Final mole (n2) = 0.4 mole

Number of mole removed =?

The number of mole removed from the tank can be obtained by finding the difference between the initial mole and final mole as illustrated below:

Number of mole removed = initial mole – final mole

Number of mole removed = n1 – n2

Number of mole removed = 1.8 – 0.4

Number of mole removed = 1.4 moles

Therefore, 1.4 moles were removed from the tank.

Answer:

7,052.6secs

Explanation:

n of Cu = +2

R.A.M of Cu = 64g

m = 7.25g

I = 3.1A

F = 96500

nF = R.A.M

It = m

2*96500 = 64

3.1*t = 7.25

1,399,250 = 198.4t

t = 7,052.6secs

Answer:

B. CH3CH2OH

Explanation:

Ethanol has a chemical formula of CH3CH2OH, it is the second member of the series in the alkanol family. Ethanol is a colourless, volatile liquid with a characteristic smell and taste. It is readily soluble in water in all proportions. It has a boiling point of 78° C. The physical properties such as the solubility of alkanols are affected by the presence of hydrogen bonding. The hydroxyl group is capable of bonding to other alkanol molecules. The boiling points rise with increasing molecular mass.

    Hydrogen bonding helps the molecules to stick together. For example comparing the boiling point of pentane ( 36° C) with that of butan-1-ol (118° C) , the boiling point of alkanol is much higher even though the two compound are of similar relative molecular mass. This is due to the presence of hydrogen bonds in butanol.

    Hydrocarbons are not soluble in water but alkanols are soluble in water because of the hydroxyl groups in the molecules can form hydrogen bond with water. Solubility of alkanol in water decreases as the number of carbon atom increases. Primary alcohol with more than five carbon atoms are insoluble in water.

Answer:

Molality, Solvent, Solute, Mole fraction, Molarity.

Explanation:

The expression of concentration that provides the moles of solute per kilograms of solvent is Molality.  This in the only expression referred to the solvent.

A solution is made up of 0.15 grams of sodium chloride in 1 liter of water. For this solution, the Solvent is water.  When water is present, it is usually considered the solvent.

A solution is made up of 0.15 grams of sodium chloride in 1 liter of water. For this solution, the Solute is sodium chloride.  There can be 1 or more solutes in a solution.

If you place 5 moles of sodium chloride and 4 moles of sucrose into 11 moles of water, the Mole fraction of sodium chloride would be 0.25.  The mole fraction is equal to the moles of a substance divided by the total number of moles.

A way to express concentration that provides the moles of solute per liter of solution is Molarity.

Answer:

identical conditions, separate samples of O2 and an unknown gas were allowed to effuse through identical membranes simultaneously. After a certain amount of time, it was found that 6.23 mL of O2 had passed through the membrane, but only 3.85 mL of of the unknown gas had passed through. What is the molar mass of the unknown gas

identical conditions, separate samples of O2 and an unknown gas were allowed to effuse through identical membranes simultaneously. After a certain amount of time, it was found that 6.23 mL of O2 had passed through the membrane, but only 3.85 mL of of the unknown gas had passed through. What is the molar mass of the unknown gas

Explanation:

identical conditions, separate samples of O2 and an unknown gas were allowed to effuse through identical membranes simultaneously. After a certain amount of time, it was found that 6.23 mL of O2 had passed through the membrane, but only 3.85 mL of of the unknown gas had passed through. What is the molar mass of the unknown gas