Answer:
21.21 m/s
Explanation:
Let KE₁ represent the initial kinetic energy.
Let v₁ represent the initial velocity.
Let KE₂ represent the final kinetic energy.
Let v₂ represent the final velocity.
Next, the data obtained from the question:
Initial velocity (v₁) = 15 m/s
Initial kinetic Energy (KE₁) = E
Final final energy (KE₂) = double the initial kinetic energy = 2E
Final velocity (v₂) =?
Thus, the velocity (v₂) with which the car we travel in order to double it's kinetic energy can be obtained as follow:
KE = ½mv²
NOTE: Mass (m) = constant (since we are considering the same car)
KE₁/v₁² = KE₂/v₂²
E /15² = 2E/v₂²
E/225 = 2E/v₂²
Cross multiply
E × v₂² = 225 × 2E
E × v₂² = 450E
Divide both side by E
v₂² = 450E /E
v₂² = 450
Take the square root of both side.
v₂ = √450
v₂ = 21.21 m/s
Therefore, the car will travel at 21.21 m/s in order to double it's kinetic energy.
For the car to be able to double its kinetic energy, it would need to travel at a speed of approximately 21.21m/s.
Given the data in the question;
Speed of the car; [tex]v_1 = 15m/s[/tex]
Speed for the car to double its kinetic energy; [tex]v_2 = \ ?[/tex]
Using the expression for kinetic energy:
[tex]K_E = \frac{1}{2}mv^2[/tex]
Where m is the mass and v is the velocity
Now, Initial Kinetic Energy will be;
[tex]K_E_1 = \frac{1}{2}mv_1^2 \\\\K_E_1 = \frac{1}{2}*m*(15)^2\\\\K_E_1 = \frac{1}{2}*m*225\\\\K_E_1 = 112.5*m[/tex]
For the kinetic energy to become double
[tex]K_E_2 = 2 * K_E_1\\\\\frac{1}{2}mv_2^2 = 2 * ( 112.5 * m)\\\\\frac{1}{2}mv_2^2 = 2m( 112.5)\\\\v_2^2 = 4( 112.5)\\\\v_2^2 = 450\\\\v_2 = \sqrt{450}\\\\v_2 = 21.21m/s[/tex]
Therefore, for the car to be able to double its kinetic energy, it would need to travel at a speed of approximately 21.21m/s.
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What season is it in your town when it is fall in the Southern Hemisphere
Answer:
i am in the southern hemisphere
Explanation:
Answer:
its winter ................
After school, you watch your friend Katie run to a truck as soon as she hears the truck's music playing. Later, you find out the truck is the ice cream vendor's vehicle. How would a behaviorist interpret Katie's running to the truck?
Katie has been conditioned to the music and has associated the musical truck with serving ice cream.
Katie uses the music as a test of her biological reflexes.
Katie feels empathetic for the man driving the ice cream truck in such hot weather and wants to take him a drink of water.
Katie remembers the pattern of the music and knows the truck is too far away to reach unless she runs.
Answer:
A- Katie has been conditioned
Explanation:
Katie has associated the ice cream truck music with something positive like ice cream that makes her happy. it's kinda like a dog clicker, whenever a dog hears the click they know that click means a treat, which is the same for Katie, ice cream jingle means treat.
A plane flies from NY to LA at a constant speed of 800 km/hr. How long will it take a plane to fly 4200 km?
Answer: i don’t know the answer but
Explanation:
Divide the distance by the speed. That gives the travel time.
t = d/v = (4200 km) / (800 km/hr) = ? hrs
If it takes Jeff 3 hours and 33 minutes to drive 500 miles, what is his average velocity over this time?
Answer:
141 mphExplanation:
aver. velocity = distance over time
= 500 miles
3 hours + (33 min. x 1 hr. )
60 min.
= 500 miles
3.55 hours
= 140.845 ≈ 141 miles / hour
neon sign transformer has a 460W AC output with an rms voltage of 15 kV when connected to a normal household outlet. There are 500 turns of wire in the primary coil. How many turns of wire does the secondary coil have
Answer:
The number of turns in the secondary coil is 62,500 turns.
Explanation:
Given;
power of the transformer, P = 460 W
output voltage, V₂ = 15 kV = 15,000 V
input voltage of normal household outlet, V₁ = 120 V
number of turns in the primary coil, N₁ = 500 turns
number of turns in the secondary coil, N₂ = ?
Apply the following the transformer equation;
[tex]\frac{N_2}{N_1} = \frac{V_2}{V_1}\\\\N_2 = \frac{V_2}{V_1}*N_1\\\\N_2 = \frac{15000}{120}*500\\\\N_2 = 62500 \ turns[/tex]
Therefore, the number of turns in the secondary coil is 62,500 turns.
One particle, of mass m , moves with a speed v in the x-direction, and another particle, of mass 2 m , moves with a speed v/2 in the y-direction. what is the velocity of the center of mass of these two particles?
Given :
One particle, of mass m , moves with a speed v in the x-direction, and another particle, of mass 2 m , moves with a speed v/2 in the y-direction.
To Find :
The velocity of the center of mass of these two particles.
Solution :
Speed of mass m, [tex]v\ \hat i[/tex].
Speed of mass 2m , [tex]\dfrac{v}{2}\ \hat{j}[/tex] .
Speed of center of mass is given by :
[tex]v_{cm }= \dfrac{m\times( v\ \hat{i}) + 2m \times \dfrac{v}{2}\ \hat{j} }{m + 2m}\\\\v_{cm}=\dfrac{v( \hat{i} + \hat{j})}{3}[/tex]
Hence, this is the required solution.
The velocity of the center of mass of these two particles will be [tex]\rm v_{cm}= \frac{v(\vec i+\vec j)}{3}[/tex]
What is velocity?The change of displacement with regards to time is defined as speed. Speed is a scalar quantity. It is a time-based component. Its unit is m/sec.
The given data in the problem is
[tex]\rm V_i[/tex] is the speed of mass m
[tex]\rm \frac{v}{2} \hat j[/tex] is the speed of mass 2m
Speed of the center of mass will be;
[tex]\rm v_{cm}=\frac{m \times (v \hat i)+2m \times \frac{v}{2}\hat j }{m+2m} \\\\ \rm v_{cm}= \frac{v(\vec i+\vec j)}{3}[/tex]
Hence the velocity of the center of mass of these two particles will be [tex]\rm v_{cm}= \frac{v(\vec i+\vec j)}{3}[/tex].
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Assume that the left side of your heart creates a pressure of 118 mm Hg by exerting a force directly on the blood over an effective area of 16.0 cm^2. What force does it exert to accomplish?
Answer:
251.5 x 10⁻⁴ N
Explanation:
Pressure = Force / surface area
Force = pressure x area
pressure = 118 mm of Hg
= .118 x 13.6 x 9.8 N / m²
= 15.72 N / m ²
area = 16 x 10⁻⁴ m²
Force = 15.72 x 16 x 10⁻⁴
= 251.5 x 10⁻⁴ N .
A student is planning to make changes to a circuit. Which change will
increase the resistance?
A. Replace the wire with one that is longer.
B. Swap ne positions of the battery and the switch.
C. Replace the wire with one that is shorter.
D. Swap the positions of the lightbulb and the switch.
Answer:
A)
Explanation:
This is because the longer the wire is, the more resistance there is for the electricity to run through.
The student can increase the resistance by replacing the wire with one that is longer. Thus, option A is correct.
What is Ohm's law?The voltage across a conductor, according to Ohm's law, is precisely proportional to the current that passes through it.
A wire's resistance is inversely correlated with its cross-sectional area and directly correlated with its length. Most conductors have a resistance to the flow of an electric current through them. As the wire's length increases, the resistance in the wire rises.
However, according to Ohms law V=IR, a wire's length increases its resistance while decreasing its current for a given potential difference (voltage).
Therefore, replacing the wire with a longer one will increase resistance if a student plans to modify a circuit.
Thus, option A is correct.
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A piston above a liquid in a closed container has an area of 0.75m^2, and the piston carries a load of 200kg. What will be the external pressure on the upper surface of the liquid?
Answer:
2613.3 pa
Explanation:
p=F/A
p=ma/A
p=200×9.8/0.75
p=2613.3
Please help me on this
Answer:
Explanation:
read the assignment and use this
Topic sentence
Evidence from the text
Thoughts in your own words
Opinion
Wrap up sentence
T
E
T
O
W
and 2 of those make 2 paragraphs
A wagon having a mass of 32 kg is accelerated across a level road at 0.50 m/s2 . What net force acts on the wagon horizontally?
Answer:
16 NExplanation:
The force acting on an object given it's mass and acceleration can be found by using the formula
force = mass × acceleration
From the question we have
force = 32 × 0.5
We have the final answer as
16 NHope this helps you
Based on the information in the passage, What is true of gases
Answer:
that gases are gases
Explanation:
Answer:
A. Some, but not all gases are harmful to humans.
Explanation:
as a result of photosynthesis is the production of sugar molecules known as what?
Answer:
Glucose
Explanation:
Answer:
Check in your science textbook
Astronomers discover a bright X-ray source in the Milky Way. They see no counterpart in the optical bands, but it has another star orbiting it, and they determine that the X-ray source has a mass of 10 MSun. What is the most likely origin of the X-rays?
a. a black hole
b. a neutron star
c. a white dwarf
d. a gamma-ray burst
Answer:
a. a black hole
Explanation:
X-ray emission from the central degrees of the Milky Way Bright X-ray emission traces the coherent edge brightened shell-like feature, dubbed the northern chimney, located north of Sgr A* and characterized by a diameter of about 160 pc. On the opposite side, the southern chimney appears as a bright linear feature. Bright X-ray emission is observed at high latitude
a baseball was thrown with an initial velocity of 14 m/s at an angle above the horizontal . It remained in the air for 2 s. Which of the following quantities was constant while the baseball was in the air?
Answer:
Explanation:acceleration
If a baseball was thrown with an initial velocity of 14 m/s at an angle above the horizontal. It remained in the air for 2 seconds, then the acceleration of the object would remain constant while the baseball was in the air.
What is a projectile motion?It can be defined as the motion of any object or body when thrown from the earth's surface and follows any curved path under the effect of the gravitational force of the earth.
As given in the problem a baseball was thrown with an initial velocity of 14 m/s at an angle above the horizontal. It remained in the air for 2 seconds.
Thus, If a baseball was thrown with an initial velocity of 14 m/s at an angle above the horizontal. It remained in the air for 2 seconds, then the acceleration of the object would remain constant while the baseball was in the air.
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Help me
An atomic nucleus suddenly bursts apart (fission) into two pieces. Piece A with mass mA travels to the left with a speed of vA. Piece B with mass mB travels to the right with speed vB. Show the velocity of piece B in terms of mA, mB and VA.
Solution:
Consider that the nucleus is not acted by an external force. Thus, momentum is conserved, so: pBf + pAf = 0
Substituting the expression for momentum results to
mBv (_______) + (_________) mAv (______) = 0
Deriving the expression for the velocity of piece B results to
v(_____) =(mA/m ______)vA
Answer:
[tex]v_{B} = \frac{m_{A}v_{A}}{m_{B}}[/tex]
Explanation:
We can apply the law of conservation of momentum on the nucleus in its initial and final state of nucleus:
Initial Momentum = Final Momentum
momentum of nucleus before bursting = momentum of piece A + momentum of Piece B
[tex](m_{nucleus})(velocity of nucleus) = m_{A}v_{A} + m_{B}v_{B}\\[/tex]
since, nucleus was initially at rest. Therefore,
velocity of nucleus = 0 m/s
and due to opposite direction of forces:
Vb = - Vb
Therefore,
[tex](m_{nucleus})(0) = m_{A}v_{A} - m_{B}v_{B}\\\\m_{A}v_{A} = m_{B}v_{B}\\\\v_{B} = \frac{m_{A}v_{A}}{m_{B}}[/tex]
A 310 kg car is parked in a parking garage. If the car has 35,944 J of potential energy, how many
meters above ground is the car?
Gravitational potential energy is the energy stored in an object as the result of its vertical position or height. It can be calculated as its weight times the height. This is:
[tex]\boxed{U_g=W\cdot h=mgh}[/tex]
Where:
W is the weight of the objectm is the massg is gravitational accelerationh is the heightSolving for the h:
[tex]h=\dfrac{U_g}{mg} = \dfrac{35944\;J}{310\;kg\cdot 9.8\;m/s^2} = 11.8\;m[/tex]
R/ The car is parked 11.8 m above ground
4. Name three things that all games, no matter where they are played around the world, have in common.
Answer:
Key components of games are goals, rules, challenge, and interaction.
Explanation:
Hope I helped.
Answer:
the name of the games are goals, rules, challenges and interaction and mabe there can be more.
Explanation:
I hope this helped your day better this is the correct answer i got it correct on the test.
A 5000 kg meteorite falls toward the earth. What is the magnitude of the earth's acceleration just before impact? The earth's mass is 5.98 × 10^24 kg.
Answer:
8.193x10^-21m/s²
Explanation:
We have it that the gravitational force that is acting on this object is equal to the earth's gravitational force.
We start by using this formula
Ma = mg
We make a the subject of formula
a = mg/M
m = 5000kg
g = 9.8
M = 5.98x10^24kg
mg = 5000x9.8
= 49000
49000/5.98x10^24
= 8.193x10^-21m/s²
The magnitude of the earth's acceleration is 8.20 × 10^27
The parameters given in the question are;
mass= 5000 kg
g= 9.81
earth's mass= 5.98 × 10∧ 24
The formula is
= mass × acceleration due to gravity/earth's mass
= 5000 × 9.81/ 5.98^24
= 49,050/5.98 × 10^24
= 8.20 × 10^27
Hence the magnitude of the earth's acceleration just before impact is 8.20 × 10^27
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Of the pairs of galaxies listed in the answer choices, which is the closest to the Milky Way Galaxy?
Answer:
Andromeda galaxy
Explanation:
Answer:
Andromida galaxy
Explanation:
In 4 billion years the milky way and the Andromida galaxy will collide with each other
During a medieval siege of a castle, the attacking army uses a trebuchet to hurl heavy stones at the castle walls. If the trebuchet launches the stones with a velocity of +48.5" m"/s at an angle of 42.0°, how long does it take the stone to hit the ground? For those settings, what is the maximum range? How high will the stones go? Show all your work
Answer:
a) t = 6.62 s
b) x = 238.6 m
c) H = 53.7 m
Explanation:
a) We can find the time of flight as follows:
[tex] y_{f} = y_{0} + v_{0_{y}}t - \frac{1}{2}gt^{2} [/tex]
Where:
[tex]y_{f}[/tex] is the final height = 0
[tex]y_{0}[/tex] is the initial height = 0
[tex]v_{0_{y}}[/tex] is the initial vertical velocity of the stone
t: is the time
g: is the gravity = 9.81 m/s²
[tex] v_{0}sin(42)t - \frac{1}{2}gt^{2} = 0 [/tex]
[tex] 48.5 m/s*sin(42)*t - \frac{1}{2}9.81 m/s^{2}*t^{2} = 0 [/tex]
By solving the above quadratic equation we have:
t = 6.62 s
b) The maximum range is:
[tex] x = v_{0_{x}}t = 48.5 m/s*cos(42)*6.62 s = 238.6 m [/tex]
c) The maximum height (H) can be found knowing that at this height the final vertical velocity of the stone is zero:
[tex] v_{f_{y}}^{2} = v_{0_{y}}^{2} - 2gH [/tex]
[tex] H = \frac{v_{0_{y}}^{2} - v_{f_{y}}^{2}}{2g} = \frac{(48.5 m/s*sin(42))^{2} - 0}{2*9.81 m/s^{2}} = 53.7 m [/tex]
I hope it helps you!
Consider a 75.5-kg man standing on a spring scale in an elevator. Starting from rest, the elevator ascends, attaining its maximum speed of 1.65 m/s in 0.675 s. What does the spring scale register in pounds during these 0.675 s?
Answer:
208.08 pounds
Explanation:
Given that,
Mass of a man, m = 75.5 kg
Starting from rest, the elevator ascends, attaining its maximum speed of 1.65 m/s in 0.675 s.
We need to find the value of spring scale during these 0.675 s.
As the elevator ascends, net force will be given by :
F = mg + ma
a can be calculated as follows :
[tex]a=\dfrac{1.65-0}{0.675}\\\\a=2.45\ m/s^2[/tex]
So,
F = 75.5[(9.81) + (2.45)]
F = 925.63 N
We know that,
1 N = 0.224 Pounds
It means, 925.63 N = 208.08 pounds
So, the spring scale will register 208.08 pounds.
how do you believe the brain works to help you learn and grow
Answer:
I think
Explanation:
the brain grows more when you learn something new, and less when you practice things you already know. i think- lol
A 0.5 kg ball is thrown horizontally towards a wall with a speed of 10 m/s. The initial velocity is chosen to be the positive x -direction for this question. The ball horizontally rebounds back from the wall with a speed of 10 m/s in the negative x -direction. What is momentum of the ball before it hits the wall, p? What is momentum of the ball after it hits the wall, p,? What is the change in momentum of the ball, delta p? (Give both magnitude and direction for each answer.) Is momentum conserved for the ball?
Explanation:
Step one:
given dara
mass of ball m=0.kg
initial velocity u= 10 m/s
final velocity v=10m/s
Required
momentum before and after impact
the expression for momentum P
P=mv
before impact
P=mv
P1=0.5*10
P1=5(kg⋅m/s)
after impact
P=mu
P2=0.5*10
P2=5(kg⋅m/s)
change in momentum is =P1-P2= 5-5=0
yes, momentum is conserved.
What is the average velocity in the time interval 3 to 4
seconds?
Answer:
0 m/s.
Explanation:
The average velocity from 3 to 4 seconds is 0 m/s.
How many degrees should a planet move across the sky when completing one revolution around the Sun?
Answer: 18o degrees
Explanation: :)
The planet should move across the sky when completing one revolution around the Sun is 180 degrees.
What is Planet?Planets are large, spherical celestial objects that are neither stars nor their leftovers. The nebular hypothesis, which states that an interstellar cloud collapses out of a nebula to create a young protostar orbited by a proto-planetary disk, is the best theory currently available for explaining planet formation.
More than 5,000 exoplanets, as they are known, were found as a result of further astronomical advancements. These consist of hot Jupiter's, which are enormous planets that revolve around their parent.
The steady accumulation of matter accelerated by gravity, or accretion, is how planets expand within this disk. There are at least eight planets in the Solar System, including the gigantic planets Jupiter, Saturn, Uranus, and Neptune as well as the terrestrial planets Mercury, Venus, Earth, and Mars.
Therefore, the planet should move across the sky when completing one revolution around the Sun is 180 degrees.
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A 200.0 kg sled is being towed horizontally with a force of 25 N for 120 m in 30 seconds. What is the power of the applied force?
Answer:
.
Explanation:
A 100-turn coil has a radius of 7.50 cm and a resistance of 50.0 W. At what rate must a perpendicular magnetic field change to produce a current of 5.00 A in the coil
Answer:
dB / dt = -141.47 T / s
Explanation:
For this exercise let's use Faraday's law to calculate the induced electromotive force
E = - N dФ / dt
the magnetic flux is
Ф = B. A
in this case the direction of the field and the normal to area are parallel so the scalar product is reduced to the algebraic product
Ф = B A
we substitute
E = - N A dB / dt
the area of the loop is
A = π r²
we substitute
E = - N π r² dB / dt
in the exercise indicate that the resistance of the coil is R = 50.0 Ω,
E = i R
we substitute
i R = -N π r² dB / dt
dB / dT = - i R / N π r²
let's calculate
dB / dt = - 5.00 50.0 / (100 π 0.075²)
dB / dt = -141.47 T / s
Two objects, A and B, have the same volume and are completely submerged in a liquid, although A is deeper than B. Which object, if either, experiences the greater buoyant force?
a. Object B, because the closer an object is to the surface, the greater is the buoyant force.
b. Both objects experience the same buoyant force.
c. Object A, because, being at a greater depth, it experiences a greater pressure.
Answer:it would probably be C
Explanation:
In 1926 Babe Ruth hit a home run that was estimated to have landed 180. meters from home plate and to have reached a height of 21.3 meters. What was the initial velocity of the ball?
Answer:
v = 47.85 m / s , θ = 64.7º
Explanation:
This is a missile throwing exercise.
Let's find the speed to reach the maximum height, at this point the vertical speed is zero
[tex]v_{y}^{2}[/tex] = v_{oy}^{2} - 2 g y
0 = v_{oy}^{2} - 2gy
v_{oy} = √2gy
let's calculate
v_{oy} = √ (2 9.8 21.3)
v_{oy} = 20.43 m / s
now we can calculate the time it takes to get to this point
vy = v_{oy} - g t
t = v_{oy} / g
t = 20.43 / 9.8
t = 2.08 s
in projectile launching, the time it takes for the body to rise is the same as the time it takes to go down, so the total launch time is
[tex]t_{v}[/tex] = 2 t
t_{v} = 2 2.08 = 4.16 s
let's use the horizontal throw ratio
x = v₀ₓ t_{v}
v₀ₓ = x / t_{v}
v₀ₓ = 180 / 4.16
v₀ₓ = 43.27 m / s
initial velocity is
v = √ (v₀ₓ² + v_{oy}^{2})
v = √ (20.43² + 43.27²)
v = 47.85 m / s
with an angle of
tan θ = I go / vox
θ = tan⁻¹ (43.27 / 20.43)
θ = 64.7º