Answer:
[tex]E=101955.8volt/m[/tex]
The electric field direction is toward the right
Explanation:
From the question we are told that
Initial X-co-ordinate of proton [tex]X_1=20.0cm => \frac{20}{100}m[/tex]
Initial speed of Proton [tex]V_1= 3.5*10^6 m/s[/tex]
Final X-co-ordinate of proton [tex]X_2=80.0cm => \frac{80.0}{100}m[/tex]
Final speed of Proton [tex]V_2=0[/tex]
Generally the mass of Proton is given by
[tex]m_P=1.67*10^-27[/tex]
Generally the kinetic energy of the proton is mathematically given by
[tex]K.E_p=1/2mv^2[/tex]
[tex]K.E_p=1/2*1.6*10^-^2^7*(3.5*10^6)^2[/tex]
[tex]K.E_p=9.8*10^-^1^5[/tex]
Generally the change in electric potential [tex]\triangle V[/tex] is mathematically given by
[tex]\triangle V =\frac{K.E_p}{q}[/tex]
Charge on a proton [tex]q=1.602*10^-^1^9[/tex]
[tex]\triangle V =\frac{9.8*10^-^1^5}{1.602*10^-^1^9}[/tex]
[tex]\triangle V =61173.5volts[/tex]
Generally the equation for magnitude of an electric field is mathematically given by
[tex]E=\frac{\triangle V}{\triangle d}[/tex]
Where
[tex]d=0.8m-0.2m\\d=0.6m[/tex]
Therefore
[tex]E=\frac{61173.5}{0.8-0.2}[/tex]
[tex]E=\frac{61173.5}{0.6}[/tex]
[tex]E=101955.8volt/m[/tex]
The direction of the charge is towards the right
Water falls without splashing at a rate of 0.200 L/s from a height of 3.60 m into a 0.730 kg bucket on a scale. If the bucket is originally empty, what does the scale read (in newtons) 3.20 s after water starts to accumulate in it
Answer:
15.106 N
Explanation:
From the given information,
The weight of the bucket can be calculated as:
[tex]W_b = m_bg = \\ \\ W_b = (0.730 \ kg) ( 9.80 \ m/s^2) \\ \\ W_b = 7.154 \ N[/tex]
The mass of the water accumulated in the bucket after 3.20s is:
[tex]m_w= (0.20 \ L/s) ( 3.20)s[/tex]
[tex]m _w=0.64 \ kg[/tex]
To determine the weight of the water accumulated in the bucket, we have:
[tex]W_w = m_w g[/tex]
[tex]W_w = ( 0.64 \ kg )(9.80\ m \ /s^2)[/tex]
[tex]W_w = 6.272 \ N[/tex]
For the speed of the water before hitting the bucket; we have:
[tex]v = \sqrt{2gh}[/tex]
[tex]v = \sqrt{2*9.80 \ m/s^2 * 3.60 \ m}[/tex]
v = 8.4 m/s
Now, the force required to stop the water later when it already hit the bucket is:
[tex]F = v ( \dfrac {dm}{dt} )[/tex]
[tex]F = (8.4 \ m/s)( 0.200 \ L/s)[/tex]
F = 1.68 N
Finally, the reading scale is:
[tex]F_{scale[/tex] = 7.154 N + 6.272 N + 1.68 N
= 15.106 N
Answer:
F_scale ≈ 15.12 N
Explanation:
We are given;
Mass flow rate; m' = 0.2 l/s
Time; t = 3.2 s
Mass of bucket; m_b = 0.730 kg
Height; h = 3.6 m
Now, mass of water is;
m_w = 0.2 l/s × 3.2 s
m_w = 0.64 l
From conversion, 1 litre = 1 kg
Thus: m_w = 0.64 kg
Now, let's calculate final velocity from Newton's third equation of motion.
v² = u² + 2gh
Initial velocity is 0. Thus;
v² = 0 + 2(9.8 × 3.6)
v² = 70.56
v = √70.56
v = 8.4 m/s
Now, total mass of water and bucket is;
m_t = m_w + m_b = 0.64 + 0.73
m_t = 1.37 kg
Force on the scale is calculated from;
F_scale = (m_t)g + (m_w)v/t
F_scale = (1.37 × 9.81) + (0.64 × 8.4/3.2)
F_scale ≈ 15.12 N
To move the Center of Gravity (CG) forward, you could do which of the following?
