The distance travelled in total is 14 m. But the resultant displacement is the square root of the sum of squares of each distances covered in different directions, that is 10 m.
What is displacement ?Displacement is a physical quantity that, that measures how far we travelled from a mean position. The change in position is dependent on the magnitude and direction as well. Hence, displacement is a vector quantity.
The distance covered by an object is total length or sum magnitudes of the length it covered. It is a scalar quantity. Here, the distance covered is 6 + 8 = 14 m.
The resultant displacement here, is calculated as follows:
ds = √(6² + 8²) = √100 = 10 m
Therefore, the displacement of us will be 10 m.
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What is an antibody and what does it do?
an antibody is a blood protein produced in response to and counteracting a specific antigen. Antibodies combine chemically with substances which the body recognizes as alien, such as bacteria, viruses, and foreign substances in the blood.
Antibodies are proteins that help fight off infections and can provide protection against getting that disease again (immunity). Antibodies are disease specific.
A car travels at a constant speed around a circular track whose radius is 3.22 km. The car goes once around the track in 248 s. What is the magnitude of the centripetal acceleration of the car
Answer:
a = 1,838.17m/s²
Explanation:
centripetal acceleration a = v²/r
v is velocity of the car
r is the radius = 3.22km = 3220m
time t = 248
First is to find to velocity using the equation of motion:
v = u+gt
v = 0+(9.81)(248)
v = 2,432.88m/s
a = 2,432.88²/3220
a = 5,918,905.0944/3220
a = 1,838.17m/s²
The magnitude of the centripetal acceleration of the car is 1,838.17m/s²
A man runs 400.0m around the track,
then another 400.0m around the track again.
As the track is 400.Om long, the man is back
where he started!
a) calculate distance travelled
b) calculate mans displacement
Answer:
Distance = 800 m, Displacement = 0
Explanation:
It is given that,
A man runs 400 m around the track, then another 400 m around the track again.
(a) Distance travelled by an object is the sum of total path covered.
In this case, he has covered total path of 400 m + 400 m i.e. 800 m. It means he travelled a distance of 800 m.
(b) Displacement covered by an object is the shortest path covered by it. In this problem, he reaches the point from where he has started. It means that his displacement is equal to 0.
The effect wind has on an airplane can be modeled by using a wind tunnel. What is one limitation of this model
Answer:
The limitations of this this model is the amount of wind being blown to effect the airplane.
Answer: Highly skilled workers are necessary to run the wind tunnel.
Explanation: I took the quiz on A pex.
Explain why the interconnection is not valid. Explain why the interconnection is not valid. A valid interconnection would require the 3 AA and 4 AA sources to supply different currents in the same direction, which they do not. A valid interconnection would require the 3 AA and 4 AA sources to supply different currents in opposite directions, which they do not. A valid interconnection would require the 3 AA and 4 AA sources to supply the same current in opposite directions, which they do not. A valid interconnection would require the 3 AA and 4 AA sources to supply the same current in the same direction, which they do not.
Complete Question
The diagram for this question is shown on the first uploaded image
Explain why the interconnection is not valid.
i A valid interconnection would require the 3 A and 4 A sources to supply different currents in the same direction, which they do not.
ii A valid interconnection would require the 3 A and 4 A sources to supply different currents in opposite directions, which they do not.
iii A valid interconnection would require the 3 A and 4 A sources to supply the same current in opposite directions, which they do not.
iv A valid interconnection would require the 3 A and 4 A sources to supply the same current in the same direction, which they do not
Answer:
The correct option is iv
Explanation:
Looking at the diagram we see that the current source are connected in series, generally the current flowing through two source that are connected in series is suppose to be the same but in this case it is not so
i.e [tex]4A \ne 3 A[/tex] hence Kirchhoff's law is broken or not followed in this circuit which means the interconnection is not valid
also another reason why the interconnection is not valid is because the current are flowing in the different directions
explain which one would have a larger momentum a charging elephant or a buzzing bee
when are two magnets attracted?
