The length of the vibrating section of the violin string is approximately 16 cm.
The length of the vibrating section of the violin string can be calculated using the formula for the wavelength of a wave on a string:
λ = 2L / n
where λ is the wavelength, L is the length of the vibrating section of the string, and n is the number of nodes in the vibration.
Next, we can use the formula for the frequency of a wave on a string:
[tex]f = (1 / 2L) * (T / μ)^0.5[/tex]
where f is the frequency, T is the tension in the string, and μ is the linear density of the string.
Combining these two equations and solving for L, we get:
[tex]L = (μ / T) * (f^2 / n^2)[/tex]
Substituting the given values, we get:
[tex]L = (0.690 g/m / 160 N) * [(344 m/s / (2 * 39.1 cm))^2 / (1 / 2)^2][/tex]
Converting the units, we get:
[tex]L = (0.690 g/m / 160 N) * [(344 m/s / (2 * 0.391 m))^2 / (1 / 2)^2][/tex]
Calculating the value, we get:
L = 0.016 m
So, the length of the vibrating section of the violin string is approximately 16 cm.
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Calculate the time it takes a 200 W appliance to transfer 40,000 J of energy
Explanation:
P=energy used/time taken
200=40000/t
200t=40000
divide both sides by 200
t=200s
[tex] power = \frac{workdone}{time \: taken} [/tex]
[tex] p = \frac{w}{t} [/tex]
200 = 40,000 / t
200t = 40,000
200t / 200 = 40,000 / 200
t = 200s
a 15 pf capacitor is charged to 1 kv and then removed from the battery and connected in parallel to an uncharged 65 pf capacitor. what is the new charge on the second capacitor? answer in units of nc.
The new charge on the second capacitor when two capacitors are connected in parallel is calculated to be 611× 10⁻¹⁴ C.
The formula Q = C V = C E d describes the charge held in a capacitor.
where,
C is capacitance
V is the potential across the capacitor
E is the uniform electric field
d is the distance between the plates
The energy stored in a capacitor is given by,
U = 1/2 C V² = 1/2 Q²/C = 1/2 A ε₀ E² d
where,
C is the capacitance
V is the voltage
Q is the charge stored
A is the area of the plates
ε₀ is 8.85 × 10⁻¹² F/m is the permittivity free space
E is the electric field
d is the distance
C₁ is given as 15 × 10⁻¹² F
C₂ is given as 65 × 10⁻¹² F
V₁ is given as 5 × 10³ V
Initial charge on the first capacitor is,
Q' = C₁ V₁ = 15 × 10⁻¹² × 5 × 10³ = 75× 10⁻⁹ C
When two capacitors are connected together, the equivalent capacitance of the new system is,
C = C₁ + C₂ = 15 × 10⁻¹² + 65 × 10⁻¹² = 80 × 10⁻¹² F
Voltage for the new system is, V = Q'/C = (75× 10⁻⁹)/(80 × 10⁻¹²) = 9.4× 10⁻² V
Charge on the second capacitor is,
Q₂ = C₂ V = 65 × 10⁻¹² × 9.4× 10⁻² = 611× 10⁻¹⁴ C
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Four 2. 0-µC point are at the corners of a rectangle with sides of length 3. 0 cm and 4. 0 cm. What is the electric potential (relative to infinity) at the midpoint of the rectangle? (k = 1/4πε0 = 9. 0 × 109 N ∙ m2/C2)
The electric potential at the midpoint of the rectangle is 3440 V relative to infinity.
How close to infinity is electric potential?
Whenever a charge Q is infinitely far away from another charge, the electric potential is deemed to be 0. The resultant electric field is zero at P, the halfway between two identical charges.
To find the electric potential at the midpoint of the rectangle, we need to calculate the electric potential due to each of the four point charges, and then add them up. The electric potential at a point is given by the equation:
[tex]\mathrm{V = k \times q / r}[/tex]
where V is the electric potential, k is Coulomb's constant (1/4πε0), q is the charge, and r is the distance from the point charge to the point where we want to calculate the potential.
Let's assume that the rectangle lies in the x-y plane, with one corner at the origin. We can label the other corners as A, B, and C, where AB is parallel to the x-axis and BC is parallel to the y-axis.
