A car accelerating from rest for 20s to reach velocity of 15 m/s and it keeps on. moving with this velocity for 50s an then it applied the break
Stop in 30s what is the displacement?

WILL GIVE BRAINLY best answer with steps

Answers

Answer 1

Answer:

1125m

Explanation:

The car moves with a uniformly accelerated motion for 20s:

s = 1/2·a·t² + v0·t + s0 (note that vo = 0 and s0 = 0, with v0 being the initial velocity and s0 the initial displacement).

So: s = 1/2·a·t²

The acceleration will be: Δv/Δt = 15m/s / 20s = 0.75 m/s²

s1 = 1/2·0.75 m/s² · (20 s)^2 = 150m

Then it continues with the velocity he acquired (v = a·t = 0.75 m/s²·20s = 15 m/s):

s2 = vt = 15m/s·50s = 750m

The final acceleration, when stopping, will be:

a = Δv/Δt = -15m/s / 30s = -1/2 m/s²

s3 = 1/2·(1/2m/s²)·(30s)² = 225m.

Now we sum s1 with s2 and s3:

s1 + s2 + s3 = 150m + 225m + 750m = 1125m


Related Questions

If a force of 50 Newton's was applied to an object with a mass of 5 kilograms, what will the object's acceleration be?

Answers

Here’s my work to your question. I used Newton’s Second Law.
Force = mass * acceleration

A force of 50 N was applied to an object with a mass of 5 kg, then the acceleration of the object will be 10 m/s².

What is Acceleration?

The rate of change in an object's velocity with respect to time is known as acceleration in mechanics. The vector quantity of accelerations. The direction of the net force that is acting on an object determines its acceleration.

Since acceleration has both a magnitude and a direction, it is a vector quantity. Velocity is a vector quantity as well. The definition of acceleration is the change in velocity vector over a time interval divided by the time interval.

There are several types of acceleration :

Uniform AccelerationNon-Uniform AccelerationAverage Acceleration

According to the question, the given values are :

Force, F = 50 N

Mass, m = 5 kg

Force = m × a

a = 50 / 5

a = 10 m/s².

Hence, the acceleration of the object will be 10 m/s².

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A thin stream of water flows smoothly from a faucet and falls straight down. At one point, the water is flowing at a speed of 1=1.31 m/s . At a lower point, the diameter of the stream has decreased by a factor of 0.805 . What is the vertical distance ℎ between these two points?

Answers

Answer:

Explanation:

as the mass cannot change, the volume per unit time is also constant so the area of the stream times the velocity is constant

If the diameter is 1 where velocity is 1.31 m/s

area is proportional to the square of the diameter    A = (π/4)d²

1²(1.31) = 0.805²(v)

v = 1.31/0.805² = 2.02 m/s

v² = u² + 2as

2.02² = 1.31² + 2(9.81)h

h = 0.120819... m

h = 12.0 cm

Which of the following is NOT a function of the lens in the eye?
W
It can perform minor adjustments for distance.
It flattens when light rays from distant objects are to be focused.
It is a light receptor that generates nerve signals that are sent to the brain
It maintains its spherical shape to view nearby objects.

Answers

Answer:

the last one

Explanation:

For a wave, the _____ the amplitude, the _____ energy the wave carries.
Multiple choice question.

A)
larger, more

B)
smaller, more

C)
larger, less

D)
smaller, same

Answers

Answer:

HIGHER & MORE OR LARGER OR MORE

HENCE, THE ANSWER IS A. :)

Explanation:

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BRAINLIEST PLEASE I REALLY NEED IT

The work done by an electric force in moving a charge from point A to point B is 2.70 × 10‒3 J. The electric potential difference between the two points is VA ‒ VB = 50.0 V. What is the charge?

Answers

The charge moved by this electric force is [tex]5.4 \times 10^{-5} \; Coulombs[/tex].

Given the following data:

Work done = [tex]2.70 \times 10^{-3}\;Joules[/tex]Potential difference = 50.0 Volts

To determine the charge:

Mathematically, the work done by an electric force in moving a charge from one point to another is given by the formula:

[tex]W = PQ[/tex]

Where:

W is the work done.P is the electric potential difference.Q is the charge.

