Answer:
49
Step-by-step explanation:
To find the number we add to both sides to complete the square, we do b divided by 2 all squared.
(b/2)²
In this case, we have b = 14
(14/2)²
7²
49
Answer: 49
Step-by-step explanation:
To complete the square, the second leading coefficient divided by 2 squared will give you the number need to add to both sides.
For example,
14 is the second leading coefficient in the so if you divide it by 2 you get 7 and 7 squared is 49.
Only 40% of the students in a certain liberal arts college are males.Question 10 of 11 If two students from this college are selected at random, what is the probability that they are both males
Answer:
0.16
Step-by-step explanation:
Given;
40% males.
If two students are selected at random, probability (P) that they are both males is given as follows;
P = P(1) x P(2)
Where;
P(1) = Probability that the first one is a male
P(2) = Probability that the second one is also a male
Remember that there are 40% males.
This means that 40 out of 100 students selected is going to be a male.
Therefore, for the first selection, any of the 40 students could be selected. The probability P(1), that the first one is male is therefore;
40 / 100 = 0.4
Also,
Assuming there is replacement, for the second selection, any of the 40 students could be selected. The probability P(2), that the second one is also male is therefore;
40 / 100 = 0.4
Now, from;
P = P(1) x P(2)
P = 0.4 x 0.4
P = 0.16
The probability that they are both males is therefore 0.16
Please help me! Find the answer and earn 10 points
Answer:
384 square m
Step-by-step explanation:
As per description given in the question, the field is of parallelogram shape. Diagonal divides the parallelogram in two triangles
So, area of field = area of triangle 1 + area of triangle 2
Area of field
= 1/2*32 * 10 + 1/2 * 32 * 14
= 32* 5 + 32 * 7
= 32(5 + 7)
= 32 * 12
= 384 square m
The perimeter of a rectangle is 42 inches. If the width of the rectangle is 6 inches, what is the length?
A.12 inches
B.15 inches
C.21 inches
D.40 inches
Answer:
b.15 inches
Step-by-step explanation:
subtract 12 (2 6inch sides) from the perimeter
get 30 and divide by 2 to get 2 sides
Answer:
B. 15 inches.
Step-by-step explanation:
A rectangle shares two pairs of congruent opposite sides.
Perimeter = 42
Let:
the length of the rectangle = l
the width of the rectangle = w = 6
Perimeter = l + l + w + w
Plug in 42 for perimeter & 6 for w in the equation:
42 = l + l + 6 + 6
Combine like terms:
42 = ( l + l ) + (6 + 6)
42 = 2l + 12
Next, isolate the variable, l. Do the opposite of PEMDAS. First, subtract 12 from both sides:
42 (-12) = 2l + 12 (-12)
42 - 12 = 2l
30 = 2l
Next, divide 2 from both sides:
(30)/2 = (2l)/2
l = 30/2
l = 15
B. 15 inches is the length of the rectangle.
Check:
l + l + w + w = 42
15 + 15 + 6 + 6 = 42
30 + 12 = 42
42 = 42 (True).
~
Can you write a raitional number in fraction form that is equivalent to - 1.5
Answer:
-3/2.
Step-by-step explanation:
0.5 = 1/2
-1.5 = -1 1/2
= -3/2.
- 1.5 = - 15/10
- 15⁽⁵/10 = - 3/2
- ²⁾15/10 = - 30/20
- ³⁾15/10 = - 45/30
etc
what is 3a^5 over 2 in a verbal expression
please help me!!!!!!!!
Answer:
see explanation
Step-by-step explanation:
Using the double angle identity for cosine
cos2x = 2cos²x - 1
Given
cos( [tex]\frac{0}{2}[/tex] ) = [tex]\frac{1}{2}[/tex]( p + [tex]\frac{1}{p}[/tex] ) , then
cosΘ = 2[ [tex]\frac{1}{2}[/tex](p + [tex]\frac{1}{p}[/tex] ) ]² - 1
= 2 [ [tex]\frac{1}{4}[/tex](p² + 2 + [tex]\frac{1}{p^{2} }[/tex] ) ] - 1 ← distribute by 2
= [tex]\frac{1}{2}[/tex](p² + 2 + [tex]\frac{1}{p^{2} }[/tex] ) - 1 ← distribute by [tex]\frac{1}{2}[/tex]
= [tex]\frac{1}{2}[/tex] p² + 1 + [tex]\frac{1}{2p^2}[/tex] - 1
= [tex]\frac{1}{2}[/tex] p² + [tex]\frac{1}{2p^2}[/tex] ← factor out [tex]\frac{1}{2}[/tex] from each term
= [tex]\frac{1}{2}[/tex] ( p² + [tex]\frac{1}{p^{2} }[/tex] ) ← as required
Answer:
Step-by-step explanation:
Hello, please consider the following.
[tex]cos(\theta)=2cos^2(\dfrac{\theta}{2})-1\\\\=2\left(\dfrac{p+\dfrac{1}{p}}{2}\right)^2-1\\\\=\dfrac{p^2+\dfrac{1}{p^2}+2}{2}-1\\\\=\dfrac{1}{2}(p^2+\dfrac{1}{p^2})+1-1\\\\=\dfrac{1}{2}(p^2+\dfrac{1}{p^2})[/tex]
Thank you
what is the equation of a line that is perpendicular to y=-5x+11 and passes through the point (3,3)?
Answer:
[tex]y=\frac{1}{5}x+\frac{12}{5}[/tex]
Step-by-step explanation:
The slope of a line that is perpendicular to another will have an opposite-reciprocal slope. So, if the slope was -2, then the perpendicular slope would be [tex]\frac{1}{2}[/tex] .
[tex]y=-5x+11[/tex]
This is written in slope-intercept form:
[tex]y=mx+b[/tex]
m is the slope and b is the y-intercept. Find the opposite-reciprocal of the slope, -5:
[tex]y=\frac{1}{5} x+b[/tex]
Now we need to find the y-intercept. For this, substitute the given points for its appropriate value:
[tex](3_{x},3_{y})\\\\3=\frac{1}{5}(3)+b[/tex]
Solve for b:
Simplify multiplication:
[tex]\frac{1}{5}*\frac{3}{1}=\frac{3}{5}[/tex]
Insert:
[tex]3=\frac{3}{5}+b[/tex]
Subtract b from both sides:
[tex]3-b=\frac{3}{5}+b-b\\\\3-b=\frac{3}{5}[/tex]
Subtract 3 from both sides:
[tex]3-3-b=\frac{3}{5}-3\\\\-b=\frac{3}{5}-3[/tex]
Simplify subtraction:
[tex]\frac{3}{5}-3\\\\\frac{3}{5}-\frac{3}{1}\\\\\frac{3}{5}-\frac{15}{5}=-\frac{12}{5}[/tex]
Insert:
[tex]-b=-\frac{12}{5}[/tex]
Multiply both sides by - 1 to simplify b (it can be seen as -1b):
[tex]-b*(-1)=-\frac{12}{5}*(-1)\\\\b=\frac{12}{5}[/tex]
Insert:
[tex]y=\frac{1}{5}x+\frac{12}{5}[/tex]
:Done
Question 5(Multiple Choice Worth 4 points)
(02.01)A class has 9 boys and 15 girls. What is the ratio in simplest form that compares number of boys to total number of
students?
Answer:
boys: total
3 8
Step-by-step explanation:
boys:girls: total
9 : 15 : 9+15
9 15 24
Divide each by 3
3 5 8
We want the ratio of boy to total
boys: total
3 8
Find the distance between A(5,-8) and B(2,9) to the nearest hundredth.
Answer:
The answer is 17.26 unitsStep-by-step explanation:
The distance between two points can be found using the formula
[tex]d = \sqrt{ ({x1 - x2})^{2} + ({y1 - y2})^{2} } \\ [/tex]
where
(x1 , y1) and (x2 , y2) are the points
From the question the points are
A(5,-8) and B(2,9)
The distance between them is
[tex] |AB| = \sqrt{ ({5 - 2})^{2} + ({ - 8 - 9})^{2} } \\ = \sqrt{ {3}^{2} + ({ - 17})^{2} } \\ = \sqrt{9 + 289} \\ = \sqrt{298} [/tex]
| AB | = 17.26267
We have the final answer as
17. 26 units to the nearest hundredth
Hope this helps you
make k the subject of formula sq. root h/k =3
Answer:
k = h/9.
Step-by-step explanation:
√(h/k) = 3
Squaring both sides:
h/k = 9
9k = h
k = h/9.
Answer:
k=h/9
Step-by-step explanation:
sqrt(h/k)=3
1. square both sides
h/k=3^2
2. make k the subject
k=h/9
why must there be at least 2 lines on any given plane?
Answer:
there must be at least two lines on any plane because a plane is defined by 3 non-collinear points.
Step-by-step explanation:
Solve the inequality below. Use the drop-down menus to describe the solution and its greah -72 +13 > 41 Click the arrows to choose an answer from each menu. The solution to the inequality is Choose... . A graph of the solution should have Choose... and be shaded to the Choose... | 60
Answer:
x<= -4
filled in circle at -4
Round [tex]\frac{x}{10x-3}[/tex] to the nearest whole number, where x = 0.30103.
Answer:
29
Step-by-step explanation:
Given the function f(x) = x/10x-3, if x = 0.30103;
substituting the value of x into the function;
f(0.30103) = 0.30103/10(0.30103) - 3
f(0.30103) = 0.30103/(3.0103 - 3)
f(0.30103) = 0.30103/0.0103
f(0.30103) = 29.226
f(0.30103) = 29 (to nearest whole number).
What is 2000-3x400+111?
Answer:
2000-1200+111
2000-1311
689 ans.
Step-by-step explanation:
by bodmas ( bracket,of,divide, multiplication, addition, substract )
so, first we'll multiply
3x400=1200
so,
2000-1200+111
second , we'll add
1200+111 = 1311
so,
2000-1311
third , at last we'll subtract
2000-1311 = 689
so,
Ans. 689
hope the ans. is correct :)
At the Canterbury Dog Fair, 1/4 of the poodles are also show dogs and 1/7 of the show dogs are poodles. What is the least possible number of dogs at the fair?
Answer:
10
Step-by-step explanation:
Let the total number of poodles = [tex]x[/tex]
Let the total number of show dogs = [tex]y[/tex]
[tex]\frac{1}{4}[/tex] of the poodles are show dogs
and
[tex]\frac{1}{7}[/tex] of the show dogs are poodles
[tex]\therefore \dfrac{1}{4}x = \dfrac{1}{7} y[/tex]
As per the question statement, [tex]x[/tex] must be divisible by 4 and
[tex]y[/tex] must be divisible by 7.
And we have to find the least number of dogs.
So, least number divisible by 4 = 4 and
Least number divisible by 7 = 7
So, least values of [tex]x[/tex] i.e. poodles = 4 in which we have 1 show dog
Hence, 3 are not show dogs.
and least value of show dogs i.e. [tex]y[/tex] = 7 (it includes the one poodle which is also show dog).
So, least number of dogs at the fair = 7 + 3 = 10
The numbers 1-4 are each written on an index card. The 4 cards are put into a bag and 2 of them are drawn at random. What is the probability that the sum of the two cards drawn are greater than 5? I actually know the answer to this question (1/3), however, I don’t know how to solve it; please include an explanation.
Answer:
Step-by-step explanation:
Write a list of all possible outcomes
1-2
1-3
1-4
2-1
2-3
2-4
3-1
3-2
3-4
4-1
4-2
4-3
There are 12 possible outcomes. How many of them have totals of 6 or 7
I count 4
So the probability is 4/12 = 1/3, just as you said.
Is there an easier way?
You might be able to get the 12 easier.
You have 4 choices for the first number and 3 for the second.
P(12) = 4*3 = 12
Getting 6 or 7 might be somewhat trickier.
4 and 3 make seven. That gives two ways 4-3 and 3-4
4 and 2 make six. That gives 2 more ways 4-2 and 2-4
That's all that's possible.
answer: 4 ways make success. The total number of ways is 12.
Find the area of quadrilateral ABCD. A. 27.28 units² B. 33.08 units² C. 28.53 units² D. 26.47 units²
Answer:
[tex] \boxed{ \boxed{ \bold{ \purple{ \sf{28.53 \: {units}^{2} }}}}}[/tex]Option C is the correct option.
Step-by-step explanation:
For ABD
[tex] \sf{ = \frac{2.89 + 8.59 + 8.6}{2} }[/tex]
[tex] \sf{ = \frac{20.08}{2} }[/tex]
[tex] \sf{ = 10.04}[/tex]
∆ ABD = [tex] \sf{ = \sqrt{10.04(10.04 - 2.89)(10.04 - 8.59)(10.04 - 8.6)} }[/tex]
[tex] \sf{ = \sqrt{10.04 \times 7.15 \times 1.45 \times 1.44 }}[/tex]
[tex] \sf{ = \sqrt{149.8891} }[/tex]
[tex] \sf{ = 12.2429}[/tex]
For ∆ ACD ,
[tex] \sf{s = \frac{8.6 + 4.3 + 7.58}{2} }[/tex]
[tex] \sf{ = \frac{20.48}{2} }[/tex]
[tex] \sf{ = 10.24}[/tex]
∆ ACD = [tex] \sf{ = \sqrt{10.24(10.24 - 8.6)(10.24 - 4.3)(10.24 - 7.58} }[/tex]
[tex] \sf{ \sqrt{10.24 \times 1.64 \times 5.94 \times 2.66} }[/tex]
[tex] \sf{ = \sqrt{265.3456} }[/tex]
[tex] \sf{ = 16.2894}[/tex]
Area of quadrilateral ABCD = [tex] \sf{12.2429 + 16.2894}[/tex]
[tex] \sf{ = 28.5323}[/tex]
[tex] \sf{ = 28.53}[/tex] units ²
Hope I helped!
Best regards!
If tan fº = 2/1 and the measure of yw is 8 units, what is the measure of xw?
2units
4units
7units
8 units
Answer:
The measure of [tex]x_{w}[/tex] is 4 units.
Step-by-step explanation:
According to the definition of tangent, it is equal to:
[tex]\tan f = \frac{y_{w}}{x_{w}}[/tex]
Where:
[tex]f[/tex] - Angle, measured in sexagesimal degrees.
[tex]x_{w}[/tex] - Adjacent side, measured in units.
[tex]y_{w}[/tex] - Opposite side, measured in units.
If [tex]\tan f = \frac{2}{1}[/tex] and [tex]y_{w} = 8\,units[/tex], the adjacent side is:
[tex]x_{w} = \frac{y_{w}}{\tan f}[/tex]
[tex]x_{w} = \frac{8\,units}{\frac{2}{1} }[/tex]
[tex]x_{w} = 4\,units[/tex]
The measure of [tex]x_{w}[/tex] is 4 units.
The measure of xw is 4 units
Trigonometry identityGiven the following parameters
Tan fº = 2/1
This shows that;
Opposite side YW = 2
Adjacent side XW = 1
Given that YW is 8units, using the ratio of similar sides
2/1 = 8/XW
2XW = 8
XW = 4
Hence the measure of xw is 4 units
Learn more on similar figures here: https://brainly.com/question/2644832
What is the general form of a converse statement?
Answer:
To form the converse of the conditional statement, interchange the hypothesis and the conclusion. The converse of "If it rains, then they cancel school" is "If they cancel school, then it rains." To form the inverse of the conditional statement, take the negation of both the hypothesis and the conclusion.
Which decimals are less than 2.312 select all that apply A. 2.311. B.2.4 C.2.32 D.2.3 E.2.31 F.2.313
Answer:
A, D, E
Step-by-step explanation:
I hope this is correct
Answer:
a d e
Step-by-step explanation:
Help!!!!!!!!!!!!!!!!!
Answer:
x= -2
Step-by-step explanation:
3(2x-4)= -24
expand
6x-12= -24
6x= -24+12
6x= -12
x= -12/6
x= -2
Answer:
x=-2
Step-by-step explanation:
To solve the equation, we must get x isolated on one side of the equation.
[tex]3(2x-4) = -24[/tex]
3 is being multiplied by 2x -4. The inverse of multiplication is division. Divide both sides of the equation by 3.
[tex]\frac{3(2x-4)}{3} = -\frac{24}{3}[/tex]
[tex](2x-4)= -\frac{24}{3}[/tex]
[tex](2x-4)= -8[/tex]
4 is being subtracted from 2x. The inverse of subtraction is addition. Add 4 to both sides of the equation.
[tex]2x-4 +4 = -8+4[/tex]
[tex]2x= -8+4[/tex]
[tex]2x= -4[/tex]
x is being multiplied by 2. The inverse of multiplication is division. Divide both sides by 2.
[tex]\frac{2x}{2} =\frac{-4}{2}[/tex]
[tex]x=\frac{-4}{2}[/tex]
[tex]x= -2[/tex]
Let's check our solution. Plug -2 in for x and solve.
[tex]3(2x-4)= -24[/tex]
[tex]3(2(-2)-4)= -24[/tex]
[tex]3(-4-4) = -24[/tex]
[tex]3(-8)= -24[/tex]
[tex]-24=-24[/tex]
The statement above is true, so we know our solution is correct.
The answer to the equation is x= -2.
There are 21 fish in an aquarium. If 3/7 of the fish are goldfish, how many goldfish are in the aquarium?
Answer:
9
Step-by-step explanation:
21 x 3/7
= 9 ( goldfish )
Answer:
9 goldfishes
Step-by-step explanation:
Total fish = 21
Number of goldfish = 3/7 of 21
[tex]= \frac{3}{7}*21\\\\= 3 * 3\\\\= 9[/tex]
The fox population in a certain region has a continuous growth rate of 5% per year. It is estimated that the population in the year 2000 was 10,100 foxes.
a) Find a function that models the population,P(t) , after (t) years since year 2000 (i.e. t= 0 for the year 2000).
b) Use your function from part (a) to estimate the fox population in the year 2008.
c) Use your function to estimate the year when the fox population will reach over 18,400 foxes. Round t to the nearest whole year, then state the year.
Answer:
P(t) = A * (1 + r)^t ;
14,922 ;
Year 2013
Step-by-step explanation:
Given the following :
Continuous growth rate(r) = 5% = 0.05
Population in year 2000 = Initial population (A) = 10,100
Time(t) = period (years since year 2000)
A)
Find a function that models the population,P(t) , after (t) years since year 2000 (i.e. t= 0 for the year 2000).
P(t) = A * (1 + r)^t
Trying out our function for t = year 2000, t =0
P(0) = 10,100 * (1 + 0.05)^0
P(0) = 10,100 * 1.05^0 = 10,100
B.)
Use your function from part (a) to estimate the fox population in the year 2008.
Year 2008, t = 8
P(8) = 10,100 * (1 + 0.05)^8
P(8) = 10,100 * 1. 05^8
P(8) = 10,100 * 1.4774554437890625
= 14922.29
= 14,922
c) Use your function to estimate the year when the fox population will reach over 18,400 foxes. Round t to the nearest whole year, then state the year.
P(t) = A * (1 + r)^t
18400 = 10,100 * (1.05)^t
18400/10100 = 1.05^t
1.8217821 = 1.05^t
1.05^t = 1.8217821
In(1.05^t) = ln(1.8217821)
0.0487901 * t = 0.5998151
t = 0.5998151 / 0.0487901
t = 12.293787
Therefore eit will take 13 years
2000 + 13 = 2013
A family reduced the consumption of sugar from 10 kg to 8kg per month due to increase in price. Find the percentage decrease in consumption.
Answer:
20%
Step-by-step explanation:
Step 1: Find the decrease in consumption
10kg - 8kg = 2kg
So the family decrease their consumption of sugar by 2kg
Step 2: We have to find what percent did the family reduce their sugar consumption
We can divide how much they reduced by with the original amount
2kg/10kg = 1/5 kg or 20%
Therefore the family reduced the consumption of sugar by 20$
7xy - 2z use the expression above to identify the terms, factors, coefficient(s), and constant.
the product of two numbers multiplied by 7
Answer:
7(x times y)
Step-by-step explanation:
Product means multiply, so it wants you to multiply two numbers and multiply THAT by 7. So we will use two variables, in this case, I will use x and y. X times y. 7 Times that.
Answer:
7xy
Step-by-step explanation:
Let's go by parts
The product of two numbersMultiplied by 7The product of two numbers, since we don't know what are they we can called them x and y so the product means the multiplication
[tex]x*y=xy[/tex]
next xy has to be multiplied by 7
[tex]7*xy=7xy[/tex]
so 7xy is our answer
Write an algebraic expression to represent the new x-coordinate after a translation of two yards east given any initial x-coordinate, x.
Answer: x' = x - 2yd.
Step-by-step explanation:
When we have a function:
y = g(x)
A translation to the east (in this case the positive x-axis) of N units.
is written as:
y = h(x) = g(x - N)
then if in the beginning our variable was x, afther the translation the variable will be x - N.
Now in this case we have a translation of 2yd to the right (to the east)
Then our new variable, let's call it x', will be:
x' = x - 2yd.
Answer:
A translation of two yards east involves moving 2 units in the positive x-direction. Given any initial x-coordinate, x, the algebraic expression that represents the new x-coordinate after the translation is x + 2.
Step-by-step explanation:
Edementum answer.
please someone help me!!!!!!
Answer:
see explanation
Step-by-step explanation:
Using the identity
cos2Θ = 1 - 2sin²Θ, then
1 - 2sin²([tex]\frac{\pi }{4}[/tex] - [tex]\frac{0}{2}[/tex] )
= cos [2([tex]\frac{\pi }{4}[/tex] - [tex]\frac{0}{2}[/tex] )]
= sos([tex]\frac{\pi }{2}[/tex] - Θ )
= cos[tex]\frac{\pi }{2}[/tex]cosΘ + sin
= 0 × cosΘ + 1 × sinΘ
= 0 + sinΘ
= sinΘ = right side
Answer: see proof below
Step-by-step explanation:
Use the Difference Identity: sin (A + B) = sin A cos B - cos A sin B
Use the following Half-Angle Identities:
[tex]\sin\bigg(\dfrac{A}{2}\bigg)=\sqrt{\dfrac{1-\cos A}{2}}\\\\\cos\bigg(\dfrac{A}{2}\bigg)=\sqrt{\dfrac{1+\cos A}{2}}[/tex]
Use the Pythagorean Identity: cos²A + sin²A = 1 --> sin²A = 1 - cos²A
Use the Unit Circle to evaluate: [tex]\cos\dfrac{\pi}{4}=\sin\dfrac{\pi}{4}=\dfrac{1}{\sqrt2}[/tex]
Proof LHS → RHS
[tex]\text{Given:}\qquad \qquad \qquad 1-2\sin^2\bigg(\dfrac{\pi}{4}-\dfrac{\theta}{2}\bigg)\\\\\text{Difference Identity:}\quad 1-2\bigg(\sin\dfrac{\pi}{4}\cdot \cos \dfrac{\theta}{2}-\cos \dfrac{\pi}{4}\cdot \sin\dfrac{\theta}{2}\bigg)^2\\\\\text{Unit Circle:}\qquad \qquad 1-2\bigg(\dfrac{1}{\sqrt2}\cos \dfrac{\theta}{2}-\dfrac{1}{\sqrt2}\sin \dfrac{\theta}{2}\bigg)^2\\\\\\\text{Half-Angle Identity:}\quad 1-2\bigg(\dfrac{\sqrt{1+\cos A}}{2}-\dfrac{\sqrt{1-\cos A}}{2}\bigg)^2[/tex]
[tex]\text{Expand Binomial:}\quad 1-2\bigg(\dfrac{1+\cos A}{4}-\dfrac{2\sqrt{1-\cos^2 A}}{4}+\dfrac{1-\cos A}{4}\bigg)\\\\\text{Simplify:}\qquad \qquad \quad 1-2\bigg(\dfrac{2-2\sqrt{1-\cos^2 A}}{4}\bigg)\\\\\text{Pythagorean Identity:}\quad 1-\dfrac{1}{2}\bigg(2-2\sqrt{\sin^2 A}\bigg)\\\\\text{Simplify:}\qquad \qquad \qquad 1-\dfrac{1}{2}(2-2\sin A)\\\\\text{Distribute:}\qquad \qquad \qquad 1-(1-\sin A)\\\\.\qquad \qquad \qquad \qquad \quad =1-1+\sin A\\\\\text{Simplify:}\qquad \qquad \qquad \sin A[/tex]
RHS = LHS: sin A = sin A [tex]\checkmark[/tex]
∠A and ∠ B ∠B are supplementary angles. If m ∠ A = ( x + 15 ) ∘ ∠A=(x+15) ∘ and m ∠ B = ( x − 13 ) ∘ ∠B=(x−13) ∘ , then find the measure of ∠ B ∠B.
Answer:
∠B = 76°
Step-by-step explanation:
Supplementary angles add up to 180 degrees, so we know that angles A and B add up to 180.
We can set up an equation and solve for x:
(x + 15) + (x - 13) = 180
Add like terms:
2x + 2 = 180
2x = 178
x = 89
Now, we can plug in 89 as x to find the measure of angle B:
x - 13
89 - 13
= 76
= 76°
how do you know that the product 221×331 is rational?
221 is rational since 221 = 221/1
So is 331 because 331 = 331/1
The product of any two rational numbers is also rational
--------------------------
Proof:
Let x = p/q and y = r/s be two rational numbers. The q and s values are nonzero.
Their product is
x*y = (p/q)*(r/s)
x*y = (p*q)/(r*s)
which is a ratio of two integers pq and rs, so (p*q)/(r*s) is rational