You have been given two classes, a Main.java and a Coin.java. The coin class represents a coin. Any object made from it will have a 1) name, 2) weight and 3) value. As of now, the instance variables in Coin.java are all public, and the main function is calling these variables directly for the one coin made in it.
Required:
Your goal is to enforce information hiding principles in this tasl. Take Coin.java, make all instance variables private and create set/get functions for each instance variable. Then replace the direct references in main() to each instance variable with a call to an appropriate set or get function.
Answers
Answer:
Here is the Coin class:
public class Coin { //class names
private int value; // private member variable of type int of class Coin to store the value
private String coinName; // private member variable of type String of class Coin to store the coint name
private double weight; //private member variable of type double of class Coin to store the weight
public void setValue (int v) { //mutator method to set the value field
value = v; }
public void setName(String n){ //mutator method to set coinName field
coinName = n;}
public void setWeight (double w) { //mutator method to set weight field
weight = w; }
public int getValue () { //accessor method to get the value
return value; } // returns the current value
public String getName () { //accessor method to get the coin name
return coinName; } //returns the current coin name
public double getWeight () { //accessor method to get the weight
return weight; } } //returns the current weight
Explanation:
Here is the Main.java
public class Main{ //class name
public static void main(String[] args) { //start of main method
Coin penny = new Coin(); //creates object of Coin class called penny
penny.setName("Penny"); //calls setName method of Coin using object penny to set the coinName to Penny
penny.setValue(1); //calls setValue method of Coin using object penny to set the coin value to 1
penny.setWeight(0.003); //calls setWeight method of Coin using object penny to set the coin weight to 0.003
System.out.println("Coin name: " + penny.getName()); // calls getName method of Coin using penny object to get the current coin name stored in coinName field
System.out.println("Coin value: " + penny.getValue()); // calls getValue method of Coin using penny object to get the coin value stored in value field
System.out.println("Coin weight: " +penny.getWeight()); }} // calls getWeight method of Coin using penny object to get the coin weight stored in weight field
The value of coinName is set to Penny, that of value is set to 1 and that of weight is set to 0.003 using mutator method and then the accessor methods to access these values and prinln() to display these accessed values on output screen. Hence the output of the entire program is:
Coin name: Penny Coin value: 1 Coin weight: 0.003
The screenshot of the program along with its output is attached.
Related Questions
Which orientation is wider than it is tall?
Portrait
Macro
Shutter
Landscape
Answers
Answer:
Landscape
Explanation:
Landscape orientation is wider than it is tall.
Answer:
Landscape
Explanation:
Create an interface called Runner. The interface has an abstract method called run() that displays a message describing the meaning of run to the class. Create classes called Machine, Athlete, and PoliticalCandidate that all implement Runner.
The run() should print the following in each class:
Machine - When a machine is running, it is operating.
Athlete - An athlete might run in a race, or in a game like soccer.
PoliticalCandidate - A political candidate runs for office.
----------------------------------------------------------------------------------------------------
public class Athlete implements Runner
{
public void run()
{
// write your code here
}
}
--------------------------------------------------------------------------------------
public class DemoRunners
{
public static void main(String[] args)
{
Machine runner1 = new Machine();
Athlete runner2 = new Athlete();
PoliticalCandidate runner3 = new PoliticalCandidate();
runner1.run();
runner2.run();
runner3.run();
}
}
------------------------------------------------------------------------------------------
public class Machine implements Runner
{
public void run()
{
// write your code here
}
}
----------------------------------------------------------------------------------------------------
public class PoliticalCandidate implements Runner
{
public void run()
{
// write your code here
}
}
----------------------------------------------------------------------------------------------------
public interface Runner
{
// write your code here
}
----------------------------------------------------------------------------------------------------
Answers
Answer:
Please find the code and its output in the attached file.
Explanation:
In the above-given code, an interface "Runner" is defined, inside the interface, an abstract method run is declared.
In the next step, three class "Athlete, Machine, and PoliticalCandidate" s defined that implements the run method, and use the print message that holds a given value as a message.
In the next step, a class "DemoRunners" is defined, and inside the main method, the three-class object is declared, which calls the run method.
Find the maximum value and minimum value in milesTracker. Assign the maximum value to maxMiles, and the minimum value to minMiles. Sample output for the given program:
Min miles: -10
Max miles: 40
Here's what I have so far:
import java.util.Scanner;
public class ArraysKeyValue {
public static void main (String [] args) {
final int NUM_ROWS = 2;
final int NUM_COLS = 2;
int [][] milesTracker = new int[NUM_ROWS][NUM_COLS];
int i = 0;
int j = 0;
int maxMiles = 0; // Assign with first element in milesTracker before loop
int minMiles = 0; // Assign with first element in milesTracker before loop
milesTracker[0][0] = -10;
milesTracker[0][1] = 20;
milesTracker[1][0] = 30;
milesTracker[1][1] = 40;
//edit from here
for(i = 0; i < NUM_ROWS; ++i){
for(j = 0; j < NUM_COLS; ++j){
if(milesTracker[i][j] > maxMiles){
maxMiles = milesTracker[i][j];
}
}
}
for(i = 0; i < NUM_ROWS; ++i){
for(j = 0; j < NUM_COLS; ++j){
if(milesTracker[i][j] < minMiles){
minMiles = milesTracker[i][j];
}
}
}
//edit to here
System.out.println("Min miles: " + minMiles);
System.out.println("Max miles: " + maxMiles);
}
Answers
Answer:
See Explanation
Explanation:
Your program is correct and doesn't need an attachment.
However, there's a mismatch in placement of curly braces in your program
{
}
I've made corrections to that and I've added the corrected program as an attachment.
Aside that, there's no other thing to be corrected in your program.
Use another compiler to compile your program is you are not getting the required output.
Plz answer me will mark as brainliest
Answers
Answer:
True
Operating System
Booting
Which of the following is NOT solely an Internet-based company?
Netflix®
Amazon®
Pandora®
CNN®
Answers
Answer:
I think it's Pandora, though I am familiar with others
Answer:
CNN
Explanation:
Which of the following domestic appliances does not use a magnet?
A. Fridge
B. Pressing iron
C. Radio
D. Fan
Answers
Please help me. Anyone who gives ridiculous answers for points will be reported.
Answers
Answer:
Well, First of all, use Linear
Explanation:
My sis always tries to explain it to me even though I know already, I can get her to give you so much explanations XD
I have the Longest explanation possible but it won't let me say it after 20 min of writing
A CPU with a quad-core microprocessor runs _____ times as fast as a computer with a single-core processor.
two
three
four
eight
Answers
Answer:
four
Explanation:
quad means four so it runs four times faster
Technician A says that the last step in the diagnostic process is to verify the problem. Technician B says that the second step is to perform a thorough visual inspection. Who is correct
Answers
Answer:
The answer to this question is given below in the explanation section. However, the correct option is Technician B.
Explanation:
There are eight steps procedures to diagnose the engine.
Step 1 Verify the Problem
Step 2 Perform a Thorough Visual Inspection and Basic Tests
Step 3 Retrieve the Diagnostic Trouble Codes (DTCs)
Step 4 Check for Technical Service Bulletins (TSBs)
Step 5 Look Carefully at Scan Tool Data
Step 6 Narrow the Problem to a System or Cylinder
Step 7 Repair the Problem and Determine the Root Cause
Step 8 Verify the Repair and Clear Any Stored DTCs
So the correct technician is Technician B that says that the second step is to perform a thorough visual inspection.
Challenge activity 1.3.6:output basics.for activities with output like below,your output's whitespace(newlines or spaces) must match exactly.see this note.write code that outputs the following.end with a newline.This weekend will be nice.
Answers
In python:
print("This weekend will be nice.")
I hope this helps!
Your job is to write a basic blurring algorithm for a video driver. The algorithm will do the following: it will go through all pixels on the screen and for each pixel, compute the average intensity value (in red, green and blue separately) of the pixel and its 8 neighbors. (At the edges of the screen, there are fewer neighbors for each pixel.) Let's say the number of pixels on the screen is n. Then what is the order of the number of arithmetic operations (additions and divisions) required?
a. The number is order of n 4 .
b. The number is order of n2.
c. The number is order of n
d. The number is order of n3.
Answers
We define the following terms:
Lexicographical Order, also known as alphabetic or dictionary order, orders characters as follows:
For example, ball < cat, dog < dorm, Happy < happy, Zoo < ball.
