Answer:
$40.95
Step-by-step explanation:
Original price = $65.00
If the jacket is on sale for 40% off, then it is now 60% of the original price.
60% = 60/100 = 0.6
⇒ 60% of $65.00 = 0.6 × 65
= $39
If we have to pay 5% sales tax, then this means that the final price will be 105% of the sale price.
105% = 105/100 = 1.05
⇒ 105% of $39 = 1.05 × 39
= $40.95
Discount:-
[tex]\\ \rm\rightarrowtail 0.40(65)=26\$[/tex]
Now
Price after discount=65-26=39$So
Sales tax is 5%
Total price=39+0.05(39)=40.95$
PLEASE HELP
Can kept track of the number of hours that he spent at the pool each week for several weeks. He spent 8, 2, 7, 4, and 4 hours. What is the median number of hours that Van spent at the pool each week?
A. 6 hours
B. 25 hours
C. 4 hours
D. 5 hours
Answer: 4 Hours
Step-by-step explanation:
r + 11 + 8r= 29
Show answer
Answer:
r=2
Step-by-step explanation:
r + 8 r + 11 = 29
( 1 + 8 ) r + 11 = 29 9 r + 11 = 29
Now we can isolate and solve for r while always keeping the equation balanced: First, subtract 11 from each side of the equation:
9 r + 11 − 11 = 29 − 11
9 r + 0 = 18
9 r = 18
Now we can divide each side of the equation by 9 to get
r : 9 over 9 = 18 under 9
1 r = 2
r = 2
Answer: r = 2
Steps:
r + 8r + 11 = 29
9r + 11 = 29
9r + 11 - 11 = 29 - 11
9r = 18
r = 2
plz mark brainliest
one of the pages help my lil cousin out
Answer:(that was a joke)
1.) acute
2.) right
3.) obtuse
4.) acute
5.) obtuse
6.) right
Step-by-step explanation:
if hes doing advanced stuff like isosceles equilateral and that then im sorry for the answer.
if x=13 what is 5x - 2 =
Answer:
63
Step-by-step explanation:
5(13)-2 is 65-2 or 63.
Help! no links please!! a triangular prism has a base that is 12 cm. its height is 15 cm. what is its volume?
A. 60 cm3
B. 700 cm3
C. 300 cm3
D. 30 cm3
st
2. Find the surface area of the sphere below.
.
3.1 m
-
Answer:
120.7016
Step-by-step explanation:
surface area of sphere=4πr²
solution
=4*3.14*3.1*3.1
=120.7016
Is the number 6+1 rational or irrational?
Answer:
Rational
Step-by-step explanation:
An irrational number is any number that cannot be turned into a fraction. 7 can be turned into a fraction.
Which of the following shows the graph of Y = 2 In x?
Please I need the answer
Hope this helps~! Brainliest is 'preciated if it does!
Please help! Thank you
Answer:
B. -3
Step-by-step explanation:
From (-1,4) it goes down 3 (rise) units then 1 unit (run) to the right. Simply, its sloping to the left, so negative.
Solving using slope formula:
y2-y1/x2-x1
4--2/ -1-1
6/-2
3/-1
-3
Answer: B
Step-by-step explanation:
y2-y1/x2-x1
-2-4/1-(-1)
-6/1+1
-6/2
-3
Which sentence about the division of two fractions is true? A. If the dividend is greater than the divisor, the quotient will be greater than 1. B.If the dividend is less than the divisor, the quotient will be greater than 1 C. If the dividend is equal to the divisor, the quotient will be less than 1 D. If the dividend is greater than the divisor, the quotient will be less than 1.
Answer:
A. If the dividend is greater than the divisor, the quotient will be greater than 1.
Step-by-step explanation:
Checking all options
A. If the dividend is greater than the divisor, the quotient will be greater than 1.
That is,
4 ÷ 3 = 1.33
Where,
4 is the dividend
3 is the divisor
1.33 is the quotient
THIS IS TRUE
B.If the dividend is less than the divisor, the quotient will be greater than 1
That is,
3 ÷ 4 = 0.75
Where,
3 is the dividend
4 is the divisor
0.75 is the quotient
NOT TRUE
C. If the dividend is equal to the divisor, the quotient will be less than 1
That is,
3 ÷ 3 = 1
Where,
3 is the dividend
3 is the divisor
1 is the quotient
NOT TRUE
D. If the dividend is greater than the divisor, the quotient will be less than 1.
That is,
4 ÷ 3 = 1.33
Where,
4 is the dividend
3 is the divisor
1.33 is the quotient
NOT TRUE
Therefore, option A is TRUE
Let p(x) be a polynomial of degree 4 having extremum at x = 1 ,2 and
[tex]\displaystyle\sf \lim_{x\to 0}\left( 1+\dfrac{p(x)}{x^2}\right) = 2 [/tex]
Then the value of p(2) is ?
