3.
Billy has 20 pencils. Melissa gives Billy some shells.
Billy has 20 pencils. Now Billy has 36 shells. How many shells did Melissa
give him?
melissa give him?

Answer:

Step-by-step explanation:

Angle CDB=angle BAC=42°(angles subtended by same chord)

CA is diameter,therefore angle ABC=90°(angle subtended by diameter is 90°)

In triangle CBA ,angle ACB=48°[angle

sum property]

Answer 80

Step-by-step explanation:

If the line is a straight line through two parallel lines then the angles of the two intersections should be the same. Basically because they are both on the bottom right they will be the same.

The value of 'y' is 80 degrees. option B

Note that alternate angles are equal

The intersections of a transversal with two parallel lines forms various types of pairs of angles such as

In this case, the transverse line forms alternate angles of line c and b

Angle at line c = 80 degrees

Angle at line b = y

Since they are alternate angles, y = 80 degrees

Therefore, the value of 'y' is 80 degrees. option B

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The expression sin2x is a trigonometric expression

The equivalent of sin2x is (d) 2sinxcosx

The expression is given as:

sin2x

Rewrite properly as:

sin(2x)

To solve the expression, we make use of the following double angle ratio

sin(2a) = 2sin(a)cos(a)

Substitute x for a in the above equation

sin(2x) = 2sin(x)cos(x)

Rewrite the equation as

sin2x = 2sinxcosx

Hence, the equivalent of sin2x is (d) 2sinxcosx

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Answer:

D

Step-by-step explanation:

A P E X

Answer:

What are the answer choices? I would help but you didn't attach or write them.

Step-by-step explanation:

Answer:

Last Option

Step-by-step explanation:

For this to be true, everyone who works at school must be getting a wage of 8$ so the hourly range of working students at the school IS 8$

Answer:

5.4

Step-by-step explanation:

Using the distance formula:

[tex] \sqrt{ {( - 7 - ( - 2))}^{2} + {(3 - 1)}^{2} } [/tex]

[tex] \sqrt{ {( - 5})^{2} + {2}^{2} } [/tex]

[tex] \sqrt{25 + 4} [/tex]

[tex] \sqrt{29} [/tex]

[tex]5.4[/tex]

Answer:

D

Step-by-step explanation:

I is true. Limits don't care if the point defined or not. All they care about is if they are approaching a value from both sides, unequivocally.

II is not true. We need more information about the type of function.

III is true. Since the point isn't defined but the limit exist, we have a removable discontinuity

Answer:

True

Step-by-step explanation:

y = -2x + 9 is already in slope-intercept form, so we can leave it be. 8x + 4y = 28, however, is not, so we have to convert it to find the answer.

To do this we have to separate the variable 4y from the rest.

We get 4y = -8x + 28.

But, y must equal zero, so to achieve this, we divide the entire equation by 4.

Then we get y = -2x + 7

Since the slopes are the same (-2x = -2x) the lines are parallel.

The negative solution is [tex]-\frac{3}{5}[/tex]

First, add 3 on both sides.

[tex]-2|5x-1|=-8[/tex]

Then, Divide both sides by -2

[tex]|5x-1|=4[/tex]

We know 5x-1 = 4     or 5x-1=-4

[tex]x=1[/tex]             (positive)

[tex]x=-\frac{3}{5}[/tex]          (negative)

Answer:

(6,9)

Step-by-step explanation:

Answer: 405 calories

Step-by-step explanation:

Answer: x=0, 13/2......

Step-by-step explanation:

x - the part

3x one part(first number)

4x second part (second number)

so u have

3x + 4x = 1001

7x= 1001

x = 1001/7

x= 143. First number : 3x = 3• 143 = 429

Second number : 4x = 4• 143= 572

So, 429 and 572 are the numbers

Solution:

[tex]\rightarrow \frac{4^{-3} \times 3^{4} \times 4^{2} }{3^{5} \times 4^{-2} }[/tex]

[tex]\rightarrow 4^{-3 + 2} \times 3^{4 - 5} \times 4^{2} }[/tex]

[tex]\rightarrow 4^{-1} \times 3^{-1} \times 16}[/tex]

[tex]\rightarrow \frac{1}{4} \times \frac{1}{3} \times 16}[/tex]

[tex]\rightarrow \frac{1}{12} \times 16}[/tex]

[tex]\rightarrow \frac{16}{12}[/tex]

[tex]\rightarrow \boxed{\bold{\frac{4}{3} \tex\text{ (Option B)}}}[/tex]

Answer:

[tex]\dfrac43[/tex]

Step-by-step explanation:

      [tex]\dfrac{4^{-3}\cdot3^4\cdot4^2}{3^5\cdot4^{-2}}[/tex]

Separate like terms:

[tex]\implies \dfrac{4^{-3}\cdot4^2}{4^{-2}}\cdot \dfrac{3^4}{3^5}[/tex]

Use exponent rule [tex]a^b \cdot a^c=a^{(b+c)}[/tex] :

[tex]\implies \dfrac{4^{(-3+2)}}{4^{-2}}\cdot \dfrac{3^4}{3^5}[/tex]

[tex]\implies \dfrac{4^{-1}}{4^{-2}}\cdot \dfrac{3^4}{3^5}[/tex]

Use exponent rule   [tex]\dfrac{a^b}{a^c}=a^{(b-c)}[/tex]

[tex]\implies 4^{(-1--2)}\cdot {3^{(4-5)}[/tex]

[tex]\implies 4^{1}\cdot {3^{-1}[/tex]

Use exponent rule  [tex]a^{-1}=\dfrac{1}{a}[/tex]

[tex]\implies 4\cdot \dfrac13[/tex]

[tex]\implies \dfrac43[/tex]

Answer:

Vertex A'  (-8,4)

Vertex B'  (-12,12)

Vertex C'  (-4,12)

Step-by-step explanation:

Multiply all the coordinates by 4!

Answer:

[tex]A'(-8,4)\\B'(-12,12)\\C'(-4,12)[/tex]

Step-by-step explanation:

** Scale and/or dilate signal the operation symbol to be multiplication.

Definitions

[tex]A=(-2,1)\\B=(-3,3)\\C=(-1,3)[/tex]

Formulas

[tex]A'=A4\\B'=B4\\C'=C4[/tex]

Solve

[tex]A'=(-2,1)(4)=(-8,4)\\B'=(-3,3)(4)=(-12,12)\\C'=(-1,3)(4)=(-4,12)[/tex]

Answer:

a = 3b/b-3

because combined the expression and leaving alone the variable

Answer:

  (A, B) = (4, 12) or (12, 4)

Step-by-step explanation:

An Egyptian fraction is the sum of distinct unit fractions. Here, we're asked to decompose 1/3 into an Egyptian fraction sum of two fractions. There are formulas available when the sum has a numerator value of 2.

Here, the sum is a unit fraction. A reasonable approach is to use 1/(n+1) as the larger portion of 1/n. Then the other portion is 1/(n(n+1)). That is effectively what we end up with here.

__

Multiplying by 3AB gives ...

  AB = 3B +3A

Solving for B, we find ...

  AB -3B = 3A

  B(A -3) = 3A

  B = 3A/(A -3)

In order for A-3 to be a factor of A, or equal to 3, we must have ...

  A-3 = 1  ⇒  A = 4

  A-3 = 3  ⇒  A = 6

  A-3 = 3×3  ⇒  A = 4×3

This will give integer values for B when A is one of 4, 6, or 12. In the case of A=6, the two fractions are equal, which is not what you want

The two solutions are ...

  (A, B) = (4, 12) or (12, 4)

Answer: x^2 + 4x + 7

Step-by-step explanation:

Answer:

○ [tex]\displaystyle (2x + 1)(2x - 5) = 0[/tex]

Step-by-step explanation:

Find two quantities that when differed to 8, they also multiply to 20. Those will be 2 and 10. The TINIER quantity gets the plus symbol because the B-value is −8, therefore 10 gets the minus symbol, leaving 2 with the plus symbol. In extension, sinse we have a leading coefficient greater than one, we need to take extra procedures. Here is how it is done:

[tex]\displaystyle y = 4x^2 - 8x - 5 \\ \\ y = [4x^2 - 10x] + [2x - 5] \\ \:\:\:\:\:\:\:\:\:\:\:2x[2x - 5]+ 1[2x - 5] \\ \\ \boxed{[2x - 5][2x + 1] = 0}[/tex]

I am joyous to assist you at any time.

Answer:

Step-by-step explanation:

Not sure what you mean by quotient but 2956?0.03

=98,533.3333333333333333333333

Answer:

A, B, C, and D

Step-by-step explanation:

Answer:

theres no expression..?

Step-by-step explanation:

Answer:

A

Step-by-step explanation:

6

Answer:

28 m

Step-by-step explanation:

Length = x

90 = 2(17 + x)

17 + x = 90/2 = 45

so

x = 45 - 17 = 28 m

Answer:

x=1

Step-by-step explanation: