You are a contractor and charge $45 for a site visit plus an additional $24 per hour for each hour you spend working at the site. Write and solve an equation to determine how many total hours you have to work to earn $117 working at two separate work sites. Write an equation to describe the situation. Use h to represent the number of hours.

Please help asap and thanksss

Answers

Answer 1

Answer:

y = mx + b

where,

y = earning

m = slope or earning per hour = $24

x = total number of hours

b = y intercept or initial earning upon visit = $45

Hence,

y = 24x + 45

Since we are working at two separate work sites, therefore each site we must earn 810/2 = 405

So when y = 405:

405 = 24x + 45

x = 15 hours

So you must work 15 hours at each site.

Step-by-step explanation:

Answer 2

Answer:

7.56 hours.

Step-by-step explanation:

So my equation will be:

$45 + $24h

If we need to find out how many hours you have to work in order to earn $117 working at two separate work sites, the equation would look like this:

45 + 25h ÷ 2 = 117.

First we need to multiply both sides of th equation by 2.

[tex]\frac{2\left(45+25h\right)}{2}=117\cdot \:2[/tex]

Then, I had to simplify.

[tex]5+25h=234[/tex]

After simplifying, it was about time to subtract 45 from both sides of the equation.

[tex]45+25h-45=234-45[/tex]

I had to simplify again, then divide both sides by 25.

[tex]25h=189[/tex]

[tex]\frac{25h}{25}=\frac{189}{25}[/tex]

Again, I have to simplify for a final time to get the answer of..

[tex]h=\frac{189}{25}[/tex]

In decimal form, thats equal to 7.56 hours.

h = 7.56.


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A volleyball player sets a volleyball straight up into the air. The height of the volleyball, , is modeled by this equation, where t represents the time, in seconds, after that ball was set.



The volleyball reaches its maximum height after 0.625 seconds. What is the maximum height of the volleyball?

Answers

Answer:

The maximum height of the volleyball is 12.25 feet.

Step-by-step explanation:

The height of the volleyball, h(t), is modeled by this equation, where t represents the  time, in seconds, after that ball was set :

....(1)

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How many quarts of water must be added to 7 qts of a 19% saline solution to obtain a 5% saline solution?

Answers

Answer: quantity of water added = 19.6 quarts

Step-by-step explanation:

Let x= quantity of water added

Then, Quantity of saline in 7 quarts solution  = 19% of 7 = 0.19 (7)=1.33 quarts [to remove % divide number by 100]

When x quarts water is added , the quantity of solution becomes = x+7

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Now, quantity of saline remains same, so

[tex]1.33= 0.05(x+7)\\\\\Rightarrow\ 1.33x=0.05x+0.35\\\\\Rightarrow\ 1.33-0.35=0.05x\\\\\Rightarrow\ x=\dfrac{0.98}{0.05}=19.6[/tex]

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Answers

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Step-by-step explanation:

See answer

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Answers

Answer:

D. 1 : 2

Step-by-step explanation:

Given:

A(-6, -2),

B(6, 7),

C(-2, 1)

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SOLUTION:

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[tex] AC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} [/tex]

Let,

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[tex] AC = \sqrt{(4)^2 + (3)^2} [/tex]

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Find CB:

[tex] CB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} [/tex]

Let,

[tex] C(-2, 1) = (x_1, y_1) [/tex]

[tex] B(6, 7) = (x_2, y_2) [/tex]

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[tex] CB = \sqrt{(8)^2 + (6)^2} [/tex]

[tex] CB = \sqrt{64 + 36} = \sqrt{100} [/tex]

[tex] CB = 10 [/tex]

Find AC : CB

AC : CB = 5 : 10 = 1 : 2

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Answers

Answer:

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Step-by-step explanation:

Answer:

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Answers

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What is the speed?

The magnitude of the change of its position over time or the magnitude of the change of its position per unit of time; it is thus a scalar quantity.

Here given that,

A cyclist rode at a constant speed of [tex]21[/tex]mph for [tex]3[/tex] hours. Then she decreased her rate of speed to [tex]17[/tex] mph for [tex]4[/tex] hours.

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Answers

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Answer:

The number (x) in: "5 more than twice a number is 17" is what we are solving here.

Step-by-step explanation:

The first few steps in deriving the quadratic formula are shown. A table listing the first few steps in deriving the quadratic formula Which best explains why is not added to the left side of the equation in the last step shown in the table? The term StartFraction b squared Over 4 a squared EndFraction is added to the right side of the equation, so it needs to be subtracted from the left side of the equation to balance the sides of the equation. The distributive property needs to be applied to determine the value to add to the left side of the equation to balance the sides of the equation. The term StartFraction b squared Over 4 a squared EndFraction needs to be converted so it has a common denominator before adding it to the left side of the equation to balance the equation. The square root of the term needs to be found before adding the term to the left side of the equation to balance the sides of the equation.

Answers

The distributive property needs to be applied to determine the value to add to the left side of the equation to balance the sides of the equation.

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trust me

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Answers

This is the answer
I am not sure so sorry if it is wrong

Answer:

x = 3 and x = -2/7

Step-by-step explanation:

you can multiple -6 by 7 = -42

and then find what adds into -19 but can multiply together to get -42.

In this case (x-21)(x+2) would work

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then you have to make them equal to zero

x-21/7 = 0                =   x = 21/7 = 3

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Answer:

35

Step-by-step explanation:

42 divided by -6+5 show step by step

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Answer:

17

Step-by-step explanation:

Answer:

-2

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