Gravitational potential energy is the energy stored in an object as the result of its vertical position or height. It can be calculated as its weight times the height. This is:
[tex]\boxed{U_g=W\cdot h=mgh}[/tex]
Where:
W is the weight of the objectm is the massg is gravitational accelerationh is the heightSolving for the h:
[tex]h=\dfrac{U_g}{mg} = \dfrac{35944\;J}{310\;kg\cdot 9.8\;m/s^2} = 11.8\;m[/tex]
R/ The car is parked 11.8 m above ground
A bird perched in a tree is balanced or unbalanced
Answer: Balanced
Explanation: When a bird is perched on a tree it is sitting still will stay still if the forces acting on it are balanced.
A boy throws a tell ball straight up . disregarding any effects of air resistance, the forces acting 9n the ball untill it returns to the ground is are
WHAT IS CHANGES IN SOLID MATERIALS
Answer: Solid to a Liquid Liquid to a Solid Liquid to a Gas Gas to a Liquid Solid to a Gas Gas to a Solid
Explanation:
80g of kerosene was burned to raise the temperature of 3 l of water to 90c ⁰C. What is the efficiency of the burner?
Answer:
363
Explanation:
80g of kerosene was burned to raise the temperature
k = 90+273
= 363
Have you ever written a bio-data or an application letter? Share your experience in the
space below. (e.g. How did you find the experience? What was hard? What was easy?)
Leave the space blank if you have never written any of these.
Answer:
I found the experience tasking
Explanation:
I wouldn't say it was hard, neither was it easy. I'd rather go for something like it being tasking. It's worthy of note that it was my first time, and I think it's very normal especially when one hasn't been doing something of that nature previously. Of course I did my draft, which unsurprisingly happened to be not good enough, and I had to look for templates to guide me through the acceptable way.
I still did it in my own way, but in the right way. Ever since then though, I have never stuttered when writing application letters, as it had since then seem inborn
The experience of writing a bio-data or an application letter was quite a tasking goal, where proper structure is required.
The given problem is based on the fundamentals of bio-data. Biodata is a document that is used to display the biographical data about the work experience in any organization.
As per my experience it was neither hard nor easy. I'd rather go for something like it being tasking. It's worthy of note that it was my first time, and I think it's very normal especially when one hasn't been doing something of that nature previously. I did my draft, which unsurprisingly happened to be not good enough, and I had to look for templates to guide me through the acceptable way. I still did it in my own way, but in the right way. Ever since then though, I have never stuttered when writing application letters, as it had since then seem inborn.Thus, it is concluded that writing a bio-data or an application letter was quite a tasking goal, where proper structure is required.
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When the magnetic flux through a coil of wire changes, what is generated between the ends of the coil? Which equation predicts this?
Answer:
induced electromotive force (Voltage) E = - N dΦ / dt
Explanation:
When the magnetic flux this coil induces a current in each turn of the coil, which is why an induced electromotive force (Voltage) appears at the ends of the coil.
This phenomenon is fully explained by Faraday's law
E = - dΦ / dt
where in the case of a coil with N turns of has
E = - N dΦ / dt
Rl flux is the product of the normal to the area by the magnetic field, in this case the flux changes so we can assume that the area of the coil is constant
Suppose that a brass rod 2.0 m long expands 0.2 cm when its temperature is increased a certain amount. By how much will a brass rod 80 m long expand with the same change in temperature?
Answer:
0.08 m
Explanation:
Linear expansivity brass = 2 * 10^-5 C
Linear expansivity = change in length / (initial length * θ)
Change in length = 0.2cm = 0.002m
Initial length = 2m
2 * 10^-5 = 0.002 / (2 * θ)
(2 * 10^-5 * 2θ) = 0.002
4 * 10^-5θ = 0.002
θ = 0.002 / 4 * 10^-5
θ = 2 * 10^-3 / 4 * 10^-5
θ = 0.5 * 10^2
θ = 50°C
For a rod of original length 80m at the same temperature of 50°C
Linear expansivity = change in length / (initial length * θ)
Change in length = dL
2 * 10^-5 = dL / (80 * 50)
2 * 10^-5 * 80 * 50 = dL
160 * 10^-5 * 50 = dL
8000 * 10^-5 = dL
0.08 m = dL
Hence, change in length = 0.08m
What is the acceleration a of the refrigerator 4 s after the person begins pushing on it with a force of 400 N?
Answer:
What is the acceleration a of the refrigerator 4 s after the person begins pushing on it with a force of 400 N? a=2m/s^2 Applying Newton's 2nd law, a=Fnet/m=(400N)/(200kg)=2m/s^2. The acceleration is constant.
