your friend claims the geometric mean of 4 and 9 is 6, and then labels the triangle, as shown. is your friend correct? explain your reasoning.

Answer: 10 is two units from 0 on the number line, so there are six numbers that are 10 units from 0.

Step-by-step explanation:

let me have brainliest real quick

Answer: 54, 1 2/3, 1, 0.5, 0.03, 0, -1/4, -1, -4, -103

Step-by-step explanation:

54, 1, 1 2/3, 0.5, 0.03, 0, -1/4, -1, -4, -103.

First, we order the numbers by their sign: 54, 1, 1 2/3, 0.5, 0.03, 0, -1/4, -1, -4, -103.

Then we order the positive numbers in decreasing order: 54, 1 2/3, 1, 0.5, 0.03, 0.

Finally, we order the negative numbers in increasing order: -103, -4, -1, -1/4.

Putting it all together, we have: 54, 1 2/3, 1, 0.5, 0.03, 0, -1/4, -1, -4, -103.

Answer:

The value of the derivative at (-2/3, 2√3/3) is zero.

Step-by-step explanation:

Given function:

[tex]f(x)=-3x\sqrt{x+1}[/tex]

To differentiate the given function, use the product rule and the chain rule of differentiation.

[tex]\boxed{\begin{minipage}{5.4 cm}\underline{Product Rule of Differentiation}\\\\If $y=uv$ then:\\\\$\dfrac{\text{d}y}{\text{d}x}=u\dfrac{\text{d}v}{\text{d}x}+v\dfrac{\text{d}u}{\text{d}x}$\\\end{minipage}}[/tex]

[tex]\boxed{\begin{minipage}{7 cm}\underline{Differentiating $[f(x)]^n$}\\\\If $y=[f(x)]^n$, then $\dfrac{\text{d}y}{\text{d}x}=n[f(x)]^{n-1} f'(x)$\\\end{minipage}}[/tex]

[tex]\begin{aligned}\textsf{Let}\;u &= -3x& \implies \dfrac{\text{d}u}{\text{d}{x}} &= -3\\\\\textsf{Let}\;v &= \sqrt{x+1}& \implies \dfrac{\text{d}v}{\text{d}{x}} &=\dfrac{1}{2} \cdot (x+1)^{-\frac{1}{2}}\cdot 1=\dfrac{1}{2\sqrt{x+1}}\end{aligned}[/tex]

Apply the product rule:

[tex]\implies f'(x) =u\dfrac{\text{d}v}{\text{d}x}+v\dfrac{\text{d}u}{\text{d}x}[/tex]

[tex]\implies f'(x)=-3x \cdot \dfrac{1}{2\sqrt{x+1}}+\sqrt{x+1}\cdot -3[/tex]

[tex]\implies f'(x)=- \dfrac{3x}{2\sqrt{x+1}}-3\sqrt{x+1}[/tex]

Simplify:

[tex]\implies f'(x)=- \dfrac{3x}{2\sqrt{x+1}}-\dfrac{3\sqrt{x+1} \cdot 2\sqrt{x+1}}{2\sqrt{x+1}}[/tex]

[tex]\implies f'(x)=- \dfrac{3x}{2\sqrt{x+1}}-\dfrac{6(x+1)}{2\sqrt{x+1}}[/tex]

[tex]\implies f'(x)=- \dfrac{3x+6(x+1)}{2\sqrt{x+1}}[/tex]

[tex]\implies f'(x)=- \dfrac{9x+6}{2\sqrt{x+1}}[/tex]

An extremum is a point where a function has a maximum or minimum value.

From inspection of the given graph, the maximum point of the function is (-2/3, 2√3/3).

To determine the value of the derivative at the maximum point, substitute x = -2/3 into the differentiated function.

[tex]\begin{aligned}\implies f'\left(-\dfrac{2}{3}\right)&=- \dfrac{9\left(-\dfrac{2}{3}\right)+6}{2\sqrt{\left(-\dfrac{2}{3}\right)+1}}\\\\&=-\dfrac{0}{2\sqrt{\dfrac{1}{3}}}\\\\&=0 \end{aligned}[/tex]

Therefore, the value of the derivative at (-2/3, 2√3/3) is zero.

The probability of getting a head on the coin is 1/2, and the probability of getting a 4 on the die is 1/6.