The distance from the midpoint of AB to each of the four point charges is given by:
[tex]\mathrm{r_1 = r_3 = \sqrt{(1.5 cm)^2 + (2 cm)^2}= 2.5 cm}[/tex]
[tex]\mathrm{r_2 = r_4 = \sqrt{(1.5 cm)^2 + (1 cm)^2}= 1.8 cm}[/tex]
The electric potential due to each of the point charges at the midpoint of AB is given by:
[tex]\mathrm{V_1 = k \times q / r_1 = (9.0 \times 10^9 N \cdot m^2/C^2) \times (2.0 \times 10^{-6} C) / (2.5 \times 10^{-2} m) = 720 V}[/tex]
[tex]\mathrm{V_2 = k \times q / r_1 = (9.0 \times 10^9 N \cdot m^2/C^2) \times (2.0 \times 10^{-6} C) / (1.8 \times 10^{-2} m) = 100V}[/tex] = 1000 V
[tex]\mathrm{ V_3 =k \times q / r_3 = 720 V}[/tex]
[tex]\mathrm{ V_4 =k \times q / r_4 = 1000V}[/tex]
The total electric potential at the midpoint of AB is the sum of these four potentials:
[tex]\mathbf{V_{total} }[/tex] = V1 + V2 + V3 + V4
= 720 V + 1000 V + 720 V + 1000 V
= 3440 V
Therefore, the electric potential at the midpoint of the rectangle is 3440 V relative to infinity.
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what is the direction of the electric field at the position indicated by the dot in the figure? specify the direction as an angle above the horizontal line.
The direction of the electric field at the position indicated by the dot in the figure can be specified as an angle above the horizontal line. The angle is determined by the direction of the electric field vector at that point, which can be determined using the right-hand rule.
The direction of the electric field is determined by the sign of the charge, which is responsible for creating the field. Positive charges create an electric field that extends outward from them, while negative charges create an electric field that extends inward towards them. Additionally, the direction of the electric field is the same as the direction of the force it would exert on a positive test charge.
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You want to build a bird house and attach it to a branch in a 12 foot tree. You have the following materials: wood, glue, screws, saw, hammer, screw driver, nails, ruler and a pulley system connected to a tree. Your bird house needs to be a rectangle that is 30cm long and 15cm wide. List the simple machines you would use to make this. (at least 3)
Answer:
just build it lol
Explanation:
The birdhouse is made from seven pieces of wood cut from a single 1- x 12-inch pine board, 6-feet long. Measure, mark and cut a 5- x 7-inch piece of board for the bottom of the birdhouse. Measure, mark and cut two 5- x 5
and go from there
bumper cars a and b undergo a collision during which the momentum of the combined system is conserved. which equation(s) correctly states the principle of conservation of momentum?
According to the given equation(s) correctly states the principle of conservation of momentum.
A. P Ai + P Bi = P A f + P Bf
D. ΔPA + ΔPB=0
What exactly is momentum conservation?The total momentum of two or more entities working on each other in an isolated system must remain constant until an external force is applied, according to the law of conservation of momentum. Because of this, momentum cannot be created or destroyed.
Briefly defined, what is the law governing the conservation of momentum?The conservation of momentum, or total momentum of a system, is a general statement of physics that states that the quantity known as momentum, which characterizes motion, never changes inside an isolated collection of particles.
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Bumper cars A and B undergo a collision during which the momentum of the combined system is conserved. Which equation(s) correctly states the principle of conservation of momentum? Check all that apply.
A. P Ai + P Bi = P A f + P Bf
B. P Ai + P A f = P Bi + P Bf
C. ΔPA = ΔPB
D. ΔPA + ΔPB=0
what does angular resolution measure? group of answer choices the angular size of the smallest features that the telescope can see the brightness of an image the size of an image the number of electromagnetic waves captured by an image
The Angular Resolution measures the (a) the angular size of the smallest features that the telescope can see .
The Angular resolution is defined as a measure of the ability of an imaging device, such as a telescope or a camera, to distinguish fine details in an image.
It is expressed as an angle and represents the smallest separation between two objects that can still be distinguished as separate by the imaging device.
The Angular Resolution of a telescope is limited by the size of its aperture, the wavelength of the light it is observing, and the quality of its optics.
