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It is November 1 of Year 1. Sales for Dee Company for November and December of Year 1 and January of Year 2 are forecasted to be as follows:

November, 400,000; December 600,000; January, 200,000

60% of sales are credit sales; the remaining sales are cash sales. Of these credit sales, 5% are collected during the month of sale, 25% in the following month, and 65% in the second following month; 5% are never collected. Total sales for September and October of Year 1 were 100,000 and 150,000, respectively.

What is the forecasted amount of total cash collections in November of Year 1?

Answer:

The right answer is below

Step-by-step explanation:

4.7 is the length of LJ

Answer:

We are given the cost equations for Emma's and Madison's text message plans as:

Emma's Plan: y = 0.10x + 10

Madison's Plan: y = 0.15x

where y is the cost in dollars and x is the number of texts sent. We are also told that Emma and Madison paid the same amount in one month. Let's set the two equations equal to each other and solve for x:

0.10x + 10 = 0.15x

Subtracting 0.10x from both sides, we get:

10 = 0.05x

Dividing both sides by 0.05, we get:

x = 200

Therefore, Emma and Madison sent 200 text messages in one month to pay the same amount

Answer:

We will use mathematical induction to prove the formula for the sum of arithmetic sequences:

For n=1, we have:

∑j=1^1(a + (j-1)d) = a

On the other hand, we have:

n/2(2a + (n-1)d) = 1/2(2a) = a

Thus, the formula holds for n=1.

Assuming the formula holds for n=k, we will prove that it holds for n=k+1.

We have:

∑j=1^(k+1)(a + (j-1)d) = (a + kd) + ∑j=1^k(a + (j-1)d)

Using the formula for n=k, we can write:

∑j=1^k(a + (j-1)d) = k/2(2a + (k-1)d)

Substituting this back into the first equation, we have:

∑j=1^(k+1)(a + (j-1)d) = (a + kd) + k/2(2a + (k-1)d)

Simplifying the right-hand side, we get:

∑j=1^(k+1)(a + (j-1)d) = 1/2(2a + (2k+1)d)

But (k+1)/2(2a + kd + d) = 1/2(2a + (2k+1)d), so the formula holds for n=k+1.

Therefore, by mathematical induction, the formula for the sum of arithmetic sequences is proved.

The total number of creeping bentgrass shoots on a 6000 square feet putting green could range from approximately 480,000 to 600,000 shoots.

The United States Golf Association (USGA) suggests that a healthy putting green, which is well-maintained, can support around 80 to 100 creeping bentgrass plants in each square foot. As the given putting green is 6000 square feet, we can calculate the total number of creeping bentgrass plants on this area by multiplying the area by the suggested number of plants per square foot. Therefore, the total number of creeping bentgrass shoots on a well-maintained 6000 square feet putting green could range from approximately 480,000 to 600,000 shoots, based on the given range of suggested plants per square foot.

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Paul paid $1,635 in interest at the end of the loan.

Simple Interest (S.I.) is the method of calculating the interest amount for a particular principal amount of money at some rate of interest.

The simple interest formula is:

I = P * r * t

where I is the interest, P is the principal (the amount borrowed), r is the annual interest rate as a decimal, and t is the time in years.

In this problem, P = $6,000, r = 0.0545 (since the interest rate is given as 5.45%), and t = 5 years. Plugging in these values, we get:

I = 6,000 * 0.0545 * 5 = $1,635

Therefore, Paul paid $1,635 in interest at the end of the loan.

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Answer:

0.6267

Step-by-step explanation:

See the picture.

Hope its clear.

The pairs of events of random integers are pairs of events are,

even and odd , negative and positive integers, zero and non-zero integers.

Two events are mutually exclusive if they cannot occur at the same time.

Selecting a random integer from -200 to 200,

Any two events that involve selecting a specific integer are mutually exclusive.

For example,

The events selecting the integer -100

And selecting the integer 50 are mutually exclusive

As they cannot both occur at the same time.

