2 divide by 7/6
pls help

Answer:

experimental study.

Step-by-step explanation:

This study is an example of an experimental study.

The type of training program is the independent variable. The number of incidents of bullying is the dependent variable.

Since the participants of our study are affected directly in the research (the fourth-grade children) by not training against anti-bullying, the study is experimental research.

An independent variable is one that is somehow controlled or adjusted to evaluate the effects of a different variable, the dependent. Since we control whether we do bullying training here or not, our kind of training program is our independent variable, which is our dependent variable since we measure its impact on instances of bullying no.

Answer:

[tex]2[/tex]

Step-by-step explanation:

Every time the x-value increases by 1, the y-value increases by 2. Therefore, the slope of the line must be equal to [tex]2/1=\boxed{2}[/tex] (rise/y-values over run/x-values). In slope-intercept form [tex]y=mx+b[/tex], [tex]m[/tex] represents the slope of the line, [tex]b[/tex] represents the y-intercept, and [tex](x,y)[/tex] represents any point the line passes through.

Since [tex]m[/tex] represents the slope of the line, the value of

While the question only asks for this value, it's good to note that the equation of the function is [tex]y=2x+7[/tex] (find 7 by substituting any ordered pair in the table with [tex]m=2[/tex]).

Answer:

y = 2x + 7

Step-by-step explanation:

y = mx + b

For every increase of 1 in x,

there is an increase of 2 in y

m = 2

When x is 0,

y is 7

b = 7

y = 2x + 7

Answer:

$4.60

Step-by-step explanation:

1 lb ---> 80 cents

5 3/4 lb ---> 5 3/4 * 80 cents

[tex] 5 \dfrac{3}{4} \times 80 = [/tex]

[tex] = \dfrac{23}{4} \times \dfrac{80}{1} [/tex]

[tex] = \dfrac{23 \times 80}{4 \times 1} [/tex]

[tex] = \dfrac{1840}{4} [/tex]

[tex] = 460 [/tex]

460 cents = $4.60

Answer: the answer is x= -11.

Answer:

We reject H₀, we have enough argument to explain that the production line is out of control. Is producing sprinkler out of specification

Step-by-step explanation:

Data information:

27 41 22 27 23 35 30 33 24 27 28 22 24

sample size  n  =  13

sample mean    x  =   27.92

sample standard deviation   s  =  5.39

The manufacturing process under control will always produce an output with normal distribution, in this case as n < 30  we will use t-student distribution in our test.

Hypothesis Test:

Null Hypothesis                                H₀            x  =  25

Alternative Hypothesis                    Hₐ            x  >  25

The Alternative hypothesis indicates that the test is a one-tail test.

Significance level is  α = 0.05

From z-table and for  α = 0.05  and  df =  n  - 1  df = 13 - 1  df = 12

p-value  = 1.782

t(s)  =  (  x   -    25 ) / s/√n

t(s) = ( 27.92 -  25 )/ 5.39/√13

t(s)  =  2.92*3.605/ 5.39

t(s) = 1.95

From t-table  df = 12  we find that 1.95 corresponds to a p-value < 0.05

then as p-value < 0.05  we are in the rejection region for H₀  then we reject H₀. We can deduce that the production line for sprinkler is given products out of specification

how many comparisons are needed to merge two ordered lists

[2, 9, 12, 17, 20] and [1, 4, 5, 6, 7, 8, 23]

There are 11 comparisons to merge the two lists

The ordered lists are given as:

[2, 9, 12, 17, 20] and [1, 4, 5, 6, 7, 8, 23]

The number of elements in both lists are:

5 and 12

So, the number of comparison is:

Comparison = 5 + 7 - 1

Evaluate

Comparison = 11

Hence, there are 11 comparisons to merge the two lists

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Answer:

Y=x+3

Step-by-step explanation:

we have :

     x1= -7

     y1= -4

    m=1

as we know Y-y1=m(X-x1)

Y+4=(X+7)

Y+4=X+7

Y=X+7-4

Y=X+3

Answer:

[tex]Probability = \frac{4}{15}[/tex]

Step-by-step explanation:

B1 = first bag

B2= second bag

B3 = third bag

Let A = ball drawn is red

Since, there are three bags.

Probability of choosing one bag=  P(B1) = P(B2) = P(B3) = 1/3.