A substring of a string is a contiguous block of characters in the string. For example, the substrings of abc are a, b, c, ab, bc, and abc.
Given a string, , and an integer, , complete the function so that it finds the lexicographically smallest and largest substrings of length .
Input Format
The first line contains a string denoting .
The second line contains an integer denoting .
Constraints
consists of English alphabetic letters only (i.e., [a-zA-Z]).
Output Format
Return the respective lexicographically smallest and largest substrings as a single newline-separated string.
Sample Input 0
welcometojava
3
Sample Output 0
ava
wel
Explanation 0
String has the following lexicographically-ordered substrings of length :
We then return the first (lexicographically smallest) substring and the last (lexicographically largest) substring as two newline-separated values (i.e., ava\nwel).
The stub code in the editor then prints ava as our first line of output and wel as our second line of output.
Solution:-
import java.util.Scanner;
public class Solution {
public static String getSmallestAndLargest(String s, int k) {
String smallest = "";
String largest = "";
smallest = largest = s.substring(0, k);
for (int i=1; i
String substr = s.substring(i, i+k);
if (smallest.compareTo(substr) > 0)
smallest = substr;
if (largest.compareTo(substr) < 0)
largest = substr;
}
return smallest + "\n" + largest;
}
public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
String s = scan.next();
int k = scan.nextInt();
scan.close();
System.out.println(getSmallestAndLargest(s, k));
}
}
Answers
Answer:
Here is the JAVA program:
import java.util.*;
public class Solution { // class name
public static String getSmallestAndLargest(String s, int k) { //method that takes a string s and and integer k and returns lexicographically smallest and largest substrings
String smallest = ""; //stores the smallest substring
String largest = ""; //stores the largest substring
smallest = largest = s.substring(0, k); //sets the smallest and largest to substring from 0-th start index and k-th end index of string s
for(int i = 0;i<=s.length()-k;i++){ //iterates through the string s till length()-k
String subString = s.substring(i,i+k); //stores the substring of string s from ith index to i+k th index
if(i == 0){ //if i is equal to 0
smallest = subString; } //assigns subString to smallest
if(subString.compareTo(largest)>0){ //checks if the subString is lexicographically greater than largest
largest = subString; //sets subString to largest
}else if(subString.compareTo(smallest)<0) //checks if the subString is lexicographically less than smallest
smallest = subString; } //sets subString to smallest
return smallest + "\n" + largest; } //returns the lexicographically smallest and largest substrings
public static void main(String[] args) { //start of main method
Scanner scan = new Scanner(System.in); //creates Scanner object
String s = scan.next(); //scans and reads input string from user
int k = scan.nextInt(); //scans and reads integer k from user
scan.close();
System.out.println(getSmallestAndLargest(s, k)); } } //calls method by passing string s and integer k to it to display lexicographically smallest and lexicographically largest substring
Explanation:
The program takes a string s and an integer k and passes them to function getSmallestAndLargest that returns the lexicographically smallest and lexicographically largest substring. The method works as follows:
Lets say s = helloworld and k = 3
smallest = largest = s.substring(0, k);
s.substring(0, k); is returns the substring from 0th index to k-th index so it gives substring hel
for(int i = 0;i<=s.length()-k;i++) This loop iterates through the string s till s.length()-k times
s.length()-k is equal to 7 in this example
At first iteration:
i = 0
i<=s.length()-k is true so program enters the body of loop
String subString = s.substring(i,i+k); this becomes:
subString = s.substring(0,3);
subString = "hel"
if(i == 0) this is true so:
smallest = subString;
smallest = "hel"
At second iteration:
i = 1
i<=s.length()-k is true so program enters the body of loop
String subString = s.substring(i,i+k); this becomes:
subString = s.substring(1,4);
subString = "ell"
if(subString.compareTo(smallest)<0) this condition is true because the subString ell is compared to smallest hel and it is lexographically less than smallest so :
smallest = subString;
smallest = "ell"
So at each iteration 3 characters of string s are taken and if and else if condition checks if these characters are lexicographically equal, smaller or larger and the values of largest and smallest change accordingly
After the loop ends the statement return smallest + "\n" + largest; executes which returns the smallest and largest substrings. So the output of the entire program with given example is:
ell wor
Here ell is the lexicographically smallest substring and wor is lexicographically largest substring in the string helloworld
The screenshot of the program along with its output is attached.
Wireless technology is best described as a/an
stationary computing system.
office computing system.
mobile computing system.
inflexible computing system.
Answers
Answer:
mobile computing system
Explanation:
Answer:
mobile computing system... C
What is the maximum number of VLANs that can be configured on a switch supporting the 802.1Q protocol? Why?
Answers
Answer:
4096 VLANs
Explanation:
A VLAN (virtual LAN) is a group of devices on one or more LAN connected to each other without physical connections. VLANs help reduce collisions.
An 802.1Q Ethernet frame header has VLAN ID of 12 bit VLAN field. Hence the maximum number of possible VLAN ID is 4096 (2¹²). This means that a switch supporting the 802.1Q protocol can have a maximum of 4096 VLANs
A lot of VLANs ID are supported by a switch. The maximum number of VLANs that can be configured on a switch supporting the 802.1Q protocol is 4,094 VLANS.
All the VLAN needs an ID that is given by the VID field as stated in the IEEE 802.1Q specification. The VID field is known to be of 12 bits giving a total of 4,096 combinations.But that of 0x000 and 0xFFF are set apart. This therefore makes or leaves it as 4,094 possible VLANS limits. Under IEEE 802.1Q, the maximum number of VLANs that is found on an Ethernet network is 4,094.
Learn more about VLANs from
https://brainly.com/question/25867685
7. While an adjacency matrix is typically easier to code than an adjacency list, it is not always a better solution. Explain when an adjacency list is a clear winner in the efficiency of your algorithm
Answers
Answer:
The answer is below
Explanation:
Adjacency list is a technique in a computer science that is used for representing graph. It deals with a gathering of unorganized lists utilized to illustrate a limited graph. In this method, each list depicts the group of data of a peak in the graph
Adjacency List are most preferred to Adjacency Matrix in some cases which are:
1. When the graph to is required to be sparsely.
2. For iterability, Adjacent List is more preferable
Which is an example of an operating system
a
Adobe Photoshop
b
Internet Explorer
c
Windows
d
Microsoft Word
Answers
Answer:
windows
Explanation:
Examples of Operating Systems
Some examples include versions of Microsoft Windows (like Windows 10, Windows 8, Windows 7, Windows Vista, and Windows XP), Apple's macOS (formerly OS X), Chrome OS, BlackBerry Tablet OS, and flavors of Linux, an open-source operating system.
What is his resolution amount
Answers
Return to the Product Mix worksheet. Benicio wants to provide a visual way to compare the scenarios. Use the Scenario Manager as follows to create a PivotTable that compares the profit per unit in each scenario as follows:
a. Create a Scenario PivotTable report using the profit per unit sold (range B17:F17) as the result cells.
b. Remove the Filter field from the PivotTable.
c. Change the number format of the value fields to Currency with 2 decimal places and the $ symbol.
Answers
Answer:
To create a pivot table, select the columns to pivot and click on the insert option, click on the pivot table option and select the data columns for the pivot, verify the table range, select the location for the pivot and click ok. To format a column, select the columns and click the number option on the home tab, select the currency option and click on the number of decimal places
Explanation:
Microsoft Excel is a great tool for data analysis and visualization. It has several mathematical, engineering, statistical, and graphical tools for working with data.
A pivot-table is an essential tool for describing and comparing data of different types.
The steps to follow in order to produce a Pivot table would be as mentioned below:
Opting the columns for a pivot table. Now, make a click on the insert option. This click is followed by opting for the pivot table and the data columns that are available in it.After this, the verification of the range of the table is made and then, the location for the pivot table has opted. After this, the column is formatted and the number option is selected followed by the currency option, and the quantity of decimal places. A Pivot table allows one to establish a comparison between data of distinct categories(graphic, statistical, mathematical) and elaborate them.Learn more about 'Pivot Table' here:
brainly.com/question/13298479
The code below is supposed to display the name and score for the student with the highest score one time before the program ends. It is displaying Jim as the student with the highest score. It is displaying the highest score of 95. Unfortunately, Jim does not have a score of 95. Correct the following code:
Declare String students[SIZES] = {"Jen", "Jon", "Jan", "Joe", "Jim"}
Declare Integer scores[SIZES] = 70, 85, 72, 95, 90
Declare Integer index Declare Integer highest = scores[0]
Declare Integer highest Name = " " For index = 0
To SIZES //Assume that this translates to For (index = 0; index <= SIZES, index ++)
If scores[index] > highest then highest = scores[index]
End Of highestName = students[index]
End For Display "
The name of the student with the highest score is ", highest Name Display "The highest score is ", highest
Answers
Answer:
Modify
If scores[index] > highest then highest = scores[index]
End Of highest
Name = students[index]
End For Display
to
If scores[index] > highest then highest = scores[index]
Name = students[index]
End Of highest
End For Display
Explanation:
In the code, you posted the code segment that gets the name of the student with the highest score is outside the if condition that determines the highest.
