1
AI
A3
If A1 = 27A and A3 = 1.9A, what would A2 read?

1AIA3If A1 = 27A And A3 = 1.9A, What Would A2 Read?

Answers

Answer 1

Answer:

0.8A

Explanation:

because im very intelligent and beautiful so the answer is correct and its 0.8A


Related Questions

Which of the following wavelengths have the highest frequency? Group of answer choices a.infrared waves b. radio waves c.microwaves d.visible light

Answers

b...radio waves answer

Apply Pascal's law to a ketchup packet. Explain what will happen if you tear a small
hole in one corner of a packet and then squeeze the packet.

Answers

Answer:

its will explode because it's like a soda with baking soda added together and you shake it the small hole can make a huge explosion

Famous French mathematician, physicist, and philosopher Blaise Pascal announced this law in the year 1647.

What is pascal law?

According to this law, pressure applied to a liquid that is at rest is uniformly distributed throughout.

There are numerous uses for it in daily life. Numerous gadgets, like hydraulic lifts and brakes, are based on Pascal's law.

For incompressible fluids, Pascal's concept is applicable. The majority of vehicle repair shops using lifts use one common use. In essence, air from an air compressor is delivered to the top of oil in a container; the oil then exerts pressure on a sleeve or piston that raises the car.

Therefore, Famous French mathematician, physicist, and philosopher Blaise Pascal announced this law in the year 1647.

To learn more about pascals law, refer to the link:

https://brainly.com/question/21852769

#SPJ2

The height of a transverse waves is known as its?

Answers

Answer:

amplitude

Explanation:

amplitude of a wave is the maximum displacement of a point from its rest position.

hope you get it,

PLS ANSWER FAST WILL GIVE BRAINLEST!!!


Calculate the missing variables using the necessary formula and rules using "FORCE"

A water filled balloon with an overall mass of 1 kg undergoes an acceleration of 2m/s2. How much force is being applied to the ballon?

Answers

Answer:

2 Newtons

Explanation:

[tex]F = ma[/tex]

Therefore, your mass would be 1kg and your acceleration would be 2m/s/s

Plug the numbers into the equation:

[tex](1kg)(2m/s/s)[/tex]

which will equal

[tex]2 Newtons[/tex]

what are subtomic particles

Answers

Answer:

In the physical sciences, subatomic particles are smaller than atoms. They can be composite particles, such as the neutron and proton; or elementary particles, which according to the standard model are not made of other particles. Particle physics and nuclear physics study these particles and how they interact.

Explanation:

Answer:

In physical sciences, subatomic particles are smaller than atoms. They can be composite particles, such as the neutron and proton; or elementary particles, which according to the standard model are not made of other particles.

another A b c or d about the earth...

Answers

Answer:

B seismic wave

5. In an electric bell, electromagnet attracts________
towards itself.​

Answers

Ans: It attracts iron armature

A 30 N force is applied to a box, as shown below in the diagram. (g = 10 m/s2) 30N 2kg The acceleration of the box is​

Answers

30 N = (2 kg)(a)
30 N/2 kg = a
a = 15 m/s/s

The frequency of the wave is 0.4 Hz. Calculate the period.

Answers

Answer:

use the formula

Explanation:

F = 1/T

where F = frequency and T = period

so put 0.4 Hz into the frequency

0.4 =1/T

T = 2.5 seconds

hope this helps

How could a camping fire turn into a forest fire

Answers

Answer:

Campfires top the list of ways that humans start wildfires, the U.S. Forest Service said. Typically, campfires either grow out of control and the people who built the fire do not have a way to stop it, or they fail to extinguish the fire properly, allowing the fire to re-ignite after they leave.

Explanation:

Answer:

Explanation:

Wind can blow the ashes and ignite the leaves

help please!!!!!!!!!!!?!!

