You work for a parts manufacturing company and are tasked with exploring the wear lifetime of a certain bearing. You gather data on oil viscosity used and load. You see the regression output given below.
Predictor Coef Stdev t-ratio P
Constant -147.973 41.972 -3.53 0.004181
viscosity 6.262 0.474 13.21 <0.0001
load 0.298 0.04 7.43 <0.0001

s = 13.507 R² = 95.73% R² (adj = 95.02%

Analysis of Variance

Source DF SS MS F
Regression 2 49131.93 24565.96 134.65
Error 12 2189.38 182.45
Total 14 51321.3

Required:
What is the correct conclusion about the regression slopes based solely on the F-test

Answer:

.

Step-by-step explanation:

.

Answer:

80 seconds

Step-by-step explanation:

10/10 = 1

now it takes 1 seconds to count 1 sheet

80 x 1 = 80 seconds to count 80 sheets

Step-by-step explanation:

10sheets=10seconds

1sheet=1sheet÷10sheets x 10seconds

=1second

80sheets=80sheets÷1sheet x 1second

80seconds

hope this is helpful

Answer:

(a) 20226 units

(b) Marginal productivities

[tex]P_x =2500x^{-\frac{4}{5}} & y^\frac{1}{5}[/tex]

[tex]P_y =2500 x^\frac{1}{5} y^{-\frac{4}{5}}[/tex]

(c) Evaluation of the marginal productivities

[tex]P_x =803[/tex]

[tex]P_y = 15[/tex]

Step-by-step explanation:

Given

[tex]P(x,y) = 2500x^\frac{1}{5}y^\frac{1}{5}[/tex]

Solving (a): P(x,y) when x = 26 and y = 1333

[tex]P(x,y) = 2500x^\frac{1}{5}y^\frac{1}{5}[/tex] becomes

[tex]P(26,1333) = 2500*26^\frac{1}{5}*1333^\frac{1}{5}[/tex]

[tex]P(26,1333) = 20226[/tex] --- approximated

Solving (b): The marginal productivities

To do this, we simply calculate Px and Py

Differentiate x to give Px, so we have:

[tex]P(x,y) = 2500x^\frac{1}{5}y^\frac{1}{5}[/tex] becomes

[tex]P_x =2500 * x^{\frac{1}{5}-1} & y^\frac{1}{5}[/tex]

[tex]P_x =2500 * x^{-\frac{4}{5}} & y^\frac{1}{5}[/tex]

[tex]P_x =2500x^{-\frac{4}{5}} & y^\frac{1}{5}[/tex]

Differentiate y to give Py, so we have:

[tex]P(x,y) = 2500x^\frac{1}{5}y^\frac{1}{5}[/tex] becomes

[tex]P_y =2500 * x^\frac{1}{5} & y^{\frac{1}{5}-1}[/tex]

[tex]P_y =2500 x^\frac{1}{5} y^{-\frac{4}{5}}[/tex]

Solving (c): Px and Py when x = 25 and y = 1333

[tex]P_x =2500x^{-\frac{4}{5}} & y^\frac{1}{5}[/tex] becomes

[tex]P_x =2500 * 25^{-\frac{4}{5}} * 1333^\frac{1}{5}[/tex]

[tex]P_x =803[/tex] --- approximated

[tex]P_y =2500 x^\frac{1}{5} y^{-\frac{4}{5}}[/tex] becomes

[tex]P_y =2500 * 25^\frac{1}{5} * 1333^\frac{-4}{5}[/tex]

[tex]P_y = 15[/tex]

Answer:

Discount amount = $328.73

Step-by-step explanation:

Below is the calculation for the discount amount:

The marked price of bicycle = 2000

Purchase price = Rs 1921

VAT = 13%

First find the purchase price excluding VAT = 1921  - (13% of 1921) = 1671.27

Discount amount = 2000 - 1671.27

Discount amount = $328.73

Answer: [tex]5\sqrt{2}[/tex]

Step-by-step explanation:

[tex]\sqrt{10} *\sqrt{5} =\sqrt{50} =\sqrt{2*5*5} =5\sqrt{2}[/tex]

Answer:

The square root of a negative number is undefined, because anything times itself will give a positive (or zero) result. Note: Zero has only one square root (itself). Zero is considered neither positive nor negative

Answer:

sjshzhshshdhdgdgdhdhdgshshshshshwywhwhw

Answer:

-2 and -4

Step-by-step explanation:

When the quadratic equation equals 0, that means when y = 0.

