The acceleration due to gravity near the surface of the hypothetical planet is 9.79 m/s^2, which is the same as the acceleration due to gravity near the surface of the Earth.
The acceleration due to gravity near the surface of a planet is given by the formula:
g = G * M / R^2
where G is the gravitational constant (6.67 x 10^-11 Nm^2/kg^2), M is the mass of the planet, and R is the radius of the planet.
Since the mass of the hypothetical planet is the same as the Earth, we can use the mass of the Earth for M. The radius of the hypothetical planet is 1.98 times the radius of the Earth, so we can use the following for R:
R = 1.98 * 6380 km = 12618.4 km
We can now substitute these values into the formula for g:
g = 6.67 x 10^-11 Nm^2/kg^2 * 5.98 x 10^24 kg / (12618.4 x 10^3 m)^2
Simplifying this expression gives us:
g = 9.79 m/s^2
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to remove the cannula at the end of a laparoscopy, the surgeon pulls on the cannula with increasing force. how does the frictional force vary with the applied pulling force before and after the cannula begins to slide?
When the pulling force is first applied, the cannula doesn't move because of the static friction. After a while, at a certain amount of applied force, friction increases until the limit reached its threshold for the motion.
Friction is the force that resists the sliding motion between two surfaces. It can be kinetic or static. Static friction happens when the two surfaces don't slide because the amount of static friction fully counteracts an applied force. It happens until the upper limit is reached, which will happen when one applied enough amount of force to the surface. Once the upper limit is reached, the surfaces will start to slide against each other, in which the static friction becomes kinetic friction.
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A 1250 kg car traveling at a speed of 25.0 m/s rounds a 175 m radius curve.
Assuming the road is level, determine the coefficient of static friction between the car’s tires and the road.
Assuming that the curve is banked and the road is frictionless, determine the bank angle with respect to the horizontal.
The tire's static friction coefficient with the ground is 0.3.
What is static friction?
Static friction is a force that maintains an object at rest. Static friction is defined as the resistance one encounters when attempting to move a stationary object across a surface without actually moving their body or the surface, they are moving the object across.
Give a static friction illustration.
Static friction has an impact on an object when it is resting on a surface. For instance, when hiking through the woods, there is static friction created between your shoes and the ground with each step you take.
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A train travels a distance of 300 miles in 6 hours. What is the train's average speed?.
Answer:
50 mph
Explanation:
The average speed of an object can be calculated by dividing the total distance traveled by the total time taken.
Average speed = distance traveled / time taken
Average speed = 300 miles / 6 hours = 50 mph
A bullet shot underwater will experience "viscous drag" and follow this velocity equation: v_x(t) = v_ie^-bt where v_i = 365 m/s and b = 0.42 s^-1. The bullet has an initial position x_i = 85.1 m at t_i = 0 s. What is the location of the bullet at time t = 0.87 seconds? What is the maximum position of the bullet (if you wait a long time, what will its position be)? What is the x component of the acceleration of the bullet 0.5 seconds after the bullet is fired?
The derivative of the velocity equation, a x(t), gives the x component of the bullet's acceleration 0.5 seconds after it is fired: a x(t) = -b * v x(t) = -b * v i * e-bt = -0.42 * 365 * e-0.5 * 0.42 m/s2.
The bullet is located at x(0.87) = x i + v i * (1 - e-bt) = 85.1 + 365 * (1 - e-0.87 * 0.42) m at time t = 0.87 seconds.
The bullet's maximum location is reached when the velocity equals zero, which happens when v x(t) = 0. We obtain t = -ln(v i/v x) / b after solving for t. When the numbers are substituted, the result is t = -ln(365/0)/0.42, which is undefined because the denominator is zero.
The derivative of the velocity equation, a x(t), gives the x component of the bullet's acceleration 0.5 seconds after it is fired: a x(t) = -b * v x(t) = -b * v i * e-bt = -0.42 * 365 * e-0.5 * 0.42 m/s2.
