You are going to make 5 assemblies, where each assembly requires the use of 1 Type A Bolt. You have a container of bolts that consists of 20 Type A bolts, 20 Type B bolts, and 20 Type C bolts. At random, you take 10 bolts out of the container. Determine: A) The probability you took the exact number of Type A bolts you need for your 5 assemblies. B) The probability you did not take enough Type A bolts that you need for your 5 assemblies. C) The probability you took more Type A bolts than you need for your 5 assemblies.

Answers

Answer 1

Answer:

Step-by-step explanation:

You are to make 5 assemblies.

Each assembly requires the use of 1 Type A bolt.

To make the 5 assemblies, you need 5 Type A bolts.

The container of bolts has a total of 60 bolts.

The focus - Type A bolts - is 20 out of this 60.

The probability of obtaining a Type A bolt at all, is 20/60, which is = 1/3

(A) What is the probability of taking the exact number of Type A bolts you need for your 5 assemblies, if you randomly take 10 bolts from the container?

- The exact number of Type A bolts you need for the 5 assemblies is 5

1/3 × 5/10 =  5/30 =  1/6 =  0.167

(B) What is the probability of taking/having less than 5 Type A bolts out of the randomly selected 10 bolts? The solution is to sum up the following:

1/3 × 4/10 = 0.133

1/3 × 3/10 = 0.1

1/3 × 2/10 = 0.067

1/3 × 1/10 = 0.033

1/3 × 0/10 = 0

TOTAL = 0.333


Related Questions

Simplify
4a + 5b – 3b + a
2 marks)

Answers

Answer:

5a+2b

Step-by-step explanation:

4a + 5b – 3b + a

Combine like terms

4a +a  + 5b-3b

5a+2b

Hi! You need to combine the like terms, find the A’s and b’s.
Answer =5a+2b.

multiply fraction 7×2 1/2​

Answers

[tex]\frac{35}{2} \: or \: 17 \frac{1}{2} [/tex]

Step-by-step explanation:

[tex]7 \times 2 \frac{1}{2} [/tex]

Convert mixed number to fraction

[tex]2 \frac{1}{2} = \frac{5}{2} \\ \\ 7 \times \frac{5}{2} [/tex]

Simplify

[tex] \frac{7}{1} \times \frac{5}{2} = \frac{35}{2} [/tex]

Convert to mixed number

[tex]17 \frac{1}{2} [/tex]

construction company builds an average of 48 houses per year. How many houses per month does the company build?

Answers

Answer:

48 per year would be 4 houses a month

Step-by-step explanation:

4 * 12 = 48

Which point on the graph represents the y-intercept?
у
5
V
4
N 03
W
>
1
1
N
-5 4 -3 -2 -14
1 2 3 4
12
4
25

Answers

Take a picture of the assignment and post it in your question.

Answer:

a

Step-by-step explanation:

did it on edge 2020

Help please.... I have got this wrong 2xs only once chance left

Answers

Answer:

a: 5x-1 = -6

b: 5x-1 = -6

        +1   +1

5x = -5

divide

x = -1

Please help!! i cant fail math

Answers

Answer:

The scale factor is 2

Step-by-step explanation:

During a thunderstorm​ yesterday, 600 millimeters of rain fell in 30 minutes. What is the unit rate for millimeters per​ minute?

Answers

9514 1404 393

Answer:

  20 mm/min

Step-by-step explanation:

To find the rate in mm per minute, divide mm by minutes:

  (600 mm)/(30 min) = 20 mm/min . . . unit rate

During one waiter's shift, he delivered 13 appetizers, 17 entrees, and 10 desserts. What percentage of the dishes he delivered were:
A. desserts?



B. appetizers?



C. entrees?

Answers

Answer:

deserts are 32.5%

appetizers are 42.5%

deserts are 25%

Step-by-step explanation:

let me know if i helped

My wifi is acting up so I’m just gonna comment so I remember to answer this bc I’m trying to solve it but I have something to do

For what values of the variable does each of the following expressions make sense? We call the set of this values the domain of the expression. \sqrt{4-6a}

Answers

Given:

The expression is [tex]\sqrt{4-6a}[/tex].

