Write the rule that transforms p(x) into q(x), where q(x)=2p(x+3)−6

Hey there! I'm happy to help!

Let's create a basic rectangle with this length to width ratio.

Two sides are 3 and two of them have a length of 2. This would give us a perimeter (distance around) of 10.

We want to find a rectangle with a perimeter of 35 meters with this same ratio. What we can do is multiply all of the dimensions of our first rectangle by 3.5 (to get our perimeter of 10 to 35, we multiply by 3.5).

3×3.5=10.5

2×3.5=7

If we simplify 10.5:7, we have 3:2, and the perimeter of a rectangle with a length of 10.5 and a width of 7 would equal 35 meters.

Have a wonderful day! :D

Answer:

[see below]

Step-by-step explanation:

A function is a relation where one domain value is assigned to exactly one range.

An x-value in a function must not repeat.

Hope this helps.

Answer:

ratio of hours lisa works to hours lisa sleeps= 3:8

Step-by-step explanation:

lisa goes to school for 7 hours per day lisa works 3 hours per day

Lisa sleeps 8 hours per day.

For the ratio of hours lisa works to hours lisa sleeps

ratio of hours lisa works to hours lisa sleeps= hours Lisa works/hours Lisa sleeps

ratio of hours lisa works to hours lisa sleeps= 3/8

ratio of hours lisa works to hours lisa sleeps= 3:8

Answer:

Calculated z= 3.515

The Z∝/2 = ±1.96  for ∝= 0.05

The Z∝/2 = ± 2.58  for ∝= 0.01

Yes the company claims valid at a level of significance of 0.05 and 0.01

Step-by-step explanation:

Here p1= 70% = 0.7

p2= 20/45= 0.444   q= 1-p= 1-.444= 0.56

The level of significance is 0.05 and 0.01

The null and alternative hypotheses are

H0; p1= p2                Ha: p1≠p2

The test statistic used here is

Z= p1-p2/ √pq/n

Z= 0.7-0.44/ √ 0.44*0.56/45

z= 0.26/ √0.2464/45

z= 3.515

The Z∝/2 = ±1.96  for ∝= 0.05

The Z∝/2 = ± 2.58  for ∝= 0.01

For the significance level 0.05 reject null hypothesis

For the significance level 0.01 reject null hypothesis

Yes the company claims valid at a level of significance of 0.05 and 0.01

Answer:

1 week= 7 days

number of days= 9

number of weeks= 1 week and 2 days

hope it helps :)

please mark it the brainliest!

Answer:

1 week and 2 days

Step-by-step explanation:

Answer:

Option (B)

Step-by-step explanation:

Since all the four rays A, E, D and F are diverging from a point C in the different directions.

Therefore, sum of all the angles formed at a point C will be equal to 360°

m∠1 + m∠4 + m∠6 + m∠9 = 360°

25° + 34° + 146° + m∠9 = 360°

m∠9 = 360° - 205°

        = 155°

Therefore, measure of angle 9 is 155°.

Option (B) will be the correct option.

Answer:

$32.58

Step-by-step explanation:

The area needed to be painted = 9 feet × 16 feet = 144 ft². The cost of painting a 53 ft² room is a quart of paint which costs $11.99, therefore the quart needed to paint 144 ft² area is:

[tex]Number\ of \ quart=\frac{144\ ft^2}{53\ ft^2} =2.717\ quart\\[/tex]

Since one quart cost $11.99, therefore the cost of 2.717 quart is:

Cost = 2.717 × $11.99 = $32.58

It would cost $32.58 to paint a 9 feet by 16 feet

Answer:

x = -4

Step-by-step explanation:

This vertical line is x = -4.  That's all we need here.

If the three points all fall on the same straight line, then a triangle will not form. Instead, a line will. We call these points to be collinear.

If the points aren't collinear, then a triangle forms.

Answer:

No.