PLEASE CHECK THE ATTACHED FILE
We are given that ;
[tex]{\quad \longrightarrow \displaystyle \sf \lim_{x\to 0}\bigg\{1+\dfrac{p(x)}{x^2}\bigg\}=2}[/tex]
Where p(x) is a polynomial of degree 4 , it will help us later, but let's do some manipulations first ;
Can be further written as ;
[tex]{:\implies \quad \displaystyle \sf 1+\lim_{x\to 0}\bigg\{\dfrac{p(x)}{x^2}\bigg\}=2}[/tex]
[tex]{:\implies \quad \displaystyle \sf \lim_{x\to 0}\bigg\{\dfrac{p(x)}{x^2}\bigg\}=1}[/tex]
So, here p(x) is polynomial of degree 4, so it will be a biquadratic polynomial, so we will write p(x) in the form of general biquadratic polynomial, so p(x) = ax⁴ + bx³ + cx² + dx + e
Now, first find p(x)/x² ;
[tex]{:\implies \quad \sf \dfrac{p(x)}{x^2}=\dfrac{ax^{4}+bx^{3}+cx^{2}+dx+e}{x^2}}[/tex]
[tex]{:\implies \quad \sf \dfrac{p(x)}{x^2}=ax^{2}+bx+c+\dfrac{d}{x}+\dfrac{e}{x^2}}[/tex]
So now, as [tex]{\bf{x\to 0}}[/tex] , for any values of a, b, c, d and e, the RHS will approach ∞ iff d ≠ e ≠ 0, as the denominator of d and e will be approaching 0 and so the whole limit will be ∞ , but we want the limit to be approaching 1, so when if d = e = 0, the denominator of d and e will be approaching 0 (not absolutely 0), and if d = e = 0, we will have the limit be approaching ax²+ bx + c for x approaching 0 being the limit 1 , and for any values of a, b and c . So now we have ;
[tex]{:\implies \quad \displaystyle \bf \lim_{x\to 0}\dfrac{p(x)}{x^{2}}=\begin{cases}\bf \infty \:, iff\: d\neq e\neq 0 \\ \\ \bf 1\:, iff\: d=e=0\end{cases}}[/tex]
So, now we had to consider the second case, for which the limit is approaching 1, for d = e = 0, so the limand here will just be ax² + bx + c
Now, we so have ;
[tex]{:\implies \quad \displaystyle \sf \lim_{x\to 0}ax^{2}+bx+c=1}[/tex]
Putting the limit we will have ;
[tex]{:\implies \quad \sf c=1}[/tex]
So, now as p(x) have extremum at 1 and 2, so p'(x) = 0, for x = 1, 2 , so now finding p'(x)
[tex]{:\implies \quad \sf p(x)=ax^{4}+bx^{3}+x^{2}\quad \qquad \{\because c=1\: and\: d=e=0\}}[/tex]
So, differentiating both sides wr.t.x ;
[tex]{:\implies \quad \sf p^{\prime}(x)=4ax^{3}+3bx^{2}+2x}[/tex]
Now, p'(1) and p'(2) must be 0
[tex]{:\implies \quad \sf p^{\prime}(1)=4a+3b+2=0}[/tex]
[tex]{:\implies \quad \sf p^{\prime}(2)=32a+12b+4=0}[/tex]
So, now we have ;
[tex]{\quad \longrightarrow \displaystyle \begin{cases}\bf 4a+3b=-2 \\ \\ \bf 32a+12b=-4\end{cases}}[/tex]
On multiplying first equation by 8 on both sides we can thus obtain ;
[tex]{\quad \longrightarrow \displaystyle \begin{cases}\bf 32a+24b=-16 \\ \\ \bf 32a+12b=-4\end{cases}}[/tex]
On solving both the equations we will be having ;
[tex]{\quad \longrightarrow \displaystyle \begin{cases}\bf a=\dfrac{1}{4} \\ \\ \bf b=-1\end{cases}}[/tex]
So , now as d = e = 0, c = 1, a = (1/4), b = -1, so putting all the values in p(x) we can obtain p(x) as ;
[tex]{:\implies \quad \sf p(x)=\dfrac{1}{4}(x)^{4}-(x)^{3}+x^{2}}[/tex]
Now, at x = 2 ;
[tex]{:\implies \quad \sf p(2)=\dfrac{1}{4}(2)^{4}-(2)^{3}+2^{2}}[/tex]
[tex]{:\implies \quad \sf p(2)=4-8+4=8-8}[/tex]
[tex]{:\implies \quad \bf \therefore \quad \underline{\underline{p(2)=0}}}[/tex]
This is the required answer
(a+7)2
please expand it
Use a net to find the surface area of the right triangular prism
35 sq. ft.
