Answer:
[tex]192686[/tex]
Step-by-step explanation:
23×99×90+54+23-12321
=2277×90+54+23-12321
=204930+54+23-12321
=204984+23-12321
=205007-12321
=192686
Answer:
192686 is answer.
Step-by-step explanation:
= 23*99*90+54+23-12321
= 204930 +77-12321
= 205007 -12321
= 192686.
Given the function, g(x)=5x^5/x^3-2x+1, choose the correct horizontal asymptote. none y = 0 y = 1 y = 3
Answer: NONE
Step-by-step explanation:
Consider that m is the degree of the numerator and n is the degree of the denominator.
The rules for horizontal asymptote (H.A.) are as follows:
If m > n then no H.A. (use long division to find the slant asymptote)
If m = n then H.A. is y = leading coefficient of numerator/leading coefficient of denominator
If m < n then H.A. is y = 0
Given: g(x) = 5x⁵/(x³ - 2x + 1)
--> m = 5, n = 3
Since m > n then there is no H.A.
if four tires can be changed in 3/4 of an hour gow long would it take to change 19 cars
Answer:
14.25 hours
Step-by-step explanation:
Four tires = 3/4 of an hour
=> 1 car = 3/4 of an hour
=> 19 cars = ?
=> If 1 = 3/4
=> 19 = 3/4 x 19
=> 3/4 x 19
=> 57/4
=> 14.25 hours
So, it would take 14.25 hours for 19 car's tires to be changed.
Calculate the expected value of the given random variable X. This exercise assumes familiarity with counting arguments and probability. (Round your answer to one decimal place.) X is the number of green marbles that Suzan has in her hand after she selects seven marbles from a bag containing six red marbles and five green ones.
Answer:
The expected value of:
X = 3 green marbles
Step-by-step explanation:
Number of marbles in a bag = 11
Make-up of the bag = 6 red and 5 green marbles
Sussan selects 7 marbles from the bag
The probability of collecting from 5 of the green marbles = 0.45
The probability of collecting from 6 of the red marbles = 0.55
The expected value of X = the probability of selecting a green marble multiplied by the number of marbles selected
= 0.45 x 7
= 3 green marbles
Which of the following equations shows the correct way to apply the Commutative Property of Addition?(1 point) 2×(4+3)=(2×4)+3 7+y=y+7 a+(c+b)=(a+c)+b 5+5=8+2
Answer:
B. 7 + y = y + 7
Step-by-step explanation:
Commutative property of addition describe an equation in which the order of addition has no effect on the outcome of the sum. The result of addition of the expressions on the left hand side is the same as that on the right hand side. It requires only an addition to property.
In the given question, the equation that shows the correct application of commutative law of addition is; 7 + y = y + 7
Determine whether Y=-x+6 x+y=20 is parallel, perpendicular or neither
Answer:
Parallel
Step-by-step explanation:
-x+6 slope:-1
X+y=20 slope -1
Hence the answer is parallel
What is the correct relationship between events A and B: A: Laura participated in an out-of-town volleyball game at 11:00 AM last Friday. B: Laura met with her academic advisor on campus at 11:00 AM last Friday. A and B are mutually exclusive. A and B are complementary. A and B are not mutually exclusive. If B is true, A is trus
c.
What is the capacity of the airplane?
An airplane is carrying 180 passengers. This is 9/10 of the capacity of the airplane. What is the capacity of the airplane?
Answer:
the capacity of the airplane be 200 passengers
Step-by-step explanation:
According to the question, the data provided is as follows
Number of passengers in an airplane = 180
Capacity = [tex]\frac{9}{10}[/tex]
Based on the above information
Let us assume the capacity of the airplane be x
So the equation would be
[tex]\frac{9}{10} \times x = 180\\\\\\x = \frac{1,800}{9}[/tex]
So x = 200
Therefore the capacity of the airplane be 200 passengers
We simply applied the above equation so that the capacity of the airplane could come
1/64, 1/16, 1/4, 1... What is the pattern and next term???
