The required solution of the differential equation is given as y² = -4logx + 9.
The method of determining the derivative of an implicit function by differentiating each term separately, expressing the derivative of the dependent variable as a symbol, and solving the resulting expression for the symbol.
here,
Given the differential equation,
Y’+2/x*y=0
Y' = -2/xy
y (dy/dx) = -2/x
ydy = -2/xdx
y²/2 = -2logx + C
From the initial condition y(1)=3
9/2 = -2log1 + c
c = 9/2
Now,
y²/2 = -2logx + 9/2
y² = -4logx + 9
Thus, the required solution of the differential equation is given as y² = -4logx + 9.
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NO LINKS!!! URGENT HELP PLEASE!!!
1. Sketch several rectangles with a perimeter of 20 meters. Include some with small areas and some large areas, Label the dimensions of each rectangle.
In the image you can see some rectangles with different dimensions, to scale.
What is a rectangle?A rectangle is a geometric figure that is characterized by:
has four angleshas four sidesIt has two sides (base and top) that are longer than the other two sides.How to find the perimeter of a rectangle?To find the perimeter of a rectangle we must add all its sides. In this case we must illustrate a 20 m rectangle so we can draw the following variants:
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Oxana's account has an annual interest rate of 7.1% compounded monthly. What is the annual percentage yield for Oxana's account?
Answer: The annual percentage yield (APY) takes into account both the interest rate and the frequency of compounding. It is a measure of the effective rate of return over a year, taking into account the effect of compounding.
In Oxana's account, with a 7.1% interest rate
Step-by-step explanation:
You need to construct a 94% confidence interval for a population proportion. What is the upper critical value of zto be used in constructing this interval? A. 0.9699
B. 1.96
C. 1.555
D. -1.88
E. 1.88
The upper critical value to be used in constructing a 94% confidence interval is 1.88.
What is meant by confidence interval?
A confidence interval is a range of estimates for an unknown parameter in frequentist statistics. At a specified level of confidence, a confidence interval is calculated. The mean of your estimate plus and minus the range of that estimate constitutes a confidence interval.
In statistics, confidence is another word for probability. The most typical level of confidence is 95%, however, higher levels, such as 90% or 99%, are occasionally employed.
The confidence interval is given as 94% = 0.94
Based on the normal population, a confidence interval for a population proportion is calculated, and a normal probability table is then used to determine the critical value.
So if the confidence interval is 94%, the rest 6% of the data will be present outside the given confidence interval.
Out of the 6%, 3% of data will be present on either side of the interval.
So the critical value will be the value of [tex]z_{\frac{\alpha }{2} } = z_{0.03 }[/tex] = 1.88.
Therefore the upper critical value to be used in constructing a 94% confidence interval is 1.88.
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a) Factorise x²-2x-3
b) Hence, simplify
2x-1
x²-2x-3
1
X-3
Answer:
x²-2x-3 using factorisation method
Step-by-step explanation:
x²-3x+1x-3
x(x-3) 1(x-3)
(x+1) (x-3)
x=-1,x=+3
Let f be a continuous function on an interval [a, b]. Then there is a number 1, called the definite integral off on [a,b], such that for each e > 0 there is a 8 >0 so that n f($)(** – -1) - I <€ 1-1
The definite integral of a continuous function on an interval [a, b] represents the area under the graph of the function within that interval. It provides a mathematical way to measure the accumulation of change of the function over that interval.
The definite integral of a function f on the interval [a, b] is denoted by ∫f(x)dx over the interval [a, b]. This integral can be approximated by dividing the interval [a, b] into smaller subintervals and calculating the area under the graph of the function over each subinterval. The smaller the subintervals, the closer the approximation will be to the actual definite integral.
The definite integral is said to be a limit, meaning that as the size of the subintervals approaches zero, the sum of the areas under the graph over each subinterval approaches a definite value, which is the definite integral.
In mathematical terms, for each positive number e, there exists a positive number δ such that if the subintervals have width less than δ, then the difference between the sum of the areas under the graph and the definite integral will be less than e. This means that the definite integral provides a precise value for the area under the graph of the function over the interval [a, b].
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Given the general form:
F( x )= a(x^2)+bx+c
Convert it to vertex form (also known as standard form) by putting the values for a,h and k into the correct boxes.
F(x)=a(x-h)^2+k
Identify the vertex
(x,y)
General form: F( x )=6 x^2+1 x +1
Vertex form: F( x )= Answer field 1 for part 1
(x- Answer field 2 for part 1
)^2 +Answer field 3 for part 1
Vertex: (Answer field 1 for part 2
,Answer field 2 for part 2
)
The coordinates of the vertex will be (-1/12, 23/24).
What is a Quadratic equation?ax²+bx+c=0, with a not, equals 0 is a quadratic equation, which is a second-order polynomial equation in a single variable. It has at least one solution because it is a second-order polynomial equation, which is guaranteed by the algebraic fundamental theorem. The answer could be simple or complicated.
Given, a quadratic equation F( x )=6 x²+ x +1
Compared with the general formula of the quadratic equation ax²+bx+c=0,
a = 6
b = 1
c = 1
Solving the equation:
F( x )=6 x²+ x +1
F( x ) - 1 =6 x²+ x
f(x) - 1 = 6(x² + x/6)
f(x) -1 = 6(x² + x/6 + 1/144 - 1/144)
f(x) - 1 = 6(x + 1/12)² - 1/24
f(x) = 6(x + 1/12)² - 1/24 + 1
f(x) = 6(x + 1/12)² + 23/24
From the general formula of a quadratic equation to vertex form will be
F(x) = a(x-h)² + k
h will be -1/12 and k will be 23/24
therefore, The coordinates of the vertex will be (-1/12, 23/24).
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Show that the function f ∶ R^2 → R given by f(x, y) = e^x does not have
any local or global extrema.
The required function f ∶ R² → R given by f(x, y) = eˣ does not have any local or global extrema.
What is a global extreme point?A global extreme point, also known as a global maximum or minimum, is the highest or lowest value that a function attains over its entire domain. In other words, it is the maximum or minimum value of the function over the whole range of inputs, rather than just a specific interval or region.
Here,
The function f(x, y) = eˣ only depends on x and is not a function of y. This means that it does not have any extrema since its value can be arbitrarily close to zero or arbitrarily close to infinity for different x-values, and therefore it does not attain a maximum or minimum value. This holds both locally and globally.
Thus, the required function f ∶ R² → R given by f(x, y) = eˣ does not have any local or global extrema.
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can someone tell me how solve this problem?
Using the midpoint formula we will see that the coordinates of B are (-9, 1)
How to find the coordinates of point B?We know that for two points (x, y) and (a, b) the midpoint is at:
( (x + a)/2, (y + b)/2)
In this case if the coordinates of B are (x, y), we can write the equation:
(-2, 4) = ( (x + 5)/2, (7 + y)/2)
We can solve these two equations to find the coordinates of point B, we will get:
(x + 5)/2 = -2
x + 5 = -4
x = -4 - 5 = -9
And:
(7 + y)/2 = 4
7 + y = 4*2 = 8
y = 8 - 7 = 1
The coordinates of B are (-9, 1)
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Miguel has $30. He spends $6.75 on a movie ticket, $3.70 for snacks, and $1.25 for bus fare each way.
How much money does Miguel have left?
I need help with Questions 2,3,4and6
Answer:
Step-by-step explanation:
2-A
3- trapezium
4 - perpendicular
6- A
Which equation correctly represents the situation: A campground charges $5 plus $ 25 per person for rent. Use x and y for the unknown variables.
In Problems 1 and 2,y=1/(1+c1e-x) is a one-parameter family ofsolutions of the first-order DE y'=y-y2. Find asolution of the first-order IVP consisting of this differentialequation and the given initial condition.
1. y(0)=-1/3
Answer:
[tex]\displaystyle y=\frac{1}{1-4e^{-x}}[/tex]
Step-by-step explanation:
[tex]\displaystyle y=\frac{1}{1+C_1e^{-x}}\\\\-\frac{1}{3}=\frac{1}{1+C_1e^{-0}}\\\\-\frac{1}{3}=\frac{1}{1+C_1}\\ \\ 3=-1-C_1\\\\4=-C_1\\\\-4=C_1[/tex]
Thus, the specific solution to the IVP given the initial condition is [tex]\displaystyle y=\frac{1}{1-4e^{-x}}[/tex]
HELP PLEASE ITS DUE TMR
The value of the given expression is -6
What is an expression?
Mathematical expressions consist of at least two numbers or variables, at least one arithmetic operation, and a complete sentence. Any one of the following mathematical operations can be used. A sentence has the following structure: Number/variable, Math Operator, Number/Variable is an expression.
f(-2) value is the value of f(x) when x= -2
From the graph ,
f(-2)= 0
g(7)=2
Given:
-5 * f(-2) - 3*g(7)
= -5*0 - 3*2
First multiplication ,then subtraction from left to right
= 0- 3*2
=0-6
= -6
So, the value of the given expression is -6
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(photo attached)
pls help overdue!!
Answer:
k = 5.6
Step-by-step explanation:
[tex]\frac{10}{7} = \frac{8}{k}[/tex]
Cross-multiplication is applied:
(10)(k) = (8)(7)
10k = 56
k needs to be isolated and made the subject of the formula:
k = [tex]\frac{56}{10}[/tex]
k = 5.6
20 points!!!!! hope you can get it
Value of angle x = 70°
What are alternate angles?Alternate angles are angles that occur on opposite sides of the transversal line and have the same size. There are two different types of alternate angles, alternate interior angles and alternate exterior angles.
Given,
ACD = 35
BCE = 105
ABC = x
By, the figure
BA || CD
⇒ ACD = BAC (alternate angles on AC)
⇒ BAC = 35°
BCE = 105
Exterior angle is equal to sum of two opposite interior angles in the triangle.
BCE = BAC + ABC
105 = 35 + x
x = 105 - 35
x = 70°
Hence,
70° is measure of x.
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Determine the monthly payment for the installment loan.
Amount Financed (P) = $15,000
Annual Percentage Rate (R) = 5%
Number of Payments per Year (N) = 12
Time in Years (T) = 3
The monthly payment is $_____?
(Round to the nearest cent as needed.)
The monthly payment is $453.125.
How to calculate simple interest amount?If the initial amount (also called as principal amount) is P, and the interest rate is R% annually, and it is left for T years for that simple interest, then the interest amount earned is given by:
[tex]I = \dfrac{P \times R \times T}{100}[/tex]
Given;
Amount Financed (P) = $15,000
Annual Percentage Rate (R) = 5%
Number of Payments per Year (N) = 12
Time in Years (T) = 3
Now, monthly payment;
=(p*i*(1+i)^n)/((1+i)^n-1)
=15000(0.05/12)(1+0.05/12)^36/(1+0.05/12)^36-1
= 72.5/0.16
=453.125
Therefore, the monthly payment by 5% interest will be $453.125.
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9. Alicia had 3 feet of wood. She used
8
3 feet of wood. Estimate the amount of
4
wood Alicia has left.
Answer: Alicia had 3 feet of wood and she used 3 feet, so she has 3 - 3 = 0 feet of wood left.
Since we are asked to estimate the amount of wood, we could round 3 to the nearest whole number and say that Alicia has approximately 0 feet of wood left.
Step-by-step explanation:
The manager of a bookshop ordered 70 copies of Teen magazine;
s of these were charged at £1.90 each and the remainder, t, were
charged at a discounted price of £1.70 p each.
The bill for all 70 copies was £124.
How many magazines were charged at the discounted price?
Answer:
Let's call the number of magazines charged at £1.90 each "x".
So, the number of magazines charged at £1.70 each is "t=70-x".
The total cost of the x magazines is x * £1.90, and the total cost of the t magazines is t * £1.70.
The total bill for all 70 magazines is £124, so we can write an equation:
x * £1.90 + t * £1.70 = £124
x * £1.90 + (70-x) * £1.70 = £124
Expanding the equation, we get:
x * £1.90 + 70 * £1.70 - x * £1.70 = £124
x * £1.90 - x * £1.70 = £124 - 70 * £1.70
x * (£1.90 - £1.70) = £124 - 70 * £1.70
x * £0.20 = £124 - 70 * £1.70
x = (£124 - 70 * £1.70) / £0.20
Now that we have an expression for x, we can use a calculator to solve for it.
x = (124 - (70 * 1.70)) / 0.20 = 40.
So, 40 magazines were charged at £1.90 each and 70 - 40 = 30 magazines were charged at £1.70 each.
A park has two rectangular, fenced playgrounds. The first playground has a perimeter of 160 feet. The second playground is twice as long and twice as wide as the first playground. Which of these could be the perimeter of the second playground in feet? pls help now ty
a. 640
b. 320
c. 240
d. 168
The perimeter of the second park will be 320 feet. The correct option is C.
What is the perimeter?The perimeter is defined as the sum of all the sides of the object. For a rectangular park, the perimeter will be the sum of all the sides of the rectangular park.
Given that a park has two rectangular, fenced playgrounds. The first playground has a perimeter of 160 feet.
The perimeter of the first park:-
160 = 2 ( L + W )
L + W = 80
The perimeter of the second park,
P = 2 ( 2L + 2W )
P = 4 ( L + W )
P = 4 x 80
P = 320 feet
Therefore, the perimeter will be 320 feet.
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–1/2 (12x – 2) = –6x – 1
Answer:
To solve this equation, we need to isolate the variable x on one side of the equation. To do this, we can start by adding 1/2 (12x - 2) to both sides of the equation:
-1/2 (12x - 2) + 1/2 (12x - 2) = -6x - 1 + 1/2 (12x - 2)
Combining like terms on the right side of the equation, we get:
0 = -6x + 12x - 1 + (12x - 2) / 2
Simplifying further:
0 = 6x - 1 + 6x
Combining like terms again:
0 = 12x - 1
Adding 1 to both sides:
1 = 12x
Finally, dividing both sides by 12:
x = 1/12
Step-by-step explanation:
Answer: No solution.
Step-by-step explanation:
1.) Distribute -1/2
-6x + 1 = -6x - 1
2.) Move over terms to combine
0 = -2
There is no solution to this equation.
find an equation of the line passing through the given points use function notation to write the equation (4, 2) and (2, 4)
Answer:
The equation of the line passing through the points (4, 2) and (2, 4) is y = -x + 6.
Step-by-step explanation:
Given the points (4, 2) and (2, 4), we can use the point-slope form of a line, which is given by:
y - y1 = m(x - x1)
where (x1, y1) is a point on the line, m is the slope of the line, and (x, y) are the coordinates of any other point on the line.
To find the slope m, we can use the formula:
m = (y2 - y1) / (x2 - x1)
Plugging in the values for the two points, we get:
m = (4 - 2) / (2 - 4) = 2 / -2 = -1
Next, we'll substitute one of the points and the slope into the point-slope form:
y - 2 = -1 (x - 4)
Expanding the right-hand side, we get:
y - 2 = -x + 4
Adding x and 2 to both sides, we get:
y = -x + 6
So, the equation of the line passing through the points (4, 2) and (2, 4) is y = -x + 6.
Someone please help mee
The table shows the amounts of each day is attached below.
What is an equation?An equation is an expression that shows the relationship between two or more numbers and variables.
The total amount of snow that falls in three days equals the sum of the amount of snow that falls each day, then
s1 + s2 + s3 = Ts
Here s1 is the snow that fell on day 1, s2 on day 2, s3 on day 3 and Ts is the total amount of snow that fell over the three days.
We need to calculate the amount of snow that fell on the first two days by multiplying the total snow by the given fractions, like this:
s1 = 1/6 * 2 = 1/3
s2 = 7/12*2 = 7/6
Now ,
1/3+ 7/6+ s3 = 2
1.5 + s3 = 2
1.5 - 1.5 + s3 = 2 - 1.5
s3 = 2 - 1.5
s3 = 1/2
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go and give every Answer a 5 star at https://brainly.in/question/30885306#:~:text=Answer%3A%20In%20the%20lab%2C%20I%20discovered%20the%20air,areas%20usually%20experience%20either%20foggy%20or%20sunny%20weather.
I identified the Atmospheric conditions such as air pressure, temperature, and relative humidity conditions that cause snow, rain, thunderstorms, fog, and clear sky in the lab. I discovered that low-pressure zones typically have snow, rain, and stormy weather, and high-pressure areas typically have foggy or bright weather.
How do atmospheric conditions influence weather patterns?Atmospheric conditions, such as temperature, pressure, humidity, wind direction, and the presence of fronts, greatly influence weather patterns.
Changes in air pressure result in winds, which can transport warm or cold air, moisture, and storms. High humidity leads to clouds and precipitation, while low humidity often results in clear skies.
Note that temperature differences between different air masses can create fronts, which are boundaries separating different air masses, leading to changes in weather.
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Full Question:
"How do atmospheric conditions influence weather patterns?
Mr. Tabor believes that less than 75% of the students at his school completed their math homework last night. The math teachers inspect the homework assignments from a random sample of 50 students at the school.The math teachers inspect the homework assignments from a random sample of 50 students at the school. Only 68% of the students completed their math homework.We want to test H0:p=0.75;Ha:p<0.75H0:p=0.75;Ha:p<0.75, where pp = the true proportion of the students at Mr. Tabor’s school who completed their math homework last night. A significance test yields a PP-value of 0.1265.What it would mean for the null hypothesis to be true in this setting?
The required explanation for hypothesis test is described.
How take hypothesis test?When the null hypothesis is true in this setting, it means that the true proportion of students at Mr. Tabor's school who completed their math homework last night is equal to 0.75, or 75%. This is the value that Mr. Tabor initially believed, but the sample data suggests that only 68% of the students completed their homework.
A PP-value is the probability of observing a sample proportion as extreme or more extreme than the sample proportion, given that the null hypothesis is true. In this case, the PP-value of 0.1265 is not small enough to reject the null hypothesis. A commonly used significance level is 0.05, which means that if the PP-value is less than 0.05, the null hypothesis would be rejected.
So, given the PP-value of 0.1265, which is greater than 0.05, we cannot reject the null hypothesis and must conclude that there is not enough evidence to suggest that the true proportion of students who completed their homework is less than 0.75. This means that, based on the sample data, the null hypothesis that the true proportion is equal to 0.75 is not ruled out, and there is not enough evidence to support the alternative hypothesis that the true proportion is less than 0.75.
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50 POINTS!!! GIVING BRAINLIEST TO CORRECT ANSWER
Answer:
reflection over the x axis
vertical stretch of 2
vertical translation down 1 unit
Step-by-step explanation:
-2 [tex]\sqrt[3]{x}[/tex] -1
The negative in front is a reflection over the x axis
The 2 is a vertical stretch of 2
The subtraction of 1 at the end is a vertical translation down 1 unit
Harry invests a lump sum of money in a bond fund with a fixed annual interest rate of 7% that is compounded continuously.
After 17 years, the balance reaches $10,775.05. How much was initially invested?
The initial investment was $4,176.69
What is investment?Investment is the dedication of money to purchase of an asset to attain an increase in value over a period of time.
To find initially invested we can use the formula for continuously compounded interest to find the initial investment:
A = Pe^(rt)
Where:
A is the final balance ($10,775.05)P is the initial investmentr is the annual interest rate (7%)t is the number of years (17)So, solving for P:
P = A / e^(rt)
P = $10,775.05 / e^(0.07 * 17)
P = $10,775.05 / 2.56724943786794
P = $4,176.69
Therefore, the initial investment was $4,176.69.
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MATH
NATION
GR.2.4 Homework February 6, 2023
< Back to Assignments
A tissue box is 9 inches (in.) long, 4 in. wide, and 7 in. tall. What is the surface area of the tissue box?
Answer:
f(x) in ²
Duration: 00:01:41
Pre
Answer:
254in^2
Step-by-step explanation:
(SA)=2lw+2lh+2hw
L -> 9 W ->4 H -> 7
2(9)(4)+2(9)(7)+2(7)(4)
18*4+18*7+14*
72+126+56
198+56
254
If a rock is thrown from the ground with an initial velocity of 80 feet per second, then
the height of the rock, in feet, at t seconds can be modeled by
() = −162 + 80, 0 ≤ ≤ 5.
a) v(t) = -32t + 80 feet/second and a(t)= -32 feet/second²
b. t = 3 seconds.
c. 24 feet/second > 0).
d. the time at which the rock reaches its highest height is 2.5 seconds and 80 feet respectively.
e. the acceleration is given by a(2.5) = -32 feet/second²
How to calculate?The velocity, v(t), of the rock is given by the derivative of the position function s(t) with respect to time,
v(t) = ds(t)/dt = -32t + 80 feet/second.
The acceleration, a(t) = dv(t)/dt = -32 feet/second²
b) v(3) = -32*3 + 80 = 24 feet/second.
This quantity represents the velocity of the rock at t = 3 seconds.
c) At t = 3 seconds, the rock is rising up because the velocity is positive (v(3) = 24 feet/second > 0).
d) the time at which the rock reaches its highest height,
v(t) = 0, we get -32t + 80 = 0, so t = 80/32 = 2.5 seconds.
The height of the rock will be found using the position function s(t), so s(2.5) = -16(2.5)^2 + 80(2.5) = 80 feet.
e) At the highest height, the velocity of the rock is 0, so the acceleration is given by a(2.5) = -32 feet/second².
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CAN SOMEONE HELP PLEASE?✨
The presented statement states that the economic profit at units has a numerical value of -512 dollars per unit.
In C, what is a function definition?A function is a collection of several statements that work together to complete a job. Every C program we use contains at least one function, which is main (). The programs can then declare a number of extra routines in a language.
Revenue function is R (q) = 7q² + 400q
Differentiate with respect to q
R'(q) = - 7(2q) + 400.......(1)
R'(q) = - 14q + 400
Substitute q = 8 in eqn.(1)
MR(8) = -14(8) + 400
= - 112 + 400
MR(8) = -512 $ per unit
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The width of a rectangle is 4y-3.5 feet and the length is 3.5y+10 feet. Find the perimeter of the rectangle.