To make correction, we only need to bring this code segment into the loop.
See Answer
1. When you write HTML code, you use ______ to describe the structure of information on a webpage. a. a web address b. tags c. styles d. links
Answers
Answer:
b. tags
Explanation:
When you write HTML code, you use tags to describe the structure of information on a webpage. These tags are represented by the following symbols <>. All of HTML is written using different types of tags such as <body>, <main>, <div>, <nav>, etc. Each of these serves a different purpose but are all used for structuring the specific information on a website so that the information is well organized and is not all on top of each other. This also allows for specific sections to be easily targeted and styles separately from the other sections.
Online Privacy
1.)Explain why is online privacy a controversial topic?
2.)Explain why this issue is applicable to you and your peers.
3.)Explain why this issue is a federal issue and not a state or local issue.
Answers
Answer:
Yes
Explanation:
Online privacy is a controversial topic due to the fact that it's a very hard thing to navigate. Some websites use cookies that are used to store your data so in a way there taking your privacy away which is controversial because of the way they use the information. Some websites store it for use of ads while others sell it. This issue is applicable to me and my peers because of the way we use technology. It can be used to steal my information about where I live and what I look up online. Also, the information stored could have my credit or debit card credentials. This issue should be a federal and nationwide issue because this is an everyday occurrence and leaves tons of people in crushing debt every year.
explain how to use the information in an outline to start writing a business document
Answers
Answer: document
Explanation:
Which feature of a database allows a user to locate a specific record using keywords?
Chart
Filter
Search
Sort
Answers
Answer:
Search
Explanation:
Because you are searching up a specific recording using keywords.
I hope this helps
Answer:
Filter
Explanation:
I got it correct for a quiz.
If the propagation delay through a full-adder (FA) is 150 nsec, what is the total propagation delay in nsec of an 8-bit ripple-carry adder
Answers
Answer:
270 nsec
Explanation:
Ripple-carry adder is a combination of multiple full-adders. It is relatively slow as each full-adder waits for the output of a previous full-adder for its input.
Formula to calculate the delay of a ripple-carry adder is;
= 2( n + 1 ) x D
delay in a full-adder = 150 nsec.
number of full-adders = number of ripple-carry bits = 8
= 2 ( 8 + 1 ) x 150
= 18 x 150
= 270 nsec
A _____ is a smaller image of a slide.
template
toolbar
thumbnail
pane
Answers
The __________ list is intended to facilitate the development of the leading free network exploration tool.
Answers
Answer:
Nmap development list
Explanation:
The list being mentioned in this question is known as the Nmap development list. This list basically acts as an information gathering and analytical tool. It allows the user to easily roll out and integrate Nmap tools on a network in order to easily detect all of the IP addresses that are connected as well as analyze all of the details regarding each connected individual system. All of this information is highly valuable to a developer and facilitates the development process.
Explaim Why the shape of a cell is hexagonal
Answers
B1:B4 is a search table or a lookup value
Answers
Answer:
lookup value
Explanation:
Write the three working fundamental steps of a computer.
Answers
Answer:
just tryin' to help you
Explanation:
The three stages of computing are input, processing and output. A computer works through these stages by 'running' a program. A program is a set of step-by-step instructions which tells the computer exactly what to do with input in order to produce the required output.
Plz answer me will mark as brainliest
Answers
Answer:
Application
Explanation:
Application software comes in many forms like apps, and even on computers. The software is most common on computers of all kinds while mobile applications are most common on cellular devices.