You are standing on a dock that is 8 feet above the surface of a lake. You jump in the lake and touch the bottom, which is 10 feet below the surface of the water. What is the total distance that you have traveled?

Answer:

A Monomial

A single term algebraic expression is called:

Constant term

Step-by-step explanation:

A term of an algebraic expression that has a fixed numerical value in all situations and does not have any variable is called the constant term of an algebraic expression.

Example:
The algebraic expression 5x + 2y + xy + 10, 10 is the constant term of the expression.


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Single term algebraic expression is called ''Monomial''.

The monomial is a product of powers of variable with non negative integer exponent. It is the algebraic expression with single term.

Given that;

Single term in algebraic expression.

Now,

Since, We know that;

The algebraic expression with single term is called ''Monomial''.

And, The algebraic expression with double term is called ''Binomial''.

Thus, Single term algebraic expression is called ''Monomial''.

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[tex]\\ \sf\longmapsto \dfrac{BQ}{DQ}=\dfrac{RC}{CD}[/tex]

[tex]\\ \sf\longmapsto \dfrac{26}{39}=\dfrac{18}{x}[/tex]

[tex]\\ \sf\longmapsto \dfrac{2}{3}=\dfrac{18}{x}[/tex]

[tex]\\ \sf\longmapsto 2x=54[/tex]

[tex]\\ \sf\longmapsto x=27[/tex]

Answer:

18

Step-by-step explanation:

Last month the amount of rain that fell each day varied about the same as the month before is the right statement about the rainfall, Option c is correct.

The average distance between each data point and the mean is the mean absolute deviation of a dataset. It offers us an indication of how variable a dataset is.

The  given data in the problem is;

Two months ago,

The mean daily rainfall in a local city was 9. 4 cm.

The mean absolute deviation was 3. 5 cm

Last month

The mean daily rainfall in that city was 11. 5 cm

The mean absolute deviation was 1. 6 cm.

We can see that there was less variation last month than the month before since the mean absolute deviation is a measure of variance.

Hence Last month the amount of rain that fell each day varied about the same as the month before is the right statement about the rainfall, Option c is correct.

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Answer:13/15

Step-by-step explanation:

Add 7/9 and 2/3 the answer is 13/9 then divide it by 5/3 in order for you to divide get the reciprocal of 5/3 which is 3/5 then multiply it and you well get 13/15

Answer:

13/15

Step-by-step explanation:

The answer is 13/15 because:

1) In order to figure out what 7/9 + 2/3 is, we need to find the common denominator. The common denominator is 9 because 3 contains the factor 9.

7/9 + 6/9 = 13/9

We need to multiply the denominator to get to 9: 3 x 3 = 9. We have to multiply the numerator as well: 2 x 3 = 6.

2) Next, we have to divide 13/9 and 5/3. In order to divide we have to find the reciprocal of the second number. Reciprocal means to flip the fraction. The reciprocal of 5/3 is 3/5.

3) Finally, we just have to multiply 13/9 and 3/5 which is 39/45. 39/45 in simplest form is 13/15.

Hope this helps! :D

you're answer would be number 3

Answer:

m<TQS=23

Step-by-step explanation:

(3x-5)+(x+1)

4x-4=180

   +      +

4x=184

---    ----

4       4

x= 46

46/2

=23

If a ray QT bisects <RQS, then [tex]m<TQS=23.5[/tex] °

Given :

a ray QT bisects <RQS

<PQR and <RQS is a linear pair . It makes and angle 180 degree

[tex]m<PQR+m<RQS=180[/tex]

From the diagram,

m<PQR=3x-5, and m<RQS=x+1

Substitute the expression and solve for x

[tex]m<PQR+m<RQS=180\\3x-5+x+1=180\\4x-4=180\\4x=180+4\\4x=184\\Divide \; by \; 4\\x=46[/tex]

now ,  [tex]m<RQS = x+1 =46+1=47[/tex]

Given  QT bisects <RQS. it means QT divides RQS equally

[tex]m<TQS= \frac{m<RQS}{2} \\m<TQS= \frac{47}{2} \\\\m<TQS=23.5[/tex]

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Answer:A

Step-by-step explanation:

270/630 x 100= 43

answer: A

Step-by-step explanation:

270/630x100 =45

Answer:

1.) 78

2.) 162

Step-by-step explanation:

you just multiply the number outside of the parentheses by the one inside them lol

