A package states that there are 60 calories in 12 crackers

Answer:

90

Step-by-step explanation:

81/x=90/100

8100=90x

90=x

The total number of problems given in exam was 90.

Percentage, which is a relative figure used to denote hundredths of any quantity. One percent (symbolised as 1%) is equal to 100 parts; hence, 100 percent denotes the complete amount, and 200 percent designates double the amount specified.

Divide one number by the other, then multiply the result by 100 to get the percentage of the two numbers.

A student correctly answered 81 problems.

Grade received by student is 90%

Let the total number of question given in the test be 'x'.

Thus,

90% of x = 81

(90/100)x = 81

x = (81×100)/90

x = 90

Therefore, the total number of question allotted to the student is 90.

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Step-by-step explanation:

.....because the coefficient of x is 2, a positive number.

Answer:

The answer in a subtraction problem is called the difference.

Step-by-step explanation:

Hi there!

The answer to a subtraction problem is called rest or difference while the top thats being subtracted is called the minuend and the middle one is called the subtrahend.

Answer:

≈ 70.87 (rounded to the nearest hundredth)

Step-by-step explanation:

-When you do 4,819 ÷ 68, you’ll get:

70.867647058....

-So, just round it to the nearest hundredth:

70.87

Answer:

c) 75

Step-by-step explanation:

180-155 = 25

80+25+x=180

x = 75

Step-by-step explanation:

By Exterior Angle Theorem,

x = 155° - 80° = 75° (C).

Answer:

The answer is i have no clue

Given:

Inter quartile range(IQR) of a distribution = 7

25th percentile = 16

To find:

The upper quartile.

Solution:

We have,

IQR = 7

25th percentile = lower quartile = 16

We know that,

IQR = Upper quartile - Lower quartile

Let the upper quartile be [tex]Q_3[/tex].

Using the above formula, we get

[tex]7=Q_3-16[/tex]

Adding 16 on both sides, we get

[tex]7+16=Q_3-16+16[/tex]

[tex]23=Q_3[/tex]

Therefore, the upper quartile of the distribution is 23.

Answer:

three angle one slide

Step-by-step explanation:

Answer:

x>15/7

Step-by-step explanation:

Answer:

1. The journey will use 15.52 liters of petrol.

2. The approximate cost of petrol to hotel will be 2155.73 pence

3. The whole journey will take 3.36 hours

Step-by-step explanation:

Given that:

Distance of hotel from house = 163 miles

Distance covered by per liter = 10.5 miles

1/ The Hotel is 163 miles from your house.your car travels 10.5 miles for every litre of petrol. Work out approximately how many litres of petrol the journey will use.

Petrol used for total distance = [tex]\frac{Total\ distance}{Distance\ per\ liter}[/tex]

Petrol used for total distance = [tex]\frac{163}{10.5}=15.52\ liters[/tex]

The journey will use 15.52 liters of petrol.

2/The price of petrol is 138.9 pence per litre Work out the approximate cost for the petrol to the hotel .

Cost of per liter petrol = 138.9 pence

Cost for petrol to hotel = Petrol used for journey * Price per liter

Cost of petrol = 138.9 * 15.52 = 2155.73 pence

The approximate cost of petrol to hotel will be 2155.73 pence

3/ you expect to travel 50 miles in each hour of a jurney how long the whole journey should take.

Distance covered per hour = 50 miles

Time taken in whole journey = [tex]\frac{total\ distance}{distance\ per\ hour}[/tex]

Time taken in whole journey = [tex]\frac{168}{50}[/tex]

Time taken in whole journey = 3.36 hours

The whole journey will take 3.36 hours

Hence,

1. The journey will use 15.52 liters of petrol.

2. The approximate cost of petrol to hotel will be 2155.73 pence

3. The whole journey will take 3.36 hours

Answer:

The value of [tex]x[/tex] is approximately -1.531.

Step-by-step explanation:

Let [tex]3.3^{2\cdot x + 1}-103^{x+1} = 0[/tex], we proceed to solve this expression by algebraic means:

1) [tex]3.3^{2\cdot x + 1}-103^{x+1} = 0[/tex]  Given

2) [tex]3.3^{2\cdot x}\cdot 3.3 -103^{x}\cdot 103 = 0[/tex] [tex]a^{b}\cdot a^{c} = a^{b+c}[/tex]

3) [tex](3.3^{x})^{2}\cdot 3.3 -\left[\left( \sqrt{103} \right)^{2}\right]^{x}\cdot 103 = 0[/tex] [tex](a^{b})^{c} = a^{b\cdot c}[/tex]

4) [tex](3.3^{x})^{2}\cdot 3.3 - \left[\left(\sqrt{103}\right)^{x}\right]^{2}\cdot 103 = 0[/tex] [tex](a^{b})^{c} = a^{b\cdot c}[/tex]/Commutative property

5) [tex]\left[\left(\frac{3.3}{\sqrt{103}}\right)^{x}\right] ^{2}-\frac{103}{3.3} = 0[/tex] Existence of multiplicative inverse/Definition of division/Modulative property/[tex]a^{b}\cdot a^{c} = a^{b+c}[/tex]

6) [tex]\left(\frac{3.3}{\sqrt{103}} \right)^{2\cdot x}=\frac{103}{3.3}[/tex] Existence of additive inverse/Modulative property/[tex](a^{b})^{c} = a^{b\cdot c}[/tex]

7) [tex]\log \left(\frac{3.3}{\sqrt{103}} \right)^{2\cdot x}=\log \frac{103}{3.3}[/tex] Definition of logarithm.

