Answer:
32.2 units
Step-by-step explanation:
The length of a line segment can be found from its endpoint coordinates using the distance formula.
d = √((x2 -x1)² +(y2 -y1)²)
d = √((18 -2)² +(-18 -10)²) = √(16² +(-28)²) = √1040
d ≈ 32.2
The line segment is about 32.2 units long.
The approximate length of the segment is 32.25 units if the line segment has endpoints at (2, 10) and (18, -18).
What is a distance formula?It is defined as the formula for finding the distance between two points. It has given the shortest path distance between two points.
We have two points (2, 10) and (18, -18)
From the distance formula:
[tex]\rm d= \sqrt{(x_2-x_2)^2+(y_2-y_1)^2}[/tex]
[tex]\rm d= \sqrt{(18-2)^2+(-18-10)^2}[/tex]
[tex]\rm d= \sqrt{(16)^2+(-28)^2} \\\\\rm d= \sqrt{(256+784)\\[/tex]
[tex]\rm d =\sqrt{1040} \\\\d = 32.249[/tex] units or
d = 32.25 units
Thus, the approximate length of the segment is 32.25 units if the line segment has endpoints at (2, 10) and (18, -18).
Learn more about the distance formula here:
brainly.com/question/18296211
#SPJ4
A triangle has sides that measure 3 cm, 4 cm, and 5 cm. What type of triangle is it?
help pls
Answer:
it is A Scalene Triangle
Directions: Calculate the area of a circle using 3.14x the radius
1) d = 4.4 mm.
Calculate the area of the circle.
2) d = 3.7 cm.
Calculate the area of the circle.
3) r= 8.3 cm.
Calculate the area of the circle.
4) d = 5.8 yd.
Calculate the area of the circle.
5) d = 1 yd.
Calculate the area of the circle
6) r = 8 ft.
Calculate the area of the circle
[tex]\qquad\qquad\huge\underline{{\sf Answer}}♨[/tex]
As we know ~
Area of the circle is :
[tex]\qquad \sf \dashrightarrow \:\pi {r}^{2} [/tex]
And radius (r) = diameter (d) ÷ 2
[ radius of the circle = half the measure of diameter ]
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Problem 1[tex]\qquad \sf \dashrightarrow \:r = d \div 2[/tex]
[tex]\qquad \sf \dashrightarrow \:r = 4.4\div 2[/tex]
[tex]\qquad \sf \dashrightarrow \:r = 2.2 \: mm[/tex]
Now find the Area ~
[tex]\qquad \sf \dashrightarrow \: \pi {r}^{2} [/tex]
[tex]\qquad \sf \dashrightarrow \:3.14 \times {(2.2)}^{2} [/tex]
[tex]\qquad \sf \dashrightarrow \:3.14 \times {4.84}^{} [/tex]
[tex]\qquad \sf \dashrightarrow \:area \approx 15.2 \: \: mm {}^{2} [/tex]
・ ．━━━━━━━†━━━━━━━━━．・
problem 2[tex]\qquad \sf \dashrightarrow \:r = d \div 2[/tex]
[tex]\qquad \sf \dashrightarrow \:r = 3.7 \div 2[/tex]
[tex]\qquad \sf \dashrightarrow \:r = 1.85 \: \: cm[/tex]
Bow, calculate the Area ~
[tex]\qquad \sf \dashrightarrow \: \pi {r}^{2} [/tex]
[tex]\qquad \sf \dashrightarrow \:3.14 \times (1.85) {}^{2} [/tex]
[tex]\qquad \sf \dashrightarrow \:3.14 \times 3.4225 {}^{} [/tex]
[tex]\qquad \sf \dashrightarrow \:area \approx 10.75 \: \: cm {}^{2} [/tex]
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Problem 3[tex]\qquad \sf \dashrightarrow \:\pi {r}^{2} [/tex]
[tex]\qquad \sf \dashrightarrow \:3.14 \times (8.3) {}^{2} [/tex]
[tex]\qquad \sf \dashrightarrow \:3.14 \times 68.89[/tex]
[tex]\qquad \sf \dashrightarrow \:area \approx216.31 \: \: cm {}^{2} [/tex]
・ ．━━━━━━━†━━━━━━━━━．・
Problem 4[tex]\qquad \sf \dashrightarrow \:r = d \div 2[/tex]