From B1: Total balls = 10

3 red + 7 black balls.

Probability of drawing 1 red ball from it , P(A) = 3/10.

From B2: Total balls = 10

8 red + 2 black

Probability of drawing 1 red ball is, P(A) = 8/10

From B3 : Total Balls = 10

4 red + 6 black

Probability of drawing 1 red ball, P(A) = 4/10 .

To find Probability given that the ball drawn is red, that the ball is drawn from the third bag by Bayes' rule.

That is , P(B3|A)

                     [tex]=\frac{\frac{1}{3} \times \frac{4}{10}} { \frac{1}{3} \times \frac{3}{10} + \frac{1}{3} \times\frac{8}{10} + \frac{1}{3} \times \frac{4}{10}}[/tex]

                    [tex]=\frac{4}{30} \times \frac{30}{15}\\\\=\frac{4}{15}[/tex]

Therefore, the probability that it is drawn from the third bag is 4/15.

Answer:

4/15

Step-by-step explanation:

Solution of conditional probability problem:

Given:

Bags (3R,7B), (8R,2B), (4R,6B)

Let

P(R,i) = probability of drawing a red AND from bag i

P(R, 1) = 3/10 * (1/3) = 3/30

P(R, 2) = 8/10 * (1/3) = 8/30

P(R, 3) = 4/10 * (1/3) = 4/30

Let

Let P(R) = probability of drawing a red from any bag

P(R) = sum P(R,i)  for i = 1 to 3   using the addition rule

= 3/30 + 8/30 + 4/30

= 15/30

= 1 / 2

Conditional Probability of drawing from the third bag GIVEN that it is a red

= P(3 | R)

= P(R, 3) / P(R)

= 4/30 / (1/2)

= 8/30

= 4 / 15

(Since all bags contain 10 balls, by intuition, 4 red from third / 15 total red = 4/15)

Answer:

tan= 4

Step-by-step explanation:

This is actually very easy, basically u have 5 - 9.

So you have positive nine and a negative sign, which is used for subtraction, so in the integers rule, positive- negative= negative

so its 4.

I HOPE ITS RIGHT, IM 11

If tan(A)=5 and tan(B)=9 the value of tan(A−B) will be -0.086.

Trigonometry is a branch of mathematics that deals with the relationship between the sides and angles of a right-angle triangle. The trigonometric ratio is defined as the ratio of the pair of a right-angled triangle.

It discusses how triangle side lengths and angles relate to one another. Using trigonometric formulas and functions, it is mostly used to determine the unknown side lengths and angles of a right-angled triangle. Six different functions are frequently employed in trigonometry.

It is given that tan(A)=5 and tan(B)=9

As we know,

[tex]\rm tan(A -B) = \frac{tan A - tan B}{1- tan A tan B}[/tex]

Substitute the given values we get,

tan(A -B) = (tan A - tan B)/(1 + tan A tan B)

tan(A -B)  = (5-9) / (1 + 5 × 9)

tan(A -B) = (-4) / (1 + 45)

tan(A -B) = -4 / 46

tan(A -B) = -2/23

tan(A -B) = - 0.086

Thus ,if tan(A)=5 and tan(B)=9 the value of tan(A−B) will be -0.086.

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Answer:

Area of the hurricane = 7853 or 3.14  x  50 squared

9514 1404 393

Answer:

Step-by-step explanation:

I find the easiest way to answer these questions is to use a graphing calculator. It can show you the extreme values and the intercepts. The graph below shows the maximum height is 26.5 ft. The time in air is about 2.5 seconds.

__

If you prefer to solve this algebraically, you can use the equation of the axis of symmetry to find the time of the maximum height:

  t = -b/(2a) = -(40)/(2×-16) = 5/4

Then the maximum height is ...

  h(5/4) = -16(5/4)² +40(5/4) +1.5 = -25 +50 +1.5 = 26.5 . . . feet

__

Now that we know the vertex of the function, we can write it in vertex form:

  h(t) = -16(t -5/4)² +26.5

Solving for the value of t that makes this zero, we get ...

  0 = -16(t -5/4)² +26.5

  16(t -5/4)² = 26.5

  (t -5/4)² = 26.5/16 = 1.65625

Then ...

  t = 1.25 +√1.65625 ≈ 2.536954

The cannon ball is in the air about 2.5 seconds.

