Answer:
The exposed metal rusts is an example of a chemical change because rust is an example of a chemical change in objects for example bicycles, scooters, etc.
What is the volume of a substance that has a mass of 59 g and a density of 1.98 g/mL?
(show all work)
Answer:
29.8
Explanation:
The formula for volume is mass/ density, so 59/1.98. 29.8 is the answer.
a compound has a molecular formular of C12H24O6.What is the compound's empirical formula
Answer:
The empirical formula for C12 H24 O6 is C2 H4 O.
Answer:
We are given the formula of the compound:
C12H24O6
The empirical formula of a molecular formula is the lowest whole number ratio between the number of atoms of each element
The ratio of C to H to O in the given formula is :
12 : 24 : 6
we notice that all 3 of the numbers have 6 in common. Dividing all three of the numbers by 6, we get:
2 : 4 : 1
Hence, the ratio of Carbon to Hydrogen to Oxygen in the empirical formula of the given compound is 2 : 4 : 1 ,
Empirical Formula = C2H4O
help me please loves
Answer:
K and ba
Explanation:
Answer: K and Ba
Explanation:
Selenium has six valence electrons. What is the valence of selenium?
HELP ILL MARK BRAINLEST
The image below shows a model of the atom. Which subatomic particle does the arrow in
the image below identify?
?
A. electron
B. neutron
C. orbital
D. proton
The correct answer is A. Electron
Explanation:
The model of this atom depicts the nucleus of this in the center of the model, this section of the atom contains sub-particles known as protons and neutrons. Moreover, in the atom, the nucleus is surrounded by three sub-particles that orbit or move around the nucleus. These sub-particles are the electrons; these differ from other sub-particles because they have a negative charge and they are not part of the nucleus. Also, these move around the nucleus is orbits, although they move similarly to waves. According to this, the correct answer is A.
An electrochemical cell has an Eocell of 1.50 V and transfers 1 mole of electrons. The Faraday constant is 96,485 C/mol e-.
What is the value of delta G?
Answer:
ΔG° = -1.45 × 10⁵ J
Explanation:
Step 1: Given data
Standard cell potential (E°cell): 1.50 VMoles of electrons transferred (n): 1 mol e⁻Faraday constant (F): 96,485 C/mol e⁻Step 2: Calculate the standard Gibbs free energy change (ΔG°)
We will use the following expression.
ΔG° = -n × F × E°cell
ΔG° = -1 mol e⁻ × 96,485 C/mol e⁻ × 1.50 V
ΔG° = -1.45 × 10⁵ J
By apply Gibbs's free energy, the value of delta G is equal to -144727.5 Joules.
Given the following data:
Faraday constant = 96,485 C/mol e-[tex]E^{ \circ}_{cell}[/tex] = 1.50 VoltsNumber of moles of electrons = 1 molTo determine the value of delta G, we would apply Gibbs's free energy:
Mathematically, Gibbs's free energy is given by the formula:
[tex]\Delta G^\circ = -nFE^{ \circ}_{cell}[/tex]
Where:
F is Faraday constant.n is the number of moles.[tex]E^{ \circ}_{cell}[/tex] is the electromotive force.Substituting the given parameters into the formula, we have;
[tex]\Delta G^\circ = -1 \times 96485 \times 1.50[/tex]
[tex]\Delta G^\circ = -144727.5[/tex]
Delta G = -144727.5 Joules
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Write the net ionic equation for the reaction of aqueous solutions of ammonium chloride and iron(III) hydroxide.
Answer:
[tex]Fe(OH)_3(s)\rightarrow Fe^{3+}(aq)+3OH^-(aq)[/tex]
Explanation:
Hello.
In this case, for the reaction between aqueous solutions of ammonium chloride and iron (III) hydroxide, we have the following complete molecular reaction:
[tex]3NH_4Cl(aq)+Fe(OH)_3(s)\rightarrow 3NH_4OH+FeCl_3[/tex]
And the full ionic equation, taking into account that the iron (III) hydroxide cannot be dissolved as it is insoluble in water:
[tex]3NH_4^+(aq)+3Cl^-(aq)+Fe(OH)_3(s)\rightarrow 3NH_4^+(aq)+3OH^-(aq)+Fe^{3+}(aq)+3Cl^-(aq)[/tex]
Finally, the net ionic equation, considering that spectator ions are NH₄⁺, Cl⁻ as they are both the left and right side, therefore, the net ionic equation is:
[tex]Fe(OH)_3(s)\rightarrow Fe^{3+}(aq)+3OH^-(aq)[/tex]
Best regards.