Answers

Each of the questions can be answered by the browser

if a 50.0-kg mass weighs 554 n on the planet saturn, calculate saturn’s radius

Answers

Answer:

17.35 × 10^(-6) m

Explanation:

Mass; m = 50 kg

Weight; W = 554 N

Now, we know that;

W = mg

Thus; 554 = 50g

g = 554/50

g = 11.08 m/s²

Also, we know that;

mg = GMm/r²

g = GM/r²

Making t the subject gives;

r = √(GM/g)

G has a constant value of 6.67 × 10^(-11) Nm²/kg²

r = √(6.67 × 10^(-11) × 50/11.08)

r = 17.35 × 10^(-6) m

The radius of the saturn is [tex]\bold {17.35 x 10^{-6 }m}[/tex] if  a 50.0-kg mass weighs 554 N.

From Newton's second law,

W = mg  

554 = 50 x g  

g = 554/50  

g = 11.08 m/s²  

Now, Newton's law of gravitation  

[tex]\bold {F=G{\dfrac{m_1m_2}{r^2}}}[/tex]

Where,

F = force

G = gravitational constant = 6.67 x 10^-11 N.m²/kg²

m1 & m2= mass  = M = 50 kg

r = distance between centers of the masses

Put the values and solve it for r,  

[tex]\bold {r = \sqrt {(6.67 x10^{-11} \times \dfrac {50}{11.08}}}\\\\\bold {r = 17.35 x 10^{-6 }m}[/tex]

Therefore, the radius of the saturn is [tex]\bold {17.35 x 10^{-6 }m}[/tex] if  a 50.0-kg mass weighs 554 N.

To know more about Newton's law of gravitation

https://brainly.com/question/9373839

A 40-kg person is climbing 3 m up a flight of stairs in 6 seconds. How much power did they exert climbing the stairs?

Answers

Answer:

mate i got you

Explanation:

A 40-kg person is climbing 3 m up a flight of stairs in 6 seconds. How much work did they do climbing the stairs? answer choices . 400 J. 1200 J. 200 J. 120 J. Tags: Question 13 . SURVEY . 30 seconds . Report an issue . Q. A 40-kg person is climbing 3 m up a flight of stairs in 6 seconds. How much power did they exert climbing the stairs? answer choices . 400 W. 1200 W. 200 W. 120 W. Tags

200 W was used in climbing the stairs.

We'll begin by calculating the energy. This can be obtained as follow:

Mass (m) = 40 kg

Height (h) = 3 m

Acceleration due to gravity (g) = 10 m/s²

Energy (E) =?

E = mgh

E = 40 × 10 × 3

E = 1200 J

Finally, we shall determine the power exert in climbing the stairs. This can be obtained as follow:

Energy (E) = 1200 J  

Time (t) = 6 s

Power (P) =?

[tex]Power = \frac{Energy }{Time}\\\\Power = \frac{1200}{6}[/tex]

Power = 200 W

Thus, 200 W was used in climbing the stairs.

Learn more: https://brainly.com/question/5534024

Use the drawing below to answer the following question.
1 kg
10 kg
20 kg
50 kg
All of the boxes shown above can slide easily. Which box will move farthest if each is
struck with the same amount of force?
A.
the 1-kg box
B. the 10-kg box
C. the 20-kg box
D. the 50-kg box

Answers

Answer:

A

Explanation:

Force =  mass x acceleration

if the force is constant for each of the boxes, the smaller a boxes mass the greater its acceleration while the force is applied

Therefore the smaller box will have a greater initial velocity and will slide the furthest before it stops.

what's the optical illusion also known as?​

Answers

Answer:

An optical illusion (also called a visual illusion) is an illusion caused by the visual system and characterized by a visual percept that arguably appears to differ from reality. ... Cognitive visual illusions are the result of unconscious inferences and are perhaps those most widely known.

At what point does the ball have the most gravitational potential energy?

Answers

Point C. at this point, which is the highest point, all of the ball’s energy is gravitational potential energy.

