How could you correctly rewrite the equation 4(5 + 3) = 2(22 - 6) using the distributive property?
Answer:
We can correctly rewrite the equation: 4(5+3) = 2(22-6) by distributing each side.
4(5+3) = 2(22-6)
4(8) = 2(16)
32 = 32
Once you finish distributing each side, you can check to see if it is equal on both sides.
Step-by-step explanation:
Step-by-step explanation:
4(5 + 3) = 2(22 - 6)
4(8) = 2(16)
32 = 32
HELPPP plssss pls pls
Answer:
∠C = 75°
Step-by-step explanation:
using the formula for the sum of interior mangles for a polygon:
total interior angles = (180° x 5 angles) - 360° = 540°
113° + 4x + 113° + 2x + 9° + 3x + 8° = 540°
combine like terms:
9x + 243° = 540°
9x = 297°
x = 33°
∠C = 2(33) + 9 = 75°
PLEASE ANSWER ASAP FOR BRAINLEST!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!1
Answer:
bottom half
bottom- 3 x 12.5 = 37.5
front side- 3 x 4 = 12
back side- 12
left side- 4 x 12.5 = 50
right side- 50
total: 161.5
top half
front triangle- (3x4)/2 = 6
back triangle- 6
left side- 4 x 12.5 = 50
right side- 50
total: 112
161.5 + 112 = 273.5
Helppp please I'm stuck
Write the left side of the identity in terms of sine and cosine. Rewrite the numerator and denominator separately. (Do not simplify.) Simplify the fraction from the previous step such that both the fractions have the common denominator The expression from the previous step then simplifies to using what? A. Addition and a Reciprocal Identity B. Addition and a Pythagorean Identity
Answer:
[tex](a)[/tex] [tex]\frac{2}{cos\theta}/\frac{1}{sin\theta} + \frac{4sin\theta}{cos\theta} =6tan\theta[/tex]
[tex](b)[/tex] [tex]\frac{2sin\theta}{cos\theta} + \frac{4sin\theta}{cos\theta} =6tan\theta[/tex]
(c) Addition and Quotient identity
Step-by-step explanation:
Given
[tex]\frac{2sec\theta}{csc\theta} + \frac{4sin\theta}{cos\theta} =6tan\theta[/tex] --- The expression missing from the question
Solving (a): Write the left hand side in terms of sin and cosine
In trigonometry:
[tex]sec\theta = \frac{1}{cos\theta}[/tex]
and
[tex]csc\theta = \frac{1}{sin\theta}[/tex]
So, the expression becomes:
[tex]\frac{2 * \frac{1}{cos\theta}}{\frac{1}{sin\theta}} + \frac{4sin\theta}{cos\theta} =6tan\theta[/tex]
[tex]\frac{\frac{2}{cos\theta}}{\frac{1}{sin\theta}} + \frac{4sin\theta}{cos\theta} =6tan\theta[/tex]
Rewrite as:
[tex]\frac{2}{cos\theta}/\frac{1}{sin\theta} + \frac{4sin\theta}{cos\theta} =6tan\theta[/tex]
Solving (b): Simplify
[tex]\frac{2}{cos\theta}/\frac{1}{sin\theta} + \frac{4sin\theta}{cos\theta} =6tan\theta[/tex]
Change / to *
[tex]\frac{2}{cos\theta}*\frac{sin\theta}{1} + \frac{4sin\theta}{cos\theta} =6tan\theta[/tex]
[tex]\frac{2sin\theta}{cos\theta} + \frac{4sin\theta}{cos\theta} =6tan\theta[/tex]
Solving (c): The property used
To do this, we need to further simplify
[tex]\frac{2sin\theta}{cos\theta} + \frac{4sin\theta}{cos\theta} =6tan\theta[/tex]
Take LCM
[tex]\frac{2sin\theta+ 4sin\theta}{cos\theta} =6tan\theta[/tex]
Add the numerator
[tex]\frac{6sin\theta}{cos\theta} =6tan\theta[/tex]
Apply quotient identity
[tex]\frac{sin\theta}{cos\theta} = tan\theta[/tex]
This gives
[tex]\frac{6sin\theta}{cos\theta} = 6tan\theta[/tex]
Hence, the properties applied are:
Addition and Quotient identity
5(8-70) + 29 nt (n=4
Answer:
5 x 8 = 40
5 x -70 = -350
40 - 350
29 x 4 = 116t
therefore it would be 40 - 350 + 116t
I think
this is for all the linemen out there respect the gut (im a RT and DE)
Answer:
oh
Step-by-step explanation:
Which is a pair of dependent events?