The net ionic equation for the reaction of aqueous solutions should be Fe(Oh)3 ➡Fe3+(aq) + 3OH^-(aq).
Net ionic equation:
When the reaction lies between the between aqueous solutions of ammonium chloride and iron (III) hydroxide
So, here the total reaction should be
3NH4Cl(aq) + Fe(OH)3(s) ➡ 3NH4OH + FeCl3
So, here net ionic equation, considering that spectator ions are NH₄⁺, Cl⁻ since they are both the left and right sides.
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I don’t really understand, if anybody can help I’ll really appreciate it ! Thank you.
Answer:
175
Explanation:
Reactions are classified as either exothermic or endothermic. . ____________ reactions feel hot (e.g., a burning campfire), whereas _________reactions feel cool.
Answer:
Exothermic reactions feel hot
Endothermic reactions feel cool
Explanation:
In an exothermic reaction, heat is given out by the system. The energy of the reactants is greater than that of the products hence the excess energy is given off as heat. The reaction vessel feels hot.
In an endothermic reaction, the energy of products is greater than that of the reactants hence energy is taken into the system and the reaction vessel feels cool.
Please help me ! Thank you
Answer:
10
Explanation:
How many atoms of Chlorine are in 1.00 mol of Chlorine gas?
6.022 x 10∧23
3.01 x 10∧23
6.022 x 10∧24
Answer:
6.02 × 10²³ atoms Cl₂
Explanation:
Avagadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
Step 1: Define
1.00 mol Cl₂ (g)
Step 2: Use Dimensional Analysis
[tex]1.00 \hspace{3} mol \hspace{3} Cl_2(\frac{6.02(10)^23 \hspace{3} atoms \hspace{3} Cl_2}{1 \hspace{3} mol \hspace{3} Cl_2} )[/tex] = 6.02 × 10²³ atoms Cl₂
Methanol has a density of 0.79g/ml: Calculate the mass of 589ml of methanol.
Answer:
The answer is 465.31 gExplanation:
The mass of a substance when given the density and volume can be found by using the formula
mass = Density × volumeFrom the question we have
mass = 0.79 × 589
We have the final answer as
465.31 gHope this helps you
I need help with this please
Thank you
Answer:
From fastest to slowest its: (4)A to B, (1)E to F, (3)C to D, (2)D to E
Explanation:
The steeper the line is the faster she went. D to E she didn't make any progress because the line is straight. Sry I'm terrible at explaining things.
Someone please help me pass gen chem....
Suppose a boil water notice is sent out advising all residents in the area to boil their water before drinking it or using it for cooking. You need to boil 16.5 L of water using your natural gas (primarily methane) stove. What volume of natural gas is needed to boil the water if only 17.9% of the heat generated goes towards heating the water. Assume the density of methane is 0.668 g/L, the density of water is 1.00 g/mL, and that the water has an initial temperature of 20.4 °C. Enthalpy of formation values can be found in this table. Assume that gaseous water is formed in the combustion of methane.
Answer:
Solution-
From the question the volume of water = 18 L = 18000 mL
Now we can find the mass of water = (volume of water) * (density of water)
mass of water = (18000 mL) * (1.00 g/mL)
mass of water = 18000 g
Now we find the heat required to boil water = (mass of water) * (specific heat water) * (final temperature - initial temperature)
putting the value the heat required to boil water = (18000 g) * (4.184 J/g.oC) * (100 oC - 22.7 oC)
heat required to boil water = 5821617.6 J
heat required to boil water = 5821.62 kJ
The heat given by the combustion = (heat required to boil water) / (percent of heat taken by boiling)
Heat given by combustion = (5821.62 kJ) / (19.4 /100)
Therefore the heat given by combustion = (5821.62 kJ) / (0.194)
Heat given by combustion = 30008.35 kJ
As we know that the enthalpy of combustion of methane = 802.5 kJ/mol
The moles methane used = (Heat given by combustion) / (enthalpy of combustion of methane)
moles methane used = (30008.35 kJ) / (802.5 kJ/mol)
So the moles methane used = 37.39 mol
Now the mass methane = (moles methane used) * (molar mass methane)
The mass methane = (37.39 mol) * (16.04 g/mol)
The mass methane = 599.74 g
Now the volume methane = (mass methane) / (density of methane)
volume methane = (599.7356 g) / (0.660 g/L)
volume methane = 908.69 L
hope helped!!