Making Q the subject of formula, we have:

[tex]Q =\frac{W}{P}[/tex]

Substituting the given parameters into the formula, we have;

[tex]Q =\frac{2.70 \times 10^{-3}}{50}\\\\Q =5.4 \times 10^{-5} \; Coulombs[/tex]

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How is the A He related to the A Hof a reaction?​

Answers

Answer:

by giving a person to person

What would the single sample Cohen's d value be if the difference in sample mean and hypothesized mean was 16, and the sample standard deviation was 4?

Answers

Answer:

Explanation:

To calculate an effect size, called Cohen's d , for the one-sample t-test you need to divide the mean difference by the standard deviation of the difference, as shown below. Note that, here: sd(x-mu) = sd(x) . μ is the theoretical mean against which the mean of our sample is compared (default value is mu = 0).

plz help ASAP I'll mark as brainliest ​

Answers

Hi there!

1.

Hooke's law states that:

F = -kx

k = Spring constant (N/m)

x = DISPLACEMENT from equilibrium (m)

Essentially, the force of a spring is PROPORTIONAL to its spring constant and its displacement from its equilibrium point.

2.

The force of the spring (T) is not proportional to the spring's length (l), but rather its DISPLACEMENT from its equilibrium length. (Δl)

3.

The equilibrium length is where the force of the spring (T) = 0N. Looking at the graph, the line intersects this value at l = 30cm.

4.

We can begin by looking at the given graph.

When the spring force = 4N, the total length of the spring is 35 cm.

Now, the EQUILIBRIUM length is 30 cm, so the total elongation is:

35 - 30 = 5 cm.

5.1.

If the spring elongates by 10 cm, the total length of the spring is:

30 + 10 = 40 cm

According to the graph, a length of 40 cm corresponds to a force of 8N.

5.2.

We can solve for the weight of the ball using the following:

W (weight) = m (mass) · acceleration due to gravity (10N/kg)

Using a summation of forces:

∑F = T - W

The elongation that we are solving for occurs at the equilibrium point (net force = 0 N), so:

0 = T - W

T = W = 8 N

5.3.

0 = T - Mg

T = Mg

Use the prior value of T and gravity to solve:

8 = 10M

m = 0.8 kg

Model how solutes dissolve into solvents. Describe how different types of solutes and solvents might attract or repel each other.

Answers

A solvent is any substance which is able to interact with a solute and dissolve it.

A solute is any substance that is able to interact with a solvent and dissolve in it. Usually, the solute must posses similar intermolecular forces as the solvent.

For this reason, polar solutes dissolve in polar solvents while nonpolar solutes dissolve in nonpolar solvents. In polar solutes, the ions or dipoles of the solute are able to interact with the dipoles of the solvent thereby pulling the solute particles apart in order to have solvent - solute interaction.

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A body with a uniform acceleration travels distances of 24m and 64m during the first two equal consecutive intervals of time, each of duration 4s. Determine the initial velocity and acceleration of the moving body.​

Answers

Answer:

Explanation:

Average velocity in the 24 m interval is 24 / 4 = 6 m/s

Average velocity in the 64 m interval is 64 / 4 = 16 m/s

There is a 4 second interval between the two points where average velocity equals actual velocity

a = Δv/t = (vf - vi) / t = (16 - 6) / 4 = 2.5 m/s²

s = v₀t + ½at²

24 = v₀(4) + ½(2.5)4²

4v₀ = 24 - 20

v₀ = 1 m/s

Not asked for but the velocity at the end of the first segment and beginning of the second segment is 11 m/s and final velocity is 21 m/s

5. average A body sets off from rest with a constant acceleration of 8.0 m/s? What distance will it have covered after 3.0 s? 6.

Answers

Answer:

[tex]\boxed {\boxed {\sf 36 \ meters}}[/tex]

Explanation:

We are asked to find the distance a body covers. We know the initial velocity, acceleration, and time, so we will use the following kinematic equation.

[tex]d= v_i t+ \frac {1}{2} \ at^2[/tex]

The body starts at rest with an initial velocity of 0 meters per second. The acceleration is 8 meters per second squared. The time is 3.0 seconds.

[tex]v_i[/tex]= 0 m/s a= 8 m/s²t= 3 s

Substitute the values into the formula.

[tex]d= (0 \ m/s)(3 \ s) + \frac{1}{2} (8 \ m/s^2)(3 \ s)^2[/tex]

Multiply the first set of parentheses.