Answer:
Two events are dependent if the outcome of the first event affects the outcome of the second event, so that the probability is changed.
Step-by-step explanation:
Answer:
A.
You get a head and a tail in two coin tosses with two different coins.
Step-by-step explanation:
I took the test and got it right!
Yo this looks so confusing to me can someone answer this oraganized or sum
Answer:
2 units
Step-by-step explanation:
The x-coordinates are
School = 2
House = 5
Count the units (lines) between the two x-coordinates
There are 2 units between them
Help out thankssssssssss !!!!!!
Answer:
x =20?
Step-by-step explanation:
I set them equal to each other
Answer:
it says the answer s t u v
In the class legal case of Whitus v. Georgia, a jury pool of 90 people was supposed to be randomly selected from a population in which 27% were minorities. Among the 90 people se- lected, 7 were minorities. The baseline hypothesis, or null, was that the jury selection process was random. The test hypothesis, or alternative, was the process was not random (suggesting bias).
Find the probability of getting 7 or fewer minorities in a world where the jury pool selection pro- cess was supposed to be random.
a. .35400000
b. .00000354
C..00000451
d. 00000000
Answer:
C..00000451
Step-by-step explanation:
For each person in the jury, there are only two possible outcomes. Either they were minorities, or they were not. The probability of a person being a minority is independent of any other person. This means that we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
And p is the probability of X happening.
Population in which 27% were minorities.
This means that [tex]p = 0.27[/tex]
90 people
This means that [tex]n = 90[/tex]
Find the probability of getting 7 or fewer minorities in a world where the jury pool selection pro- cess was supposed to be random.
This is
[tex]P(X \leq 7) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7)[/tex]
In which
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]P(X = 0) = C_{90,0}.(0.27)^{0}.(0.73)^{90} \approx 0[/tex]
[tex]P(X = 1) = C_{90,1}.(0.27)^{1}.(0.73)^{89} \approx 0[/tex]
[tex]P(X = 2) = C_{90,2}.(0.27)^{2}.(0.73)^{88} \approx 0[/tex]
[tex]P(X = 3) = C_{90,3}.(0.27)^{3}.(0.73)^{87} = \approx 0[/tex]
[tex]P(X = 4) = C_{90,4}.(0.27)^{4}.(0.73)^{86} = 0.00000002[/tex]
[tex]P(X = 5) = C_{90,5}.(0.27)^{5}.(0.73)^{85} = 0.00000015[/tex]
[tex]P(X = 6) = C_{90,6}.(0.27)^{6}.(0.73)^{84} = 0.00000080[/tex]
[tex]P(X = 7) = C_{90,7}.(0.27)^{7}.(0.73)^{83} = 0.00000354[/tex]
So
[tex]P(X \leq 7) = 0.00000002 + 0.00000015 + 0.00000080 + 0.00000354 = 0.00000451[/tex]
So the correct answer is given by option C.
siny dy/dx= cosy(1-xcosy)
pls i need it fast
Answer:
sec y = x+1 + ce x ; c is constant
Hope it helps....
What must the missing digit be so that the number rounds to 4 when rounding to the nearest whole number?
A. 5
B. 9
C. Any number greater than 5
D. The digit does not matter
Answer:
C. any number greater than 5
Step-by-step explanation:
when rounding numbers. 5 or more up the score. the number will be rounded to the next whole number
Answer:
Step-by-step explanation:
D the digit does not metter
PLEASE HELP!
Please help me I don’t understand how to do this and it has to be done by tonight!!!
Answer:
these are notes i wrote in geometry I'm not sure if this will help. it's been a few months since i did this
What is the equation of the horizontal asymptote?
A. y = 0
B. x = 0
C. y = x
D. x = 2
Answer:
horizontal asymptote at y = 0
Step-by-step explanation:
According to the definition of asymptotes, it is a line that the function gets closer and closer to as x goes to plus or minus infinity. The definition clearly does not mention anything about the finite value of x.
However, crossing of asymptotes does not happen in the case of vertical asymptotes because for a given x, the function has only one value but the same y can be obtained for different values of x.