plz mark brainliest:DD
The volume of natural gas needed to boil the water if only 17.9% of the heat is generated towards heating water is ; 918.70 L
Using the given data :
Volume of water = 16.5 L = 16500 mL
mass of water = 16500 g ( 16500 mL * 1.00 g/mL )
Density of methane = 0.668 g/L
Density of water = 1.00 g/mL
First step : determine the heat needed to boil the water
Heat required = mass of water * specific heat water * ( Δ T )
= 16500 * 4.184 * ( 100 - 20.4 ) = 5495265.6 J
= 5495.265 kJ
∴ Heat required to boil water = 5495.265 kJ
next step ; determine the heat given by combustion
heat given by combustion = ( Heat required to boil water) / ( % of heat generated )
Heat given by combustion = ( 5495.265 ) / ( 17.9 % )
= 30699.80 kJ
Enthalpy of methane combustion = 802.5 kJ/mol
∴ moles of methane used = ( 30699.80 ) / ( 802.5 ) = 38.26 mol
next ; determine the mass of methane ( natural gas )
= ( moles of methane used ) * ( molar mass )
= 38.26 * 16.04 g/mol = 613.69 g
Final step : Calculate the volume of natural gas is needed to boil the water
= mass of natural gas / density of methane
= 613.69 g / 0.668 g/L
= 918.70 L
Hence we can conclude that the volume of natural gas needed to boil water if only 17.9% of the heat is 918.70 L .
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what’s the most abundant isotope of lawrencium
Answer:
266Lr
Thirteen isotopes of lawrencium are currently known; the most stable is 266Lr with a half-life of 11 hours, but the shorter-lived 260Lr (half-life 2.7 minutes) is most commonly used in chemistry because it can be produced on a larger scale.
Explanation:
hopefully that helps you
How many atoms are in 10 g of He
Answer:
6.7
⋅
10
23
atoms of H
Explanation:
Determine the value of the equilibrium constant (report your answer to three significant figures) for the following reaction if an equilibrium mixture contains 0.010 mol of solid PbBr2, and is 0.0100 M in Pb2+ ions and 0.0250 M in Br1- ions. Use the notation 4.31e-5 to indicate a number such as 4.31 x 10-5.
Answer:
6.25e-6 is the value of the equilibrium constant
Explanation:
we have this equation
[tex]PbBr(s) ----- Pb^{2+}(aq) + 2Br(aq)[/tex]
When at a state of equilibrium,
we have the concentration of Pb^2+ to be 0.01
we have the concentration of Br^- to be 0.025
the equilibrium constant concentration of both pure solids and liquid s are said to be equal to 1
[PbBR2] = 1
such tht
Keq = [Pb^2+] x [Br-]^2
we already know the values of these from the above.
0.01x0.025^2
= 0.01 x 0.000625
= 0.00000625
= 6.25 x 10^-6
= 6.25e^-6
Do you think there’s an advantage of process 1 over process 2 for this species?
Answer:
witch one witch species witch bone of 1 and 2
Answer:
Yes, process 1 has an advantage over process 2 for the planarian worm. Process 1 requires only one parent. If the planarian can’t find a mate, the life cycle will continue because it can still reproduce.
Explanation:
i did it
3. A student took a calibrated 200.0 gram mass, weighed it on a laboratory balance, and
found it read 196.5 9. What was the student's percent error?
Answer:
The answer is 1.71 %Explanation:
The percentage error of a certain measurement can be found by using the formula
[tex]P(\%) = \frac{error}{actual \: \: number} \times 100\% \\ [/tex]
From the question
actual mass = 200 g
error = 200 - 196.59 = 3.41
We have
[tex]p(\%) = \frac{3.41}{200} \times 100 \\ = 1.705[/tex]
We have the final answer as
1.71 %Hope this helps you
An insulated container is used to hold 47.0 g of water at 23.5°C. A sample of copper weighing 10.3 g is placed in a dry test tube and
heated for 30 minutes in a boiling water bath at 100.0°C. The heated test tube is carefully removed from the water bath with laboratory
tongs and inclined so that the copper slides into the water in the insulated container. Given that the specific heat of solid copper is
0.385 J/(g.°C), calculate the maximum temperature of the water in the insulated container after the copper metal is added.
Answer:
[tex]T_f=25.0\°C[/tex]
Explanation:
Hello.