Answer:
[tex]\huge\boxed{\text{next term}=4}\\\boxed{f(n)=4^{n-4}}[/tex]
Step-by-step explanation:
[tex]\dfrac{1}{64},\ \dfrac{1}{16},\ \dfrac{1}{4},\ 1,\ ...[/tex]
It's the geometric sequence where
[tex]a_1=\dfrac{1}{64},\ q=4[/tex]
[tex]\dfrac{1}{16}=\dfrac{1}{64}\cdot4\\\\\dfrac{1}{4}=\dfrac{1}{16}\cdot4\\\\1=\dfrac{1}{4}\cdot4\\\\1\cdot4=4\to\text{next term}[/tex]
[tex]f(n)=\dfrac{1}{64}\cdot4^{n-1}=\dfrac{1}{4^3}\cdot4^{n-1}=\dfrac{4^{n-1}}{4^3}\\\\\text{use}\ \dfrac{a^n}{a^m}=a^{n-m}\\\\f(n)=4^{n-1-3}=4^{n-4}[/tex]
The owner of an automobile repair shop studied the waiting times for customers who arrive at the shop for an oil change. The following data with waiting times in minutes were collected over a one-month period.2 5 10 124 4 5 1711 8 9 812 21 6 87 13 18 3(a) Develop a frequency distribution using classes of 0-4, 5-9, 10-14, 15-19, and 20-24.Class Frequency0-4 5-9 10-14 15-19 20-24 Total (b) Develop a relative frequency distribution using the classes in part (a). If required, round your answers to two decimal places.Class Relative Frequency0-4 5-9 10-14 15-19 20-24 Total (c) Develop a cumulative frequency distribution using the classes in part (a).(c) Develop a cumulative frequency distribution using the classesClass Cumulative Frequency0-4 5-9 10-14 15-19 20-24 (d) Develop a cumulative relative frequency distribution using the classes in part (a). If required, round your answers to two decimal places.Class Cumulative Relative Frequency0-4 5-9 10-14 15-19 20-24 (e) What proportion of customers needing an oil change wait 9 minutes or less?%
Answer:
Kindly check explanation
Step-by-step explanation:
Waiting times collected over a one month period:
2 5 10 12 4 4 5 17 11 8 9 8 12 21 6 8 7 13 18 3
A)
Class(x) - - frequency(f)
0-4 - - - - - 4
5-9 - - - - - - 8
10-14 - - - - - 5
15-19 - - - - - 2
20-24 - - - - 1
B)
Class(x) - - frequency(f)- - relative frequency(rf)
0-4 - - - - - 4 - - - - - - - - - - 4/20 = 0.20
5-9 - - - - - - 8 - - - - - - - - - - 8/20 = 0.40
10-14 - - - - - 5 - - - - - - - - - - 5/20 = 0.25
15-19 - - - - - 2 - - - - - - - - - - 2/20 = 0.10
20-24 - - - - 1 - - - - - - - - - - - 1/20 = 0.05
C)
Class(x) - - frequency(f) - - cumulative frequency
0-4 - - - - - 4 - - - - - - - - - - - 4
5-9 - - - - - - 8 - - - - - - - - - - - 12
10-14 - - - - - 5 - - - - - - - - - - - 17
15-19 - - - - - 2 - - - - - - - - - - - 19
20-24 - - - - 1 - - - - - - - - - - - - 20
D)
Class(x) - - f - - cf - - - - rf - - - - - - crf
0-4 - - - - 4 - -- 4 - - - 0.20 - - - 0.20
5-9 - - - - - 8 - - 12 - - - 0.40 - - - 0.60
10-14 - - - 5 - - -17 - - - 0.25 - - - 0.85
15-19 - - - 2 - - - 19 - - - 0.10 - - - 0.95
20-24 - - 1 - - - 20 - - 0.05 - - - 1.00
crf - cumulative relative frequency
rf - relative frequency
cf - cumulative frequency
E) 0.6 (from the cumulative relative frequency column)
9 minutes or less :
Frequency = 12, total frequency = 20
12 / 20 = 0.6
The frequency distribution of the given data and frequency table for them would be presented as mentioned below.