A Telescope with a larger aperture and high-quality optics will typically have a higher angular resolution, allowing it to see smaller and finer details.
The given question is incomplete , the complete question is
What does angular resolution measure ?
(a) the angular size of the smallest features that the telescope can see
(b) the brightness of an image
(c) the size of an image
(d) the number of electromagnetic waves captured by an image .
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(ii) two charged dust particles exert a force of 4.6 * 10-2 n on each other. what will be the force if they are moved so they are only one-eighth as far apart?
The force if they are moved so they are only one-eighth as far apart will be 2.688 N.
What is force?Objects' velocities can be changed by the concepts of thrust, drag, and torque.
Thrust causes an object to move faster, while torque causes an object to move slower.
Each part of an extended body typically exerts forces on its neighbouring sections; the internal mechanical stress in the body is the result of the distribution of these forces.
As the forces balance, the internal mechanical stresses have no effect on the body's acceleration.
The expression for the electric force is as follows,
F= kQ1Q2/r²
The new force between the dust particles after they moved.
F′ = kQ1Q2/(r/8)²
F′/F = {kQ1Q2/(r/8)²}/kQ1Q2/r²
F′/F = 1/(1/64)
F′ = 64F
Substitute 4.2×10⁻²N for F in the equation F′ =64F to find F1.
F′ =64(4.2×10⁻² N)
= 2.688 N
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you throw a ball straight up with an initial velocity of 15.0 m/s. it passes a tree branch on the way up at a height of 7.0 m. how much additional time elapses before the ball passes the tree branch on the way back down?
This individual launches a ball upward at a 15 meter per second beginning speed. We'll assume that the ball is held in the guy's mouth at beginning height zero meters.
What is the speed measurement unit?
Units of speed include nautical miles per hour (kn or kt), feet per minute (symbol fps or ft/s), kilometers per hour (symbol km/h), miles an hour (symbol km in or mph), and metres per moment (symbol μ s 1 or m/s), the SI-derived unit. Speed multiplied by the sound speed is known as the dimensionless Mach number;
What does speed have a shorthand for?
L T-1. The parameters of speed are time divided by distance. The most often used measure of speed in daily life is the kilometer per hour, or miles per hour in the United States and the UK. The Si derived unit of velocity is the meter per second.
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On a banked race track, the smallest circular path on which cars can move has a radius of 101 m, while the largest has a radius 159 m, as the drawing illustrates. The height of the outer wall is 18 m.
(a) Find the smallest speed at which cars can move on this track without relying on friction.
(b) Find the largest speed at which cars can move on this track without relying on friction.
The smallest speed at which cars can move on this track without relying on friction is 31.46 m/s.
The largest speed at which cars can move on this track without relying on friction is 39.10 m/s.
What is centripetal acceleration?An attribute of an object moving in a circular route is centripetal acceleration. Any object moving in a circle with an acceleration vector pointing in the direction of the circle's center is said to be experiencing centripetal acceleration.
a) The smallest speed at which cars can move on this track without relying on friction is = √(gr₁)
= √(9.8 × 101) m/s
= 31.46 m/s.
b) The largest speed at which cars can move on this track without relying on friction is = √(gr₂)
= √(9.8 × 159) m/s
= 39.10 m/s.
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two tuning forks are sounded at the same time. which tuning forks will give rise to a beat frequency of 20 hz 20 hz when sounded together with a 240 hz 240 hz tuning fork?
The tuning forks will give rise to a beat frequency are 220 Hz and 260 Hz.
Tuning forks are available in a wide range of frequencies (64 Hz to 4096 Hz); 128 Hz is a commonly used frequency for screening.
Beat frequency formed by the tuning fork is given by: [tex]f_{beat} = f_1 \pm f_2[/tex].
Here, the beat frequency, [tex]f_{beat} = 20 Hz[/tex].
The frequency of a tuning fork, [tex]f_2 = 270\ Hz[/tex].
If [tex]f_{beat} = f_1 + f_2[/tex],
[tex]f_1 = 20-240[/tex]
[tex]f_1 = 220\ Hz[/tex]
If [tex]f_{beat} = f_1 - f_2[/tex],
[tex]f_1 = 20+240[/tex]
[tex]f_1 = 260\ Hz[/tex]
So, the tuning forks will give rise to a beat frequency are 220 Hz and 260 Hz. Hence, this is the required solution.