By looking at the graph, whenever y = 0 is when the graph crosses the x-axis.

The graph crosses the x-axis at only two points:

(-4, 0) and (-2, 0)

So the solutions to the graph when  -x^2 - 6x - 8 equals 0 is -2 & -4.

Hope it helps (●'◡'●)

Answer:

-2 and -4

Step-by-step explanation:

if you'll notice the function goes through the x axis at -2 and -4

Answer:

Scientific notation uses exponential notation. When a number is written in scientific notation, the exponent tells you if the term is a large or a small number. A positive exponent indicates a large number and a negative exponent indicates a small number that is between 0 and 1.

Answer:

Look at the exponitial factor. If it is like 10^2 or like 10^10 the number is very big because it is raised to a very big power. Oppisitely, when it is rasied to a negative number, the number producted will have many decimal places. For example 10^-1 is literaly 0.1.

Step-by-step explanation:

Yes I got u

The expected payout is

2 × 0.5 + 4 × 0.2 + 6 × 0.15 + 8 × 0.1 + 10 × 0.05

= 1 + 0.8 + 0.9 + 0.8 + 0.5

= 4

The expected value of the winnings from this game is $3.90.

It is the chance of an event to occur from a total number of outcomes.

The formula for probability is given as:

Probability = Number of required events / Total number of outcomes.

Example:

The probability of getting a head in tossing a coin.

P(H) = 1/2

We have,

To find the expected value of the winnings, we multiply each possible payout by its probability and then sum these products.

So,

Expected Value = (2 x 0.5) + (4 x 0.2) + (6 x 0.15) + (8 x 0.1) + (10 x 0.05)

Expected Value = 1 + 0.8 + 0.9 + 0.8 + 0.5

Expected Value = 3.9

Therefore,

The expected value of the winnings from this game is $3.90.

Learn more about probability here:

https://brainly.com/question/14099682

#SPJ7

Answer:

25%

Step-by-step explanation:

Based on the boxplot given ;

The boxplot can be summarized as follows :

Lower quartile, Q1 = 50 (starting point of the box)

Median (Q2), 50th percentile = 70 (vertical line in between the box)

The upper quartile marks the 75th percentile, Q3 = 81 (end point of the box)

The total distribution is 100% and hence, the percentage above the score 81 will be :

100% - 75% = 25%

Answer:

B. the mean

Step-by-step explanation:

According to the Bar Chart shown, the number of DVDs sold at a local music store during one week are displayed.

Therefore, the measure(s) of central tendency that can be used to determine the average number of DVDs sold each day is the mean.

This is because the mean is the sum total of the number of DVDs sold, divided by the number, which gives the average.

Answer:

The Mean

Step-by-step explanation:

I took the test

Step-by-step explanation:

Answer:

[tex]T_n = \frac{1}{4^{n-1}}[/tex]

Step-by-step explanation:

Given

[tex]({)1, 1/4, 1/16, 1/64, 1/256, ... (})[/tex]

Required

The general term

The given sequence is geometric.

So first, we calculate the common ratio (r)

[tex]r = T_2/T_1[/tex]

So, we have:

[tex]r = 1/4 \div 1[/tex]

[tex]r = 1/4[/tex]

The function is then calculated using:

[tex]T_n =T_1 * r^{n-1}[/tex]

This gives

[tex]T_n =1 * 1/4^{n-1}[/tex]

[tex]T_n = \frac{1}{4^{n-1}}[/tex]

Answer:

C. m<c = 140°

Step-by-step explanation:

Let's analyse each of the given options:

A. m<a = 140° is TRUE

Rationale: angle a and 140° are vertical angles. Vertical angles are congruent.