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Any line, segment, or ray that passes through the midpoint of a segment and is perpendicular to that segment is a()_
For a line segment, the line that passes through its midpoint and also perpendicular to it is called its perpendicular bisector.
What do you mean by perpendicular bisector ?A line that divides another line segment into two equal halves by intersecting it perpendicularly is known as a perpendicular bisector. A rule, compass, and pencil can be used to draw a perpendicular bisector.
When two lines cross at right angles or 90 degrees, they are said to be perpendicular to one another. A line that splits a line into two equally sized parts is known as a bisector. A line segment's perpendicular bisector suggests that it meets the segment at a 90-degree angle and splits it into two equal halves.
Therefore, For a line segment, the line that passes through its midpoint and also perpendicular to it is called its perpendicular bisector.
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Rigid bar ACB is supported by an elastic circular strut DC having an outer diameter of 15 in. And inner diameter of 14. 4 in. The strut is made of steel with a modulus elasticity of ksi. Point load kips is applied at B. Calculate the change in length of the circular strut DC. What is the vertical displacement of the rigid bar at point B?
The change in length of the circular strut DC = 0.00018 in.
The vertical displacement of the rigid bar at point B = 0.00009 in.
The change in length of the circular strut can be calculated as follows:
[tex]\triangle L = \frac{P * L}{(\pi * R^2 * E)}[/tex] where L is the length of the strut (approximated as the height difference between points C and D), R is the average radius of the strut (14.7 in), and E is the modulus of elasticity of steel (29,000 ksi).
[tex]\triangle L = 5 * \sqrt{2} * (15/2) / (\pi * (14.7^2) * 29000)[/tex]
= 0.00018 in
The vertical displacement of the rigid bar at point B can be calculated as follows:
Δy = ΔL / 2
Δy = 0.00018 / 2 = 0.00009 in
So, the change in length of the circular strut DC is 0.00018 inches and the vertical displacement of the rigid bar at point B is 0.00009 inches.
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The complete question is:
Rigid bar ACB is supported by an elastic circular strut DC having an outer diameter of 15in. and inner diameter of 14.4in. The strut is made of steel with a modulus elasticity of E = 29,000 ksi. Point load P = 5kips is applied at B. Calculate the change in length of the circular strut DC. What is the vertical displacement of the rigid bar at point B?
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if a solution appears red, approximately what wavelength of light is it absorbing?
A solution that appears red is absorbing light between 400 and 700 nm in wavelength.
Photons with various wavelengths make up the electromagnetic spectrum (EM) spectrum. In a narrow region of the electromagnetic spectrum, photons, which are unusual in that they exhibit both wave-like and particle-like properties, produce visible light and colors.
The wavelengths of this portion of visible light are roughly in the 400–700 nm range (one nm is equal to 10-9 meters). When all the wavelengths are present, it appears as white light. Each particular wavelength is associated with a different color.
Because all light travels at the same speed, the relationship between a wave's wavelength and frequency is inverse: as one value increases, the other value decreases.
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a 40 n box is pulled up ramp at a constant speed. the ramp makes and angle of 37° to the horizontal. when the box has traveled 5 m, how much work will have been done by gravity?
Work will have been done by gravity is Ws=159.72 J
Given:
• The fore exerting on box is F=40 N.
• The distance covered by box is d=5 m.
• The angle to the horizontal is 0 = 37°.
The expression of work done by the gravity is given by,
WS=Fdcostheta
Substitute the values in the above expression.
Ws=(40 N) x (5 m) x cos37"
Ws=159.72 J
The product of a force's component acting in the displacement's direction and its magnitude is known as the work done by the force.
When an object is moved over a distance by an external force, at least a portion of that force must be applied in the direction of the displacement. This is known as work in physics.
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if electrons are accelerated from rest in an electron gun by sending them through a potential difference of 11.0 kv, what is the resulting kinetic energy of each electron?
The resulting kinetic energy of each electron would be equal to 11 keV.