Any pair of events that involve selecting a specific integer are mutually exclusive.

Here are a few examples,

Selecting an even integer and selecting an odd integer.

Selecting a negative integer and selecting a positive integer

Selecting the integer 0 and selecting an integer that is not 0.

But,

Events such as selecting an even integer and selecting an integer between -100 and 100 are not mutually exclusive.

As there are even integers between -100 and 100.

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Answer:

N and E is 90 degrees

N and S is 180 degrees

N and W is 90 degrees

When the graph of the equation y=a(x−2)(x+4) in the xy-plane is a parabola with vertex (c,d), then the value of d is equal to option (A) -9a

To find the vertex of the parabola, we need to complete the square by factoring out the constant term a and adding and subtracting a term that will allow us to write the quadratic in the form

y = a(x - h)^2 + k,

where (h,k) are the coordinates of the vertex. We have

y = a(x - 2)(x + 4) = a(x^2 + 2x - 8x - 8) = a[(x + 1)^2 - 9]

Expanding the square and factoring out the constant term a, we get

y = a[(x + 1)^2 - 9] = a(x + 1)^2 - 9a

Comparing this to the standard form of the quadratic, we see that the vertex is at (-1,-9a). The value of d is -9a

Therefore, the correct option is (A) -9a

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Answer:

The order from least to greatest is:

8.2 x 10^-7 < 5.8 x 10^-5 < 1.2 x 10^3 < 9.7 x 10^3 < 3.4 x 10^6

Answer:

it is already in the correct order

Step-by-step explanation:

Step-by-step explanation:

Refer to pic..........

According to the given information, the missing values in the ratio table are:

7. 6:1/3, 12:2, 6:1, 24:4

8. 1/4:3, 2:6, 1:12, 5/4:15

9. 1/3:8/3, 2/3:2/3, 1:1, 4/3:1.04

What is ratio?

A ratio is a mathematical comparison of two or more quantities. Ratios express the proportional relationship between the quantities being compared. Ratios are often written using a colon (:) or as a fraction, such as "1:2" or "1/2".  

7.

We can simplify the ratio of feet to seconds by converting 1/3 to its equivalent fraction with a denominator of 3:

Ratio of feet to seconds = 6 : 1/3 = 6 : (1/3) = 6 : (1/3) x (3/3) = 6 : 1

So, the ratio of feet to seconds is 6 : 1.

Using this ratio and the other ratios given, we can create equations to solve for the missing values:

6 : 1 = 12 : x

Cross-multiplying, we get: 6x = 12

Solving for x, we get: x = 2

y : 1 = 6 : 1

Cross-multiplying, we get: y = 6

6 : 1 = 24 : z

Cross-multiplying, we get: 6z = 24

Solving for z, we get: z = 4

Therefore, the missing values are:

x = 2, y = 6, z = 4

8.

We can set up equations based on the given ratios and solve for the missing values.

1/4 : x = blue ribbon : red ribbon

y : 6 = blue ribbon : red ribbon

1 : z = blue ribbon : red ribbon

5/4 : 15 = blue ribbon : red ribbon

To find x:

1/4 : x = 1 : z (since blue ribbon : red ribbon = 1 : z)

Cross-multiplying, we get:

1z = 4x

z = 4x

To find y:

y : 6 = 1/4 : x (since blue ribbon : red ribbon = 1/4 : x)

Cross-multiplying, we get:

y * x = 6 * 1/4

y * x = 3/2

y = (3/2) / x

To find z:

1 : z = 5/4 : 15 (since blue ribbon : red ribbon = 1 : z)

Cross-multiplying, we get:

1 * 15 = 5/4 * z

z = (1 * 15 * 4) / 5

z = 12

Therefore, the values of x, y, and z are x = 3, y = 2, and z = 12.

9.

To find the values of x, y, and z, we need to first simplify the ratios given.