[tex]\qquad \sf \dashrightarrow \:r = 5.8 \div 2[/tex]
[tex]\qquad \sf \dashrightarrow \:r = 2.9 \: \: yd[/tex]
now, let's calculate area ~
[tex]\qquad \sf \dashrightarrow \:3.14 \times {(2.9)}^{2} [/tex]
[tex]\qquad \sf \dashrightarrow \:3.14 \times 8.41 [/tex]
[tex] \qquad \sf \dashrightarrow \:area \approx26.41 \: \: yd {}^{2} [/tex]
・ ．━━━━━━━†━━━━━━━━━．・
problem 5[tex]\qquad \sf \dashrightarrow \:r = d \div 2[/tex]
[tex]\qquad \sf \dashrightarrow \:r = 1 \div 2[/tex]
[tex]\qquad \sf \dashrightarrow \:r = 0.5 \: \: yd[/tex]
Now, let's calculate area ~
[tex]\qquad \sf \dashrightarrow \:\pi {r}^{2} [/tex]
[tex]\qquad \sf \dashrightarrow \:3.14 \times (0.5) {}^{2} [/tex]
[tex]\qquad \sf \dashrightarrow \:3.14 \times 0.25[/tex]
[tex]\qquad \sf \dashrightarrow \:area \approx0.785 \: \: yd {}^{2} [/tex]
・ ．━━━━━━━†━━━━━━━━━．・
problem 6[tex]\qquad \sf \dashrightarrow \:\pi {r}^{2} [/tex]
[tex]\qquad \sf \dashrightarrow \:3.14 \times {(8)}^{2} [/tex]
[tex]\qquad \sf \dashrightarrow \:3.14 \times 64[/tex]
[tex]\qquad \sf \dashrightarrow \:area = 200.96 \: \: yd {}^{2} [/tex]
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please help asap have a good day and ily
Answer:
Pretty sure it's 2:30 P.M.
Step-by-step explanation:
If her track practice started at 12:00 P.M., and and ran relays for one hour, it would already be 1:00 P.M.
Then she practiced the long jump for an hour and thirty minutes. Add another hour to that and it would be 2:00 P.M. Add thirty minutes, and it would be 2:30 P.M.
Hopefully that makes sense to you
Select the correct answer.
Which number is an irrational number?
A.
B.
C.
D.
Answer:
you do not have any numbers, only letters so I cannot answer your question. sorry...
Step-by-step explanation:
Select the correct answer.
Which number is an irrational number?
A.
B.
C.
D.
Find the value of cos⁻¹ (cos7π/6).
Answer:
5π/6
Step-by-step explanation:
Given :
cos⁻¹ (cos7π/6)Solving :
We know that : cos⁻¹ cosθ = θBut we can't just do that in this caseBecause the range of cos values is [0, π]Clearly, our value does not lie in this rangeWe have to take a different Quadrant other than the 3rd Quadrant which gives cos a negative valueThe 2nd Quadrant also has cos values negativeTherefore,cos⁻¹ cos (π - π/6)cos⁻¹ cos (5π/6)⇒ 5π/6 ∈ [0, π] ⇒ It lies in the range!Answer:
5π Over 6
Step-by-step explanation:
You can write 7π6 as (π+π6)Thus we can clearly see the angle falls in the third quadrant. And the cosine value in third quadrant is always negative. Hence, cos(π+π6)=−cos(π6)coming back to the question cos−1[cos(7π6)]=cos−1[−cos(π6)]=π−cos−1[cos(π6)]=π−π6=5π6
Hello people ~
factorise ↷
x^2 + 6x + 8
[tex]\qquad\qquad\huge\underline{\boxed{\sf Answer}}[/tex]
Let's solve ~ ☂
⧠ Here, I'm using middle term split method :
[tex] \qquad\rightarrowtail \sf {x}^{2} + 6x + 8[/tex]
[tex] \qquad\rightarrowtail \sf {x}^{2} + 4x + 2x+ 8[/tex]
[tex] \qquad\rightarrowtail \sf {x(x}^{} + 4) + 2(x+ 4)[/tex]
[tex] \qquad\rightarrowtail \sf (x + 2)(x+ 4)[/tex]
[tex]\\ \rm\rightarrowtail x^2+6x+8[/tex]
[tex]\\ \rm\rightarrowtail x^2+4x+2x+8[/tex]
[tex]\\ \rm\rightarrowtail x(x+4)+2(x+4)[/tex]
[tex]\\ \rm\rightarrowtail (x+2)(x+4)[/tex]
Done!
