A 1000 kg dragon is at rest sleeping in outer space. A 50 kg unicorn runs into the dragon with a velocity of 600 ms . The final velocity of the dragon is 40 ms . What is the final velocity of the unicorn?

Explanation:

A diode is an electrical element which offers the flow of current freely in one direction with very less resistance.

The given figure depicts a diode in forward bias, where the p-side and the n-side of the diode are connected to positive and negative terminals respectively. In such a case the current flows from the p-side to n-side of the p-n junction very easily and the value of the current increases rapidly after a certain voltage, this voltage is called threshold voltage.

We can deduce from the graph that the resistance of the diode reduces with increase in voltage. As resistance is given by the formula:

[tex]R=\frac{V}{i}[/tex]

Answer:

R = 0.86 m

Explanation:

The formula for the range of the projectile motion can be used here:

[tex]R = \frac{v^2 Sin2\theta}{g}[/tex]

where,

R = Range of projectile = distance between Jake and Fred = ?

v = launch speed = 3 m/s

θ = Launch Angle = 35°

g = acceleration due to gravity = 9.81 m/s²

Therefore,

[tex]R = \frac{(3\ m/s)^2Sin[(2)(35^o)]}{9.81\ m/s^2}\\\\[/tex]

R = 0.86 m

Answer:

(a) i) The distance travelled by the cycle in half round is approximately 65.97 m

ii) The displacement is 42 m

(b) (i) The distance travelled in one round is approximately 131.95 m

(ii) The displacement of the cycle in one round is 0

Explanation:

The diameter of the track through which the cycle travels, D = 42 m

(a) i) Half round is the motion of half the length of the circular path

The distance travelled by the cycle in half round = The length of half the circular track = (1/2) × π × D

∴ The distance travelled by the cycle in half round = (1/2) × π × 42 m = 21·π m ≈ 65.97 m

ii) The displacement half round = The change in the location of the cycle = The difference between the start and stop locations of the cycle on a straight line after half round

The angle at the center of the circular path the cycle turns in half round  = 180°

Therefore, the path between the start and stop location of the cycle in half round = The diameter of the circular track

The displacement of the cycle in half round = The diameter of the circular track = 42 m

(b) (i) The distance travelled in one round = The perimeter of the circular track = π·D

∴ The distance travelled in one round = π × 42 m ≈ 131.95 m

(ii) The displacement of the cycle in one round = The change in the location of the cycle

The start and stop location of the cycle after moving one round is the same, therefore, there is no change in the location of the cycle.

Therefore we have;

The displacement of the cycle in one round = 0 (no change in location of the cycle)

Answer:

Explanation:

mass and distance

Answer:

t=1/4v1

Explanation:

Given data

Car one

Speed =v1

Time =t

Distance =1/4 mile

Given data

Car two

Speed =v1/2

Time =t

Distance =d

Speed =distance/time

v1=1/4/t

v1t=1/4

t=1/4*1/v1

t=1/4v1 seconds

Direct current (DC) is the flow of electric charge in only one direction. It is the steady state of a constant-voltage circuit. Most well-known applications, however, use a time-varying voltage source. Alternating current (AC) is the flow of electric charge that periodically reverses direction.

Answer:

Attenuation

Step By step Explanation:

The decrease in the intensity of light over distance, such as with increasing depth in water, is known as ______.

It is called attenuation.

The decraese in the amplitude of the signals is called attenuation.

Answer:

[tex]H_{max}=3.4m[/tex]

Explanation:

From the question we are told that:

Mass 1 [tex]m_1=5kg[/tex]

Mass  [tex]m_2=2kg[/tex]

Distance above floor [tex]d=2.5m[/tex]

Generally the equation for Conservation of energy is mathematically given by

[tex]0.5m_1v^2+0.5m_2v^2=2mg[/tex]

[tex]0.5m_1v^2+0.5m_2v^2=2g(m_1-m_2)[/tex]

[tex]v^2(0.5*m_1+0.5*m_2)=2*g(m_1-m_2)[/tex]

[tex]v^2(0.5*5+0.5*2) = 2 * 9.8 * (5 - 2)[/tex]

[tex]v^2=\frac{58.8}{3.5}[/tex]

[tex]v=4.1m/s[/tex]

Generally the equation for The maximum height of lighter block  is mathematically given by

[tex]H_{max}=d+\frac{v^2}{2g}[/tex]

[tex]H_{max}=2.5+\frac{16.2}{2*9.81}[/tex]

[tex]H_{max}=3.4m[/tex]

Answer:

Average speed = 24 km/h

Explanation:

Given the following data;

Uniform speed A = 30 km/h

Uniform speed B = 20 km/h

To find the average speed;