To find:

The domain of the expression.

Solution:

We have,

[tex]\sqrt{4-6a}[/tex]

We know that, the square root is defined for only non-negative values. So,

[tex]4-6a\geq 0[/tex]

[tex]4\geq 6a[/tex]

Divide both sides by 6.

[tex]\dfrac{4}{6}\geq a[/tex]

[tex]\dfrac{2}{3}\geq a[/tex]

Thus, the value of variable less than [tex]\dfrac{2}{3}[/tex] make any sense.

Therefore, the domain of the given expression is [tex](-\infty,\dfrac{2}{3}][/tex].

The domain of a function is the set of input values the function can take

The domain of the expression is: [tex]\mathbf{(-\infty, \frac 23]}[/tex]

The expression is given as:

[tex]\mathbf{\sqrt{4 - 6a}}[/tex]

Set the radicand to 0

[tex]\mathbf{4 - 6a = 0}[/tex]

Add 6a to both sides

[tex]\mathbf{6a = 4}[/tex]

Divide both sides by 6

[tex]\mathbf{a = \frac 23}[/tex]

This means that, the value of a must not be greater than 2/3.

Hence, the domain of the expression is: [tex]\mathbf{(-\infty, \frac 23]}[/tex]

Read more about domain at:

https://brainly.com/question/1632425

[tex]\frac{x}{5}[/tex] + 7 = -3

Answers

Answer:

[tex]\huge{\fbox{\sf{ x = -50}}}[/tex]

Step-by-step explanation:

[tex]\frac{x}{5} + 7 = -3[/tex]

Take the L.C.M of 5 and 1 ( i.e 5 )

⇒[tex]\frac{x+7 * 5}{5} = -3[/tex]

⇒[tex]\frac{x+35}{5} = -3[/tex]

Do cross multiplication

⇒[tex]x + 35 = -3 * 5[/tex]

⇒[tex]x + 35 = -15[/tex]

Move 35 to right hand side and change its sign

⇒[tex]x = -15 - 35[/tex]

Remember : The negative integers are always added but posses the negative ( - ) sign.

⇒[tex]x = -50[/tex]

The value of x is [tex]\boxed{\sf{ -50}}[/tex]

Hope I helped!

Best regards!

~[tex]\text{ TheAnimeGirl}[/tex]

Here's a linear equation in variable x and we have to compute the value of x for the above equation.

Given equation:

[tex] \large{ \rm{ \dfrac{x}{5} + 7 = - 3}}[/tex]

So, Let's start solving the above equation:

Move 7 to the Right hand side,

Remember: Inverse of addition is subtraction

[tex] \sf{ \dfrac{x}{5} = - 3 - 7}[/tex]

[tex] \sf{ \dfrac{x}{5} = - 10}[/tex]

Now multiplying 5 in other side because again the inverse of division is multiplication,

[tex] \sf{ x = - 10 \times 5}[/tex]

[tex] \sf{x = \boxed{ \red{ - 50}}}[/tex]

And the required value for x is -50. So, we are done....

Carry On Learning !

Consider the line y=-1/2x+8
What is the slope of a line parallel to this line?
What is the slope of a ine perpendicular to this line?

Answers

Given parameters:

Equation of the line is y = -[tex]\frac{1}{2} x[/tex] + 8

Unknown:

Slope of line parallel to this line = ?

Slope of line perpendicular = ?

Solution:

A line parallel to this line will have the same slope with it.

A line perpendicular will have the negative inverse of this slope;

Slope of line  = - [tex]\frac{1}{2}[/tex]

Slope of line parallel to this line = [tex]-\frac{1}{2}[/tex]

Slope of line perpendicular = negative inverse = -( -([tex]\frac{1}{\frac{1}{2} }[/tex]))   = 2

So, the slope of line parallel to this line is - 1/2 and that perpendicular is 2

5 times a number is 6 less than the square of that number

Answers

Answer:

5x = x^2 - 6

Step-by-step explanation:

a number can be represented by x,

5 times a number can be represented as the product of 5 and x, 6 less than the square of that number tells us that this is equal to a number squared minus 6. is tells us that these two expressions are equal.

If you want a working number, just solve by completing the square once this is in standard form. This is then converted to vertex form.

x^2-5x-6 = (x-5/2)^2-49/4 = (x^2-5x+25/4) -49/4 = x^2-5x-6.

(x-5/2)^2-49/4=0

(x-5/2)^2=49/4

(x-5/2) = ±√49/4

(x-5/2) = ±7/2

x=5/2±7/2

x=(5±7)/2

x=12/2,-2/2

x=6,-1

Thus, the number can either be 6 or -1.

WHAT IS THE AVERAGE OF -2.5, 5.2, 1.7, -0.8?

Answers

The average is 0.9

-2.5 + 5.2 + 1.7 + (-0.8) = 3.6

3.6 / 4 = 0.9

Answer:

0.9

Step-by-step explanation:

-2.5 + 5.2 + 1.7 + -0.8 = 3.6

3.6 / 4 = 0.9

Suppose that when a fabric production process is in control, the number of flaws in a piece of fabric of length l yards has a Poisson distribution with mean (.02)l. Suppose that periodically a length of fabric of 10 yards is inspected and the flaws are counted. If there are too many flaws, say more than k, the process will be presumed to be out of control, and stopped, and fixed. What should k be such that the probability of stopping the process when it is really in control is at most 5%

Answers

Answer:

Answer is attached below

Step-by-step explanation:

A length of fabric sampled = 10 yards

number of flaws in a piece of fabric having  length = l yards

Poisson distribution mean = 0.02l

If the flaws are > k  = process out of control hence would be stopped and fixed

Calculate The value of  K  such that the probability of stopping the process when it is really in control is at most 5%

using Poisson distribution

attached below is the detailed solution

the function f(x)=-4x+9 has a range given by {1, -3, -7, -15, -19, -23} select the domain values of the function from the list. complete the explanation for how you arrived at your answer. btw this isn’t actually a test it’s assigned as hw but please help

Answers

Let's see what to do buddy....

_________________________________

Remember from now on ,

rang = output

and also Remember ,

output = y = f(x)

So : range = f(x)

So we must put the range number instead of f(x) and solve for x.

Let's do it...

=======================================

[tex]f(x) = 1[/tex]

[tex] - 4x + 9 = 1[/tex]

Both sides minus 9

[tex] - 4x = 1 - 9[/tex]

[tex] - 4x = - 8[/tex]

Negatives simplified

[tex]4x = 8[/tex]

Divided both sides by 4

[tex]x = \frac{8}{4} \\ [/tex]

[tex]x = 2[/tex]

_________________________________

[tex]f(x) = - 3[/tex]

[tex] - 4x + 9 = - 3[/tex]

[tex] - 4x = - 3 - 9[/tex]

[tex] - 4x = - 12[/tex]

[tex]4x = 12[/tex]

[tex]x = \frac{12}{4} \\ [/tex]

[tex]x = 3[/tex]

_________________________________

[tex]f(x) = - 7[/tex]

[tex] - 4x + 9 = - 7[/tex]

[tex] - 4x = - 7 - 9[/tex]

[tex] - 4x = - 16[/tex]

[tex]4x = 16[/tex]

[tex]x = \frac{16}{4} \\ [/tex]

[tex]x = 4[/tex]

_________________________________

[tex]f(x) = - 15[/tex]

[tex] - 4x + 9 = - 15[/tex]

[tex] - 4x = - 15 - 9[/tex]

[tex] - 4x = - 24[/tex]

[tex]4x = 24[/tex]

[tex]x = \frac{24}{4} \\ [/tex]

[tex]x = 6[/tex]

_________________________________

[tex]f(x) = - 19[/tex]

[tex] - 4x + 9 = - 19[/tex]

[tex] - 4x = - 19 - 9[/tex]

[tex] - 4x = - 28[/tex]

[tex]4x = 28[/tex]

[tex]x = \frac{28}{4} \\ [/tex]

[tex]x = 7[/tex]

_________________________________

[tex]f(x) = - 23[/tex]

[tex] - 4x + 9 = - 23[/tex]

[tex] - 4x = - 23 - 9[/tex]

[tex] - 4x = - 32[/tex]

[tex]4x = 32[/tex]

[tex]x = \frac{32}{4} \\ [/tex]

[tex]x = 8[/tex]

=======================================

So the domain values are :

x = { 2 , 3 , 4 , 6 , 7 , 8 }

_________________________________

And we're done.

Thanks for watching buddy good luck.

♥️♥️♥️♥️♥️

PLEASE PLEASE HELP WILL MARK BRAINLIEST
Find the equation of the line in slope-intercept form through (−5, 6) with slope = 3

Answers

Answer:

The answer is

[tex] \huge y = 3x + 21[/tex]

Step-by-step explanation:

To find an equation of a line given the slope and a point we use the formula

[tex]y - y_1 = m(x - x_1)[/tex]

where

m is the slope

( x1 , y1) is the point

From the question the point is (−5, 6) and slope = 3

The equation of the line is

[tex]y - 6 = 3(x + 5) \\ y - 6 = 3x + 15 \\ y = 3x + 15 + 6[/tex]

We have the final answer as

[tex]y = 3x + 21[/tex]

Hope this helps you

Answer:

The answer is y=3x+21

Step-by-step explanation:

You hire 2 students to deliver takeout menus around town. One student (Darla), delivers 350 menus in 2 hours, and another student (Drew, delivers 510 in 3 hours. Who works the faster?​

Answers

Darla is faster she gets more done in less time yes drew has a higher total but he worked a extra hour

Darla is faster because she gets more done in less time

wwe.iw What is the square root of -1? Oi O1 O1​

Answers

Answer:

i (imaginary number)

Step-by-step explanation:

[tex] \sqrt{ - 1} = i(imaginary \: number)[/tex]

help and explain if you can please ​

Answers

Hope this helps please give brainliest

Please answer I need help thank you

Answers

Answer:

what is the question

Step-by-step explanation:

which statement is true about the transformation

Answers

Answer:

Where are the statements

Answer:

The answer is A

Step-by-step explanation:

Got this from edge

Which of the following statements is true for all sets A,B and C? Give a proof

or a counter example.


(a) A ⊆ ((A∩B)∪C).

(b) (A∪B)∩C = (A∩B)∪C.

(c) (A\B)∩C = (A∩C) \ (B∩C).

Answers

Answer:

(a) and (b) are not true in general. Refer to the explanations below for counterexamples.

It can be shown that (c) is indeed true.

Step-by-step explanation:

This explanation will use a lot of empty sets [tex]\phi[/tex] just to keep the counterexamples simple.

(a)

Note that [tex]A \cap B[/tex] can well be smaller than [tex]A[/tex]. It should be alarming that the question is claiming [tex]A\![/tex] to be a subset of something that can be smaller than [tex]\! A[/tex]. Here's a counterexample that dramatize this observation:

Consider:

[tex]A = \left\lbrace 1 \right\rbrace[/tex].[tex]B = \phi[/tex] (an empty set, same as [tex]\left\lbrace \right\rbrace[/tex].)[tex]C = \phi[/tex] (another empty set.)

The intersection of an empty set with another set should still be an empty set:

[tex]A \cap B = \left\lbrace 1\right\rbrace \cap \left\lbrace\right\rbrace = \left\lbrace\right\rbrace[/tex].

The union of two empty sets should also be an empty set:

[tex]((A \cap B) \cup C) = \left\lbrace\right\rbrace \cup \left\lbrace\right\rbrace = \left\lbrace\right\rbrace[/tex].

Apparently, the one-element set [tex]A = \left\lbrace 1 \right\rbrace[/tex] isn't a subset of an empty set. [tex]A \not \subseteq ((A\cap B) \cup C)[/tex]. Contradiction.

(b)

Consider the same counterexample

[tex]A = \left\lbrace 1 \right\rbrace[/tex].[tex]B = \phi[/tex] (an empty set, same as [tex]\left\lbrace \right\rbrace[/tex].)[tex]C = \left\lbrace 2 \right\rbrace[/tex] (another empty set.)

Left-hand side:

[tex](A \cup B) \cap C = \left(\left\lbrace 1 \right\rbrace \cup \left\lbrace \right\rbrace\right) \cap \left\lbrace 2 \right\rbrace\right = \left\lbrace 1 \right\rbrace \cap \left\lbrace 2 \right\rbrace = \left\lbrace \right\rbrace[/tex].

Right-hand side:

[tex](A \cap B) \cup C = \left(\left\lbrace 1 \right\rbrace \cap \left\lbrace \right\rbrace\right) \cup \left\lbrace 2 \right\rbrace\right = \left\lbrace \right\rbrace \cup \left\lbrace 2 \right\rbrace = \left\lbrace 2 \right\rbrace[/tex].

Apparently, the empty set on the left-hand side [tex]\left\lbrace \right\rbrace[/tex] is not the same as the [tex]\left\lbrace 2 \right\rbrace[/tex] on the right-hand side. Contradiction.

(c)

Part one: show that left-hand side is a subset of the right-hand side.

Let [tex]x[/tex] be a member of the set on the left-hand side.

[tex]x \in (A \backslash B) \cap C[/tex].

[tex]\implies x\in A \backslash B[/tex] and [tex]x \in C[/tex] (the right arrow here reads "implies".)

[tex]\implies x \in A[/tex] and [tex]x \not\in B[/tex] and [tex]x \in C[/tex].

[tex]\implies (x \in A\cap C)[/tex] and [tex]x \not\in B \cap C[/tex].

[tex]\implies x \in (A \cap C) \backslash (B \cap C)[/tex].

Note that [tex]x \in (A \backslash B) \cap C[/tex] (set on the left-hand side) implies that [tex]x \in (A \cap C) \backslash (B \cap C)[/tex] (set on the right-hand side.)

Therefore:

[tex](A \backslash B) \cap C \subseteq (A \cap C) \backslash (B \cap C)[/tex].

Part two: show that the right-hand side is a subset of the left-hand side. This part is slightly more involved than the first part.

Let [tex]x[/tex] be a member of the set on the right-hand side.

[tex]x \in (A \cap C) \backslash (B \cap C)[/tex].

[tex]\implies x \in A \cap C[/tex] and [tex]x \not\in B \cap C[/tex].

Note that [tex]x \not\in B \cap C[/tex] is equivalent to:

[tex]x \not \in B[/tex], OR[tex]x \not\in C[/tex], ORboth [tex]x \not\in B[/tex] AND [tex]x \not \in C[/tex].

However, [tex]x \in A \cap C[/tex] implies that [tex]x \in A[/tex] AND [tex]x \in C[/tex].

The fact that [tex]x \in C[/tex] means that the only possibility that [tex]x \not\in B \cap C[/tex] is [tex]x \not \in B[/tex].

To reiterate: if [tex]x \not \in C[/tex], then the assumption that [tex]x \in A \cap C[/tex] would not be true any more. Therefore, the only possibility is that [tex]x \not \in B[/tex].

Therefore, [tex]x \in (A \backslash B)\cap C[/tex].

In other words, [tex]x \in (A \cap C) \backslash (B \cap C) \implies x \in (A \backslash B)\cap C[/tex].

[tex](A \cap C) \backslash (B \cap C) \subseteq (A \backslash B)\cap C[/tex].

Combine these two parts to obtain: [tex](A \backslash B) \cap C = (A \cap C) \backslash (B \cap C)[/tex].

Give the next three terms of each Sequence.
1. 2,9,16,23,30,...
2. 49,44,39,34,29,...
3. 81,27,9,3,1,...
4. 1,4,9,16,25,...
5. 18,14,10,6,2,.....

Answers

1.) 37
2.)24
3.)1/3
4.)36
5.)-2

Hope it helps !!

what is 6.1x3 x 6.9x3.1

Answers

Answer:

391.437

Step-by-step explanation:

Answer:

391.437

Step-by-step explanation:

6.1x3=18.3

18.3x6.9=126.27

126.27x3.1=391.437

The sum of matrices A and B is C.

Answers

Answer:

Step-by-step explanation: -3

How much less than -2 is -6?​

Answers

Answer is :

-4

Step-by-step explanation:

because -2-4=-6

“CAN”
PLACE VALUE
How does the 5 in the tens place
compare to the 5 in the ones place?
3,055

Answers

The 5 in the tens place is 50 in value
The 5 in the ones place is 5 in value

Juliet wants to read more this year. So far, she has read two books for a total of 730 pages. Juliet's goal is to read 25 pages each day for the rest of the school year. Let x represent the number of days that she has followed her plan, and let y represent the total number of pages read.

Which of the following linear equations can Juliet use to model her plan and calculate the total number of pages read?


y=25−730xy is equal to 25 minus 730 x

y=730−25xy is equal to 730 minus 25 x

y=25+730xy is equal to 25 plus 730 x

y=730+25x

Answers

Answer: y= 730+25x

Step-by-step explanation:

Given: Total pages she already read = 730

Pages read by her in 1 week = 25

Let x = number of days that she has followed her plan, and let y = the total number of pages read.

Then total pages she will read in x days = 25x

therefore , Total pages she read till now(y) =730 + 25x

Hence, the linear equations can Juliet use to model her plan and calculate the total number of pages read:

y= 730+25x

A scientist measured the water pressure at different depths. She made a table showing her findings. The x-values represent the depth, in meters. The y-values represent the pressure in atmospheres (atm).

x
y
0
0
15
3
30
6

Assuming there is a proportional relationship, which additional set of values could be included in the table?
(10, 2)
(40, 9)
(50, 38)
(100, 76)

Answers

Answer:

(10, 2)

Step-by-step explanation:

I just did the quiz.

The additional set of values that could be included in the table will be ( 10, 2). the correct option is A.

What are ratios and proportions?

An ordered pair of numbers a and b, represented as a / b, is a ratio if b is not equal to 0. A proportion is an equation that sets two ratios at the same value. The numerical relationship between two values demonstrates how frequently one value contains or is contained within another.

Given table is as follows:-

x             y

0            0

15           3

30          6

Here the x-values represent the depth, in meters. The y-values represent the pressure in atmospheres (atm).

The ratio between the values x and y is 15:3 or 30:6 or 5 :1. From the given options the additional set of values that could be included in the table having the same ratio of 5:1 is ( 10, 2 ).

Therefore, the additional set of values that could be included in the table will be (10, 2). the correct option is A.

To know more about ratios and proportions follow

https://brainly.com/question/12024093

#SPJ2

pleas help me y'all please

Answers

Answer:

D

Step-by-step explanation:

in order to compare all the numbers, we have to express them all in the same form to compare them easily, we will choose to convert all of them to decimal form:

20% = 20/100 = 0.2

1/3 = 0.33333

3.4 x 10⁻¹ = 0.34

-5/2 = -2.5

comparing all these numbers, it is now clear that in decending order:

0.34 > 0.33333 > 0.2 > -2.5

or

3.4 x 10⁻¹ > 1/3 > 20% > -5/2

(Answer D)

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