Step-by-step explanation:

The points may be in a straight line, and that doesn't form a triangle.

Answer:

False the conjugate of 2+5i is 2-5i .

Step-by-step explanation:

Hope it will help you :)

[tex](0,-4)[/tex] fits the linear equation perfectly.

Hope this helps.

Answer:

the y-intercept is the point (0, -4) on the plane

Step-by-step explanation:

In order to find the y-intercept, write the equation in "slope intercept form"  solving for "y":

[tex]2\,y=x-8\\y=\frac{x-8}{2} \\y=\frac{x}{2} -\frac{8}{2} \\y=\frac{x}{2} -4[/tex]

Recall now that the y-intercept is the value at which the line crosses the y-axis (when x = 0), therefore:

[tex]y=\frac{x}{2} -4\\y=\frac{0}{2} -4\\y=-4[/tex]

So the y-intercept is the point (0, -4) on the plane.

First set up the ratio 2/5 = 10/x where x is the number of girls.

Now, we can use cross-products to find the missing value.

So we have (2)(x) = (5)(10).

Simplifying, we have 2x = 50.

Dividing both sides by 2, we find that x = 25.

So there are 25 girls in the class if there are 10 boys.

Answer: 300%

Step-by-step explanation:

percent of increase: new/old×100%-100%

Since it is percent of increase, you need to subtract the original percent (100%) from the current percent.

------------------

new (current)=2000

old (original)=500

 new/old×100%-100%

=2000/500×100%-100%

=4×100%-100%

=400%-100%

=300%

Hope this helps!! :)

Please let me know if you have any question or need further explanation

Answer:

0.185185185185185185.........

Step-by-step explanation:

i used a  calculator, to the nearst tenth is 0.18 to the nearest 100th is 0.185 also the 185 is repeating so u put a line over the numbers 185

Answer:

3 ÷ 162 = 0.01851851851

If you meant 162 ÷ 3 it is 54

If niether of the two answers above didnt answer your question, then sorry

Answer:

I believe the answer is A.

Step-by-step explanation:

If there are 13 daises per bouquet, that means one bouquet is all daises. The other bouquet has 30 flowers. 30-13 is 17 which means there are 17 other flowers rather than daises. 17 is greater than 13 by 4 which is not that  much. Therefore I think the answer is letter A.

Answer:

The correct answer is A.  The probability of randomly selecting a daisy from Bouquet S is less than the probability of randomly selecting a daisy from bouquet T.  

Step-by-step explanation:

We are told that Bouquet S contains 30 flowers and 13 of those flowers are daisies.   Therefore, the probability of selecting a daisy from Bouquet S can be modeled by:

13/30, which is greater than 1/3 but less than 1/2

We are also told that Bouquet T contains 13 flowers and 13 daises.  From this information, we can conclude that all of the flowers in Bouquet T are daises, or the probability can be modeled by:

13/13 = 1

Therefore, because the probability of selecting a daisy from Bouquet S is 13/30 and the probability of selecting a daisy from Bouquet T is 1, we can conclude that, as option A states, the probability of selecting a daisy from Bouquet S is less than the probability of selecting a daisy from Bouquet T.

Hope this helps!

Answer:

AM= Half of AB

or, 3x+3=(8x-6)/2

or, 6x+6=8x-6

or, 2x=12

Therefore,x=6

so,AM=3*6+3=21

So the units is 21

Answer:

[tex]\Huge \boxed{21}[/tex]

Step-by-step explanation:

AM = 3x + 3

AB = 8x - 6

Point M is the midpoint of AB.

So, AM = AB/2

3x + 3 = (8x - 6)/2

Multiplying both sides by 2.

2(3x + 3) = 8x - 6

Expanding brackets.

6x + 6 = 8x - 6

Subtracting 6x from both sides.

6 = 2x - 6

Adding 6 to both sides.

12 = 2x

Dividing both sides by 2.

6 = x

Let x = 6 for the length of AM.