B. m<b = 140° is TRUE.

Rationale: angle a and 140° are alternate interior angles. Alternate interior angles are congruent.

C. m<c = 140° is NOT TRUE.

Rationale: angle c and 140° are same side interior angles. Same side interior angles are supplementary.

D. m<d = 140° is TRUE.

Rationale: angle d and 140° are corresponding angles. Corresponding angles are congruent.

the e-function stuff can be confusing sometimes, but notices that g(x) / the blue line, is just somewhat lower, rest is the same.

how much lower? look at the y-intercepts

f(0)= "about 5"

g(0)= "about -3"

with this y-intercept only option c can work

Answer:

A

Step-by-step explanation:

the first one in the picture

( solution at pic)

Answer:

The answer is 32 divided by 4

Step-by-step explanation:

Because in each box there is 4. There are 8 ovals all together. So 8×4, you get 32 and divide it by the number of squares in an oval which is 4

Answer:

the answer is 32 divided by 4=8

Step-by-step explanation:

because when you look at the ovals there's eight ovals and in side there's four squares..

HOPE THIS HELPS!!!!!

Answer:

I think no. D is the answer

Answer:

The total amount due after five years is $57,000.

Step-by-step explanation:

Recall that simple interest is given by the formula:

[tex]\displaystyle A=P(1+rt)[/tex]

Where A is the final amount, P is the principal amount, r is the rate, and t is the time (in years).

Since we are investing a principal amount of $38,000 at a rate of 10.0% for five years, P = 38000, r = 0.1, and t = 5. Substitute:

[tex]\displaystyle A=38000(1+(0.1)(5))[/tex]

Evaluate. Hence:

[tex]\displaystyle A=\$ 57,000[/tex]

The total amount due after five years is $57,000.

Answer:

y = 26.3x² - 116.9x + 109.6

Step-by-step explanation:

Given the data ;

Year Period Users (Millions)

2004 1 1

2005 2 5

2006 3 11

2007 4 58

2008 5 145

2009 6 359

2010 7 607

2011 8 846

A quadratic regression model can be obtained using a quadratic regression calculator ; The quadratic regression modeled obtained is in the form :

y = Ax² + Bx + C

y = 26.3x² - 116.9x + 109.6

Complete Question

A few years ago, people tended to have relatively large CD collections. For students at a large university in the midwest, the mean number of CDs owned was 78 with a standard deviation of 90. To confirm these numbers, a random sample of 120 students from this university was collected and the size of their CD collections recorded. These particular 120 students had a mean CD collection size of 80 CDs. What is the numerical value of the sample mean?

Answer:

Sample Mean [tex]\=x=80[/tex]

Step-by-step explanation:

From the question we are told that:

Population Mean [tex]\mu=78[/tex]

Standard deviation [tex]\sigma=90[/tex]

Sample size [tex]n=120[/tex]

Sample Mean [tex]\=x=80[/tex]

Therefore

The numerical value of the sample mean is

Sample Mean [tex]\=x=80[/tex]

Answer:

243.125

Step-by-step explanation:

First do the integral part

11110011

1. From left to right, starting with a zero,

2. add the digit, double, move on to the next digit and repeat step 2 until digits are exhausted.

The successive results are

1

3

7

15

30

60

121

243

For the decimal part, we proceed similarly but

1. From the right-most digit proceed to the left, start with a zero.

2. Add the digit, halve, move on to the next digit and repeat step 2 until the decimal is reached.

Successive results are:

0.5

.25

.125

So the final result is 11110011.001 binary is 243.125 decimal

Answer:

0.1003 = 10.03% probability that a simple random sample of size n= 10 results in a sample mean greater than 40 inches.

Gestation periods:

1) 0.3539 = 35.39% probability a randomly selected pregnancy lasts less than 260 days.

2) 0.0465 = 4.65% probability that a random sample of 20 pregnancies has a mean gestation period of 260 days or less.