Since the coin toss and the die roll are independent events, we can multiply the probabilities to get the probability of both events happening at the same time:

P(head and 4) = P(head) × P(4)

P(head and 4) = (1/2) × (1/6)

P(head and 4) = 1/12

P(head and 4) ≈ 0.0833 (rounded to four decimal places)

Therefore, the probability of getting a head on the coin and the number 4 on the die is approximately 0.0833.

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When [tex]x[/tex] approaches infinity, the function's graph moves closer to the x-axis and horizontal equilibrium point at [tex]y = 3[/tex]. For [tex]x -2[/tex], which is denoted by such an open ring at [tex](-2, 3)[/tex] on the graph, the function is undefined.

A graphs is a pictorial display or diagram that displays facts or numbers in an organized way in math. The relationships between multiple things are frequently represented by the points on a graph.

The graph is a mathematics structure made up of a collection of points Coordinates and a set of lines connecting some pairs of VERTICES that may or may not be empty. There is a chance that the edges will be directed, or orientated.

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The volume of the solid rounded to the nearest whole number is approximately 262 cubic units.

If we rotate a semicircle about its diameter, we get a solid called a hemisphere. The volume of a hemisphere is given by the formula:

V = (2/3)πr³

where r is the radius of the hemisphere.

In this case, the diameter of the semicircle is given as 10, so the radius is half of that, i.e., r = 5. Substituting this value in the formula, we get:

V = (2/3)π(5)³

= (2/3)π(125)

= 250π/3

≈ 261.8

What is the area and volume of hemisphere?

The curved surface area of a hemisphere = 2r² square units. The total surface area of a hemisphere = 3r² square units. The volume of a hemisphere is determined by the formula (⅔)r cubic units.

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In response to the stated question, we may state that Hence the chances  probability of Baxter's Shelties not having a Tri-Color puppy this year are 0.45, or 45%.

Probabilistic theory is a branch of mathematics that calculates the likelihood of an event or proposition occurring or being true. A risk is a number between 0 and 1, with 1 indicating certainty and a probability of around 0 indicating how probable an event appears to be to occur. Probability is a mathematical term for the likelihood or likelihood that a certain event will occur. Probabilities can also be expressed as numbers ranging from 0 to 1 or as percentages ranging from 0% to 100%. In relation to all other outcomes, the ratio of occurrences among equally likely alternatives that result in a certain event.

To determine the likelihood that Baxter's Shelties will not have a Tri-Color puppy this year, add the probabilities of all other potential colour combinations and subtract them from one (since the sum of all probabilities must be 1).

White and Sable: 0.18 + 0.12 = 0.3

White and Blue Merle: 0.1 + 0.05 = 0.15

0.05 Bi-Black

Bi-Blue: 0.02 Sable Merle: 0.03

As a result, the overall likelihood of NOT getting a Tri-Color puppy is:

1 - (0.3 + 0.15 + 0.05 + 0.03 + 0.02) = 1 - 0.55 = 0.45

Hence the chances of Baxter's Shelties not having a Tri-Color puppy this year are 0.45, or 45%.

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B. We fail to reject the null hypothesis. In hypothesis testing, the significance level, denoted by a, is the probability of rejecting the null hypothesis when it is true.

If the p-value is less than the significance level, we reject the null hypothesis. In this case, the p-value is 0.05, which is greater than the significance level of 0.04. Option C is not necessarily true as the term "unusual" is subjective and can vary depending on the context. Option D is not necessarily true as the critical region may be in the other tail of the normal curve.

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In response to the stated question, we may state that As a result, the 66th derivative of f(x) = 4 sin(x) is 4 sin(x) (x).

In mathematics, the derivative of a function with real variables measures how sensitively the function's value varies in reaction to changes in its parameters. Derivatives are the fundamental tools of calculus. Differentiation (the rate of change of a function with respect to a variable in mathematics) (in mathematics, the rate of change of a function with respect to a variable). The use of derivatives is essential in the solution of calculus and differential equation problems. The definition of "derivative" or "taking a derivative" in calculus is finding the "slope" of a certain function. Because it is frequently the slope of a straight line, it should be enclosed in quotation marks. Derivatives are rate of change metrics that apply to almost any function.

Using the chain rule and the derivative of the sine function repeatedly yields the 66th derivative of the function [tex]f(x) = 4 sin (x).[/tex]

The derivative of sin(x) is cos(x), and the derivative of cos(x) is -sin(x), and this pattern repeats itself every two derivatives.