80 sq. ft.
84 sq. ft.
244 sq. ft
256 sq. ft.
258 sq. ft.
270 sq. ft.
286 sq. ft.
5,040 sq. ft.
Answer:
244 sq. ft.
Step-by-step explanation:
The net for a triangular prism consists of a central rectangle and two triangles. The length of the central rectangle is equal to the perimeter of the triangular faces.
__
The area of the central rectangle of the net is ...
A = LW = (12 +7 +10 ft)(6 ft) = 174 ft²
The two triangles are right triangles, so the area of each is half the product of the leg lengths.
A = 1/2(bh) = 1/2(10 ft)(7 ft) = 35 ft²
Then the sum of the rectangle and two triangles is ...
surface area = 174 ft² +2 × 35 ft² = 244 ft²
The science club is planning a field trip to a museum. Each student will pay $10 for admission and an equal share of the $200 transportation cost. The total cost per student is given by the expression LaTeX: C=\frac{200}{S}+10C = 200 S + 10, where LaTeX: SS is the number of students that went on the field trip. What does the term LaTeX: \frac{200}{S}200 S in the expression represent?
Answer: [tex]\dfrac{200}{S}[/tex] represents the transport cost per student in the expression.
Step-by-step explanation:
Given: For trip,
Admission fee per student = $10
Transport cost (for all students0 = $200
Here, S represents the number of students went on the field trip.
Transport cost per student = (Total cost) ÷ Total student
So, [tex]\dfrac{200}{S}[/tex] represents the transport cost per student.
Hence, [tex]\dfrac{200}{S}[/tex] represents the transport cost per student in the expression.
Find the common difference of the arithmetic sequence.
4, 10, 16, 22, . . .
Answer:
The answer is 6
Step-by-step explanation:
This is due to the nth term sequence going up by 6
-x + 3 = 7
X=-4
X= 7
X= 4
X = -7
Answer:
x = -4
Step-by-step explanation:
Step 1: Write equation
-x + 3 = 7
Step 2: Solve for x
Subtract 3 on both sides: -x = 4Divide both sides by -1: x = -4Step 3: Check
Plug in x to verify it's a solution.
-(-4) + 3 = 7
4 + 3 = 7
7 = 7
Please help!!!!!!!!!
Help complete the square in picture please 20 points
Answer:
x = 3 +√43, x = 3 - √43
Step-by-step explanation:
x^2 - 6x - 34 = 0
move the 34 across
x^2 - 6x = 34
take -6 and divide by two, then square it
(-6/2)^2 = 9
add the product to your equation
x^2 - 6 + 9 = 34 + 9
solve
(x - 3)^2 = 43
x - 3 = ± √43
x = 3 ± √43
Please helpppp
Prove (1-cosA)(1+CosA)(1+cot^2A)=1
Answer:
= 1= RHS
Step-by-step explanation:
shee i got u bud ok LHS-
(1+cot^2A)(1+cosA)(1-cosA)
=Cosec^2A(1-cos^2A)
=1/sin^2A×(sin^2A)
= 1= RHS
A truck costs $80,000. It depreciates in value $6,000 per year. Write a linear model in the form v(t)=mt + b where v(t) represents the current value of the truck after t years of ownership.
The required expression is v(t) = 80,000 - $6000t
Cost of the truck = $80,000
Depreciation rate = $6000/year
What is cost price?
Cost price is that price for buyer which he pays to seller for an object or product.
Required expression-
m = $6000
t = time in years
b = original price
v(t) = mt + b
v(t) = -$6000t + $80000
negative sign for depreciation
Thus, the required expression is v(t) = 80,000 - $6000t
Learn more about cost price here:
https://brainly.com/question/11027396
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Is this correct?
I have a test tomorrow tell the answer quickly
Answer:
No, it is not correct. You should divide by 21 and 3.
Step-by-step explanation:
3x=21
x=7
Q 1)
3(x + 5) = 36
3x + 15 = 36
3x = 36 - 15
3x = 21
x = 21/3
x = 7
Verification:
3(x + 5) = 36
3(7 + 5) = 36
3(12) = 36
36 = 36
Hence proved that x = 7
What is the slope of the line y
= -4?
Answer:
The slope is 0 or there is no slope.
Step-by-step explanation:
Only a y-intercept of -4.
Answer:
0
Step-by-step explanation:
The slope is defined as rise/run. Since y does not increase at all as x increases, the slope is 0.
Approximately 9% of men have a type of color blindness that prevents them from distinguishing between red and green. suppose that 8 men are selected at random. what is the probability that at least one of them will have this type of red-green color blindness
HELP ASAP LOOK AT PICTURE
Answer:
A XD (um i dont know what else to put sof frpijfpoemd-eod)
A mother shared a sum of money amongst his three sons Jorge, Luis and Robert in the ratio of 3:5:4 respectively. If Robert received $320. How much was the total money shared?
she cut the sum in (3+5+4) in 12 parts
J had 3/12 of the sum S
L had 5/12 of the sum S
and R had 4/12 of the sum S
4/12 x S = 320
S = 320 x 12/4
S = 960
$960 shared
how to find the marked price of an article
Answer:
I don't really know what you mean so I would say to just look on the tag but if you gave more info then I could help you out
I need help figuring this out and how to do it
Answer:
5) y=2x^2+16x+32
Step-by-step explanation:
So the following equations on your paper are in vertex form. We want to turn these into standard form.
Remember, standard form is ax^2+bx+c and vertex form is y=a(x-h)^2+k
Lets expand our first problem, y=2(x+4)^2
y=2(x+4)(x+4)
y=2(x^2+8x+16)
y=2x^2+16x+32
Our answer for question 5 is y=2x^2+16x+32
If you need help with the other questions just add a comment.
Answer:
#5
y = 2(x + 4)^2 y = 2((x + 4)(x + 4))y = 2(x(x + 4) + 4(x + 4))y = 2(x^2 + 4x + 4x + 16) y = 2(x^2 + 8x + 16) y = 2x^2 + 16x + 32#6
y = -2(x + 2)^2 y = -2((x + 2)(x + 2)) y = -2(x(x + 2) + 2(x + 2)) y = -2(x^2 + 2x + 2x + 4) y = -2(x^2 + 4x + 4) y = -2x^2 - 8x - 8#7
y = -(x + 7)^2 y = -((x + 7)(x + 7)) y = -(x(x + 7) + 7(x + 7))y = -(x^2 + 7x + 7x + 49) y = -(x^2 + 14x + 49) y = -x^2 - 14x - 49#8
y = (x - 5)^2 + 9 y = (x - 5)(x - 5) + 9 y = x(x - 5) + (-5)(x - 5) + 9 y = x^2 - 5x - 5x + 25 + 9 y = x^2 - 10x + 25 + 9 y = x^2 - 10x + 36How many arrangements of the cabbages keep repeated words together.
It is 5,760.
Stay safe & humble <3
What cup should Jacob pick
volume of cylinder = 3.14×1.5×1.5×4
1.34×2.25×4=
1.34×9=
12.06 in³
volume of cone =1/3×3.14×2×2×6
1/3×3.14×4×6
1/3×3.14×24
3.14×8
=25.12 in³
therefore he need to buy the cone shaped cup
how do i factor n2 - n - 56
[tex] {n}^{2} - n - 56 = [/tex]
[tex](n - 8)(n + 7)[/tex]
_____________________________________________
[tex]a {x}^{2} + bx + c = 0[/tex]
[tex]delta = {b}^{2} - 4ac[/tex]
[tex]x(1) = \frac{ - b + \sqrt{delta} }{2a} \\ [/tex]
[tex]x(2) = \frac{ - b - \sqrt{delta} }{2a} \\ [/tex]
_____________________________________________
[tex] {n}^{2} - n - 56 = 0[/tex]
[tex]delta = ({ - 1})^{2} - 4(1)( - 56)[/tex]
[tex]delta = 1 + 224[/tex]
[tex]delta = 225[/tex]
Thus ;
[tex]n(1) = \frac{ - ( -1) + \sqrt{225} }{2 \times 1} \\ [/tex]
[tex]n(1) = \frac{1 + 15}{2} \\ [/tex]
[tex]n(1) = \frac{16}{2} \\ [/tex]
[tex]n(1) = 8[/tex]
And[tex]n(2) = \frac{ - ( - 1) - \sqrt{225} }{2 \times 1} \\ [/tex]
[tex]n(2) = \frac{ 1 - 15}{2} \\ [/tex]
[tex]n(2) = - \frac{14}{2} \\ [/tex]
[tex]n(2) = - 7[/tex]
So[tex]n(1) = 8[/tex]
[tex]n(1) - 8 = 0 \: \: \: (\alpha )[/tex]
[tex]n - 8 = 0 \: \: \: \: ( \alpha )[/tex]And[tex]n(2) = - 7[/tex]
[tex]n(2) + 7 = 0 \: \: \: \: \: ( \beta )[/tex]
[tex]n + 7 = 0 \: \: \: \: ( \beta )[/tex]_____________________________________________
[tex] \alpha \times \beta = [/tex]
[tex](n - 8)(n + 7)[/tex]