Frequency Distribution
Given that,
Data
2 5 10 12 4 4 5 17 11 8 9 8 12 21 6 8 7 13 18 3
a). The use of classes to create a frequency distribution through classes would be as follows:
Class(X) frequency(f)
0-4 4
5-9 8
10-14 5
15-19 2
20-24 1
b). The relative frequency distribution would be as follows:
Class(X) frequency(f) relative frequency(rf)
0-4 4 4/20 = 0.20
5-9 8 8/20 = 0.40
10-14 5 5/20 = 0.25
15-19 2 2/20 = 0.10
20-24 1 1/20 = 0.05
c). The cumulative frequency distribution would be as follows:
Class(X) frequency(f) cumulative frequency(cf)
0-4 4 4
5-9 8 12
10-14 5 17
15-19 2 19
20-24 1 21
d). The cumulative frequency distribution employing classes in part a would be as follows:
Class(X) (f) (cf) rf crf
Frequency Cumulative Relative Cumulative Relative
Frequency Frequency Frequency
0-4 4 4 0.20 0.20
5-9 8 12 0.40 0.60
10-14 5 17 0.25 0.85
15-19 2 19 0.10 0.95
20-24 1 21 0.05 1
e). The proportion of customers requiring an oil change wait 9 minutes would be:
Frequency [tex]= 12[/tex]
Total Frequency [tex]= 20[/tex]
The Proportion of customers requiring an oil change wait 9 minutes or less
[tex]= 12/20\\= 0.6[/tex]
Learn more about "Frequency Distribution" here:
brainly.com/question/7523130
Write the rational number 0.3 in the form ab , where a and b are integers.
Answer:
[tex]\frac{a}{b} = \frac{3}{10}[/tex]
Step-by-step explanation:
Given
[tex]Number = 0.3[/tex]
Required
Represent as [tex]\frac{a}{b}[/tex]
Let [tex]\frac{a}{b} = 0.3[/tex]
This can be further written as
[tex]\frac{a}{b} = \frac{0.3}{1}[/tex]
Multiply the numerator and denominator by 10
[tex]\frac{a}{b} = \frac{0.3 * 10}{1 * 10}[/tex]
[tex]\frac{a}{b} = \frac{3}{10}[/tex]
Since 3 and 10 are both integers, then
[tex]\frac{a}{b} = \frac{3}{10}[/tex]
is 6 a solution of 2x+7=3x
Answer:
No
Step-by-step explanation:
because the answer is 7
2x + 7 = 3x
2x + 7 - 7 = 3x - 7
2x = 3x - 7
2x - 3x = 3x - 7 - 3x
-x = -7
x = 7
simplify 2⁰+5¹+4³/7
Your question has been heard loud and clear.
2^0= 1
5^1= 5
4^3=64
2^0+5^1+4^3/7= 1+5+64/7 = 6+64/7= 15.14
So , 2^0+5^1+4^3/7 = 15.14
Thank you
Zoom In
In Exercises 1-4, use the figure shown. Find the length of each segment.
U
-6-5-4-3-2-1
0
1
2 3
4 5
6 7
8
1. RS =
2. RT =
3. ST
4. RU=
oooo
For Exercises 5-7, use the figure shown.
5. What is PQ?
6. What is QR?
7. What is PR?
Points A, B, C, and D on the figure below are collinear. Use the figure for
Exercises 8 and 9
A
3x
4x
13
8. If AC = 24, what is AB?
9. If BC = 15, what is BD?
Use the figure shown for Exercises 10-13.