The ratio between orange fabrics and yellow fabric is:

1/3 : 8/3

We can simplify this ratio by multiplying both sides by 3 to get:

1 : 8

The ratio between 2/3 and x is:

2/3 : x

The ratio between 1 and y is:

1 : y

The ratio between 4/3 and z is:

4/3 : z

We can simplify this ratio by multiplying both sides by 3/4 to get:

1 : (4/3)z or 1 : 1.33z (rounded to two decimal places)

Now we have the following ratios:

Orange : Yellow = 1 : 8

2/3 : x = 2/3 : x

1 : y = 1 : y

1 : (4/3)z = 1 : 1.33z

To solve for x, y, and z, we can use cross-multiplication.

Orange : Yellow = 1 : 8

1/8 = (Orange / Yellow)

8/1 = (Yellow / Orange)

2/3 : x = 2/3 : x

This ratio is already in its simplest form, so x = 2/3.

1 : y = 1 : y

This ratio is already in its simplest form, so y = 1.

1 : (4/3)z = 1 : 1.33z

1 = (4/3)z / 1.33z

1 = 0.96z

z = 1.04

Therefore, the values of x, y, and z are:

x = 2/3, y = 1, z = 1.04

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Answer:

Regions 1 and 4

Step-by-step explanation:

There are 2 overlapping regions for A (coffee) and B(tea)

These are Region 4 which represents the adults who drink both coffee and tea but not cola

and

Region 1 which represents the adults who drink coffee, tea and cola

So combined these two regions we get all adults who drink both coffee and tea

The amount that LeeCo pays Macy for the office equipment at the $6,300 list price, sales terms of 3/10, n/30 FOB with payment made within the discount window, is $6,111.

A cash discount refers to a reduction in the price of an item due to payment within the discount period.

A cash discount incentivizes the customer to make prompt payments.

The list price of the equipment = $6,300

Sales terms: 3/10, n/30 FOB

Prepaid freight = $40

Cash discount = $189 ($6,300 x 3%)

Payment after the discount = $6,111 ($6,300 - $189)

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Answer: 816

Step-by-step explanation:

Let's denote the monthly payment by x.

Then, Al paid a total of 42x dollars over 42 months.

We know that the total payment for the loan was $34,267. Therefore, we can set up the equation:

42x = 34267

Solving for x, we get:

x = 34267/42

x ≈ 816

So Al's monthly payment was approximately $816.

Answer:

To find the derivative of this function, we'll use the product rule and the chain rule. Let's begin by writing the function in a more readable form using parentheses:

y = e^x * csc(x) * (1 / x) * csc(x)

Now we can apply the product rule, letting u = e^x and v = csc(x) * (1 / x) * csc(x):

y' = u'v + uv'

To find u' and v', we'll need to use the chain rule.

u' = (e^x)' = e^x

v' = (csc(x) * (1 / x) * csc(x))'

= (csc(x))' * (1 / x) * csc(x) + csc(x) * (-1 / x^2) * csc(x) + csc(x) * (1 / x) * (csc(x))'

= -csc(x) * cot(x) * (1 / x) * csc(x) - csc(x) * (1 / x^2) * csc(x) - csc(x) * (1 / x) * csc(x) * cot(x)

= -csc(x) * [cot(x) * (1 / x) + (1 / x^2) + (cot(x) / x)]

Now we can substitute these into the product rule formula:

y' = e^x * csc(x) * (1 / x) * csc(x) * [-cot(x) * (1 / x) - (1 / x^2) - (cot(x) / x)] + e^x * (-csc(x) * cot(x) * (1 / x) * csc(x) - csc(x) * (1 / x^2) * csc(x) - csc(x) * (1 / x) * csc(x) * cot(x))

Next, we can simplify this expression. One way to do this is to factor out common terms:

y' = e^x * csc(x) * (1 / x) * csc(x) * [-cot(x) * (1 / x) - (1 / x^2) - (cot(x) / x)] - e^x * csc(x) * cot(x) * (1 / x) * csc(x) * [1 + (cot(x) / x)]

Now we can simplify further by combining like terms:

y' = e^x * csc(x) * (1 / x) * csc(x) * [-cot(x) * (2 / x) - (1 / x^2)] - e^x * csc(x) * cot(x) * (1 / x) * csc(x) * [1 + (cot(x) / x)]

= e^x * csc(x) * (1 / x) * csc(x) * [-2cot(x) / x - 1 / x^2 - cot(x) / x^2] - e^x * csc(x) * cot(x) * (1 / x) * csc(x) * [1 + cot(x) / x]

At this point, the derivative is simplified as much as possible.