CHOOSE THE CORRECT ANSWER
Workers in an office of 60 staff were asked their favourite type of take-away.
The results are summarised in the table.
Pizza=8
Curry=8
Fish & chips=5
Kebab=9
Other=30
Work out the size of each angle to draw a pie chart.
PA ANSWERR NEED SOME ANSWERS THNKS
Answer:
16. j = 105 °
17. Q = 68 °
18. s = 97 °
19. t = 70 °
20. r = 125 °
Step-by-step explanation:
16. Name the angle that is supplementary to angle J as K, and label the angle that is next to K as G
Angle G = 105, because it is corresponding to the 105 angle.
Since G is supplementary to K, angle K = 75.
So, J = 105
17. Name the angle that is supplementary to angle Q as R
Angle R = 112, because it is corresponding to the 112 angle.
Since R is supplementary to Q, angle Q = 68.
18. Name the angle that is supplementary to the 83 angle as L
Angle L = 97, since angle L and the 83 angle are supplementary angles
-> Angle S = 97, since S and L are alternate angles
19. Angle T = 70, since angle T and the 70 angle are corresponding angles.
20. Name the angle that are alternate angles with angle R as Q
Angle Q = 125, because it is corresponding to the 125 angle.
Since angle Q and angle R are alternate angles, angle R = 125.
(Note : alternate angles and corresponding angles are equal to each other, supplementary angles add up to 180.)
-5
What is the sign of a.
()
when a = 0 and b < 0?
b
Sos I need help
[tex]\qquad\qquad\huge\underline{\boxed{\sf Answer}}[/tex]
The sign of a will be negative ~
let the value of be be ' -x ' , -x is a negative number (b = -x < 0)
[tex]\qquad \sf \dashrightarrow \: a \times \frac{ - b}{b} [/tex]
[tex]\qquad \sf \dashrightarrow \: a \times \frac{ - ( - x)}{ - x} [/tex]
[tex]\qquad \sf \dashrightarrow \: a \times \frac{ x}{ - x} [/tex]
[tex]\qquad \sf \dashrightarrow \: a \times \frac{ - x}{ x} [/tex]
[tex]\qquad \sf \dashrightarrow \:a \times - 1[/tex]
[tex] \qquad \sf \dashrightarrow \:- a[/tex]
Therefore, the term a, has a negative sign unless it's value is substituted, I.e -a = 0 ( having no sign )
Ella traveled by train to visit her friend.
• It took 3 hours for Ella to reach her destination.
• The train averaged a speed of 100 miles per hour.
Enter an equation to express the distance, d, Ella traveled.
Answer:
d = st, d = 100 x 3
Step-by-step explanation:
distance = speed x time
distance = 100 x 3, therefore, distance = 300, but if you just want the equation, it is d = 100 x 3 or d = st
Step-by-step explanation:
d = 100 x 3.
d= 100n
where n = time the journey took.
Pls help me on this problem I’m confused
5 quarts I think 4 cups per quart has 5 quarts and 2 cups I think
Answer:
1 quart = 4 cups
8 × 4 = 32
32 - 6 = 26
26 - 18 = 8
he has 2 quarts left
Find the value of a. Round your answer to the nearest tenth. B 10 77.5 A C 7.9
Answer:
[tex]\displaystyle 11,3[/tex]
Step-by-step explanation:
Use the Law of Cosines to find the length of the third edge:
Solving for Angles
[tex]\displaystyle \frac{a^2 + b^2 - c^2}{2ab} = cos\angle{C} \\ \frac{a^2 - b^2 + c^2}{2ac} = cos\angle{B} \\ \frac{-a^2 + b^2 + c^2}{2bc} = cos\angle{A}[/tex]
Use [tex]\displaystyle cos^{-1}[/tex]towards the end or you will throw your result off!