Answer:
when the negative and positive energy is connected
Explanation:
How does energy from the sun travel to earth .
Answer:
through uv light
ASAP PLEASE :)
How can we add kinetic energy to a baseball or football?
Answer:
Hitting it or throwing it with force.
suppose you put some ice is put into a container of water at room temperature. For faster cooling, the ice should (i) be allowed to float naturally in the water or (ii) be pushed to the bottom of the container with a glass rod and held there. Explain your answer.
Answer:
i am just trying it could be wrong too i am not sure about it but according to me the ans is (1)let ice be allowed to float naturally in the water
Explanation:
if u put water in ice or ice in water the temperature of water decreases and then the process gets slower but if u allow to float it then the temperature of water and surrounding air decreases and the heat is lost from air and water both so here the heat is more than only just water here it allows both to give heat and in 2nd option the heat is only lost by water and gained by icehere it allows only water to give heat so the heat is less in surrounding of ice in water so more heat more faster the process therefore i think the 1st option is correct
A tennis ball is released from a height of 2.0 m above the floor, and then bounces three times. With each bounce, dissipative forces cause it to lose 16.0% of its mechanical energy. How high does it reach after the third bounce?
140 cm
120 cm
120 mm
12 cm
Answer:
12 cm
Explanation:
From what I got with my answer (8.192 cm) I went ahead and rounded it to the closest answer which is 12 cm. Hopefully im correct but if not, I apologize in advance.
Work occurs when (2 points) an applied force results in movement of an object in the same direction as the applied force an object is subjected to balanced forces resulting in movement of the object the energy present is the result of the force acting on the object the movement of the object was caused by a force and is in the opposite direction of the force
Answer:
.
Explanation:
The gravitational constant G was first measured accurately by Henry Cavendish in 1798. He used an exquisitely sensitive balance to measure the force between two lead spheres whose centers were 0.27 m apart. One of the spheres had a mass of 188 kg, while the mass of the other sphere was 0.93 kg.
What was the ratio of the gravitational force between these spheres to the weight of the lighter sphere?
The gravitational force between the spheres is
[tex]F_{\rm g}=\dfrac{G(188\,\mathrm{kg})(0.93\,\mathrm{kg})}{(0.27\,\mathrm m)^2}\approx1.6\times10^{-7}\,\mathrm N[/tex]
where G = 6.674 x 10⁻¹¹ N m²/kg².
The weight of the lighter sphere is
[tex]F_{\rm w}=(0.93\,\mathrm{kg})g\approx9.1\,\mathrm N[/tex]
where g = 9.80 m/s².
The ratio between the two forces is then
[tex]\dfrac{F_{\rm g}}{F_{\rm w}}\approx1.8\times10^{-8}[/tex]
A train travels from Boston to New York. It travels at a speed of 180 km/h for two hours, speeds up to 200 km/h for the next four hours and then slows down to 120 km/h for the next six hours. What is the average speed of the train for this trip?
Answer:
156 2/3 km/hr
Explanation:
Average speed is found by dividing total distance by total time.
180 km/hr in 2 hrs is 360 miles
200 km/hr in 4 hrs is 800 miles
120 km/hr in 6 hrs is 720 miles
Total time is 12 hrs; Total distance 1880 hrs
Divide distance by time and you have 156 2/3 km/hr. This is your average speed.
leaves uses_,_and_to make food for the plant
light, water, carbon dioxide
Explanation:
c02 , h20 and light
Lithium can be found in?
Answer:
Lithium does not occur as the metal in nature. Is found combined in small amounts in nearly all igneous rocks and in the waters of many mineral springs. Spodumene, petalite, lepidolite, and amblygonite are the more important minerals containing lithium.
Lithium can be found in Lithium-ion batteries, some heat-resistant glass and ceramics, some grease lubricants, and some anti-depressant medications.
