Answer:
54g
Explanation:
Given parameters:
Number of moles of H₂O = 3 moles
Unknown:
mass of water = ?
Solution:
To solve this problem, we use the expression below:
mass = number of moles x molar mass
Molar mass of H₂O = 2(1) + 16 = 18g/mol
Mass of water = 3 x 18 = 54g
Calculate the mass, in grams, of 1.2000 mol Mg₃N₂
HCl, NaCl, and CO are all examples of chemical
properties
bonds
formulas
changes
Answer:
HCL, NACL and CO are the examples of chemical formulas
How many molecules are there in 2 moles of FeF3
Answer:it is 4
Explanation:
I multiple and divided it
Which of the following is a true statement?
All flat-topped hills are plateaus.
Volcanoes form all flat-topped hills.
All flat-topped hills are mesas.
Flat-topped hills can either be plateaus or mesas.
Answer:
D Flat Top Hills Can Be Plateaus or mesas
Explanation:
1) If I have 45 liters of helium in a balloon at 250 C and increase the temperature of the balloon to 550 C, what will the new volume of the balloon be?
Answer:
V₂ = 70.80 L
Explanation:
Given data:
Initial volume of He = 45 L
Initial temperature = 250 °C
Final temperature = 550 °C
Final volume = ?
Solution:
Initial temperature = 250 °C (250+273.15 K= 523.15 K)
Final temperature = 550 °C (550 + 273.15 k= 823.15 K)
According to Charles Law.,
Mathematical expression:
V₁/T₁ = V₂/T₂
V₁ = Initial volume
T₁ = Initial temperature
V₂ = Final volume
T₂ = Final temperature
Now we will put the values in formula.
V₁/T₁ = V₂/T₂
V₂ = V₁T₂/T₁
V₂ = 45 L × 823.15 K / 523.15 K
V₂ = 37041.75 L.K / 523.15 K
V₂ = 70.80 L
I need help asap please help me
How many atoms are in 5 moles of Cadmium?
3 × 10²⁴ atoms Cd
General Formulas and Concepts:Math
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightChemistry
Atomic Structure
Using Dimensional AnalysisAvogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.Explanation:Step 1: Define
5 mol Cd (Cadmium)
Step 2: Identify Conversions
Avogadro's Number
Step 3: Convert
Set up: [tex]\displaystyle 5 \ moles \ Cd(\frac{6.022 \cdot 10^{23} \ atoms \ Cd}{1 \ mol \ Cd})[/tex]Multiply: [tex]\displaystyle 3.011 \cdot 10^{24} \ atoms \ Cd[/tex]Step 4: Check
Follow sig fig rules and round. We are given 1 sig fig.
3.011 × 10²⁴ atoms Cd ≈ 3 × 10²⁴ atoms Cd
Which bonds below are hydrophilic?
A) CC, CH
B) NH, OH, OP, OC
C) NH, OH, OP, OC, CC, CH
if mixture didn't exist how would life be different
Answer:
boring
Explanation:
life would be meaningless like everyone being like on person
1. Matter can (change form/be created)
Answer: Yes
Explanation:
Duh it can change. Because matter is what we are made of, and if we change, then matter also changes along with us :)
I NEED APPROPRIATE ANSWERS SO IF ANYONE CAN PLEASE ANSWER THESE TWO QUESTIONS I WILL GIVE YOU BRAINIEST. Can someone please help me with these two questions:
What happens when PURE sodium (Na) and water react?
12. What happens when sodium chloride (NaCl or table salt) mixes with water? Is it the same or different when PURE sodium reacts with water?
Answer:
1. When salt is mixed with water, the salt dissolves because the covalent bonds of water are stronger than the ionic bonds in the salt molecules
2. Pure sodium explodes on contact with water
Explanation:
exactly 1mol of n2o4 is placed in an empty 1 l container. if at equilibrium n2o4 is dissociated 20%, what is the value of equilibruim constant
Answer:
K = 0.2
Explanation:
Based on the chemical dissociation of N₂O₄:
N₂O₄ ⇄ 2NO₂
The equilibrium constant, K, of the reaction is:
K = [NO₂]² / [N₂O₄]
Now, if 20% of N₂O₄ is dissociated, 80% remains as N₂O₄ = 0.8mol/L = 0.8M
as 20% is dissociated, 0.2moles of N₂O₄ were dissociated and 0.2*2 = 0.4mol/L of NO₂ are produced.
