X-rays carry more energy than visible light. Compare the frequencies and wavelengths of these two types of EM radiation.

The linear speed of the hoop's center of mass just as the hoop leaves the incline and rolls onto a horizontal surface can be calculated using the equation for conservation of energy is  5.41 m/s.

The equation is KEf = KEi + PEi.

where, KEf is the kinetic energy of the hoop just as it leaves the incline and KEi is the initial kinetic energy of the hoop at the beginning of the incline and PEi is the initial potential energy of the hoop at the beginning of the incline. The initial potential energy of the hoop is equal to the mass of the hoop (3.2 kg) multiplied by the acceleration due to gravity (9.8 m/s2) multiplied by the height of the incline (1.40 m):

PEi = 3.2 kg × 9.8 m/s² × 1.40 m = 44.56 J

The initial kinetic energy of the hoop is equal to 0, since the hoop is starting from rest.

Therefore, the equation for conservation of energy can be written as follows:

KEf = 0 + 44.56 J

The kinetic energy of the hoop just as it leaves the incline is equal to the mass of the hoop (3.2 kg) multiplied by the linear speed of the hoop's center of mass (v) squared, divided by two:

KEf = 3.2 kg × (v²) / 2

By combining the two equations above, we can solve for the linear speed of the hoop's center of mass just as the hoop leaves the incline and rolls onto a horizontal surface:

v = √(2 × 44.56 J / 3.2 kg) = 5.41 m/s

Therefore, the linear speed of the hoop's center of mass just as the hoop leaves the incline and rolls onto a horizontal surface is 5.41 m/s.

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The distance from which the 14 kg mass have to fall is 40.4 m and the speed at which the mass would be moving on Mars when the drum gains 150.0 J of kinetic energy is 11.7 m/s.

The mass required to fall through a distance of 5.00 m is 14.0 kg. When it comes to the gravitational acceleration of Earth, the mass of 14.0 kg requires 150.0 J of kinetic energy to be supplied to the drum. On Mars, the same system would operate with a gravitational acceleration of 3.71 m/s².

To figure out the distance that the 14.0-kg mass will have to fall on Mars to give the same amount of kinetic energy, use the following formula:

PE = mgh

PE = KE (because KE = work done = energy given to the drum)

Substituting the values, we get:

KE = mgh (on earth)

KE = 150.0 J

m = 14.0 kg, g = 9.81 m/s², h = distance fallen

On Mars, we will need to use the formula:

KE = mgh

KE = mgh (on Mars)

KE = 150.0 J

m = 14.0 kg, g = 3.71 m/s², h = distance fallen

h = 40.4 m

KE = 1/2 mv² + mgh

where, KE = 150.0 J

m = 14.0 kg

g = 3.71 m/s²

h = distance fallen

Substituting the above values, we get:

KE = 1/2 mv² + mgh

150.0 = 1/2 × 14.0 × v² + 14.0 × 3.71 × h

Substituting the value of h from part (a) gives:

150.0 = 1/2 × 14.0 × v² + 14.0 × 3.71 × 40.4

Now we can solve the above equation for v:

v = 11.7 m/s

Therefore, the speed at which the mass would be moving on Mars when the drum gains 150.0 J of kinetic energy is 11.7 m/s.

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The correct option is D; The cart moved at a constant velocity of 0.5m/s for the entire 7 seconds.

Constant acceleration is represented as a horizontal line on the acceleration graph. The slope of the velocity graph represents the acceleration. On the velocity graph, constant acceleration Equals constant slope = straight line.

Acceleration is represented in a velocity-time graph by the slope, or steepness, of the graph line. If the line slopes upward, as seen in the figure between 0 and 4 seconds, velocity increases, and acceleration is positive. The velocity-time graph will be a curve when the acceleration increases with time, as anticipated by the equation: v = u + at.

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Dealing with continuously variable data such as sound and light waves is called signal processing.

Signal processing is the manipulation of signals to extract useful information or transform them into a desired form. It is a broad field that encompasses many different applications, including audio and video processing, communication systems, radar systems, and control systems.

Signal processing techniques can be used to analyze and manipulate sound waves, such as filtering out unwanted noise, compressing or expanding dynamic range, or modifying the frequency spectrum of a signal. In the case of light waves, signal processing techniques can be used to remove noise, enhance contrast or color, or manipulate the spatial frequency content of an image.