Explanation:
The person begins to push a refrigerator with a force of 400 N. So, the acceleration of the refrigerator will be 2 m/s².
What is Acceleration?In mechanics, acceleration is the measure of how rapidly an object's velocity changes over time. It is a vector quantity. An object's acceleration depends on the direction of the net force exerted on it.
A vector quantity, acceleration is something that has both a magnitude and a direction. As a vector quantity, velocity is also. The ratio of the velocity vector change over a time interval to that interval is the definition of acceleration.
There are several types of acceleration :
Uniform AccelerationNon-Uniform AccelerationAverage AccelerationAccording to the question, the given values are :
Force applied to the refrigerator is 400 N.
The mass of the refrigerator is 200 kg.
Use the 2nd law of newton,
[tex]Force= mass*acceleration[/tex]
Acceleration = 400/200
Acceleration = 2 m/s².
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What are the 6 uses of electromagnet?
A food processor draws 8.47 A of current when connected to a potential difference of 110 V.
a. What is the power consumed by this appliance?
b. How much electrical energy is consumed by this food processor monthly (30 days) if it is used on average of 10.0 min every day?
c. Assume that the price of electrical energy is 7.00 $/kWh. What is the monthly cost of using this food processor?
2. The electric meter in a house indicates that the refrigerator consumes 70.0 kWh in a week.
a. What is the power consumption of the refrigerator?
b. Assuming it is connected to a potential difference of 120 V , how much current does the refrigerator draw?
3. The heating element of an electric broiler dissipates 2.8 kW of power when connected to a potential difference of 120 V.
a. What is the resistance of the element?
b. How much current does the broiler draw? Use two ways to find out, and verify your answer.
Answer:
i want the answer
Explanation:i want the answer
a. The power consumed by this appliance is 931.7W
b. The electrical energy is consumed by this food processor monthly (30 days) if it is used on average of 10.0 min every day is 4.65kWh
c. The monthly cost of using this food processor is 32.55 $
What is power?
The rate of consumption of energy is power. it is given by the product of potential difference(V) and current(I)
a. P = VI
here V = 110V . I = 8.47 A
P = 110 x 8.47 = 931.7W
hence power consumed is 931.7 W
b. electrical energy consumed by this food processor monthly (30 days) if it is used on average of 10.0 min every day is
E = P/t
Here, P = 931.7 W = 0.93kW
t = 10 x 30 = 300 min = 5 h
So, E =0.93 x 5 = 4.65 kWh
hence electrical energy consumed is 4.65kWh
c. The monthly cost of using the food processor is
given ,
Cost of one unit is 7.00$
Cost of 4.65 unit will be 7.0 x 4.65 = 32.55$
monthly cost of using the food processor is 32.55$
2.
a. Power consumption of refrigerator is 416 W
P = E/t
Here, E = 70 kwh . t = 1 week = 168 h
So, P= 70/168 = 0.416 kW = 416 W
b. Current drawn by the refrigerator is 3.46A
P = VI
Here, V = 120V, P = 416 W
So, I = P/V = 416/120 = 3.46 A
3.
a. The resistance of the element is 5.14 Ω
b. Current drawn by the boiler is 23,33A
What is resistance?Resistance is the hindrance caused in the flow of current
a. The resistance is given by [tex]R = v^{2} / P[/tex]
here V = 120V , P = 2.8kW = 2800W
R = (120 x 120)/ 2800 = 5.14Ω
Hence Resistance of the boiler is 51.4Ω
b. V = IR so, I = V /R
Here, V = 120V , R = 5.14Ω
So, I = 120/51.4 = 23.33 A
Hence current drawn by the boiler is 23.33A
The alternate way to find the current is by using formula
P = VI
I = P/V
Since, P = 2800W, V = 120V
So, I = 2800/120 =23.33 A
Hence Current comes out to be the same from both the method which verifies the answer .
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An object with a mass of 10.5kg is traveling at a velocity of 9m/s. What is the kinetic energy of
the object?
Four charges are placed on the corners of a rectangle. What is the resultant force on the positive charge (a = 1.1 m, b = 0.9 m, q = 2.3 × 10-9C)?
Answer:
F = 93.49 × 10^(-9) N
Explanation:
We are given;
Length of rectangle; a = 1.1 m
Width of rectangle; b = 0.9 m
Charge on rectangle; q = 2.3 × 10^(-9) C
Formula for force is;
F = kq²/r²
Where;
k is a constant = 8.99 x 10^(9) N.m²/C²
a) on the width side, we have;
F = [8.99 x 10^(9) × (2.3 × 10^(-9))²]/0.9²
F = 58.79 × 10^(-9) N
This is on the y-axis
b) on the length side, we have;
F = [8.99 x 10^(9) × (2.3 × 10^(-9))²]/1.1²
F = 39.3 × 10^(-9) N
This is on the x-axis
C) using pythagoras theorem, for the diagonal side, we have c² = a² + b².
