Given,
Force = 10,000 N
Distance = 30 m
Time = 40 s
Work done = force × distance
Work = 10,000 × 30
Work = 300,000 J
______
꧁✿ ᴿᴬᴵᴺᴮᴼᵂˢᴬᴸᵀ2222 ✬꧂
The work done on the object is equal to the power it experiences which is equal to 735 watts.
What is work done?Work done is defined as the product of force applied and the distance over which the force is applied on the object. Work is done on an object when a force is applied to an object and the object is moved through a particular distance.
The time rate of doing work is called as power, which is designated by the symbol P. It is measured in the units of watts, where one watt is equal to one joule energy applied per second time.
Work done on an object is equal to the force (F) multiplied by the distance d in the direction of the force. Where, time interval is Δt.
P = W/Δt = F × d/Δt = m × g × h/Δt = 100 × 9.8 × 30 / 40
Power = 735 watts
The power of the object is 735 watts.
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How fast is an object going if it travels from San Diego to Anaheim in 1.25 hours (hr)? The distance from San Diego to Anaheim is 93 miles (mi).
a) 74.4 mi/hr
b) 116.25 mi/hr
c) 0.013 mi/hr
d) 84.25 mi/hr
e) None of the answers
Answer:
74.4 mph
Explanation:
Since we have the distance in miles and the time it took in hours, we can divide the two to get miles per hour.
speed = mi/hr
speed = 93/1.25
speed = 74.4 mph
How to calculate average velocity with a change in acceleration is not constant.
Regardless of acceleration, average velocity can always be calculated from its definition:
average velocity = (change in position) / (change in time)
It's only when acceleration is constant that the average velocity can be computed using initial and final velocities. Under this condition,
average velocity = (initial velocity + final velocity) / 2
Déterminer la charge de noyau d’atome d’oxygène en coulomb C
Answer:
determine a large mam I have no idea
does the force change if the density change in a object
Answer:
No
Explanation:
It doesn't depend on the density
Answer:No. If you take all your masses and and squeeze them into a tiny volume,
A bob attached to a string of length L = 1.25 m, initially found at the equilibrium
position, is given an initial velocity v = 0.8 m/s. The maximum displacement angle,
Omax, is: (Take g=10 m/s)
17
3.2
13
10.2
6.4
Clear selection
A hoh attached to a string of length 2 m is displaced by an angle of 8º and then
The maximum displacement angle of the bob is 13⁰.
The given parameters;
Length of the pendulum, L = 1.25 mInitial velocity of the bob, v = 0.8 m/sThe maximum displacement of the bob is calculated by applying the principle of conservation of energy;
[tex]P.E = K.E\\\\mgh = \frac{1}{2} mv^2\\\\h = \frac{v^2}{2g} \\\\h = \frac{0.8^2}{2\times 10} \\\\h = 0.032 \ m[/tex]
The maximum displacement angle is calculated as follows;
[tex]cos \theta = \frac{L-h}{L} \\\\cos \theta = \frac{1.25 - 0.032}{1.25} \\\\\cos \theta = \frac{1.218}{1.25} \\\\cos \theta = 0.9744\\\\\theta = cos^{-1}(0.9744)\\\\\theta = 13\ ^0[/tex]
Thus, the maximum displacement angle of the bob is 13⁰.
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Please help me on this 1 assignment im giving 25 points GOOD LUCK!
Answer:
Explanation:
im sorry if this doesn't help but i think its A
I’m not sure what this is… help please
Answer:
A) Slower
Explanation:
Less / low energy means less / slower speed.
Have a nice day!
I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)
- Heather
A ball is projected at an immovable wall with a speed vi and bounces back the wall in such a manner that it only has 1/3 of its original linear momentum. a) Determine what fraction of the kinetic energy is lost in the collision.
The fraction of the kinetic energy of the ball lost during the collision is [tex]\frac{1}{3}[/tex].
The given parameters;
initial speed of the ball, = vifinal momentum of the ball, Pf = ¹/₃PiThe initial and final momentum of the ball is calculated as;
[tex]P_i = m_ivi[/tex]
[tex]P_f = m_fv_f = \frac{1}{3} m_iv_i[/tex]
The initial and final kinetic energy of the ball is calculated as;
[tex]K.E_i = \frac{1}{2} m_iv_i^2 = \frac{1}{2} P_iv_i\\\\K.E_f = \frac{1}{2} m_fv_f^2= \frac{1}{2} (\frac{1}{3} P_iv_i)= \frac{1}{6} P_iv_i[/tex]
The change in the kinetic energy is calculated as;
[tex]\Delta K.E = K.E_f - K.E_i \\\\\Delta K.E = \frac{1}{6} P_iv_i - \frac{1}{2} P_iv_i = \frac{1}{3} P_iv_i[/tex]
Thus, the fraction of the kinetic energy of the ball lost during the collision is [tex]\frac{1}{3}[/tex].
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A football player kicks the ball with an initial velocity of 28.3 m/s at an angle of 60° above the horizontal. The ball is in the air for a total of 5.00 s before hitting the ground. Ignoring air resistance, what would be the ball's horizontal displacement?
Hi there!
Since the ball is directed 60° above the horizontal, we must use its HORIZONTAL component to find its displacement.
We can take the cosine to do so:
vcosθ = 28.3cos(60) = 14.15 m/s
Since the ball is in the air for 5 sec, we can use the following equation:
displacement = velocity · time (d = vt)
Plug in the values:
d = 14.15 · 5 = 70.75 m
Definition of Speed?
speed- the rate something moves or operates
Can I have brainlist please
The Speed are distance covered by the object in unit time.The S.I unot of speed is metre per second written as m/sec.It is a scalar quantity.
Speed=Distance/TimeAverage speed=Total distance covered/Total time takenThe speed is measured in metres per second ( ms- ¹ )
Where denoted by s
The distance travelled is measured in metres (m) and denoted by d
t is the amount of time spent and measured in seconds s
Explanation:There are Two Types of Speed are :Uniform Speed: When the distance travelled by a body is equal in equal interval of time then the speed is uniform. Non-uniform Speed: When the distance travelled by a body is unequal in an equal interval of time then the speed is known as non- uniform speed.There are four different forms of speed are : If an object travels the same distance in the same amount of time, it is said to be moving at a uniform speed.When an object travels a different distance at equal intervals of time, it is said to be moving at variable speed.The Average speed is the average speed determined by the ratio of the total distance travelled by an object to the entire amount of time it took to travel that distance.The speed of an object at any given moment when it is travelling at a variable speed is referred to as the object's instantaneous speed.Know more:The Discover of the Speed is Galileo Who was the Discover the speed as the distance covered per unit of time.Speed is measured as the ratio of distance to the time in which the distance was coveredThe dimensional formula of speed is:M ⁰ L ¹ T -¹ The measurement of speed in vehicles, speedometers are used. To measure the distance covered odometers are used. The Speed can also be calculated with the help of a graph. The Distance-time graph helps in understanding the speed of an object.An instrument to measure immediate speed is a speedometer.186,282 miles per second is another way to write the speed of light.In dry air, the speed of sound is 343.2 meters per second.What is the centripetal force acting on a 1.5 kg mass moving in a circular path with a centripetal
acceleration of 18 m/s2
The centripetal force acting on a 1.5 kg mass moving in a circular path is 27N
A centripetal force is a net force acting on an object in order to maintain the object's movement in a circular motion.
According to Newton's first law, it states an object will continue to proceed its movement in a straight line unless acted upon by an external force.
The centripetal force is the external force at work here and It's the net force that propels the object in a circular motion.
Using the formula for calculating centripetal force:
[tex]\mathbf{F_c = mass (m) \times acceleration (a)}[/tex]
[tex]\mathbf{F_c = 1.5 \ kg \times18 \ m/s^2}[/tex]
[tex]\mathbf{F_c = 27 \ N}[/tex]
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As an aeroplane decelerates, its kinetic energy decreases. Suggest what happens to this energy
they are converted into thermal and sound energy as well as the kinetic energy in the air
2. physical quantities which do not depend on any physical quantities for their measurements are known as
Answer:
Fundamental quantities
flat mirror: draw ray diagram for an object placed at F
Answer:
...
Explanation:
I'm doing this for points sorry
HELP
How much heat energy is required to raise the temperature of 37.5g of water from 23.0°C to 55.2°C? The specific heat for water is 4.184 J/g°C. (Include your calculation to receive credit.)
Answer: 5.05 J
Explanation:
Qcalorimeter: m*c* ΔT --> (37.5g)*(4.184J/g ° C)*(55.2 °C – 23.0 °C) Qcalorimeter: 5.05 J
According to specific heat capacity, 5.052 kJ of heat energy is required to raise the temperature of 37.5 g of water from 23.0°C to 55.2°C.
What is specific heat capacity?Specific heat capacity is defined as the amount of energy required to raise the temperature of one gram of substance by one degree Celsius. It has units of calories or joules per gram per degree Celsius.
It varies with temperature and is different for each state of matter. Water in the liquid form has the highest specific heat capacity among all common substances .Specific heat capacity of a substance is infinite as it undergoes phase transition ,it is highest for gases and can rise if the gas is allowed to expand.
It is given by the formula ,
Q=mcΔT
Substitution in above formula, givesQ= 37.5×4.184×32.2=5052.18 J or 5.052 kJ.
Thus , 5.052 kJ of heat energy is required to raise the temperature of 37.5g of water from 23.0°C to 55.2°C.
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What is the half-life for the radioactive decay of particle that
starts with 400.00 g and ends up with 12.50 g if the total time
was 50 minutes for the decay to occur?
Answer:
ytyug
Explanation:
Daniel is 50.0 meters away from a building. He observes that his line-of-sight to the tip of the building makes an angle of 63.0° with the horizontal. What is the height of the building?
Answer:
willie tower
Explanation:
mataas kasi
URGENT! 40 POINTS! For each situation below, make a model of the situation and find the work done on the box using both energy and forces.
1. A 2 kg box with some initial velocity slides up a frictionless ramp, which is at a 15ᵒ
angle to the ground, until the box comes to rest 1 second later.
2. A 2 kg box initially at rest slides down a frictionless ramp (at 15ᵒ from the ground) for
1 second.
3. A 2 kg box is thrown upward with an initial speed of 3.5 m/s. Consider the box from
the time it was thrown until it reaches its maximum height.
4. A 2 kg box is dropped from an initial height of 10 m.
I have some physics, I just don't know what formulas to use or where to start. Help is much appreciated.
Answer:
i dont know but ask your mom for help
Explanation:
some brainly things dont work so ask your mom for some help or someone you know ok
3.2.1.3.2 Practice with Work and Forces …A_K_
The rate at which work is done is called
a. efficiency
b. effort time
c.
force
d. power
Please select the best answer from the choices provided
Ο Α
ОВ
ОС
Answer:
The rate at which work is done is power
5. How are electromagnetic waves similar to ocean waves?.
Answer:
Electromagnetic waves have crests and troughs similar to those of ocean waves. The distance between crests is the wavelength. The shortest wavelengths are just fractions of the size of an atom, while the longest wavelengths scientists currently study can be larger than the diameter of our planet!
Explanation:
hope it's helps u ...........!
A fairly efficient steam turbine engine fired by coal is used to drive an electric generator. The generator operates between 2100°C and 385°C.
(a) Determine the maximum possible efficiency of the engine.
Answer: 72.3 %
Formula:
e = 1 - (Tc / Th) = 1 - (Qc / Qh) = ( W / Qh)
Explanation: Unsure??
(b) The engine absorbs 1.15 105 J from the hot reservoir every second. If the actual efficiency of the engine is 40.3%, determine the mechanical power the engine delivers.
Answer: 46 kW
Explanation:
Energy absorbed by the engine (J) * actual efficiency of the engine (%) = mechanical power the engine delivers (kW)
How does 1 - (385/2100) = 72.3 % ?
What do I Plug in to make e = 72.3 %
Use kelvin not celsius
C + 273 = K
This will fix my problem of the equation not making sense.
what are the musical instrument of liturgy and devitional music.
help me plssss
Answer: A hymn which accompanies religious observances and rituals. And others like guitar, violin, flute, harp and the organ
Explanation: Gradually people instructed the natives not only in singing but also in playing various instruments like guitar, violin, flute, harp and later on, the organ.
The first observation of block oscillation was in a semiconductor superlattice with period 10nm.
Answer:How did family life under Prince Shotoku’s rule reflect Confucian ideals?
Women had rights and were equal to their husbands.
Children were taught to value individualism over community.
People were expected to give up worldly concerns and turn to nature.
Households were structured to maintain order, with the husband as head.
Explanation:
A very light rod 40cm long is pivoted at the centre. A weight of 50N is placed at one end. Where is the place to put a weight of 200N in order that the rod is in equilibrium?
Hi there!
We can go about this problem using a summation of torques.
In order to ensure the rod is in equilibrium, we must satisfy the condition:
Στ = 0
Since the rod is "very light", we can disregard its mass.
The equation for torque is:
τ = rFsinθ
In this instance, the torques are the weights of the objects and their distance from the pivot.
As the rod is 40 cm, the pivot is at 20 cm. Also, the torques must sum up to 0, so:
0 = rF1 - rF2
r1F1 = r2F2
0.20(50) = r2(200)
Solve:
10 = r2(200)
r2 = 0.05 m = 5 cm
The 200N weight must be put at a distance of 5 cm from the OTHER SIDE of the pivot in order to balance the rod.
PLEASE ANSWER NEED HELP!!!!!!!! PLEASE THE CORRECT ANSWER!!!!!!
Why are those with low cardiovascular fitness more prone to heart disease than those whose cardiovascular fitness is high?
A.
Exercise decreases the size of arteries, causing heart disease.
B.
Those with lower cardiovascular fitness will have weaker heart muscles.
C.
High cardiovascular fitness means that the heart rate is rarely elevated.
D.
Cardiovascular fitness is the only factor that determines the strength of the heart.
PLEASE NO LINKS OR I WILL REPORT YOU
People with low cardiovascular fitness are more prone to heart disease than those whose cardiovascular fitness is high because those with lower cardiovascular fitness will have weaker heart muscles. Thus, the correct option is B.
What is Cardiovascular fitness?Cardiovascular fitness may be defined as the accommodation of the cardiovascular system to furnish oxygenated blood to functioning muscles. It includes the muscles of the heart, lungs, blood vessels, etc.
People with low cardiovascular fitness have lower furnishing of oxygenated blood to various organs like the heart, lungs, etc. Due to this, the muscles of specific body parts or organs may undergo a state of inactivity suddenly for a fraction of seconds.
This activity constantly leads to various heart-related diseases directly or indirectly in the life of an individual.
Therefore, the correct option for this question is B.
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what are some things to keep in mind before and while playing volelyball
A car travels at 40 mph. what distance will it travel in 3 hours?
Car speed = 40m/ hour
3 hours = 40 × 3 = 120m /hour
Answer:
120
Explanation:
if the car travels 40 in one hour , to find the speed in 3 hours multiply 40 x 3 which will give us 120
A ball is thrown from ground level at an angle of 0 and the initial velocity components are 7.5m/s and 13m/s. Ignoring air resistance, calculate each of:
1- The initial velocity is vi
2- The value of the angle at which the ball was thrown
3 - The horizontal range of the ball R
I assume you mean an angle of θ, and not 0. I also assume the given components of the initial velocity are horizontal and vertical, respectively, so that
1. the initial velocity vector is
[tex]\boxed{\vec v_i = (7.5\,\vec\imath + 13\,\vec\jmath) \dfrac{\rm m}{\rm s}}[/tex]
which means the ball is thrown with an initial speed of
√((7.5 m/s)² + (13 m/s)²) ≈ 15 m/s,
and
2. the angle made by [tex]\vec v_i[/tex] with the positive horizontal axis is θ such that
[tex]\tan(\theta) = \dfrac{13}{7.5} \implies \theta \approx \arctan(1.7) \approx \boxed{60^\circ}[/tex]
3. At time t, the ball attains a height y and horizontal range x according to
y = (13 m/s) t - g/2 t²
x = (7.5 m/s) t
where g = 9.8 m/s². When the ball reaches the ground (y = 0) for t > 0, we have
(13 m/s) t - g/2 t² = 0
13 m/s - g/2 t = 0
t = 2 (13 m/s)/g = (26 m/s)/g
Plugging this time into the x equation gives a horizontal range of
x = (7.5 m/s) (26 m/s)/g ≈ 20. m
How does the electric energy between two negativly charged particles change if one particles charge is increased by a factor of 2
Answer:
i dont know this one
Explanation:
sorry i wish i could help but if u look closley on that qyestion you will understand it mor
A 2 kg object has a specific heat capacity of 1,700 J/(kg \cdot⋅oC)
To raise this object's temperature from 15 Celsius to 25 Celsius, the object must absorb _______ Joules of heat.
The amount of heat needed to raise the temperature of a 2kg object from 15°C to 25°C is 34000J.
HOW TO CALCULATE SPECIFIC HEAT CAPACITY:
The amount of heat absorbed by an object can be calculated by using the following expression:Q = m.c.∆TWhere;
Q = amount of heat absorbed or released (J)m = mass of objectc = specific heat capacity (J/g°C)∆T = change in temperature (°C)According to this question, 2 kg object has a specific heat capacity of 1,700J/kg°C and was raised from a temperature of 15 Celsius to 25 Celsius. The heat absorbed is calculated as follows:Q = 2 × 1700 × {25 - 15}Q = 3400 × 10Q = 34000JTherefore, the amount of heat needed to raise the temperature of a 2kg object from 15°C to 25°C is 34000J.Learn more about how to calculate heat absorbed at: https://brainly.com/question/11194034?referrer=searchResults