Add clay to the nose.
Increase the density of the nose material.
Decrease the volume of the horizontal and vertical stabilizer material.
All of the above.
its not Increase the density of the nose material bc i tried that so help pleasee
Answer:
I think it's no. 3
Decrease the volume of the horizontal and vertical stabilizer material.
Explanation:
Lemme know if it's correct
Answer:
all of the above
Explanation:
Squamous cells are basically clear, dead cells, filled with an ingredient of keratin
called eleidin.
True
False
Squamous cells, which are tiny, flat cells that resemble fish scales, are present in the tissue that makes up the skin's surface, and the lining of the digestive and respiratory systems.
What are the characteristics of Squamous cells?Simple squamous epithelial cells serve as filtration and diffusion mediators. They enable facile transmembrane transit of tiny molecules (i.e., across the membrane and through the cell) because of their straightforward and thin construction.
The centre of squamous epithelial cells, which are big, flattened cells loaded with cytoplasm, is a small, spherical nucleus. They are spherical and unevenly flat.
Therefore, The lumen is a free area that is surrounded by simple squamous epithelium. Simple squamous cells join together to produce a layered structure.
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A light ray in glass (n=1.5) hits the air-glass interface at an angle of 10 degrees from the normal. What angle from the normal is the light ray in the air (n=1.0)? (You can use the small angle approximation.)
Answer:
The angle from the normal is 15.1°.
Explanation:
We can find the angle by using Snell's law:
[tex] n_{1}sin(\theta_{1}) = n_{2}sin(\theta_{2}) [/tex]
Where:
n₁: is the first medium (glass) = 1.5
n₂: is the second medium (air) = 1.0
θ₁: is the first angle (in the glass) = 10°
θ₂: is the second angle (in the air) =?
[tex] \theta_{2} = arcsin(\frac{n_{1}sin(\theta_{1})}{n_{2}}) = arcsin(\frac{1.5*sin(10)}{1.0}) = 15.1 ^{\circ} [/tex]
Therefore, the angle from the normal is 15.1°.
I hope it helps you!
Assume that, as the battery wears out, the voltage decreases at 0.03 volts per second and, as the resistor heats up, the resistance is increasing at 0.02 ohms per second. When the resistance is 100 ohms and the current is 0.02 amperes, at what rate is the current changing
Answer:
[tex]\frac{dI}{dt} =-3*10^-^4amps/sec[/tex]
Explanation:
From the question we are told that
Voltage decreases at [tex]\frac{dv}{dt} =-0.03volts/sec[/tex]
Resistance increase at [tex]\frac{dR}{dt}=0.02ohms /sec[/tex]
Resistance at [tex]R=100ohms[/tex]
Current at [tex]I=0.02amps[/tex]
Generally the equation for ohms law is mathematically represented as
[tex]V=IR[/tex]
Therefore
[tex]\frac{dV}{dt} =R\frac{dI}{dt} +I\frac{dR}{dt}[/tex]
Generally making [tex]\frac{dI}{dt}[/tex] subject of the formula in the above equation mathematically gives
[tex]\frac{dV}{dt} =R\frac{dI}{dt} +I\frac{dR}{dt}[/tex]
[tex]R\frac{dI}{dt} = \frac{dV}{dt} -I\frac{dR}{dt}[/tex]
[tex]\frac{dI}{dt} =\frac{1}{R} (\frac{dV}{dt} -I\frac{dR}{dt})[/tex]
Therefore
[tex]\frac{dI}{dt} =\frac{1}{100}((-0.03) -(0.02)*(0.02))[/tex]
Generally it is given that the change in current is
[tex]\frac{dI}{dt} =-3*10^-^4amps/sec[/tex]
Assess It! Question #2: Which of the following statements about the Law
of Acceleration is true?