It is a common misconception that graphs of functions can’t cross the asymptotes. This is true only for vertical asymptotes. In fact, there are several examples of functions whose graphs cross the horizontal asymptote. For example:
f(x) = (xe)^((-x)^2)
The horizontal asymptote of the above function is y=0 but it still crosses the x axis at x=0.
hope that helps, I really don't know thought. Quite tricky
WILL MARK! please help:)
Find x and y so that ABCD will be a parallelogram.
Answer:
The answer is the first one; x = 6 y =42
Help nnananannanannanananannannanansnnsnsnnsnsnsnsnnsns
Answer:
2
Step-by-step explanation:
The two x's end up being -4 and 6, so added together that's 2
In a survey of 140 undergraduate students in an elementary statistics class at UW, 12 said they were left-handed and 128 said they were right-handed. Assume the students are representative of all UW undergrads. Do these data provide evidence that the proportion of UW undergrads who are left-handed differs from the national proportion of 0.10 at the 5% significance level?
data: 12 out of 140, null probability 0.1 z = 0.563, p-value = 0.5731 alternative hypothesis: true p is not equal to 0.1 95 percent confidence interval: 0.04971124 0.14384532 sample estimates: P 0.08571429
a) Define the null and alternative hypothesis for answering the question being asked. Define both in words and in symbols.
b) The R output for running this test is shown below. What do you conclude for this test? Include your decision and an interpretation in the context of the problem. Be specific.
c) Explain in words what the p-value of 0.5731 means.
Answer:
a) The null hypothesis, H₀; p = 0.1
The alternative hypothesis, Hₐ; p ≠ 0.1
b) The proportion of left handed undergrads in UW differs from the national proportion of 0.1
c) The p-value is larger than the level of significance therefore there is statistical evidence supporting the alternative hypothesis
Step-by-step explanation:
The given data are;
The number of students in the sample, n = 140
The number of left handed students in the sample = 12
The number of right handed students in the sample = 128
The proportion of left handed students in the sample, [tex]\hat p[/tex] = 12/140 = 0.08571429
The significance level = 5%
The national proportion, p₀ = 0.1
a) The null hypothesis, H₀; p = 0.1
The null hypothesis is the proportion of left handed students in the UW is the same as the national proportion of 0.1
The alternative hypothesis, Hₐ; p ≠ 0.1
The alternative hypothesis is the proportion of left handed students in the UW is not the same as the national proportion of 0.1
b) Given from the output values of the Confidence Interval at 95% confidence level, (0.04971124, 0.14384532) which are both positive values, and the p-value of 0.5731, we conclude that there is a difference between the proportion of left-handed UW undergraduate students and the national proportion of 0.1
c) Given that the p-value of 0.5731 is larger than the significance level of 0.05, we reject the null hypothesis and there is significant statistical evidence to suggest that the proportion of UW undergrads who are left handed differs from the national proportion of 0.10
Which equations represent exponential growth functions? Select all that apply.
Question 6 options:
f(x)=(2.6)x
g(x)=(52)x
h(x)=(0.4)x
m(x)=(13)x
Pls help me guys!! :)
Answer:
what there is nothing, what can we help you
Answer:
I am ready to help you.ask question.
what is another way to show 2 x 4/6
Answer:
[tex]2 \frac{4}{6} [/tex]
I think this is it?? very sorry if it's incorrect
Answer:
4/3 or 1 1/3
Step-by-step explanation:
2 * 4/6
= 8/6 (You multiply 2 by the numerator, 4)
= 4/3 (Cancel out the common factor in the numerator and denominator, 2)
Mixed number form: 1 1/3
Geometry Need Help. I will give brainliest
Answer:
1 or 0.5
Step-by-step explanation:
What is the equation for the line of reflection?
x=6
y=6
y=x
y=2
Three landmarks of baseballachievement are Ty Cobb’s batting average of 0.420 in 1911,Ted Williams’s 0.406 in 1941, and George Brett’s 0.390in 1980. These batting averages cannot be compared directly becausethe distribution of major league batting averages has changed overthe years. The distributions are quite symmetric and (except foroutliers such as Cobb, Williams, and Brett) reasonably normal.While the mean batting average has been held roughly constant byrule changes and the balance between hitting and pitching, thestandard deviation has dropped over time. Here are the facts:
Decade
Mean
Standard Deviation
1910s
0.266
0.0371
1940s
0.267
0.0326
1970s
0.261
0.0317
Compute the standard units for the batting averages of Cobb,Williams, and Brett to compare how far each stood above his peers.Who is the better player of the three?