As a result, the first derivative of f(x) is:

[tex]f'(x) = 4 cos (x)[/tex]

The second derivative is as follows:

[tex]f"(x) = -4 sin (x)[/tex]

The third derivative is as follows:

[tex]f"'(x) = -4 cos (x)[/tex]

The fourth derivative is as follows:

[tex]f""(x) = 4 sin (x)[/tex]

And so forth.

[tex]f^{(66)(x)} = 4 sin (x)[/tex]

Because the pattern repeats every four derivatives, the 66th derivative is the same as the second, sixth, tenth, fourteenth, and so on.

As a result, the 66th derivative of f(x) = 4 sin(x) is 4 sin(x) (x).

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The answer of the given question based on finding the missing length of a triangle the answer is , None of the answer choices match this value exactly, but the closest one is D) 15. Therefore, the answer is D) 15.

In geometry,  triangle is  two-dimensional polygon with three straight sides and three angles. It is one of  basic shapes in geometry and can be defined as  closed figure with three line segments as its sides, where each side is connected to two endpoints called vertices. The sum of  interior angles of  triangle are 180° degrees.

Triangles are classified based on length of their sides and  measure of their angles. A triangle can be equilateral, isosceles, or scalene based on whether all sides are equal, two sides are equal, or all sides are different, respectively.

To find the missing length indicated, we can use the Pythagorean theorem, which states that in a right triangle, the sum of the squares of the lengths of the two legs (the sides adjacent to the right angle) is equal to the square of the length of the hypotenuse (the side opposite the right angle).

In this triangle, we can see that the two legs have lengths of 9 and 16, and the hypotenuse has length X. So we can write:

9²+ 16² = X²

Simplifying the left-hand side:

81 + 256 = X²

337 = X²

Taking the square root of both sides (and remembering that X must be positive, since it is a length):

X = sqrt(337)

X ≈ 18.3575

So the missing length indicated is approximately 18.3575. None of the answer choices match this value exactly, but the closest one is D) 15. Therefore, the answer is D) 15.

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Answer:

Yes. If you are asking if the duration between those two times is a total of 12 hours, the answer is yes.

Step-by-step explanation:

9:45am is 12 hours away from 9:45pm. This applies to all times and their am/pm counterparts such as 12am/12pm.

The points with high leverage have the potential to exert a strong influence on the estimated regression coefficients and can lead to large changes. However, the relationship between leverage and residual variance is not straightforward, and it is possible for a point with high leverage to have a small residual variance or vice versa.

In statistics, The point with the highest leverage in a dataset is the observation that has the largest deviation from the mean of the predictor variable. Residual variance is a measure of the difference between the actual values of the response variable and the values predicted by the regression model.

In the case where the point with the highest leverage has the smallest residual variance, it suggests that this observation is well-explained by the regression model and that it does not have a large effect on the overall fit of the model.

This may occur if the point is located near the center of the distribution of the response variable or if it has predictor variable values that are consistent with the overall trend of the data.

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Step-by-step explanation:

The balance will be the initial deposit ( p = 3000)  plus the interest earned for two years  p r t     where r = decimal interest per year   t = 2 years

Balance = $   3000  +    3000 * .025 * 2  = $ 3150.00

The Davenports' medical expenses contribute to their total itemized deductions are $375 (7.5% for 2019).

The costs you incurred for state and local income or sales taxes, real estate taxes, personal property taxes, mortgage interest, and disaster losses are all included in itemised deductions. You can also count charitable donations and a portion of your out-of-pocket medical and dental costs.

Currently for the 2019 (due 2020), you can deduct medical expenses that exceed 7.5% of your AGI, but back then in 2019, the threshold was 7.5%, not 10%.

So the Davenports can only deduct

$5,250 - ($65,000 x 7.5%) = $375

if they decided to itemize their deductions.

The threshold will increase back to 10% starting 2020 (due 2021) tax returns.

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Answer: it represents half of the students in 1 class

Step-by-step explanation:

1/2 divided by s

Answer:

1/2s would then represent one half (or 50%) of the students in the singular class stated.

Answer: y = 4(x² − 1)(x² − 4).

Step-by-step explanation:

We need to find the equation of the curve that passes through the point (2, 0).

We start by separating the variables dy/dx and y and integrating both sides:

(2x² - 5) dy/dx = 8x(y + 9)

dy/(y + 9) = (4x/(2x² - 5)) dx

Integrating both sides:

ln|y + 9| = 2ln|2x² - 5| + C

where C is the constant of integration.

Rewriting in exponential form:

|y + 9| = e^(2ln|2x² - 5| + C)

|y + 9| = e^(ln|2x² - 5|² + C)

|y + 9| = k(2x² - 5)²

where k is the constant of integration.