In this case, considering that the sample of hot copper is submerged into the water and the container is isolated, the heat lost by the copper is gained by the water so we can write:
[tex]Q_{Cu}=-Q_w[/tex]
In terms of mass, specific heat and temperature we write:
[tex]m_{Cu}C_{Cu}(T_f-T_{Cu})=-m_wC_w(T_f-T_w)[/tex]
Whereas the final temperature is the same for both copper and water because they are in contact until thermal equilibrium is reached. In such a way, the required maximum temperature no more than the equilibrium temperature and is computed as shown below:
[tex]T_f=\frac{m_{Cu}C_{Cu}T_{Cu}+m_wC_wT_w}{m_{Cu}C_{Cu}+m_wC_w}[/tex]
Thus, plugging the given data in the formula, we obtain:
[tex]T_f=\frac{10.3g*0.385\frac{J}{g\°C}*100\°C +47.0g*4.184\frac{J}{g\°C}*23.5\°C }{10.3g*0.385\frac{J}{g\°C}+47.0g*4.184\frac{J}{g\°C}}\\\\T_f=25.0\°C[/tex]
Which is a small change considering the initial one, because the mass of water is greater than the mass of copper as well as for the specific heats.
Best regards!
The maximum temperature of the water in the insulated container after the copper metal is added is 25 °C
From the question given above above, the following data were obtained:
Mass of water (Mᵥᵥ) = 47 g
Temperature of water (Tᵥᵥ) = 23.5°C
Specific heat capacity of water (Cᵥᵥ) = 4.184 J/gºC
Mass of copper (M꜀) = 10.3 g
Temperature of copper (M꜀) = 100 °C
Specific heat capacity of copper (C꜀) = 0.385 J/gºC
Equilibrium temperature (Tₑ) =?The equilibrium temperature of the mixture can be obtained as follow:
Heat loss by copper = Heat gained by water
Q꜀ = Qᵥᵥ
M꜀C꜀(M꜀ – Tₑ) = MᵥᵥCᵥᵥ(Tₑ– Mᵥᵥ)
10.3 × 0.385 (100 – Tₑ) = 47 × 4.184 (Tₑ – 23.5)
3.9655 (100 – Tₑ) = 196.648 (Tₑ – 23.5)
Clear bracket
396.55 – 3.9655Tₑ = 196.648Tₑ – 4621.228
Collect like terms
396.55 + 4621.228 = 196.648Tₑ + 3.9655Tₑ
5017.778 = 200.6135Tₑ
Divide both side by 200.6135
Tₑ = 5017.778 / 200.613
Tₑ = 25 °CThus, the equilibrium temperature of the mixture is 25 °C. Therefore, the maximum temperature of the water in the insulated container is 25 °C
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Help :( the blue boxes are clickable
Answer:
I am sure they are why won't they
Which 2 letters have the most kinetic energy?
W
X
Y
Z
Answer:
See Explanation (X and Z)
Explanation:
The question has missing details as the attachment that illustrates the graph is missing.
I'll answer this question using the attached.
Kinetic energy increases as height decreases
Base on the attachment, from order of highest height to the least, we have:
W
Y
Z
X
So, we can conclude that X has the highest kinetic energy and it is immediately followed by Z
Hence:
X and Z answers the question
What happens when the elements in group 2 react with water?
Answer:
The Group 2 metals become more reactive towards the water as you go down the Group.
Explanation:
These all react with cold water with increasing vigour to give the metal hydroxide and hydrogen. ... You get less precipitate as you go down the Group because more of the hydroxide dissolves in the water. Summary of the trend in reactivity.
Please mark me brainliest! hope this helped!
God bless!
How do the test variables (independent variables) and outcome variables (dependent variables) in an experiment compare? A. The test variables (independent variables) and outcome variables (dependent variables) are the same things. B. The test variable (independent variable) controls the outcome variable (dependent variable). C. The test variable (independent variable) and outcome variable (dependent variable) have no affect on each other. D. The outcome variable (dependent variable) controls the test variable (independent variable).
Answer:
I'm on the exact same queston
Answer:
The test variable (independent variable) controls the outcome variable (dependent variable)
Explanation:
its right on study island
A student reacts 5.0 g of sodium with 10.0 g of chlorine and collect 5.24 g of sodium chloride. What is the percent yield of this combination reaction
Answer: The percent yield of this combination reaction is 41.3 %
Explanation : Given,
Mass of [tex]Na[/tex] = 5.0 g
Mass of [tex]Cl_2[/tex] = 10.0 g
Molar mass of [tex]Na[/tex] = 23 g/mol
Molar mass of [tex]Cl_2[/tex] = 71 g/mol
First we have to calculate the moles of [tex]Na[/tex] and [tex]Cl_2[/tex].
