A large airplane typically has three sets of wheels: one at the front and two farther back, one on each side under the wings. Consider the Boeing 787 "Dreamliner", with a mass of 177000 kg. In this particular model, the distance from the front wheels to the rear set of wheels is 21.7 m.
(a) If the center of mass of the airplane is along a line through the center and 3.00 m in front of the rear wheels, how much force, in meganewtons, does the ground exert on each set of rear wheels when the plane is at rest on the runway?
(b) How much force, in meganewtons, does the ground exert on the front set of wheels?
(a) The force the ground exerts on each set of rear wheels when the plane is at rest on the runway is 0.743 MN.
(b) The force the ground exerts on the front set of wheels is 0.239 MN.
Center mass of the airplaneThe concept of center mass of an object can be used to dtermine the mass distribution of the airplane along the line through the center.
Some assumptionsThe wheels under the wind do not pass through the center line.The position of the front wheel is constant and it is zero mark (origin).The rear wheels are at 21.7 m markPosition of the center mass of the plane is calculated as follows;
Let the position of the center mass, Xcm = y
the center mass is 3 m in front of rear wheels, that is
21.7 - y = 3
y = 21.7 - 3
y = 18.7 m
Xcm = 18.7 m
Mass of the plane at the position of the rear wheelsLet the mass of the plane at front wheels = M1
Let the mass of the plane at rear wheels = M2
[tex]X_{cm} = \frac{M_1x_1 + M_2x_2}{M_1 + M_2}[/tex]
[tex]18.7 = \frac{M_1(0) + M_2(21.7)}{177000} \\\\3,309,900 = 21.7M_2\\\\M_2 = \frac{3,309,900}{21.7} \\\\M_2 = 152,529.95 \ kg[/tex]
Force exerted by the ground on each rear wheelThere are two rear wheels, and the force exerted on each wheel due to mass of the airplane at this position is calculated as follows;
[tex]W = mg\\\\W_1 = W_2 = \frac{1}{2} (mg) = \frac{1}{2} (152,529.95 \times 9.8) = 743,396.76 \ N= 0.743 \ MN[/tex]
Mass of the plane at the position of the front wheelM1 + M2 = 177,000
M1 = 177,000 - M2
M1 = 177,000 - 152,529.95
M1 = 24,470.05 kg
Force exerted by the ground on the front wheelW = mg
W = 24,470.05 x 9.8
W = 239,806.5 N = 0.239 MN
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The centripetal force is proportional to the _____. mass velocity squared inverse of the radius All of the above
Answer:
Velocity squared.
Explanation:
We know that,
[tex]\text{F}_{\text{Centripetal}} = \dfrac{mv^2}{r}, \text{which implies} ~\text{F}_{\text{Centripetal}} \propto v^2[/tex]
How far back into the universe are we able to see? Explain.
Answer:
About 46 billion light years Because space expands so what we didn’t see before is what we could see now. An example could be how everyone thought Pluto was a regular sized planet but once you get a look at the bigger picture and compare it to other thing in space we now know Pluto is a dwarf planet.
How many times does the light beam shown in FIGURE 26-59 reflect from (a) the top and (b) the bottom mirror?
Answer:
5
Explanation:
how many electrons flow through a 3 A current in 3 seconds
A ballplayer catches the ball 4 seconds after throwing it straight up in the air. What speed did he throw it and how high did it go?
Answer:
Speed of the ball when it was thrown = 16.67 m/s
Height reached by the ball = 14.16 s
Explanation:
Given time in the ball comes to the same height from where the ball was thrown is 3.4 s.
Let us assume that the ball was thrown with a speed of u in the upward direction. Since only gravitational force acts on the particle in the downward direction, it has a constant acceleration in the downward direction.
We also know that a particle has the same magnitude of velocity when it is under a free fall at a fixed height but direction is opposite i.e., initially in the upward direction and finally in the downward direction.
https://tex.z-dn.net/?f=%5Ctherefore%20%5Cdfrac%7B-u-u%7D%7B3.4%7D%3D%20-9.8%5C%5C%5CRightarrow%20%5Cdfrac%7B2u%7D%7B3.4%7D%3D%209.8%5C%5C%5CRightarrow%202u%20%3D%209.8%5Ctimes%203.4%5C%5C%5CRightarrow%20u%20%3D%20%5Cdfrac%7B9.8%5Ctimes%203.4%7D%7B2%7D%5C%5C%5CRightarrow%20u%20%3D%2016.67%5C%20m%2Fs
Hence, the particle was thrown with a speed of 16.67 m/s.
Now, we also note that the particle has zero velocity at its maximum height.
So, from the initial position to the maximum height reached by the particle, we have
https://tex.z-dn.net/?f=0%5E2%20%3D%20u%5E2%2B2as%5C%5C%5CRightarrow%20s%20%3D%20%5Cdfrac%7Bv%5E2-u%5E2%7D%7B2a%7D%5C%5C%5CRightarrow%20s%20%3D%20%5Cdfrac%7B0%5E2-16.67%5E2%7D%7B2(-9.8)%7D%5C%5C%5CRightarrow%20s%20%3D14.16%5C%20m
Hence, the maximum height reached by the ball is 14.16 m.
9. aDefine refraction of light. Draw the ray diagram when an object is placed at C in a concave mirror Write any two natures of that image
Answer:
the process of bending of light when travling throw different mediume is called refraction of light.
An ideal simple machine is one that...
Select one:
a. conserves force.
b. conserves distance.
c. conserves work.
d. conserves velocity.
An ideal simple machine is one that conserves forces because every input force is useful or not lost to friction and it is considered as a perfect or ideal system.
What is an ideal machine?An ideal machine is a type of machine whose efficiency is 100 percent. This type of machine does not loss heat to friction or does no work against frictional forces.
When energy is not lost to friction, we say that such system is perfect or ideal. Or simply put, such system conserves forces.
In Ideal machine, mechanical advantage is one.
Mechanical advantage = output force / input force
In ideal simple machine, output force = input force
Therefore, ideal simple machine is one that conserves forces because every input force is useful or not lost to friction and it is considered as a perfect or ideal system.
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A vector is 0.888 m long and
points
in a
205 degree
direction.
Find the y-component of the
vector.
Answer:
Since the second quadrant ends at 180 deg,
205 will be 25 deg into the third quadrant (-x and -y)
y = -.888 sin 25 = -.375
One can also write y = .888 sin 205 = -.375
she incorrect? Select all that apply.
because electromagnetic waves can only travel in gases
А
B
because electromagnetic waves can only travel through solids
С
because electromagnetic waves only come from the Sun
D
because electromagnetic waves are not created using force on a medium
m
because electromagnetic waves are created using accelerating charges
F
because electromagnetic waves require a medium to travel
electromagnetic waves can travel not only through air and solid materials, but also through the vacuum of space.
hope it helps...!!!
Sample Response: Yes, his graph is correct because it shows that as the average kinetic energy increases, so does the temperature. This is called a direct relationship. What did you include in your response? Check all that apply. As average kinetic energy increases, temperature also increases. The graph shows a direct relationship between average kinetic energy and temperature.
The graph will be correct, if it shows a direct relationship between average kinetic energy and temperature of the gas molecules.
What is average kinetic energy?The average kinetic energy of a gas molecule is the energy possesed by the gas due to its relative motion.
Average kinetic energy of gas molecules has a direct relationship with temperature of the gas molecules. As the gas temperature increases, the kinetic energy of the gas increases and consequently, the speed of the gas increases as well.
Thus, the graph will be correct, if it shows a direct relationship between average kinetic energy and temperature of the gas molecules.
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Answer:
Select both
Explanation:
You included all needed information
A negatively charged plastic comb is brought close to, but does not touch, a small piece of paper. If the comb and the paper are attracted to each other the charge on the paper
A) must be negative
B) may be positive or neutral
C) may be negative or neutral D)must be positive
If the comb and the paper are attracted to each other the charge on the paper, is D)must be positive
Laws of electrical attraction
This states that
Like charges attract Unlike charges repelNow, given that a negatively charged plastic comb is brought close to, but does not touch, a small piece of paper. If the comb and the paper are attracted to each other the charge on the paper, this implies that both the negatively charged plastic comb and the paper have opposite charges.
Since the charge on the plastic comb is negative, this means that the charge on the paper must be positive
So, if the comb and the paper are attracted to each other the charge on the paper, is D)must be positive
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Fill in the blank with the correct response.
Light striking a mirror at a 45° angle will be reflected at a
A 15kg penguin slides on its belly down an icy, frictionless glacier. If the penguin started from rest and reaches a speed of 11m/S when at the bottom, how high is the glacier? (Metres)
Answer:
Mechanical Energy (initial) = Mechanical energy (final)
Ep(initial) + Ek(initial) = Ep(final) + Ek(final)
mgh(initial) + 1/2mv²(initial) = mgh(final) + 1/2mv²(final)
m being the mass of the penguin (kg)
g being gravitational acceleration (9.80 m/s²)
v(initial) being zero
h(final) being zero,i.e. final height is zero
v(final) being final velocity
solve for h(initial) being initial height at the top of the glacier
answer will be in metres
NB: don't forget to square the velocity
Explanation:
Since they mentioned frictionless, we know that this is a closed system therefore we are free to use this equation of conservation of mechanical energy
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Two particles are 15 meters apart.
Particle A has a charge of 6.0*10^-4 C
Particle B has a charge of 5.0*10^-4 C.
The resulting Coulomb force is 12 N. At the same distance, what combination of charges would yield the same Coulomb force?
A. Particle A: 8.0*10^-4 C, and Particle B: 3.0*10^-4 C
B. Particle A: 12.0*10^-4 C, and Particle B: 2.5*10^-4 C
C. Particle A: 9.0*10^-4 C, and Particle B: 8.0*10^-4 C
D. Particle A: 9.0*10^-4 C, and Particle B: 3.0*10^-4 C
Considering the Coulomb's Law, the combination of particle A: 12.0×10⁻⁴ C and particle B: 2.5×10⁻⁴ C would yield the same Coulomb force of 12 N.
Coulomb's LawCharged bodies experience a force of attraction or repulsion on approach.
From Coulomb's Law it is possible to predict what the electrostatic force of attraction or repulsion between two particles will be according to their electric charge and the distance between them.
From Coulomb's Law, the electric force with which two point charges at rest attract or repel each other is directly proportional to the product of the magnitude of both charges and inversely proportional to the square of the distance that separates them:
[tex]F=k\frac{Qq}{d^{2} }[/tex]
where:
F is the electrical force of attraction or repulsion. It is measured in Newtons (N).Q and q are the values of the two point charges. They are measured in Coulombs (C).d is the value of the distance that separates them. It is measured in meters (m).K is a constant of proportionality called the Coulomb's law constant. It depends on the medium in which the charges are located. Specifically for vacuum k is approximately 9×10⁹ [tex]\frac{Nm^{2} }{C^{2} }[/tex].The force is attractive if the charges are of opposite sign and repulsive if they are of the same sign.
This caseIn this case, you know that two particles are 15 meters apart and the resulting Coulomb force is 12 N.
On the other side, you know:
Particle A: 8.0×10⁻⁴ C, and Particle B: 3.0×10⁻⁴ CParticle A: 12.0×10⁻⁴ C, and Particle B: 2.5×10⁻⁴ CParticle A: 9.0×10⁻⁴ C, and Particle B: 8.0×10⁻⁴ CParticle A: 9.0×10⁻⁴ C, and Particle B: 3.0×10⁻⁴ CReplacing in the Coulomb's Law, you get:
[tex]F=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{(8x10^{-4}C) (3x10^{-4} C )}{(15 m)^{2} }[/tex] → F= 9.6 N[tex]F=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{(12x10^{-4}C) (2.5x10^{-4} C )}{(15 m)^{2} }[/tex] → F= 12 N[tex]F=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{(9x10^{-4}C) (8x10^{-4} C )}{(15 m)^{2} }[/tex] → F= 28.8 N[tex]F=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{(9x10^{-4}C) (3x10^{-4} C )}{(15 m)^{2} }[/tex] → F=10.8 NFinally, the combination of particle A: 12.0×10⁻⁴ C and particle B: 2.5×10⁻⁴ C would yield the same Coulomb force of 12 N.
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The weight of your science book presses on the desk.
A. Gravity pulls on the book.
B. Gravity pulls on the desk.
C. The desk pushes on the book.
Answer:
A. Gravity pulls on the book :)
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PLEASE HELP!! A TOTAL OF 50 POINTS WHEN GIVEN BRAINLIEST!!
Part A: Find the work done in lifting 1 L of blood (mass 1 kg ) from the foot to the head of a 1.9 m -tall person.
Part B: If blood circulates through the body at the rate of 5.0 L/min , estimate the heart's power output. (Your answer underestimates the power by a factor of about 5 because it neglects fluid friction and other factors.)
Explanation:
for part A:
work done is equal to change in potential energy which is
MgH
so the answer is 1.9 × 1 × 9.81
ANSWER FOR PART A: 18.639
FOR PART B:
power = flow rate x gh
= 5×9.81×1.9
93.195 watts
any help here please ???
Answer:
16 reflection,incidence
Two people of equal mass attempt a tug-of-war with a 10 m long rope
while standing on ice. On pulling the rope, they both slide towards
each other. What will be the acceleration for each person?
Answer:
Explanation:
As the poster has noted above in comment, the acceleration for each person will be the same. This is because when they tugon the rope, there will be tension force on the rope pulling the two persons towards each other. The tension force will be the same for them. As they also have equal mass, by Newton's Second Law of Motion, Force = mass * acceleration, their acceleration will be the same.
A 53 g ice cube at −30◦C is dropped into a container of water at 0◦C. How much water freezes onto the ice? The specific heat of ice is 0.5 cal/g · ◦ C and its heat of fusion of is 80 cal/g. Answer in units of g.
For A 53 g ice cube at −30◦C is dropped into a container of water at 0◦C, the amount of water that freezes onto the ice? is mathematically given as
x = 9.93 g
What is the amount of water that freezes onto the ice?Where
Energy received = energy given out
Generally, the amount of water is mathematically given as
(53)(0.5)(30) = (80)(x)
Therefore
x = (49)(0.5)(16)/(80)
x = 9.93 g
In conclusion, the mass of water
x = 9.93 g
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Aresultant vector is the *blank* of two or more vectors.
Answer:
Vector sum.
Adding two things together to make one is usually referred to as a sum, therefore, we can identify this as that.
The jet engine of an airplane expels hot gas.
A. The airplane is propelled in the same direction as the hot gas.
B. The airplane is propelled in the opposite direction as the hot gas.
C. The airplane is propelled against the outside air.
Answer:
B. The airplane is propelled in the opposite direction as the hot gas.
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Is this d or not? Pls helppppp
Answer:
B load
Explanation:
definitely not D.
a power source is a battery or a power generator (like at power plants or on good old-fashioned bicycles to have light in the dark).
the fan uses the electrical energy coming from a power source.
if it would be a "propeller" at a wind farm (where power is generated by the wind blowing in between the blades making them turn and as such generating electrical power), then yes, but that is not what the description is telling us.
so, since it is using electrical power to do something, it is a load on the net or circuit or grid.
because it takes out some energy, the actual power generator has to work a little bit harder to maintain the energy level in the grid. just like you have to work harder when you have to carry a bigger weight (or load). hence the name.
the fan will have some conducive material inside (an electrical motor is a structure of coils of wires around magnets, and the power goes through these wires, so they have to be conductive).
and the fan will have a switch, which breaks or establishes the flow of electric energy and therefore determines, if and when the fan is working or not.
a diamond sparkles more than a glass cut to similar shapes,why?
Answer:
because when you shape glass it's not a shiny as diamond
What is the approximate electrostatic force between two protons separated by a distance of 1.0 x 10-6 meter?
1) 2.3 x 10-16 N and repulsive
2) 9.0 x 1021 N and repulsive
3) 9.0 x 1021 N and attractive
4) 2.3 10-16 N and attractive
Answer:
2.3×10^-16
Explanation:
Charge of proton = 1.6×10^-19
let q(a) and q(b) be the two protons.
According to the Coulumbs Laws ;
F = kq(a)×q(b) / r^2
where k = 9.0×10^9 and r is the distance of seperation.
So having a distance of 1.0×10^-6 in our case ;
F = (9.0×10^9×1.6×10^-19×1.6×10^-19)/(1.0××10^-6)^2
F = (2.304×10^-28)/(1.0×10^-12)
F = 2.304×10^-16N
Since the both charges are positively charged they will repel .
A light bulb operating at a dc voltage of 120 V has a power rating of 60 W. How much current is flowing through this bulb
[tex]\\ \rm\rightarrowtail I=\dfrac{P}{V}=\dfrac{60}{120}=\dfrac{1}{2}=0.5A[/tex]
acar start from rest and go with velocity of 4m/s for 4second what is acceleration of car
Answer:
1 m/s^2
Explanation:
The formula for accleration is a=Δv/Δt
where, Δv = final velocity - initial velocity = 4 - 0 = 4
initial velocity = 0 since the car starts form rest and final velovity is 4 as the car goes from rest till 4 m/s
Δt = 4 since the car takes 4 seconds to reach a velocity of 4m/s
Hence, a = 4 m/s / 4 s = 1 m/s^2
Answer:
1m/s
Explanation:
Given
initial velocity(u)=0
final velocity(v)=4m/s
timetaken (t)=4
Aceleration(a)=v-u÷t
now
=4-0÷4
=1m/s
state the formula to compute average speed acquired by a vehicle to cover a distance between two points.
ty! :)
A stage has a radius R = 2.00 m and a mass M = 100 kg. The stage, which has a circular disk
shape, rotates in a horizontal plane, without any friction, about a vertical axle. Sandra has a
mass of m = 60.0 kg and she walks from the rim of the stage toward the center. Calculate the
angular speed when she reaches a point r = 0.500 m from the center, if the angular speed of the
system is 2.0 rad/s when Sandra is at the rim
i want the answer of this exercise
The Ice and steam points of a certain thermometer are found to be 20 cm apart. What temperatureis recorded in Celsius when the length of mercury theard is 5cm above the ice point mark?