Thus;
F = [8.99 x 10^(9) × (2.3 × 10^(-9))²]/(1.1² + 0.9²)
F = 23.54 × 10^(-9) N
Using trigonometric ratios, we can find the angle θ.
tan θ = b/a
tan θ = 0.9/1.1
tan θ = 0.8182
θ = tan^(-1) 0.8182
θ = 39.29°
Resolving along x and y axis, we have;
F_x = 23.54 × 10^(-9) × cos 39.29°
F_x = 18.22 × 10^(-9) N
F_y = 23.54 × 10^(-9) × sin 39.29°
F_y = 14.91 × 10^(-9) N
Resultant force will be;
F = √((Σf_x)² + (ΣF_y)²)
F = √[(18.22 × 10^(-9)) + (39.3 × 10^(-9))]² + [(14.91 × 10^(-9)) + (58.79 × 10^(-9))²]
F = √[(33.0855 × 10^(-16)) + (54.317 × 10^(-16))]
F = 93.49 × 10^(-9) N
What do the skull and vertebrae have in common
Answer: ok
Explanation: ok
How high of a hill should an 80-kg person climb to expend 40,000 joules of energy?
A. 4.1 km
B. 4.9 km
C. 51 m
D. 500 m
Answer:
1: 51 m
2: some energy was transformed to other forms
3: 3.24
4: 45j
5: 1020
Explanation:
The required height of hill is 51 m. Hence, option (C) is correct.
Given data:
The mass of person is, m = 80 kg.
The energy expended during climbing is, E = 40,000 J.
The energy possessed by the body by virtue of height is known as potential energy. In the given case, the energy expended by the person will be stored in the form of potential energy. Then,
E = U
E = mgh
here, h is the height of hill and g is the gravitational acceleration.
Solving as,
40000 = 80(9.8) h
h ≈ 51 m
Thus, we can conclude that the required height of hill is 51 m. Hence, option (C) is correct.
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HELP ASAP !!!
A train rolls past a stationary observer. To him, the train is moving at a speed
of 25 m/s west, and a woman on the train is moving at a speed of 24.6 m/s
west. How long does it take the woman to move 4 m relative to the train?
A. 7.1 s
B. 9.0 s
C. 8.4 s
D. 10 s
Answer:
10 seconds a mile. D. 10 s
Explanation:
25-24.6= .4
To find how long she will take to move 4 m relative to the train, take the distance she wants to travel divided by her velocity relative to the train.
4 / .4 = 10
Hope this helps you! :)
Answer:
10s
Explanation:
how are frequency and were peroid related?
Answer:
Frequency and period are distinctly different, yet related, quantities. Frequency refers to how often something happens. Period refers to the time it takes something to happen. Frequency is a rate quantity.
Answer:
Frequency and period are distinctly different, yet related, quantities. Frequency refers to how often something happens. Period refers to the time it takes something to happen. Frequency is a rate quantity.
Explanation:
matter can be a solid, lquid or gas. but you cannot see the particles or adoms that make up matter because they are
Answer:
very small...
Explanation:
i guess... but i may be missing something. the question feels too straightforward
How does the air pressure inside a tennis ball change when you hit it?
A light bulb uses 1.2 A when connected across a 120 V source. What is the resistance by the bulb?
What is the height of a building that an object is dropped from if it has a mass of 3 kg and hits the ground with a velocity of 50 m/s?
Answer:
125 m
Explanation:
m = 3kg
v = 50m/s
u = 0m/s
a = +g = 10m/s²
s = H = ?
using the formula,
v² = u² + 2as
50² = 0² + 2(10)(H)
2500 = 20H
H = 2500/20
H = 125m
according to newton's first law of motion what is the reason for a ball throwing up in the airfall back to earth
2. An 85.5 kg astronaut is training for accelerations that he will experience upon reentry. He is placed in a centrifuge (r = 12.0 m) and spun at a constant angular velocity of 18.4 rpm. Answer the following:
(a) What is the angular velocity of the centrifuge in ?
(b) What is the linear velocity of the astronaut at the outer edge of the centrifuge?
(c) What is the centripetal acceleration of the astronaut at the end of the centrifuge?
(d) How many g’s does the astronaut experience?
(e) What is the centripetal force experienced by the astronaut?