5 points
A: Increasing an object's mass decreases the amount of force required to move it
B: Decreasing the mass of an object increases its acceleration while force is
constant
C: Increasing the force applied to an object does not change its acceleration while
mass is constant
D: Decreasing the force applied to an object increases its acceleration while mass is
constant
Answer:
Statement B is the only true statement
"Decreasing the mass of an object increases its acceleration while force is constant."
Explanation:
Recall that Newton's 2nd Law states:
F = m * a
Therefore, if the force (F) is constant, and the mass (m) decreases, the acceleration (a) of the object must increase.
This agrees with the statement labeled as B: "Decreasing the mass of an object increases its acceleration while force is constant."
The true statement about the law of acceleration is that decreasing the mass of an object increases its acceleration while force is constant.
NEWTON'S LAW:
The relationship between the force, mass and acceleration has been explained by Newton in his law. The equation is as follows:Force = mass × accelerationAccording to the equation, the mass is inversely proportional to the acceleration. This means that as the mass increases, the acceleration decreases and vice versa. Therefore, the true statement about the law of acceleration is that decreasing the mass of an object increases its acceleration while force is constant.Learn more at: https://brainly.com/question/25116504?referrer=searchResults
Amateur radio operators in the United States can transmit on several bands. One of those bands consists of radio waves with a wavelength near . Calculate the frequency of these radio waves.
This question is not complete, the complete question is;
Amateur radio operators in the United States can transmit on several bands. One of those bands consists of radio waves with a wavelength near 20 m . Calculate the frequency of these radio waves.
Answer: frequency of the radio waves is 15 MHz
Explanation:
Given that;
wavelength λ = 20 m
we know that; Speed of light C = 3 × 10⁸ m/s
frequency f = ?
we know that;
frequency f = Speed of light C / wavelength λ
so we substitute
frequency f = (3 × 10⁸m/s) / (20m)
frequency f = 15 × 10⁶ Hz
we also know that 1 Hertz = 0.000001 Megahertz
so
frequency f = 15 × 10⁶ Hz × 0.000001
frequency f = 15 MHz
Therefore frequency of the radio waves is 15 MHz
why is there a difference between potential and kinetic energy?
Potential energy is stored energy because it has the potential to do something which laters turns into kinetic energy which is the moving energy.
What body part is the metric system based upon?
legs
arms
feet
fingers
The metric system is an internationally used system of checking various quantiles if weight tat includes the length, temperature, mass, etc., and is used in everyday life.
As nearly all the units are based on the human body they include the thumb joint was taken as yardsticks and was once used to define distance.Hence the option D is correct.
Learn more about the part is the metric system based upon.
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I think about you all day and at night I watch the stars shoot
I know love is not a game but I can't control what my heart do
I messed up so many times, I know you thinking I don't want you
I never tell you lies, I'm always giving you the hard truth
Remember we was way more than friends, I just wonder, "Would you love me again?"
I'm always having spaceship vibes, sometimes I think that I'm an alien
What is this song?
Answer:
Spaceship Vibes
Explanation:
Song written by NoCap
Two carts connected by a 0.50 m spring hit a wall, compressing the spring to 0.25 m. The spring constant k is
N
200
m
What is the elastic potential energy stored from the spring's compression?
Khan aced my?
Answer:
6.25J
Explanation:
bc that’s the answer on khan
Two carts connected by a 0.50 m spring hit a wall, compressing the spring to 0.25 m. If the spring constant k is 200 N/m, then the elastic potential energy stored from the spring's compression would be 6.25 J.
What is the spring constant?The spring constant is used to define the stiffness of the spring, the greater the value of the spring constant stiffer the spring and it is more difficult to stretch the spring.
The mathematical relation for calculating the spring constant is as follows
F = - Kx
as given in the problem Two carts connected by a 0.50 m spring hit a wall, compressing the spring to 0.25 m. If the spring constant k is 200 N/m,
The elastic potential energy stored is given by
E = 1/2 kx²
=0.5×200×0.25²
=6.25 J
Thus, the elastic potential energy stored from the spring's compression would be 6.25 J.
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Block A of mass M is at rest and attached to the top of a spring. The block compresses the spring a distance d from its uncompressed length at equilibrium. Block B of mass 2M is released from rest at a height h above block A . The two blocks collide and stick together. Express all answers in terms of d , h , M , and physical constants, as appropriate.
Required:
a. Derive an expression for the spring constant k of the spring.
b. Derive an expression for the speed of block B just before it collides with block A.
c. Derive an expression for the speed of the blocks immediately after the collision.
d. Derive an expression for the maximum compression of the spring after the collision.
e. If the collision between the blocks was elastic, would the maximum compression of the spring be greater than, less than, or equal to that found in part (d)? Justify your answer.
Answer:
a) k = Mg / d , b) v = √2gh , c) v_{f} = [tex]\frac{2}{3} \ \sqrt{2gh}[/tex], d) x² + 6d x - [tex]\frac{8}{3}[/tex] dh = 0
e)the spring must compress a greater distance.
Explanation:
a) when the block of mass M is placed on the spring, we have an equilibrium condition,
∑ F = 0
[tex]F_{e}[/tex]- W = 0
k d = Mg
k = Mg / d
b) let's use the concepts of energy to find the velocity of the block just before the collision
starting point. Position when released
Em₀ = U = m g h
lowest point. Right at the point of shock
[tex]Em_{f}[/tex] = K = ½ m v²2
as there is no friction, energy is conserved
Em₀ = Em_{f}
mg h = ½ m v²
v = √2gh
c) The velocity of the two blocks after the collision, we define a system formed by the two blocks, in such a way that the forces during the collision are internal and the moment is conserved
initial instant. Just before the crash
p₀ = 2M v + M 0
final instant. Just after the shock, before the spring compression begins
p_{f} = (2M + M) v_{f}
the moment is preserved
p₀ = p_{f}
2M v = 3M v_{f}
v_{f} = ⅔ v
v_{f} = [tex]\frac{2}{3} \ \sqrt{2gh}[/tex]
d) now we work with the joined system after the collision, let's use the concepts of energy
starting point. After shock, before beginning spring compression
Em₀ = K = ½ (3M) [tex]v_{f}^2[/tex]
Em₀ = 3/2 M (\frac{2}{3} \ \sqrt{2gh})²
Em₀ = 4/3 M gh
final point. With the spring fully compressed
Em_f = K_e + U = ½ k x² + (3M) g x
in this case we have taken the zero of gravitational potential energy at the point where the blocks collide, as there is no friction, the energy is conserved
Em₀ = Em_f
4/3 M g h = ½ k x² + 3M g x
½ k x² + 3Mg x - 4/3 Mgh = 0
we substitute the expression for k
[tex]\frac{1}{2}[/tex] ([tex]\frac{Mg}{d}[/tex]) x² + 3Mg x - [tex]\frac{4}{3}[/tex] Mgh = 0
[tex]\frac{x^{2} }{2d}[/tex] + 3 x - [tex]\frac{4}{3}[/tex]h = 0
to find the value of the spring compression, the second degree equation must be solved
x² + 6d x - [tex]\frac{8}{3}[/tex] dh = 0
x = [-6d ±[tex]\sqrt{(36 d^{2} - 4 \frac{8}{3} dh) }[/tex] ] / 2
x = [-6d ± 6d [tex]\sqrt{ 1 - \frac{32}{3 \ 36} \ \frac{h}{d} }[/tex] ]/2
x = 3d ( -1± [tex]\sqrt{ 1 - 0.296 \frac{h}{d} }[/tex] )
e) If the collision elastic force would not lose any part of the kinetic energy during the collision, therefore the speed of the block of mass M would be much higher and therefore the spring must compress a greater distance.
Need help fast pls thanks
Answer:
We need the question
Explanation:
The answer is the first choice.
A bat with a force of 50 N hits a softball with a mass of 0.5 kg. What will the softball's acceleration rate be?
Answer:
100m/s²
Explanation:
F=ma
50=0.5a
a=50/0.5
a=100
Describe what determines magnetism and how an electromagnet works.
Answer:
Magnetism is the force exerted by magnets when they attract or repel each other
hope it helps you:)
A ball is thrown upward and reaches a maximum height of 20 meters and then returns back to where it was launched. What is the displacement of the ball?