[tex]d= ( 0 \ m/s * 3 \ s) + \frac{1}{2} ( 8 \ m/s^2)(3 \ s)^2[/tex]

[tex]d=0 \ m + \frac{1}{2} ( 8 \ m/s^2)(3 \ s)^2[/tex]

Solve the exponent.

(3 s)²= 3 s* 3 s= 9 s²

[tex]d= 0 \ m + \frac{1}{2}( 8 \ m/s^2)(9 \ s^2)[/tex]

Multiply again.

[tex]d= 0 \ m + \frac{1}{2} ( 72 \ m)[/tex]

[tex]d= 36 \ m[/tex]

The body will cover a distance of 36 meters.

The earth has a mass of 5.972 x 1024 Kg. You decide to
put the satellite in an orbit 400 Km above the surface of the earth which has a radius of 6,371 Km, so the total
distance from the center of the earth to the satellite is 6,771,000 m. What will you need the velocity of the
satellite to be to stay in orbit? Show your work

Answers

Answer:

Explanation:

You want the required centripetal force to equal gravity force

if m is the mass of the satellite

ma = mv²/R

a = v²/R

F = ma = GMm/R²

a = GM/R²

v²/R = GM/R²

v² = GM/R

v = √(GM/R)

v = √(6.674 x 10⁻¹¹(5.972 x 10²⁴)/6.771 x 10⁶)

v = 7.672 x 10³ m/s

The force as a function of displacement of a moving object is presented by the graph. How much work is done when the object moves from 5 m to 8 m? *

Answers

Answer:

Explanation:

Work is the area under the curve between the limits

W = ½(5)(8 - 5) = 7.5 J

The work done when an object moves from 5 m to 8 m is 7.5 J.

Work done

The work done in moving an object from one point to another is equal to the product of force and displacement of the object.

W = Fs

Area under a curve

The work done on an object is equal to area under the curve

The area between point 5 m and 8 m = ¹/₂ x (8 - 5) x 5 = 7.5 J

Thus, the work done when an object moves from 5 m to 8 m is 7.5 J.

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1. 1. are the charged parts of an atom.
a. Only electrons
b. Only protons
c. Neutrons only
d. Electrons and neutrons
e. Electrons and protons
f. Protons and neutrons

Answers

Answer:

e. Electrons and protons

Explanation:

16. The K-T boundary is a layer of rock that separates the time of the dinosaurs from
their extinction. According to the law of superposition which of the following is true?
A. Paleontologists would expect to find dinosaur bones below the K-T boundary but
not above.
B. Paleontologists would expect to find dinosaur bones far away from tectonic plate
boundaries where new crust is being created
C. Paleontologists would expect to find dinosaur bones above the K-T boundary but
not below.
D. Paleontologists would expect to find dinosaur bones close to tectonic plate
boundaries where new crust is being created

Answers

According to the law of superposition, the statement 'it is expected to find dinosaur bones below the K-T boundary but not above'' is TRUE. This boundary separates the Cretaceous and Tertiary periods.

The law of superposition is used by paleontologists to explain a sequence of sedimentary rock layers from the oldest layer at the base to reach the surface (newer).

Moreover, the K-T boundary is a boundary that separates sediments of the Cretaceous period from the Tertiary period.

This boundary (K-T boundary) dates approximately 65 million years (Mya) ago, i.e., the period in which dinosaurs became extinct.

Learn more about the law of superposition:

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A boy weighing 445 N swings on a 2-m long swing. If his horizontal speed at the lowest point is 3 m/s, what total force must the ropes holding the swing be able to withstand?

Answers

Explanation:

We need to calculate the centripetal force:

Fc = W + F

With Fc being the centripetal force, W the weight of the boy, F the centrifugal force (apparent).

We know that we can calculate the apparent centrifugal force thank to the formula:

F = (m·v²)/r = 204N

So we can write:

Fc = W + F = 445N + 204N = 649N

Using the formula below, calculate the kinetic energy of the 6 gram stone going 10 Mph
going 10 mph
KE = 1/2 Mass x Speed?
=

Answers

Answer:

Explanation:

A wonderful (NOT) mixed unit problem

convert mph to m/s

v = 10 mi/hr(5280 ft/mi)(12 in/ft)(2.54 cm/in) / (100 cm/m) / (3600 s/hr)

v = 4.4704 m/s

KE = ½(0.006)4.4704²

KE = 0.05995342848 J

KE = 0.06 J


A 25.0kg boy is sliding on a frictionless frozen lake at 5.00m/s to the north when he is struck by a 1.00kg
snowball moving at 15.0m/s from the west. If the snowball sticks to him, how fast, and in what direction,
does the boy move after the collision?