Since the curve passes through the point (2, 0), we can substitute these values into the equation above to find k:

|0 + 9| = k(2(2)² - 5)²

9 = k(36)

k = 1/4

Substituting this value of k back into the equation, we get:

|y + 9| = (1/4)(2x² - 5)²

y + 9 = (1/4)(2x² - 5)² or y + 9 = -(1/4)(2x² - 5)²

Simplifying the right-hand side of each equation, we get:

y + 9 = (1/4)(4x⁴ - 20x² + 25)

or

y + 9 = -(1/4)(4x⁴ - 20x² + 25)

Expanding and simplifying, we get:

y = 4x⁴/4 - 5x²/2 + 25/4 - 9 or y = -4x⁴/4 + 5x²/2 - 25/4 - 9

y = x⁴ - 5x² + 19/4 or y = -x⁴/4 + 5x²/2 - 41/4

Thus, the equation of the curve passing through the point (2, 0) with the given gradient is y = 4(x² − 1)(x² − 4).

The total amount after forty years with interest compounded every twenty years is ₹ 56,444.61 and the total interest earned is ₹ 6,444.61.

To find the total amount and total interest after forty years with interest compounded every twenty years, we can use the formula of compound interest

A = P(1 + r/n)^(nt)

Where

A = total amount

P = principal amount = ₹50,000

r = annual interest rate = 0.5%

n = number of times interest is compounded per year = 1 (compounded every 20 years)

t = time in years = 40

Using this formula, we can calculate the total amount and total interest as follows

Total amount = P(1 + r/n)^(nt) = 50000(1 + 0.005/1)^(12) * (1 + 0.005/1)^(12) = ₹ 56,444.61

Total interest = Total amount - Principal = ₹ 56,444.61 - ₹ 50,000 = ₹ 6,444.61

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Step-by-step explanation:

(a) Experimental probability of rolling an even number = (number of rolls for 2, 4, and 6) / (total number of rolls) = (4 + 5 + 6) / 40 = 0.375

(b) Theoretical probability of rolling an even number = number of even outcomes / total number of outcomes = 3 / 6 = 0.5

(c) Statement 2 is true: With a small number of rolls, it is not surprising when the experimental probability is much greater than the theoretical probability.

(a) The interval (-∞, ∞).

(b) The interval (-∞, ∞).

(c) The interval (-∞, ∞).

(d) The interval (-π/2, π/2) \ {0}.

(a) The longest interval in which the given initial value problem is certain to have a unique twice-differentiable solution is the interval where the coefficient function, 3t, is continuous and bounded. Since 3t is a continuous and bounded function for all t in the interval (-∞, ∞), the given initial value problem is certain to have a unique twice-differentiable solution for all t in (-∞, ∞).

(b) The longest interval in which the given initial value problem is certain to have a unique twice-differentiable solution is the interval where the coefficient functions, t(t - 4), 3t, and 4, are continuous and bounded. Since t(t - 4), 3t, and 4 are continuous and bounded functions for all t in the interval (-∞, ∞), the given initial value problem is certain to have a unique twice-differentiable solution for all t in (-∞, ∞).

(c) The longest interval in which the given initial value problem is certain to have a unique twice-differentiable solution is the interval where the coefficient functions, cost and In|t|, are continuous and bounded. Since cost and In|t| are continuous and bounded functions for all t in the interval (-∞, ∞), the given initial value problem is certain to have a unique twice-differentiable solution for all t in (-∞, ∞).

(d) The longest interval in which the given initial value problem is certain to have a unique twice-differentiable solution is the interval where the coefficient functions, x - 2, 1, and (x - 2)tanx, are continuous and bounded. Since x - 2, 1, and (x - 2)tanx are continuous and bounded functions for all x in the interval (-π/2, π/2) \ {0} , the given initial value problem is certain to have a unique twice-differentiable solution for all x in (-π/2, π/2) \ {0}.