A force of 50 N acts upon a 10 kg block. Calculate the acceleration of the object.
State and explain Gauss's law in
electrostatics and use it to determine the electric field
intensity due to a line charge.
To find:-
To find the electric field due to a point charge using Gauss's Law .Answer:-
Gauss's law in electrostatics states that the electric flux through a closed surface is equal to 1/ε0 times the charge enclosed by that surface, that is,
[tex]\implies \displaystyle \phi_E = \oint \vec{E} .\vec{ds} \\[/tex]
Also ,
[tex]\implies\displaystyle \oint \vec{E}.\vec{ds} =\dfrac{q}{\epsilon_0} \\[/tex]
Linear density of charge:-
It ise defined as charge per unit length. Mathematically,
[tex]\implies\displaystyle \lambda =\dfrac{q}{\ell} \\[/tex]
where ,
[tex] q[/tex] is the charge .[tex]\ell[/tex] is the length of the conductor.For figure see attachment.
Now let us assume that the linear density of charge is [tex]\lambda[/tex] . There is a point P near the wire at a distance of " r " from it , where we are interested in calculating the electrical field. Imagine a coaxial Gaussian cylinder of length [tex]\ell[/tex] , and radius " r " such that the point P lines on its surface.
Calculating Electrical flux through the cylinder:-
[tex]\implies\displaystyle \phi_E = 0 + 0 + \oint E.ds \\[/tex]
[tex]\implies\displaystyle\phi_E = \oint E.ds \ \cos0^o \\[/tex]
[tex]\implies\displaystyle \phi_E = \oint Eds \\[/tex]
[tex]\implies\displaystyle \phi_E = E\oint ds \\[/tex]
[tex]\implies\displaystyle \phi_E = E (2\pi r\ell) \ \ dots (1) \\[/tex]
From Gauss's law:-
[tex]\implies\displaystyle \phi_E =\dfrac{q}{\epsilon_0} \\[/tex]
[tex]\implies\displaystyle \phi_E = \dfrac{\lambda \ell}{\epsilon_0}\ \dots (2) \\[/tex]
Therefore , from equation (1) and (2) , we have;
[tex]\implies\displaystyle E \times 2\pi r \ell =\dfrac{\lambda\ell}{\epsilon_0}\\[/tex]
[tex]\implies\displaystyle \underline{\underline{\green{ E =\dfrac{1}{4\pi \epsilon_0}\dfrac{2\lambda}{r}}}}\\[/tex]
And we are done!
To increase muscular strength the number of reputation should be?
A high
B light
C heavy
D low
increase muscular endurance the number of repetitions should be?
A high
B light
C heavy
D low
To increase muscular endurance the weight being lifted should be?
A high
B light
C heavy
D low
to increase muscular strength the weight being lifted should be?
A high
B light
C heavy
D low
Answer:
Explanation:
heavyy
Two point charges of magnitudes +5.00 μC, and +7.00 μC are placed along the x-axis at x = 0 cm and x = 100 cm, respectively. Where must a third charge be placed along the x-axis so that it does not experience any net force because of the other two charges? Two point charges of magnitudes +5.00 μC, and +7.00 μC are placed along the x-axis at x = 0 cm and x = 100 cm, respectively. Where must a third charge be placed along the x-axis so that it does not experience any net force because of the other two charges? 50 cm 45.8 cm 9.12 cm 91.2 cm 4.58 cm
Answer:
45.8 cm
Explanation:
To solve this, we will use the formula
5 / x² = 7/(1 - x)²
5 / x² = 7 / (1 - 2x + x²)
5 / 7 = x² / (1 - 2x + x²)
x = 0.5 * (√(35) - 5) meters
x = 0.5 * (5.916 - 5)
x = 0.5 * (0.916)
x = 0.458 or x = 45.8
The position where the third charge is placed along the x-axis so that it does not experience any net force because of the other two charges is 45.8 cm.