Answer:

A

[tex]\boxed{a=\frac{9}{2}}}[/tex]

[tex]\boxed{b=\frac{15}{2}}[/tex]

Step-by-step explanation:

By ratio and proportion

Let's solve for "a" first:-

[tex]\cfrac{a}{6} =\cfrac{6}{8}[/tex]

[tex]8a=36[/tex]

[tex]\cfrac{8a}{8}=\cfrac{36}{8}[/tex]

[tex]\boxed{a=\frac{9}{2}}}[/tex]

Now, Let's solve for "b":-

[tex]\cfrac{b}{6} =\cfrac{10}{8}[/tex]

[tex]8b=60[/tex]

[tex]\cfrac{8b}{8}=\cfrac{60}{8}[/tex]

[tex]\boxed{b=\frac{15}{2}}[/tex]

Therefore, your answer is A!!!!

~

Answer:

-16

Step-by-step explanation:

(n+1) 2 n=-9

Step 1 Plug in -9 for n:    (-9+1)x 2

Step 2 Add -9 and 1:      -8x2

Step 3 Multiply -8 and 2:  -16

Answer:b

Step-by-step explanation:

Answer:  Stephano's marble will reach the mark sooner.

Answer:

I think its $1,500

Step-by-step explanation:

6 times 750 = 4,500

4,500- 3,000= 1,500

Calculate the area of the floor:

Area = 1.6 x 2.3 = 3.68 square meters

Using the given formula: Pressure = force/area

200 = force / 3.68

Solve for force by multiplying both sides by 3.68

Force = 200 x 3.68

Force = 736 N/m^2

Correct to the nearest 5N/m^2 = 735 N/m^2

First of all we need to calculate the area of the floor and then we will find the pressure using the formula for pressure...

[tex]\red{ \rule{35pt}{2pt}} \orange{ \rule{35pt}{2pt}} \color{yellow}{ \rule{35pt} {2pt}} \green{ \rule{35pt} {2pt}} \blue{ \rule{35pt} {2pt}} \purple{ \rule{35pt} {2pt}}[/tex]

Area of floor ↯

[tex] \sf \: area = length \times breadth[/tex]

[tex] \sf \: area = 1.6 \times 2.3[/tex]

[tex] \sf \: area = 3.68 \: {m}^{2} [/tex]

[tex]\purple{ \rule{300pt}{3pt}}[/tex]

Finding force ↯

[tex] \tt \: pressure = \frac{force}{area} [/tex]

[tex] \tt \: 200 = \frac{force}{3.68} [/tex]

[tex] \tt \: force = 200 \times 3.68[/tex]

[tex] \tt \: force = 736 \: newton[/tex]

Thus, The maximum force is 736 Newton...~

Answer:

Your answer is: A) k = -3

Step-by-step explanation:

Hope this helped : )

Let's solve for x

9(2x+1) < 9x - 18

18x+9 < 9x-18

18x-9x < -18-9

9x < -27

x < -27/9

x < -3

Any value smaller than -3 is in the solution set

That means we have {-4, -5, -6, ...} as our solution set if x was only allowed to be an integer.

We can rule out choices B through D because of this. Only choice A remains, which I'm assuming you meant to say -4 instead of simply 4. If choice A says -4, then this is the answer.

If it doesn't say -4, then that isn't the answer and none of the answer choices work.

Note: if your original inequality is [tex]9(2x+1) \le 9x-18[/tex] then it solves to [tex]x \le -3[/tex] allowing x = -3 to be part of the solution set now. If you have an "or equal to" then that means B) -3 is the answer.

It seems like there might be a typo somewhere so I would double check.

Answer:

5894

Step-by-step explanation:

1  mile is 1760

so multiply 1760 by 3.4

Answer:

21

Step-by-step explanation:

30 - 9 +3

30 - 12

18

18 - 12=4

      12/4 = -3

18 - -3

21

the answer is 21

30 - 9 = 21
21 + 3 = 24
12 divided by 4 = 3
24 - 3 = 21


21 is the answer once again

The point (5, 290) denoted that the jaguar has run a distance of 290 feet in 5 seconds.

Jaguar speed is 58 feet per second.

The coordinates in a graph indicate the location of a point with respect to the x-axis and y-axis.

The coordinates in a graph show the relationship between the information plotted on the given x-axis and y-axis.

