A merry-go-round at a playground is a circular platform that is mounted parallel to the ground and can rotate about an axis that is perpendicular to the platform at its center. The angular speed of the merry-go-round is constant, and a child at a distance of 1.4 m from the axis has a tangential speed of 2.2 m/s. What is the tangential speed of another child, who is located at a distance of 2.1 m from the axis?
(a) 1.5 m/s
(b) 3.3 m/s
(c) 2.2 m/s
(d) 5.0 m/s
(e) 0.98 m/s

Answers

Answer 1

Answer:

[tex]V_2=3.3m/s[/tex]

Explanation:

From the question we are told that:

Distance [tex]d_1=1.4m[/tex]

Tangential speed [tex]V=2.2m/s[/tex]

Distance 2 [tex]d_2=2.1m[/tex]

Generally the equation for Angular velocity is mathematically given by

 [tex]w=\frac{v}{r}[/tex]

Therefore

 [tex]\frac{v_1}{r_1}=\frac{v_2}{r_2}[/tex]

 [tex]V_2=\frac{2.2*2.1}{1.4}[/tex]

 [tex]V_2=3.3m/s[/tex]


Related Questions

A man pulls his dog (m=20kg) on a sled with a force of 100N at a 60° angle from the horizontal. What is the horizontal component of the force?
A) 100N
B) 196N
C) 50N
D) 86N

Answers

Answer:

Option C. 50 N

Explanation:

From the question given above, the following data were obtained:

Force (F) applied = 100 N

Angle (θ) = 60°

Horizontal component (Hₓ) =?

The horizontal component of the force can be obtained as follow:

Hₓ = F × Cos θ

Hₓ = 100 × Cos 60

Hₓ = 100 × 0.5

Hₓ = 50 N

Therefore, the horizontal component of the force acting on the dog is 50 N

If a rock displaces 7 ml of water, what is the volume of the rock?

Answers

Answer:

if i am not mistaken the volume is 7, because it only took that much space

Use a scientific calculator to perform the operation below.
5.92 x 107 + 2.11 x 106
A. 6.13 x 107
B. 2.81 x 101
C. 1.25 x 1014
D. 5.71 x 107
SUBMIT

Answers

Answer:

A. 6.13 x 107

Explanation:

Given the expression

5.92 x 10^7 + 2.11 x 10^6

First, we need to convert to the whole number

5.92 x 10^7 = 59200000

2.11 x 10^6 = 2110000

Add both values

59200000 + 2110000

= 61,310,000

Express in standard form

= 6.13 * 10^7

This gives the required result

1. Given an object that follows this time-dependent velocity function: ~v(t) = 2 m/s 2 tˆi − 3 m/s 3 t 2ˆj, and assuming the object begins at the origin at t=0s, where will the object be at t=2.0s?

2. Suppose an object of mass 2.0kg begins at rest and is acted upon by a force F(t) = 5.0N e^−0.1t . What will the object’s speed be after ten seconds?

Answers

Answer:

Explanation:

V=ds/dt

Where s =distance traveled

Given

V= 2ti - 3t²j

ds/dt=2ti - 3t²j

ds=(2ti - 3t²j)dt

Integrating

S= 2t²i/2 - 3t³j/3 + C

S=t²i - t³j + C

Since the object starts from Rest when t=0 and s(distance)=0

0=0²i - 0³j + C

C=0

Therefore

S=t²i - t³j

At t=2sec

S=(2)²i - (2)³j

S=4i - 8j

Magnitude of S(distance) = √4²+(-8)²

S= 4√5 meters

S=8.94meters.

2.mass =2kg

F(t)=5e^-0.1t

From Newton 2nd Law

F(t) = mdv/dt

5e^-0.1t= 2dv/dt

2dv = (5e^-0.1t)dt

Integrating

2V(t) = 5e^-0.1t/(-0.1) + C

2v(t) = - 50e^-0.1t + C

Since it started from rest at t=0. That is v(0)=0

2(0) = -50e^-0.1(0) + C

0 = -50 + C

C= 50

v(t) = -50e^-0.1t + 50

At t=10sec

v(10) = -50e^-0.1(10) + 50

V= -18.39 + 50

V= 31.61ms-¹.