(please could you kindly mark my answer as brainliest)

As the triangles are similar to each other, using congruent theorem, we get the value of side g = 2m.

Comparable triangles are those that resemble one another but may not be precisely the same size. Comparable items are those that share the same shape but differ in size.

This shows that when shapes are amplified or demagnified, they superimpose one another. This feature of similar shapes is often known as "similarity".

As per the triangles,

g/5 = 4/10

⇒ g = 4 × 5/10

⇒ g = 2m.

Therefore, we conclude that the value of g = 2m as per the similar triangles' theorem.

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The pairs of alternate interior angles are given as follows:

Alternate interior angles are pairs of angles that are formed when a transversal intersects two parallel lines. Alternate interior angles are located on opposite sides of the transversal and inside the parallel lines.

From the image given at the end of the answer, the parameters for this problem are given as follows:

Hence the pairs of alternate interior angles are given as follows:

As they are between lines l and k, on opposite sides of line t.

The diagram is given by the image presented at the end of the answer.

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The correct answer is C. A normal distribution is a symmetric probability distribution that is bell-shaped when graphed. When plotted on a horizontal scale, the curve starts on the horizontal axis, rises to a central peak, and then falls back to the horizontal axis.

The curve is symmetric, meaning that the left and right halves of the curve are mirror images of each other. The curve approaches the horizontal axis but never touches it, which indicates that there is a non-zero probability of observing values at any distance from the mean, although the probability decreases as the distance from the mean increases.

Normal distribution is a type of probability distribution that is commonly found in natural and social phenomena, where the majority of the observations tend to cluster around the mean, with fewer observations further away from the mean.

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Answer:

To find the integral of f(x) = 2x + 5/3 over the interval [0, 5], we can use the definite integral formula:

∫[a,b] f(x) dx = F(b) - F(a)

where F(x) is the antiderivative of f(x).

First, we find the antiderivative of f(x):

F(x) = x^2 + (5/3)x + C

where C is the constant of integration.

Next, we evaluate F(5) and F(0):

F(5) = 5^2 + (5/3)(5) + C = 25 + (25/3) + C

F(0) = 0^2 + (5/3)(0) + C = 0 + 0 + C

Subtracting F(0) from F(5), we get:

∫[0,5] f(x) dx = F(5) - F(0)

= 25 + (25/3) + C - C

= 25 + (25/3)

= 100/3

Therefore, the definite integral of f(x) = 2x + 5/3 over the interval [0, 5] is 100/3.

Answer:

The answer is C

Step-by-step explanation:

Assuming this is a fair coin, the theoretical probability of the coin going on one side, let's say heads, is 50%, or 0.5. So what's the chance the coin lands head 5 times? To do this we do 0.5^5 OR 0.5*0.5*0.5*0.5*0.5. Both of these answers equal 0.03125. So C is the Answer. Hope this helps :D

The graph demonstrates that local producers will provide 8,000 tonnes of apricots at the global price of $400 per tonne.

A graph is a visual representation of data that's frequently used to demonstrate how variables relate to one another or to show how trends change over time. Graphs can come in many various forms, including line graphs, bar graphs, pie charts, scatter plots, and more. Graphs are frequently used to simplify the presentation of complicated data in disciplines like economics, mathematics, science, and the social sciences.

given

The graph indicates that the cost of apricots in the globe is $400 per tonne. In the absence of the quota, the US would purchase 5,000 tonnes of apricots at the market rate. The United States will only be permitted to acquire 3,000 tonnes of apricots under the quota, though.