Answer Expert Verified
Hello here is your answer and also please mark me as brainlest
Since one revolution around a circle is 2 pi radian; hence 1 rpm equals 2 pi radians per minute. And because a minute has 60 seconds, 1 rpm equals 1/60 revolution per second. Therefore, we have 2 pie/60 * 15.3 = 0.2513 rps. The linear velocity v = wr where w is the angular velocity in rad/s and r is the distance. So we have 0.2513 * 10.0 = 2.513 rad/s The centripetal acceleration is given by a = w^2 r = (2.513)^2 * 10 = 63.15 rad/s2 The centripetal force F = mass * centripetal acc = 75 * 63.15 = 4736.25 N The torque = centripetal force * distance = 4736 * 63.15 = 299078.4 Nm Two forces acts on the astronaut. The normal force and acceleration due to gravity.
I hope this help you
brainlest
Rotational kinematics and Newton's second law allow to find the results for the astronaut's movement in the centrifuge are:
a) The angular velocity is: w = 1.927 rad / s
b) The linear velocity is: v = 23.1 m / s
c) The centripetal acceleration is: a = 6.417 10³ m / s²
d) The centripetal acceleration is: a = 6.548 10² g
e) The centripetal force F = 5.49 10⁵ N
given parameters
The mass of the astronaut m = 85.5 kg Centrifuge radii r = 12.0 m Angular velocity w = 18.4 rpm (2prad / 1rev) (1min / 60s) = 1.927 rad / sTo find
a) angular velocity
b) linear velocity
c) centripetal acceleration
d) acceleration in units of gravity (g)
e) the centripetal force
The angular velocity is defined as the rotated angle in the unit of time.
[tex]w = \frac{\Delta \theta}{t}[/tex]
Angular and linear variables are related.
v = w r
Where w is the angular velocity, θ is the angle, t the time, v the lienal velocity and R the radius of the cetnrifuga
Let's answer the questions:
a) The angular velocity of the centrifuge and the astronaut are equal
w = 1.927 rad / s
b) Linear velocity
v = 1.927 12.0
v = 23.1 m / s
c) Centripetal acceleration has the formula:
a = [tex]\frac{v^2}{R}[/tex]
a = [tex]\frac{23.1^2}{12.0}[/tex]
a = 6.417 10³ m / s²
d) The value of this eceleration as a function of gravity
[tex]\frac{a}{g}[/tex] = 6.417 10³ / 9.8
[tex]\frac{a}{g}[/tex] = 6.548 10²
a = 6.548 10² g
e) The centripetal force
F = ma
F = 85.5 6.417 10³
F = 5.49 10⁵ N
In conclusion, using rotational kinematics and Newton's second law we can find the results for the movement of the astronaut in the centrifuge are:
a) The angular velocity is: w = 1.927 rad / s
b) The linear velocity is: v = 23.1 m / s
c) The centripetal acceleration is: a = 6.417 10³ m / s²
d) The centripetal acceleration is: a = 6.548 10² g
e) The centripetal force F = 5.49 10⁵ N
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Did the energy you used to lift the notebook get stored in the book as potential energy? Explain your answer with reasons.
Answer:
Because when you move a object the energy stored in moving objects. As the object moves faster, more energy is stored. Motion energy is the sum of potential and kinetic energy in an object that is used to do work.
Explanation:
answer it please
What is the Central Idea of "Shelter Dog Protects Owner with Epilepsy“
What is the author’s viewpoint?
Do you agree or disagree with that viewpoint?
Why? Explain your answer.
parpgraph 1-2
Answer:
Yes, the energy used to lift the book was stored in the book as potential energy. The book moved when it was let go.
Explanation:
This is what edmentum sample answer says so I hope this helps out!
A cup of coffee is sitting on a table in a train that is moving with a constant velocity. The coefficient of static friction between the cup and the table is 0.30. Suddenly, the train accelerates. What is the maximum acceleration that the train can have without the cup sliding backward on the table?
Answer:
a = 2.94 m/s²
Explanation:
In order for the cup not to slip, the unbalanced force on cup must be equal to the frictional force:
Unbalanced Force = Frictional Force
ma = μR = μW
ma = μmg
a = μg
where,
a = maximum acceleration for the cup not to slip = ?
μ = coefficient of static friction = 0.3
g = acceleration due to gravity = 9.8 m/s²
Therefore,
a = (0.3)(9.8 m/s²)
a = 2.94 m/s²
A carriage of 20 kg is pulled with a force of 35 N. How far the carriage will go
doing 95 J work?
