2. A 2500 kg car is slowed down uniformly from an initial velocity of 20.0 m/s to
the north by a 6250 N braking force acting opposite the car's motion. Use the
impulse-momentum theorem to answer the following questions:
a. What is the car's velocity after 2.50 s?
b. How far does the car move during 2.50 s?
c. How long does it take the car to come to a complete stop?

Answer:

The force will be [tex]F_{c}=2.47 N[/tex]

Explanation:

Let's use the centripetal force equation.

[tex]F_{c}=m\omega ^{2}R[/tex]

Where:

m is the mass of the bunch of bananas

ω is the angular speed

R is the radius

Now, 1 rev every 4 seconds or 0.25 rev/sec is the angular speed, but we need to write this speed in rad per second.

[tex]\omega =0.25\frac{rev}{s}=0.25*2\pi \frac{rad}{s}=1.57 \frac{rad}{s}[/tex]

FInally, the force will be:

[tex]F_{c}=2.0*1.57^{2}*0.5[/tex]

[tex]F_{c}=2.0*1.57^{2}*0.5[/tex]

[tex]F_{c}=2.47 N[/tex]

I hope it helps you!

Small cuts or scratches on your body, which are easier to "repair," lead to very rapid

blood clotting; more serious wounds, like a deep gash in your leg, clot more slowly.

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Answer:

Force of sun on  earth can  be written:

F = G M m / R^2

Centripetal force on earth can be written:

F= m w^2 R

Equating these:

G M / R^2 = w^2 R

Or   w^2 = G (M / R^3)

Since no/ days per year is proportional to w (time for 1 revolution)

Increasing M (mass of sun) would increase w or decrease length of year

Increasing the mean radius R would decrease w  or increase length of year

Answer:

149.96J

Explanation:

Given parameters:

Number of stairs = 33

Height  = 0.25m

Weight  = 599.85N

Unknown:

Energy the person takes to reach the top  = ?

Solution:

To solve this problem;

  The energy it takes is given as:

          Energy  = weight x height

          Energy  = mass x gravity x height

Now,

  Insert the given parameters and solve;

        Energy  = 599.85 x 0.25  = 149.96J

Answer:

0.7432m²

1152in²

Explanation:

a) Usng the conversion

1ft² = 0.0929m²

8ft² = y

y = 8 × 0.0929

y = 0.7432m²

Hence 8ft² in m² is 0.7432m²

For ft² to in²

1ft² = 144in²

8ft² = x

X =8×144

x = 1152in²

Hence 8ft² expressed in in² is 1152in²

Answer:

1. 65 N.

2. 160 N.

3. 0 N.

4. 210 N.

5. 90 N.

Explanation:

1. Determination of the net force.

Force applied to the right (Fᵣ) = 80 N

Force applied to the left (Fₗ) = 145 N

Net force (Fₙ) =?

Fₙ = Fₗ – Fᵣ

Fₙ = 145 – 80

Fₙ = 65 N

Thus, the net force is 65 N

2. Determination of the net force.

Force 1 applied to the left (F₁) = 35 N

Force 2 applied to the left (F₂) = 125 N

Net force (Fₙ) =?

Fₙ = F₁ + F₂

Fₙ = 35 + 125

Fₙ = 160 N

Thus, the net force is 160 N.

3. Determination of the net force.

Force applied to the right (Fᵣ) = 75 N

Force applied to the left (Fₗ) = 75 N

Net force (Fₙ) =?

Fₙ = Fₗ – Fᵣ

Fₙ = 75 – 75

Fₙ = 0

Thus, the net force is 0 N

4. Determination of the net force.

Force 1 applied to the right (F₁) = 150 N

Force 2 applied to the right (F₂) = 60 N

Net force (Fₙ) =?

Fₙ = F₁ + F₂

Fₙ = 150 + 60

Fₙ = 210 N

Thus, the net force is 210 N.

5. Determination of the net force.

Force applied to the right (Fᵣ) = 115 N

Force applied to the left (Fₗ) = 25 N

Net force (Fₙ) =?

Fₙ = Fᵣ – Fₗ

Fₙ = 115 – 25

Fₙ = 90 N

Thus, the net force is 90 N

Answer:

The average force exerted by the water on the ground is 17.53 N.

Explanation:

Given;

mass flow rate of the water, m' = 135 kg/min

height of fall of the water, h = 3.1 m

the time taken for the water to fall to the ground;

[tex]h = ut + \frac{1}{2}gt^2\\\\h = 0 + \frac{1}{2}gt^2\\\\t = \sqrt{\frac{2\times 3.1}{9.8} } \\\\t = 0.795 \ s[/tex]

mass of the water;

[tex]m = m't\\\\m = 135 \ \frac{kg}{min} \ \times \ 0.795 \ s \ \times \ \frac{1 \ \min}{60 \ s} \ = 1.789 \ kg[/tex]

the average force exerted by the water on the ground;

F = mg

F = 1.789 x 9.8

F = 17.53 N

Therefore, the average force exerted by the water on the ground is 17.53 N.

Answer:

The object gains or loses electrons to become charged. Both are a movement of electrons from the negative to the positive charge. A circuit has a continuous current provided by a voltage source.

Explanation:

Answer:

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Explanation:

I need points sorry

Answer:

honestly this was so long ago can i get brainliest i need 2 more until i am at expert level

Explanation:

Answer: Four times

Explanation:

Given

If Pressure and Volume is double

For ideal gas

PV=nRT

where P=Pressure

V=volume

n=no of moles

R=gas constant

T=temperature

Initially

PV=nRT......(i)

after doubling

(2P)(2V)=nRT'.......(ii)

divide (i) and (ii)

[tex]\frac{PV}{4PV}=\frac{nRT}{nRT'}\\T'=4T[/tex]

So, Temperature becomes 4 times

Answer: 100 cm

Explanation: When an object at the bottom of a tank with water is viewed vertically from above, to the observer, it seems the object is closer to the eye, i.e., the apparent depth of the object is less than the real depth the object is. This is caused by Refraction, which happens when an incident light passing through an interface between two different media causing the light to be deflected.

The relation between real and apparent depths is given by:

[tex]n=\frac{Dr}{Da}[/tex]

where

n is refractive index of the surface

Dr is real depth

Da is apparent depth

For the coin at the bottom of a tank, apparent depth is:

[tex]n=\frac{Dr}{Da}[/tex]

[tex]Da=\frac{Dr}{n}[/tex]

[tex]Da=\frac{130}{1.3}[/tex]

Da = 100

Apparent displacement of the coin viewed vertically from above is 100 cm.

Answer:

The heat change of the system is 30 J.

Explanation:

Given;

increase in internal energy of a system, ΔU = 80 J

work done on the system, W = 50 J

The heat change of the system can be calculated from first law of Thermodynamics;

ΔU = Q - W

where;

Q is the heat absorbed by the system

W is the work done by the system (negative when work is done by the system and positive when work is done on the system)

Since work was done on the system the increase internal energy is given as;

ΔU = Q  + W

ΔU  - W = Q

80 J - 50 J = Q

30 J = Q

Therefore, the heat change of the system is 30 J.

Answer:

3.75 km away

Explanation:

From the law of moments, clockwise moments = anticlockwise moment

So WL = wl where W = weight of elephant = Mg and M = mass of elephant = 5000 kg, L = distance of elephant from axis of rotation = 0.75 m, and w = weight of mouse = mg where m= mass of mouse = 100 g = 0.1 kg and l =  distance of mouse from axis of rotation = unknown and g = acceleration due to gravity.

So, MgL = mgl

ML = ml

l = ML/m

= 5000 kg × 0.75 m/0.1 kg

= 3750 kgm/0.1 kg

= 37500 m

= 3.75 km away

Answer:

A-50 N

Explanation:

Answer:

D) See the explanation below.

Explanation:

Heat transfer is always given from a body of higher temperature to a lower temperature. In this way the heat from the boiling water is transferred to the ice bars and the energy of the phase change from solid to liquid from the ice is transferred to the environment

Answer:

DU = 20 Joules

Explanation:

Given the following data;

Heat absorbed, Q = 60J

Workdone, W = 40J

To find the internal energy;

We would use first law of thermodynamics given by the formula;

Change in internal energy (DU) = Q - W

where;

U is internal energy.

Q is the heat absorbed.

W is the work done.