Solving for Edges
[tex]\displaystyle b^2 + a^2 - 2ba\:cos\angle{C} = c^2 \\ c^2 + a^2 - 2ca\:cos\angle{B} = b^2 \\ c^2 + b^2 - 2cb\:cos\angle{A} = a^2[/tex]
Take the square root of the final result or it will be thrown off!
Let us get to wourk:
[tex]\displaystyle 10^2 + 7,9^2 - 2[10][7,9]\:cos\:77,5 = a^2 \hookrightarrow 100 + 62,41 - 158\:cos\:77,5 = a^2 \hookrightarrow \sqrt{128,212541} = \sqrt{a^2}; 11,323097677... \\ \\ \boxed{11,3 \approx a}[/tex]
I am joyous to assist you at any time.
the question is too hard
Answer:
a
Step-by-step explanation:
7(g-9)+12=26
7(g-9)+12-12=26-12
7(g-9)=14
7(g-9)/7=14/7
g-9=2
g-9+9=2+9
g=11
Answer:
(A) G= 11
Step-by-step explanation:
26=7(g-9)+12
(take 12 to 26)
so it will be 7(g-9)= 26-12
=> 7(g-9)= 14
(then take 7 to 14)
=> g-9= 14/2
=> g-9= 2
(then take 9 to 2)
g= 2 + 9
g= 11hope it is properly explained
STAY SAFE, HAVE A NICE DAY
Calculate the area of the equilateral triangle using the formula for area of a regular polygon, and compare it to Bianca’s answer. The apothem, rounded to the nearest tenth, is units. The perimeter of the equilateral triangle is units. Therefore, the area of the equilateral triangle is , or approximately 43. 5 units2. The calculated areas are.
The calculated areas of both are the same instead of using the different formulas that are 43. 5 squared unit.
What is the area of a regular polygon?The area of the polygon is the product of half of the apothem of the triangle and perimeter.
The area of the polygon = [tex]\frac{1}{2} \times h \times p[/tex]
The side of the triangle is 10 units.
Apothem of an equilateral triangle
[tex]s = \frac{\sqrt{3} a}{6}[/tex]
s= [tex]\sqrt{3} \times 10/6[/tex]
s = 2.88
Here, a is the side of the triangle.
Thus the apothem of the triangle is 2.9 units.
The perimeter of the equilateral triangle is equal to the three times the sides.
Perimeter of the equilateral triangle ,
P = 3(10)
P = 30
Therefore, the perimeter of the equilateral triangle is 30 units.
The area of the equilateral triangle-
The area of the polygon = [tex]\frac{1}{2} \times h \times p[/tex]
A = [tex]1/2 \times 2.9 \times 30[/tex]
A = 43.5
Thus the area of the equilateral triangle is 43.5 squared units.
Therefore, The calculated areas of both are the same instead of using the different formulas.
Learn more about the apothem;
brainly.com/question/10580427
Answer:
(A) 2.9
(C)30
(A)1/2(2.9)(30)
(D)The same despite using different formulas
Step-by-step explanation:
I did it
m exponent 2 plus 15 if m =4
Answer:
31
Step-by-step explanation:
[tex]4^{2}[/tex]=16
16+15=31
Find the value of x. 136° (8x + 40) (The figure is not to scale.)
Answer:
x= 12
Step-by-step explanation:
Hope u understood it
"PLEASE MARK ME THE BRAINLIEST"
n 12. Find the volume of the sphere.
Answer:
2929 1/3 [tex]\pi[/tex] in^3
Step-by-step explanation:
The equation for the volume of a sphere is [tex]\frac{4}{3} \pi r^3[/tex].
Insert 13 for r. Then, simplify.
What is 7 1/3 x 2/5?