Answers

The final velocity of the boy after the collision with snowball is 4.84 m/s at 18.4⁰ north-east

The given parameters;

Mass of the boy, m₁ = 25 kgSpeed of the boy, u₁ = 5 m/sMass of the snowball, m₂ = 1.0 kgSpeed of the snow ball, u₂ = 15 m/s

The initial momentum of the boy is calculated as follows;

[tex]P_y = m_1 u_1\\\\P_y = 25 \times 5\\\\P_y = 125 \ kgm/s \ \ north[/tex]

The initial momentum of the snowball is calculated as follows;

[tex]P_x = m_2 u_2\\\\P_x = 1 \times 15 \ \\\\P_x = 15 \ kgm/s \ \ west[/tex]

The resultant momentum of the boy and the snowball after collision is calculate as follows;

[tex]P_f = \sqrt{P_y^2 + P_x^2} \\\\P_f = \sqrt{125^2 + 15^2} \\\\P_f = 125 .9 \ kgm/s[/tex]

The final velocity of the system boy-snowball system is calculated as;

[tex]v_f(m_1 + m_2)= P_f\\\\v_f = \frac{P_f}{m_1 + m_2} \\\\v_f = \frac{125.9}{25 + 1} \\\\v_f = 4.84 \ m/s[/tex]

The direction of the boy after the collision is calculated as follows;

[tex]\theta = tan^{-1}(\frac{v_y}{v_x} )\\\\\theta = tan^{-1} (\frac{5}{15} )\\\\\theta = 18.4 \ ^0[/tex]

Thus, the final velocity of the boy after the collision with snowball is 4.84 m/s at 18.4⁰ north-east

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What happens to the gravitational force between two objects if the distance between them triples?

A. The force increases by a factor of 9

B. The force decreases by a factor of 9

C. The force decreases by a factor of 3

D. The force increases by a factor of 3

Answers

So as two objects are separated from each other, the force of gravitational attraction between them also decreases. ... If the separation distance between any two objects is tripled (increased by a factor of 3), then the force of gravitational attraction is decreased by a factor of 9 (3 raised to the second power).

So the answer you are looking for is B.
The answer will be B.

Gravity obeys something called the inverse square law.

This means if distance increases by a factor of x, the force of gravity will decrease by a factor of x^2

For example, if distance increases by 2, the force would be 4 times weaker

If Distance increases by a factor of 3, the force will be 9 times weaker

6. A man with a mass of 75 kg standing on a skateboard is holding a medicine ball that has
a mass of 20 kg. If the man throws the ball to the left with a speed of 10 m/s,
a) What happens to the man on the skateboard?
b) What is the man's speed after throwing the ball?

Answers

Answer:

Explanation:

Conservation of momentum

a) the man and skateboard move to the right.

b) His speed depends on the reference frame of the ball speed.

If the speed of the ball is 10 m/s relative to ground and the man's final speed is v, then.

(75 + 20)(0) = 20(10) + 75(v)

v = -200/75 = -2.6666...

|v| = 2.7 m/s relative to the ground

This is the likely answer they are seeking.

If the ball is thrown with a speed of 10 m/s relative to the man

(70 + 20)(0) = 20(v + 10) + 75v

20v + 200 = - 75v

          200 = - 95v

               v = -2.105... m/s velocity or a speed of

              |v| = 2.1 m/s relative to ground

and the ball has a velocity of 10 - 2.1 = 7.9 m/s relative to ground.

One indicator NOT related to domestic violence is
violent attitudes
good nutrition
violations of court orders
substance abuse

Answers

Answer:

good nutrition

Explanation:

I think that one's pretty self explanatory

Select the correct answer.
What is the force that can cause two pieces of iron to attract each other?
A.
gravitational force
B.
magnetic force
C.
elastic force
D.
electrostatic force

Answers

Answer:

A. gravitational force always true.

B, C and D could be true under the correct conditions

PLEASE ANSWER THIS QUICK
GIVING BRAINLIEST TO THE ONE WHO ANSWERS


Rust is a compound that occurs when the element iron and oxygen combine. Do they create a physical or a chemical change?