While using your calc to evaluate -50e^-0.1(10)

Don't forget the -(minus) sign at the top of the exponential.

If you neglect it... You'll have a different answer.

Hope this helps.

Have a great day!!!

A 2.2 kg, 20-cm-diameter turntable rotates at 80 rpm on frictionless bearings. Two 600 g blocks fall from above, hit the turntable simultaneously at opposite ends of a diagonal, and stick. What is the turntable's angular velocity, in rpm, just after this event?

Answers

Answer:

[tex]w_2=38.3rpm[/tex]

Explanation:

From the question we are told that:

Mass of turntable [tex]M=2.2kg[/tex]

Diameter of turntable [tex]d=20cm=>0.2m[/tex]

Angular Velocity [tex]\omega =80rpm[/tex]

Mass of Blocks [tex]M_b=600g=>0.6kg[/tex]

Generally the equation for inertia is mathematically given by

Initial scenario at \omega=80rpm

 [tex]I_1=\frac{1}{2}mR^2[/tex]

 [tex]I_1=\frac{1}{2}*2.2*0.1^2[/tex]

 [tex]I_1=0.11kgm^2[/tex]

Final scenario

 [tex]I_2=I_1+2mR^2[/tex]

 [tex]I_2=0.011+(2*0.6*0.12)[/tex]

 [tex]I_2=0.023[/tex]

Generally the equation for The relationship between Angular velocity and inertia is mathematically given by

 [tex]I_1w_1=I_2w_2[/tex]

 [tex]w_2=\frac{I_1 \omega}{I_2}[/tex]

 [tex]w_2=\frac{0.011*80}{0.023}[/tex]

 [tex]w_2=38.3rpm[/tex]

calculate the work function that requires a 455 nm photon to eject an electron of a value 0.73 eV

Answers

Answer:

W = 2 eV

Explanation:

Given that,

The wavelength of a photon = 455 nm

The kinetic energy of a photon, K = 0.73 eV

We need to find the work function of the electron. It can be solved using Einstein's equation such that,

[tex]W=E-K[/tex]

E is the energy of the photon

So,

[tex]W=\dfrac{hc}{\lambda}-K\\\\W=\dfrac{6.63\times 10^{-34}\times 3\times 10^8}{455\times 10^{-9}\times 1.6\times 10^{-19}}-0.73\\\\W= 2.73\ eV-0.73\ eV\\\\W=2\ eV[/tex]

So, the work function of the metal is 2 eV.

Planets closer to a star will have what type of average temperature

Answers

Answer:

Mercury - 800°F (430°C) during the day, -290°F (-180°C) at night. Venus - 880°F (471°C) Earth - 61°F (16°C) Mars - minus 20°F (-28°C)30-Jan-2018

A team of people who traveled to the North Pole by dogsled lived on butter because they needed to consume 6 000 dietitian's Calories each day. Because the ice there is lumpy and irregular, they had to help the dogs by pushing and lifting the load. Assume they had a 16-hour working day and that each person could lift a 500-N load. How many times would a person have to lift this weight 1.00 m upwards in a constant gravitational field, where (g = 9.80m/s2) where to do the work equivalent to 6 000 Calories?

Answers

Answer:

The right solution is "50200 days".

Explanation:

Given:

Calories intake,

= 6000 kcal,

or,

= [tex]2.52\times 10^7 \ J[/tex]

Force,

= 500 N

As we know,

⇒ [tex]Work \ done = Force\times distance[/tex]

Or,

⇒ [tex]distance = \frac{Work \ done}{Force}[/tex]

By putting the values, we get

                  [tex]=\frac{2.52\times 10^7}{500}[/tex]

                  [tex]=0.502\times 10^5[/tex]

                  [tex]=50200 \ m[/tex]

hence,

The number of days will be:

= [tex]\frac{50200}{1}[/tex]

= [tex]50200 \ days[/tex]

if a cyclist is travelling a road due east at 12km/h and a wind is blowing from south-west at 5km/h. find the velocity of the wind relative to the cyclist.​

Answers

Answer:

The velocity of wind with respect to cyclist is [tex]-15.5 \widehat{i} - 3.5 \widehat{j}[/tex].