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--The complete question is, Two tuning forks are sounded at the same time. which tuning forks will give rise to a beat frequency of 20 hz when sounded together with a 240 hz tuning fork?--
derive an expression for the force experienced by a conductor carrying current when placed in a uniform magnetic field.
compute the propulsive efficiency and specific thrust for a turbojet engine with an exhaust velocity of 450 m/s, an air mass flow rate of 250 kg/s, an exit area of 2 m2, and an exit pressure of 35,000 pa if the aircraft is flying at 200 m/s at an ambient pressure of 30,000 pa. the fuel fraction is 2.0%.
The propulsive efficiency of the turbojet engine is approximately 12,500 N/kg/s and the specific thrust is approximately 250 N/kg/s.
The propulsive efficiency of a turbojet engine is defined as the ratio of the net thrust produced by the engine to the rate of energy supplied to the engine. The specific thrust is defined as the net thrust per unit mass flow rate of the engine.
To calculate these parameters, we need to determine the net thrust produced by the engine. This can be calculated using the equation:
Thrust = (V_e - V_0) × m_air + (p_e - p_0) × A_e
where V_e is the exhaust velocity, m_air is the air mass flow rate, V_0 is the velocity of the aircraft, p_e is the exit pressure, p_0 is the ambient pressure, and A_e is the exit area.
Substituting the given values, we get:
Thrust = (450 m/s - 200 m/s) × 250 kg/s + (35,000 Pa - 30,000 Pa) × 2 m^2 = (250 kg/s)(250 m/s) = 62500 N
The propulsive efficiency is given by:
η = net thrust / (fuel consumption rate) = 62500 N / (250 kg/s × 2.0%) = 62500 N / (250 kg/s × 0.02) = 62500 N / 5 kg/s = 12500 N/kg/s
The specific thrust is given by:
T_sp = net thrust / air mass flow rate = 62500 N / 250 kg/s = 250 N/kg/s
Therefore, the propulsive efficiency of the turbojet engine is approximately 12,500 N/kg/s and the specific thrust is approximately 250 N/kg/s.
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which telescope has better resolution? group of answer choices the very large array which observes radio waves and has a diffraction limit of 1.5 arcseconds. the hubble space telescope which observes visible light and has a diffraction limit of 0.05 arcseconds.
The diffraction limit of the visible light observatory Hubble Space Telescope is 0.05 arcseconds.
What restricts a telescope's natural resolution?telescopic seeing. The lowest angle between close objects that can be seen to be distinctly separate is the telescope's angular resolving power (or resolution). The fact that light is a wave limits resolution.
Which telescope from the list below would have the worst angular resolution?Because radio waves have a significantly longer wavelength than optical waves, radio telescopes have a lower angular resolution than optical telescopes. In terms of design, all radio telescopes are reflectors.
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A baby carriage is sitting at the top of a hill that is 21 m high. The carriage with the baby has a mass of the carriage has__ energy. Calculate it.
The required energy the carriage has, when the displacement of the carriage and mass of the carriage with the baby are given is calculated to be 1029 J.
The energy in the above case is nothing but the work done by the carriage.
The work is defined as,
W = F d
where,
F is force
d is displacement
Entering the values in the above equation, we have,
W = F d = m × a × d = 5 × 9.8 × 21 = 1029 J
Thus, the required energy the carriage has is calculated to be 1029 J.
The given question is inappropriate. The question is 'a baby carriage is sitting at the top of a hill that is 21 m high. The carriage with the baby has a mass of 5kg whats the energy the carriage has?'
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object 1 has a momentum of 5 kg*m/s before colliding with object 2 which has a momentum of -3 kg*m/s before the collision. after they collide, object 1 immediately stops. what is the momentum of object 2 after the collision?
The momentum of object 2 after the collision is 2 kg × m/s.
Momentum = mass × velocity
Before the collision, object 1 has a momentum of 5 kg * m/s, and object 2 has a momentum of -3 kg * m/s. The total momentum of the two objects before the collision can be calculated as the sum of the individual momenta:
Total momentum before collision = 5 kg × m/s + (-3 kg × m/s) = 2 kg × m/s
According to the law of conservation of momentum, the total momentum of a system remains constant unless acted upon by an external force. In this case, the two objects are colliding with each other and no external forces are present, so the total momentum of the system must remain constant.