8) [tex]2\cdot x\cdot \log \left(\frac{3.3}{\sqrt{103}} \right)= \log \frac{103}{3.3}[/tex]     [tex]\log_{b} a^{c} = c\cdot \log_{b} a[/tex]

9) [tex]2\cdot x \cdot [\log 3.3-\log \sqrt{103}] = \log 103 - \log 3.3[/tex]      [tex]\log_{b} \frac{a}{d}[/tex]

10) [tex]x\cdot (2\cdot \log 3.3-\log 103) = \log 103 - \log 3.3[/tex]     [tex]\log_{b} a^{c} = c\cdot \log_{b} a[/tex]/Associative property

11) [tex]x = \frac{\log 103-\log 3.3}{2\cdot \log 3.3-\log 103}[/tex]   Existence of multiplicative inverse/Definition of division/Modulative property

12) [tex]x \approx -1.531[/tex]  Result

The value of [tex]x[/tex] is approximately -1.531.

Answer:

slope = 3

Step-by-step explanation:

Choose any two points: For example, (2, 4) and (4, 10)

Find the difference in y. This is called the "rise."

rise = 10 - 4 = 6

In the same order, find the difference in x. this is called the "run."

run = 4 - 2 = 2

slope = rise/run

slope = 6/2

slope = 3

Answer:

10y²+24.5

Step-by-step explanation:

distribute.

10y²+24.5

Hope this helps plz hit the crown :D

The equivalent expression for the given expression is 10y²+24.5.

The given expression is 10(y² + 2.45).

Equivalent expressions are expressions that work the same even though they look different. If two algebraic expressions are equivalent, then the two expressions have the same value when we plug in the same value for the variable.

The equivalent expression is

10(y² + 2.45)

=10y²+24.5

Therefore, the equivalent expression for the given expression is 10y²+24.5.

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Answer:

its the second one

Step-by-step explanation:

u just mulitply the terms together and add the exponents

Answer:

the measure of angle 12 is 68degrees

Answer:

[tex]XY = 4.9[/tex]

Step-by-step explanation:

[tex]\angle Y = 45^\circ[/tex]

[tex]\angle Z = 60^\circ[/tex]

[tex]XZ = 4[/tex]

Required

Determine the length of XY?

This question is supported with the attachment.

To solve for the length of XY, we make use of the sine law which states:

[tex]\frac{sin\ A}{a} = \frac{sin\ B}{b} = \frac{sin\ C}{c}[/tex]

In this case:

[tex]\frac{sin\ \angle Y}{XZ} = \frac{sin\ \angle Z}{XY} = \frac{sin\ X}{YZ}[/tex]

Substitute in, the following values:

[tex]\angle Y = 45^\circ[/tex]

[tex]\angle Z = 60^\circ[/tex]

[tex]XZ = 4[/tex]

The expression becomes:

[tex]\frac{sin\ 45}{4} = \frac{sin\ 60}{XY}[/tex]

Cross multiply

[tex]XY * \sin\ 45 = 4 * \sin\ 60[/tex]

Make XY the subject

[tex]\frac{XY * \sin\ 45}{\sin\ 45} = \frac{4 * \sin\ 60}{\sin\ 45}[/tex]

[tex]XY = \frac{4 * \sin\ 60}{\sin\ 45}[/tex]

[tex]XY = \frac{4 * 0.8660}{0.7071}[/tex]

[tex]XY = \frac{3.4640}{0.7071}[/tex]

[tex]XY = 4.89888276057[/tex]

[tex]XY = 4.9[/tex] --- approximated

Answer:

XY = 4.9

Step-by-step explanation:

Answer: The percentage of 0.20 is 20%.

Step-by-step explanation: 0.20 represents the 20% of 100%.

Answer: 20%

Step-by-step explanation: You just move the dot 2 times to the right and it will be 20%

60 x 5 + 45 = 345 Seconds

Answer:

x=43,y=-44

Step-by-step explanation:

hey i hope it helps you

2x+y=42(7)

8x+7y=36(1)

14x+7y=294

8x+7y=36

6x=258

divide both sides by 6

x=43

to get y

2x+y=42

equate x=43

8(43)+7y=36

344+7y=36

344-36=7y

308=7y

divide both sides by 7

y=-44

Answer:

B, C, E

Step-by-step explanation:

On edge 2021

Answer:

4:120

Step-by-step explanation:

for 120 student they would be 4 teacher needed per 30 student

4:120

Ruiz would get back 55 dollars 0 cents

Answer:

166.67 pounds

Step-by-step explanation:

Set up a proportion where x is Tom's weight in pounds:

[tex]\frac{75}{x}[/tex] = [tex]\frac{0.45}{1}[/tex]

Cross multiply and solve for x:

75 = 0.45x

166.67 = x

So, Tom weighs approximately 166.67 pounds

WORD PROBLEM:

slopev=

[tex]diffrence \: in \: y \: coordinate \\ diffrence \: in \: x \: coordinate[/tex]

so

Y=11_5 =6

X = -7_(-3) = -4.

slope = (-4,6)

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