Replacing in K:
K = [0.4M]² / [0.8M]
K = 0.2A pitcher throws a ball and it reaches home plate 60 ft away in 0.41
seconds. What is the approximate speed of the ball?
O 100 ft/s
50 ft/s
O 146 ft/s
0 24.6 ft/s
Answer:
The answer is 146.
Explanation:
To calculate speed, you have to divide the distance by the time. So, 60/0.41 would be approximately 146.
Calculate the energy required to heat 179g of ethanol from to . Assume the specific heat capacity of ethanol under these conditions is . Be sure your answer has the correct number of significant digits.
Answer:
9.52 × 10³ J
Explanation:
There is some info missing but I found it on the web.
Calculate the energy required to heat 179g of ethanol from -2.2 °C to 19.6 °C. Assume the specific heat capacity of ethanol under these conditions is 2.44 J/g.°C. Be sure your answer has the correct number of significant digits.
Step 1: Given data
Mass of ethanol (m): 179 gInitial temperature: -2.2°CFinal temperature: 19.6 °CSpecific heat capacity of ethanol (c): 2.44 J/g.°CStep 2: Calculate the temperature change
ΔT = 19.6 °C - (-2.2 °C) = 21.8 °C
Step 3: Calculate the energy required (Q)
We will use the following expression.
Q = c × m × ΔT
Q = 2.44 J/g.°C × 179 g × 21.8 °C
Q = 9.52 × 10³ J
please help !!!
What law states that matter can never be created or destroyed?
A. The law of gravity
B. The law of constant phases
C. The law of conservation of matter
D. The atomic theory
Answer:
C) The law of conservation of matter
Explanation:
Conservation means keeping/ retaining something, in this case it is matter. Hope this helps!
What is hydrophilic.
Answer:
of, relating to, or having a strong affinity for water
Explanation:
Answer:
water loving or havin affection for water, not like hydrophobic wich is fear of water or not resistant to water
Explanation:
Select the correct answer.
An iron bar at 200°C is placed in thermal contact with an identical iron bar at 120°C in an isolated system. After 30 minutes, both iron bars are at 160°C. If the iron bars were placed in thermal contact in an open system instead of an isolated system, how would the results be different? Assume that the room temperature is 25°C.
A.
The temperatures of the iron bars after 30 minutes would be less than 160°C because heat would be lost to the surroundings.
B.
It would take more than 30 minutes for both iron bars to reach 160°C because heat would be transferred less efficiently.
C.
The temperatures of both iron bars would increase as they absorb heat from the surroundings.
D.
The temperatures of both iron bars would decrease because pieces of them would be lost to the surroundings.
It is not D or C
Pick A or B
12. What is the volume of 0.07 mol of neon gas at STP?
2 L Ne
General Formulas and Concepts:Math
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightChemistry
Atomic Structure
Using Dimensional AnalysisSTP (Standard Conditions for Temperature and Pressure) = 22.4 L per mole at 1 atm, 273 KExplanation:Step 1: Define
0.07 mol Ne (g)
Step 2: Identify Conversions
STP - 22.4 L per mole
Step 3: Convert
Set up: [tex]\displaystyle 0.07 \ mol \ Ne(\frac{22.4 \ L \ Ne}{1 \ mol \ Ne})[/tex]Multiply: [tex]\displaystyle 1.568 \ L \ Ne[/tex]Step 4: Check
Follow sig fig rules and round. We are given 1 sig fig.
1.568 L Ne ≈ 2 L Ne
Draw a Lewis structure for C2H3Cl . Include all hydrogen atoms and show all unshared electron pairs. None of the atoms bears a formal charge, and all atoms have octets (except for hydrogen atoms, which have duets).
Answer:
See attached picture.
Explanation:
Hello!
In this case, since C2H3Cl is an organic compound we need a central C-C parent chain to which the three hydrogen atoms and one chlorine atom provides the electrons to get all the octets except for H as given on the statement.
In such a way, on the attached picture you can find the required Lewis dot structure without formal charges and with all the unshared electron pairs, considering there is a double bond binding the central carbon atoms in order to compete their octets.
Best regards!
