Write the ratio 2 : 5 in the form of 1 : n ?

Answer:

The point (0.75, 0.25) is not on the unit circle.

Step-by-step explanation:

The unit circle has radius 1, so:

[tex] {.75}^{2} + {.25}^{2} = .5625 + .0625 = .625 [/tex]

Answer:

$65.33

Step-by-step explanation:

12x = 784

÷12     ÷12

x = 65.33

They would each have to pay $65.33.

I hope this helps!

Answer: 5√(50) = 35.36 m^2

Step-by-step explanation:

The cross section is a rectangle, so its area formula is: Area = length * width.

If you look, the width is the diagonal of the side of the cube; thus, you can use Pythagorean theorem to find its measurement: a^2 + b^2 = c^2 → 5^2 + 5^2 = c^2 →

50 = c^2 → c = √(50)

Now, use the area formula and get: Area = 5 * √(50) = 5√(50) = 35.36 m^2 :)

Answer:

19.308

Step-by-step explanation:

The probability of throwing a sum of 10 at least 7 times in 9 throws of a pair of fair dice is 0.083

Probability refers to a possibility that deals with the occurrence of random events. The probability of all the events occurring need to be 1.

P(E) = Number of favorable outcomes / total number of outcomes

We assume that the probability of throwing a sum of 10 in a pair of fair dice is

[tex]\frac{n(5,5)(6,4)(4,6)}{n\: all\: events}[/tex]

= 3/36

= 0.083

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Answer:

x=4 + y/7

y= -28 + 7x

Step-by-step explanation:

Febuary 10th because on the left colom it showss the dates just look for the 10

Answer:

7

Step-by-step explanation:

4+6+7+8+10= 35/5= 7

Median and Mean= 7

6x+1-(3x-1)

=3x+2

Let's see point E in its original position: (3.-4)

Now lets transform the point (x,y) -->  (x + 8, y +5)

               (3, -4) --> (3 + 8, -4 + 5) --> (11, 1)

Therefore coordinate E's new position is (11, 1)

Hope that helps!

Answer:

26535600

Step-by-step explanation:

This took so much work to get into a format I could read hahaha!

I hope it helps!

30 x 12 x -13 x 15(12+-13+15)(12+-13)(12+15) = 26535600

Step-by-step explanation:

linear pair

linear pair

alternate angles.

alternate angles

cointerior angles

I will hope that you like my answer

Answer:

Step-by-step explanation:

How many numbers from 1 to 50 are multiples of 3?

3, 6, 9, 12, 15, 18 .......

Let's change the start and end value of the array and find the number of terms

Start at 3 and go all the way to 48 because those are the first and last multiples of 3 in this array.

There is a formula that allows us to quickly find the number of terms

We subtract the first term from the last term and divide by the amount of increase, then we add 1.

(48 - 3) / 3 + 1   =   16 numbers are exactly divisible by 3.

We have 50 numbers and 16 of them divisible by 3

16 / 50  = 8 / 25 probability

The probability that the chosen integer is divisible by 3 is 8/25 if an integer is chosen at random from 1 to 50 inclusive option first is correct.

It is defined as the ratio of the number of favorable outcomes to the total number of outcomes in other words the probability is the number that shows the happening of the event.

We have the number from 1 to 50.

Total numbers between 1 to 50 or total outcomes = 50

Total favorable outcomes = total number which is divisible by 3

[tex]=\frac{48-3}{3} +1[/tex]

= 15 + 1

= 16

Now probability will be:

= 16/50

= 8/25

Thus, the probability that the chosen integer is divisible by 3 is 8/25 if an integer is chosen at random from 1 to 50 inclusive option first is correct.

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Answer:

5x=2x+12

5x-2x=12

3x=12

x=4

A is the coreect one

We have sides of triangle as [tex]4.5[/tex] inches, [tex]6[/tex] inches and [tex]7[/tex] inches.

So the sum of square of two smallest side is-

[tex]=4.5^2+6^2[/tex]

[tex]=20.25+36[/tex]

[tex]=56.25[/tex]

Now lets find the value of square of longest side of triangle-

[tex]=7^2[/tex]

[tex]=49[/tex]

Now from both value

[tex]49[/tex] [tex]\neq[/tex] [tex]56.25[/tex]

[tex]7^2[/tex] [tex]\neq[/tex] [tex]4.5^2+6^2[/tex]

So from Pythagoras theorem the given triangle is not a right triangle so it can not moved to the corner.

Thus, Since the triangle is not a right triangle therefore it can not moved to the corner.