10. What is m_PTR?
11. What is m_PTQ?
12. What is m2QTS?
13. Understand Luis said that m2 QTR = 80
Explain Luis's error
Answer/Step-by-step Explanation:
When calculating the length of a segment on a number line, the absolute value of the difference between one point on the numberline, and another point is what we're looking for.
1. Length of RS = |-5 - (-2)| = |-5 + 2| = |-3|
RS = 3
2. Length of RT = |-5 - 2| = |-7|
RS = 7
3. Length of ST = |-2 - 2| = |-4|
ST = 4
4. Length of RU = |-5 - 8| = |-13|
RU = 13
5. Given that the following coordinates:
P = 3
Q = 8
R = 14
5. PQ = |3 - 8| = |-5| = 5
6. QR = |8 - 14| = |-6| = 6
7. PR = |3 - 14| = |-11| = 11
Given that points A, B, C, and D are collinear, and AB = x, BC = 3x, CD = 4x - 13
8. If AC = 24,
BC can be calculated as follows:
AB + BC = AC
[tex] x + 3x = 24 [/tex]
Solve for x
[tex] 4x = 24 [/tex]
Divide both sides by 4
[tex] x = 6 [/tex]
Thus,, BC = 3x = 3(6) = 18
BC = 18
9. If BC = 15, BD can be calculated as follows:
Find the value of x first
BC = 3x
15 = 3x
Divide both sides by 3
5 = x
x = 5.
BD = [tex] 3x + (4x - 13) [/tex]
Plug in the value of x
BD = [tex] 3(5) + (4(5) - 13) = 15 + (20 - 13) [/tex]
BD = [tex] 15 + 7 = 22 [/tex]
BD = 22
10. m<PTR = 80° (taking the reading at the top from 0°)
11. m<PTQ = 45°
12. m<QTS = 128 - 45 = 83°
13. Luis read m<QTR wrongly, what he measured was the whole of <PTR.
According to the angle addition theorem, m<QTR = 80 - 45 = 35°.
16 equals 9x + 4 - 5x solve for x
Answer:
x = 3
Step-by-step explanation:
Step 1: Write out equation
16 = 9x + 4 - 5x
Step 2: Combine like terms
16 = 4x + 4
Step 3: Subtract 4 on both sides
12 = 4x
Step 4: Divide both sides by 4
3 = x
Step 5: Rewrite
x = 3
Clara is growing her hair out and wants it to be no longer than 15 cm but more than 11 cm. Her hair is 7 cm right now and grows at a rate of 0.25 cm per week. The compound inequality 11 < 7 + 0.25t ≤ 15 models the scenario. How long will it take Clara to grow out her hair to the desired length? It will take Clara more than weeks and up to and including weeks to grow out her hair.
Answer:
It will take Clara more than
16
weeks and up to and including
32
weeks to grow out her hair.
Answer:
It will take Clara more than 16 weeks and up to and including 32 weeks to grow out her hair.
Step-by-step explanation:
solve the system of equations below
5x+2y=9
2×-3y=15
Answer:
The solution is (3, -3)
Step-by-step explanation:
5x + 2y = 9
2x - 3y = 15
Use elimination by addition/subtraction. Multiply the first equation by 3 and the second by 2, obtaining:
15x + 6y = 27
4x - 6y = 30
----------------------
19x = 57
This yields x = 3.
Substituting 3 for x into 5x + 2y = 9, we get 5(3) + 2y = 9, or
15 + 2y = 9, or
2y = -6
This yields y = -3.
The solution is (3, -3)
Find the distance between the points (-12, 10) and (16, 10)
A right triangle has the following vertices. Find the area of the triangle.
(7,-3), (4,-3), (4,9)
(A.) 18 square units
(B.) 36 square units
(C.) 27.4 square units
(D.) √153 square units
Answer:
B. 36 square unitsStep-by-step explanation:
Ara of a triangle = 1/2 * base * height.
Before we find the area, we must look for all the sides of the triangle by taking the difference between any two points.