As a result of this quota, the United States will purchase 3,000 tonnes of apricots at the world price.

The graph demonstrates that local producers will provide 8,000 tonnes of apricots at the global price of $400 per tonne.

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Probability that precisely 5 people will respond that they would feel comfortable is 0.0808

Probability that more than 5 people will respond that they would feel comfortable is0.1061

Probability that at most 5 people will respond that they would feel comfortable is 0.9747

Probability is a way to gauge how likely something is to happen. Several things are difficult to forecast with absolute confidence.

35 percent of households claim that having $50,000 in savings would make them feel comfortable. Ask 8 homes that were chosen at random if they would feel comfortable if they had $50,000 in savings.

Binomial conundrum with p(secure) = 0.35 and n = 8.

the likelihood that the number of people who claim they would feel comfortable is

(a) The number exactly five is equal to ⁸C₅ (0.35)5×(0.65)×3=binompdf(8,0.35,5) = 0.0808.

(b) more than five = 1 - binomcdf(8,0.35,4) = 0.1061

(c) at most five = binomcdf(8,0.35,5) = 0.9747.

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The probability that less than 8.4% of the individuals in the sample hold multiple jobs is approximately 0.0681 or 6.81%.

What is Probability ?

Probability can be defined as ratio of number of favourable outcomes and total number outcomes.

To determine whether it is appropriate to use the normal approximation, we need to check whether the conditions for using the normal distribution are met.

We can use the following criteria:

The sample size is large enough: n × p ≥ 10 and n × (1 − p) ≥ 10

The observations are independent

Here, we are given that the sample size is n = 66. To check the first condition, we need to find the expected number of individuals who hold multiple jobs in the sample, which is given by:

np = 0.12 × 66 = 7.92

n(1-p) = 66 - 7.92 = 58.08

Both np and n(1-p) are greater than or equal to 10. So, the sample size is large enough and the first condition is met.

Additionally, we can assume that the observations are independent since the sample is random and represents less than 10% of the population of employed adults in the United States.

Therefore, it is appropriate to use the normal approximation.

To find the probability that less than 8.4% of the individuals in the sample hold multiple jobs, we need to standardize the sample proportion using the formula:

z = (p'- p) / [tex]\sqrt{(p(1-p) / n)}[/tex]

where p' is the sample proportion, p is the population proportion (0.12), n is the sample size (66), and sqrt represents the square root.

Substituting the values, we get:

z = (0.084 - 0.12) / [tex]\sqrt{((0.12)(1-0.12) / 66)}[/tex] = -1.496

Using a standard normal distribution table, we can find that the probability of z being less than -1.496 is approximately 0.0681.

Therefore, the probability that less than 8.4% of the individuals in the sample hold multiple jobs is approximately 0.0681 or 6.81%.

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The ordered pairs of given equation are (3/2,4), (1/3, -3),(5/6,0)

An ordered pair is composed of the ordinate and the abscissa of the x coordinate, with two values supplied in parentheses in a specified sequence. Placing a point on the Cartesian plane could be beneficial for visual comprehension.

for example, the ordered pair (x, y) signifies an ordered pair in which 'x' is referred to as the first element and 'y' is referred to as the second element. These items, which can be either variables , have distinct names depending on the context in which they are used. In an ordered pair, the element order is quite significant.

Given Equation of Y=6x−5

First Ordered pair;(,4)

y=4

x=4+5/6

x=3/2

First Ordered pair;(, -3)

y=-3

x=-3+5/6

x=1/3

First Ordered pair; (,0)

y=0

x=5/6

The ordered pairs of given equation are

(3/2,4), (1/3, -3),(5/6,0)

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The complete question is:

For The Equation, Y=6x−5

Complete The Given Ordered Pairs (,4), (, -3), (,0)

Answer:

2 + √[26] + √[50]

Step-by-step explanation:

To find the perimeter of a triangle with vertices given in the coordinate plane, we need to calculate the distance between each pair of vertices and then add them up.