Mathematically, the average speed of an object is given by the formula;

[tex] Average \; speed = \frac {total \; distance}{total \; time} [/tex] ..... equation 1

Total time = TA + TB

[tex] T_{A} = \frac {x}{30} [/tex]

[tex] T_{B} = \frac {x}{20} [/tex]

[tex] Total \; time = \frac {x}{30} + \frac {x}{20} [/tex]

[tex] Total \; time = \frac {5x}{60} [/tex]

Total distance = x + x

Total distance = 2x

Substituting the values into equation 1;

[tex] Average \; speed = \frac {2x}{\frac {5x}{60}} [/tex]

[tex] Average \; speed = \frac {2x*60}{5x} [/tex]

[tex] Average \; speed = \frac {120}{5} [/tex]

Average speed = 24 km/h

Answer:

[tex]d=0.59m[/tex]

Explanation:

From the question we are told that:

Mass [tex]m=67.3 kg[/tex]

Spring constant [tex]\mu=1.23 * 10^3 N/m[/tex]

Fall Height [tex]h=0.921m[/tex]

Generally the Energy theorem equation for momentum is mathematically given by

Change in KE=Work done by gravity + work done by spring

[tex]0=mg*(h + d) - \frac{\mu d^2}{2}[/tex]

[tex]0=(67.3 * 9.81 (0.921 + d)) -\frac{(1.23 * 10^3 * d^2}{ 2}[/tex]

[tex]0=608.1-660.213d-615d^2[/tex]

Solving Quadratic equation

[tex]d=0.59m[/tex]

Answer:

attached below

Explanation:

The initial conditions :

x(0) = - 9 inches = -3/4 ft

x'(0) = - 2 ft/sec

spring stretched  3 inches = 1/4 ft

mass = w / g = 4 Ib / 32 ft/sec^2 = 1/8  slug

the spring constant ( k ) = w / l  = 4 / ( 1/4 ) = 16 Ib/ft

applying the second law of motion

m d^2x/dt^2 +  b dx/dt  + kx

= 1/8 d^2x/dt^2  + 2 dx/dt  + 16 x

= d^2x/dt^2  + 16 dx/dt  +  128 x  ------- ( 1 )

we will resolve the above equation to obtain the required equation of motion  x( t )

Attached below is the remaining part of the solution

Speed = Distance/Time

=> Speed = 100m/16s

=> Speed = 6.25m/s

=> Speed = 6.25 ms^-1

Answer:

Value of the resistors​ R = 2 ohm

Explanation:

Given:

Resistor R1 = 4 ohm

Resistor R2 = 4 ohm

Find:

Value of the resistors​ R

Computation:

We know that Resistor R1 and Resistor R2 connected in parallel series.

So,

Using common resistance in parallel series

⇒ 1/R = 1/R1 + 1/R2

⇒ 1/R = 1/4 + 1/4

⇒ 1/R = (1 + 1) / 4

⇒ 1/R = 2/4

⇒ R = 4/2

⇒ R = 2

Value of the resistors​ R = 2 ohm

Answer:

0.0366 m

Explanation:

We are given;

Current density; J = 540 A/cm² = 540 × 10⁴ m

Current; I = 0.57 A

Now, formula for current density is;

J = I/A

Where A is area = πr²

Thus;

J = I/(πr²)

r = √(I/(Jπ))

r = √(0.57/(540π))

r = 0.0183 m

Diameter = 2 × radius

Diameter = 2 × 0.0183

Diameter = 0.0366 m

Answer:

1.the friction of air, gravity2.gravity

Answer:

The softball experiences an applied force as a result of Amy’s throw. As the ball moves, it experiences drag from the air it passes through. It also experiences a downward pull because of gravity.

Explanation:

Plato

Answer:

Explanation:

This is a recoil problem, which is just another application of the Law of Momentum Conservation. The equation for us is:

[tex][m_av_a+m_ev_e]_b=[m_av_a+m_ev_e]_a[/tex] which, in words, is

The momentum of the astronaut plus the momentum of the piece of equipment before the equipment is thrown has to be equal to the momentum of all that same stuff after the equipment is thrown. Filling in:

[tex][(90.0)(0)+(.50)(0)]_b=[(90.0)(v)+(.50)(-4.0)]_a[/tex]

Obviously, on the left side of the equation, nothing is moving so the whole left side equals 0. Doing the math on the right and paying specific attention to the sig fig's here (notice, I added a 0 after the 4 in the velocity value so our sig fig's are 2 instead of just 1. 1 is useless in most applications).