3(6) + 3

18 + 3

21

Step-by-step explanation:

(A) Let a triangle be formed with height of pole h, length of base b and angle of elevation 58°. (Due to lack of a figure).

Tan 58° = h / b = 1.6

(B) Let another triangle be formed with height of pole h, length of base (b + 90) and angle of elevation 36°. (Due to lack of a figure).

Tan 36° = h / (b + 90) = 0.72

(C) Simplifying the two equations :

1.6b = 0.72b + 64.8

b = 64.8 / 0.88 = 73.6 m

h (height of pole) = 1.6 * 73.6 = 117.76 m

Answer:

x = -2

Step-by-step explanation:

​x−3x=2(4+x)

Distribute

x - 3x = 8 +2x

Combine like terms

-2x = 8+2x

Subtract 2x from each side

-2x-2x = 8+2x-2x

-4x = 8

Divide by -4

-4x/-4 = 8/-4

x = -2

Answer:

x-3x=2(4+x)

-2x=8+2x

-2x-2x=8

-4x=8

x=8/-4

x=-2

hope it helps budy x=2

mark me brainliest

Answer:

K=3.333

Step-by-step explanation:

-3=9(5-2k)/5

-3=45-18k/5

-15=45-18k

18k=60

K=60/18

K=3.3333

A)78°

135°+a° =180°

a°=45°

57°+x°+a°=180°

57°+x°+45°=180°

102°+x°=180°

x°=180°-102°

x°=78°

Answer:

C. Why? No repeating x values.

Answer:

Option B

Option E

Step-by-step explanation:

By the use of following postulates we can prove the two right triangles to be congruent.

1). HA - [Equal hypotenuse and an cute angles]

2). LL - [Two legs should be equal]

3). LA - [One leg and one angle must be equal]

4). ASA - [Two angles and the side containing these angles should be equal]

In the given right triangles,

1). OJ ≅ IL

2). ∠O ≅ ∠I

3). ∠J ≅ ∠L

Therefore, two postulates HA, ASA will be applicable for the congruence of the two triangles given.

Options A and E will be the answer.

Answer:

asa, ha, aas

Step-by-step explanation:

Answer:   A) a² = b² - w² + 2wx

Step-by-step explanation:

b² - (w - x)² = a² - x²

b² - (w² - 2wx + x²) = a² - x²

b² - w² + 2wx - x² = a² - x²

b² - w² + 2wx       = a²

Answer:

− 4 y  − 7

Step-by-step explanation:

Remove parentheses.

− 4 y − 4 − 3

Subtract  3  from  − 4

− 4 y  −  7

.

Answer: 11

Step-by-step explanation:

30 - 2(7+2)- 1        Distribute or  solve parentheses

30 - 14 -4 - 1  

30 - 19 = 11  

Answer:

x = 1/25

Step-by-step explanation:

2/5x+1/x=35

[tex]2/5x+1/x=35[/tex]

taking 1/x common

[tex]1/x(2/5+1)=35[/tex]

[tex](2+5)/5=35x\\7/5 = 35x\\x = 7/(5*35) = 1/(5*5) = 1/25[/tex]

Thus, value of x is 1/25

Answer: d) Neither of the answers are correct

Step-by-step explanation:

Law of Cosines: a² = b² + c² - 2bc · cos A

Note: The letters can be swapped but the letters on the outside must be the same.

Answer:

The correct answer is:

It is a continuous random variable. (B)

Step-by-step explanation:

Continuous random variables are variables that take on infinite possibility of values, hence the number of possible outcomes of a random variable cannot be counted. For instance, in this example, the amount of rainfall measured using a rain guage or a pluviometer has infinite possibilities of outcomes. it can either be 22.3 Liters, 20.1 Liters etc, up to infinity, in fact between 20 and 21 litres, there is an infinite possibility of outcomes.

Discrete random variables are variables that have a finite possibility of outcomes. the possibilities of occurrences can be counted. For example, if a coin is tossed, the coin can either land on its head or tail, hence there are two possibilities, making the variables discrete

The correct answer is:

It is a continuous random variable (B)

Step-by-step explanation:

Continuous Random Variables are variables that take on a number of possibilities of values that cannot be counted. The values have infinite possibilities. In this example, the height of a Giraffe measured in meters can be an unlimited possibility if values say, 10.5m, 15.22m 12.0m etc. The possibilities are endless.

Discrete Random variables are variables that take on a number of possibility of occurrences that can be counted. For instance, if a dice is rolled, the possibilities can either be a 1, 2, 3, 4, 5 or 6. There are six values that can be gotten, nothing in-between.

THANKS

0

0.0

(0 votes)

Answer:

1. Yes, there is sufficient evidence to support the claim that student cars are older than faculty cars.

2. The 98% confidence interval for the difference between the two population means is [1.432 years, 3.968 years].

Step-by-step explanation:

We are given that randomly selected 110 student cars to have ages with a mean of 8 years and a standard deviation of 3.6 years, while randomly selected 75 faculty cars to have ages with a mean of 5.3 years and a standard deviation of 3.7 years.

Let [tex]\mu_1[/tex] = mean age of student cars.

[tex]\mu_2[/tex]   = mean age of faculty cars.

So, Null Hypothesis, [tex]H_0[/tex] : [tex]\mu_1 \leq \mu_2[/tex]      {means that the student cars are younger than or equal to faculty cars}

Alternate Hypothesis, [tex]H_A[/tex] : [tex]\mu_1>\mu_2[/tex]      {means that the student cars are older than faculty cars}

(1) The test statistics that will be used here is Two-sample t-test statistics because we don't know about the population standard deviations;

                             T.S.  =  [tex]\frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)} {s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }[/tex]   ~   [tex]t_n_1_+_n_2_-_2[/tex]

where, [tex]\bar X_1[/tex] = sample mean age of student cars = 8 years

[tex]\bar X_2[/tex] = sample mean age of faculty cars = 5.3 years

[tex]s_1[/tex] = sample standard deviation of student cars = 3.6 years

[tex]s_2[/tex] = sample standard deviation of student cars = 3.7 years

[tex]n_1[/tex] = sample of student cars = 110

[tex]n_2[/tex] = sample of faculty cars = 75

Also, [tex]s_p=\sqrt{\frac{(n_1-1)\times s_1^{2}+(n_2-1)\times s_2^{2} }{n_1+n_2-2} }[/tex]  = [tex]\sqrt{\frac{(110-1)\times 3.6^{2}+(75-1)\times 3.7^{2} }{110+75-2} }[/tex]  = 3.641

So, the test statistics =  [tex]\frac{(8-5.3)-(0)} {3.641 \times \sqrt{\frac{1}{110}+\frac{1}{75} } }[/tex]  ~ [tex]t_1_8_3[/tex]

                                     =  4.952    

The value of t-test statistics is 4.952.

Since the value of our test statistics is more than the critical value of t, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region.

Therefore, we support the claim that student cars are older than faculty cars.

(2) The 98% confidence interval for the difference between the two population means ([tex]\mu_1-\mu_2[/tex]) is given by;

98% C.I. for ([tex]\mu_1-\mu_2[/tex]) = [tex](\bar X_1-\bar X_2) \pm (t_(_\frac{\alpha}{2}_) \times s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} })[/tex]

                                 = [tex](8-5.3) \pm (2.326 \times 3.641 \times \sqrt{\frac{1}{110}+\frac{1}{75} })[/tex]

                                 = [tex][2.7 \pm 1.268][/tex]

                                 = [1.432, 3.968]

Here, the critical value of t at a 1% level of significance is 2.326.

Hence, the 98% confidence interval for the difference between the two population means is [1.432 years, 3.968 years].