Answers

Answer:

I think it's a chemical change.

Which type of muscle cell can have multiple nuclei

Answers

Answer:

Skeletal muscle cells

Explanation:

Skeletal muscle cells are long, cylindrical, and striated. They are multi-nucleated meaning that they have more than one nucleus. This is because they are formed from the fusion of embryonic myoblasts.

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What is the plot of the story the monkey and the crocodile

Answers

Answer:

the plot is about a crocodile who lives in a river.....

Explanation:

It is about a crocodile who lives in a river. He becomes friends with a monkey that lives on a tree on the river bank. Consequently, the monkey shares the fruits of the tree with his friend, the crocodile. Further, the crocodile takes a share for his wife.

What do these weapon stats mean?

Idle sway control is measured in Fc???

Flinch resistance is measured in N.

Answers

Answer:

its sort of like how Pounds are measured in lbs

Explanation:

Pounds are measured in lbs when they dont sound anything similar, same thing applies to gun technology.

In three to five sentences, identify the acid, base, conjugate acid, and conjugate base. Use patterns in the periodic table to explain why the substances you identified acted as the acid and the base in this reaction.

Answers

A conjugate acid is formed from the base  by accepting a proton from the acid .

A conjugate base is obtained from the Brownstead - Lowry acid when it looses a proton while the conjugate acid is obtained from the Brownstead - Lowry base when it accepts a proton. In the Brownstead - Lowry sense, acid base reaction involves the loss or gain of a proton.

Consider the hypothetical reaction; AH + :B ⇄ BH + :A. The specie BH is the conjugate acid while the specie  :B is the  Brownstead - Lowry base . The specie :A is the conjugate base while the specie AH is the  Brownstead - Lowry acid.

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9. If the force acting on a mass of 4kg accelerates it at a rate of 2m/s2, what will be the acceleration of the body when the force is doubled? ​

Answers

Explanation:

Force= mass× acceleration

Force= 4×2

= 8N

Doubling the force, 8×2= 16N

16= 4 × a

a= 16/4

= 4m/s²

An airplane accelerates from rest down a runway at 9.50 m/s2 for 29.3 seconds when it
takes off. What is the distance traveled while taking off?

Answers

Answer:

Explanation:

s = ½at²

s = ½(9.50)(29.3²) = 4,077.8275

s = 4080 m

when rounded to the three significant digits of the question numerals.

You have a pendulum clock made from a uniform rod of mass M and length L pivoting around one end of the rod. Its frequency is 1 radian/sec. The pivot breaks. Though the mass change is negligible, you need to rehang the rod halfway between the old pivot point and the middle of the rod. The new oscillation frequency is:
A. 0.88 rad/sec
B. 1.13 rad/sec
C. 1.07 rad/sec
D. 0.92 rad/sec

Answers

The new oscillation frequency of the pendulum clock is 1.14 rad/s.

     

The given parameters;

Mass of the pendulum, = M Length of the pendulum, = LInitial angular speed, [tex]\omega _i[/tex] = 1 rad/s

The moment of inertia of the rod about the end is given as;

[tex]I_i = \frac{1}{3} ML^2[/tex]

The moment of inertia of the rod between the middle and the end is calculated as;

[tex]I_f = \int\limits^L_{L/2} {r^2\frac{M}{L} } \, dr = \frac{M}{3L} [r^3]^L_{L/2} = \frac{M}{3L} [L^3 - \frac{L^3}{8} ] = \frac{M}{3L} [\frac{7L^3}{8} ]= \frac{7ML^2}{24}[/tex]

Apply the principle of conservation of angular momentum as shown below;

[tex]I _i \omega _i = I _f \omega _f\\\\\frac{ML^2}{3} (1 \ rad/s)= \frac{7ML^2}{24} \times \omega _f\\\\\frac{24 \times ML^2}{3 \times 7 ML^2} (1 \ rad/s)= \omega _f\\\\1.14 \ rad/s = \omega _f[/tex]

Thus, the new oscillation frequency of the pendulum clock is 1.14 rad/s.

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