Answer: 0
Explanation: because when it return total displacement is 0
a small glass or plastic tube that contains a piece of wire is called a circuit breaker
T or F?
Answer:
False, it is a fuse.
Explanation:
In electronics and electrical engineering, a fuse is an electrical safety device that operates to provide overcurrent protection of an electrical circuit. Its essential component is a metal wire or strip that melts when too much current flows through it, thereby stopping or interrupting the current. It is a sacrificial device; once a fuse has operated it is an open circuit, and must be replaced or rewired, depending on its type.
Fuses have been used as essential safety devices from the early days of electrical engineering. Today there are thousands of different fuse designs which have specific current and voltage ratings, breaking capacity and response times, depending on the application. The time and current operating characteristics of fuses are chosen to provide adequate protection without needless interruption. Wiring regulations usually define a maximum fuse current rating for particular circuits. Short circuits, overloading, mismatched loads, or device failure are the prime or some of the reasons for fuse operation.
A fuse is an automatic means of removing power from a faulty system; often abbreviated to ADS (Automatic Disconnection of Supply). Circuit breakers can be used as an alternative to fuses, but have significantly different characteristics.
Source: https://en.wikipedia.org/wiki/Fuse_(electrical)
A fuse is a small glass or plastic tube that contains a piece of wire. That wire is carefully calibrated so that it will only allow a certain level of current to pass through it. Any more, and the wire will melt from the heat, breaking the circuit. This means that if a power surge comes into your home, a circuit will be broken before it causes damage to your appliances.
A circuit breaker achieves the same thing, but by a different method. A circuit breaker also disconnects the circuits in your home if the current gets too large but does it using electromagnets. If the current gets high enough, then the electromagnet will become powerful enough to attract a contact and break the circuit that way.
Both circuit breakers and fuses can be used to help with another situation. If you have an appliance with a metal case and that appliance comes in contact with a live wire, it can cause you to electrocute yourself. But if that metal case is connected to a ground wire (the third pin in some plugs), then the electricity will flow through the ground wire, through the circuit breaker or fuse box, and break the circuit, stopping you from potentially getting electrocuted.
Source: https://study.com/academy/lesson/the-differences-between-fuses-circuit-breakers.html
When the 5.0 kg cylinder fell 100 m, the final temperature of the water was °C and the change in temperature was °C.
When the 5.0 kg cylinder fell 500 m, the final temperature of the water was °C and the change in temperature was °C.
Answer:
26.17
1.17
30.86
5.86
Explanation:
said they were correct on my assignment
an impulse is a force acting over some amount of time to cause a change in momentum. on the other hand, work is a
Answer:
force; distance; energy.
Explanation:
An impulse can be defined as the net force acting an object for a very short period of time.
Mathematically, impulse is given by the formula;
[tex] Impulse = force * time[/tex]
An impulse is a force acting over some amount of time to cause a change in momentum. On the other hand, work is a force acting over some amount of distance to cause a change in energy.
Mathematically, work done is given by the formula;
[tex] Work done = force * distance [/tex]
Ignoring mass and weight contributed by fuel, what happens when the space shuttle takes off and moves away from earth?
Answer:
Its mass increases and weight decreases. Its mass remains constant and weight decreases.
Help please..................
HELP ME PLEASE, I'M BEING TIMED FAST
Answer:
A) Energy is tranferred from Joey to the water. The temperature of the water increases.
Explanation:
At first Joey jumps and gains a height above the water level of the pool, this way has an energy potential initial, as Joey falls into the water his speed is increased that is to say its energy potential is transformed into kinetic energy, and at the moment of impact with the water, this energy kinetic is transformed into heat which is transferred to the water. Therefore the temperature increment.
Note: This is one of the reasons why space agencies are studying spatial asteroids that are directed toward the earth, as these come with great kinetic energy, and great potential energy, if these are of a considerable size can cause catastrophic damage, even if they fall into the ocean, due to the large amount of energy which can cause the instantaneous evaporation of large amounts of water and collateral damage in other areas.