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The given question is incomplete, the complete question is:

determine the longest interval in which the given initial value problem is certain to have a unique twice- differentiable solution. Do not attempt to find the solution. (a) ty" + 3y = 1, y(1) = 1, y'(1) = 2   (b)   t(t – 4)y" + 3ty' + 4y = 2, y(3) = 0, y'(3) = -1 (c)   y" + (cost)y' + 3( In |t|) y = 0, y(2) = 3, y'(2) = 1 (d) (x - 2)y"+y' +(x - 2)(tan x) y = 0, y(3) = 1, y'(3) = 2

Answer:

To solve for r, we can start by simplifying the equation:

1475/2pi = (3/4r^2pi) + (1/4pi*(r-15)^2) + (1/4pi(r-25)^2)

Multiplying both sides by 2*pi:

1475 = 3/4r^2pi2 + 1/4pi*(r-15)^22 + 1/4pi*(r-25)^2*2

1475 = 3/2r^2pi + 1/2pi(r-15)^2 + 1/2pi(r-25)^2

Multiplying both sides by 2:

2950 = 3r^2pi + pi*(r-15)^2 + pi*(r-25)^2

Distributing pi:

2950 = 3r^2pi + pir^2 - 30pir + 225pi + pir^2 - 50pir + 625pi

Combining like terms:

2950 = 5r^2pi - 80pir + 850*pi

Rearranging:

5r^2pi - 80pir + 850*pi - 2950 = 0

Simplifying:

5r^2pi - 80pir + 675*pi = 0

Dividing both sides by 5*pi:

r^2 - 16*r + 135 = 0

This is a quadratic equation, which can be solved using the quadratic formula:

r = (-(-16) ± sqrt((-16)^2 - 4(1)(135))) / (2(1))

r = (16 ± sqrt(256 - 540)) / 2

r = (16 ± sqrt(284)) / 2

r ≈ 1.7321 * 16 or r ≈ 8.2679

Since r represents the distance from the center of the octagon to a vertex, only the larger value of r makes sense in this context.

Therefore, r ≈ 8.2679 feet.

To find the area of the region in which the cow can graze, we can divide the octagon into eight congruent isosceles triangles with base 25 feet and height equal to the distance from the center to a side (which is equal to r).

The area of each triangle is (1/2)bh = (1/2)(25)(8.2679) = 103.3494 square feet.

Multiplying by 8 to account for all eight triangles:

8 * 103.3494 = 826.7952 square feet.

Rounding to the nearest square foot:

The area in which the cow can graze is approximately 827 square feet

The percentage of students earned a B in the statistics course is 22.5%. So, the correct option is B).

To find the percentage of students who earned a B in the course, we need to determine the total number of students who took the course and the number of students who earned a B.

Using the information given in the bar chart, we can determine that there were a total of 40 students who took the statistics course. The number of students who earned a B is given as 9 in the bar chart. Therefore, the percentage of students who earned a B is (9/40) x 100%, which simplifies to 22.5%.

The total number of students who took the statistics course is:

Y = A + B + C + D + F = 5 + 9 + 11 + 8 + 7 = 40

The percentage of students who earned a B is:

(B/Y) x 100% = (9/40) x 100% = 22.5%

Therefore, the correct answer is (B) 22.5%.

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A = {u + 2v, -3} is the basis for subspace U given that the set A is now linearly independent and that U = span(A).

Since U = span(S), and the set S is linearly independent, let S = {u, v} be the basis of the subspace U.

Now determine whether or not the set A = {u + 2v, -3v} is linearly independent.

A set of vectors must all have linear combinations that add up to zero in order for them to be considered linearly independent. Let a and b represent any scalars so that,

a(u + 2v) + b(-3v) = 0

Simplify the obtained equation.

au + 2av - 3bv = 0

au + v(2a - 3b) = 0

Make 2a - 3b = A.

Rewrite the equation that was found using this.

Now because u and v are linearly independent, a and A must be zero, and as a result, the constant b is also zero.

Set A is hence linearly independent.

Also, au + Av ∈ U, so, U = span(A).

Considering that the set A is now linearly independent and that U = span(A), the basis for subspace U is A = {u + 2v, -3}.

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The complete question is:

If {u, v} is a basis for the subspace U, show that {u + 2v, −3v} is also a basis for U.

The set of ordered pair that does not represent a function is option 1 {(4,0), (8, -8), (4,1), (5,8)}.

A function in mathematics is a relationship between two sets in which every element of the first set (referred to as the domain) is connected to exactly one element of the second set (called the range). A function is typically represented by the symbol f(x), where x is a domain element and f(x) is a corresponding range element.

We know that, a set of ordered pairs represents a function if each input is associated with only one output.

From the given options we observe that, {(4,0), (8, -8), (4,1), (5,8)}, does not represent a function.

Hence, the set of ordered pair that does not represent a function is option 1 {(4,0), (8, -8), (4,1), (5,8)}.

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The set of all n×n invertible matrices with the standard operations of matrix addition and scalar multiplication is (b) not a subspace.