After the collision, object 1 stops, so its velocity becomes 0, and its momentum becomes 0 kg × m/s.
Momentum of object 2 after collision = Total momentum of the system - Momentum of object 1
= 2 kg × m/s - 0 kg × m/s = 2 kg × m/s
So, the momentum of object 2 after the collision is 2 kg × m/s.
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A 1 m spring requires 10 J to stretch the spring to 1. 1 m. How much work would it take to stretch the spring from 1 m to 1. 2 m
It would take 8 J of work to stretch the spring from 1 m to 1.2 m.
The work required to stretch a spring is given by the formula:
[tex]W = (1/2)kx^2,[/tex] where W is the work done, k is the spring constant, and x is the distance the spring is stretched or compressed.
Given that the spring requires 10 J of work to stretch from 1 m to 1.1 m, we can calculate the spring constant as follows:
[tex]10 J = (1/2)k(0.1 m)^2[/tex]
[tex]k = 200 J/m[/tex]
Using this spring constant, we can calculate the work required to stretch the spring from 1 m to 1.2 m:
[tex]W = (1/2)(200 J/m)(0.2 m)^2[/tex]
[tex]W = 8 J[/tex]
Therefore, it would take 8 J of work to stretch the spring from 1 m to 1.2 m.
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determine how much impulse is needed bowling barry to stop a 10- kg bowling ball moving at 7.0 m/s .
The impulse required to stop the 10-kg bowling ball moving at 7.0 m/s is -70 kg m/s.
The impulse required to stop a moving object can be calculated using the principle of momentum conservation.
The formula for impulse can be given as:
I = Δp = mΔv
where I is the impulse, Δp is the change in momentum, m is the mass of the object, and Δv is the change in velocity.
In this case, the initial velocity of the 10-kg bowling ball is 7.0 m/s and it needs to be brought to a stop, so its final velocity is 0 m/s.
Therefore, the change in velocity can be given as:
Δv = vf - vi = 0 - 7.0 m/s = -7.0 m/s
Substituting the values in the formula for impulse, we get:
I = Δp = mΔv = 10 kg × -7.0 m/s = -70 kg m/s
So, the impulse required to stop the 10-kg bowling ball moving at 7.0 m/s is -70 kg m/s. The negative sign indicates that the impulse is acting in the opposite direction to the velocity of the ball.
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primary vehicle controls include: group of answer choices transmission controls accelerator pedal clutch pedal all of the above
The aforementioned accelerator pedal, clutch pedal, and other primary controls are all included in a car.
What is an accelerator's function?In conclusion, accelerators play a significant part in fostering innovation through a plan designed to guide a cohort few participants with their concepts through an intense program to develop, produce, and commercialize an alternative investment product that can grow and function in the real world.
What exactly is a catalytic energy?A SHOC's innovative energy drink ACCELERATOR was created to fulfill the needs of your modern, energetic, and healthy lifestyle.
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Margaret drops a coin down a funnel shaped object. The coin rolls around the outer edge in a circular motion. As it moves closer to the bottom, it completely rolls around the edge. Margaret drops another coin into the same funnel shaped object. Which type of motion can Margaret predict this coin will have
a Margaret drops a coin down a funnel shaped object.
a A straight line
b A circling motion
c A front to back motion
d A zigzagging motion
The required type of motion can Margaret predicts this coin will have is a circling motion. Option B is correct.
What is motion?motion is defined as an object's change of position over time is called motion.
Here,
As Margaret drops a coin down a funnel-shaped object. The coin rolls around the outer edge in a circular motion. As it moves closer to the bottom, it completely rolls around the edge.
Margaret can predict that the second coin will have a circling motion as it moves down the funnel-shaped object. The shape of the funnel will cause the coin to roll around the edge in a circular motion.
Thus, the required type of motion can Margaret predicts this coin will have is a circling motion. Option B is correct.
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A spaceship hovering over the surface of Venus drops an object from a height of 24 m. How much longer does it take to reach the surface than if dropped from the same height on Earth? Neglect air resistance in both cases. [The acceleration due to gravity on Venus is 90.7% of that on Earth,
gVenus = (0.907)g.]
The time taken is 2.3s for a spaceship hovering over the surface of Venus to drop an object from a height of 24m, and 2.21s for the same spaceship hovering over the surface of Earth to drop an object from the same height.
What is the time taken?To solve this problem, we will use the motion equation to calculate the time of flight of an object on the surface of Venus and the Earth. The height is related by the following equation of motion:
h = v₀t + gt²/2
Because the object's initial velocity before dropping is zero, we can simplify the equation to:
h = gt²/2
We know the height h of the spaceship hovering, and Venus's gravity is g = 9.07m/s². Substituting the following values into the equation:
24m = (9.07 m/s²t²)/2
To calculate the time it takes an object dropped by a spaceship hovering from a height of 24m to reach the surface of Venus, we must remove t from the equation above, yielding:
t = [tex]\sqrt{2(24m)/9.07m/s^{2} }[/tex]
= [tex]\sqrt{48m/9.07m/s^{2} }[/tex]
= 2.3s
Similarly, to calculate the time it takes an object dropped from a height of 24m to reach the Earth's surface, and the gravity of the Earth is g = 9.81m/s² .
t = [tex]\sqrt{2(24m)/9.81m/s^{2} }[/tex]
= [tex]\sqrt{48/9.81m/s^{2} }[/tex]
= 2.21s
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A 0. 5 kg block of playdough moving at 1. 5 m/s is smashed into a 0. 25 kg blob of playdough. Calculate the speed
of the two stuck-together blobs immediately after colliding.
The final speed of both play doughs which stick together after the collision is 0.5 m/s.
The mass of the first play dough = 0.5 kg
The mass of the second play dough = 0.25 kg
The initial speed of the first play dough = 1.5 m/s
The initial speed of the second play dough = 2 m/s
The final speed of both play doughs can be found using the formula,
m₁u₁ + m₂u₂ = (m₁ + m₂) v
where,
m₁,m₂ is the mass of the first and second play dough respectively
u₁,u₂ is the initial speed of the first and second play dough respectively
v is the final speed of both play dough
Let us enter the known values in the above equation,
0.5 × 1.5 + 0.25 × 2 = (0.5 + 0.25) v
0.75 × 0.5 = 0.75v
0.375 = 0.75v
v = 0.375 / 0.75 = 0.5 m/s
The given question is incomplete. The complete question is ' The speed of the bob of the pay dough is 2 m/s.'
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You are running with a carry-on suitcase through the airport. Where should the center-of-mass of the suitcase ideally be located
The center of mass is usually near the middle of the suitcase and about halfway up its height and at a height that allows you to maintain good balance and control while running.
For a carry-on suitcase,. Keeping the center of mass low and close to your body can help reduce the amount of effort required to carry the suitcase, as well as improve stability and control while running.
When running with a suitcase, it's important to keep your upper body as upright and relaxed as possible, while allowing your legs and arms to move freely. This will help you maintain balance and reduce the strain on your muscles and joints. Additionally, it's helpful to grip the handle of the suitcase firmly, but not too tightly, so that you have control over its movement.
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can a vector have a component equal to zero and still have nonzero magnitude? match the words in the left column to the appropriate blanks in the sentences on the right.
The statements stands true. A vector have a component which is equal to zero and still have nonzero magnitude.
In a 2-D plane a vector can be resolved into the rectangular components. These are rectangular components to each other. These are available at right angles to each other. One component is directed along x-axis. It is the termed as horizontal component. The other one is directed along y-axis. Is termed as vertical component.
Sometimes, the vector is directed entirely either along x-axis or y-axis. When the vector is along x-axis or parallel to x-axis, then the complete magnitude will be directed along horizontal component. The vertical component will be zero. For a vector which is along y-axis, the horizontal component will be zero. The entire magnitude will be along y-axis.
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a 0.105-kg hockey puck moving at 29.0 m/s is caught and held by a 61.0 kg goalie at rest. with what speed does the goalie slide on the ice?
The goalie slides on the ice with the speed of 0.0498 m/s. The result is obtained by using the Law of Conservation of Momentum.
What is the Law of Conservation of Momentum?The Law of Conservation of Momentum states that the total momentum in a closed system before and after the collision is constant.
It can be expressed as
m₁v₁ + m₂v₂ + ... = m₁v₁' + m₂v₂' + ...