Answer:
2.71 m
Explanation:
Force is the product of mass and acceleration
F=m*a
Work done is the product of force and distance
Work done=F*d
In this case;
F= 35 N
Work done = 95 J
95 =35 * d
95 /35 = d
2.71 m= d
what are the characteristics of image when object is between f1 and 2f1 for concave lense?
Answer:
The required diagram is shown in the figure. When an object is placed in front of the convex lens, i.e., between 2F
1
and F
1
, its image is formed beyond 2F
2
on the other side of the lens. The image is real, inverted and enlarged.
solution
Riding a bicycle on a flat, smooth surface is a lot easier than riding it along a bumpy surface or up a hill. A bumpy surface creates more friction with your bike tires than a smooth surface does, and going up a hill means fighting gravity.
Write about a time you had to ride a bicycle on a difficult surface. What did you have to do to adjust your riding?
Answer:
one time i was one the flat ground at my aunts house then we went on a hike so i brought my bike it had just rained that day so it was kinda muddy so there was sticks everywhere.i was riding up hill and noticed that it was very hard,then i rode down hill and it was much better
Explanation:
sound is faster than light that is why we hear thunder before we see lightning
Answer:
false
Explanation:
sound travels slower than light. that is why we see lightning before we hear the thunder
A motobike's tire rotates with a constant angular speed of 62.8 rad/s. The radius of a tire is 30cm. Assuming that no slipping occurs, the number of
revolutions of the tire in one second is:
a.
12.6
b.
20
C.
18.8
d.
10
Answer:
10
Explanation:
Given that :
Angular speed (w) = 62.8 rad/s
Radius of tire (r) = 30 cm
Number of revolutions per second :
s = 2πr
s = 2π * 0.3 = 1.8849555
The number or revolutions per second :
θ = s / r
θ = 1.884955 / 0.3
θ = 6.283185 rad
Number of revolutions per second :
62.8 / 6.283185
= 9.9949309
= 10
How much energy is stored in a 2.80-cm-diameter, 14.0-cm-long solenoid that has 200 turns of wire and carries a current of 0.800 A
Answer:
The energy stored in the solenoid is 7.078 x 10⁻⁵ J
Explanation:
Given;
diameter of the solenoid, d = 2.80 cm
radius of the solenoid, r = d/2 = 1.4 cm
length of the solenoid, L = 14 cm = 0.14 m
number of turns, N = 200 turns
current in the solenoid, I = 0.8 A
The cross sectional area of the solenoid is given as;
[tex]A = \pi r^2\\\\A = \pi (0.014)^2\\\\A = 6.16*10^{-4} \ m^2[/tex]
The inductance of the solenoid is given by;
[tex]L = \frac{\mu_0 N^2A}{l} \\\\L = \frac{(4\pi*10^{-7})(200^2)(6.16*10^{-4})}{0.14}\\\\L = 2.212*10^{-4} \ H[/tex]
The energy stored in the solenoid is given by;
E = ¹/₂LI²
E = ¹/₂(2.212 x 10⁻⁴)(0.8)²
E = 7.078 x 10⁻⁵ J
Therefore, the energy stored in the solenoid is 7.078 x 10⁻⁵ J
The energy stored in a 2.80-cm-diameter, 14.0-cm-long solenoid that has 200 turns of wire and carries a current of 0.800 A is 7.07 × 10⁻⁵ J.
A solenoid is a type of electromagnet, whose purpose is to generate a controlled magnetic field through a coil wound into a tightly packed helix.
First, given the diameter of the solenoid (d) is 2.80 cm (0.0280 m), we can calculate the cross-sectional area (A) using the following expression.
[tex]A =\pi \times (\frac{d}{2} )^{2} = \pi \times (\frac{0.0280}{2} )^{2} = 6.16 \times 10^{-4} m^{2}[/tex]
Next, we will calculate the inductance (L) of the solenoid using the following expression.
[tex]L = \frac{\mu _0 \times N^{2} \times A}{l} = \frac{(4\pi \times 10^{-7}H/m ) \times 200^{2} \times (6.16 \times 10^{-4}m^{2} )}{0.140m} = 2.21 \times 10^{-4} H[/tex]
where,
μ₀ is the vacuum permeabilityN is the number of turnsl is the length of the solenoidFinally, for a current (I) of 0.800 A, we can calculate the energy stored (E) using the following expression.
[tex]E = \frac{1}{2} \times L \times I^{2} = \frac{1}{2} \times (2.21 \times 10^{-4}H ) \times (0.800A)^{2} = 7.07 \times 10^{-5} J[/tex]
The energy stored in a 2.80-cm-diameter, 14.0-cm-long solenoid that has 200 turns of wire and carries a current of 0.800 A is 7.07 × 10⁻⁵ J.
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