The kinetic energy (KE) of a moving object can be calculated using the equation KE = 1/2 mv^2, where m is the mass of the object and v is its velocity. When electrons are accelerated by a potential difference, they gain kinetic energy due to their increased velocity.
In an electron gun, electrons are accelerated by a potential difference of 11.0 kV, which means that 11,000 volts of electrical energy are used to give the electrons kinetic energy. The resulting kinetic energy of each electron can be calculated using the equation KE = qV, where q is the charge of the electron and V is the potential difference.
The charge of an electron is -1.60 x 10^-19 C, so the kinetic energy of each electron can be calculated as follows:
KE = qV = (-1.60 x 10^-19 C) * (11,000 V) = -1.76 x 10^-14 J = -1.76 x 10^-14 / 1.60 x 10^-19 = -11 eV, or -11 electron volts.
So, the resulting kinetic energy of each electron would be equal to 11 electron volts, or 11 keV.
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which of the following best describes the type of heat transfer that occurs in the external cooler of the hampson-linde cycle apparatus? a. conduction occurs as dry ice loses heat to the coil of the external cooler. b. convection occurs as the coil of the external cooler loses heat to dry ice. c. conduction occurs as the coil of the external cooler gains heat from nitrogen gas. d. convection occurs as nitrogen gas gains heat from the coil of the external cooler.
"Convection occurs as nitrogen gas gains heat from the coil of the external cooler," best describes heat transfer in the Hampson-Linde cycle external cooler. Thus, Option D holds the truth.
In the Hampson-Linde cycle, the external cooler operates by exchanging heat between the refrigerant (nitrogen gas) and the cooling medium (dry ice). The nitrogen gas circulates through the coil of the external cooler and loses heat to the cooling medium through the process of convection. Convection is the transfer of heat by the movement of fluids (in this case, nitrogen gas).
As the nitrogen gas moves through the coil, it comes into contact with the colder dry ice and loses heat, causing it to cool. The cooled nitrogen gas then returns to the rest of the cycle to be recompressed and cooled again.
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When 100hz oscillator is used to generate a sinusoidal wave on a string, the wavelength is 10cm. When tension of string is doubled the generator produces what frequency and wavelength? Please show work and explain
A new frequency of 200 Hz will be generated by the generator when the string's tension is doubled. The wavelength is 0.2 m.
Given:
Frequency, f = 100 Hz
Wavelength, 10 cm
From the wave equation for a string:
v = f × λ
v = (100 Hz) × (10 cm)
v = (100 Hz) × (0.10 m) = 10 m/s
When the tension is doubled, the new frequency is:
f' = 2 × 100 Hz
f' = 200 Hz
The new wavelength is:
2 × 0.1 = 0.2 m
Hence, the frequency is 200 Hz.
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standard blueprint plans and elevations are generally drawn in is______projection.
Standard blueprint plans and elevations are generally drawn in orthographic projection.
Orthographic projection is a way of creating 2D representations of 3D objects by projecting their lines and shapes onto a flat surface. In this type of projection, parallel lines in the object remain parallel in the projection and perpendicular lines appear as perpendicular. It is used in engineering, technical drawings, and computer graphics as it provides a clear and accurate representation of the object. The final image is a combination of multiple views taken from different angles, which can be combined to create a 3D representation of the object. Orthographic projections are essential for visualizing and understanding the shape and form of objects, especially in the design and construction industries.
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A particle leaves the origin with an initial velocity=(3.76i)m/s and a constant acceleration =(-1.43i-2.69j) m/s^2. When the particle reaches its maximum x coordinate, what are (a) its velocity, (b) its position vector
When the particle reaches its maximum x - coordinate then its velocity is (- 0.43j) m/s. and its position of the vector is (9.26, - 5.67) m.
Let's assume that the time at which the particle arrives at its most extreme x coordinate is t.
(a) At that point "t", the velocity of the particle is given that:
v = v0 + at = (3.76i) m/s + (- 1.43i - 2.69j) [tex]m/s^2[/tex] * t
Since the particle arrives at its greatest x coordinate right now, its velocity in the x direction will be 0 m/s.