When a charged particle moves perpendicularly to a uniform magnetic field, what best describes its trajectory
Answer:
A circle.
Explanation:
When a charged particle moves perpendicularly to a uniform magnetic field, what best describes its trajectory is a circle.
This ultimately implies that, a charged particle moving perpendicularly to a uniform magnetic field would undergo or experience a uniform circular motion and this simply, describes its trajectory.
Additionally, the frequency would be directly proportional to the mass of the charged particle.
Two rope tows operate on the same ski slope. Tow A with a heavier load pulls as fast as Tow B. Which does the most work? Which has the most power?
Answer:
tow a has the most power but tow b does the most work
Explanation:
Tow A with a heavier load pulls as fast as Tow B, Then A does The most work, and A also has more power.
What is power?It is defined as the Rate of work done or the ratio of work done and time.
If the amount of work(W) is down over a time interval of (t) then the power is given by,
P=W/t
Where W=is work done by a force is known as a product of force and distance.
t= time interval in s.
Force
F= force which is known as the rate of momentum.=mv/t
where m= mass of the body in kg.
v= velocity in m/s.
Here in the question, given that A pulls heavier weight than B that means A applied more force which results in more work.
When more work is done by A than by B then the power of an also greater than B because they move at the same velocity.
Hence, The Work done as well as the power of A is more.
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PLEASE NEED HELP ASAP
Answer:
My youngins heartless, so they ain't playin' no games
We really want 'em dead, he got hit up close range
He fuc__ked up in the head, he wanna see some more brains
On that corner, I couldn't stay up out that do_0pe game
My cousin got indicted dealin' coc__aine
She an Insta>:gram addict, she want more fame
I used to starve, now I'm blowing up like pro__pane
Told my inner self, "I promise you I won't change"
Explanation:
Free association and dream analysis are techniques used in psychoanalysis to discover a person’s unconscious urges.
Please select the best answer from the choices provided
True or False?
Answer:
T on edge
Explanation:
Answer:
true
Explanation:
what is work? how do we solve for work?
Answer: Work can be calculated with the equation: Work = Force × Distance. The SI unit for work is the joule (J), or Newton • meter (N • m). One joule equals the amount of work that is done when 1 N of force moves an object over a distance of 1 m.
Explanation:
Answer:Work can be calculated with the equation: Work = Force × Distance. The SI unit for work is the joule (J), or Newton • meter (N • m). One joule equals the amount of work that is done when 1 N of force moves an object over a distance of 1 m.
Explanation:
What is the approximate momentum of a car with a mass of 1200 kg and a
velocity of 30.0 km/h? *
A. 13.0 N.S
B. 40.0 N.S
C.3.60 104 N.S
D. 5.40 x 104 N.S
In the first 2 seconds of a race, an athlete accelerates constantly from 0 m/s and reaches a
speed of 9 m/s.
Calculate the acceleration of the athlete. You do not need to state the unit here.
Given :
Initial speed, u = 0 m/s.
Final speed, v = 9 m/s.
Time taken to reach that speed, t = 2 sec.
To Find :
The acceleration of the athlete.
Solution :
We know, in uniform acceleration motion :
[tex]v= u+at\\\\a = \dfrac{v-u}{t}\\\\a = \dfrac{9-0}{2}\ m/s\\\\a = 4.5 \ m/s^2[/tex]
Therefore, acceleration of the athlete is 4.5 m/s².
On a sunny day, a family decided to take sail on a nearby lake. During sailing the wind applies a force of 25N north on the sails of the sailboat. The
water however exerts a force of 20 N east. If the total mass of both the sailboat and the crew (family on board) is 20kg, what is the magnutude and
direction of the acceleration produced?
Answer:
its n
Explanation:
The acceleration of the boat is obtained as 1.6 ms-2.
We have to obtain the resultant force acting on the boat in order to obtain the acceleration of the boat.
Resultant force on the boat = √(25)^2 + (20)^2 = √625 + 400 = 32 N
Now recall that from Newton's laws; F = ma
m= mass of the body
a = acceleration of the body
32 N = 20Kg × a
a = 32 N/20Kg
a = 1.6 ms-2
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