There are many different tools and techniques that can be used in signal processing, depending on the specific application. Some common techniques include Fourier analysis, which decomposes a signal into its frequency components, and digital signal processing, which involves the use of digital algorithms to manipulate signals.

Overall, signal processing is a fundamental aspect of many modern technologies and is used in a wide range of applications, from audio and video processing to medical imaging and telecommunications.

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One of the actions that can be taken to help Joshua trees to survive climate change is protecting them from the direct impact of human activities.

Joshua trees are a part of the Agavaceae family and are also known by the name of Yucca brevifolia. It is a type of tree-like yucca that grows in arid regions such as the Mojave Desert. These trees are known for their unique, spiky green leaves and their rough trunk that has sharp leaves which grow upward. Joshua trees have a lifespan of about 500 to 1000 years and can grow up to 40 feet tall.

Joshua trees are being threatened due to climate change. Climate change is affecting their natural habitat and therefore, they cannot germinate and grow as easily as they used to do before. As a result, the number of Joshua trees is on the decline. To ensure the survival of these trees, we need to act immediately.

One of the most effective ways to help the Joshua trees survive climate change is to protect them from the direct impact of human activities. There are various ways to do this such as reducing carbon emissions, minimizing deforestation, promoting reforestation, and more. If we want these trees to survive, we need to act now to prevent further damage to their habitat. By protecting these trees from the negative effects of climate change, we can ensure their survival and preserve their beauty for generations to come.

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Parts of the mixer become hot because some of the electrical energy is converted into heat energy.

When electrical energy flows through a wire, it encounters resistance, which causes the wire to heat up. In a mixer, the electric motor converts electrical energy into mechanical energy to rotate the blades, but some of the electrical energy is lost as heat due to resistance in the motor's winding and other electrical components. This heat energy can accumulate in the mixer's parts and cause them to become hot. In many electrical devices, heat is an undesirable byproduct of energy conversion and can lead to reduced efficiency, damage, or safety hazards.

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--The complete Question is,  Fill in the blanks. " Parts of the mixer become hot because some of the electrical energy is changed into____"--

If the metal sphere is positively charged, then the excess electrons will move to the metal sphere. But if it's negatively charged, the excess electrons will repel the metal sphere.

The magnetic field at the center of the loop is calculated to be 0.159 T.

The magnetic field at the center of a flat, circular loop with 17 turns, a radius of 12.5 cm, and a current of 0.60 A can be determined by using the equation B = µ₀.n.I/2.π.r, where

Using this equation, the magnetic field at the center of the loop is calculated to be 0.159 T.

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Given passage is a story reading about a community called "Sitio Katamakawan" and their unhealthy living and lifestyle.

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Explanation:

Planets closer to the sun will appear to transit from time to time

   = 2      Venus and Mercury     ( I suppose you could include the Moon..an eclipse ....haha)

All of the planets further from the sun than earth will not transit

Potentially ALL of the planets could transit the sun (earth included)  if observed outside solar system   HOWEVER if you are not observing from near the orbital plane of

the planets NONE of them would transit

For maximum transits, the planets should all be in the same orbital plane and the observer should be very close to this plane also.

The horizontal force is 44 kg m/s². The ratio of this force to the skater's weight is 0.69 kg m/s²/kg.

The track contains straight stretches and 16-metre-diameter semicircles for short-track speed skating. Suppose that a skater weighing 64 kg completes the turn at a constant speed of 11 m/s.

1) The horizontal force on the skater is determined by the centripetal force equation, F = mv²/r, where F is the force, m is the mass, v is the velocity, and r is the radius.

Using the given parameters, the horizontal force is therefore 64 kg x 11 m/s²/16 m = 44 kg m/s².

2) The ratio of this force to the skater's weight can be calculated by dividing the force (44 kg m/s²) by the weight (64 kg).

(44 kg m/s²) ÷64 kg = 0.69 kg m/s²/kg.

This gives a ratio of 0.69 kg m/s²/kg.

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We can apply the formula [tex]v = \sqrt{(14.715 m/s^2 * r)}[/tex]   to determine the peregrine falcon's speed. A falcon can reach a centripetal acceleration that is 1.5 times the acceleration of free fall.

We can use the centripetal acceleration formula to find the speed of the peregrine falcon in this scenario:

[tex]a_c = v^2 / r[/tex]

where [tex]a_c[/tex]is the centripetal acceleration, v is the speed of the peregrine falcon, and r is the radius of the circular turn.

We are given that the centripetal acceleration of the peregrine falcon is 1.5 times the free-fall acceleration, which we can approximate as 9.81 m/s². Therefore, we have:

[tex]a_c = 1.5 * 9.81 m/s^2\\a_c = 14.715 m/s^2[/tex]

We can also assume that the radius of the circular turn is a characteristic of the maneuvering ability of the peregrine falcon, and is independent of its speed. Therefore, we can write:

[tex]a_c = v^2 / r[/tex]

Solving for v, we get:

[tex]v = \sqrt{(a_c * r)}[/tex]

Substituting the values we obtained earlier, we get:

[tex]v = \sqrt{(14.715 m/s^2 * r)}[/tex]

Therefore, the speed of the peregrine falcon in this tight circular turn depends on the radius of the turn. If we know the radius, we can use the equation [tex]v = \sqrt{(14.715 m/s^2 * r)}[/tex] to calculate the speed of the peregrine falcon.

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The average force exerted on the car during this time is 4850 N.

We can use the equation F = ma to find the average force exerted on a 970 kg car that starts from rest on a horizontal roadway and accelerates eastward for 5.00 seconds when it reaches a velocity of 25.0 m/s. Here is the solution to the problem:

Given,

Mass of the car, m = 970 kg

Initial velocity of the car, u = 0

Final velocity of the car, v = 25.0 m/s

Time is taken by the car to attain the final velocity, t = 5.00 s

Acceleration of the car, a = (v - u) / t = (25.0 - 0) / 5.00 = 5.00 m/s²

Average force exerted on the car during this time, F = m × a= 970 kg * 5.00 m/s²= 4850 N

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The substituent in Phenol is added to the ortho and para positions of the benzene ring. The substituent in Benzaldehyde is added to the ortho and para positions of the benzene ring.

The substituent in Bromobenzene is added to the ortho and para positions of the benzene ring. The substituent in Nitrobenzene is added to the meta position of the benzene ring. The substituent in Toluene is added to the ortho and para positions of the benzene ring.

Substituents on different aromatic compounds. The substituent is added to different positions for each of the aromatic compounds if they undergo electrophilic aromatic substitution. The positions where the substituents are added to Phenol, Benzaldehyde, Benzoic Acid, Bromobenzene, Nitrobenzene, and Toluene are described below:

Phenol- The substituent in Phenol is added to the ortho and para positions of the benzene ring.

Benzaldehyde- The substituent in Benzaldehyde is added to the ortho and para positions of the benzene ring.

Benzoic Acid- The substituent in Benzoic acid is added to the meta position of the benzene ring.

Bromobenzene- The substituent in Bromobenzene is added to the ortho and para positions of the benzene ring.

Nitrobenzene- The substituent in Nitrobenzene is added to the meta position of the benzene ring.

Toluene- The substituent in Toluene is added to the ortho and para positions of the benzene ring.

Thus, we can see that the positions of the substituent in each aromatic compound depend on the particular compound that undergoes electrophilic aromatic substitution.

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The potential energy of the ball at this point is maximum as the ball has the highest height at this point.
The momentum of the ball at this point is given by the product of mass and velocity. As the velocity of the ball is zero, its momentum is also zero.
Momentum = 0, KE = 0, PE > 0
Hence, the ranks of quantities at each point are as follows:
A) C, B = D, A
B) C, B = D, A
C) A, B = D, C

The ball is at rest at the left of the metal track. It is assumed to have enough friction to roll, but not enough to reduce its speed. In this question, we have to rank the quantities from the greatest to the least at each point. Given below are the quantities that are to be ranked,

a) Momentum,

b) KE,

c) PE.
Rank of quantities at each point:
At point A: Here, the ball has the maximum height. It is at rest at this point. At this point, the ball has the highest potential energy, PE.
PE>KE=0
The velocity of the ball at this point is zero. Hence, the kinetic energy of the ball is zero.
The momentum of the ball is given by the product of mass and velocity. As the velocity of the ball is zero, its momentum is also zero.
Momentum = 0, KE = 0, PE > 0
At point B: At this point, the ball has converted some of its potential energy into kinetic energy. The ball has lost some of its height, and hence, its potential energy.
[tex]PE>BKE, KE>BPE[/tex]
As the ball is moving, it has some velocity. Hence, it has kinetic energy.
The momentum of the ball at this point is given by the product of mass and velocity. As the velocity of the ball is non-zero, its momentum is also non-zero.
Momentum > 0, KE > 0, PE < 0
At point C: At this point, the ball has lost all its potential energy, and all of it is converted into kinetic energy.
[tex]KE>CPE, PEC=0[/tex]
The velocity of the ball is the highest at this point. Hence, the kinetic energy of the ball is the highest at this point.
The momentum of the ball at this point is given by the product of mass and velocity. As the velocity of the ball is the highest at this point, its momentum is also the highest.
Momentum > 0, KE > 0, PE = 0
At point D: At this point, the ball has lost all its kinetic energy due to friction. Hence, it comes to rest at this point.
KE=0, PED>0

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Options b and c are correct. These two are the reasons that indicate why one doesn't have to know how the wire is bent.

An electric field is a vector field created by a charged object. When a charged particle interacts with the electric field of another charged particle, it will experience a force, which can be either attractive or repulsive. The electric field at a given point in space is determined by the charge and distribution of charges in the space, as well as by the location and orientation of the observer. The strength of the electric field is measured in units of volts per meter (V/m).

Electric field (E) is not dependent on how the wire is bent, only the diameter of the wire is needed. And since conventional current flows in the direction of [tex]E\rightarrow[/tex], E is the same in every part of the wire with uniform properties. This implies that E must be parallel to the wire at every location even if the wire twists and turns. Therefore, even if the wire is bent, one need not know its shape, as long as the properties remain constant.

Thus, options b and c are the correct answers.

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In simple meters, the beat is divided into two parts, while in compound meters, the beat is divided into three parts.

A meter, or time signature, in music notation is a fraction-like symbol placed at the beginning of a piece of music that indicates the number and duration of beats in each measure. In simple meters, such as 2/4 or 3/4, the beat is subdivided into two parts, which are typically equal in duration. In compound meters, such as 6/8 or 9/8, the beat is subdivided into three parts, each of which is typically shorter than the beat duration and adds up to the beat duration. Compound meters are often used in music genres such as jazz, Latin, and folk music.

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In music theory, a beat is divided into two equal parts in simple meters, while in compound meters, the beat is generally divided into three equal parts. One example of a compound meter is 6/8, where the 6 beats would be split into two groups of 3 beats.

In music theory, specifically relating to rhythm and meter, a beat can be divided into different ways depending on whether the music is in simple meter or compound meter. In simple meters, the beat is divided into two equal parts. However, in compound meters, the beat is typically divided into three equal parts.

For example, if you have a compound meter such as 6/8, there are 6 beats in a measure, and these 6 beats would split into two groups of 3 beats, giving it a 'triplet feel'. This contrasts with a simple meter like 2/4, where the beats would divided into two halves.

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1) The frequency fi of the ith normal mode is given by the equation fi = v/2λi, where λi is the wavelength of the ith mode.

2) The three lowest normal mode frequencies f1, f2, and f3 can be expressed in terms of L, v, and constants as follows: f1=v/2L, f2=v√2/2L, and f3=v2/2L.

3) The frequencies can be listed in increasing order as f1=v/2L, f2=v√2/2L, f3=v2/2L.

A dynamical system's normal mode of motion is a pattern of motion in which every component oscillates sinusoidally at the same frequency and with the same fixed phase relationship. The normal modes' description of free motion occurs at set frequencies. These constant frequencies of a system's normal modes are referred to as its natural or resonant frequencies.

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Water slows down neutrons that are leaving nuclear processes quickly. As the water warms up, steam is produced. Electricity is generated by the turbine that the steam turns.

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Answer:

Explanation:

a) The mass of the cube can be calculated using the equation Mass = Volume x Density. The volume of the cube can be calculated as (5.00×10 cm)^3 = 125 cm³. Substituting this volume into the equation gives Mass = 125 cm³ x 7.86 g/cm³ = 983.5 g.

b) The number of iron atoms in the cube can be calculated using Avogadro's number (6.02 x 10^23 atoms/mol). The number of moles can be calculated using the molar mass of iron, 55.9 g/mol. Thus, the number of moles can be calculated as 983.5 g / 55.9 g/mol = 17.61 moles. Multiplying this by Avogadro's number gives the number of iron atoms in the cube as 1.07 x 10^24 atoms.

According to the wave equation, v = fλ, where v is the wave speed, f is the frequency, and λ is the wavelength. If we increase the wavelength and keep the wave speed the same, the frequency of the wave will decrease.

This is because, if we increase the wavelength but keep the wave speed constant, the wave will have to take longer to complete one full cycle, which means that the number of cycles completed per second (the frequency) will be lower.

Another way to think about this is to consider the relationship between wavelength and frequency in a wave. In general, waves with longer wavelengths have lower frequencies, and waves with shorter wavelengths have higher frequencies. This is because the wavelength represents the distance between two consecutive peaks or troughs in the wave, and the frequency represents the number of cycles completed per unit of time.

If the wavelength increases, the number of peaks or troughs per unit of time will decrease, and thus the frequency will decrease as well.

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Answer:

The mass remains the same since stoichiometrically one mole reacts and one mole is formed

Explanation:

Calcium chloride is reacting with Sodium sulphate to form a white precipitate of calcium sulphate.

[tex]{ \sf{CaCl _{2} + Na_{2} SO_{4} → CaSO _{4} + 2NaCl}}[/tex]

From the equation, 1 mole of calcium chloride forms 1 mole of calcium sulphate.

R.F.M of CaCl2 = 40 + (35.5×2) = 111

R.F.M of CaSO4 = 40 + 32 + (16×4) = 136

R.F.M of Na2SO4 = (23×2) + 32 + (16×4) = 142

R.F.M of 2NaCl = 2[23 + 35.5] = 117

[tex]{ \sf{(r.f.m \: of \: rectants) = (r.f.m \: of \: products)}} \\{ \sf{ (mass \: of \: rectants) = (mass \: of \: products)}} \\ \\ { \sf{(111 + 142) = (136 + 117)}} \\ { \sf{300.23 = x}} \\ \\ { \sf{x = \frac{300.32}{(111 + 142)} \times (136 + 117) }} \\ \\ { \sf{x = \frac{300.32}{253} \times 253 }} \\ \\ { \sf{x = 300.32}}[/tex]

Answer:

The mass remains the same

Explanation:

A resultant force of 5437 N would accelerate an 810 kg mass at 6.7 m/s². The answer that you have entered is 5427 and that is why it says incorrect.

A resultant force is the single force that represents the combined effect of two or more forces acting on an object. It is the net force that results from the vector sum of all the individual forces. The direction and magnitude of the resultant force determine the motion of the object, whether it is at rest, moving at a constant velocity, or accelerating.

To calculate the resultant force, we can use the formula:

Resultant force = mass x acceleration

Plugging in the given values, we get:

Resultant force = 810 kg x 6.7 m/s²

Resultant force = 5437 N

Therefore, a resultant force of 5437 N would accelerate an 810 kg mass at 6.7 m/s².

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The normal force of the car is equal to the weight of the car,  2,652.56 N. The maximum speed the car can have without losing contact with the road is equal to the square root of the product of the normal force of the car and the radius of the hill. That is,9.87 m/s.

A car with a mass of 720kg going over a hill at 12 m/s can be represented by the following Free Body Diagram (FBD):
The normal force of the car can be calculated using the equation
 Normal Force = m × g × cos θ
 where m is the mass of the car, g is the gravitational acceleration (9.81 m/s2), and θ is the angle of the hill.
 Therefore, Normal Force = 720kg × 9.81 m/s2 × cos 70° = 2,652.56 N.
 The maximum speed that the car can have without losing contact with the road at the top of the hill is equal to the square root of the equation
 v2 = (2 × Normal Force × Radius of Curvature) / m
where v is the speed of the car, Normal Force is the calculated normal force of the car, and m is the mass of the car.
Therefore, the maximum speed of the car = √[(2 × 2,652.56 N × 70 m) / 720kg] = 9.87 m/s.  

Therefore normal force of car is 2,652.56 N and maximum speed of car is 9.87 m/s.

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The magnitude of the difference amongst the two vectors is sqrt (13) units.

Let's call the two vectors A and B. We can use the Law of Cosines to find the magnitude of their difference:

|A - B|^2 = |A|^2 + |B|^2 - 2|A||B|cosθ

where θ is the angle between the two vectors.

Substituting the given values, we get:

|A - B|^2 = (3) ^2 + (4) ^2 - 2(3)(4) cos60°

Simplifying, we get:

|A - B|^2 = 9 + 16 - 12

|A - B|^2 = 13

Taking the square root of both sides, we get:

|A - B| = sqrt (13)

Therefore, the magnitude of the difference between the two vectors is sqrt (13) units.

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When an electron is near the Earth's equator, it deflects if its velocity is in the following directions:

When an electron is near the Earth's equator and its velocity is in the direction of:

(a) Downward: The magnetic field lines are perpendicular to the Earth's surface at the equator, so the force on the electron is perpendicular to its velocity. The magnetic force on the electron is in the direction of eastward or westward.

(b) Northward: Magnetic force will act in the direction of eastward.

(c) Westward: Magnetic force will act in the direction of northward.

(d) Southeastward: In the southeastward direction, the magnetic force on the electron will be in the direction of northward.

To sum up, when an electron is near the Earth's equator, the direction of the magnetic force on it changes based on the direction of its velocity.

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Explanation:

All R's in series:    just add them together : 200 + 200 + 200 Ω = 600Ω

One in series with two in parallel :

   = 200 Ω   +    200*200/(200+200) Ω = 300Ω

All three in parallel :

    R = 1 / (1/200 + 1/200 + 1/200) = 66.7 Ω

Because we measured the altitude from the Earth's centre, which is below the surface, the outcome is negative. As a result, the observatory is located 6.37 km below sea level.

Most importantly, placing an observatory on a mountainside means that there is less air to look through, improving the quality of the "seeing". Moreover, there is less air above you on a mountainside to absorb starlight.

The following is the equation for gravitational acceleration at a distance from the Earth's centre:

g = G M / r²

Given that the observatory is located r kilometres above the Earth's surface, we have:

g = G M / (r + Rearth)²

where Rearth is the Earth's radius. The observatory's altitude, h, can be calculated using the following formula:

gsealevel - g = 0.0055 m/s²

G M / (r + Rearth)² - G M / Rearth² = 0.0055 m/s²

G M (1/Rearth² - 1/(r + Rearth)²) = 0.0055 m/s²

r + Rearth = sqrt(G M / (0.0055 m/s² Rearth²) + Rearth²)

r = sqrt(G M / (0.0055 m/s² Rearth²) + Rearth²) - Rearth

Plugging in the values for G, M, and Rearth, we get:

r = sqrt((6.6743 × 10⁻¹¹ m³ kg⁻¹ s⁻²) × (5.9722 × 10²⁴ kg) / (0.0055 m/s² × (6.37 × 10⁶ m)²) + (6.37 × 10⁶ m)) - 6.37 × 10⁶ m

r = 2859.9 m

Therefore, the altitude of the observatory is:

h = r - Rearth = 2859.9 m - 6.37 × 10⁶ m = -6.37 × 10⁶ m + 2859.9 m

h = -6.367 × 10⁶ m

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An arrow fired from a bow keeps moving because of momentum conservation.

When an arrow is fired from a bow, it keeps moving after it leaves the bow because of the conservation of momentum.

When the bowstring is pulled back, the potential energy in the bow is stored as elastic potential energy in the bowstring. When the bowstring is released, the elastic potential energy is transferred to the arrow, which causes the arrow to accelerate forward.

According to Newton's third law of motion, for every action, there is an equal and opposite reaction. When the bowstring exerts a force on the arrow, the arrow exerts an equal and opposite force on the bowstring, causing the bow to recoil backward. This recoil also contributes to the momentum of the arrow.

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To calculate the time between claps, we can use the formula:

time = 2 x distance / speed of sound

Substituting the given values, we get:

time = 2 x 24.0 m / 325 m/s = 0.148 s

Therefore, Sophie waited for 0.148 seconds between claps.

The frequency of 1.5 × 10^12 Hz corresponds to the microwave region of the electromagnetic spectrum. Therefore, the type of radiation emitted is microwave radiation.

The wave speed of the buoy can be calculated using the formula:

wave speed = wavelength / period

Since the buoy rises to its maximum height n times in 4 seconds, its period is 4/n seconds. Therefore, the expression for its wave speed is:

wave speed = 1/(4/n) = n/4 m/s

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