[tex]\text{Moles of }Na=\frac{\text{Given mass }Na}{\text{Molar mass }Na}[/tex]
[tex]\text{Moles of }Na=\frac{5.0g}{23g/mol}=0.217mol[/tex]
and,
[tex]\text{Moles of }Cl_2=\frac{\text{Given mass }Cl_2}{\text{Molar mass }Cl_2}[/tex]
[tex]\text{Moles of }Cl_2=\frac{10.0g}{71g/mol}=0.141mol[/tex]
Now we have to calculate the limiting and excess reagent.
The balanced chemical equation will be:
[tex]2Na+Cl_2\rightarrow 2NaCl[/tex]
From the balanced reaction we conclude that
As, 2 mole of [tex]Na[/tex] react with 1 mole of [tex]Cl_2[/tex]
So, 0.217 moles of [tex]Na[/tex] react with [tex]\frac{0.217}{2}=0.108[/tex] moles of [tex]Cl_2[/tex]
From this we conclude that, [tex]Cl_2[/tex] is an excess reagent because the given moles are greater than the required moles and [tex]Na[/tex] is a limiting reagent and it limits the formation of product.
Now we have to calculate the moles of [tex]NaCl[/tex]
From the reaction, we conclude that
As, 2 mole of [tex]Na[/tex] react to give 2 mole of [tex]NaCl[/tex]
So, 0.217 mole of [tex]HCl[/tex] react to give 0.217 mole of [tex]NaCl[/tex]
Now we have to calculate the mass of [tex]NaCl[/tex]
[tex]\text{ Mass of }NaCl=\text{ Moles of }NaCl\times \text{ Molar mass of }NaCl[/tex]
Molar mass of [tex]NaCl[/tex] = 58.5 g/mole
[tex]\text{ Mass of }NaCl=(0.217moles)\times (58.5g/mole)=12.7g[/tex]
Now we have to calculate the percent yield of this reaction.
Percent yield = [tex]\frac{\text{Actual yield}}{\text{Theoretical yield}}\times 100[/tex]
Actual yield = 5.24 g
Theoretical yield = 12.7 g
Percent yield = [tex]\frac{5.24g}{12.7g}\times 100[/tex]
Percent yield = 41.3 %
Therefore, the percent yield of this combination reaction is 41.3 %
5 advantages of storing oil underground in salt dome?
Answer:
Salt domes storage has advantages in cost, security, environmental risk, and maintenance. Salt formations offer the lowest cost, most environmentally secure way to store crude oil for long periods of time. Stockpiling oil in artificially-created caverns deep within the rock-hard salt costs historically about $3.50 per barrel in capital costs. Storing oil in above ground tanks, by comparison, can cost $15 to $18 per barrel - or at least five times the expense. Also, because the salt caverns are 2,000-4,000 feet below the surface, geologic pressures will sea; any crack that develops in the salt formation, assuring that no crude oil leaks from the cavern. An added benefit is the natural temperature differential between the top of the caverns and the bottom - a distance of around 2,000 feet; the temperature differential keeps the crude oil continuously circulating in the caverns, giving the oil a consistent quality.
How many moles would be in 24.23 grams of SrSO4?
Use two digits past the decimal for all values.
Answer:
about 0.13 mol
Explanation:
To find number of mols when given grams you first have to find the molar mass of the compound. This is done by adding up the atomic masses of the element in the compound. So Sr= 88 g/mol S=32 g/mol and O=16 g/mol. Then 88+32+(16x4)=184. Then using this you can convert from grams to mols by dividing the grams by the molar mass. So, 24.23/184 equals about 0.13 mol.
Please help
What is an element
Answer:
An element is atoms with the same number of protons.
Explanation:
Protons, electrons, and neutrons.
Check all of the boxes that are true about the proton:
it is outside the nucleus
it has a positive charge
it has no mass
it has a negative charge
it is inside the nucleus
it is the same as the atomic number
it is the same as the number of neutrons
75% of the isotopes have a mass
Answer:
it is outside the nucleus F
it has a positive charge T
it has no mass F
it has a negative charge F
it is inside the nucleus ...it is part OF the nucleus.
it is the same as the atomic number T
it is the same as the number of neutrons F
75% of the isotopes have a mass ima just guess cuz i dunno about this one...i think it matters on the atom element.
Explanation:
What was the atomic theory about?
A. The properties of the nucleus
B. The existence of isotopes
C. The structure of the atom
D. The existence of electrons
Answer:
The structure of the atom