Thus, we have:
0 = 3.76i - 1.43t I
By solving t, we find:
t = 3.76/1.43
Substituting the value of t into the expression for velocity, we'll get:
v = (3.76i) m/s + (- 1.43i - 2.69j) m/s^2 * (3.76/1.43) = (- 0.43j) m/s
Thus, the velocity of the particle at the time it arrives at its maximum x coordinate is (- 0.43j) m/s.
(b) The position of the particle is given:
r = r0 + v0t + (1/2)at^2
Substituting in the values for r0 (origin), v0, a, and t, we find:
r = (0,0) + (3.76i) m/s * (3.76/1.43) + (1/2)(- 1.43i - 2.69j) [tex]m/s^2[/tex] * (([tex]3.76/1.43)^2[/tex]))
r = (9.26, - 5.67) m
Thus, the position of the particle when it arrives at its greatest x coordinate is (9.26, - 5.67) m.
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Can you show me how to do this
Answer: C. 12
Weight= mass* gravity. Were going to have to do the inverse operation
Mass= weight/gravity^2. So were going to divide.
120/9.81 = 12.2324159021 or 12.
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the position of the particle as a function of time is given by x(t) = e-(t - 3)2, where x is in meters and t is in seconds. what is the velocity of the particle, in meters per second, at t = 2.9 s?
For a particle having a position of function e^-(t - 3)², the velocity at 2.9 s is calculated to be 0.198008 m/s.
The position of a particle is denoted by a function x(t) = e^-(t - 3)², where x is the distance and t is the time.
Differentiate the function, to find velocity.
v(x) = d/dt(x) = d/dt[e^-(t - 3)²]
v(x) = e^-(t - 3)²[-2(t - 3)]
Now, substitute the value of t = 2.9 in the equation
v(2.9) = e^-(2.9 - 3)²[-2(2.9 - 3)]
v(2.9) = e^-(-0.1)²[-2(-0.1)]
Use the exponent formula a^-b = 1/a^b
v(2.9) = 1/e^(-0.1)²[0.2]
v(2.9) = 1/e^(0.01)[0.2]
Substitute the value of e^0.01 = 1.01005
v(2.9) = (1/1.01005)[0.2]
Use the arithmetic operation of division,
v(2.9) = (0.99004)[0.2]
v(2.9) = 0.198008
Therefore, the velocity of the particle is 0.198008 m/s.
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the test charge is launched from point x with an initial speed v0 and is observed to pass through point y. is the speed of the test charge at point y greater than, less than, or equal to v0? explain your reasoning.
It is impossible to determine the speed of the test charge at point y based solely on the information provided. The speed of the charge at point y could be greater than, less than, or equal to v0 depending on various factors such as the presence of electric or magnetic fields, resistance, or other forces that may have acted on the charge between points x and y. A detailed analysis of the situation taking into account all relevant factors would be required to determine the speed of the charge at point y.
About Speed ChargeSpeed Charge is a derived quantity derived from the principal quantities of length and time, where the formula for speed is distance divided by time. Velocity is a vector quantity that indicates how fast an object is moving. The magnitude of this vector is called speed and is expressed in meters per second.
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If you are traveling 60 km, how many mph is that?
60 kilometers per hour is equal to 37.28 miles per hour.
Define distance.
Distance is the sum of an object's movements, regardless of direction. Distance can be defined as the amount of space an object has covered, regardless of its starting or ending position.
The pace at which an object's position changes in any direction is referred to as its speed. The distance traveled in relation to the time it took to travel that distance is how speed is defined. Since speed simply has a direction and no magnitude, it is a scalar quantity. You must always multiply or divide by 1.6 to determine MPH. When moving at 60 km/h, the calculation is 60/1.609344, or 37.28 mph.
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with what initial speed must a ball be thrown straight up to reach the same maximum height hh ?
The initial speed required to reach a maximum height hh is equal to √2gh, where g is the acceleration due to gravity and h is the height.