Need help ASAP
Thanks + BRAINLIST only for correct answer

1.Cell phones convert sound waves into______waves.
-light waves
-sound waves
-radio waves

2.Electromagnetic waves used in cell phone communications are called?
-microwave
-radio wave
-infrared
-all of the above

3.To send out a radio signal far and wide...it is called?
-broadcast
-casting
-antenna

Answers

Answer:

answer my question

Explanation:

Mhm yeah correct I think yeah yeah lol

plzzzzzzz helppppppp

Answers

Answer:

6th amendment

Explanation:

the judge denied her request for a lawyer when she requested one

What is the velocity of a 750 kg object at a height of 0m if it’s ME is 3590J?

Answers

Answer:

Sorry for this question

A sound wave produced by a chime 515 m away is heard 1.50 s later. What is the speed of the sound in the air?

Answers

Answer:

the speed of the sound in the air is 343.3 m/s

Explanation:

The computation of the speed of the sound in the air is shown below:

As we know that

Speed = Distance ÷ time

So, here speed be 515 m

And, the time is 1.50 seconds

So, the speed of the sound is

= 515 m ÷ 1.50 seconds

= 343.3 m/s

hence, the speed of the sound in the air is 343.3 m/s

these two pls :)))) ill mark brainliest :)

Answers

Answer:

Bowling Ball: weight on Earth = 49 N

Textbook: Mass = 2 kg; weight on the moon = 3.2 N

Large dog: weight on Earth = 490 N; weight on the moon = 80 N

Law of Universal Gravitation: [tex]F_{G}=\frac{Gm_{1}m_{2}}{r^{2}}[/tex]

[tex]F_{G}[/tex] = gravitational force (Newtons/N)

G = gravitational constant, 6.67430 × 10¹¹ [tex]\frac{N*m^{2}}{kg^{2}}[/tex]

m₁ and m₂ = masses of two objects (kilograms/kg)

r² = square of distance between centers of the two objects (meters/m)

Have a fantastic day!

Use newton's law to explain the vertical acceleration of a projectile

Answers

Answer:

Explained below

Explanation:

Newton's first law of motion: This law states that an object will remain at rest or continue in constant motion except it's acted upon by an external force. In projectile motion, the horizontal component of velocity will remain unchanged because we ignore air resistance since no force is acting in that horizontal direction.

Newton's second law of motion: This law states that force is the product of mass and acceleration. In projectile the force acts downwards, thus f = mg.

But g = a since internal forces will cancel out.

Thus, F = ma

Suppose the Sun is 1.29025 X 108 km from
Earth.
The speed of light is 2.99792 x 108 m/s.
How long does it take for its light to reach
us?
Answer in units of min.

Answers

Answer:

It takes the Sun's light 7.17 minutes to reach us.

Explanation:

We can calculate the time that takes the light to reach us by using the following equation:

[tex] t = \frac{d}{c} [/tex]    

Where:

d: is the distance = 1.29025x10⁸ km = 1.29025x10¹¹ m

c: si the speed of light = 2.99792x10⁸ m/s  

Hence, the time is:

[tex] t = \frac{d}{c} = \frac{1.29025 \cdot 10^{11} m}{2.99792 \cdot 10^{8} m/s} = 430.38 s = 7.17 min [/tex]

Therefore, it takes the Sun's light 7.17 minutes to reach us.

I hope it helps you!

3. If you were in a car collision, would you rather be hit by Vehicle 1 (2,027 kg) or Vehicle 2 (1,415 kg) from Activity 73? Explain.​

Answers

Answer:

I say vehicle one, because both will apply the same amount of force but, because vehicle two has less mass, it will accelerate more rather than vehicle one which will accelerate less.

Why do we not feel air pressure?

Answers

Answer:

Explanation:

Is beacuse of the air within our bodys is exerting the same pressure out wards so tjere is no pressure difference

Answer:

it is because our body itself is not  adept enough to resist the air pressure. For every reaction, there be an balanced opposite reaction according to Newton's law. namely, all forces such as air pressure are in proportion therefore we will not perceive air pressure which also means no net force.    

Explanation:

Pls, help with this! I'm having trouble. will give points!!

Answers

Answer:

yes

no

no

no

no

yes

Explanation:

What is the netforce?

