Answer:
In classical mechanics, kinetic energy (KE) is equal to half of an object's mass (1/2*m) multiplied by the velocity squared. For example, if a an object with a mass of 10 kg (m = 10 kg) is moving at a velocity of 5 meters per second (v = 5 m/s), the kinetic energy is equal to 125 Joules, or (1/2 * 10 kg) * 5 m/s2.
A single covalent bond is stronger than a single hydrogen bond so why does a group of polar molecules tend to have a higher boiling point than a group of non polar molecules
Answer:
this question makes no sense
Explanation:
like how do you get this question
Answer:They require more energy to break intermolecular forces hence polar molecules have higher melting points and boiling points than non-polar molecules of similar size, shape and number of electrons.
Explanation:
what is the velocity of a 50 kg dog with 3000 j of kinetic energy
Answer:
KE = 225000000 J
Explanation:
Answer:
10.954. from equation. KE=1/2m(v^2)
2KE=m(v^2) 6000=50(v^2) (v^2)=6000/50
(v^2)=120. square root for all v=10.954 m/s
Which image shows an example of the electromagnetic force in action?
Answer:
Where are the images?
Explanation:
I can't help if there is no image(s) to this question.
An object with a mass of 13.2 kg is accelerating at 9.4 m/s? What force is being applied on the object?
Round your answer to the appropriate number of significant figures and use the following formula:
force = mass x acceleration
Force = mass x acceleration:
Force = 13.2 kg x 9.4 m/s
Force = 124.08
Force = 124 Newtons
The force will be = 124 N
What is newton's second law of motion?
Newton's second law is a quantitative description of the changes that a force can produce on the motion of a body. It states that the time rate of change of the momentum of a body is equal in both magnitude and direction to the force imposed on it.
according to newton's second law of motion
Force = mass * acceleration
given
mass = 13.2 kg
acceleration = 9.4 m/s
force = 13.2 * 9.4
= 124.08 N
Rounding off answer to the appropriate number of significant figures
force = 124 N
learn more about newton's second law :
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according to newton's third law, of a sledgehammer hits a wall with a force of 1000 n, how much force does the wall hit the sledgehammer? a - 1000 n b 1000 n c 0 n d 500 n
The correct option is A: the force exerted on the wall by the sledgehammer is - 1000 N
Newton's third lawNewton's third law of motion states that for every action or force, there is an equal but oppositely directed force.
Application of the newton's third lawForce with which the sledgehammer hits the wall = 1000 N
From the Newton's third law, an equal but oppositely directed force is exerted on the sledgehammer by the wall.Thus, the force exerted by the sledgehammer on the wall = -1000 N
The negative sign indicates that the force acts in a direction opposite to that of the sledgehammer.Thus, the correct option is A: the force exerted on the wall by the sledgehammer is - 1000 N
Learn more about Newton's third law and force at: https://brainly.com/question/13874955
If the density of gold is 19.3 g/mL, what is the mass of 5mL of gold?
Answer:
96.5 mL
Explanation:
can someone explain why is the answer 3.1?
i dont know Im sorry but why Im messaging is because when more people respond it usually is the first to pop up so someone else will see this and be able to help you Explanation:
A book with a. mass of 1 kg is sliding on a table. If the frictional force on the book is 5 N, calculate the book’s acceleration. Is it speeding up or slowing down?
Force = mass x acceleration:
5N = 1kg x acceleration
Acceleration = 5N / 1 kg
Acceleration = 5 m/s^2
Acceleration is a positive value so it is speeding up
the purpose of many scientific investigations is to test a {n}
Answer:
Scientific investigation is a quest to find the answer to a question using the scientific method.
Explanation:
the scientific method is a systematic process that involves using measurable observations to formulate, test or modify a hypothesis.
Connor rode an inner tube down a river. For 4.6 minutes, he moved downriver at 15 meters per minute. During this time, how far did he move?
answers:
3.26 meters
3.26 minutes
69 meters
69 minutes
Answer:
69 meters
Explanation:
Block A has a mass of 2kg and a speed of 50 m/s along the positive x axis.
Block B has a mass of 4 kg and a speed of 25 m/s along the negative x axis.
The two blocks collide head-on in a perfectly elastic collision.
Determine the velocity of each mass after the collision.
Momentum is conserved, so
(2 kg) (50 m/s) + (4 kg) (-25 m/s) = (2 kg) v₁' + (4 kg) v₂'
where v₁' and v₂' are the velocities of the two blocks after the collision. Simplifying this gives
100 kg•m/s - 100 kg•m/s = (2 kg) v₁' + (4 kg) v₂'
0 = (2 kg) v₁' + (4 kg) v₂'
v₁' = -2v₂'
Energy is also conserved, so
1/2 (2 kg) (50 m/s)² + 1/2 (4 kg) (-25 m/s)² = 1/2 (2 kg) (v₁')² + 1/2 (4 kg) (v₂')²
Simplifying yields
2500 J + 1250 J = (1 kg) (v₁')² + (2 kg) (v₂')²
3750 J = (1 kg) (v₁')² + (2 kg) (v₂')²
Substitute v₁' = -2v₂' and solve for v₂' :
3750 J = (1 kg) (-2v₂')² + (2 kg) (v₂')²
3750 J = (6 kg) (v₂')²
(v₂')² = 625 J/kg = 625 m²/s²
v₂' = 25 m/s
Then the first block has final velocity
v₁' = -2 (25 m/s)
v₁' = -50 m/s
Draw a nitrogen cycle and explain in short.
please help me
Answer: biogeochemical process
Explanation:
stella is driving down a steep hill. she should keep her car __________ to help _________.
Answer:
Stella is driving down a steep hill. She should keep her car in a lower gear to help slow her vehicle.
Explanation:
hi my name is coolboy123hillok
Answer:
you should change that name
29) A cheetah can accelerate from rest to 25
m/s in 6 s. Assuming that the cheetah moves
with constant acceleration, what distance does
it cover in the first 3 s
Answer:
[tex]\huge\boxed{\sf S = 18.75 \ meters}[/tex]
Explanation:
Given Data:
Initial Velocity = Vi = 0 m/s (rest)
Final Velocity for 6 seconds = Vf = 25 m/s
Time (1) = T1 = 6 seconds
Time (2) = T2 = 3 seconds
Required:
Distance for 3 seconds = S = ?
Solution:
For 6 seconds, the acceleration will be:
[tex]\displaystyle a = \frac{Vf-Vi}{t} \\\\a = \frac{25 - 0}{6} \\\\a = 25 / 6\\\\\boxed{a = 4.167 \ m/s^2}[/tex]
Since, acceleration is constant, it will be the same at 3 seconds as well.
Using second equation of motion to find Distance (S) with time being 3 seconds:
[tex]\displaystyle S= Vit+\frac{1}{2} at^2\\\\S = (0)(3)+ \frac{1}{2} (4.167)(3)^2\\\\S = \frac{1}{2} (4.167)(9)\\\\S = \frac{37.5}{2} \\\\\boxed{S = 18.75 \ meters}\\\\\rule[225]{225}{2}[/tex]
Hope this helped!
~AH1807