Explanation:

speed of cyclist = 12 km/h east

speed of wind = 5 km/h south west

Write the speeds in the vector form

[tex]\overrightarrow{vc} = 12 \widehat{i}\\\\overrightarrow{vw} = - 5 (cos 45 \widehat{i} + sin 45 \widehat{j})\\\\\overrightarrow{vw} =-3.5 \widehat{i} - 3.5 \widehat{j}[/tex]

The velocity of wind with respect to cyclist is

[tex]\overrightarrow{vw} =-3.5 \widehat{i} - 3.5 \widehat{j}\overrightarrow{v_(w/c)} = \overrightarrow{vw}-\overrightarrow{vc}\\\\\overrightarrow{v_(w/c)} = - 3.5 \widehat{i} - 3.5 \widehat{j} - 12 \widehat{i}\\\\\overrightarrow{v_(w/c)} =-15.5 \widehat{i} - 3.5 \widehat{j}[/tex]

A 15-cm-focal-length converging lens is 19 cm to the right of a 6.0-cm-focal-length converging lens. A 1.0-cm-tall object is distance L to the left of the 6.0-cm-focal-length lens.

Required:
For what value of L is the final image of this two-lens system halfway between the two lenses?

Answers

Answer:

L = 11.014 cm

Explanation:

Halfway between the two lenses is 19/2 = 9.5 cm.

Thus, this means virtually with respect to lens, the final image is at -9.5 cm

Thus, from here, we will work this out backwards.

Let's first solve for the initial position of the object for the second lens;

(1/S2) + (1/s'2) = (1/f2)

Where s'2 is the real image.

F2 is focal length

Thus;

(1/s'2) = (1/f2) - (1/s2)

(1/s'2) = (1/15) - (1/-9.5)

(1/s'2) = 0.1719

s'2 = 5.82 cm

The object for the second lens is located at 5.82 cm in front of the second lens.

Now, The object for the second lens and the image for the first lens will be the same.

This means the distance of the image from the first lens is at; 19 - 5.82 = 13.18 cm.

Now let's solve for the object distance of the first lens which will be denoted by L.

1/L = (1/f1) + (1/s'1)

Where f1 = 6 cm

1/L = (1/6) - (1/13.18)

1/L = 0.090794

L = 1/0.090794

L = 11.014 cm

A gas is enclosed in a cylinder fitted with a light frictionless piston and maintained at atmospheric pressure. When 7950 kcal of heat is added to the gas, the volume is observed to increase slowly from 12.8 m^3 to 19.4 m^3.

Required:
a. Calculate the work done by the gas. Express your answer with the appropriate units.
b. Calculate the change in internal energy of the gas, Express your answer with the appropriate units.

Answers

Answer:

Explanation:

From the question we are told that:

Energy [tex]Q=7950kcal=3.3*10^7[/tex]

Initial Volume [tex]V_1=12.8 m^2[/tex]

Final Volume [tex]V_2=19.4 m^2[/tex]

a)

Generally the equation for Work done is mathematically given by

 [tex]W=P \triangle V[/tex]

Where

 [tex]P= Pressure at 1atm[/tex]

Therefore

 [tex]W=(1.01*10^5)(19.4-12.8)[/tex]

 [tex]W=6.67*10^5J[/tex]

a)

Generally the equation for Change in internal energy of the gas is mathematically given by

 [tex]\triangle U=Q-W[/tex]

 [tex]\triangle U=3.3*10^7-6.67*10^5J[/tex]

 [tex]\triangle U=3.2*10^7J[/tex]

Why do you think we see the sun moves across the sky?
answer it for brainlliest

Answers

Answer:

From Earth, the Sun looks like it moves across the sky in the daytime and appears to disappear at night. This is because the Earth is spinning towards the east. The Earth spins about its axis, an imaginary line that runs through the middle of the Earth between the North and South poles.

a horizontal turntable with radius 0.8 m is rotation about a vertical axis at ts center. a small block sits on the turntable at a distance of 0.4 m from the acis and rotates in a circular path at a speed of 0,800 m/s. what minim coeeficent of static friction between the blok and the turntable is required for the block not to slip

Answers

Answer: 0.04

Explanation:

Given

Radius of turntable [tex]r=0.8\ m[/tex]

Block is present at a distance of [tex]r_o=0.4\ m[/tex]

Turntable rotates at a speed of [tex]v=0.8\ m/s[/tex]

angular speed of turntable [tex]\omega =\dfrac{v}{r}[/tex]

[tex]\Rightarrow \omega =\dfrac{0.8}{0.8}\\\Rightarrow \omega =1\ rad/s[/tex]

block will experience a force i.e. centripetal force equal to [tex]m\omega ^2r[/tex]. This must balance the friction force [tex]\mu mg[/tex]

[tex]\Rightarrow m\omega^2 r_o=\mu mg\\\Rightarrow 1^2\times 0.4=\mu \times 9.8\\\Rightarrow \mu =0.04[/tex]

Thus, the coefficient of static friction force is [tex]0.04[/tex]

Nick and Chloe left their campsite by canoe and paddle downstream at an average speed of 12 km/h. They turned around and paddled back upstream at an average speed of 4 km/h. The total trip took 1 hour. After how much time did the campers turn around downstream

Answers

Her average speed is 1.6 miles per hour. Average speed is total distance covered by total time taken to do it. She swims 4 miles upstream, and at 1 mph, it takes 4 hours. She comes back downstream at 4 mph and so she covers the 4 miles in 1 hour. Her total mileage is 8 miles. It takes 4 + 1 hours or 5 hours to cover it. The 8 miles divided by 5 hours is 1 3/5 miles per hour, or 1.6 mph for an average speed.

The time spent by the campers when they turn around downstream is 15 minutes.

Total distance traveled by Nick and Chloe

The concept of total distance traveled by Nick and Chloe can be used to determine the time they turn around downstream.

Let time for downstream = t1

Let time for upstream = t2

distance covered in upstream = distance covered in downstream = d

12(t1) = d

4(t2) = d

12t1 = 4t2

t1 + t2 = 1

t2 = 1 - t1

12t1 = 4(1 - t1)

12t1 = 4 - 4t1

16t1 = 4

t1 = 4/16

t1 = 0.25 hours

t1 = 0.25(60 min) = 15 mins

Learn more about distance here: https://brainly.com/question/2854969

#SPJ2

A moving object is in equilibrium. What bests describes the motion of the object if mo force changes

•It will change directions
•It will slow down
•It will maintain the state of motion
•It will speed up and ten slow down

Answers

Answer:

telekinesis moving things with your mind

A very basic concept when dealing with forces is the idea of equilibrium or balance. In general, an object can be acted on by several forces at the same time. A force is a vector quantity which means that it has both a magnitude (size) and a direction associated with it. If the size and direction of the forces acting on an object are exactly balanced, then there is no net force acting on the object and the object is said to be in equilibrium. Because there is no net force acting on an object in equilibrium, then from Newton's first law of motion, an object at rest will stay at rest, and an object in motion will stay in motion.

Answer: I will maintain the state of motion.

3.1Chất điểm chuyển động thẳng với phương trình: x = – 1 + 3t2
– 2t
3
(hệ SI, với t ≥ 0). Chất điểm dừng lại để

đổi chiều chuyển động tại vị trí có tọa độ:

Answers

Answer:

eqcubuohwehuuc

Explanation:

the the the the the the the the the the the the the the the the dhueirrjhrhjrirjrheh3jeiiruj fnrhfjjjrjrj fjfiirrjejrjejej jrkrjrjrjrjrjdjdjfjrhruriruru rjridjhwjjsjd

What must a scientist do in order to develop a testable hypothesis?
A. Identify a conclusion that provides the most popular explanation
for the question.
B. Determine whether experimental observations can provide
evidence to support a conclusion.
C. Copy the opinions of other scientists with similar questions.
D. Survey the preferences of other scientists who have done similar
research.