0 = 90.0v - 2.0 and

2.0 = 90.0v so

v = .022 m/s This is the rate at which he is moving TOWARDS the ship (negative was moving away from the ship, as indicated by the - in the problem). Now we can use the d = rt equation to find out how long this process will take him if he wants to reach his ship before he dies.

12 = .022t and

t = 550 seconds, which is the same thing as 9.2 minutes

Explanation:

the high heels has a more pressure than flat soles bcoz small area has more pressure than large area.

Answer:

:) :) :) :) :) :) :) :) :)

Explanation:

:) :) :) .......

the correct answer is ---- 122

Answer:

1. 100 J

2. 225 J

Explanation:

We'll begin by calculating the mass of the object. This can be obtained as follow:

Velocity (v) = 5 ms¯¹

Kinetic energy (KE) = 25 J

Mass (m) =?

KE = ½mv²

25 = ½ × m × 5²

25 = ½ × m × 25

25 = 25m / 2

Cross multiply

25m = 25 × 2

25m = 50

Divide both side by 25

m = 50 / 25

m = 2 Kg

1. Determination of the kinetic energy when the velocity is doubled.

Mass (m) = 2 Kg

Velocity (v) = double the initial velocity

= 2 × 5 ms¯¹

= 10 ms¯¹

Kinetic energy (KE) =?

KE = ½mv²

KE = ½ × 2 × 10²

KE = ½ × 2 × 100

KE = 100 J

2. Determination of the kinetic energy when the velocity increased three times.

Mass (m) = 2 Kg

Velocity (v) = three times the initial velocity

= 3 × 5 ms¯¹

= 15 ms¯¹

Kinetic energy (KE) =?

KE = ½mv²

KE = ½ × 2 × 15²

KE = ½ × 2 × 225

KE = 225 J

Answer:

B

Explanation:

The writers are from a trusted source that is considered impartial. The message is backed up by scientific investigation, and the writers have no monetary gain from their message.

Answer:

Explained below.

Explanation:

Let the initial velocity from the top of the tower of height(h) be u'

Now, since it is projected horizontally, the horizontal distance covered will be due to having a uniform horizontal velocity (u) while it will possess a vertical distance in the downward direction due to constant acceleration due to gravity (g).

If the time it takes the ball to reach the ground is "t", then we can say the horizontal distance travelled by the ball is denoted as; x(t) = x, while the vertical distance is denoted by; y(t) = y

Now, since it's a projectile the intial velocity (u) will have vertical and horizontal components which are;

u_y and u_x respectively.

Applying kinematic equations, we have;

x = u_x•t + ½at²

Acceleration is zero in the horizontal x direction. Thus;

x = u_x•t

For the vertical y-direction;

y = u_y•t + ½at²

Here since direction is in that of gravity, then a = g.

Also, since the initial velocity has no downward component, then u_y = 0 m/s

Thus;

y = ½gt²

From x = u_x•t, we have;

t = x/u_x

Thus;

y = ½g(x/u_x)²

y = ½gx²/(u_x)²

Let g/(u_x)² be treated as a constant with the letter k.

Thus;

y = kx²

This is the form of a parabolic equation.

Thus, it has been proved that the projectile follows the path of a parabola.

Answer:

Density → Mass and Length.

Acceleration → Length and Time.

Force → Mass, Length and Time.

Pressure → Mass, Length and Time.

Work → Mass, Length and Time.

Answer:

For smooth surface:The light rays bounce off the table and all move in the same direction.

Explanation:

Given that,

The voltages across them are 40,50 and 60 volts respectively, and the charge on each condenser is 6×10⁻⁸ C.

(a) Capacitance of capacitor 1,

[tex]C_1=\dfrac{Q}{V_1}\\\\C_1=\dfrac{6\times 10^{-8}}{40}\\\\C_1=1.5\times 10^{-9}\ F\\\\C_1=1.5\ nF[/tex]

Capacitance of capacitor 2,

[tex]C_2=\dfrac{Q}{V_2}\\\\C_2=\dfrac{6\times 10^{-8}}{50}\\\\C_2=1.2\times 10^{-9}\ F\\\\C_2=1.2\ nF[/tex]

Capacitance of capacitor 3,

[tex]C_3=\dfrac{Q}{V_3}\\\\C_3=\dfrac{6\times 10^{-8}}{60}\\\\C_3=1\times 10^{-9}\ F\\\\C_3=1\ nF[/tex]

(b) The equivalent capacitance in series combination is :

[tex]\dfrac{1}{C}=\dfrac{1}{C_1}+\dfrac{1}{C_2}+\dfrac{1}{C_3}\\\\\dfrac{1}{C}=\dfrac{1}{1.5}+\dfrac{1}{1.2}+\dfrac{1}{1}\\\\C=0.4\ nF[/tex]

Hence, this is the required solution.