We have,

Each point on the graph denotes the speed of the jaguar.

Point (5, 290) denotes that in 5 seconds the jaguar has run 290 feet.

The speed of the jaguar.

= Distance / Time

= 290/5

= 58 feet

Thus,

The speed of the jaguar is 58 feet per second.

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Answer:

41 minutes

Step-by-step explanation:

it is 41 minutes

Answer:

(a)  [tex]\theta=\tan^{-1}(-0.890)[/tex]

[tex]\implies \theta=-41.66908262 \pm 180 \textdegree n[/tex]

[tex]\implies \theta=138.3309174..., 318.3309174...[/tex]

[tex]\implies \theta=138\textdegree, 318\textdegree[/tex]

(b)  [tex]\theta=\cos^{-1}\left(\dfrac{\sqrt{3} }{2}\right)[/tex]

[tex]\implies \theta=30 \textdegree \pm360 \textdegree n, 330 \textdegree \pm360 \textdegree n[/tex]

[tex]\implies \theta=30 \textdegree , 330 \textdegree[/tex]

(c)  [tex]\theta=\sin^{-1}\left(\dfrac{1 }{2}\right)[/tex]

[tex]\implies \theta=30 \textdegree \pm360 \textdegree n, 150 \textdegree \pm360 \textdegree n[/tex]

[tex]\implies \theta=30 \textdegree , 150 \textdegree[/tex]

Answer:

192m

Step-by-step explanation:

6m x 4m x 8m = 192m

50% of 60 minutes is 30 minutes

0.50 * 60 = 30

10% of 60 minutes is 6 minutes

0.10 * 60 = 6

75% of 60 minutes is 45 minutes

0.75 * 60 = 45

the order is, 65% of 80, 170% of 30, 82% of 50

0.65 * 80 = 52

0.82 * 50 = 41

1.70 * 30 = 51

200,000 * 0.01x = 130,000

130,000/200,000 = 0.65

0.65/0.01 = 65

the plane used 65% of fuel capacity on this flight

Answer:

Step-by-step explanation:

1) 50% of 60 minutes is 30 minutes

2) 10% of 60 minutes is 6 minutes

3) 75% of 60 minutes is 45 minutes

4) 52%

5) 41%

6)51%

FINAL QUESTION:

260,000,000 fuel used

Answer:

x>2

Step-by-step explanation:

2x-3+x>x+1

3x-3>x+1

2x>4

x>2

Answer:  x = 5

Step-by-step explanation:

(3x + 22) and (3x + 128) are supplementary angles, which means that they add up to 180, so we can write our equation.

(3x + 22) + (3x + 128) = 180

   3x + 22 + 3x + 128 = 180

                   6x + 150 = 180

                             6x = 30

                                x = 5

Answer:

You would start your graph at (1,7.5) (2, 15) (3, 22.5) (4, 30) (5, 37.5)  

Step-by-step explanation:

What you do is for every hour you add 7.50. I don' know how many hours you need to graph so I just gave you the first five, But you should start to see a pattern, just continue with the pattern and you will get it right! Hope this helps!

Answer:

[tex]y\leq \dfrac12x+3[/tex]

Step-by-step explanation:

Choose 2 points on the line:  (-6, 0) and (0, 3)

[tex]\sf slope=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{0-3}{-6-0}=\dfrac12[/tex]

point-slope form of linear equation:  [tex]\sf y-y_1=m(x-x_1)[/tex]

[tex]\implies \sf y-0=\dfrac12(x-(-6))[/tex]

[tex]\implies \sf y=\dfrac12x+3[/tex]

Solid line : ≤ or ≥

Dashed line: < or >

Therefore as the line is solid, and the shading is below the line,

[tex]\implies \sf y\leq \dfrac12x+3[/tex]

Slope:-

[tex]\\ \tt\Rrightarrow m=\dfrac{4-3}{2}=1/2[/tex]

Equation of line in point slope form

[tex]\\ \tt\Rrightarrow y-3=1/2x[/tex]

[tex]\\ \tt\Rrightarrow y=1/2x+3[/tex]

Equation of shaded region

[tex]\\ \tt\Rrightarrow y\leqslant 1/2x+3[/tex]

Answer: 50 right?

Step-by-step explanation:

Answer:

30 plus 20

Step-by-step explanation:

or 15 35

25 25

or 0 59