Answers

The correct answer is option B. Determine whether experimental observations can provide evidence to support a conclusion.

1. Identify the research question: Begin by clearly defining the question or problem that you want to investigate. This question should be specific and focused, allowing for clear hypotheses to be developed.

2. Conduct background research: Familiarize yourself with existing knowledge and previous research related to your question. This step will help you understand the current state of knowledge in the field and identify any gaps or areas that require further investigation.

3. Formulate a hypothesis: Based on your background research, develop a hypothesis that proposes a possible explanation or answer to your research question. A hypothesis should be a clear statement that can be tested through experimentation or observation. It should be specific, measurable, and falsifiable, meaning that it can be proven wrong if the evidence does not support it.

4. Design experiments or observations: Once you have formulated a hypothesis, consider the experimental or observational methods that can be used to test it. Determine what data you need to collect, what variables you need to manipulate or measure, and what controls should be put in place to ensure the validity of your results.

5. Predict outcomes: Based on your hypothesis, make predictions about the expected outcomes of your experiments or observations. These predictions should be derived from your hypothesis and should be specific enough to be tested.

6. Conduct the experiment or observation: Carry out the planned experiments or observations, ensuring that you collect and record data accurately. Implement proper controls and procedures to minimize any biases or confounding factors that could affect the results.

7. Analyze the data: Once you have collected the data, analyze it using appropriate statistical or analytical methods. Evaluate whether the data supports or contradicts your hypothesis and predictions.

8. Draw conclusions: Based on the analysis of your data, draw conclusions about whether the evidence supports or refutes your hypothesis. Clearly state the findings and discuss their implications in the context of the research question.

9. Communicate the results: Share your findings with the scientific community through scientific papers, presentations, or other appropriate means. Allow other scientists to review and replicate your work, fostering further discussion and advancement in the field.

Remember, the scientific process is iterative, and developing a hypothesis is just the starting point. Scientists continuously refine and revise their hypotheses based on new evidence and insights gained from their experiments and observations.

For more such questions on observations , click on:

https://brainly.com/question/16846001

#SPJ8

How is wind generated?
O A. Air molecules move from areas of low pressure to areas of high
pressure.
O B. Air molecules move more slowly where the temperature is higher
and the pressure is lower.
C. Air molecules move more quickly where the temperature is lower
and the pressure is higher.
D. Air molecules move from areas of high pressure to areas of low
pressure.

Answers

Answer:

Explanation:

Wind is caused by the uneven heating of the atmosphere by the sun, variations in the earth's surface, and rotation of the earth. ... Wind turbines convert the energy in wind to electricity by rotating propeller-like blades around a rotor. The rotor turns the drive shaft, which turns an electric generator

4. Brandon throws a tennis ball vertically upward. The ball returns to the point of release after 4.0 s. What is the
speed of the ball as it is released?

Answers

Answer:

-39.2m/s

Explanation:

Using the equation of motion;

v = u + at

Since the ball is thrown upward, the acceleration due to gravity acting on it will be negative, hence a = -g

v = u - gt

Since g = 9.8m/s²

t = 4.0s

u = 0m/s

v = 0 + (-9.8)(4)

v = 0 + (-9.8)(4)

v = -39.2m/s

Hence the speed of the ball before release is -39.2m/s

You sit on ice and shove a heavy box with your feet with a given force. What will you and the box share? *
A) Same acceleration
B) equal and opposite acceleration
C) the equal and opposite force
D) same force
explain please

Answers

Answer:

the correct answer is C

Explanation:

In this exercise we will analyze the situation.

When the person is on the ice, the friction coefficient is very small, if the box is in a place where there is no ice, the coefficient is different, so the friction force on each body is different.

Therefore the acceleration that each body acquires is different.

If we apply the conservation of momentum, each body moves in the opposite direction, but with different speeds.

