You are 5 years less than your older brother express the age of your elder brother in terms of your age using variable​

Answer:

Step-by-step explanation:

200 divides into 1000 so that is part of the HCF.

x^2 and x^3 are present so the HCF contains x^2

y^2 and y^5 are present so the HCF contains y^2

HCF = 200*x^2 * y^2

Answer:

there are infinitely many solutions

Step-by-step explanation:

1/2(b+14) is the same as (b+14)/2, so no matter what number you plug in for b, both sides will always be equal. thus, there is infinitely many solutions.

hope this helps <3

Answer: there is no solution.

Step-by-step explanation:

We can see mentally that when we multiply both sides by 2, we will be left with b+14 on both sides which will cancel out ( “b” will cancel out) so there is no solution.

Step-by-step explanation:

I don't understand. what are W, C, Y, Z ?

all I can do is solving the 4 systems of equations for x and y.

y = -2x - 3

y = 2x - 1

adding the equations

2y = 0 - 4 = -4

y = -2

-2 = 2x - 1

-1 = 2x

x = -1/2

y = x + 4

y = -x + 2

adding the equations

2y = 0 + 6 = 6

y = 3

3 = x + 4

x = -1

y = -2x + 3

y = x + 4

multiply second equation by 2, add the result to first

2y = 2x + 8

3y = 0 + 11 = 11

y = 11/3

11/3 = x + 4 = x + 12/3

x = -1/3

y = 2x - 1

y = -x + 2

multiply second equation by 2, add the result to first

2y = -2x + 4

3y = 0 + 3 = 3

y = 1

1 = -x + 2

-1 = -x

x = 1

Answer:

15x^3-70x^2+65x+30

Step-by-step explanation:

1) 5(3x+1)= (15x+5)

2) (15x+5)(x-2)=15x^2-25x-10

3) (15x^2-25x-10)(x-3)=15x^3-70x^2+65x+30

Answer:

No solutions since they are two variables and it supposed to be solved simultaneously

Answer:

x²+6x+9

x²+3x+3x+9

x(x+3)+3(x+3)

=(x+3)(x+3)

Ur answer sir :)

1) 6⁴

2) t²

3) b⁴

4) 5²× 7³

5) 2²× a²

6)a³× c⁴× d

Answer:

The answer is A!

Step-by-step explanation:

Answer:

your answer is b 8/10 - 5/10

Step-by-step explanation:

Answer:

k = 7

Step-by-step explanation:

The constant of proportionality k is calculated as

k = [tex]\frac{miles}{hours}[/tex]

Using the values from the table , then

k = [tex]\frac{14}{2}[/tex] = [tex]\frac{42}{6}[/tex] = [tex]\frac{56}{8}[/tex] = [tex]\frac{70}{10}[/tex] = 7

Answer:

(x, y) = (-1, 1)

Step-by-step explanation:

The fraction 8/3 of the chocolate bars would each of you get.

The division in mathematics is one kind of operation. In this process, we split the expressions or numbers into the same number of parts.

Given:

You have 4/3 chocolate bars.

You want to give 1/2 of the chocolate bars to your friend.

To find the fraction of the chocolate bars would each of you get:

Use division operation,

4/3 ÷ 1/2

Rearranging to multiplication term,

4/3 x 2/1

= 8/3

Therefore, 8/3  fraction of the chocolate bars would each of you get.

To learn more about the division;

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#SPJ2

Answer:9.1 units

Step-by-step explanation: Hope you get it right :D

Answer:

Step-by-step explanation:

     MARKS  

        %    Max   Actual  

Hindi 50%    100 50  

English 75%     140 105  

Math              160 90  

(245/400)

least to greatest

-4.5

-4

-3 1/2

-3

2.5

Answer:

-4.5, -4, -3 1/2, 2.5, 3

Step-by-step explanation:

Answer:

[tex]\huge\color{green}\boxed{\colorbox{black}{Answer ☘}}[/tex]

To find - sum of the given two terms.

[tex](4 + 3x) + (5 - 4x + 2x {}^{2} ) \\ 4 + 3x + 5 - 4x + 2x {}^{2} \\ = > 2x {}^{2} - x + 9[/tex]

[tex]\color{purple}\boxed{\colorbox{black}{Additional Information♡}}[/tex]

we basically added the like terms together..

like, the terms ( 3x and -4x ) will be added together.. and the terms ( 4 and 5 ) will be added together...

since there's none other term having "x²" as the coefficient.. so 2x² will be left as it is!

hope helpful~

The sum of the expression 4+3x and 5-4x+2x² is 2x² + 7x + 9

Given:

4+3x

5-4x+2x²

(4+3x) + (5-4x+2x²)

= 4 + 3x + 5 - 4x + 2x²

= 2x² + 3x - 4x + 5 + 4

= 2x² + 7x + 9

Therefore, the sum of the expression is 2x² + 7x + 9

Learn more about sum:

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What the judge should do is adhere strictly to the rules.

This is so because, in case of not abiding by the rules, the referee would be allowing the players to modify the sport at will, which would go against the stability of the game and the predictability of the rules.

Therefore, in case the captains want to modify the rules, in any case they should contact the governing association of the sport to request said modifications.

Learn more about referees in https://brainly.com/question/8186953

The referee will have to allow halftime interval as a result of one of the

players wanting it.

Every sport has rules which guides the game to ensure fair play and  prevent

confusion from happening. Referee decisions are based on the rule of the

game but can also be negotiated.

In this scenario, if all the players wanted eliminate the halftime interval, it

could have been honored .But in this case, the referee has to follow the rules

of the game due to the other player disagreeing with the suggestion.

Read more about Sport rules https://brainly.com/question/1862654

If I understand the problem correctly

The blank on the left would be 14

and the blank on the top would be 350

Answer:

A. 85  B. 87  C. 60

Step-by-step explanation:

As shown in the shapes, A, is a full circle making 360 degrees full. B, a half circle making 180 degrees half. C, a full circle again making 360 degrees full.

A: [360-(132+63+80)]

360 - 275

=85

B: [180(60+33)]

180 - 93

=87

C: [360(120+60+120)]

360 - 300

=60

Answer:

36 And 59

Step-by-step explanation:

Answer:

A Todays soup  will be less tomatoey

Step-by-step explanation:

Answer:

answer is 19............

The slope of B'C' is 1 and it can be determined by using formula of scale factor.

Given that,

ABC is an isosceles right triangle in which has a slope of -1 and m ∠ABC = 90°.

ABC is dilated by a scale factor of 1. 8 with the origin as the center of dilation, resulting in the image A'B'C'.

We have to determine,

What is the slope of B'C'?

According to the question,

ABC is an isosceles right triangle in which,

Slope of AB = -1

And AB is perpendicular to BC.

When the two lines are perpendicular to each other then,

[tex]\rm The \ slope\ of\ AB \times Slope\ of \ BC = -1\\\\-1 \times Slope\ of \ BC = -1\\\\ Slope\ of \ BC = 1\\[/tex]

ABC is dilated by a scale factor of 1. 8 with the origin as the center of dilation, resulting in the image A'B'C'.

Length of Line segment A'B'= 1.8 × AB

So, the slope of the two-line Segment that is AB and A'B' are the same.

Slope of A'B'= -1

Length of Line segment C'B'= 1.8 × CB

So, the slope of the two lines that is CB and C'B' are the same.

The slope of B'C' is 1.

Hence, The required slope of B'C' is 1.

For more details Slope refer to the link given below.

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Answer:

Slope of 1

Step-by-step explanation:

C.  1

Answer:

  cos(52°) = 18/x

  x = 18·sec(52°)

Step-by-step explanation:

The mnemonic SOH CAH TOA reminds you that ...

  Cos = Adjacent/Hypotenuse

In this geometry, that means ...

  cos(52°) = 18/x

You can use the relation sec(x) = 1/cos(x) to rewrite this as ...

  x = 18·sec(52°)

_____

You can also use the complementary angle and the complementary trig function.

  sin(90° -52°) = 18/x

Answer:

around 1.36

Step-by-step explanation:

Answer:

ages would no longer get larger as the mouse hovers over them. The transition would happen over 10s, since this is the default duration.