Given :
Two point charges of magnitudes +5.00 μC, and +7.00 μC are placed along the x-axis at x = 0 cm and x = 100 cm, respectively.
The following calculation can be used in order to determine the position where the third charge is placed along the x-axis so that it does not experience any net force because of the other two charges.
[tex]\rm \dfrac{5}{x^2}=\dfrac{7}{(1-x)^2}[/tex]
Simplify the above expression by cross multiplying.
[tex]5(x^2+1-2x)=7x^2[/tex]
[tex]\rm 5x^2 + 5 - 10x = 7x^2[/tex]
[tex]2x^2+2x-1=0[/tex]
Further, simplify the above expression in order to determine the value of x.
x = 0.458
x = 45.8 cm
Therefore, the correct option is b).
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A man starts walking at a steady speed of 1 m/s and 6s later his son sets off from the same point in pursuit of him, starting at rest and accelerating at 2/3 m/s/s. How far do they go before they are together?
Answer:
The father will walk 6 more meters and the son will walk 12 meters
Explanation:
Uniform Speed and Acceleration
This is a problem where two objects have different types of motion. The father walks at a constant speed and later, his son starts a constant acceleration motion in pursuit of him.
Let's start with the father, whose speed is v=1 m/s during t=6 seconds. He travels a distance:
[tex]x=vt=1*6=6\ m[/tex]
Now the son, starting from rest (vo=0) accelerates at a=2/3 m/s^2. His speed will increase and eventually, he will catch up with his father. Let's suppose it happens at a time t1.
The distance traveled by the son is given by:
[tex]\displaystyle xs=v_o.t_1+\frac{a.t_1^2}{2}[/tex]
Since vo=0:
[tex]\displaystyle xs=\frac{a.t_1^2}{2}[/tex]
The father will continue with constant speed and travels a distance of:
[tex]xf=v.t_1[/tex]
For them to catch up, the distance of the son must be 6 m more than the distance of the father, because of the leading distance he has already taken. Thus:
[tex]xs=xf+6[/tex]
Substituting the equations of each man:
[tex]\displaystyle \frac{a.t_1^2}{2}=v.t_1+6[/tex]
We know a=2/3, v=1:
[tex]\displaystyle \frac{2}{3}\cdot\frac{t_1^2}{2}=t_1+6[/tex]
Simplifying:
[tex]\displaystyle \frac{t_1^2}{3}=t_1+6[/tex]
Multiply by 3:
[tex]t_1^2=3t_1+18[/tex]
Rearranging:
[tex]t_1^2-3t_1-18=0[/tex]
Factoring:
[tex](t_1-6)(t_1+3)=0[/tex]
Solving:
[tex]t_1=6 , t_1=-3[/tex]
Since time cannot be negative, the only valid solution is
[tex]t_1=6\ s[/tex]
The distance traveled by the son in 6 seconds is:
[tex]\displaystyle xs=\frac{2/3\cdot 6^2}{2}[/tex]
[tex]xs=12\ m[/tex]
Note the father will travel
[tex]xf=1*6=6\ m[/tex]
This 6 m plus the 6 m he was ahead of the son, make them meet while walking at 6 seconds.
Answer: The father will walk 6 more meters and the son will walk 12 meters
How does Newton’s second law apply to golf
Answer: Newton's Second Law of Motion is proven through the way the golf ball flies through the air. Newton's law states that the net force of an object (Fnet) is equivalent to the object's mass (m) multiplied by the object's acceleration (a). In other words, Fnet = ma.
Explanation: Vote me brainliest ;D
A car travels 90 km/h. How long does it take for the car to travel
400 km?
b. 1.5x103 s
C. 1.5x104 s
a. 4x104 s.
d. 1.6x104s
Answer:
4.44 hr
Explanation:
distance= rate*time
400km/(90 km/hr)=time
time=4.44 hr
I’ve been stuck on this question, what’s the answer to this question?