If we use Newton's third law, the force applied to each body has the same magnitude and opposite direction, which is why the force is of the action and reaction type

Consequently the correct answer is C

Aluminium has a specific heat capacity of 900 J/(kg°C).
The internal energy of a 2.0kg block of aluminium increases by 13500 j.
By how much does the temperature of the block increase?

B 0.13°C
C 7.5°C
A
0.067 °C
D 15°C

Answers

Answer:

24300000K

Explanation:

Q=mc(change in temperature)

900X2.0=1800.0

1800.0X13500= 24300K

According to specific heat capacity, the temperature of the block increases by 7.5°C.

What is specific heat capacity?

Specific heat capacity is defined as the amount of energy required to raise the temperature of one gram of substance by one degree Celsius. It has units of calories or joules per gram per degree Celsius.

It varies with temperature and is different for each state of matter. Water in the liquid form has the highest specific heat capacity among all common substances .Specific heat capacity of a substance is infinite as it undergoes phase transition ,it is highest for gases and can rise if the gas is allowed to expand.

It is given by the formula ,

Q=mcΔT

Substitute values in above formula ,Δt=Q/mc=13500/2×900=7.5°C.

Thus,  the temperature of the block increases by 7.5°C.

Learn more about specific heat capacity,here:

https://brainly.com/question/29766819

#SPJ2

If R1 and R2 are in parallel and R3 is in series with them then equivalent resistance will be

Answers

Answer:

Refer to the attachment!~

A balky cow is leaving the barn as you try harder and harder to push her back in. In coordinates with the origin at the barn door, the cow walks from x = 0 to x = 6.9 m as you apply a force with x-component F _ { x } = - [ 20.0 N + ( 3.0 N / m ) x ]F x =−[20.0N+(3.0N/m)x]. How much work does the force you apply do on the cow during this displacement?

Answers

Answer:

The work done is -209.42 J.

Explanation:

F(x) = (- 20 - 3 x ) N

x = 0 to x = 6.9 m

Here, the force is variable in nature, so the work done by the variable force is given by

[tex]W =\int F dx\\\\W =\int_{0}^{6.9}(-20- 3x dx )\\\\W= \left [ - 20 x - 1.5 x^2 \right ]_{0}^{6.9}\\\\W = - 20 (6.9 - 0) - 1.5(6.9\times 6.9 - 0)\\\\W =- 138 - 71.42\\\\W = - 209.42 J[/tex]

A steel cable lying flat on the floor drags a 20 kg block across a horizontal, frictionless floor. A 100 N force applied to the cable causes the block to reach a speed of 4.2 m/s in a distance of 2.0 m.
What is the mass of the cable?

Answers

Answer:

m_cable = 2,676 kg

Explanation:

For this exercise we must look for the acceleration with the kinematic ce relations

          v² = v₀² + 2 a x

since the block starts from rest, its initial velocity is vo = 0

          a = v² / 2x

          a = 4.2² /(2 2.0)

          a = 4.41 m / s²

now we can use Newton's second law

Note that the mass that the extreme force has to drag is the mass of the block plus the mass of the cable.

          F = (m + m_cable) a

          m_cable  = F / a -m

          m_cable = 100 / 4.41 - 20

          m_cable = 2,676 kg

chứng minh V=kq/r từ mối liên hệ giữ E và V

Answers

Answer:V=Aq=KQr

Explanation:

Không biết V bạn kí hiệu ở đây là gì nhỉ? Có phải là điện thế?

Điện thế tại 1 điểm trong điện trường được định nghĩa là công làm vật dịch chuyển từ vị trí đó đến vô cùng. V = A/q

Chứng minh thì được, nhưng chỉ e bạn không có hiểu biết về nguyên hàm, tích phân nên không hiểu.