What is the acceleration ?
Acceleration is the rate of change of velocity over time, and is usually denoted by the symbol a. It is an important concept in physics and is related to force, mass, and velocity. Acceleration can be calculated by dividing the change in velocity by the time it took for the change to occur. Acceleration is a vector quantity, meaning that it has both magnitude and direction. When an object changes its direction, its acceleration is not constant and is referred to as centripetal acceleration. In the absence of external forces, objects in motion tend to maintain constant speed in a straight line, and therefore have no acceleration.
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A physics student adds two displacement vectors with magnitudes of 8. 0 km and 4. 0 km. Which one of the following statements is true concerning the magnitude of the resultant displacement?.
The resultant displacement when adding two displacement vectors with magnitudes of 8.0 km and 4.0 km will have a magnitude of 10 km.
This is because the magnitude of the resultant displacement vector is equal to the square root of the sum of the squares of the magnitudes of the individual vectors. In this case, the magnitude of the resultant displacement vector is equal to the square root of (8.0 x 8.0) + (4.0 x 4.0), which is equal to 10 km.
Adding two vectors together can also be done by using the trigonometric method. The magnitude of the resultant vector is equal to the sum of the magnitudes of the individual vectors, while the direction of the resultant vector is the angle between the two vectors. To calculate the magnitude of the resultant vector, we use the Pythagorean theorem and the Law of Cosines.
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The amplitude of a damped oscillator decreases to 0.9 times its original magnitude in 5 s. In another 10 s, it will decrease to α times its original magnitude, where α equals? a.0.7
b.0.81
c.0.729
d.0.6
A) A damped oscillator's amplitude drops to 0.9 times its initial value in 5 seconds. In another ten seconds, it will shrink to a size equal to twice its initial magnitude 0.81.
What does a damped oscillator's amplitude decrease to?A damped oscillator's amplitude drops to 0.9 times its initial value in 5 seconds. It will shrink to times its initial magnitude in another 10 seconds, where equals.
How does the damped oscillator's amplitude change over time?The frequency of a damped harmonic oscillator is 5 oscillations per second. Every ten oscillations, the amplitude is reduced to half of its original magnitude.
Why does amplitude fall off as damping is applied?Damping forces oppose motion, resulting in energy loss from the oscillating system, which lowers the oscillation's amplitude.
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if we quadruple the energy in a vessel of gas, what happens to the velocity of the gas particles?
The velocity of the gas particles will increase, as energy is directly proportional to temperature and temperature is directly proportional to velocity.
The relationship between energy, temperature and velocity of gas particles is known as the Kinetic Molecular Theory. According to this theory, an increase in energy will cause an increase in temperature, which in turn will cause an increase in the velocity of the gas particles. Therefore, if the energy in a vessel of gas is quadrupled, the temperature of the gas will also increase and the velocity of the gas particles will increase as a result. This increase in particle velocity is due to the fact that the particles have more energy to move around and are therefore able to move faster. The faster the particles move, the higher the velocity of the gas.
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the magnitude of a force between two equal charges is 4 n when the charges are 2 m apart. what is the force between the charges if the distance between them is increased to 6 m?
The required value of force between the equal charges is calculated to be 0.44 N.
The relation between force, charges and distance is known to be
F = (k q₁ q₂)/r²
In this problem, the charges are said to be equal. So, q₁ = q₂.
Mathematical equation becomes, F₁ = k q²/r₁²
Force F₁ is given as, 4N
Distance between the charges r₁ = 2 m
Putting the values in the above equation, we have,
F₁ = k q²/r₁²
4 = k q²/4
So, k q² = 16
Now, r₂ is said to be increased to 6 m.
Let us find the force F₂.
F₂ = k q²/r₂²
Putting the known values, we have
F₂ = 16/36 = 0.44 N
Thus, the required force is calculated to be 0.44 N.
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a planet orbits a star along an elliptical path, with the star at a focus of the ellipse. the planet's path can be modeled by the ellipse shown below, centered at the origin, with a horizontal major axis. if the minimum distance from the planet to the star is 70 million km and the maximum distance is 280 million km, write the equation of the ellipse (in millions of km).