Given D = √(x₂-x₁)²+(y₂-y₁)²
Given the coordinates P(7,-3), Q(4,-3), R(4,9)
For the coordinates P(7,-3), Q(4,-3)
Given PQ = √(4-7)²+(-3+3)²
PQ = √(-3)²+0
PQ = √9
PQ = 3
For coordinates P(7,-3), R(4,9)
Given PR = √(4-7)²+(9+3)²
PR = √(-3)²+12²
PR = √9+144
PR = √153
For coordinates Q(4,-3), R(4,9)
Given QR = √(4-4)²+(9+3)²
QR = √(0)²+12²
QR = √0+144
QR = 12
Since it is a rright angled triangle, the base of the triamgle will be QR and the height will be PQ since the longest side is PR
Area of the triangle = 1/2 * PQ*QR
Area of the triangle = 1/2 * 12*6
Area of the triangle = 6*6
Area of the triangle = 36 square units
What percent of 290 is 120?
Round your answer to the tenths place.
__________________ percent
Answer:
41.4%
Step-by-step explanation:
120/290 = x/100
290x = 120 * 100
x = 41.3793...
The revenue, in dollars, of a company that produces video game systems can be modeled by the expression 5x2 + 2x – 80. The cost, in dollars, of producing the video game systems can be modeled by 5x2 – x + 100, where x is the number of video game systems sold. If profit is the difference between the revenue and the cost, what expression represents the profit?
Answer: 3x-180
Step-by-step explanation:
Given: Expression for Revenue = [tex]5x^2 + 2x - 80[/tex]
Expression for Cost = [tex]5x^2- x + 100[/tex]
If profit is the difference between the revenue and the cost then the expression for profit will be:
Profit = Revenue - cost
[tex]=5x^2 + 2x - 80-(5x^2- x + 100)\\\\=5x^2 + 2x - 80-5x^2+x-100\ \ [\text{Multiply ' - ' sign inside the bracket}]\\\\=2x+x-80-100\\\\=3x-180[/tex]
Hence, the expression represents the profit is 3x-180 .
Answer:
its 3x-180 and for the seond one its $2,820
Step-by-step explanation:
got it right on edge
The common ratio in a geometric series is 0.50.50, point, 5 and the first term is 256.
Find the sum of the first 6 terms in the series.
Answer:
504
Step-by-step explanation:
I think the correct question is like:The common ratio in a geometric series is 0.50 ( point 5) and the first term is 256.
Find the sum of the first 6 terms in the series.
If it's right, then
Sₙ = (a₁ × (1 - rⁿ)) / (1 - r)
S₆ = (256 × ( 1 - 0.5⁶)) / (1 - 0.5)
= (256 × 0.984375) / 0.5
= 504
hope it will help :)
Write the equation of the line that contains (8,0) and is parallel to the line -3x+4y=4
Answer:
y = (3/4)x - 6
Step-by-step explanation:
if line is parallel to -3x + 4y = 4, that means that they both have the same slope
Slope of that second line is 3/4.
now time to find the y-intercept
0 = 3/4*8 + b
therefore, b = -(3/4)*8 = -3*2 = -6
Therefore, equation of line is y = (3/4)x - 6
A newsletter publisher believes that above 41A% of their readers own a personal computer. Is there sufficient evidence at the 0.100.10 level to substantiate the publisher's claim?
Complete Question
A newsletter publisher believes that above 41% of their readers own a personal computer. Is there sufficient evidence at the 0.10 level to substantiate the publisher's claim?
State the null and alternative hypotheses for the above scenario.