- Xét tại vị trí cách điện tích Q một đoạn x, khi đó điện tích q sẽ chịu 1 lực: dF=KQ.qx2

Điện tích q dịch chuyển 1 khoảng dx rất nhỏ. Khi đó công do lực điện trường gây ra là:

dA=dF.dx=KQ.qx2dx

Công để dịch chuyển điện tích q từ vị trí r đến vô cùng là:

A=∫∞rdA=∫∞rKQ.qx2dx=KQ.qr−KQ.q∞=KQ.qr

Theo đúng định nghĩa: V=Aq=KQr

The more bonds an atom can make, the more likely it is to combine with other aton
Which element is most likely able to make the greatest variety of bonds?
nitrogen
hydrogen
oxygen
carbon

Answers

Answer:

carbon has tetra valency while oxygen  can make 2 bonds while nitrogen can make 3 bonds  and hydrogen can make 1 bond so i think answer is definatly carbon

Explanation:

Two uncharged metal spheres, spaced 25.0 cm apart, have a capacitance of 26.0 pF. How much work would it take to move 12.0 nC of charge from one sphere to the other? Answer in Joules.

Answers

Answer:

[tex]W=2.76\times 10^{-6}\ J[/tex]

Explanation:

Given that,

The distance between two spheres, r = 25 cm = 0.25 m

The capacitance, C = 26 pF = 26×10⁻¹² F

Charge, Q = 12 nC = 12 × 10⁻⁹ C

We need to find the work done in moving the charge. We know that, work done is given by :

[tex]U=\dfrac{Q^2}{2C}[/tex]

Put all the values,

[tex]U=\dfrac{(12\times 10^{-9})^2}{2\times 26\times 10^{-12}}\\\\U=2.76\times 10^{-6}\ J[/tex]

So, the work done is [tex]2.76\times 10^{-6}\ J[/tex].

A string of length 3m and total mass of 12g is under a tension of 160N. A transverse harmonic wave with wavelength 25cm and amplitude 2cm travels to the right along the string. It is observed that the displacement at x=0 at t=0 is 0.87cm. a) What is the wave? b) Wrote the wave function, y(x,t) c) Find the particle velocity at position x=0 at time t=10s. What is the maximum particle velocity?​

Answers

Answer:

What is the answer bro idont now

Imagine that you are standing on a spherical asteroid deep in space far from other objects. You pick up a small rock and throw it straight up from the surface of the asteroid. The asteroid has a radius of 9 m and the rock you threw has a mass of 0.113 kg. You notice that if you throw the rock with a velocity less than 45.7 m/s it eventually comes crashing back into the asteroid.

Required:
Calculate the mass of the asteroid.

Answers

Answer:

M = 1.409 10¹⁴ kg

Explanation:

In this exercise we have that the prioress with a minimum speed can escape from the asteroid, therefore we can use the conservation of energy relation.

Starting point. When you drop the stone

         Em₀ = K + U

         Em₀ = ½ m v² - G m M / r

where M and r are the mass and radius of the asteroid

Final point. When the stone is too far from the asteroid

          Em_f = U = - G m M / R_f

as there is no friction, the energy is conserved

          Em₀ = Em_f

          ½ m v² - G m M / r = - G m M / R_f

          ½ v² = G M (1 / r - 1 /R_f)

indicate that for the speed of v = 45.7 m /s, the stone does not return to the asteroid so R_f = ∞

          ½ v² = G M (1 /r)

          M = [tex]\frac{v^2 r}{2G}[/tex]

 

let's calculate

          M = [tex]\frac{45.7^2 \ 9}{ 2 \ 6.67 \ 10^{-11}}[/tex]