Equation of the ellipse is x^2/a^2 + y^2/b^2 = 1
where an is the semi-major axis (the opposite half of the major axis) and b is the semi-minor axis (half of the minor axis).
The semi-major axis, which measures the distance from the planet's center to one of the foci, is the average of the minimum and maximum distances between the planet and the star:
(70 + 280)/2 = (175 million km)=a
The semi-major axis is equal to the square root of the product of the center-to-other-focus distance and the semi-major axis, divided by the difference between these two numbers:
105 million kilometers is equal to b = (a * 70 / (a - 70)) = 175 * 70.
Consequently, the orbital ellipse of the planet has the following equation:
x^2/175^2 + y^2/105^2 = 1
The ellipse describing the planet's orbit around the star has the following equation in millions of kilometers:
x^2/30,625 + y^2/11,025 = 1
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two like charges are separated by some distance. describe quantitatively what will happen to the force exerted by one charge on the other if the distance between the charges is doubled. the force will become:
If the distance between the charges is doubled. the force will become 1/4 times.
Why do electrostatic forces exist?
Positive and negative charges are known to interact with one another. The magnitude of the electrostatic force, however, serves as a gauge for the strength of this interaction. The magnitude of the electric charges and the spacing between them both contribute to this force.
Between two charges that are separated by a distance, there is an electrostatic force. The size of each charge and the separation between them determine the strength of the electrostatic force.
F ∝ 1/r^2
F2= 1/4 xF1
As a result, the force between the charges decreases by a factor of 4 as the distance between them doubles.
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1. Every human cell (when in the non-diving state) contains a total of 6x 109 base-pairs of DNA. The separate between the base pairs on DNA strands is about 3.3 Angstrom. Calculate the total length of DNA in every cell. Express the answer in meters and round to an integer number.2. The diameter of a typical human cell is 10 um. Based on your answer to the previous question, how many cells can one line up along the length of the DNA from one cell?
1. To calculate the total length of DNA in a human cell, we first need to convert the number of base pairs to meters.
The distance between base pairs is given as 3.3 Angstroms, so we need to convert this to meters.
1 Angstrom = 10^-10 meters
So, 3.3 Angstrom = 3.3 x 10^-10 meters
The total number of base pairs in one cell is 6 x 10^9, so the total length of DNA in one cell is:
6 x 10^9 base-pairs x 3.3 x 10^-10 meters/base-pair = 0.198 meters
2. To calculate the number of cells that can be lined up along the length of the DNA from one cell, we need to divide the length of the DNA by the diameter of a cell.
The diameter of a typical human cell is 10 um, so we need to convert this to meters:
10 um = 10^-6 meters
The length of DNA in one cell is 0.198 meters, so the number of cells that can be lined up along the length of the DNA from one cell is:
0.198 meters / (10^-6 meters/cell) = 1.98 x 10^6 cells
Rounding this answer to an integer number, we get 1.98 x 10^6 cells = 1,980,000 cells.
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in the human body when the triceps applies a force to the olecranon in extending the non-supported forearm at the elbow, it exemplifies: second-class levers. none of the answers are correct. first-class levers. third-class levers.
Option d. third-class levers. When the triceps applies a force to the olecranon in extending the non-supported forearm at the elbow, it exemplifies third-class levers.
In the human body, when the rear arm muscles applies a power to the olecranon in broadening the non-upheld lower arm at the elbow, it represents second rate class switches.
A second rate class switch is a switch framework where the work (the power applied by the rear arm muscles muscle) is situated between the heap (the heaviness of the lower arm) and the support (the elbow joint). In second rate class switches, the work is typically more prominent than the heap and the development is more slow contrasted with five star switches. Nonetheless, second rate class switches give a mechanical benefit, implying that a more modest power can be utilized to move a bigger burden.
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The complete question is in the human body when the triceps applies a force to the olecranon in extending the non-supported forearm at the elbow, which of the following class levers:
a. second-class levers.
b. first-class levers.
c. none of the answer are correct.
d. third-class levers.
use a dmm to measure the electrical resistance (in ohm’s, ) of a resistor. what happens if you reverse the leads?
When the lead locations of a multimeter are switched, the electrical resistance in a circuit alters.
By injecting a little voltage into the circuit and monitoring the current, a DMM ohmmeter measures the current. Due to the included diode junctions, semiconductors are polarity sensitive in their conductivity. The recorded voltage will simply change the sign if the leads are flipped when using a handheld voltmeter. For bench meters connected to lines, caution is required since it frequently happens that the negative terminal has been connected to earth ground. The terminals of meters should not be connected to ground or instrument enclosures since doing so may accidentally short-circuit components to the ground.
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How much work must be done on a spring with a spring constant of 80 N/m to stretch the spring 20 cm?
The amount of work that must be done on the spring to stretch it to 20 cm is 1.6 J.
What is the amount of work done on the spring?The amount of work done on the spring is calculated by applying the following formula as shown below.
W = ¹/₂kx²
where;
k is the spring constantx is the extension of the springThe amount of work that must be done on the spring to stretch it to 20 cm is calculated as follows;
W = ¹/₂ x ( 80 N/m ) x ( 0.2 m ) ²
W = 1.6 J
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light travels at 300,000 km/sec. about how far does light travel in 10 years?
As we move through the Milky Way galaxy, convert to light-years. NASA/JPL-Caltech is credited with producing the video. With the use of light-time, we can measure the vast distances of space.
What is the concept of light year?Light flows through interstellar space at a speed of 186,000 miles per second (300,000 km/s) and a rate of 5.88 trillion miles (9.46 trillion km/s) each year.
Given the amount of time it takes for light to reach our eyes, everything we see in the night sky has already occurred. In other words, if you see something from a distance of 1 light-year away, you see it precisely as it was a year ago.
Therefore, The distance that light travels in a light-year is one year. Light flows through interstellar space at a speed of 186,000 miles per second (300,000 km/s) and a rate of 5.88 trillion miles (9.46 trillion km/s) each year.
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As we move through the Milky Way galaxy, convert to light-years. Caltech is credited with producing the video. With the use of light-time, we can measure the vast distances of space.
What is the concept of light year?Light flows through interstellar space at a speed of 186,000 miles per second (300,000 km/s) and a rate of 5.88 trillion miles (9.46 trillion km/s) each year.
Given the amount of time it takes for light to reach our eyes, everything we see in the night sky has already occurred. In other words, if you see something from a distance of 1 light-year away, you see it precisely as it was a year ago.
Therefore, The distance that light travels in a light-year is one year. Light flows through interstellar space at a speed of 186,000 miles per second (300,000 km/s) and a rate of 5.88 trillion miles (9.46 trillion km/s) each year.
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Find the amount of work W_ABCDA done by the electrostatic force on the charged particle as it moves from A to B to C to D to A.
W = - F electrostatic. dr is the amount of work done by the electrostatic force on a charged particle, where F electrostatic is the electrostatic force acting on the particle and dr is the particle's displacement.
In this case, the particle moves from point A to point B to point C to point D to point A. To determine the total work done by the electrostatic force, we must calculate and add the work done during each segment of the displacement.
W_AB = - ∫F_electrostatic.dr from A to B
W_BC = - ∫F_electrostatic.dr from B to C
W_CD = - ∫F_electrostatic.dr from C to D
W_DA = - ∫F_electrostatic.dr from D to A
W ABCDA = W AB + W BC + W CD + W DA is the total work done by the electrostatic force. The electrostatic force is assumed to be constant along the particle's path in this equation. However, if the magnitude or strength of the electric field changes along the path, the equation becomes more complicated.
NOTE: W ABCDA cannot be calculated precisely without more information about the electrostatic force acting on the particle and the path it takes from point A to point B to point C to point D and back to point A.
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