Using the distance formula, the distance between the first two vertices is:

√[(x2 - x1)^2 + (y2 - y1)^2] =

√[(-4 - (-4))^2 + (1 - 3)^2] =

√[0 + 4] = 2

The distance between the second and third vertices is:

√[(x2 - x1)^2 + (y2 - y1)^2] =

√[(-5 - (-4))^2 + (-4 - 1)^2] =

√[1 + 25] = √[26]

Finally, the distance between the third and first vertices is:

√[(x2 - x1)^2 + (y2 - y1)^2] =

√[(-4 - (-5))^2 + (3 - (-4))^2] =

√[1 + 49] = √[50]

Therefore, the perimeter of the triangle is:

2 + √[26] + √[50]

This is the exact answer, and we cannot simplify it further.

To graph the equation l = w + 2, we can use the following steps:

Choose a range of values for the width w that we want to graph. Let's say we choose w = 0 to w = 5.

Plug each value of w into the equation to find the corresponding value of l. For example, when w = 0, l = 0 + 2 = 2. When w = 1, l = 1 + 2 = 3.

w l = w + 2

0 2

1 3

2 4

3 5

4 6

5 7

Plot each point on a coordinate plane using the value of w as the x-coordinate and the value of l as the y-coordinate.

Connect the points with a straight line to create the graph of the equation.

The resulting graph should be a straight line with a slope of 1 and a y-intercept of 2, as shown below:

markdown

Copy code

 |

7 |-    +

 |     |

6 |-     \

 |      \

5 |-       \

 |        \

4 |-         \

 |          \

3 |-           \

 |            \

2 |- - - - - - - \

 0 1 2 3 4 5 6

       w

Note that the graph represents all the possible pairs of width w and length l that satisfy the equation l = w + 2. Since the equation describes a rectangle that is one inch longer than it is wide, we can see that the graph includes all the possible rectangles that fit this description.

 |

7 |-    +

 |     |

6 |-     \

 |      \

5 |-       \

 |        \

4 |-         \

 |          \

3 |-           \

 |            \

2 |- - - - - - - \

 0 1 2 3 4 5 6

       w

Note that the graph represents all the possible pairs of width w and length l that satisfy the equation l = w + 2. Since the equation describes a rectangle that is one inch longer than it is wide, we can see that the graph includes all the possible rectangles that fit this description.

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Answer:

To find the probability of getting someone who tested positive given that he or she had the disease, we need to use the formula for conditional probability:

P(positive|disease) = P(positive and disease) / P(disease)

From the given data, we can see that there are 136 individuals who tested positive and actually had the disease. Therefore, P(positive and disease) = 136.

We can also see that there are a total of 136 + 8 = 144 individuals who actually had the disease. Therefore, P(disease) = 144.

Substituting these values into the formula, we get:

Simplifying, we get:

Rounding to three decimal places, we get:

Therefore, the probability of getting someone who tested positive given that he or she had the disease is approximately 0.944.

Answer:

Let's assume that Mr. Nkalle invested an amount of x in Scheme A and (20900 - x) in Scheme B.

The simple interest earned on Scheme A in 2 years would be:

SI(A) = (x * 9 * 2)/100 = 0.18x

The simple interest earned on Scheme B in 2 years would be:

SI(B) = [(20900 - x) * 8 * 2]/100 = (3344 - 0.16x)

The total simple interest earned in 2 years is given as N$3508:

SI(A) + SI(B) = 0.18x + (3344 - 0.16x) = 3508

0.02x = 164

x = 8200

Therefore, Mr. Nkalle invested N$8200 in Scheme A and N$12700 (20900 - 8200) in Scheme B. So the amount invested in Scheme B was N$12700.

Answer:

1 cubic meter = 1000000 cm cubed

Step-by-step explanation:

[tex]1m^3*10^6=1000000cm^3[/tex]

Answer:

1 cubic meter = 10000000 cm cube