Step-by-step explanation:

Answer:

a and b

Step-by-step explanation:

Answer:

404

Step-by-step explanation:

Simplify = 8 + 30 x 13 + 6

Left to right = 8 + 390 + 6

Result = 404

Leave a brainliest if this helped.

Answer:

404

Step-by-step explanation:

do the equation inside the brackets first (BIDMAS) - 5 x 6 = 30

48 / 6 = 8

8 + (30 x 13) + 6 = 38

30 x 13 = 390

8 + 390 + 6 = 404

If the given equations are indeed

[tex]\begin{cases}x-\frac4{5y} = 9\frac45 \\ -14x - 4y = -46\end{cases}[/tex]

we can solve by substitution. Solve the second equation for x :

[tex]-14x - 4y = -46[/tex]

[tex]\implies 7x + 2y = 23[/tex]

[tex]\implies7x = 23 - 2y[/tex]

[tex]\implies x = (23 - 2y)/7[/tex]

Substitute this into the first equation and solve for y :

[tex]\dfrac{23-2y}7 - \dfrac4{5y} = 9\dfrac45[/tex]

On the right side, write the mixed number as an improper fraction:

[tex]9 + \dfrac45 = \dfrac{45}5 + \dfrac45 = \dfrac{45+4}5 = \dfrac{49}5[/tex]

[tex]\implies \dfrac{23-2y}7 - \dfrac4{5y} = \dfrac{49}5[/tex]

Multiply both sides of this equation by 35y (the LCM of the denominator of all three fractions)

[tex]35y \times \dfrac{23-2y}7 - 35y \times \dfrac4{5y} = 35y \times \dfrac{49}5[/tex]

[tex]5y\times(23-2y) - 7\times4 = 7y \times 49[/tex]

[tex]115y - 10y^2 - 28 = 343y[/tex]

[tex]10y^2 + 228y + 28 = 0[/tex]

[tex]5y^2 + 114y + 14 = 0[/tex]

To solve the quadratic, I'll complete the square :

[tex]5\left(y^2 + \dfrac{114}5y\right) + 14 = 0[/tex]

[tex]5\left(\left(y + \dfrac{57}5\right)^2 - \left(\dfrac{57}5\right)^2 \right) + 14 = 0[/tex]

[tex]5\left(y + \dfrac{57}5\right)^2 - \dfrac{57^2}5 + 14 = 0[/tex]

[tex]5\left(y + \dfrac{57}5\right)^2 = -\dfrac{3179}5[/tex]

This system has no real solutions since the square of any real number must be positive.

If we allow complex numbers, we can continue solving to end up with two complex solutions for y,

[tex]\left(y + \dfrac{57}5\right)^2 = -\dfrac{3179}{25}[/tex]

[tex]y + \dfrac{57}5 = \pm i \sqrt{\dfrac{3179}{25}}[/tex]

[tex]y = -\dfrac{57}5 \pm i\dfrac{17\sqrt{11}}5[/tex]

and we can go on to solve for x.

Hence my comment; I suspect you meant to write the system

[tex]\begin{cases}x-\frac45 y = 9\frac45 \\ -14x - 4y = -46\end{cases}[/tex]

because its solution is far simpler. Multiplying through the first equation by 5 gives

[tex]5\times x - 5 \times \dfrac45 y = 5 \times 9\dfrac45[/tex]

[tex]\implies 5x - 4y = 49[/tex]

(since we know 9 + 4/5 = 49/5)

Meanwhile, multiplying through the second equation by -1 gives

[tex]-1 \times (-14x) + (-1) \times (-4y) = -1 \times (-46)[/tex]

[tex]\implies 14x + 4y = 46[/tex]

So if we combine the two equations, we can eliminate y and solve for x :

[tex](5x - 4y) + (14x + 4y) = 49 + 46[/tex]

[tex]\implies 19x = 95[/tex]

[tex]\implies \boxed{x = 5}[/tex]

and solving for y gives

[tex]14x + 4y = 46[/tex]

[tex]\implies 70 + 4y = 46[/tex]

[tex]\implies 4y = -24[/tex]

[tex]\implies \boxed{y = -6}[/tex]