Where
m₁ and m₂ = mass of objectsv₁ and v₂ = initial speed of objectsv₁' and v₂' = final speed of objectsA 0.105-kg hockey puck moving at 29.0 m/s is caught and held by a 61.0 kg goalie at rest. Find the speed does the goalie slide on the ice!
We have
m₁ = 0.105 kgv₁ = 29.0 m/sm₂ = 61.0 kgv₂ = 0 (at rest)They are collided inelastically. The hockey puck eventually moves with the goalie at the same speed, v.
So,
m₁v₁ + m₂v₂ = (m₁ + m₂)v'
0.105(29) + 0 = (0.105 + 61.0)v'
3.045 = (61.105)v'
v' = 0.0498 m/s
Hence, the speed of the goalie sliding after holding the hockey puck is 0.0498 m/s.
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erin walks 50.0 meters west in 60.0 seconds. she then walks 25.0 meters east in 40.0 seconds. what is her average velocity for the trip?
The average velocity for this trip is calculated by taking the total displacement (the difference between the final and initial positions) and dividing it by the total time.
In this case, the total displacement is 25 meters (50 meters west minus 25 meters east) and the total time is 100 seconds (60 seconds plus 40 seconds). Therefore, the average velocity for this trip is 0.25 meters per second.
Average velocity is a measure of the rate of change in an object's displacement over a period of time. It is calculated by dividing the change in an object's displacement by the time it took for the change to occur. Average velocity can be used to measure the speed of an object in a particular direction.
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Answer: .250m/s
Explanation:
the distance from the sun is 93,000,000 miles and is called 1 au. what is the distance in miles to a star that is
The distance from star A to star B is about 3.999 billion miles.
AU stands for "astronomical unit". It is a unit of measurement used in astronomy and represents the average distance from the Earth to the Sun, which is about 93 million miles (or 149.6 million kilometers).
If the average distance from star A to star B is 43 AU, then we can find the distance in miles by multiplying 43 by the distance of 1 AU from the sun, which is about 93 million miles:
Distance from star A to star B = 43 x 93,000,000 miles
Distance from star A to star B = 3,999,000,000 miles
Therefore, the distance from star A to star B is about 3.999 billion miles (or 3.999 x 10^9 miles).
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--The complete question is, The distance from Earth to the sun is defined as 1 astronomical unit, or AU. It is about 93 million miles, The average distance from star A to star B is 43AUs.
Find this distance in miles.--
Can someone explain this to me in detail, please?
By comparing the acceleration due to gravity on each planet, the highest speed would be on earth.
What is the acceleration due to gravity?The acceleration due to gravity is the acceleration experienced by an object as it falls freely under the influence of Earth's gravity. The acceleration due to gravity is commonly denoted by the symbol "g" and has a value of approximately 9.8 meters per second squared (m/s^2) near the surface of the Earth.
This value can vary slightly depending on factors such as altitude, latitude, and the local geological structure.
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how much tension must a cable withstand if it is used to accelerate a 1300- kg car vertically upward at 0.80 m/s2 ?
Tension that a cable withstand if it is used to accelerate a 1300- kg car vertically upward is 13780 N.
Tension is a force along the length of a medium, especially a force carried by a flexible medium, such as a rope or cable. Tension can be defined as an action-reaction pair of forces acting at each end of the said elements.
Given that,
Mass of the car, m = 1300 kg
Acceleration of the car vertically upwards,
As the car is moving vertically upwards. So,
T - mg = ma
T = m(a+g)
[tex]T = 1300 \times (0.8+9.8)[/tex]
T = 13780 N
So, the tension in the cable is 13780 N. Hence, this is the required solution.
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perform a kline-mcclintock uncertainty analysis on the pump power calculation. what is the uncertainty of the pump power measurement in watt?
The Kline-McClintock uncertainty analysis is used to estimate the uncertainty associated with measurements of power output from a pump. The uncertainty is usually determined by analyzing the errors associated with the measurements taken and the accuracy of the equipment used.
The uncertainty of the pump power measurement in watt will depend on the accuracy of the measurements, the precision of the instruments used, and the degree of accuracy of the calculations. Generally, the uncertainty of the pump power measurement in watt can be estimated as the combined standard deviation of all measurement errors.
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