Answers

Answer:

6 Newtons to the left.

Explanation:

We can convert  this into a generic algebra equation by giving directions positive and negative values.

The 6 will be positive, and the 10 and 2 will be negative.

Add 10 and 2 to have 12.

6-12 = -6.

Therefore you have 6 newtons to the left (negative).

Take the force towards the right as positive (+6N) and towards the left as negative (-12N)
Add both as net force is the sum of all forces acting on an object
6N+(-12N)= -6N

Scientists treat the number of stars in a given volume of space as a Poisson random variable. The density of our galaxy in the vicinity of our solar system is 3 stars per 10 cubic light-years. What is the probability of one or more stars in 10 cubic light-years? Round your answer to 4 decimal places.

Answers

Answer:

[tex]P(X\ge 1) = 0.9502[/tex]

Explanation:

Given

Density = 3 starts in 10 cubic light years.

Required

Determine the probability of 1 or more in 10 cubic light years

Since the number of stars follow a Poisson distribution, we make use of:

[tex]P(X=k) = f(x) = (\lambda T)^k\frac{ e^{-\lambda T}}{k!}[/tex]

[tex]\lambda = density[/tex]

[tex]\lambda = \frac{3}{10}[/tex]

[tex]\lambda = 0.3[/tex]

T = the light years

[tex]T = 10[/tex]

Calculating [tex]P(X \ge 1)[/tex]

In probability:

[tex]P(X \ge 1) = 1 - P(X = 0)[/tex]

Calculating P(X=0)

Substitute 0 for k and the values for [tex]\lambda[/tex] and T in

[tex]P(X=k) = f(x) = (\lambda T)^k\frac{ e^{-\lambda T}}{k!}[/tex]

[tex]P(X=0) = (0.3* 10)^0 * \frac{ e^{-0.3 * 10}}{0!}[/tex]

[tex]P(X=0) = (3)^0 * \frac{ e^{-0.3 * 10}}{1}[/tex]

[tex]P(X=0) = (3)^0 * e^{-0.3 * 10}[/tex]

[tex]P(X=0) = 1 * e^{-0.3 * 10}[/tex]

[tex]P(X=0) = 1 * e^{-3}[/tex]

[tex]P(X=0) = e^{-3}[/tex]

[tex]P(X=0) = 0.04979[/tex]

Substitute 0.04979 for P(X=0) in [tex]P(X \ge 1) = 1 - P(X = 0)[/tex]

[tex]P(X\ge 1) = 1 - 0.04979[/tex]

[tex]P(X\ge 1) = 0.95021[/tex]

[tex]P(X\ge 1) = 0.9502[/tex] ---  approximated

Hence, the required probability is 0.9502

A child is standing on the platform of a station, watching the trains.
.
A train travelling at 30 m/s takes 3 s to pass the child.
What is the length of the train?
A 10m
B 30 m
C 90 m
D 135 m

Answers

C. 90 m

30m per second... and it takes 3 seconds

3x30= 90
c 90 m
30 times 3 equals 90

An object is placed 110 mm from a concave mirror with a focal length of 5.0 cm.

Answers

Answer:

Approximately 92 mm.

Explanation:

Object's distance, u = 110 mm = 11 cm

focal length of the mirror = 5 cm

Image distance, v = ?

To determine the image distance, apply the mirror's formula;

[tex]\frac{1}{f}[/tex] = [tex]\frac{1}{u}[/tex] + [tex]\frac{1}{v}[/tex]

[tex]\frac{1}{v}[/tex] = [tex]\frac{1}{f}[/tex] - [tex]\frac{1}{u}[/tex]

   = [tex]\frac{1}{5}[/tex] - [tex]\frac{1}{11}[/tex]

   = [tex]\frac{11-5}{55}[/tex]

[tex]\frac{1}{v}[/tex] = [tex]\frac{6}{55}[/tex]

⇒ v = [tex]\frac{55}{6}[/tex]

       = 9.166667

v = 9.2 cm

The image distance is 92 mm.

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