Answer:

y = 72.5

x = 35.

Step-by-step explanation:

First Off, Let's Divide the question.

Let's Find the variable y :

there are 2 y(s), so it is 2y.

equation:   2y +35   =180.

I put 180 because A straight Line is always 180.

2y+35=180

1. Subtract both sides.

2y =  145

y = 72.5

Next,Find x

So y + y + x = 180.

We already know y, which is 72.5

72.5 +72.5 + x = 180

72.5 +72.5

x + 145 = 180

x =  35.

Hope This Helps!

9514 1404 393

Answer:

  A(x) = 20000(0.88)^x

Step-by-step explanation:

The general form of these exponential equations is ...

  A(x) = a·b^x

where 'a' is the initial value, and b is the annual growth factor. x is the elapsed time in years.

The growth factor is ...

  growth factor = 1 + growth rate

Here, the growth rate per year is -12%, so the growth factor is ...

  b = 1 -12% = 88% = 0.88

Of course, the initial value is a=20,000, so the equation is ...

  A(x) = 20000(0.88)^x

Step-by-step explanation:

Tập nghiệm của [tex]2^x=-1[/tex] là tập rỗng nha bạn. Vì 2 là số dương nên mũ mấy cũng dương hết.

Answer:

y = 0 or 12

Step-by-step explanation:

[tex]Let \ (x _ 1 , y _ 1) \ and \ (x _ 2 , y _ 2 ) \ be \ the \ coordinates \ \\\\Distance \ between \ the \ points = \sqrt{(x_2 - x_1)^2 + (y_ 2 -y_1)^2}\\\\[/tex]

[tex]Given : distance = 10 \ units , (x_1 , y _ 1 ) = ( - 1 , 6 ) \ and \ (x_2 , y _ 2 ) = (7 , y )\\\\[/tex]

[tex]Substituting \ the \ values \ \\\\10 = \sqrt{(7 -(-1))^2 + (y - 6)^2}\\\\10 = \sqrt{(7 + 1)^2 + ( y - 6 )^2}\\\\10 = \sqrt{8^2 + ( y - 6)^2 }\\\\10 = \sqrt{64 + (y -6)^2 } \\\\Squaring \ both \ sides \\\\10^2 = (\sqrt{64 + (y -6)^2 })^2\\\\100 = 64 + ( y -6)^2\\\\100 - 6 4 = ( y -6)^2 \\\\36 = ( y - 6 )^2\\\\\sqrt{36} = y - 6\\\\\pm 6 = y - 6 \\\\So, \\\\\ y - 6 = 6 => y = 12\\\\\ \ \ \ y - 6 = - 6 => y = 0[/tex]

The y coordinate of the point is P ( 7 , 12 ) or P ( 7 , 0 ) where the distance of the point is 10 units from Q ( -1 , 6 )

The distance of a line between 2 points is always positive and given by the formula

Let the first point be A ( x₁ , y₁ ) and the second point be B ( x₂ , y₂ )

The distance between A and B is D , and the distance D is

Distance D = √ ( x₂ - x₁ )² + ( y₂ - y₁ )²

Given data ,

Let the first point be P ( 7 , y )

Let the second point be Q ( -1 , 6 )

Now , the distance between P and Q is D = 10 units

So , on simplifying the equation , we get

Distance D = √ ( x₂ - x₁ )² + ( y₂ - y₁ )²

10 = √ [ ( 7 - ( - 1 ) )² + ( y - 6 )² ]

Squaring both sides of the equation , we get

100 = ( 8 )² + ( y - 6 )²

Subtracting 64 on both sides of the equation , we get

( y - 6 )² = 36

Taking square roots on both sides , we get

y - 6 = ±6

Adding 6 on both sides , we get

y = +6 + 6 = 12

or y = -6 + 6 = 0

So , the coordinates of the point P is  P ( 7 , 12 ) or P ( 7 , 0 )

Hence , the distance formula is solved and coordinates of the point P is  P ( 7 , 12 ) or P ( 7 , 0 )

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Answer:

What ever.....

tan46 = x/8

x = 8×tan46

x = 8,28424251

Answer:

Step-by-step explanation:

Answer:

x<8

Step-by-step explanation:

Answer:

DE = 24

Step-by-step explanation:

The midsegment DE is half the length of the third side AC , that is

DE = [tex]\frac{1}{2}[/tex] AC = [tex]\frac{1}{2}[/tex] × 48 = 24

Answer:

-1/4x² + 3

Step-by-step explanation:

Given that:

Path of sprinkler is modeled by the quadratic function :

w(x) = -1/4(x^2 -12 )

w(x) = height of the water, in meters, at position x

The height of ceiling as a constant or Coefficient = w(x)

Expanding w(x)

-1/4(x^2 -12 )

-1/4 * x² + 1/4 * 12

-1/4x² + 3

The height of ceiling is -1/4x² + 3

Answer:

5

Step-by-step explanation:

275x5= 1375

1375+55=1430

Answer: 3 and 4

Step-by-step explanation:

Answer:

(345)8 = (11100101)2

(11100101)2 =  E5

Step-by-step explanation:

Step 1: Look up each octal digit to obtain the equivalent group of three binary digits

(3)8 = (011)2

(4)8 = (100)2

(5)8 = (101)2

Step 2: Group each value of step 1 to make a binary number:  

011 100 101  

So, (11100101)2 is the binary equivalent to (345)8

Step 3: Converting the binary number to hexadecimal.

Write down the binary number:  

11100101

Step 4: Group all the digits in sets of four starting from the LSB (far right). Add zeros to the left of the last digit if there aren't enough digits to make a set of four:

1110 0101

Step 5: Use the table below to convert each set of three into an hexadecimal digit:

1110 = E, 0101 = 5

So, E5 is is the hexadecimal equivalent to the decimal number 11100101.

Answer:

Where's the graph?

Step-by-step explanation:

Answer:

x^2-2x=10

a few more steps...

the answer is 1+the square root of 11

Answer:

option 2

Step-by-step explanation:

4)

Equation of a Circle with centre ( a , b) and radius r

[tex](x - a)^2 + (y-b)^2 = r^2\\[/tex]

Given centre = ( -3 , 4), r = 5

Therefore Equation

                       [tex](x - ( - 3))^2 + (y-4)^2 = 5^2\\\\(x + 3)^2 + (y-4)^2 = 25[/tex]

5)

Centre =  ( 2 , 0) , radius, r = 3

[tex](x - 2)^2 + (y-0)^2 = 3^2\\\\(x -2)^2 + y^2 = 9[/tex]

Answer:

0.375

Step-by-step explanation:

Check the picture below.

whenever we do division of decimals, we have to mind how many decimals are there on each amount, the dividend as well as the divisor, that way we pad with zeros the other amount accordingly whilst losing the dot, for example, to say divide 3 by 0.123, 3 has no decimals, whilst 0.123 has three decimals, so we can just divide 3000 by 0123, so dividing 3 by 0.123 is the same as dividing 3000 by 123.  Another example, if we were to divide say 23.761 by 555.89331, the dividend has 3 decimals, that means 3 zeros the other way, the divisor has 5 decimals, that means 5 zeros the other way while losing the dots, so we'd end up dividing 2376100000 by 55589331000, which we can simplify to just 2376100 by 5589331, as you can see in the picture in this case.

Answer:

[tex]\huge\boxed{\boxed{\underline{\textsf{\textbf{Answer}}}}}[/tex]

Let's consider each of the statements.

1. Six below zero.

⟹ Any number below zero will be negative. So, the value will be [tex]\boxed{-6}[/tex]

____________________

2. The opposite of six.

⟹ The opposite of 6 wil be negative 6. The value again will be [tex]\boxed{-6}[/tex]

____________________

3. Negative six.

⟹ Negative six in numerical form is [tex]\boxed{-6}[/tex]

____________________

4. The absolute value of six.

⟹ Here they've asked the absolute value of 6 which will be [tex]\boxed{6}[/tex]

____________________

⏩ So, the statement which doesn't have the same value will be ⇻ [tex]\boxed{statement \ 4}[/tex]

____________________

ʰᵒᵖᵉ ⁱᵗ ʰᵉˡᵖˢ

[tex]RainbowSalt2^{2}2^{2}[/tex]

Answer:

1- statistical

2- statistical

4 - statistical

remaining others are non statistical in my opinion