Math
Answer:
Step-by-step explanation:
you would multiply the fractions
then you would add the hole number
Answer:
2 14/15
Step-by-step explanation:
Find a value for Y and give a reason for your answer
Step-by-step explanation:
inscribed angles subtended by the same arc are equal.
the central angle of a circle is twice any inscribed angle subtended by the same arc.
the first statement tells us that the 53° angle as well as y stay the same size no matter where on their arcs (between the 2 points connected to O) they would be. so, we don't need to bother with any line lengths.
the 2nd statement tells us that x = 2×53 = 106°. the 53° and x angles refer to the short arc on the right of the 2 points connected to O.
and y and x refer to the larger arc on the left of the 2 line connected to O. that means according to the second statement : 360-x (the big angle around O) = 2y
so,
360 - 106 = 2y
254 = 2y
y = 127°
PLEASE HELP!
Solve for x. 4/5 = x/7 x =
Answer:
5.6
Step-by-step explanation:
4/5 = .8
so ? ÷ 7 = .8|
7 x .8 = 5.6
x= 5.6
x = 5.6
hope it helps...!!!!
-
nd
According to the line of best fit, about how many words
will Jean have typed when she completes 60 minutes of
typing?
0 2,500
o 2,750
3,000
O
3,250
Answer:
C. 3000
Step-by-step explanation:
i took the quiz!
also 60 and 3000 line up
Answer:
C 3,000
Step-by-step explanation: It's right on Edge
Leila received 5/7 of 49 votes for the class president. How many votes did she receive?
Answer:
71.428571%
Step-by-step explanation:
You divide 5 by 7
The (period,amplitude,frequence) of y=1/4cos1/2x is 4pie.
one of these is the answer need help
Answer:
period
Step-by-step explanation:
The attached graph shows a period of the function. Its amplitude is 1/4 (vertical distance from centerline to peak). Its period is 4π (horizontal distance from peak to peak). Its frequency is the reciprocal of the period, so would be 1/(4π).
The value 4π is the period of the function.
Find the volume of a cone with a height of 3.25 centimeters and
a diameter of 2.2 centimeters.
Answer:
As per Provided Information
Height of cone h is 3.25 cm
Diameter of cone is 2.2 cm
Radius = Diameter/2Radius = 2.2/2
Radius = 1.1 cm
We have been asked to determine the volume of the cone .
Using Formulae
[tex] \boxed{\bf \:Volume_{(Cone)} = \cfrac{1}{3} \pi {r}^{2}h}[/tex]
Substituting the given value and let's solve it
[tex]\sf\longrightarrow \: Volume_{(Cone)} = \cfrac{1}{3} \times 3.14 \times {1.1}^{2} \times 3.25 \\ \\ \\ \sf\longrightarrow \: Volume_{(Cone)} = \cfrac{1}{3} \times 3.14 \times 1.21 \times 3.25 \\ \\ \\ \sf\longrightarrow \: Volume_{(Cone)} = \cfrac{1}{3} \times 3.14 \times 3.9325 \\ \\ \\ \sf\longrightarrow \: Volume_{(Cone)} = \cfrac{1}{3} \times 12.34805 \\ \\ \\ \sf\longrightarrow \: Volume_{(Cone)} = \cfrac{12.34805}{3} \\ \\ \\ \sf\longrightarrow \: Volume_{(Cone)} = 4.11 {cm}^{3} [/tex]
Therefore,
Volume of the cone is 4.11 cm³ .Evaluate the function for the given value of x.
Answer:
f(-6)= -41 923
Step-by-step explanation:
f(-6)= -( -6)⁶ +5(-6)⁴+8(-6)³+2(-6) -7 you substitute x with -6 the you use a calculator which will then give you - 41923
solve for x and y 13x−28=24
x=4
also uhh where does the y go-
pls can I get some help this is compound interest (10) will give brainliest
Answer:
2.7
Step-by-step explanation:
What is 164 divided by 5.40
Answer:
30.37
Step-by-step explanation:
164÷5.40164×100/54016400/540give 30.37Answer:
[tex]164 \div 5.40 ={\ 30.3704{}}[/tex]
The answer is 30.3704
Lines a and b are parallel.
what is the value of x?
A) 15
B) 16
C) 56
D) 64
Answer:
56
Step-by-step explanation: