ylinder has a base radius of 9 feet and a height of 4 feet. What is its volume in cubic feet, to the nearest tenths place?

Answer:

$10/hour

Step-by-step explanation:

Solving

Take two points and find slope

Slope

Pay rate 10$/h

Answer:

$168.75

Step-by-step explanation:

In the morning you'll have a time of about 4 hours.

In the afternoon you'll have 8.5 hours.

You take these and add them together 4 + 8.5 = 12.5

Then you take your sum and multiply it by the wage you make per hour 13.50 x 12.5 = $168.75

The volume of this right prism that has a triangular base is equal to 108 cubic meters.

Mathematically, the volume of a right prism is given by this formula:

V = L x W x H

Where:

Given the following data:

Length of base = 6 meters.

Width of base = 4 meters. cm.

Height of prism = 4.5 meters.

Substituting the given parameters into the formula, we have;

V = 6 x 4 x 5

V = 108 cubic meters.

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Answer: 54 m³

Step-by-step explanation: proof with more answers

Answer:

b no.is the correct answer.

Use the slope formula and pick any two points  to find the slope.

m= Y2- Y1/x2-x1

I picked the points (1,8) (3,14).

14-8/3-1= 6/2= 3

Hope this helps .

Answer:

2x/x+2

Step-by-step explanation:

Factor out 2x in the numerator

Then you get: 2x(x+4)

Factor the denominator

Two numbers that multiply to 8 and add to 6(2 and 4)

So you get: (x+2)(x+4)

Now you have: (2x(x+4))/(x+2)(x+4)

Simplify by cancelling the x+4

2x/x+2

Hey there!

Answer: [tex] \Rightarrow \boxed {\sf{\frac{2x}{(x+2)}}}[/tex]

Solving steps:-

[tex] \rightarrow\sf{\frac{ {2x}^{2} + 8x}{ {x}^{2} + 6x + 8} }[/tex]

[tex] \rightarrow\sf{\frac{ 2x(x + 4)}{ {x}^{2} + 4x +2x + 8} }[/tex]

[tex] \rightarrow\sf{\frac{ 2x(x + 4)}{ x (x + 4) +2(x + 4)} }[/tex]

[tex] \rightarrow\sf{\frac{ 2x\sout{(x + 4)}}{ \sout{(x + 4)} (x + 2)} }[/tex]

[tex] \rightarrow\sf{\frac{ 2x}{ (x + 2)} }[/tex]

~Done~

Answer: Answer:

A. is your answer

When using the Slope Method, your answer is y - 5 = 4(x - 2).

Feel free to give brainliest.

Have a great day everyone!

This being a piecewise function, trying to solve f(2), we must find which two equations we can use.

We can use the function '3x + 1' because its domain is 'x is greater than or equal to 2

   --> f(2) = 3(2) + 1 = 7

Hope that helps!

Answer:

x⁴ - 8x² + 9

Step-by-step explanation:

The Area of the smallest square is A1 = x . x = x²

The Area of the second square is A2 = ( x² - 3 )(x² - 3)

A2 = x⁴ - 3x² - 3x² + 9

A2 = x⁴ - 6x² + 9

The Area of the Shaded shape is A2 - A1

x⁴ - 6x² + 9 - x²

x⁴ - 8x² + 9

Answer:

$40

Step-by-step explanation:

Old Sale Price = $100

It was given 60% discount

 60% of 100 = 0.6 x 100 = 60

we remove the discount from  the original price( 100 -60 ) =  40.

So the new sale price for the pants are now $40

Answer:

it's 2.9 that's how. I get the qnswer

4) -0.3 = -1/3 < -1/7 since the bigger a negative number is the less positive it is. 1/8 is positive so it is clear that it should be placed last. & thus do all options this way.

5) B

Area of a triangle = ½ bh.

where b = base &

h = height.

Area of outer shape = (½ x 16 x 12) in^2.

= 96 in^2.

Area of unshaded inner shape = (½ x 3 x 4) in^2.

= 6 in^2.

Area of shaded region = (96 – 6) in^2.

= 90 in^2.

How far both planes travelled is an illustration of distance

Both planes are 510 km apart at 2 pm

The rates of the two planes are given as:

Plane A = 300km/h

Plane B = 45km/h

Calculate the difference (r) in their rates

r = 300km/h - 45km/h

This gives

r = 255km/h

At 2 pm, both planes have travelled for 2 hours.

So, the distance between them is:

d = 255 * 2

d = 510km

Hence, both planes are 510 km apart at 2 pm

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Answer:

B

Step-by-step explanation:

(8,12)=(x1, y1)

(1,3)=(X2, y2)

distance=√(x2-x1)^2+(y2-y1)^2

=√(1-8)^2+(3-12)^2

=√(49+81)

√130

=11.40

[tex]\dfrac{3a^2-6a+3}{a^2-1}\\\\=\dfrac{3(a^2 -2a+1)}{(a+1)(a-1)}\\\\=\dfrac{3(a-1)^2}{(a+1)(a-1)}\\\\=\dfrac{3(a-1)}{a+1}\\\\=\dfrac{3a-3}{a+1} ~~~\text{for}~ a\neq 1[/tex]

Answer:

[tex]\begin{aligned}{&\cos \theta=\frac{10}{26} \\\bf{&\tan \theta=\frac{24}{10}}\end{aligned}[/tex]

Step-by-step explanation:

Since the angle is in the first quadrant, the values of all trigonometric functions are positive. Also. the formulas for the trigonometric functions we need to find from the problem are shown below:
[tex]\begin{aligned}\cos \theta &=\frac{x}{r} \\\tan \theta &=\frac{y}{x}\end{aligned}[/tex]

Based on the formulas listed, the value of y and r are y = 24 and r = 26 respectively. This means that in order to determine the value of the other functions, we need In compute for the value of x using the Pythagorean Theorem:

[tex]\begin{aligned}r^{2} &=x^{2}+y^{2} \\r^{2}-y^{2} &=x^{2}+y^{2}-y^{2} \quad\left[\text { \text{Subtracting \ both \ sides \ of \ the \ equation\ by} } y^{2}\right] \\r^{2}-y^{2} &=x^{2} \\\sqrt{r^{2}-y^{2}} &=\sqrt{x^{2}} \\\sqrt{r^{2}-y^{2}} &=x \\\sqrt{26^{2}-24^{2}} &=x \\10 &=x\end{aligned}[/tex]Then, substituting this to the formula to determine the answers yields:

[tex]\begin{aligned}\cos \theta &=\frac{x}{r} \\&=\frac{10}{26} \\\tan \theta &=\frac{y}{x} \\&=\frac{24}{10}\end{aligned}[/tex]

Therefore, the answers are:

[tex]\begin{aligned}&\cos \theta=\frac{10}{26} \\&\tan \theta=\frac{24}{10}\end{aligned}[/tex]

Answer:

See below

Step-by-step explanation:

We are here given that ,

[tex]\longrightarrow \sin\theta =\dfrac{24}{26}[/tex]

And we would like to find out other trigonometric ratios ( since it is not mentioned about which two I will find out all 6 ) . As we know that ,

[tex]\longrightarrow \sin\theta =\dfrac{perpendicular}{hypotenuse} =\dfrac{p}{h}[/tex]

So that ,

[tex]\longrightarrow \dfrac{p}{h} =\dfrac{24}{26}[/tex]

Let us assume the given ratio to be 24x : 26x .

So we can say that ,

Now let's find out the value of base , so that we can find out the other ratios .

By Pythagoras Theorem ,

[tex]\longrightarrow (perpendicular) ^2+(base)^2=(hypotenuse) ^2[/tex]

Substitute the respective values ,

[tex]\longrightarrow (26x)^2=(24x)^2+b^2\\[/tex]

[tex]\longrightarrow 676x^2 = 576x^2+b^2\\ [/tex]

[tex]\longrightarrow b^2=100x^2\\[/tex]

[tex]\longrightarrow b =\sqrt{100x^2}\\[/tex]

[tex]\longrightarrow \boldsymbol{ b = 10x } [/tex]

Now we may find the other ratios as ,

[tex]\longrightarrow \cos\theta = \dfrac{base}{hypotenuse}=\dfrac{10x}{26x}=\boxed{\boldsymbol{\dfrac{5}{13}}}\\[/tex]

[tex]\longrightarrow \tan\theta =\dfrac{perpendicular}{base}=\dfrac{24x}{10x}=\boxed{\boldsymbol{\dfrac{12}{5}}}\\[/tex]

[tex]\longrightarrow \cosec\theta =\dfrac{hypotenuse}{perpendicular}=\dfrac{26x}{24x}=\boxed{\boldsymbol{\dfrac{13}{12}}}\\ [/tex]

[tex]\longrightarrow \sec\theta =\dfrac{hypotenuse}{base}=\dfrac{26x}{10x}=\boxed{\boldsymbol{\dfrac{13}{5}}} \\[/tex]

[tex]\longrightarrow \cot\theta =\dfrac{base}{perpendicular}=\dfrac{10x}{24x}=\boxed{\boldsymbol{\dfrac{5}{12}}} [/tex]

And we are done !

The value of sin(80°)cos(20°) – cos(80°)sin(20°) using the trignometry property is √3/2.

The difference formula in trignometry for the sine funciton is given as,

[tex]\sin(A-B)=\sin(A)\cos(B) -\cos(A)\sin(B)[/tex]

The trignometric equation given in the problem is,

[tex]\sin(80^o)\cos(20^o) -\cos(80^o)\sin(20^o)[/tex]

Compare this equation with the above eqution, we get,

[tex]A=80^o\\B=20^o[/tex]

Thus, this equation can be written as,

[tex]\sin(80^o)\cos(20^o) -\cos(80^o)\sin(20^o)=\sin(80-20)\\\sin(80^o)\cos(20^o) -\cos(80^o)\sin(20^o)=\sin(60)\\\sin(80^o)\cos(20^o) -\cos(80^o)\sin(20^o)=\dfrac{\sqrt{3}}{2}[/tex]

Hence, the value of sin(80°)cos(20°) – cos(80°)sin(20°) using the trignometry property is √3/2.

Learn more about the difference formula in trignometry here;

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Answer:

6

Step-by-step explanation:

because 5 is greater than 4

Step-by-step explanation:

Answer:

11.42

Step-by-step explanation:

since the diameter is 66 cm, then its radius is half that or 33 cm.

[tex]\textit{arc's length}\\\\ s=r\theta ~~ \begin{cases} r=radius\\ \theta =\stackrel{radians}{angle}\\[-0.5em] \hrulefill\\ r=33\\ \underset{complete~turn}{\theta =2\pi ~\hfill } \end{cases}\implies s=(33)(2\pi )\implies s=66\pi \implies s\approx 207.34~cm[/tex]

Answer:

N = -1

explanation:

x = N

solving steps:

[tex]\sf f(x)=x^2+2x-15[/tex]

To find symmetry of a quadratic function.

                                                                   vertex formula    :   [tex]\sf x=\dfrac{-b}{2a}[/tex]

[tex]a=1,\:b=2[/tex]

[tex]\sf x=\dfrac{-2}{2\cdot \:1}[/tex]

[tex]\sf x = -1[/tex]

Then,

N = -1

Answer for first question: x-intercept(s): (92,0)(92,0) y-intercept(s): (0,−95) for second question : x-intercept(s): (23,0)(23,0) y-intercept(s): (0,−12)

Step-by-step explanation:

Answer:

20% off

Step-by-step explanation:

Divide:

72.8/364

Answer:

.20

Convert:

.20=20%

The shopkeeper giving 80% discount on the Christmas tree during the sale.

A discount is an amount that is subtracted from the regular price of an item.

[tex]discount \ percent = \frac{original \ price - final \ price }{original \ price } \times 100[/tex]

According to the given question.

The marked price of the Christmas tree i.e. original price = $364.

The price of the Christmas tree on sale i.e. final price  = $72.80

So,

The discount given on the Christmas tree

= Original price - final price

= $364 - $72.80

= 291.2

Therefore,

Discount percent  = [tex]\frac{291.2}{364} (100)= 80 \ percent[/tex]

Hence, the shopkeeper giving 80% discount on the Christmas tree during the sale.

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Answer:

False.

Step-by-step explanation:

Because 12 and 9 are both multiples of 3.

Answer:

The answer should be C. 250 in^3

Answer:

C. 250 in^3

Step-by-step explanation:

Answer:

x-y=3

Step-by-step explanation:

Answer:

[tex]x - y = 3[/tex]

is

[tex]y - 3 = (x - 6)[/tex]

in standard form

The equations that has a leading coefficient of 3, and a constant of -2 are:

0 = 3x² + 2x – 2

0 = –3x + 3x² – 2

0 = –1x – 2 + 3x²

A leading coefficient is the term that has the highest degree in a polynomial expression.

A constant is a term that has only numbers and contains no variable.

We are given the following equations:

The first, third, and last equations each has a leading coefficient of 3 and a constant of -2.

Therefore, the equations that has a leading coefficient of 3, and a constant of -2 are:

0 = 3x² + 2x – 2

0 = –3x + 3x² – 2

0 = –1x – 2 + 3x²

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