A car is at velocity of 20 km/h. If the car traveled 120 km in 3 hours at constant acceleration, what is its final velocity?
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Answer:

its temperature stays constant

Explanation:

Answer:

a = 1,838.17m/s²

Explanation:

centripetal acceleration a = v²/r

v is velocity of the car

r is the radius = 3.22km = 3220m

time t = 248

First is to find to velocity using the equation of motion:

v = u+gt

v = 0+(9.81)(248)

v = 2,432.88m/s

a = 2,432.88²/3220

a = 5,918,905.0944/3220

a = 1,838.17m/s²

The magnitude of the centripetal acceleration of the car is 1,838.17m/s²

Answer:

It is toward the center

Explanation:

light, water, carbon dioxide

Explanation:

c02 , h20 and light

Answer:

The most important is that the thermal conductivity of the armadillas several orders of magnitude lower than the thermal conductivity of the metal, therefore it is easier to maintain the temperature in winter

Explanation:

Cement and bricks are used in the construction of houses instead of metal, for several reasons

* The most important is that the thermal conductivity of the armadillas several orders of magnitude lower than the thermal conductivity of the metal, therefore it is easier to maintain the temperature in winter

* Metal has more oxidation problems than brick

* The cost of sheet metal is higher than the cost of cement brick.

Answer:

45.8 cm

Explanation:

To solve this, we will use the formula

5 / x² = 7/(1 - x)²

5 / x² = 7 / (1 - 2x + x²)

5 / 7 = x² / (1 - 2x + x²)

x = 0.5 * (√(35) - 5) meters

x = 0.5 * (5.916 - 5)

x = 0.5 * (0.916)

x = 0.458 or x = 45.8

The position where the third charge is placed along the x-axis so that it does not experience any net force because of the other two charges is 45.8 cm.

Given :

Two point charges of magnitudes +5.00 μC, and +7.00 μC are placed along the x-axis at x = 0 cm and x = 100 cm, respectively.

The following calculation can be used in order to determine the position where the third charge is placed along the x-axis so that it does not experience any net force because of the other two charges.

[tex]\rm \dfrac{5}{x^2}=\dfrac{7}{(1-x)^2}[/tex]

Simplify the above expression by cross multiplying.

[tex]5(x^2+1-2x)=7x^2[/tex]

[tex]\rm 5x^2 + 5 - 10x = 7x^2[/tex]

[tex]2x^2+2x-1=0[/tex]

Further, simplify the above expression in order to determine the value of x.

x = 0.458

x = 45.8 cm

Therefore, the correct option is b).

For more information, refer to the link given below:

https://brainly.com/question/24391667

Answer:

i am just trying it could be wrong too i am not sure about it but according to me the ans is (1)let ice be allowed to float naturally in the water

Explanation:

if u put water in ice or ice in water the temperature of water decreases and then the process gets slower but if u allow to float it then the temperature of water and surrounding air decreases and the heat is lost from air and water both so here the heat is more than only just water here it allows both to give heat and in 2nd option the heat is only lost by water and gained by icehere it allows only water to give heat so the heat is less in surrounding of ice in water so more heat more faster the process therefore i think the 1st option is correct

Answer:

4.44 hr

Explanation:

distance= rate*time

400km/(90 km/hr)=time

time=4.44 hr

Answer:

156 2/3 km/hr

Explanation:

Average speed is found by dividing total distance by total time.

180 km/hr in 2 hrs is 360 miles

200 km/hr in 4 hrs is 800 miles

120 km/hr in 6 hrs is 720 miles

Total time is 12 hrs; Total distance 1880 hrs

Divide distance by time and you have 156 2/3 km/hr. This is your average speed.

Answer:

TRUE

Explanation:

Answer:

True

Explanation:

Answer:

two positively charged objects

Explanation:

Answer:

v = 2√2 m/s

Explanation:

The following data were obtained from the question:

Height (h) = 10 m

Acceleration due to gravity (g) = 10 m/s²

Horizontal distance (s) = 4 m

Horizontal velocity (v) =.?

Next, we shall determine the time taken for the ball to get to the target.

This can be obtained as shown below:

Height (h) = 10 m

Acceleration due to gravity (g) = 10 m/s²

Time (t) =?

h = ½gt²

10 = ½ × 10 × t²

10 = 5 × t²

Divide both side by 5

t² = 10/5

t² = 2

Take the square root of both side.

t = √2 s

Finally, we shall determine the horizontal velocity as shown below:

Horizontal distance (s) = 4 m

Time (t) = √2 s

Horizontal velocity (v) =.?

s = vt

4 = v × √2

Divide both side by √2

v = 4 /√2

Rationalise the denominator

v = (4 /√2) × √2/√2

v = 4 × √2 / √2 × √2

v = 4 × √2 / 2

v = 2√2 m/s

Answer:

D

Explanation:

when you try to find out if it is positive, the line goes from left to right, and in this question the line is going upward.

Answer: A. Nuclear power produces radioactive waste.

Answer:

4th

Explanation:

Rise and fall of the water level on the sea shore

Answer:

12 cm

Explanation:

From what I got with my answer (8.192 cm) I went ahead and rounded it to the closest answer which is 12 cm. Hopefully im correct but if not, I apologize in advance.

Answer:

Hitting it or throwing it with force.

Answer:

.

Explanation:

Answer:

The father will walk 6 more meters and the son will walk 12 meters

Explanation:

Uniform Speed and Acceleration

This is a problem where two objects have different types of motion. The father walks at a constant speed and later, his son starts a constant acceleration motion in pursuit of him.

Let's start with the father, whose speed is v=1 m/s during t=6 seconds. He travels a distance:

[tex]x=vt=1*6=6\ m[/tex]

Now the son, starting from rest (vo=0) accelerates at a=2/3 m/s^2. His speed will increase and eventually, he will catch up with his father. Let's suppose it happens at a time t1.

The distance traveled by the son is given by:

[tex]\displaystyle xs=v_o.t_1+\frac{a.t_1^2}{2}[/tex]

Since vo=0:

[tex]\displaystyle xs=\frac{a.t_1^2}{2}[/tex]

The father will continue with constant speed and travels a distance of:

[tex]xf=v.t_1[/tex]

For them to catch up, the distance of the son must be 6 m more than the distance of the father, because of the leading distance he has already taken. Thus:

[tex]xs=xf+6[/tex]

Substituting the equations of each man:

[tex]\displaystyle \frac{a.t_1^2}{2}=v.t_1+6[/tex]

We know a=2/3, v=1:

[tex]\displaystyle \frac{2}{3}\cdot\frac{t_1^2}{2}=t_1+6[/tex]

Simplifying:

[tex]\displaystyle \frac{t_1^2}{3}=t_1+6[/tex]

Multiply by 3:

[tex]t_1^2=3t_1+18[/tex]

Rearranging:

[tex]t_1^2-3t_1-18=0[/tex]

Factoring:

[tex](t_1-6)(t_1+3)=0[/tex]

Solving:

[tex]t_1=6 , t_1=-3[/tex]

Since time cannot be negative, the only valid solution is

[tex]t_1=6\ s[/tex]

The distance traveled by the son in 6 seconds is:

[tex]\displaystyle xs=\frac{2/3\cdot 6^2}{2}[/tex]

[tex]xs=12\ m[/tex]

Note the father will travel

[tex]xf=1*6=6\ m[/tex]

This 6 m plus the 6 m he was ahead of the son, make them meet while walking at 6 seconds.

Answer: The father will walk 6 more meters and the son will walk 12 meters

Currently, the magnetic south pole lies about ten degrees distant from the geographic north pole, and sits in the Arctic Ocean north of Alaska. The north end on a compass therefore currently points roughly towards Alaska and not exactly towards geographic north.

The gravitational force between the spheres is

[tex]F_{\rm g}=\dfrac{G(188\,\mathrm{kg})(0.93\,\mathrm{kg})}{(0.27\,\mathrm m)^2}\approx1.6\times10^{-7}\,\mathrm N[/tex]

where G = 6.674 x 10⁻¹¹ N m²/kg².

The weight of the lighter sphere is

[tex]F_{\rm w}=(0.93\,\mathrm{kg})g\approx9.1\,\mathrm N[/tex]

where g = 9.80 m/s².

The ratio between the two forces is then

[tex]\dfrac{F_{\rm g}}{F_{\rm w}}\approx1.8\times10^{-8}[/tex]

Acceleration is the change in the velocity of the object with time. Acceleration is the same for both objects so both objects will reach the ground at the same time.

Given that both the object dropped at the same time. So the gravitational acceleration of both the objects will be the same which is nearly 10 m/s.

The force at object 1 is given below.

[tex]F_1 = m_1\times g = m_1\times a_1[/tex]

Where m1 is the mass of object 1 and a1 is the acceleration of object 1.

[tex]F _1 = 1\times 10 = 10 \;\rm N[/tex]

The acceleration of object 1 is calculated as below.

[tex]a_1 = \dfrac{F_1}{m_1}[/tex]

[tex]a_1=\dfrac{10}{1} = 10 \;\rm m/s^2[/tex]

The force at object 2 is given below.

[tex]F_2 = m_2\times g = m_2\times a_2[/tex]

Where m2 is the mass of object 2 and a2 is the acceleration of object 2.

[tex]F_2 = 2\times 10 =20 \;\rm N[/tex]

The acceleration of object 2 is calculated as below.

[tex]a_2 = \dfrac{F_2}{m_2}[/tex]

[tex]a_2=\dfrac{20}{2} = 10 \;\rm m/s^2[/tex]

Hence we can conclude that the acceleration of both the objects is the same at every point so they will reach the ground at the same time.

To know more about the acceleration, follow the link given below.

https://brainly.com/question/12134554.

Answer:

Lithium does not occur as the metal in nature. Is found combined in small amounts in nearly all igneous rocks and in the waters of many mineral springs. Spodumene, petalite, lepidolite, and amblygonite are the more important minerals containing lithium.

Lithium can be found in Lithium-ion batteries, some heat-resistant glass and ceramics, some grease lubricants, and some anti-depressant medications.

To find:-

Answer:-

Gauss's law in electrostatics states that the electric flux through a closed surface is equal to 1/ε0 times the charge enclosed by that surface, that is,

[tex]\implies \displaystyle \phi_E = \oint \vec{E} .\vec{ds} \\[/tex]

Also ,

[tex]\implies\displaystyle \oint \vec{E}.\vec{ds} =\dfrac{q}{\epsilon_0} \\[/tex]

Linear density of charge:-

It ise defined as charge per unit length. Mathematically,

[tex]\implies\displaystyle \lambda =\dfrac{q}{\ell} \\[/tex]

where ,

For figure see attachment.

Now let us assume that the linear density of charge is [tex]\lambda[/tex] . There is a point P near the wire at a distance of " r " from it , where we are interested in calculating the electrical field. Imagine a coaxial Gaussian cylinder of length [tex]\ell[/tex] , and radius " r " such that the point P lines on its surface.

Calculating Electrical flux through the cylinder:-

[tex]\implies\displaystyle \phi_E = 0 + 0 + \oint E.ds \\[/tex]

[tex]\implies\displaystyle\phi_E = \oint E.ds \ \cos0^o \\[/tex]

[tex]\implies\displaystyle \phi_E = \oint Eds \\[/tex]

[tex]\implies\displaystyle \phi_E = E\oint ds \\[/tex]

[tex]\implies\displaystyle \phi_E = E (2\pi r\ell) \ \ dots (1) \\[/tex]

From Gauss's law:-

[tex]\implies\displaystyle \phi_E =\dfrac{q}{\epsilon_0} \\[/tex]

[tex]\implies\displaystyle \phi_E = \dfrac{\lambda \ell}{\epsilon_0}\ \dots (2) \\[/tex]

Therefore , from equation (1) and (2) , we have;

[tex]\implies\displaystyle E \times 2\pi r \ell =\dfrac{\lambda\ell}{\epsilon_0}\\[/tex]

[tex]\implies\displaystyle \underline{\underline{\green{ E =\dfrac{1}{4\pi \epsilon_0}\dfrac{2\lambda}{r}}}}\\[/tex]

And we are done!

Answer:

No

Explanation:

S=d/t Speed equals distance divided by time. That's a helpful equation in this case. Leah's wave took 10 seconds, and the distance was 6 meters.

6/10=.6

Betty's wave took 10 seconds, but the distance was 60 meters this time.

60/10=6

We know that 6 and .6 are not the same numbers, so we can see that the waves aren't the same.

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