Answer:
Ted Williams has the highest standardized score, hence Williams is the best of the three
Cobb is the second highest and hence, the better player
George Brett is third
Step-by-step explanation:
Given the data:
Decade : 1910 __ 1940 ____ 1970
Mean, μ: 0.266 __0.267 ___ 0.261
S/dev, σ : 0.0371 _ 0.0326 __ 0.0317
To compute the standard unit for batting averages, we obtain the standardized score for each of Cobb,Williams, and Brett.
Standardized score (Zscore) : (x - μ) / σ
Cobb, x = 0.420
Ted Williams, x = 0.406
George Brett, x = 0.390
COBB:
Zscore = (0.420 - 0.266) / 0.0371 = 4.1509
Ted Williams :
Zscore = (0.406 - 0.267) / 0.0326 = 4.2638
George, Brett = (0.390 - 0.261) / 0.0317 = 4.0694
Ted Williams has the highest standardized score, hence Williams is the best of the three
Cobb is the second highest and hence, the better player
George Brett is third
the sum of -6 times a number x and 9 is at least 27. what are the possible values of the number
8. Determine the area of a sector
with a central angle of 42° in a
circle with radius 3 inches.
NEED IT ASAP
Answer:
[tex]\boxed {\boxed {\sf A \approx 3.3 \ in^2}}[/tex]
Step-by-step explanation:
Since we are given the central angle in degrees, we should use the following formula for sector area.
[tex]A= \frac {\theta}{360}* \pi r^2[/tex]
The angle is 42 degrees and the radius is 3 inches. Therefore,
[tex]\theta= 42 \\r=3 \ in[/tex]
[tex]A=\frac {42}{360} * \pi (3 \ in)^2[/tex]
Solve the exponent.
(3 in)²= 3 in*3in = 9 in²[tex]A=\frac {42}{360} * \pi (9 \ in^2)[/tex]
Multiply all three numbers together.
[tex]A= 0.116666666667* 3.14159265359 * 9 \ in^2[/tex]
[tex]A=3.29867228627 \ in^2[/tex]
Let's round to the tenth place. The 9 in the hundredth place tells us to round the 2 up to a 3.
[tex]A \approx 3.3 \ in^2[/tex]
The area of the sector is approximately 3.3 square inches.
Find the equation of a line parallel to y - 5 = 6x – 10 that passes through the
point (4,10). (answer in slope-intercept form)
Answer:
y=6x-14
Step-by-step explanation:
y=mx+b
m=slope
b=y-intercept
add 5 on both sides to make y on the left side and the other part on the right side.
y=6x-5
IMPORTANT: Parallel lines have the same slope
if the line passes through the point (4,10) we can substitute values for x and y into y=mx+b
10=4m+b
Now since we know that this line is parallel to y=6x-5 they have the same slope which means m is 6
10=4(6)+b
now solve for b
-14=b
so we know that m is 6 and b =14 now we substitute it back into y=mx+b for m and b
y=6x-14
Hope that helps :)
Today only a table is being sold at a 15% discount. The sale price is $629
Answer:
740
Step-by-step explanation:
Answer:
The answer is $566.73.
Step-by-step explanation:
The way that you find the answer is dividing .15 to the price
A right prism has height 8 and triangular bases with sides of length 7, 8, and 9. What is the: Total surface area of the prism?
Answer:
the total surface area of the prism is 245.67
Step-by-step explanation:
Given;
height of the triangular prism, h = 8
length of the triangular bases, = 7, 8, and 9
The total surface area of the prism is calculated as;
T.S.A = ph + 2B
Where;
p is the perimeter of the base
B is area of the base
P = 7 + 8 + 9 = 24
Area of the base can be calculated using Hero's formula;
[tex]S = \frac{7+8+9}{2} = 12\\\\Base \ area (B) = \sqrt{12(12-7)(12-8)(12-9)} = 26.833[/tex]
T.S.A = (24 x 8) + 2 x 26.833
T.S.A = 192 + 53.666
T.S.A = 245.67
Therefore, the total surface area of the prism is 245.67
If a video game cost $60 and it's on sale for 10% off, how much is the discount?
Answer:
$6
Step-by-step explanation:
Percentages have a cool little trick where they can be reversed :) 10% of 60 is a little tough, but we can switch it to 60% of 10, which is much easier. 60% of 10 is 6, so the discount is $6