The lewis structure of given molecule is given below. Carbon has 4 electron. out of which electron make bond with carbon and one with hydrogen and chlorine.
If the compound's molecular formula is known, electron dot structures or Lewis dot formulas can be drawn. It describes the type of bond and the placement of the atoms within the molecule that are joined together. In homage of American chemist Gilbert Newton Lewis, molecules are depicted as having a Lewis electron dot structure or simply a Lewis structure. The lewis structure of given molecule is given below.
To know more about lewis structure, here:
https://brainly.com/question/32662174
#SPJ6
How many grams do 6.7×1025 atoms of carbon weigh?
A)224
B)128
C)1336
D)4325
at a particulat temperature, a smaple of pure water has a Kw of 7.7x10-14. what is the hydroxide concentration of this sample
Answer: The hydroxide concentration of this sample is [tex]3.85\times 10^{-7}[/tex]
Explanation:
When an expression is formed by taking the product of concentration of ions raised to the power of their stoichiometric coefficients in the solution of a salt is known as ionic product.
The ionic product for water is written as:
[tex]K_w=[H^+]\times [OH^-][/tex]
[tex]7.7\times 10^{-14}=[H^+]\times [OH^-][/tex]
As [tex][H^+]=[OH^-][/tex]
[tex]2[OH^-]=7.7\times 10^{-14}[/tex]
[tex][OH^-]=3.85\times 10^{-7}[/tex]
Thus hydroxide concentration of this sample is [tex]3.85\times 10^{-7}[/tex]
How many molecules are in 50.0 grams of NaOH?
7.53 × 10²³ molecules NaOH
General Formulas and Concepts:Math
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightChemistry
Atomic Structure
Reading a Periodic TableUsing Dimensional AnalysisAvogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.Explanation:Step 1: Define
50.0 g NaOH
Step 2: Identify Conversions
Avogadro's Number
Molar Mass of Na - 22.99 g/mol
Molar Mass of O - 16.00 g/mol
Molar Mass of H - 1.01 g/mol
Molar Mass of NaOH - 22.99 + 16.00 + 1.01 = 40 g/mol
Step 3: Convert
Set up: [tex]\displaystyle 50.0 \ g \ NaOH(\frac{1 \ mol NaOH}{40 \ g \ NaOH})(\frac{6.022 \cdot 10^{23} \ molecules \ NaOH}{1 \ mol \ NaOH})[/tex]Multiply: [tex]\displaystyle 7.5275 \cdot 10^{23} \ molecules \ NaOH[/tex]Step 4: Check
Follow sig fig rules and round. We are given 3 sig figs.
7.5275 × 10²³ molecules NaOH ≈ 7.53 × 10²³ molecules NaOH
When 1 mole of P4O10(s) reacts with H2O(l) to form H3PO4(aq) according to the following equation, 453 kJ of energy are evolved. P4O10(s) 6H2O(l)4H3PO4(aq)
The question is incomplete, the complete question is;
When 1 mole of P4O10(s) reacts with H2O(l) to form H3PO4(aq) according to the following equation, 453 kJ of energy are evolved.
P4O10(s) + 6H2O(l)When 1 mole of P4O10(s) reacts4H3PO4(aq)
Is this reaction endothermic or exothermic? _________endothermicexothermic
Answer:
The reaction is exothermic
Explanation:
An exothermic reaction refers to any reaction in which heat was EVOLVED. The word was stressed to indicate that it holds the key to answering the question correctly.
We were told in the question that heat was evolved, hence the reaction is exothermic in nature.
The balanced thermochemical equation of the reaction is :
P₄O₁₀(s) + 6H₂O(l) → 4H₃PO₄(aq) ____ ΔH = -453 kJ
What is the mass in grams of 7.5 x 10^15 atoms of nickel, Ni?
7.3 × 10⁻⁷ g Ni
General Formulas and Concepts:Math
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightChemistry
Atomic Structure
Reading a Periodic TableUsing Dimensional AnalysisAvogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.Explanation:Step 1: Define
7.5 × 10¹⁵ atoms Ni
Step 2: Identify Conversions
Avogadro's Number
Molar Mass of Ni - 58.69 g/mol
Step 3: Convert
Set up: [tex]\displaystyle 7.5 \cdot 10^{15} \ atoms \ Ni(\frac{1 \ mol \ Ni}{6.022 \cdot 10^{23} \ atoms \ Ni})(\frac{58.69 \ g \ Ni}{1 \ mol \ Ni})[/tex]Multiply: [tex]\displaystyle 7.30945 \cdot 10^{-7} \ g \ Ni[/tex]Step 4: Check
Follow sig fig rules and round. We are given 2 sig figs.
