You are going to factor the polynomial x^2−17x+16x, you find the product of (a)(c)and the sum of (b.) Which two factors would you choose to factor your polynomial?

Based on the sample data, there is a 95% chance that the true proportion of all smartphone users who would admit to walking into something or someone while texting on their cell phone is between 0.199 and 0.271.

A 95% confidence interval for the proportion of all smartphone users who would admit to walking into something or someone while texting on their cell phone can be calculated as follows:

Let p be the true proportion of all smartphone users who would admit to walking into something or someone while texting on their cell phone. Based on the sample of 750 respondents, the point estimate of p is 176/750 = 0.235.

Using the normal approximation to the binomial distribution, the standard error of the point estimate is estimated as [tex]\sqrt{ (p(1-p)/n)}[/tex], where n = 750. This gives us a standard error of [tex]\sqrt{(0.235 * 0.765/750)}[/tex] = 0.018.

A 95% confidence interval for the true proportion p is then given by the point estimate plus or minus 1.96 times the standard error. This gives us the following interval:

0.235 - 1.96 * 0.018 <= p <= 0.235 + 1.96 * 0.018

0.199 <= p <= 0.271

So, we are 95% confident that the true proportion of all smartphone users who would admit to walking into something or someone while texting on their cell phone is between 0.199 and 0.271.

Interpretation: Based on the sample data, there is a 95% chance that the true proportion of all smartphone users who would admit to walking into something or someone while texting on their cell phone is between 0.199 and 0.271.

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To solve a 3×3 augmented matrix use the method of elementary row operations.

What is a matrix?

A matrix is a rectangular array or table with numbers or other objects arranged in rows and columns. Matrices is the plural version of matrix. The number of columns and rows is unlimited. Matrix operations include addition, scalar multiplication, multiplication, transposition, and many others.

An augmented matrix for a system of equations is a matrix of numbers where each column contains all the coefficients for a single variable and each row represents the constants from one equation (both the coefficients and the constant on the other side of the equal sign).

The system of equations are - x - 2y + 3z = 7, 2x + y + z = 4, -3x + 2y -2z = -10

Here is the augmented matrix for this system.

[tex]\left[\begin{array}{rrr|r}1 & -2 & 3 & 7 \\2 & 1 & 1 & 4 \\-3 & 2 & -2 & -10\end{array}\right][/tex]

This matrix can be solved using the method of elementary row operations.

Interchange Two Rows. With this operation interchange all the entries in row  i and row j. The notation used here is Ri ↔ Rj.

[tex]\left[\begin{array}{rrr|r}1 & -2 & 3 & 7 \\2 & 1 & 1 & 4 \\-3 & 2 & -2 & -10\end{array}\right] \stackrel{R_1 \leftrightarrow R_3}{\rightarrow}\left[\begin{array}{rrr|r}-3 & 2 & -2 & -10 \\2 & 1 & 1 & 4 \\1 & -2 & 3 & 7\end{array}\right][/tex]

Multiply a Row by a Constant. In this operation multiply row i by a constant c and the notation will be cRi.

[tex]\left[\begin{array}{rrr|r}1 & -2 & 3 & 7 \\2 & 1 & 1 & 4 \\-3 & 2 & -2 & -10\end{array}\right] \stackrel{-4 R_3}{\rightarrow}\left[\begin{array}{rrr|r}1 & -2 & 3 & 7 \\2 & 1 & 1 & 4 \\12 & -8 & 8 & 40\end{array}\right][/tex]

Add a Multiple of a Row to Another Row.

Row i will be replaced in this procedure with row i times a constant c plus row j. Ri + cRi → Rj is the notation for this operation. This procedure involves taking an input from row i multiplying it by c, adding the equivalent value from row j, and then returning the result to row i.

[tex]\left[\begin{array}{rrr|r}1 & -2 & 3 & 7 \\2 & 1 & 1 & 4 \\-3 & 2 & -2 & -10\end{array}\right] \begin{gathered}R_3-4 R_1 \rightarrow R_3 \\\rightarrow\end{gathered}\left[\begin{array}{rrr|r}1 & -2 & 3 & 7 \\2 & 1 & 1 & 4 \\-7 & 10 & -14 & -38\end{array}\right][/tex]

Let’s go through the individual computation to make sure you followed this.