A Subspace is defined as a subset of a vector space that is itself a vector space under the same operations of addition and scalar multiplication defined on the original vector space.

To be a subspace of Mₙ,ₙ, a subset of Mₙ,ₙ must satisfy three conditions:

(i) The subset must contain the zero matrix,

(ii) The subset must be closed under matrix addition, meaning that if A and B are in the subset, then (A + B) is also in the subset.

(iii) The subset must be closed under scalar multiplication, meaning that if A is in the subset and c is any scalar, then cA is also in the subset.

The set of all n×n invertible matrices does not contain the zero matrix, as the zero matrix is not invertible.

Therefore, it fails to meet the first condition and cannot be a subspace, the correct option is (b).

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The given question is incomplete, the complete question is

Determine whether the subset of Mₙ,ₙ is a subspace of Mₙ,ₙ with the standard operations of matrix addition and scalar multiplication.

The set of all n×n invertible matrices is

(a) Subspace

(b) Not a subspace.

Answer: 1 hour and 36 minutes

Step-by-step explanation:

We can use the concept of the work formula, which states that the amount of work done is equal to the rate of work multiplied by time.

Let's start by finding the rate of work of each worker. We know that eight workers can load 4320 bricks in 1 hour, so the rate of work of each worker is:

rate of work = amount of work / time = 4320 bricks / (8 workers x 1 hour) = 540 bricks/hour

Now we want to know how long it would take for five workers to load the same amount of bricks. We can use the work formula again, but this time we know the rate of work and the amount of work, and we want to find the time:

amount of work = rate of work x time

Substituting the values we know:

4320 bricks = (540 bricks/hour) x time x 5 workers

Simplifying, we get:

time = 4320 bricks / (540 bricks/hour x 5 workers) = 1.6 hours or 1 hour and 36 minutes

Therefore, it would take 1 hour and 36 minutes for 5 workers to load 4320 bricks on the truck.

The values or variables listed in the function declaration are called formal parameters to the function.

They are used to store the data that is passed into the function when it is called. The formal parameters are local variables, meaning that the values stored in them are only available within the function.

The arguments are the values passed to the function when it is called. These values are then assigned to the formal parameters and are used within the function to perform the desired task.

Formal arguments are produced at function entry and removed at function exit, behaving similarly to other local variables inside the function.

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To solve the equation -12x + 24 = 0, we want to get x by itself on one side of the equation.

First, we can subtract 24 from both sides:

- 12x + 24 - 24 = 0 - 24

This simplifies to:

- 12x = -24

Next, we can divide both sides by -12:

- 12x / -12 = -24 / -12

This simplifies to:

x = 2

Therefore, the solution to the equation -12x + 24 = 0 is x = 2.

The cylindrical has a surface area of 414 square units due to its 9-unit radius and 14-unit height.

A cylinder is a three-dimensional geometric form made up of two circular bases that are parallel to one another and are joined by a curved lateral surface. It can be pictured as a solid item with a constant circular cross-section along its entire length. The measurements of a cylinder, such as the radius and height of the circular bases, affect its characteristics. The surface area, volume, and horizontal surface area of a cylinder are some of its typical characteristics. Mathematical formulas can be used to determine these properties.

given

The following algorithm determines a cylinder's surface area:

[tex]A = 2\pi r^2 + 2\pi rh[/tex]

where r is the cylinder's base's radius, h is the cylinder's height, and (pi) is a mathematical constant roughly equivalent to 3.14.

Inputting the numbers provided yields:

[tex]A = 2\pi (9)^2 + 2\pi (9)(14)\\[/tex]

A = 2π(81) + 2π(126) 

A = 162π + 252π

A = 414π

The cylindrical has a surface area of 414 square units due to its 9-unit radius and 14-unit height.

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Continuous numerical values make up the data type for the variable "Age of a tennis player selected at random in the Wimbledon tennis tournament."

Discrete numerical, continuous numerical, and categorical data are the three basic types that can be identified.

- Non-numerical categorical variables, such as gender or eye colour, represent categories or groups.

- Discrete numerical data, such as the number of siblings or pets, are numerical data that can only take on specified values.

Continuous numerical data, like age or weight, are numerical data that can have any value within a range.

Because age can have any value within a range, the data for the variable "Age of a randomly chosen tennis player in the Wimbledon tennis competition" is continuous numerical (for example, a player could be 18.5 years old or 25.2 years old). Hence, continuous numerical data is the right response.

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