7.30945 × 10⁻⁷ g Ni ≈ 7.3 × 10⁻⁷ g Ni
54 is the atomic number for ?Xe.
Answer:
Xenon
Atomic Number: 54
Explanation:
Periodic Table
Answer:
Xenon
Explanation:
Xenon is a chemical element with symbol Xe and atomic number 54.
Rutherfordium-261 has a half-life of 1.08 min. How long will it take for a sample of rutherfordium to lose one-third of its nuclei?
Answer:
[tex]t=1.712min[/tex]
Explanation:
Hello!
In this case, since the radioactive decay equation is:
[tex]\frac{A}{A_0}=2^{-\frac{t}{t_{1/2} }[/tex]
Whereas A stands for the remaining amount of this sample and A0 the initial one. In such a way, since the sample of rutherfordium is reduced to one-third of its nuclei, the following relationship is used:
[tex]A=\frac{1}{3} A_0[/tex]
And we plug it in to get:
[tex]\frac{\frac{1}{3} A_0}{A_0}=2^{-\frac{t}{t_{1/2}} } \\\\\frac{1}{3}=2^{-\frac{t}{t_{1/2}} }[/tex]
Now, as we know its half-life, we can compute the elapsed time for such loss:
[tex]log(\frac{1}{3})=log(2^{-\frac{t}{t_{1/2}} })\\\\log(\frac{1}{3})=-\frac{t}{t_{1/2}} }*log(2)[/tex]
[tex]t=-\frac{log(\frac{1}{3})t_{1/2}}{log(2)} \\\\t=1.71min[/tex]
Best regards!
is sodium a mixure or substance
Answer:
it is a substance
Explanation:
because sodium is an element which its consistent is only sodium atom
Which is the following is true about the properties of the mantle?
The mantle produces magnetic fields.
The mantle is hotter the core.
The mantle contains two different layers.
There are rock samples collected from the mantle.
Answer:
it's the 2 I'm pretty sure
Explanation:
please give me a heart
Answer:
Explanation:
sd dsf sd f sdf sdf
You have 8 red M&Ms, 6 brown M&Ms, 4 yellow M&Ms, and 3 green M&Ms.
What percent of M&Ms are red?
Answer to 1 Decimal Place (Check your rounding)
Answer:
38.1
Explanation:
8+6+4+3=21
8/21
38.1
Suppose 6.63g of zinc bromide is dissolved in 100.mL of a 0.60 M aqueous solution of potassium carbonate. Calculate the final molarity of zinc cation in the solution. You can assume the volume of the solution doesn't change when the zinc bromide is dissolved in it. Round your answer to 3 significant digits.
Answer:
[Zn²⁺] = 4.78x10⁻¹⁰M
Explanation:
Based on the reaction:
ZnBr₂(aq) + K₂CO₃(aq) → ZnCO₃(s) + 2KBr(aq)
The zinc added produce the insoluble ZnCO₃ with Ksp = 1.46x10⁻¹⁰:
1.46x10⁻¹⁰ = [Zn²⁺] [CO₃²⁻]
We can find the moles of ZnBr₂ added = Moles of Zn²⁺ and moles of K₂CO₃ = Moles of CO₃²⁻ to find the moles of CO₃²⁻ that remains in solution, thus:
Moles ZnB₂ (Molar mass: 225.2g/mol) = Moles Zn²⁺:
6.63g ZnBr₂ * (1mol / 225.2g) = 0.02944moles Zn²⁺
Moles K₂CO₃ = Moles CO₃²⁻:
0.100L * (0.60mol/L) = 0.060 moles CO₃²⁻
Moles CO₃²⁻ in excess: 0.0600moles CO₃²⁻ - 0.02944moles =
0.03056moles CO₃²⁻ / 0.100L = 0.3056M = [CO₃²⁻]
Replacing in Ksp expression:
1.46x10⁻¹⁰ = [Zn²⁺] [0.3056M]
[Zn²⁺] = 4.78x10⁻¹⁰M