Explanation:
[tex]\sf{H_2CO_3 + NaOH \longrightarrow NA_2CO_3 + H_2O}[/tex]
Where [tex]\sf{H_2CO_3 }[/tex] is Carbonic AcidWhere [tex]\sf{ NaOH }[/tex] is Sodium HydroxideReaction gives out [tex]\sf{ NA_2CO_3 + H_2O}[/tex]Where [tex]\sf{ NA_2CO_3 }[/tex] is Sodium HydroxideAnd [tex]\sf{ H_2O}[/tex] is water.So, [tex]\sf{ NA_2CO_3 }[/tex] Sodium Carbonate is the answer.
Hope it helps :)
for which pair of objects would adding the same amount of eletrons to each object result in a decrease in a electrical force
Answer:
two positively charged objects
Explanation:
A car is at velocity of 20 km/h. If the car traveled 120 km in 3 hours at constant acceleration, what is its final velocity?
What happens to the temperature of a substance while it is changing state?
Answer:
its temperature stays constant
Explanation:
Being a micro-manager is an example of using effective team building techniques
T or F
Answer:
TRUE
Explanation:
Answer:
True
Explanation:
A automotive test driver travels due north in a prototype hybrid vehicle at 30 mi/h
for 2 hours. She then reverses her direction and travels due south at 60 mi/h for 1 hour.
What is the average speed of the vehicle?
a) 40 mi/h
b) 50 mi/h
c) zero mi/h
d) 60 mi/h
e) 30 mi/h
Answer:
Option A. 40 mi/h
Explanation:
To obtain the average speed of the vehicle, we'll begin by calculating the distance travelled by the vehicle in each case. This is illustrated below:
Case 1:
Speed = 30 mi/h
Time = 2 h
Distance =...?
Speed = Distance /Time
30 = Distance /2
Cross multiply
Distance = 30 × 2
Distance = 60 mi
Case 2:
Speed = 60 mi/h
Time = 1 h
Distance =...?
Speed = Distance /Time
60 = Distance /1
Cross multiply
Distance = 60 × 1
Distance = 60 mi
Finally, we shall determine the average speed of the vehicle as follow:
Total distance travelled = 60 + 60
Total distance travelled = 120 mi
Total time = 2 + 1
Total time = 3 h
Average speed =..?
Average speed = Total Distance travelled /Total time
Average speed = 120/3
Average speed = 40 mi/h
Therefore, the average speed of the vehicle is 40 mi/h
A 1-kilogram object is thrown horizontally and a 2-kilogram object is dropped vertically at
the same instant and from the same point above the ground. Which of the following will
be the same for both objects at any given instant?
Acceleration is the change in the velocity of the object with time. Acceleration is the same for both objects so both objects will reach the ground at the same time.
How do you find out the common value for both objects?Given that both the object dropped at the same time. So the gravitational acceleration of both the objects will be the same which is nearly 10 m/s.
The force at object 1 is given below.
[tex]F_1 = m_1\times g = m_1\times a_1[/tex]
Where m1 is the mass of object 1 and a1 is the acceleration of object 1.
[tex]F _1 = 1\times 10 = 10 \;\rm N[/tex]
The acceleration of object 1 is calculated as below.
[tex]a_1 = \dfrac{F_1}{m_1}[/tex]
[tex]a_1=\dfrac{10}{1} = 10 \;\rm m/s^2[/tex]
The force at object 2 is given below.
[tex]F_2 = m_2\times g = m_2\times a_2[/tex]
Where m2 is the mass of object 2 and a2 is the acceleration of object 2.
[tex]F_2 = 2\times 10 =20 \;\rm N[/tex]
The acceleration of object 2 is calculated as below.
[tex]a_2 = \dfrac{F_2}{m_2}[/tex]
[tex]a_2=\dfrac{20}{2} = 10 \;\rm m/s^2[/tex]
Hence we can conclude that the acceleration of both the objects is the same at every point so they will reach the ground at the same time.
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