Answer:

There are many areas but

Step-by-step explanation:

Area of square is L × W

where you multiply both length × width you get the answers squared

Area of a cube is L × W × H

this is where you multiply all length × width × height and get the answer cube

Answer:

a) 160km

b) it will take 3.2 hours or 192 minutes or 3 hours and 12 minutes

Step-by-step explanation:

a) d=speedxtime

so, 64x2. 5=160km

b) time=d/s

so, 160/50

it will take 3.2 hours or 192 minutes or 3 hours and 12 minutes

Answer:

y = -3

Step-by-step explanation:

When you graph it on a graphing calculator or on desmos, it appears to be at y = -3

solutions:

1) G ≅ F

2) DA ≅  ES

Explanation:

Q)1

ΔBIG ≅ ΔFNS

pairs that are congruent:

From the list given,

→ G ≅ F is not necessarily congruent.

Q)2

ΔDAL ≅ ΔEKS

pairs that are congruent:

From the list given,

DA ≅  ES  is not necessarily congruent.

Usually the congruence is done according to naming

So

<B=F

<I=<N

<G=<S

#2

Check the naming

So

DA=EK

So option D

Answer:

y = 4

Step-by-step explanation:

Given:

[tex]-12=-3y[/tex]

Solve:

[tex]\mathrm{Divide\:both\:sides\:by\:}-3[/tex]

[tex]\frac{-3y}{-3}=\frac{-12}{-3}[/tex]

[tex]\mathrm{Simplify}[/tex]

Note: Negative + Negative = positive

y = 4

~lenvy~

Answer:

b ≈ 18.3303

[tex]b = \sqrt{{c}^{2} - {a}^{2} } [/tex]

[tex]b = \sqrt{ {19}^{2} - {5}^{2} } [/tex]

[tex]b = 18.3303[/tex]

If two pentagons are similar, then their sides are proportional. To find PT, we'll need to set up a proportion.

AE / PT = AB / PQ

---There are many ways to set up this proportion, it just depends on what side lengths you have and ensuring that they match up on both shapes.

6 / x = 5 / 12.5

5x = 75

x = 15

Length of PT = 15 cm

Option C

Hope this helps!

Answer:

X = 64

Y = 18

Z = 98

Step-by-step explanation:

Angles on a straight line always add up to 180 Degrees

Vertical Opposite Angles are equal to each other

X = 64

Y = 18

Z = 180 - 64 - 18 = 98

Answer:

[tex] {3}^{2} = 9 \\ \\ 81 = 9[/tex]

Answers:

Choice A) 0

Choice B) 0.5

=======================================================

Explanation:

Matia claims that [tex]x^2 > x[/tex]

However, the claim isn't true when 0 ≤ x ≤ 1.

For example, x = 0 leads to [tex]x^2 = 0^2 = 0[/tex]

Meaning that [tex]x^2 > x[/tex] would update to [tex]0 > 0[/tex] which is false.

------------------

Similarly, if x = 0.5, then

[tex]x^2 > x\\\\0.5^2 > 0.5\\\\0.25 > 0.5 \ \text{which is also false}\\\\[/tex]

Because the last inequality is false, the first inequality must also be false for x = 0.5

-------------------

Those last two previous sections showed that x = 0 and x = 0.5 are counter-examples to Matia's claim to thereby prove it false.

Answer:

you will fill 78 boxes

Step-by-step explanation:

dozen = 12

936 divided by 12=78

The quarterly payment will be $1,127.86

Compound interest is the interest on a loan or deposit that  levied on both the first principal and the collected interest from past periods.

The amortization formula is ...

[tex]A=\dfrac{P\timesr}{(1-(1+r)^{-n}}[/tex]

where A is the payment amount, P is the principal amount, r is the interest rate per period, and n is the number of periods.

Here, we have

P=$16,231, r=0.051/4=0.01275, n=4·4=16.

So, the payment is ...

[tex]A=\dfrac{16231\times 0.01275}{1-(1.01275)^{-16}}[/tex]  

[tex]A=$1127.86[/tex]

Hence the quarterly payment amount is $1,127.86.

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The equation that models the students is a linear equation

The equation that models the number of students in each bus is 6x = 216, and the number of students in each bus is 36

The given parameters are:

Students = 221

Van = 5

The rest students = 6 buses

Start by calculating the number of students remaining:

Remaining students = 221 - 5

Remaining students = 216

Represent the number of students in each bus with x.

So, we have:

6 buses * x  = Remaining students

This gives

6x = 216

Divide both sides by 6

x = 36

Hence, the equation that models the number of students in each bus is 6x = 216, and the number of students in each bus is 36

Read more about linear equations at:

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