Substituting into the equation, we have;

DU = 60 - 40

DU = 20 Joules

Answer:

The magnitude of each force is 66.67 N

Explanation:

Given that the magnitude of the tension forces are equal. Let the magnitude of the tension forces be represented by x, such that;

|OA| = |OB| = |OC| = x

Since their summation = 200 N, then;

|OA| + |OB| + |OC| = 200

This implies that;

x + x + x = 200

3x = 200

x = [tex]\frac{200}{3}[/tex]

    = 66.6667

x = 66.67 N

Therefore, the magnitude of each tension force is approximately 66.67 N

Answer:

r2 = 1.25 × 10^(6) m

Explanation:

We are given;

Initial kinetic energy; K_1= 8.0 x 10^(7) J

Mass of planet zero; M = 4.0 x 10^(23) kg

Mass of space probe; m = 10 kg

Radius of planet zero; r1 = 2 × 10^(6) m

From conservation of energy, we can say that;

Initial potential energy + Initial kinetic energy = Final potential energy + Final kinetic energy

This is;

U1 + K1 = U2 + K2

Using formula for potential energy: U = GMm/r, we can write it as;

GMm/r1 + K1 = GMm/r2 + K2

Where Maximum distance = r2

At maximum distance from the center of Zero, K2 = 0.

Thus;

GMm/r1 + K1 = GMm/r2

Making r2 the subject, we have;

r2 = GMm/((GMm/r1)+ K1)

Where G is gravitational constant = 6.67 × 10^(-11) N/m²/kg2

Thus;

r2 = (6.67 × 10^(-11) × 4.0 x 10^(23) × 10)/((6.67 × 10^(-11) × 4.0 x 10^(23) × 10)/(2 × 10^(6)) + (8.0 × 10^(7)))

r2 = 1.25 × 10^(6) m

Answer:

The height (h) will be: [tex]\frac{3}{4}R =h[/tex]  

Explanation:

The scape speed equation is given by:

[tex]v_{scape}=\sqrt{\frac{2GM}{R}}[/tex]

Now, the speed of the missile is

[tex]v_{missile}=\frac{1}{2}v_{scape}[/tex]

[tex]v_{scape}=\frac{1}{2}\sqrt{\frac{2GM}{R}}[/tex]

Using the conservation of energy, we can find the maximu height of the missile.

[tex]E_{i}=E_{f}[/tex]

[tex]\frac{1}{2}mv_{scape}^{2}-mgR =-mgh[/tex]

[tex]\frac{1}{2}\frac{2GM}{4R}-gR =-gh[/tex]

[tex]\frac{GM}{4R}-gR =gh[/tex]

Let's recall that g = GM/R², using the equivalence principle. When R is the radius of the earth and M is the mass of the earth.

[tex]\frac{1}{4}gR-gR =-gh[/tex]

[tex]\frac{1}{4}R-R =-h[/tex]    

Therefore the height (h) will be:

[tex]\frac{3}{4}R =h[/tex]    

I hope it helps you!

Answer:

60*12.0= 720 = v/60 * 12.0 squared which is 1,728

Explanation:

Horizontal velocity component: Vx = V * cos(α)

The horizontal velocity of the projectile is 6.0m/s

If a projectile is launched at an angle from the horizontal and at a velocity v, the horizontal velocity of the projectile is expressed as:

[tex]v_x =vcos \theta[/tex]

Given the following parameters

v = 12.0m/s

[tex]\theta=60^0[/tex]

Substitute the given parameters into the formula to have:

[tex]v_x=12.0cos60\\v_x=12.0(0.5)\\v_x=6.0m/s\\[/tex]

Hence the horizontal velocity of the projectile is 6.0m/s

Learn more here: https://brainly.com/question/23916021

Answer:

i dont know.

Explanation:

school is pointless

Explanation:

In an elastic collision, two or more bodies are in contact with one another and there is no net loss of kinetic energy in the system. By the virtue of this, the bodies and objects do not stick together after they collide.

Both momentum and kinetic energy are conserved in an elastic collision. An example is when a football hits a wall.

For an inelastic collision, the bodies sticks together after they collide and there is a loss of kinetic energy after they collide. An example of this type of collision is when a gum is throw against a wall.

Answer:

True

Explanation:

Answer:

car d

Explanation:

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Which letter represents the position at which the basketball has the greatest potential energy? Explain. Point C. At this point, which is the highest point, all of the ball's energy is gravitational potential energy.

Answer:

A

Explanation:

Answer:

95.7 degrees

Explanation:

The angle through which the particle rotate in radians is 1.667 rad.

Given the following data:

To determine the angle through which the particle rotate in radians:

Mathematically, the angular displacement or arc length in circular motion is given by the formula:

[tex]S=r\theta[/tex]

Where:

Making [tex]\theta[/tex] the subject of formula, we have:

[tex]\theta=\frac{S}{r}[/tex]

Substituting the given parameters into the formula, we have;

[tex]\theta = \frac{2.50}{1.50} \\\\\theta =1.667 \;rad[/tex]

Read more: https://brainly.com/question/8898885

Answer:

86.7

Explanation:

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