          M = 1.409 10¹⁴ kg

What must be the same for any two resistors that are connected in a series

Answers

The potential difference must be the same
Other Questions
Qu factores geogrficos contribuyen a la consistencia de los productos de las colonias del sur? Please help me. I don't want turn in this assignment late. No links, and please right the one that is with this lesson.Not random things. The Pizza Company is considering a new three-year expansion project. The key data are shown below:The company hired a consulting firm to help evaluate the project and paid the consulting fee of $60,000. The company owns the space. If company did not invest in the project, it can receive after-tax rental fee for $300,000 per year for 3 years. However, if thecompany invested in the project, it will use the space for the project. The fixed cost to produce pizza is required at $150,000 per year. It is estimated that 50,000 units will be sold in the first year and that 40,000 units and 30,000 units will be sold in the second and third years respectively. Each pizza is expected to sell for $25 and the production cost will be $15 per unit. The sales price and variable cost should increase with inflation. Expected inflation rate per year is 5%. The project requires an initial investment in working capital of $500,000, which will be required in each year at 10% of revenue in the following year. The purchase of the machinery at the start of the project is $1,000,000. The shipping and installation cost are $200,000. The machinery will be depreciated straight-line to zero. It is estimated that the machinery can be sold at the end of the project for $250,000. To finance the project, the company would need to take a one-million dollar loan at 8% interest rate p.a. from HSBC over the life of the project. Annual interest expense is $80,000. The corporate tax rate is 34%. The Pizza Company is evaluating its cost of capital under alternative financing arrangements. In consultation with the consulting firm, the Pizza Company expects to be able to issue new Debt at Par with a coupon rate of 8% (coupons paid annually) and to issue new preferred stock with a $4 per share dividend at $32 a share. The common stock of the Pizza Company is currently selling for $22 a share while its book value is $6. The Pizza Company expects to pay a totaldividend of $525,000 for its 200,000 common shares outstanding next year. Market analysts foresee a growth in dividends of the company at the rate of 4% per year. The Pizza Company raises capital using 30% bond, 20% preferred stock, and 50% common stocka. What is the cost of capital (WACC) of the Pizza Company?b. Calculate the NPV of the project using the cost of capital calculated in part (a).Should the project be accepted? The sequence of subunits in a protein is most directly dependent on the *O region in the cell where enzymes are producedDNA in the chromosomes in a cellO type of cell in which starch is foundkind of materials in the cell membrane 2 brothers are 1m 60 cm and 1m 44cm tall. What is their ratio of their height In which government system does the government not interfere with the production and selling of goods Miranda's financial aid stipulates that her tuition not exceed $1500. If her college charges a $55 registration fee for the term plus $275 per course, what is the greatest number of courses for which Miranda can register? Miranda can register for at most how many courses? 2+2-2-5+5+6+4+8-2+47+28 Tp nghim ca phng trnh 2^x=-1 l what is equivalent to 64 1/4 which consumers live in neritic zone Translate this word problem as a system of equations and then solve using substitution.The sum of two numbers is 84. One number is three times the other. Find the numbers.Put your answer in this form: The numbers are 3 and 6. 17.35 ma of current is flowing though a brown-red-brown resistor,what is v paste or draw pictures of five junk food items and list five harmful effects of those items The diagram below represents the time a cell spends in the two main phasesof the cell cycle. In which phase does a cell spend more time?A. ProphaseB. MitosisC. MeiosisD. Interphase Chromosomes contain the genetic material found in cells. true or false?1. true2. false Fill in the blank in the following sentence with the appropriate indirect object pronoun. Los estudiantes ___ dan la tarea a la profesora. Los murales de este expresionista mexicano estn localizados en Estados Unidos y en Mxico. Sus murales intentaban demostrar la rica historia de Mxico y expresar las ideas del gobierno al pblico. A) Franck de las MercedesBajo la influencia de Mir y Picasso, l desarroll un estilo que reflejaba el mundo del sueo. Sus obras eran hiperrealistas con imgenes de fantasa y lo absurdo. Intentaba mezclar las ideas y presentarlas como una realidad alternativa. B) Pablo PicassoEl arte pop y el arte abstracto manifiestan las influencias del arte abstracto de Nueva York y los artistas de grafiti. No estudi el arte en una escuela, pero imita famosos artistas modernos. C) Salvador DalSin duda, sus obras muestran influencias de frica en el uso de las formas. Pas por una etapa de gris, azul y rojo. Usaba los colores y las formas geomtricas para hacer comentarios de todo lo que le rodeaba en la sociedad. D) Jos Clemente Orozco the Greeks. felt at home with human godsA. themB. themselvesC. yourselvesD.they Someone help please!!!