-3 - 4(1) = -7

2 - 4(-2) = 10

-2 - 4(3) = -14

-10 - 4(7) = -38

Therefore, the matrix is solved using row operations.

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Let P(t)=36(1−e^(−kt))+56 represent the expected core for a student who studied t hour for a test, suppose k=0. 24 so student scored 56% without studying.

If the student don't study then,

It corresponds to t= 0 .

We can evaluate the function with the t=0 so we can have

P(t) = 36(1−e^(−kt)) + 56

were k = 0.24

P(0) = 36 (1 - [tex]e^{0.24(t)}[/tex]) + 56

= 36 (1 - [tex]e^{0.24(0)}[/tex]) + 56

= 36 (1 - 1 ) + 56

=56%

Therefore, Let P(t)=36(1−e^(−kt))+56 represent the expected core for a student who studied t hour for a test is 56%.

The derivative of a function of a real variable in mathematics quantifies the sensitivity of the function's value (output value) to changes in its argument (input value). Calculus's core tool is the derivative. The velocity of an item, for instance, is the derivative of its position with respect to time; it quantifies how quickly the object's position varies as time passes.

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To choose the best option for the company, it is important to consider the total amount of interest that will be paid over the life of the loan.

With the 30-year loan, the total interest paid over the life of the loan will be higher than with the 15-year loan, because the interest rate is higher and the loan is paid over a longer period of time.

However, the shorter loan term means that the monthly payments are higher, which could be a financial burden for the company. Therefore, it is important to compare the total interest paid over the life of the loan for both options to determine which is the best option for the company.

Complete question:

A company i planning to purchae a plot of land for $200,000 to build a factory there are two option offered by a lending intitution. The first option is to make a down payment of $200,000 and take a $600,000 30-year mortgage loan with an interest rate of 3.5%. The second option is to make a $100,000 down payment and take a $700,000 15-year mortgage loan with an interest rate of 3.0%.

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Answer:

To calculate the monthly payment for a loan, you can use the following formula: P = L[c(1 + c)^n]/[(1 + c)^n – 1]

Step-by-step explanation:

See the attachment for detail

Answer: 19/20

Step-by-step explanation:

Probability of tomato spaghetti = tomato sauce and probability of spaghetti

Probability (tomato sauce) = 1/4
Probability (spaghetti) = 1/5
Probability (tomato spaghetti) = 1/4 x 1/5 = 1/20
Probability of not tomato spaghetti = 1- probability of tomato spaghetti
= 1 - 1/20  = 19/20

In geometry, an angle is often measured in units of radians, which is a way to express the size of an angle in terms of the length of the arc it cuts off on the circumference of a circle.

This relationship between an angle and an arc length is given by the formula:

Arc Length = Radius * Angle (in radians)

Rearranging this formula to solve for the angle, we have:

Angle (in radians) = Arc Length / Radius

Plugging in the values for the radius (2.2) and the arc length (12.2), we get:

Angle (in radians) = 12.2 / 2.2 = 5.54

Rounding to the nearest 10th, the angle in radians is approximately 5.5.

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Answer:

X = 2

Step-by-step explanation:

5x + 10 = 2x + 16

3x + 10 = 16

3x = 6

x = 2

Hope this helps! Pls give brainliest!

So x/1 + y/-2 = 1 and x/1 + y/-2 = 1 are the slope intercept forms of graphs 1, respectively.

The optimal angle in geometry is where the line's incline contacts the y-axis. a point where a line or curve's y-axis crosses it. This is demonstrated using the equation and for straight line, Y = shifting from traditional, where m denotes the slope and c the en la. The line's slope (m) as well as y-intercept (b) are highlighted in the analytic form of the equation. The slope is feet and the y-intercept is b when an equation has to have the intercept form (y=mx+b). It is also reasonable to rewrite some equations so that they appear to be slope intercepts. For example, the inclination and y-intercept are both modified to 1 if y=x is rewritten as y=1x+0.

given

The slope intercept form = x/a + y /b = 1

1) for graph 1

The intercept form is  x/1 + y/-2 = 1

2) for graph 2

The intercept form is x /-1 + y /1 = 1

So x/1 + y/-2 = 1 and x/1 + y/-2 = 1 are the slope intercept forms of graphs 1, respectively.

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The percentage score is 50%, for instance, if you get a test score of 50 out of 100. This can be calculated as follows: Percentage is (50/100) × 100, or 50. Proportion: A proportion is a statement indicating the equality of two ratios.

Two ratios are equal if they are equal by a certain proportion. Simply divide one part by the whole to get the proportion's ratio.

While percentage expresses a ratio or fraction with a constant denominator of 100, proportion expresses the equivalent of two ratios or fractions.

In order to express a component of a total as a fraction or a decimal, percentages and proportions are two related ideas. Here is how to determine each of them:

One technique to express a number as a fraction of 100 is to use a percentage. You multiply the part by 100 and divide by the whole to get a percentage. The formula to determine a percentage is as follows:

Percentage is equal to (Part/Whole) × 100.

To obtain the ratio and calculate a proportion, divide one part by the total. If you wish to know how many apples make up 25% of a collection of 20 apples, for instance, you can set up a proportion as follows:

Part / Whole = Percentage / 100

Part / 20 = 25 / 100

Part = (25 / 100) × 20 = 5

So, 25% of the collection is 5 apples.

In general, you can use these formulas to calculate percentages and proportions based on the information you have. The key is to always make sure you have the correct units and understand what the whole and part represent.

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The equation would be written in exponential form as follows: [tex]$$\ln(m) = n \Rightarrow m = e^n$$[/tex]

The equation ln(m)=n can be rewritten in exponential form as m=e^n. This can be seen by taking the natural logarithm (ln) of both sides of the equation. The natural logarithm of m is equal to n, so we have ln(m)=n. Applying the exponential function, e^x, to both sides of the equation gives us m=e^n. This can be further understood by calculating the exponential of both sides.

For example, if n = 1, then ln(m)=1, so m=e^1. Applying the exponential function, e^x, to both sides of the equation, we have m=e^1. Calculating e^1 gives us m=e^1=2.718. Thus, ln(m)=1 can be rewritten in exponential form as m=2.718.

The equation in Latex would be written as follows: [tex]$$\ln(m) = n \Rightarrow m = e^n$$[/tex]

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The value of integral ∫(0,8)  [4f(x) + 6g(x)] dx on the interval of (0,8) is 264

when ∫(0,8) f(x) dx = 39 and  ∫(0,8)g(x) dx =18.

Integration is a method of adding or summing up the parts to find the whole. It is a reverse process of differentiation, where we reduce the functions into parts.

Given that,

∫(0,8) f(x) dx = 39 and  ∫(0,8)g(x) dx =18

∫(0,8)  [4f(x) + 6g(x)] dx

Apply linearity rule of integration,

= ∫(0,8) 4f(x) dx + ∫(0,8) 6g(x) dx

=4 ∫(0,8) f(x) dx + 6∫(0,8) g(x) dx

= 4(39) + 6(18)

= 156 + 108

= 264

therefore, the value of integral ∫(0,8)  [4f(x) + 6g(x)] dx on the interval of (0,8) is 264

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The product of the expression (a + b) and (a - 2b) will be a² - ab - 2b².

Algebra is the study of abstract symbols, while logic is the manipulation of all those ideas.

The acronym PEMDAS stands for Parenthesis, Exponent, Multiplication, Division, Addition, and Subtraction. This approach is used to answer the problem correctly and completely.

The expressions are given below.

(a + b) and (a - 2b)

Then the product of the expression is given as,

⇒ (a + b)(a - 2b)

⇒ a² - 2ab + ab - 2b²

⇒ a² - ab - 2b²

The product of the expression (a + b) and (a - 2b) will be a² - ab - 2b².

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Ken borrowed P8,077.84 from Haguel for a period of 2 years and a month.

To calculate the amount Ken borrowed,

We need to use the formula for compound interest:

A = P * (1 + r/n)^(nt)

Where:

A is the amount after t years

P is the principal amount (the amount borrowed)

r is the annual interest rate (8% in this case)

n is the number of times the interest is compounded in a year (4 times in this case, since the interest is compounded quarterly)

t is the number of years

We know the amount after 2 years and 1 month,

So we can use that information to solve for the principal amount P.

First, we need to convert the number of years and months into a single value in terms of years:

2 years and 1 month = 2 + 1/12 = 2.0833 years

Next, we can plug in the values into the formula:

A = P * (1 + r/n)^(nt)

A = P * (1 + 0.08/4)^(4 * 2.0833)

A = P * (1.02)^(8.3333)

A = P * 1.2288

We also know that Ken is paying P2,500 every 3 months,

So we can multiply that by 4 (since there are 4 quarters in a year) to find the annual payment:

P2,500 * 4 = P10,000

And we know that A = P * 1.2288,

So we can substitute in the values we have:

P10,000 = P * 1.2288

Now we can solve for P:

P = P10,000 / 1.2288

P = 8077.84

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The function that best models the data table is; Option D: h(T) = -0.85t² + 1.63t + 1.51

A mathematical function model is defined as a mathematical description  by means of a function or an equation- of a real-world situation such as size of a population, demand for a product, speed of a falling object, life expectancy of a person at birth, or cost of emission reductions, etc.

From the table, we see that at time, t = 0 s, height(h) = 1.5 m.

Looking at the options, it means that options A and C cannot be correct.

Finally, at t = 1, h = 2.3. Plugging 1 for t in option D gives;

h(1) = -0.85(1²) + (1.63)1 + 1.51

= -0.85 + 3.12

= 2.27

This is approximately 2.3 and will be the correct option

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With the identification of plans, angles, Rectangles, and segments, you can find the shoe box in the attachment.

Every point on a Plano has the same level because it is a space with only two dimensions.

The ángulos are a component of a plan that is created from two recitals with a common vertex. In the case of our shoe box, all angles are right-angled, despite the perspective appearing to be greater or smaller than 90 degrees.

Semirrectas are rectus with a known beginning but no known end. We can extend two segments in the shoe box so that they become semi-rectangles.

The segments are straight lines with clearly defined beginnings and end. All of the lines that form in the shoe box are segments.

The following is identified in the drawing.

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The Full question:

Consider a traditional and illustrated shoe box. This illustration indicates or names the following. ​

The nature and scope of the conclusion that a study can reach refers to the limitations and generalizability of the results obtained.

It depends on the research design, methodology, and sample size used. The conclusion can only be applied to the specific population and conditions studied.

The study may also have limitations due to biases or confounding variables that can affect the validity of the conclusion. To have a stronger conclusion, it is important to have a well-designed study with a large and representative sample, and to control for extraneous variables.

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The circumference of the circle is 18.84 cm. Therefore, option C is the correct answer.

The circumference is the length of any great circle, the intersection of the sphere with any plane passing through its centre. A meridian is any great circle passing through a point designated a pole.

Given that, a circle has a diameter of 6 cm.

We know that, the formula to find the circumference of the circle is 2πr.

Here, radius = 6/2 =3 cm

Now, circumference = 2×3.14×3

= 18.84 cm

Therefore, option C is the correct answer.

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For the velocity function v(t) = t³ - 3t² + 12t + 4, with interval 0 ≤ t ≤ 3, the maximum acceleration is option D: 21 m/s².

What is velocity?

The pace at which an object's position changes in relation to a frame of reference and time is what is meant by velocity. Although it may appear sophisticated, velocity is just the act of moving quickly in one direction. Since it is a vector quantity, the definition of velocity requires both magnitude (speed) and direction.

The velocity function is v(t) = t³ - 3t² + 12t + 4.

The interval is given as - [0,3]

Maximize the function to obtain the value of t.

v'(t) = a(t) = 3t² - 6t + 12

Maximize it again -

a'(t) = 6t - 6 = 0

6t = 0 + 6

t = 6/6

t = 1

Now there are three critical points for t = {0,1,3}

1 and 3 are endpoints of the interval [0,3].

To get the maximum acceleration, plug in the values of t in the equation .

First substitute the value t = 0 -

a(0) = 3t² - 6t + 12

a(0) = 3(0)² - 6(0) + 12

a(0) = 12

Now substitute the value t = 1 -

a(1) = 3t² - 6t + 12

a(1) = 3(1)² - 6(1) + 12

a(1) = 3 - 6 + 12

a(1) = 15 - 6

a(1) = 9

Now substitute the value t = 3 -

a(3) = 3t² - 6t + 12

a(3) = 3(3)² - 6(3) + 12

a(3) = 27 - 18 + 12

a(3) = 39 - 18

a(3) = 21

So, the maximum acceleration is 21 m/s² when t =3.

Therefore, the maximum acceleration is 21 m/s².

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The statistical test that Juan wants to use to test the hypothesis about the mean sales dollars among three shopping malls is an Analysis of Variance (ANOVA).

ANOVA is a hypothesis testing technique used to compare the means of multiple groups. In this case, the three shopping malls are the groups and the mean sales dollars are the variables. The purpose of ANOVA is to determine if there is a significant difference in the means of the groups.

ANOVA uses a null hypothesis that all the means are equal, and an alternative hypothesis that at least one mean is different. The test statistic calculated by ANOVA is the F-value, which is the ratio of the between-group variance to the within-group variance. If the F-value is large, it indicates that the differences between the means are significant, and therefore, the null hypothesis is rejected.

In conclusion, Juan can use ANOVA to test the hypothesis about the mean sales dollars among the three shopping malls. ANOVA provides a powerful tool to compare means across multiple groups and helps to determine if there are any significant differences between them.

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15

There's 5 people behind me and 10 people in front of me.

Ji-Yoon's loading speed is 6 trucks per hour.

From the question, we have the following parameters that can be used in our computation:

Ji-Yoon loaded 84 Trucks in 14 hours

Ji-Yoon's loading speed an be calculated by dividing the total number of trucks loaded (84) by the number of hours it took to load them (14):

This is repesented as

84/14 = 6

Hence, the speed is 6 trucks per hour

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The probability of selecting a $10 dollar bill or a $5 dollar bill would be = 13/23

Probability is defined as the expression that can be used to represent the possible outcome of an event which may likely occur or not.

The quantity of $1 bill = 10

The quantity of $5 bill = 10

The quantity of $10 bill = 3

The sum total of bills in the box = 23

The probability of choosing a 5 or 10 bills;

= 10+3/23

= 13/23

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Answer:The rate of speed is the rate at which the total distance is traveled in the time taken.

The Space Explorer B travel 6.67 times faster than Space Explorer A.

What is rate of speed?

The rate of speed is the rate at which the total distance is traveled in the time taken. Rate of speed can be given as,

Here,  is the distance traveled by the object and  is time taken but the object to cover that distance.

Step-by-step explanation:The equation given in the problem is,

Here,  represented the number of miles that the satellite, Space Explorer B, flies in hours.

The satellite, Space Explorer A, flies 24000 miles in 20 hours.

The speed of the Space Explorer A, which flies 24000 miles in 20 hours is,

Thus the Space Explorer A, travels 1200 miles per hour.

As the Space Explorer B, travel is 8000 miles per hour and the Space Explorer A, travels 1200 miles per hour. Thus the ratio of the speed of both is,

Thus the Space Explorer B travel 6.67 times faster than Space Explorer A.

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Answer:

6

Step-by-step explanation:

If 5r+25=30, r=1. Therefore, r+5 would be 6.

Answer:

r has to be equal to 1, because 5 + 25 = 30, so r would be equal to 1 because 1 * 5 = 5 therefore the value will not change.

Now that we know that r = 1, the answer to r + 5 =

1 + 5 = 6

Step-by-step explanation:

Hope it helps! =D

The vector parametric equations that describe the helical path you take from the point (28, 0, 0) to the point (28, 0, 40) as you make 4 revolutions during the time interval 0 ≤ t ≤ 1 are:

x(t) = 28 + 18 cos(πt / 15)

y(t) = 18 sin(πt / 15)

z(t) = 50t

To find a vector parametric equation for the helical path, we need to describe the position of a point on the spiral staircase as it moves from (28, 0, 0) to (28, 0, 40) while making 4 revolutions during the time interval 0 ≤ t ≤ 1.

Let's define the following parameters:

R: Radius of the spiral staircase = 18 feet

H: Height of the spiral staircase = 50 feet

N: Number of revolutions during the time interval = 4

T: Total time taken to complete N revolutions = 1 hour (or 60 minutes)

The parametric equations for the helical path can be given as follows:

x(t) = 28 + R × cos(2πNt/T)

y(t) = R × sin(2πNt/T)

z(t) = H × t

Where:

x(t), y(t), z(t) are the coordinates of the point on the helical path at time t.

R × cos(2πNt/T) and R × sin(2πNt/T) describe the circular motion of the point in the xy-plane as it makes N revolutions over the time interval.

H × t describes the linear motion of the point along the z-axis.

Now, let's plug in the given values:

R = 18 feet

H = 50 feet

N = 4

T = 60 minutes

And simplify the equations:

x(t) = 28 + 18 × cos(2π × 4t / 60)

y(t) = 18 × sin(2π × 4t / 60)

z(t) = 50 × t

Simplifying further:

x(t) = 28 + 18 × cos(π × t / 15)

y(t) = 18 × sin(π × t / 15)

z(t) = 50 × t

These equations describe the helical path you take from the point (28, 0, 0) to the point (28, 0, 40) as you make 4 revolutions during the time interval 0 ≤ t ≤ 1.

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Average velocity = 0 gives the horizontal component of the launch velocity .

What does average velocity mean?

The difference between the change in position or displacement (x) and the time periods (t) during which the displacement happens is known as average velocity.

                     Depending on how the displacement is displaced, the average velocity may be positive or negative. Meters per second (m/s or ms-1) is the standard international unit for average velocity.

Typical flight of a projectile is as shown in the picture above.

In the problem it is given that initial velocity V₀ at an angle θ

above the horizontal. As such inn the picture U=  V₀

This velocity can be resolved into its  x and y components.

Component along x axis, and

Component along y  axis = V₀ Sin θ

Let t be time of flight.

    Average velocity = Displacement/time of flight

  It is given that "It lands at the same level from which it was launched", means that displacement in the y axis is = 0  

      Average velocity  = 0/t  = 0  ............1

cos  θ component.

 Average velocity  =    V₀  cos  θ ............ 2

Average velocity we need to add both vectors along x and y directions

. In this instant it is simple as one of the vectors is  

                        Average velocity  = 0

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For the given triangles ΔABC ≈ ΔADE, the measurement  of angle ACB is, 87°

Triangles with the same shape but different sizes are said to be similar triangles. Squares with any side length and all equilateral triangles are examples of related objects. In other words, if two triangles are similar, their corresponding sides are proportionately equal and their corresponding angles are congruent. Triangle resemblance is shown here by the symbol "≈"

Given that,

One triangle, ΔABC

one segment DE which is intersecting sides AB & AC

ΔABC has one similar triangle inside, which is ΔADE

Triangle ΔABC and ΔADE similar,

So, we can say ΔABC ≈ ΔADE

And it is known that

for similar triangles, ratio of corresponding angles of both the triangles are equal for similar triangles

so, ∠DAE/∠AED  = ∠CAB/∠ABC

⇒  62°/(11x -2)°  =  62°/(6x + 13)°

⇒  (11x -2)°  = (6x + 13)°

⇒   11x - 6x = 13 + 2

⇒    5x  = 15

⇒      x = 3

So,

∠ADE = 11x - 2 = 11 x 3 - 2 = 31°   =  ∠ABC

It is known that,

Sum of all the interior angles of triangle is 180°

Now,

∠ACB + ∠CAB + ∠ABC = 180°

∠ACB + 62° + 31°  = 180°

∠ACB  = 180° - 93°

           =  87°

Hence, the angle ACB is 87°

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Answer:

Sunrise; $35

Step-by-step explanation:

Hope it helps! =D

Check the picture below.

so to get the EQUATion of each lines, we'll use those points you see in the picture for each, now we're only getting their "equation" only just yet, then we'll do the inequality part.

for the blue line

[tex](\stackrel{x_1}{0}~,~\stackrel{y_1}{-5})\qquad (\stackrel{x_2}{5}~,~\stackrel{y_2}{0}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{\textit{\large rise}} {\stackrel{y_2}{0}-\stackrel{y1}{(-5)}}}{\underset{\textit{\large run}} {\underset{x_2}{5}-\underset{x_1}{0}}} \implies \cfrac{0 +5}{5} \implies \cfrac{ 5 }{ 5 } \implies 1[/tex]

[tex]\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-5)}=\stackrel{m}{ 1}(x-\stackrel{x_1}{0}) \implies y +5 = 1 ( x -0) \\\\\\ y+5=x\implies \boxed{y=x-5}[/tex]

for the red line

[tex](\stackrel{x_1}{-4}~,~\stackrel{y_1}{3})\qquad (\stackrel{x_2}{6}~,~\stackrel{y_2}{-2}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{\textit{\large rise}} {\stackrel{y_2}{-2}-\stackrel{y1}{3}}}{\underset{\textit{\large run}} {\underset{x_2}{6}-\underset{x_1}{(-4)}}} \implies \cfrac{-5}{6 +4} \implies \cfrac{ -5 }{ 10 } \implies - \cfrac{ 1 }{ 2 }[/tex]

[tex]\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{3}=\stackrel{m}{- \cfrac{ 1 }{ 2 }}(x-\stackrel{x_1}{(-4)}) \implies y -3 = - \cfrac{ 1 }{ 2 } ( x +4) \\\\\\ y-3=- \cfrac{ 1 }{ 2 }x-2\implies \boxed{y=- \cfrac{ 1 }{ 2 }x+1}[/tex]

now, the dashed line for the red one, means the borderline is not included so whatever "y" is, is either > or <.

the solid line for the blue line means, the borderline is included, so whatever "y" is, is ⩾ or ⩽.

now, what area do we shaded, let's deal with the red one first.

well, do usually a true/false region check, so we pick a point on either side of the line, hmmmm for simplicity let's pick the origin, (0,0), which is below the red line, that means x = 0 and y = 0

[tex]y ~~ \square- \cfrac{ 1 }{ 2 }x+1\implies 0~~ \square-\cfrac{1}{2}(0)+1\implies 0~~ \square ~~ 1\implies 0 < 1[/tex]

so the sign that will make that statement true can only possible by "<", meaning that "0 is less than 1", that means that equation is

[tex]{\Large \begin{array}{llll} y ~~ < - \cfrac{ 1 }{ 2 }x+1 \end{array}}[/tex]

now let's deal with the blue line.

same gig, we'll do a true/false region check, hmm let's pick for the sake of simplicity and slacking the same point, (0,0) which is above the blue line

[tex]y ~~ \square ~~ x-5\implies 0~~ \square ~~0-5\implies 0~~ \square ~~-5\implies 0\geqslant -5[/tex]

so only sign that makes that true is "⩾" for the blue line, because "0 is indeed greater or equal than -5", so we get

[tex]{\Large \begin{array}{llll} y \geqslant x-5 \end{array}}[/tex]

now, bear in mind that we could have pick some other point, on either side, and the issue is, to make it a true or false statement by using either inequality, for example if we end up with two values such as -9 [  ] -1, well, -9 is lesser than -1, so it can only be -9 < -1 or -9 ⩽ -1 to make it true, now if we want to make that statement false, we simply do -9 > -1 or such, and that part is "no shaded", because is false, -9 is not greater than -1.