3) 0.004 = 0.4% probability that a random sample of 50 pregnancies has a mean gestation period of 260 days or less.

4) 0.9844 = 98.44% probability a random sample of size 15 will have a mean gestation period within 10 days of the mean.

Step-by-step explanation:

To solve these questions, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

The height, X, of all 3-year-old females is approximately normally distributed with mean 38.72 inches and standard deviation 3.17 inches.

This means that [tex]\mu = 38.72, \sigma = 3.17[/tex]

Sample of 10:

This means that [tex]n = 10, s = \frac{3.17}{\sqrt{10}}[/tex]

Compute the probability that a simple random sample of size n= 10 results in a sample mean greater than 40 inches.

This is 1 subtracted by the p-value of Z when X = 40. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{40 - 38.72}{\frac{3.17}{\sqrt{10}}}[/tex]

[tex]Z = 1.28[/tex]

[tex]Z = 1.28[/tex] has a p-value of 0.8997

1 - 0.8997 = 0.1003

0.1003 = 10.03% probability that a simple random sample of size n= 10 results in a sample mean greater than 40 inches.

Gestation periods:

[tex]\mu = 266, \sigma = 16[/tex]

1. What is the probability a randomly selected pregnancy lasts less than 260 days?

This is the p-value of Z when X = 260. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{260 -  266}{16}[/tex]

[tex]Z = -0.375[/tex]

[tex]Z = -0.375[/tex] has a p-value of 0.3539.

0.3539 = 35.39% probability a randomly selected pregnancy lasts less than 260 days.

2. What is the probability that a random sample of 20 pregnancies has a mean gestation period of 260 days or less?

Now [tex]n = 20[/tex], so:

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{260 - 266}{\frac{16}{\sqrt{20}}}[/tex]

[tex]Z = -1.68[/tex]

[tex]Z = -1.68[/tex] has a p-value of 0.0465.

0.0465 = 4.65% probability that a random sample of 20 pregnancies has a mean gestation period of 260 days or less.

3. What is the probability that a random sample of 50 pregnancies has a mean gestation period of 260 days or less?

Now [tex]n = 50[/tex], so:

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{260 - 266}{\frac{16}{\sqrt{50}}}[/tex]

[tex]Z = -2.65[/tex]

[tex]Z = -2.65[/tex] has a p-value of 0.0040.

0.004 = 0.4% probability that a random sample of 50 pregnancies has a mean gestation period of 260 days or less.

4. What is the probability a random sample of size 15 will have a mean gestation period within 10 days of the mean?

Sample of size 15 means that [tex]n = 15[/tex]. This probability is the p-value of Z when X = 276 subtracted by the p-value of Z when X = 256.

X = 276

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{276 - 266}{\frac{16}{\sqrt{15}}}[/tex]

[tex]Z = 2.42[/tex]

[tex]Z = 2.42[/tex] has a p-value of 0.9922.

X = 256

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{256 - 266}{\frac{16}{\sqrt{15}}}[/tex]

[tex]Z = -2.42[/tex]

[tex]Z = -2.42[/tex] has a p-value of 0.0078.

0.9922 - 0.0078 = 0.9844

0.9844 = 98.44% probability a random sample of size 15 will have a mean gestation period within 10 days of the mean.

Answer:

The correct answer is B. 33 1/3%.

Step-by-step explanation:

Given that A's salary is 50% more than B's, to determine how much percent is B's salary less than A's, the following calculation must be performed:

Salary A = B + 50

Salary B = 100

Salary A = 100 + 50 = 150

150 = 100

100 = X

100 x 100/150 = X

10,000 / 150 = X

66.666 = X

100 - 66,666 = 33,333

Answer:

B. 33 1/3%.

Step-by-step explanation:

Hope this helps

Answer:

you simply have to do ide the coefficients and subtract the power

MODE IS THE NUMBER THAT IS REPEATED THE HIGHEST TIME..

HERE, IN YOUR QUESTION 5CAME 2 TIMES i.e. it is repeated highest time .so mode=5....