Answer:
The null hypothesis is [tex]H_o : p \le 0.411[/tex]
The alternative hypothesis is [tex]H_a : \mu > 0.41[/tex]
Step-by-step explanation:
From the question we are told that
The proportion is [tex]p = 0.41[/tex]
Generally the null hypothesis is [tex]H_o : p \le 0.411[/tex]
The above condition represents the null hypothesis because it contains and equality in its condition
The alternative hypothesis is [tex]H_a : \mu > 0.41[/tex]
Using a rating scale, Tekinarslan (2008) measured computer anxiety among university students who use the computer very often, often, sometimes, and seldom. Below are the results of the one-way ANOVA. Source of Variation SS df MS F Between groups 1,959.79 3 653.26 21.16* Within groups (error) 3,148.61 102 30.86 Total 5,108.41 105 (a) What are the values for N and k
Answer:
K = 4 ; N = 106
Step-by-step explanation:
Given the following :
Source of VARIATION - SS - df - - MS - - - - - F
Between groups - 1,959.79 - 3 - - 653.26 - 21.16*
Error - - - - - - - - 3,148.61 - - - - 102 - - 30.86
Total - - - - - - - - - - - 5,108.41 - 105
The degree of freedom between group (treatment) (DFT) is obtained using the formula ;
K - 1, where k = number of groups observed
DFT = K - 1 ; From the ANOVA table, DFT = 3
3 = K - 1
3 + 1 = K
K = 4
To obtain sample size (N) :
Degree of freedom of Error (DFE) is the difference between the sample size and the number of groups observed.
DFE = N - K ; From. The table DFE = 102 ; K = 4
102 = N - 4
102 + 4 = N
N = 106
A teacher covered the exterior of a rectangular prism-shaped box that measured 8 inches by 9 inches by 10 inches using one sheet of. ... by 9 inches by 10 inches using one sheet of rectangular-shaped wrapping paper that measured 2 feet by 3 feet. ... How many square inches of wrapping paper were left over?
Answer:
380 square inches or 380 in²
Step-by-step explanation:
We are given 2 parameters in the question
A rectangular prism and a rectangular wrapping paper.
To solve the question above, we have to find the areas of these two parameters.
a) Formula for the area of the Rectangular Prism = 2(WL+ HL + HW)
The Rectangular Prism has the dimensions of Length × Width × Height = 8 inches by 9 inches by 10 inches
Where
L = Length = 8 inches
W = Width = 9 inches
H = Height = 10 inches
Area of the Rectangular Prism = 2[(9 × 8) + (10 × 8) + (9 × 10)]
= 2(72 + 80 + 90)
= 2(242)
= 484 in²
b) Formula for the area of a Rectangular shaped wrapping paper
= Length × Breadth
The wrapping paper has measurements of:
2 feet by 3 feet
Since the dimensions of the rectangular prism is in inches, we have to convert that of the rectangular prism to inches as well
1 foot = 12 inches
2 feet = 2 × 12 inches = 24 inches
3 feet = 3 × 12 inches = 36 inches
Area of the Rectangular shaped wrapping paper = Length × Width
= 24 in × 36 in
= 864 in²
The amount of square inches of wrapping paper left.
= Area of Rectangular wrapping paper - Area of Rectangular prism
= 864 in² - 484 in²
= 380 in²
If 12 babies made up 0.1% of the babies born each day – how many in total were born each day?
Answer:
120 babies
Step-by-step explanation:
Divide 12 by 0.1:
12/0.1
= 120
So, 120 babies were born each day.
heplfdjnhkmxdjnhkml,;.
Answer:
d
Step-by-step explanation:
im pretty sure the right answer would be 12 and 21 just doesn't look right
In a study of 1228 randomly selected medical malpractice lawsuits, it was found that 856 of them were dropped or dismissed (based on data from the Physicians Insurers Association of America). Use a 0.01 significance level to test the claim that there is a difference between the rate of medical malpractice lawsuits that go to trial and the rate of such lawsuits that are dropped or dismissed.
Answer:
we accept the alternate hypothesis that
there is a difference between the rate of medical malpractice lawsuits that go to trial and the rate of such lawsuits that are dropped or dismissed.
Step-by-step explanation:
We first write out our null and alternate hypothesis.
H0: no difference
H1: there is difference
n = 1228
P = 856
X = n-p
= 372
Z = ((x+0.5)-1228/2) divided by √1228/2
= 372.5 - 614/17.52
= -13.784
|Z|= 13.784
The decision is to reject the null hypothesis and accept the alternate because there is evidence that dismissed lawsuit if bigger than 0.5. so there is difference between lawsuits that go to trial and lawsuits that are dismissed
For each of the following vector fields
F, decide whether it is conservative or not by computing the appropriate first order partial derivatives. Type in a potentialfunction f (that is, ∇f = F) with f(0,0)=0. If it is not conservative, type N.
A. F(x,y)=(−16x+2y)i+(2x+10y) j f(x,y)= _____
B. F(x,y)=−8yi−7xj f(x,y)=_____
C. F(x,y)=(−8sin y)i+(4y−8xcosy)j f(x,y)=_____
(A)
[tex]\dfrac{\partial f}{\partial x}=-16x+2y[/tex]
[tex]\implies f(x,y)=-8x^2+2xy+g(y)[/tex]
[tex]\implies\dfrac{\partial f}{\partial y}=2x+\dfrac{\mathrm dg}{\mathrm dy}=2x+10y[/tex]
[tex]\implies\dfrac{\mathrm dg}{\mathrm dy}=10y[/tex]
[tex]\implies g(y)=5y^2+C[/tex]
[tex]\implies f(x,y)=\boxed{-8x^2+2xy+5y^2+C}[/tex]
(B)
[tex]\dfrac{\partial f}{\partial x}=-8y[/tex]
[tex]\implies f(x,y)=-8xy+g(y)[/tex]
[tex]\implies\dfrac{\partial f}{\partial y}=-8x+\dfrac{\mathrm dg}{\mathrm dy}=-7x[/tex]
[tex]\implies \dfrac{\mathrm dg}{\mathrm dy}=x[/tex]
But we assume [tex]g(y)[/tex] is a function of [tex]y[/tex] alone, so there is not potential function here.
(C)
[tex]\dfrac{\partial f}{\partial x}=-8\sin y[/tex]
[tex]\implies f(x,y)=-8x\sin y+g(x,y)[/tex]
[tex]\implies\dfrac{\partial f}{\partial y}=-8x\cos y+\dfrac{\mathrm dg}{\mathrm dy}=4y-8x\cos y[/tex]
[tex]\implies\dfrac{\mathrm dg}{\mathrm dy}=4y[/tex]
[tex]\implies g(y)=2y^2+C[/tex]
[tex]\implies f(x,y)=\boxed{-8x\sin y+2y^2+C}[/tex]
For (A) and (C), we have [tex]f(0,0)=0[/tex], which makes [tex]C=0[/tex] for both.
Which expression is equivalent to the following complex fraction?
StartFraction 3 Over x minus 1 EndFraction minus 4 divided by 2 minus StartFraction 2 Over x minus 1 EndFraction
StartFraction 2 (x minus 2) Over negative 4 x + 7 EndFraction
StartFraction negative 4 x + 7 Over 2 (x minus 2) EndFraction
StartFraction negative 4 x + 7 Over 2 (x squared minus 2) EndFraction
StartFraction 2 (x squared minus 2) Over (negative 4 x + 7) EndFraction
Answer:
[tex]\dfrac{-4x+7}{2(x-2)}[/tex]
Step-by-step explanation:
Write the terms of numerator and denominator using a common denominator.
[tex]\dfrac{\dfrac{3}{x-1}-4}{2-\dfrac{2}{x-1}}=\dfrac{\left(\dfrac{3-4(x-1)}{x-1}\right)}{\left(\dfrac{2(x-1)-2}{x-1}\right)}}=\boxed{\dfrac{-4x+7}{2(x-2)}}[/tex]
Answer: It's B on Edge 1843
Step-by-step explanation:
Don't listen to the guys in the comments they have peanuts for brains